1.

In the figure AB = 12 cm BC = 7 cm CD = 8 cm, AD = 10 cm, find [3]i. The length of AE ii. The length of CFiii. The length of EF​

Answer»

ANSWER:

In the given figure, let CE=CF=x

It is also given that AB=12 cm, BC=8 cm and AC=10 cm, therefore,

AF=AD=10−x

BE=BD=8−x

Now consider,

AB=AD+BD

⇒12=10−x+8−x

⇒12=18−2x

⇒2x=18−12

⇒2x=6

⇒x=

2

6

=3

Therefore, CE=x=3 cm, AF=10−3=7 cm and BD=8−3=5 cm

Hence, CE=3 cm, AF=7 cm and BD=5 cm.

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