332354 + Interview Questions in Secondary School in Math

1.	PLEASE HELP ME STATISTICS AND PROBABILITYConstruct a: frequency distribution, class boundaries, cumulative frequencies, and relative frequency.Number of Students per Class at the School of Nursing of ABC University45 44 23 50 25 35 54 55 50 40 4045 54 55 50 45 36 38 50 42 54 5355 55 50 45 47 45 48 51 51 36 4546 41 52 52 50 25 35 35 35 45 4040 40 45 45 46 46 47 51 56 55 50
Answer» ANSWER: Mathematics INCLUDES the STUDY of such topics as QUANTITY, structure, space, and change. It has no generally accepted DEFINITION. Mathematicians seek and use patterns to formulate new conjectures; they resolve the truth or falsity of such by mathematical proof.✿

1.

PLEASE HELP ME STATISTICS AND PROBABILITYConstruct a: frequency distribution, class boundaries, cumulative frequencies, and relative frequency.Number of Students per Class at the School of Nursing of ABC University45 44 23 50 25 35 54 55 50 40 4045 54 55 50 45 36 38 50 42 54 5355 55 50 45 47 45 48 51 51 36 4546 41 52 52 50 25 35 35 35 45 4040 40 45 45 46 46 47 51 56 55 50

Answer»

ANSWER:

Mathematics INCLUDES the STUDY of such topics as QUANTITY, structure, space, and change. It has no generally accepted DEFINITION. Mathematicians seek and use patterns to formulate new conjectures; they resolve the truth or falsity of such by mathematical proof.✿

Discussion

2.	Find bc it diameter of circle 10cm and ac is 6 cm
Answer» Answer: 4 cm Step-by-step EXPLANATION: DIAMETER 10 Ac 6 Bc = 10-6 = 4CM

2.

Find bc it diameter of circle 10cm and ac is 6 cm

Answer»

Answer:

4 cm

Step-by-step EXPLANATION:

DIAMETER 10

Ac 6

Bc = 10-6 = 4CM

Discussion

3.	N=?Beta(n,2) = 1/42
Answer» ANSWER: N= 7 Step-by-step explanation: explanation is GIVEN in ATTACHMENT hope you will UNDERSTAND

3.

N=?Beta(n,2) = 1/42

Answer»

ANSWER:

N= 7

Step-by-step explanation:

explanation is GIVEN in ATTACHMENT

hope you will UNDERSTAND

Discussion

4.	Hey!!The wheels of a car are of diameter 80 cm each. How many complete revolutions does each wheel make in 10 minutes when the car is travelling at a speed of 66 km per hour?
Answer» GIVEN : Diameter of a wheel of a car = 80 cm The speed of the car = 66 km/HR Time in which the car covers a particular distance at a speed of 66 km/hr = 10 minutes To find : Number of complete revolutions the car MAKES in 10 minutes Concept Used : Formula to calculate distance :- $\boxed{ \sf{ \pmb{ \blue{Distance = Speed \times Time}}}} \quad \star$ Formula to calculate radius :- $\boxed{ \sf{ \pmb{ \blue{Radius = \dfrac{Diameter}{2} }}}} \quad \star$ Formula to calculate circumference of circle :- $\boxed{ \sf{ \pmb{ \blue{Circumference = 2\pi r}}}} \quad \star$ where, Take π = 22/7 r = radius Solution : Firstly, we will calculate the distance travelled by the car in 10 minutes. For that we will convert the time from 10 minutes into hrs first. As we KNOW, 1 min = 1/60 hr Divide the value by 60 to convert it from minutes into hr. → Time = 10 min = 10/60 hr Using formula, $\\ \dashrightarrow \quad \sf Distance = Speed \times Time$ Substituting the given VALUES, $\\ \dashrightarrow \quad \sf Distance = 66 \times \dfrac{10}{60}$ $\\ \dashrightarrow \quad \sf Distance = 66 \times \dfrac{1 \not0}{ 6 \not0}$ $\\ \dashrightarrow \quad \sf Distance = \not66 \times \dfrac{1}{ \not6}$ $\\ \dashrightarrow \quad \sf Distance = 11$ $\\ \dashrightarrow \quad \sf \red{Distance = 11 \: km}$ Now, Convert the distance covered by the car in 10 minutes from km into cm. For that, multiply the value by 100000 cm. → Distance = 11 km = 11 × 100000 = 1100000 cm. Now, Calculate the circumference of the wheel. For that firstly, find the radius. Using formula, $\\ \dashrightarrow \quad\sf Radius = \dfrac{Diameter}{2}$ Substituting the given values, $\\ \dashrightarrow \quad\sf Radius = \dfrac{80}{2}$ $\\ \dashrightarrow \quad\sf Radius = \dfrac{ \not80}{ \not2}$ $\\ \dashrightarrow \quad\sf Radius = 40$ $\\ \dashrightarrow \quad\sf \red{Radius \: \: of \: \: the \: \: wheel = 40 \: cm}$ Using formula, $\\ \dashrightarrow \quad \sf Circumference = 2\pi r$ Substituting the given values, $\\ \dashrightarrow \quad \sf Circumference = 2 \times \dfrac{22}{7} \times 40$ $\\ \dashrightarrow \quad \sf Circumference = \dfrac{1760}{7} cm \: or \: 251.43 \: cm$ Number of revolutions × Circumference = Distance travelled in 10 minutes $\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions \times \dfrac{1760}{7} = 11$ $\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions = 1100000 \times \dfrac{7}{1760}$ $\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions = 110000 \not0 \times \dfrac{7}{176 \not0}$ $\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions = 110000 \times \dfrac{7}{176}$ $\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions = 4375$ $\\ \star \quad \sf \blue{No. \: \: of \: \: revolutions \: \: that \: \: the \: \: car \: \: makes \: \: in \: 10 \: minutes \: = 4375}$

4.

Hey!!The wheels of a car are of diameter 80 cm each. How many complete revolutions does each wheel make in 10 minutes when the car is travelling at a speed of 66 km per hour?

Answer»

GIVEN :

Diameter of a wheel of a car = 80 cm
The speed of the car = 66 km/HR
Time in which the car covers a particular distance at a speed of 66 km/hr = 10 minutes

To find :

Number of complete revolutions the car MAKES in 10 minutes

Concept Used :

Formula to calculate distance :-

$\boxed{ \sf{ \pmb{ \blue{Distance = Speed \times Time}}}} \quad \star$

Formula to calculate radius :-

$\boxed{ \sf{ \pmb{ \blue{Radius = \dfrac{Diameter}{2} }}}} \quad \star$

Formula to calculate circumference of circle :-

$\boxed{ \sf{ \pmb{ \blue{Circumference = 2\pi r}}}} \quad \star$

where,

Take π = 22/7
r = radius

Solution :

Firstly, we will calculate the distance travelled by the car in 10 minutes.

For that we will convert the time from 10 minutes into hrs first.

As we KNOW,

1 min = 1/60 hr

Divide the value by 60 to convert it from minutes into hr.

→ Time = 10 min = 10/60 hr

Using formula,

$\\ \dashrightarrow \quad \sf Distance = Speed \times Time$

Substituting the given VALUES,

$\\ \dashrightarrow \quad \sf Distance = 66 \times \dfrac{10}{60}$

$\\ \dashrightarrow \quad \sf Distance = 66 \times \dfrac{1 \not0}{ 6 \not0}$

$\\ \dashrightarrow \quad \sf Distance = \not66 \times \dfrac{1}{ \not6}$

$\\ \dashrightarrow \quad \sf Distance = 11$

$\\ \dashrightarrow \quad \sf \red{Distance = 11 \: km}$

Now,

Convert the distance covered by the car in 10 minutes from km into cm.

For that, multiply the value by 100000 cm.

→ Distance = 11 km = 11 × 100000 = 1100000 cm.

Now, Calculate the circumference of the wheel. For that firstly, find the radius.

Using formula,

$\\ \dashrightarrow \quad\sf Radius = \dfrac{Diameter}{2}$

Substituting the given values,

$\\ \dashrightarrow \quad\sf Radius = \dfrac{80}{2}$

$\\ \dashrightarrow \quad\sf Radius = \dfrac{ \not80}{ \not2}$

$\\ \dashrightarrow \quad\sf Radius = 40$

$\\ \dashrightarrow \quad\sf \red{Radius \: \: of \: \: the \: \: wheel = 40 \: cm}$

Using formula,

$\\ \dashrightarrow \quad \sf Circumference = 2\pi r$

Substituting the given values,

$\\ \dashrightarrow \quad \sf Circumference = 2 \times \dfrac{22}{7} \times 40$

$\\ \dashrightarrow \quad \sf Circumference = \dfrac{1760}{7} cm \: or \: 251.43 \: cm$

Number of revolutions × Circumference = Distance travelled in 10 minutes

$\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions \times \dfrac{1760}{7} = 11$

$\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions = 1100000 \times \dfrac{7}{1760}$

$\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions = 110000 \not0 \times \dfrac{7}{176 \not0}$

$\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions = 110000 \times \dfrac{7}{176}$

$\\ \dashrightarrow \quad \sf No. \: \: of \: \: revolutions = 4375$

$\\ \star \quad \sf \blue{No. \: \: of \: \: revolutions \: \: that \: \: the \: \: car \: \: makes \: \: in \: 10 \: minutes \: = 4375}$

Discussion

5.	___ -3,-2,-1,0,1 2,3, ____ are called
Answer» Answer: CALLED -5, -4,-3,-2,-1,0,1,2,3,4, integers

5.

_ -3,-2,-1,0,1 2,3, __ are called

Answer»

Answer:

CALLED -5, -4,-3,-2,-1,0,1,2,3,4, integers

Discussion

6.	1 x% of 130 = 10.4, then the value of x is :
Answer» Answer: 8 Step-by-step explanation: 130*x/100=10.4 13x/10=10.4 13x=104 x=8

6.

1 x% of 130 = 10.4, then the value of x is :

Answer»

Answer:

8

Step-by-step explanation:

130*x/100=10.4

13x/10=10.4

13x=104

x=8

Discussion

7.	In ∆PQR, AB//QR. If PA/PB=3, find PB/BR
Answer» i don't know sorry for the first time in the application

7.

In ∆PQR, AB//QR. If PA/PB=3, find PB/BR

Answer»

i

don't

know

sorry

for

the

first

time

in

the

application

Discussion

8.	What is the area of triangle with base 48 cm and height 36 cm
Answer» ½×base ×height ½×48×36 864cm² Hope this WORKS

8.

What is the area of triangle with base 48 cm and height 36 cm

Answer»

½×base ×height

½×48×36

864cm²

Hope this WORKS

Discussion

9.	1) If the amount of loan is Rs. 5000 and the interest at the end of first year is Rs 250, then compound interest in the second year will be levied on _________.(a) Rs. 5000(b) Rs. 5250(c) Rs. 5500(d) Rs. 250
Answer» ANSWER: (B) RS. 5250 Step-by-step EXPLANATION: (b) Rs. 5250

9.

1) If the amount of loan is Rs. 5000 and the interest at the end of first year is Rs 250, then compound interest in the second year will be levied on _________.(a) Rs. 5000(b) Rs. 5250(c) Rs. 5500(d) Rs. 250

Answer»

ANSWER:

(B) RS. 5250

Step-by-step EXPLANATION:

(b) Rs. 5250

Discussion

10.	5z + 7/3 = 4/3 Z - 14
Answer» ANSWER: krishnatiwaryiamanewboygivepoints

10.

5z + 7/3 = 4/3 Z - 14

Answer»

ANSWER:

krishnatiwaryiamanewboygivepoints

Discussion

11.	अर्द्धवार्षिकबाजार परशव नेD40,000 161.उधार लिया।दले होगे7वर्ष नपकितने रूपयेH
Answer» ANSWER: I THINK that your QUESTION is WRONG

11.

अर्द्धवार्षिकबाजार परशव नेD40,000 161.उधार लिया।दले होगे7वर्ष नपकितने रूपयेH

Answer»

ANSWER:

I THINK that your QUESTION is WRONG

Discussion

12.	how many spherical bullets each of 5cm in diameter can be cast from a rectangular block of metal 11dm × 1m × 5dm?
Answer» ANSWER: 8403 bullets Step-by-step explanation: 1dm=10cm 1m=100cm Hence TOTAL volume of BLOCK = L×B×H =110×100×50cm ³ =5,50,000cm³ No. of bullets CAST = =8403 bullets PLS MARK AS BRAINLIEST.

12.

how many spherical bullets each of 5cm in diameter can be cast from a rectangular block of metal 11dm × 1m × 5dm?

Answer»

ANSWER:

8403 bullets

Step-by-step explanation:

1dm=10cm

1m=100cm

Hence TOTAL volume of BLOCK = L×B×H

=110×100×50cm ³

=5,50,000cm³

No. of bullets CAST =

=8403 bullets

PLS MARK AS BRAINLIEST.

Discussion

13.	B) Convert the following in to Militers(1)8 L 800 ml
Answer» Answer: 8 L 800ml=8800ml Step-by-step EXPLANATION:

13.

B) Convert the following in to Militers(1)8 L 800 ml

Answer»

Answer:

8 L 800ml=8800ml

Step-by-step EXPLANATION:

Discussion

14.	A. Express ratio in simplest form: 125 8:1 kgb. Find the angles. The angles are complementary and the larger is four times the smaller angle,c. Find x in the following figure:AB \| CDAted. The perimeter of a square is 20 em. Find its area,e. Find the mean of First 7 whole numbers.f. Find the mode(s) of the given set of data. 4,6,8,4,10,4,6,12,6,10,g. Find the altitude of the triangle if its area is 25 ares and base is 20 m.h. Find the median of: 4,8, 12, 16, 20, 24, 28, 32
Answer» Answer: HELLO mate! Step-by-step explanation: 1st Question isn't clear 2.)The measure of each angles, 1 angle = x. the other and the larger angle is 4 times the smaller. so, 4x. x° + 4x° = 90° 5x° = 90°, x= 90/5°, x= 18° smallest Angle measures = 18° Largest angle measures = (4×18)°= 72° C.)Kindly, Upload the figure. d.)The perimeter of a square= 4S = 20m 1 SIDE,/ Measure of its LENGTH = 20/4. 1 side =5m. then, area of The square = S²= 5²= 25m². E.)The first 7 whole Numbers, = 0, 1, 2, 3, 4, 5, 6. hence, The arithemtic mean= sum of Total Numbers / Total Number. (0+1+2+3+4+5+6)/7= 21/7= 3. F.)Mode of the Given Number Series, 4,6,8,4,10,4,6,12,6,10. 10=2; 6=3; 4=3; 8=1; 12=1;. Mode of this series is, 6 and 4. G.)25m² is the area of the Traingle, traingle Area's = 1/2×Base×Height. 1/2×Base=20m× (H)m. 20Hm²/2= 25m². (20H)m²=25m²×2 20H = 50, H= 50/20. H=5/2m. Height of the Triangle = 5/2m H.)as it is already in ascending order, I don't need to arrange it. 4,8,12, (16,20), 24,28,32. Median = (16+20)/2= 36/2= 18. Thank you mate! Have a great day ahead!

14.

A. Express ratio in simplest form: 125 8:1 kgb. Find the angles. The angles are complementary and the larger is four times the smaller angle,c. Find x in the following figure:AB | CDAted. The perimeter of a square is 20 em. Find its area,e. Find the mean of First 7 whole numbers.f. Find the mode(s) of the given set of data. 4,6,8,4,10,4,6,12,6,10,g. Find the altitude of the triangle if its area is 25 ares and base is 20 m.h. Find the median of: 4,8, 12, 16, 20, 24, 28, 32

Answer»

Answer:

HELLO mate!

Step-by-step explanation:

1st Question isn't clear

2.)The measure of each angles,

1 angle = x.

the other and the larger angle is 4 times the smaller.

so, 4x.

x° + 4x° = 90°

5x° = 90°, x= 90/5°, x= 18°

smallest Angle measures = 18°

Largest angle measures = (4×18)°= 72°

C.)Kindly, Upload the figure.

d.)The perimeter of a square= 4S = 20m

1 SIDE,/ Measure of its LENGTH = 20/4.

1 side =5m.

then, area of The square = S²= 5²= 25m².

E.)The first 7 whole Numbers, = 0, 1, 2, 3, 4, 5, 6.

hence,

The arithemtic mean= sum of Total Numbers / Total Number.

(0+1+2+3+4+5+6)/7= 21/7= 3.

F.)Mode of the Given Number Series,

4,6,8,4,10,4,6,12,6,10.

10=2; 6=3; 4=3; 8=1; 12=1;.

Mode of this series is,

6 and 4.

G.)25m² is the area of the Traingle,

traingle Area's = 1/2×Base×Height.

1/2×Base=20m× (H)m.

20Hm²/2= 25m². (20H)m²=25m²×2

20H = 50, H= 50/20. H=5/2m.

Height of the Triangle = 5/2m

H.)as it is already in ascending order,

I don't need to arrange it.

4,8,12, (16,20), 24,28,32.

Median = (16+20)/2= 36/2= 18.

Thank you mate!

Have a great day ahead!

Discussion

15.	2/5 multiply 95 what is the answer please tell me
Answer» ANSWER: Answer is 38. Step-by-step EXPLANATION: I THINK it will HELP you.

15.

2/5 multiply 95 what is the answer please tell me

Answer»

ANSWER:

Answer is 38.

Step-by-step EXPLANATION:

I THINK it will HELP you.

Discussion

16.	7xy + 5x has _____ term
Answer» Answer: 2 TERMS THE GIVEN POLYNOMIAL HAS 2 TERMS

16.

7xy + 5x has _____ term

Answer»

Answer:

17.	22 m 50 cm + 25 m 75 cm
Answer» 22 m 50 cm + 25 m 75 cm = 47 m 125 cm = 48 m 25 cm

22 m 50 cm + 25 m 75 cm

Answer»

22 m 50 cm + 25 m 75 cm

= 47 m 125 cm

= 48 m 25 cm

Discussion

18.	THE ARITHMETIC MEAN OF FIRST THREE MULTIPLES OF 7
Answer» FIRST 3 MULTIPLES of 7: 7,14,21 Mean=7+14+21/3=42/3=14

18.

THE ARITHMETIC MEAN OF FIRST THREE MULTIPLES OF 7

Answer»

FIRST 3 MULTIPLES of 7: 7,14,21

Mean=7+14+21/3=42/3=14

Discussion

19.	(4)When polynomial x^3 + 3x^2 + 3x + 1 is divided by x + 1, the remainder is_____(a) 1(b) 0(c) 3(d) -6(5)If Y coordinate of a point is zero, then this point always lies in_______(a) Quadrant 1(b) Quadrant 2 (c) On x-axis (d) On y-axis
Answer» Answer: p.folow me Step-by-step explanation: When a polynomial p(x) is divided by (x−a) , the remainder is p(a) .” Also, when a polynomial p(x) is divided by another polynomial q(x) ,the degree of the remainder is at most 1 less than the degree of q(x) . USING the remainder THEOREM, we can write: p(1)=3;p(3)=5 p(x) can be written as: Dividend=(Divisor×Quotient)+Remainder p(x)=(x−1)(x−3)Q(x)+r(x) r(x) is the remainder polynomial and Q(x) is the Quotient polynomial. Since r(x) is linear, r(x)=Ax+B , where A and B are ARBITRARY constants. ⟹p(x)=(x−1)(x−3)Q(x)+Ax+B Now, p(1)=A+B=3⟹A+B=3 p(3)=3A+B=5⟹3A+B=5 Solving the 2 EQUATIONS, we get A=1 and B=2 . Therefore, r(x)=Ax+B=x+2 r(−2)=−2+2=0 Hence, r(−2)=0

19.

(4)When polynomial x^3 + 3x^2 + 3x + 1 is divided by x + 1, the remainder is_(a) 1(b) 0(c) 3(d) -6(5)If Y coordinate of a point is zero, then this point always lies in___(a) Quadrant 1(b) Quadrant 2 (c) On x-axis (d) On y-axis

Answer»

Answer:

p.folow me

Step-by-step explanation:

When a polynomial p(x) is divided by (x−a) , the remainder is p(a) .”

Also, when a polynomial p(x) is divided by another polynomial q(x) ,the degree of the remainder is at most 1 less than the degree of q(x) .

USING the remainder THEOREM, we can write:

p(1)=3;p(3)=5

p(x) can be written as:

Dividend=(Divisor×Quotient)+Remainder

p(x)=(x−1)(x−3)Q(x)+r(x)

r(x) is the remainder polynomial and Q(x) is the Quotient polynomial. Since r(x) is linear, r(x)=Ax+B , where A and B are ARBITRARY constants.

⟹p(x)=(x−1)(x−3)Q(x)+Ax+B

Now,

p(1)=A+B=3⟹A+B=3

p(3)=3A+B=5⟹3A+B=5

Solving the 2 EQUATIONS, we get A=1 and B=2 .

Therefore, r(x)=Ax+B=x+2

r(−2)=−2+2=0

Hence, r(−2)=0

Discussion

20.	Divide 64 in the ratio 2 is to 6.
Answer» Step-by-step explanation: REDUCE the GIVEN ratio to the lowest form and then form EQUATION.

20.

Divide 64 in the ratio 2 is to 6.

Answer»

Step-by-step explanation:

REDUCE the GIVEN ratio to the lowest form and then form EQUATION.

Discussion

21.	Find the indicated terms of the sequence whose nth terms are: An = (n - 1)(2-n)(3-n); a1,a2,a3
Answer» ANSWER: $a_{1}$ = 0 $a_{2}$ =0 $a_{<klux>3</klux>}$ = 0 Explanation: GIVEN: The nth term of an A.P. = $a_{n}$ = (n - 1)(2-n)(3-n) To find: a1, a2 & a3 Proof: $a_{n}$ = (n - 1) (2-n) (3-n) Putting n= 1 we get: = $a_{1}$ = (1-1) (2-1) (3-1) ⇒ $a_{1}$ = (0) (1) (2) ⇒ $a_{1}$ = 0 HENCE, first term = $a_{1}$ = 0 2. Putting n= 2 we get: = $a_{2}$ = (2-1) (2-2) (3-2) ⇒ $a_{2}$ = ( 1 ) (0) (1) ⇒ $a_{2}$ =0 Hence, second term = $a_{2}$ =0 3. Putting n= 3 we get: = $a_{3}$ = ( 3-1) (2-3) (3-3) ⇒ $a_{3}$ = (2) (-1) (0) ⇒ $a_{3}$ = 0 Hence, THIRD term = $a_{3}$ = 0 Thus, the indicated terms of the sequence are respectively: $a_{1}$ = 0 $a_{2}$ =0 $a_{3}$ = 0 Hope you got that. Thank You.

21.

Find the indicated terms of the sequence whose nth terms are: An = (n - 1)(2-n)(3-n); a1,a2,a3

Answer»

ANSWER:

$a_{1}$ = 0
$a_{2}$ =0
$a_{<klux>3</klux>}$ = 0

Explanation:

GIVEN:

The nth term of an A.P. = $a_{n}$ = (n - 1)(2-n)(3-n)

To find:

a1, a2 & a3

Proof:

$a_{n}$ = (n - 1) (2-n) (3-n)

Putting n= 1 we get:

= $a_{1}$ = (1-1) (2-1) (3-1)

⇒ $a_{1}$ = (0) (1) (2)

⇒ $a_{1}$ = 0

HENCE, first term = $a_{1}$ = 0

2. Putting n= 2 we get:

= $a_{2}$ = (2-1) (2-2) (3-2)

⇒ $a_{2}$ = ( 1 ) (0) (1)

⇒ $a_{2}$ =0

Hence, second term = $a_{2}$ =0

3. Putting n= 3 we get:

= $a_{3}$ = ( 3-1) (2-3) (3-3)

⇒ $a_{3}$ = (2) (-1) (0)

⇒ $a_{3}$ = 0

Hence, THIRD term = $a_{3}$ = 0

Thus, the indicated terms of the sequence are respectively:

$a_{1}$ = 0
$a_{2}$ =0
$a_{3}$ = 0

Hope you got that.

Thank You.

Discussion

22.	6. If p(n) is a polynomial of degree n>1 and 'a' is any real number the p(a)=0means factor p(n)(1) (n-a) (ii) (n+a) (iii) (n-1) (V)(n+2)
Answer» ANSWER: p(n) is a polynomial of degree n>1 and 'a' is any real NUMBER the p(a)=0 means factor p(n) (1) (n-a) (ii) (n+a) (iii) (n-1) (V)(n+2

22.

6. If p(n) is a polynomial of degree n>1 and 'a' is any real number the p(a)=0means factor p(n)(1) (n-a) (ii) (n+a) (iii) (n-1) (V)(n+2)

Answer»

ANSWER:

p(n) is a polynomial of degree n>1 and 'a' is any real NUMBER the p(a)=0

means factor p(n)

(1) (n-a) (ii) (n+a) (iii) (n-1) (V)(n+2

Discussion

23.	No. of people speak Hindi English Punjabi Gujrati Marathi Bengali respectively30 12 6 4 5 3 draw a piechart to represent this data
Answer» LOL how we gonna draw a PIE chart here now!!

Discussion

24.	Convert 4 1 \2 and 3 1\ 4 into like fraction
Answer» Step-by-step EXPLANATION: ANSWER is in the image hope it is HELPFUL

24.

Convert 4 1 \2 and 3 1\ 4 into like fraction

Answer»

Step-by-step EXPLANATION:

ANSWER is in the image

hope it is HELPFUL

Discussion

25.	What is the coefficient form of x^3-1?
Answer» ANSWER: c. Step-by-step EXPLANATION: i HOPE this answer will HELP you

25.

What is the coefficient form of x^3-1?

Answer»

ANSWER:

c.

Step-by-step EXPLANATION:

i HOPE this answer will HELP you

Discussion

26.	Which of the following bodies have more kinetic energy- Body A having mass 1.5 kgmoving with speed 30 ms or a body B having mass 2 kg moving with speed 20 msl?Justify your answer.
Answer» Step-by-step EXPLANATION: We know that, the kinetic ENERGY is K.E= 2 1 MV 2 ....(I) Checking all options given - A) m=3M & v=v K.E= 2 1 mv 2 K.E= 2 1 ×3M×v 2 K.E= 2 3Mv 2 B) m=3M & v=2v K.E= 2 1 mv 2 K.E= 2 1 ×3M×4v 2 K.E=6Mv 2 C) m=2M & v=3v K.E= 2 1 mv 2 K.E= 2 1 ×2M×9v 2 K.E=9Mv 2 D) m=M & v=4v K.E= 2 1 ×M×16v 2 K.E=8Mv 2

26.

Which of the following bodies have more kinetic energy- Body A having mass 1.5 kgmoving with speed 30 ms or a body B having mass 2 kg moving with speed 20 msl?Justify your answer.

Answer»

Step-by-step EXPLANATION:

We know that, the kinetic ENERGY is

K.E=

2

1

MV

2

....(I)

Checking all options given -

A) m=3M & v=v

K.E=

2

1

mv

2

K.E=

2

1

×3M×v

2

K.E=

2

3Mv

2

B) m=3M & v=2v

K.E=

2

1

mv

2

K.E=

2

1

×3M×4v

2

K.E=6Mv

2

C) m=2M & v=3v

K.E=

2

1

mv

2

K.E=

2

1

×2M×9v

2

K.E=9Mv

2

D) m=M & v=4v

K.E=

2

1

×M×16v

2

K.E=8Mv

2

Discussion

27.	____ place value system is used in India for representing large numbers
Answer» This is your ANSWER PLEASE GIVE me a THANK

27.

____ place value system is used in India for representing large numbers

Answer»

This is your ANSWER

28.	A rational number between -½ and ½ is
Answer» Answer: YARR MERA answer 0/ 4 a Raha h

A rational number between -½ and ½ is

Answer»

Answer:

YARR MERA answer 0/ 4 a Raha h

Discussion

29.	Parallel faces have a common edge
Answer» ANSWER: No Hope IE helps Step-by-step EXPLANATION: Mark it as Brainlist

29.

Parallel faces have a common edge

Answer»

ANSWER:

No

Hope IE helps

Step-by-step EXPLANATION:

Mark it as Brainlist

Discussion

30.	ABC is right angled at B. if AC=25cm,BC=7cm. find the length of AB.
Answer» ANSWER: USE H² =P² + B² Pythagoras THEORM

30.

ABC is right angled at B. if AC=25cm,BC=7cm. find the length of AB.

Answer»

ANSWER:

USE H² =P² + B²

Pythagoras THEORM

Discussion

31.	If a bar magnet is hung freely in air with help of thread , it will be steady in the direction______East - WestNorth - SouthEast - South
Answer» ANSWER: NORTH -south is the answer please mark me as brainliest

31.

If a bar magnet is hung freely in air with help of thread , it will be steady in the direction______East - WestNorth - SouthEast - South

Answer»

ANSWER:

NORTH -south is the answer please mark me as brainliest

Discussion

32.	804 Solve.(1) The following table shows the number of workers in a factory andtheir daily wages. Find the median of the daily wages.Daily wages100-110 110-120 120-130 130-140 140-150 150-160(Rupees)No. of3738403328workers 37384033224
Answer» Step-by-step EXPLANATION: pls REFER the above PICS for the ANSWER☝ Mark the answer as BRAINLIST!!!!

32.

804 Solve.(1) The following table shows the number of workers in a factory andtheir daily wages. Find the median of the daily wages.Daily wages100-110 110-120 120-130 130-140 140-150 150-160(Rupees)No. of3738403328workers 37384033224

Answer»

Step-by-step EXPLANATION:

pls REFER the above PICS for the ANSWER☝

Mark the answer as BRAINLIST!!!!

Discussion

33.	The price of 2 pencils and 3 erasers is ₹46.The price of 3 pencils and 5 erasers is ₹74.Find theprice of 1 pencil and 1 eraser.
Answer» ANSWER: i ഡോണ്ട് നോ തെ ANAWER sorru

33.

The price of 2 pencils and 3 erasers is ₹46.The price of 3 pencils and 5 erasers is ₹74.Find theprice of 1 pencil and 1 eraser.

Answer»

ANSWER:

i ഡോണ്ട് നോ തെ ANAWER sorru

Discussion

34.	Two lines are given to be parallel the equation of one of the line is 4x +3y =14, then find the equation of secondline
Answer» ANSWER: the equation of SECOND LINE will be same because the are PARALLEL, mark me barainlist

34.

Two lines are given to be parallel the equation of one of the line is 4x +3y =14, then find the equation of secondline

Answer»

ANSWER:

the equation of SECOND LINE will be same because the are PARALLEL, mark me barainlist

Discussion

35.	Write the degree of the polynomial 4x²+x²+y²+4y²
Answer» ANSWER: The CORRECT answer is 2.

35.

Write the degree of the polynomial 4x²+x²+y²+4y²

Answer»

ANSWER:

The CORRECT answer is 2.

Discussion

36.	How much food can this container hold radius 3in 9 height
Answer» ANSWER: Here your ANS,in ATTACHEMENT FORM.

36.

How much food can this container hold radius 3in 9 height

Answer»

ANSWER:

Here your ANS,in ATTACHEMENT FORM.

Discussion

37.	Rationalise 3/root 19
Answer» Answer: 0.688 Step-by-step explanation: 3/√19 = 3/4.358 = 0.688

37.

Rationalise 3/root 19

Answer»

Answer:

0.688

Step-by-step explanation:

3/√19

= 3/4.358

= 0.688

Discussion

38.	My sister needs to do this and I genuinely forgot how to do so brain.ly do your thing
Answer» ANSWER: square root of 225 = 15 square root of 64 = 8

38.

My sister needs to do this and I genuinely forgot how to do so brain.ly do your thing

Answer»

ANSWER:

square root of 225 = 15

square root of 64 = 8

Discussion

39.	, please help meDon't spam
Answer» ANSWER: tgi-izbe-fjv can ANYONE COME

39.

, please help meDon't spam

Answer»

ANSWER:

tgi-izbe-fjv can ANYONE COME

Discussion

40.	What is the area of this shape. Put in terms of pi
Answer» ANSWER: THATS not a shape Step-by-step EXPLANATION:

40.

What is the area of this shape. Put in terms of pi

Answer»

ANSWER:

THATS not a shape

Step-by-step EXPLANATION:

Discussion

41.	Solve the two-step equation below:5.1 = –3x – 4.2___________________use the following steps:1. Add 4.2 to both sides.2. Divide both sides by -3._______________The solution is x = __
Answer» ANSWER: EQUATION: Step-by-step explanation: 5.1= -3X - 4.2 -3x= - 4.2 - 5.1 -3x= -9.3 x= 9.3 + 3 x= 12.3

41.

Solve the two-step equation below:5.1 = –3x – 4.2_______use the following steps:1. Add 4.2 to both sides.2. Divide both sides by -3._The solution is x =

Answer»

ANSWER:

EQUATION:

Step-by-step explanation:

5.1= -3X - 4.2

-3x= - 4.2 - 5.1

-3x= -9.3

x= 9.3 + 3

x= 12.3

Discussion

42.	2. The number of words in a child’s vocabulary is a function of the child’s age. A typical child at the age of 20 months has a vocabulary of 300 words. At the age of 50 months, the child’s vocabulary has increased to 2,100 words. Graph the pairs of points generated from the last two sentences, where the age is the independent variable and the vocabulary is the dependent variable.How many words would a 30-month old child know? How many words would a 40-month old child know?How many words does a typical child learn each month from the age of 20 months to the age of 50 months? Could a graph be used to estimate how many words a 10-month old child knows? Explain.
Answer» Answer: hhguioknb24gyùiì8776yyi8okkhhy88oily Step-by-step EXPLANATION: Edinburgh th minute when he got the GIVEN ROMAN numeral in hindu ARABIC the given Roman numeral in hindu Arabic the given Roman numeral in hindu Arabic the given Roman numeral in hindu Arabic the given Roman numeral in hindu Arabic

42.

2. The number of words in a child’s vocabulary is a function of the child’s age. A typical child at the age of 20 months has a vocabulary of 300 words. At the age of 50 months, the child’s vocabulary has increased to 2,100 words. Graph the pairs of points generated from the last two sentences, where the age is the independent variable and the vocabulary is the dependent variable.How many words would a 30-month old child know? How many words would a 40-month old child know?How many words does a typical child learn each month from the age of 20 months to the age of 50 months? Could a graph be used to estimate how many words a 10-month old child knows? Explain.

Answer»

Answer:

hhguioknb24gyùiì8776yyi8okkhhy88oily

Step-by-step EXPLANATION:

Edinburgh th minute when he got the GIVEN ROMAN numeral in hindu ARABIC the given Roman numeral in hindu Arabic the given Roman numeral in hindu Arabic the given Roman numeral in hindu Arabic the given Roman numeral in hindu Arabic

Discussion

43.	32. A motor cycle tyre is sold for Rs 300/- What is the purchase prices25% profit is added to it.
Answer» Step-by-step explanation: S.P= Rs.300 C.P=? Profit=25% Now, let the c.p be X C.P= S.P-profit x=300-25% of x x=300-25/100× x x=300-x/20 x+x/20=300 20X + x=300×20 21X =6000 x=6000/21 x=285.75

43.

32. A motor cycle tyre is sold for Rs 300/- What is the purchase prices25% profit is added to it.

Answer»

Step-by-step explanation:

S.P= Rs.300

C.P=?

Profit=25%

Now,

let the c.p be X

C.P= S.P-profit

x=300-25% of x

x=300-25/100× x

x=300-x/20

x+x/20=300

20X + x=300×20

21X =6000

x=6000/21

x=285.75

Discussion

44.	If the mth term of an AP is 1/n and the nth term is 1/m,show that the sum of mn terms is 1/2(mn+1).
Answer» Given:- mth term of an AP is 1/n. the nth term is 1/m. To prove:- the sum of mn terms is 1/2(mn+1). step-by-step SOLUTION:- Let mth term of AP be ‘Am’ and nth term of AP be ‘An’ Therefore, Am = a+ (m-1)d=1/n ----------(i) An = a+(n-1)d=1/m ------------(ii) Subtracting equation (ii) from (i) d[(m - 1) - (n - 1)] = 1/n - 1/m, d(m - n) = (m - n)/mn, d = 1/mn --------(III) Substituting equation (iii) in (i) a + (m - 1)/mn = 1/n, a = 1/n[1 - (m - 1)/m], a = 1/mn --------(iv) Now AMN i.e the mnth term of AP = a + (mn - 1)d, Substitute equation (iii) and (iv) in Amn, 1/mn + (mn - 1)/mn = 1/mn[1 + (mn - 1)] = mn/mn = 1, then the mn term = 1 Sum of MN term:- :- Amn = mn/2 ( 2/mn + (mn-1)1/mn) = 1 + (mn)/2 - 1/2 = mn /2 + 1/2 = 1/2 (mn + 1)

44.

If the mth term of an AP is 1/n and the nth term is 1/m,show that the sum of mn terms is 1/2(mn+1).

Answer»

Given:-

mth term of an AP is 1/n.
the nth term is 1/m.

To prove:-

the sum of mn terms is 1/2(mn+1).

step-by-step SOLUTION:-

Let mth term of AP be ‘Am’ and nth term of AP be ‘An’

Therefore,

Am = a+ (m-1)d=1/n ----------(i)

An = a+(n-1)d=1/m ------------(ii)

Subtracting equation (ii) from (i)

d[(m - 1) - (n - 1)] = 1/n - 1/m,

d(m - n) = (m - n)/mn,

d = 1/mn --------(III)

Substituting equation (iii) in (i)

a + (m - 1)/mn = 1/n,

a = 1/n[1 - (m - 1)/m],

a = 1/mn --------(iv)

Now AMN i.e the mnth term of AP = a + (mn - 1)d,

Substitute equation (iii) and (iv) in Amn,

1/mn + (mn - 1)/mn

= 1/mn[1 + (mn - 1)]

= mn/mn = 1,

then the mn term = 1

Sum of MN term:- :-

Amn = mn/2 ( 2/mn + (mn-1)1/mn)

= 1 + (mn)/2 - 1/2

= mn /2 + 1/2

= 1/2 (mn + 1)

Discussion

45.	Solve the following pair of linear equations by substitution method
Answer» ANSWER: where is the QUESTION ⁉️⁉️

45.

Solve the following pair of linear equations by substitution method

Answer»

ANSWER:

where is the QUESTION ⁉️⁉️

Discussion

46.	AB is diameter and AC is a chord of a circle. If AB = 34cm and AC = 30cm, then find thedistance of chord AC from the center of the circle
Answer» Answer: 8 cm Step-by-step explanation: AOX is a right angled triangle ∴AO 2 =OX 2 +AX 2 ⇒17 2 =OX 2 +15 2 ⇒OX 2 =17 2 −15 2 ⇒OX 2 = 64 ⇒OX=8cm

46.

AB is diameter and AC is a chord of a circle. If AB = 34cm and AC = 30cm, then find thedistance of chord AC from the center of the circle

Answer»

Answer:

8 cm

Step-by-step explanation:

AOX is a right angled triangle

∴AO

2

=OX

2

+AX

2

⇒17

2

=OX

2

+15

2

⇒OX

2

=17

2

−15

2

⇒OX

2

=

64

⇒OX=8cm

Discussion

47.	10-if the mean of 16, 14, X, 23, 20 is 18. Find thevalue of x.a. 17b-16
Answer» Answer :- Option a is correct. The value of X is 17. Given :- The mean of 16, 14, x, 23 and 20 is 18. To FIND :- The value of x. Step-by-step EXPLANATION :- We know that :- $\underline{ \boxed{ \sf Mean = \dfrac{Sum \: of \: observations}{Number \: of \: observations}}}$ Here, Sum of observations = 16 + 14 + x + 23 + 20. Number of observations = 5. Mean = 18. ----------------- $\underline{\underline{\mathfrak{Substituting \: these \: values \: in \: the \: formula,}}}$ $\boxed{\sf \dfrac{16 + 14 + x + 23 + 20}{5} = 18}$ Adding all the numbers, $\implies\boxed{ \sf\dfrac{73 + x}{5} = 18}$ Transposing 5 from LHS to RHS, changing it's sign, $\implies\boxed{ \sf73 +x = 18 \times 5}$ On multiplying 18 by 5, $\implies \boxed {\sf73 + x = 90}$ Transposing 73 from LHS to RHS, changing it's sign, $\implies\boxed{ \sf x = 90 - 73}$ Subtracting 73 from 90, $\implies \overline{\boxed{\sf x = 17.}}$ ----------------------------------------------------------- Hence, the value of x is 17.

47.

10-if the mean of 16, 14, X, 23, 20 is 18. Find thevalue of x.a. 17b-16

Answer»

Answer :-

Option a is correct.

The value of X is 17.

Given :-

The mean of 16, 14, x, 23 and 20 is 18.

To FIND :-

The value of x.

Step-by-step EXPLANATION :-

We know that :-

$\underline{ \boxed{ \sf Mean = \dfrac{Sum \: of \: observations}{Number \: of \: observations}}}$

Here,

Sum of observations = 16 + 14 + x + 23 + 20.

Number of observations = 5.

Mean = 18.

-----------------

$\underline{\underline{\mathfrak{Substituting \: these \: values \: in \: the \: formula,}}}$

$\boxed{\sf \dfrac{16 + 14 + x + 23 + 20}{5} = 18}$

Adding all the numbers,

$\implies\boxed{ \sf\dfrac{73 + x}{5} = 18}$

Transposing 5 from LHS to RHS, changing it's sign,

$\implies\boxed{ \sf73 +x = 18 \times 5}$

On multiplying 18 by 5,

$\implies \boxed {\sf73 + x = 90}$

Transposing 73 from LHS to RHS, changing it's sign,

$\implies\boxed{ \sf x = 90 - 73}$

Subtracting 73 from 90,

$\implies \overline{\boxed{\sf x = 17.}}$

-----------------------------------------------------------

Hence, the value of x is 17.

Discussion

48.	15, 25, 35, 45,55,55, 65,35, 25, 1515, 55, 65, 55, 45, 35, 65, 25, 45, 2515, 25, 35 45 55 75 45,65 25.5565, 75, 35,55, 45, 55, 65, 45, 35, 5575 65, 55, 45, 35, 25, 55, 65,25 55Find mode
Answer» Answer: what is this question PLEASE give WRITE question please

48.

15, 25, 35, 45,55,55, 65,35, 25, 1515, 55, 65, 55, 45, 35, 65, 25, 45, 2515, 25, 35 45 55 75 45,65 25.5565, 75, 35,55, 45, 55, 65, 45, 35, 5575 65, 55, 45, 35, 25, 55, 65,25 55Find mode

Answer»

Answer:

what is this question

PLEASE give WRITE question please

Discussion

49.	How much money does 4 ten rupee notes and 3 five rupee notes make? write relation using letters
Answer» Answer: 5time usuejeehegehemwmwhuwkwkwkw

49.

How much money does 4 ten rupee notes and 3 five rupee notes make? write relation using letters

Answer»

Answer:

5time usuejeehegehemwmwhuwkwkwkw

Discussion

50.	Let A = {2, {2}, (√2)2 } , B = {2, {2}, {{2}}} and C = {2}. Evaluate the truth and falsity of the following statements. a. A ⊆ B Please write your reason *
Answer» Step-by-step EXPLANATION: Statement-1: If A ≠ I and A ≠ - I, then det A = - 1. Statement-2: If A ≠ I and A ≠ - I, then TR (A) ≠ 0 . (A) Statement-1 is FALSE, Statement-2 is true. (B) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1. (C) Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1. (D) Statement-1 is true, Statement-2 is false

50.

Let A = {2, {2}, (√2)2 } , B = {2, {2}, {{2}}} and C = {2}. Evaluate the truth and falsity of the following statements. a. A ⊆ B Please write your reason *

Answer»

Step-by-step EXPLANATION:

Statement-1: If A ≠ I and A ≠ - I, then det A = - 1. Statement-2: If A ≠ I and A ≠ - I, then TR

(A) ≠ 0

. (A) Statement-1 is FALSE, Statement-2 is true. (B) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.

(C) Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.

(D) Statement-1 is true, Statement-2 is false

Discussion

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Parallel faces have a common edge

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Write the degree of the polynomial 4x²+x²+y²+4y²

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Solve the two-step equation below:5.1 = –3x – 4.2_______use the following steps:1. Add 4.2 to both sides.2. Divide both sides by -3._The solution is x =

32. A motor cycle tyre is sold for Rs 300/- What is the purchase prices25% profit is added to it.

If the mth term of an AP is 1/n and the nth term is 1/m,show that the sum of mn terms is 1/2(mn+1).

Solve the following pair of linear equations by substitution method

AB is diameter and AC is a chord of a circle. If AB = 34cm and AC = 30cm, then find thedistance of chord AC from the center of the circle

10-if the mean of 16, 14, X, 23, 20 is 18. Find thevalue of x.a. 17b-16

15, 25, 35, 45,55,55, 65,35, 25, 1515, 55, 65, 55, 45, 35, 65, 25, 45, 2515, 25, 35 45 55 75 45,65 25.5565, 75, 35,55, 45, 55, 65, 45, 35, 5575 65, 55, 45, 35, 25, 55, 65,25 55Find mode

How much money does 4 ten rupee notes and 3 five rupee notes make? write relation using letters

Let A = {2, {2}, (√2)2 } , B = {2, {2}, {{2}}} and C = {2}. Evaluate the truth and falsity of the following statements. a. A ⊆ B Please write your reason *