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The GIVEN AREA is 30 cm sq.
atq...............  l×b=30
                     l×5=30
                       l=6
so length is 6 cm

now for perimeter
2{l+b}
2[6+5}
2{11}
=22 cm

Let,
The breadth of the park be x m,
Length of the park be (x+17) m

___________

Perimeter of rectangle =2(lenght + breadth)

Here,

178= 2(x + x+ 17)

178/2 = x + x+ 17

89 = 2x + 17

89-17 = 2x


72 = 2x

72/2 = x

36= x

, _____________, _

Then,

Breath of park = x = 36 m

Length of the park = x +17 = 36+17 = 53 m


I hope this will help you


-by ABHAY

( 2 + /3 ) - ( 2 - /3 )
= 2 + /3 - 2 + /3
= 2/3



=> here /3 = ROOT 3

Here's your ANSWER FRIEND:-
mean of the GIVEN QUESTION is 5.

(x+5) (2x + 3)
= 2x^2 + 3X + 10X + 15
= 2x^2 + 13x + 15

A MISTAKE in question INSTEAD of I he should be used in LAST line

x be correct attempts and y be incorrect attempts
then 5x-2y=30
5(10)-2y=30
2y=20
y=10
Therefore he answered 10 QUESTIONS incorrectly...
HOPE it helps....

Hey friend

Your QUESTION is incomplete since you have not attached your PICTURE. KINDLY REPOST your question.

Final Answer = 0

Understanding:
1) Maximumum Value of sin a = 1
2) Trigonometric Identities

STEP :

1) Max(sin a) = 1
=> sinA =sinB=sinC =1

2) COS A = cos B = cos C = 0

Hope you understand my answer :

This is your ANSWER I HOPE it is RIGHT

To prove that a-1 /a-1 +b-1 +a-1 /a-1 -b-1 = 2b2 /b2 -a2Lets take the LHS (Left Hand SIDE) first:

=1/a÷1/a+1/b + 1/a÷1/a -1/b

Next take the LCM for the denominator, so it becomes:

=1/a÷b+a /ab + 1/a÷b-a /ab

=1/a×ab /b+a+ 1/a×ab /b-a

Now 'a' gets CANCELLED in both the numerator and the denominator. So it becomes:

=1/a×ab /b+a+ 1/a×ab /b-a

=b /b+a+b /b-a

take the LCM of the denominator and so it becomes:

=b(b-a)/(b+a)(b-a)+b(b+a)/(b-a)(b+a)

=b2 -ab /b2 -a2 +b2 +ab /b2 -a2

=b2 -ab +b2 +ab /b2 -a2

=b2+b2/b2-a2

=2b2/b2 -a2 ==== RHS (Right Hand Side)

HOPE it helps u!!!!!

The MATERIALS USED PREPARE any food items are called ingredients

X=2+√3=2+1.67=3.67 as √3 is EQUAL to 1.67

Which SOLUTIONS DEAR.
PLS MENTION

Yes it is true because SINCE the INVERSE of a matrix is unique THEREFORE the solution will ALSO be unique.

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Given,
First term ( a ) = 5
Last term ( l) = 45
Sum of n terms = 400 .

We KNOW that,
Sum of n terms = n/2 ( a + l)

400 = n/2 ( 5 + 45 )

400/50 =n/2

8 = n/2

8 * 2 = n.

n = 16 .

So, 16 th term = 45

a + 15 d = 45

5 + 15d = 45

15d = 40

d = 8/3 .

SECOND term = a + d = 5 + 8/3 = 23/3

Common difference = 8/3

HOPE HELPED !

2.k^2/4 -(k-6)k/2-3k=0
k^2/2 - k^2/2+3k-3k=0
so all VALUES cancels out ....

on DIFFERENTIATING ,we GET...
4x+k-6=0
so, 4(-k/2)+k-6=0
-2k+k-6=0
-k-6=0
-k =6
k= -6....
I hope this is the ANSWER....

Because TWO opposite​ SIDES R PARALLELS

In a way, an eigenvalue PROBLEM is a problem that looks as if it should have continuous answers, but instead only has discrete ones. The problem is to find the numbers, called eigenvalues, and their matching vectors, called eigenvectors. This is extremely general—it is used in differential equations (because solutions to linear differential equations form linear spaces!) and DESCRIBED in detail in linear algebra.

The basic idea for linear equations is this: Ax = bhas a unique solution if A is invertible, and has either many or no solutions if not. If it were basic algebra, we would divide both sides of the equation by A, but division is not defined for matrices. So we work around it; if your calculator’s division button were stuck, and you needed to divide a number by 2, what would you do? You could multiply by 0.5, and get the answer. 0.5 is the (multiplicative) inverse of 2. So we want to solve by FINDING the matrix A^(-1) that we could multiply the equation Ax = b by, and get A^(-1) A x = A^(-1) b = I x = x.

The basic idea for eigenvalues is this: Does Ax = Lx for some vector x and number L? (USUALLY lambda is used for L.)

Imagine a 3x3 matrix A that transforms vectors in 3D into other vectors in 3D. The eigenvalue question is this: what vectors are not rotated by A? And if they aren’t rotated, are they reversed, smaller, larger, or the same magnitude? What number L is the LENGTH of eigenvector xmultiplied by when A acts on it?

Some matrices don’t have real eigenvalues or eigenvectors— a rotation matrix in 2 D, for example, rotates everything. (The zero vector 0doesn’t count, because that always works trivially.) Some matrices have one or more; some have a “full set” of n eigenvectors in n dimensions. Those matrices we call “diagonalizable.” This is important in quantum mechanics because if you can diagonalize a matrix that means you can measure a thing and get specific answers.

Here the matrix is SINGULAR THEREFORE the DETERMINANT is 0. After expanding you will get equation. After that I am attaching it's SOLUTION.

Required no = HCF of 21, 35 and 49 
HENCE ANSWER is 7

Plz CHECK UR question. Where is a and b? I THINK it should be x^2+xy+y^2

No LINEAR REGRESSION cannot be USED for PREDICTIONS

Hola....!!!!

Here's ur ans.⬇

Quadratic EQUATION = 3x^2 - X - 4

By MIDDLE term split ,

3x^2 - 4X + 3x - 4

x(3x - 4) + 1 (3x -4)

(x+1 ) (3x - 4)

x = -1

x = 4/3

✌Hope it HELPS

Buddy DAD dinner add to DAYS a WEEK so to watch REDDY until the essay FYI t they get cut was dry of DEVIL hydro heis gud it

Aloha ! ☺️✨




________________________




As we know ,

Adjacent SIDES of a ||gm is 180 °


Now ,

LET the angles be 2x and 3x ,


2x+3x = 180°

5x = 180°

x = 36°



•°• The angles = 2x = 72°

= 3x = 108°



✔️ The MEASURE of big angle = 108° ✔️



__________________________



Hope it helps you...!! ✌️✨

Here is your answer but remember this:-

a = FIRST TERM
l = last term
n = number of terms
d = common difference
Sn = SUM of all term (answer)

QUE. 4
i) a = 1
l = 13
d = 2
n = 7

Answer is 49.

ii) a = 1
l = 19
n = 10

Answer is 100.

iii) a = 1
l = 23
n = 12

Answer is 144.

Hope it helps.
If you satisfied mark it brainliest.