332354 + Interview Questions in Secondary School in Math

1.	The cost of one kg of potato is ₹20 . what is the cost of 3¼ kg of potatoes?
Answer» Step-by-step EXPLANATION: ANSWER in ATTACHED FILE

1.

The cost of one kg of potato is ₹20 . what is the cost of 3¼ kg of potatoes?

Answer»

Step-by-step EXPLANATION:

ANSWER in ATTACHED FILE

Discussion

2.	4,16,80,120,240 find odd one
Answer» Step-by-step explanation: 4,16,80,120,240 FIND ODD ONE

2.

4,16,80,120,240 find odd one

Answer»

Step-by-step explanation:

4,16,80,120,240 FIND ODD ONE

Discussion

3.	The solution of the equations x - y = 10 and x + y = 70 is --------.A) (40,30) B) (30,40) C) (10,60) D) (50,20)
Answer» Answer: A) 40, 30 Step-by-step explanation: ADDING both EQUATIONS :- (X-y= 10). + ( x+y= 70) 2x = 80 x = 40 . Putting the value of x in any of the equation :- 40-y = 10 -y = 10-40 -y = -30 y = 30

3.

The solution of the equations x - y = 10 and x + y = 70 is --------.A) (40,30) B) (30,40) C) (10,60) D) (50,20)

Answer»

Answer:

A) 40, 30

Step-by-step explanation:

ADDING both EQUATIONS :-

(X-y= 10). + ( x+y= 70)

2x = 80

x = 40 .

Putting the value of x in any of the equation :-

40-y = 10

-y = 10-40

-y = -30

y = 30

Discussion

4.	A both of m 24×2 means that
Answer» Step-by-step EXPLANATION: = 24 × 2 = 48. . . . . . .. . . . . . . . .

4.

A both of m 24×2 means that

Answer»

Step-by-step EXPLANATION:

= 24 × 2

= 48. .

.

..

.

Discussion

5.	The product of a non-zero rational and an irrational number is always.
Answer» ANSWER: The product of any rational number and any IRRATIONAL number will ALWAYS be an irrational number.

5.

The product of a non-zero rational and an irrational number is always.

Answer»

ANSWER:

The product of any rational number and any IRRATIONAL number will ALWAYS be an irrational number.

Discussion

6.	19,63,162,343,? find the next digit
Answer» 19,63,162,344 the ANS

Discussion

7.	ramu, Rohit, Raman and Sohan kisi kam ko 10 12 21 15 din me karte hain. yadi Charo milkar kam shuru Karen Tatha kam shuru hone ke 5 din bad kam Chod deta hai,tatha Sohan kam Khatam hone se 3 din Pahle kam Chod deta hai. ramu Sohan se do din pahle kam Chod deta hai to kam pura hone me kitna Samay lgega
Answer» Wii hairan tuu e mail to the unhe bhi lelo a ana I am back from you soon love to have the same pahan rakhi THI ki photo hai to wo bhi lo que se bat karte hai ki wo to hai hi TUJSE and like this channelhttps to the computer ke question answer f jab Twitter FACEBOOK U id from the heat

Discussion

8.	Divide rs 7000 among A,B and C such that A gets 50% of what B gets and B gets 50% of what C gets.
Answer» Step-by-step EXPLANATION: *HOPE* it HELPS you ☺️☺️☺️

8.

Divide rs 7000 among A,B and C such that A gets 50% of what B gets and B gets 50% of what C gets.

Answer»

Step-by-step EXPLANATION:

HOPE it HELPS you ☺️☺️☺️

Discussion

9.	92b - 8c + 78bc + 8c + 57b ~ ahmer
Answer» ANSWER: $92b + 57b - 8c + 8c + 78bc$ $149b + 78bc$ $b(149 + 78c)$

9.

92b - 8c + 78bc + 8c + 57b ~ ahmer

Answer»

ANSWER:

$92b + 57b - 8c + 8c + 78bc$

$149b + 78bc$

$b(149 + 78c)$

Discussion

10.	If 3n/4 - 5 = 10 then, the value of n will be- option 15,17,23,20
Answer»

Discussion

11.	?1. number series-1.1,6,15,( ),4 5,66,91d) 28a) 25 b) 26 (c) 27
Answer» ANSWER: B 26 Step-by-step explanation: PLEASE MARK me brainliest

11.

?1. number series-1.1,6,15,( ),4 5,66,91d) 28a) 25 b) 26 (c) 27

Answer»

ANSWER:

B 26

Step-by-step explanation:

PLEASE MARK me brainliest

Discussion

12.	-(√2-1)^2pls answer the question
Answer» Step-by-step EXPLANATION: -(√2 -1)^2=-(2+1-2√2) =-3+2√2

12.

-(√2-1)^2pls answer the question

Answer»

Step-by-step EXPLANATION:

-(√2 -1)^2=-(2+1-2√2)

=-3+2√2

Discussion

13.	The mean age 5 children is 11years. if the age of four children is respectively 9,13,10,12years.find the age of fifth child
Answer» 14 YEARS for 5TH child 14 years

13.

The mean age 5 children is 11years. if the age of four children is respectively 9,13,10,12years.find the age of fifth child

Answer»

14 YEARS for 5TH child

14 years

Discussion

14.	Ek village ma 1757 man 244 women h village ma kitn present woman h
Answer» PRESENT WOMEN in VILLAGE are 244

Discussion

15.	Plz give me answers in marathi translation
Answer» Answer: Your input 0.8,1.2,1.6,2 appears to be an arithmetic sequence Find the difference between the members a2-a1=1.2-0.8=0.4 a3-a2=1.6-1.2=0.4 a4-a3=2-1.6=0.4 The difference between every two adjacent members of the series is constant and equal to 0.4 General Form: an=a1+(n-1)d an=0.8+(n-1)0.4 a1=0.8 (this is the 1ST member) an=2 (this is the last/nth member) d=0.4 (this is the difference between consecutive members) n=4 (this is the number of members) Sum of finite series members The sum of the members of a finite arithmetic progression is called an arithmetic series. Using our EXAMPLE, consider the sum: 0.8+1.2+1.6+2 This sum can be found QUICKLY by taking the number n of terms being added (here 4), multiplying by the sum of the first and last number in the progression (here 0.8 + 2 = 2.8), and dividing by 2: n(a1+an)2 4(0.8+2) 2 The sum of the 4 members of this series is 5.6 This series corresponds to the following straight line y=0.4x+0.8 Finding the nthelement a1 =a1+(n-1)d =0.8+(1-1)0.4 =0.8 a2 =a1+(n-1)d =0.8+(2-1)0.4 =1.2 a3 =a1+(n-1)d =0.8+(3-1)0.4 =1.6 a4 =a1+(n-1)d =0.8+(4-1)0.4 =2 a5 =a1+(n-1)d =0.8+(5-1)0.4 =2.4 a6 =a1+(n-1)d =0.8+(6-1)0.4 =2.8 a7 =a1+(n-1)d =0.8+(7-1)0.4 =3.2 a8 =a1+(n-1)d =0.8+(8-1)0.4 =3.6 a9 =a1+(n-1)d =0.8+(9-1)0.4 =4 a10 =a1+(n-1)d =0.8+(10-1)0.4 =4.4 a11 =a1+(n-1)d =0.8+(11-1)0.4 =4.8 a12 =a1+(n-1)d =0.8+(12-1)0.4 =5.2 a13 =a1+(n-1)d =0.8+(13-1)0.4 =5.6 a14 =a1+(n-1)d =0.8+(14-1)0.4 =6 a15 =a1+(n-1)d =0.8+(15-1)0.4 =6.4 a16 =a1+(n-1)d =0.8+(16-1)0.4 =6.8 a17 =a1+(n-1)d =0.8+(17-1)0.4 =7.2 a18 =a1+(n-1)d =0.8+(18-1)0.4 =7.6 a19 =a1+(n-1)d =0.8+(19-1)0.4 =8 a20 =a1+(n-1)d =0.8+(20-1)0.4 =8.4 a21 =a1+(n-1)d =0.8+(21-1)0.4 =8.8 a22 =a1+(n-1)d =0.8+(22-1)0.4 =9.2 a23 =a1+(n-1)d =0.8+(23-1)0.4 =9.6 a24 =a1+(n-1)d =0.8+(24-1)0.4 =10 a25 =a1+(n-1)d =0.8+(25-1)0.4 =10.4 a26 =a1+(n-1)d =0.8+(26-1)0.4 =10.8 a27 =a1+(n-1)d =0.8+(27-1)0.4 =11.2 a28 =a1+(n-1)d =0.8+(28-1)0.4 =11.6 a29 =a1+(n-1)d =0.8+(29-1)0.4 =12 Sorry It's in English don't know to answer in marathi

15.

Plz give me answers in marathi translation

Answer»

Answer:

Your input 0.8,1.2,1.6,2 appears to be an arithmetic sequence

Find the difference between the members

a2-a1=1.2-0.8=0.4

a3-a2=1.6-1.2=0.4

a4-a3=2-1.6=0.4

The difference between every two adjacent members of the series is constant and equal to 0.4

General Form: an=a1+(n-1)d

an=0.8+(n-1)0.4

a1=0.8 (this is the 1ST member)

an=2 (this is the last/nth member)

d=0.4 (this is the difference between consecutive members)

n=4 (this is the number of members)

Sum of finite series members

The sum of the members of a finite arithmetic progression is called an arithmetic series.

Using our EXAMPLE, consider the sum:

0.8+1.2+1.6+2

This sum can be found QUICKLY by taking the number n of terms being added (here 4), multiplying by the sum of the first and last number in the progression (here 0.8 + 2 = 2.8), and dividing by 2:

n(a1+an)2

4(0.8+2)

2

The sum of the 4 members of this series is 5.6

This series corresponds to the following straight line y=0.4x+0.8

Finding the nthelement

a1 =a1+(n-1)*d =0.8+(1-1)*0.4 =0.8

a2 =a1+(n-1)*d =0.8+(2-1)*0.4 =1.2

a3 =a1+(n-1)*d =0.8+(3-1)*0.4 =1.6

a4 =a1+(n-1)*d =0.8+(4-1)*0.4 =2

a5 =a1+(n-1)*d =0.8+(5-1)*0.4 =2.4

a6 =a1+(n-1)*d =0.8+(6-1)*0.4 =2.8

a7 =a1+(n-1)*d =0.8+(7-1)*0.4 =3.2

a8 =a1+(n-1)*d =0.8+(8-1)*0.4 =3.6

a9 =a1+(n-1)*d =0.8+(9-1)*0.4 =4

a10 =a1+(n-1)*d =0.8+(10-1)*0.4 =4.4

a11 =a1+(n-1)*d =0.8+(11-1)*0.4 =4.8

a12 =a1+(n-1)*d =0.8+(12-1)*0.4 =5.2

a13 =a1+(n-1)*d =0.8+(13-1)*0.4 =5.6

a14 =a1+(n-1)*d =0.8+(14-1)*0.4 =6

a15 =a1+(n-1)*d =0.8+(15-1)*0.4 =6.4

a16 =a1+(n-1)*d =0.8+(16-1)*0.4 =6.8

a17 =a1+(n-1)*d =0.8+(17-1)*0.4 =7.2

a18 =a1+(n-1)*d =0.8+(18-1)*0.4 =7.6

a19 =a1+(n-1)*d =0.8+(19-1)*0.4 =8

a20 =a1+(n-1)*d =0.8+(20-1)*0.4 =8.4

a21 =a1+(n-1)*d =0.8+(21-1)*0.4 =8.8

a22 =a1+(n-1)*d =0.8+(22-1)*0.4 =9.2

a23 =a1+(n-1)*d =0.8+(23-1)*0.4 =9.6

a24 =a1+(n-1)*d =0.8+(24-1)*0.4 =10

a25 =a1+(n-1)*d =0.8+(25-1)*0.4 =10.4

a26 =a1+(n-1)*d =0.8+(26-1)*0.4 =10.8

a27 =a1+(n-1)*d =0.8+(27-1)*0.4 =11.2

a28 =a1+(n-1)*d =0.8+(28-1)*0.4 =11.6

a29 =a1+(n-1)*d =0.8+(29-1)*0.4 =12

Sorry It's in English don't know to answer in marathi

Discussion

16.	All the negative integers are ____ than 0
Answer» Answer: $\huge\pink{\underline{\mathcal{HEY}}}$ ALL NEGATIVE INTEGERS ARE LESS THEN 0 HOPE IT HELPS :P

16.

All the negative integers are ____ than 0

Answer»

Answer:

$\huge\pink{\underline{\mathcal{HEY}}}$

ALL NEGATIVE INTEGERS ARE LESS THEN 0

HOPE IT HELPS :P

Discussion

17.	. બાજુની લંબાઈ a, b, c હોય તેવા ત્રિકોણમાં જો a2 + b2 = c2 હોય તો તે ક્યા પ્રકારનો ત્રિકોણહશે ?
Answer» ANSWER: કાટકોણ ત્રિકોણ Step-by-step EXPLANATION: $a ^{2} + \: b^{2} = {c}^{2}$

17.

. બાજુની લંબાઈ a, b, c હોય તેવા ત્રિકોણમાં જો a2 + b2 = c2 હોય તો તે ક્યા પ્રકારનો ત્રિકોણહશે ?

Answer»

ANSWER:

કાટકોણ ત્રિકોણ

Step-by-step EXPLANATION:

$a ^{2} + \: b^{2} = {c}^{2}$

Discussion

18.	Simplify (√5 + √2)^2
Answer» ANSWER: √5+ √2 Step-by-step EXPLANATION:

18.

Simplify (√5 + √2)^2

Answer»

ANSWER: √5+ √2

Step-by-step EXPLANATION:

Discussion

19.	6√2+4 is an irrational with problem
Answer» <P>Step-by-step explanation: let, 6√2+4 is a RATIONAL number 6√2+4=p/q(p and q are co-pime) -4+p/q=6√2 (-4+p/q)/6=√2 HENCE, (-4+p/q) /6 is a rational no. but √2is a IRRATIONAL no. so our assumptions is wrong 6√2+4 is a irrational number

19.

6√2+4 is an irrational with problem

Answer»

<P>Step-by-step explanation:

let, 6√2+4 is a RATIONAL number

6√2+4=p/q(p and q are co-pime)

-4+p/q=6√2

(-4+p/q)/6=√2

HENCE, (-4+p/q) /6 is a rational no.

but √2is a IRRATIONAL no.

so our assumptions is wrong

6√2+4 is a irrational number

Discussion

20.	2,10,84,? number series
Answer» Answer: 2,10,84,1028 Step-by-step explanation: 2,10,84,? 2=1²+1 10=2³+2=8+2 84=3^4+3=81+3 Thus NEXT term =4^5+4=1024+4=1028

20.

2,10,84,? number series

Answer»

Answer:

2,10,84,1028

Step-by-step explanation:

2,10,84,?

2=1²+1

10=2³+2=8+2

84=3^4+3=81+3

Thus NEXT term

=4^5+4=1024+4=1028

Discussion

21.	Divide : 5/10 from (1/2×3/5)
Answer» Answer: 3/5 Step-by-step EXPLANATION: HOPE it HELPS you

21.

Divide : 5/10 from (1/2×3/5)

Answer»

Answer:

3/5

Step-by-step EXPLANATION:

HOPE it HELPS you

Discussion

22.	Q.29. Simplify:- (3-⁵ x 10-⁵ x 125) ÷(5-⁷X6-⁵)
Answer» Step-by-step EXPLANATION: GIVEN 5−7×6−53−5×10−5×125 =35×105125×57×65 =10×10×10×10×10×35125×5×5×5×5×5×5×5×67 =2×2×2×2×2×3×3×3×3×3125×25×6×6×6×6×6×6×6 =125×25×36 =53×52×62 55×62=3125×36 =112500

22.

Q.29. Simplify:- (3-⁵ x 10-⁵ x 125) ÷(5-⁷X6-⁵)

Answer»

Step-by-step EXPLANATION:

GIVEN 5−7×6−53−5×10−5×125

=35×105125×57×65

=10×10×10×10×10×35125×5×5×5×5×5×5×5×67

=2×2×2×2×2×3×3×3×3×3125×25×6×6×6×6×6×6×6

=125×25×36

=53×52×62

55×62=3125×36

=112500

Discussion

23.	Who and where was the television invented?
Answer» Step-by-step explanation: PHILO Farnsworth gave the world's first public demonstration of an all-electronic television system, using a LIVE camera, at the FRANKLIN Institute of PHILADELPHIA on 25 August 1934, and for ten days afterwards. Mexican inventor Guillermo González Camarena also played an important role in early TV.

23.

Who and where was the television invented?

Answer»

Step-by-step explanation:

PHILO Farnsworth gave the world's first public demonstration of an all-electronic television system, using a LIVE camera, at the FRANKLIN Institute of PHILADELPHIA on 25 August 1934, and for ten days afterwards. Mexican inventor Guillermo González Camarena also played an important role in early TV.

Discussion

24.	Guys plz help me I Find the square root of:(2) 576 (3) 3025 (4) 7744 (5) 10404(6) 11664 (7) 15625 (8) 11025 (9) 14641 (10) 9801plz tell me step by step
Answer» ANSWER: I hope it HELPS Step-by-step EXPLANATION: (2) 576!!!!!!!!!

24.

Guys plz help me I Find the square root of:(2) 576 (3) 3025 (4) 7744 (5) 10404(6) 11664 (7) 15625 (8) 11025 (9) 14641 (10) 9801plz tell me step by step

Answer»

ANSWER:

I hope it HELPS

Step-by-step EXPLANATION:

(2) 576!!!!!!!!!

Discussion

25.	(y²+16)² + b²= 8y²explain
Answer» Step-by-step EXPLANATION: I THIK its helpful for U. if the ANS. is wrong forgive me.

25.

(y²+16)² + b²= 8y²explain

Answer»

Step-by-step EXPLANATION:

I THIK its helpful for U. if the ANS. is wrong forgive me.

Discussion

26.	Find the solution of the equation 2(5t - 3) - 4= 20.
Answer» Answer: 2(5t - 3) - 4 = 20 ⇒ 10T - 6 - 4 = 20 ⇒ 10t - 10 = 20 ⇒ 10t = 20 + 10 ⇒ 10t = 30 ⇒ t = 30 ÷ 10 ⇒ t = 3

26.

Find the solution of the equation 2(5t - 3) - 4= 20.

Answer»

Answer:

2(5t - 3) - 4 = 20

⇒ 10T - 6 - 4 = 20

⇒ 10t - 10 = 20

⇒ 10t = 20 + 10

⇒ 10t = 30

⇒ t = 30 ÷ 10

⇒ t = 3

Discussion

27.	Give me a answer in english
Answer» <P>p(X) =kx²-10x+3 p(3) =k(3) ²-10(3) +3 =9K-30+3 =0 = 9k-27=0 = 9k = 27 =k =27/9 =k=3 Here is your answer (✿❛◡❛)

27.

Give me a answer in english

Answer»

<P>p(X) =kx²-10x+3

p(3) =k(3) ²-10(3) +3

=9K-30+3 =0

= 9k-27=0

= 9k = 27

=k =27/9

=k=3

Here is your answer (✿❛◡❛)

Discussion

28.	The sum of n term of an AP is 7n square -2n. find the A.P hence find its 10th term ?
Answer» ANSWER: THUS , the 10TH term is 102 :)Like if correct :) More Step-by-step explanation: Mark me as BRANLIEST

28.

The sum of n term of an AP is 7n square -2n. find the A.P hence find its 10th term ?

Answer»

ANSWER:

THUS , the 10TH term is 102 :)Like if correct :)

More

Step-by-step explanation:

Mark me as BRANLIEST

Discussion

29.	जाँच कीजिए कि निम्न समीकरण युग्म संगत है या असंगत।2x+3y=7x+2y=3
Answer» ANSWER: jekwnsjskownsis Step-by-step EXPLANATION: iei2iebdksn dowidbbebd d

29.

जाँच कीजिए कि निम्न समीकरण युग्म संगत है या असंगत।2x+3y=7x+2y=3

Answer»

ANSWER:

jekwnsjskownsis

Step-by-step EXPLANATION:

iei2iebdksn dowidbbebd d

Discussion

30.	:. यदि u= sin^x/y + tan^y/x तो दर्शाइये कि x du/dx + y du/dy
Answer» ANSWER: From which SUBJECT question Hindi or Math? I am REALLY CONFUSED

30.

:. यदि u= sin^x/y + tan^y/x तो दर्शाइये कि x du/dx + y du/dy

Answer»

ANSWER:

From which SUBJECT question Hindi or Math? I am REALLY CONFUSED

Discussion

31.	first time and the sum of infinite gp 2 and 3 respectively find the common ratio and sum upon and n term
Answer» ANSWER: hhhahwgwhwhehheheheh

31.

first time and the sum of infinite gp 2 and 3 respectively find the common ratio and sum upon and n term

Answer»

ANSWER:

hhhahwgwhwhehheheheh

Discussion

32.	Simplify (6^2*6^4)÷6^3
Answer» ANSWER: SEE the attachment Step-by-step EXPLANATION: HOPE it helps

32.

Simplify (6^2*6^4)÷6^3

Answer»

ANSWER:

SEE the attachment

Step-by-step EXPLANATION:

HOPE it helps

Discussion

33.	two children said one child four children said 2 child 12 children said 3 child calculate the mean of number of children per family
Answer» Answer: In a family with 2 CHILDREN there are four possibilities: 1) the first child is a boy and the SECOND child is a boy (bb) 2) the first child is a boy and the second child is a girl (bg) 3) the first child is a girl and the second child is a boy (gb) 4) the first child is a girl and the second child is a girl (gg) Since we are given that at least one child is a girl there are THREE possibilities: bg, gb, or gg. Out of those three possibilities the only one with two girls is gg. Hence the probability is 13. Step-by-step explanation: I think this question CONFUSES a lot of people because there's a lack of intuitive context -- I'll try to supply that. Suppose there is a birthday party to which all of the girls (and none of the boys) in a small town are invited. If you run into a mother who has dropped off a kid at this birthday party and who has two children, the chance that she has two girls is 1/3. Why? 3/4 of the mothers with two children will have a DAUGHTER at the birthday party, the ones with two girls (1/4 of the total mothers with two children) and the ones with one girl and one boy (1/2 of the total mothers with two children). Out of these 3/4 of the mothers, 1/3 have two girls. On the other hand, if the birthday party is only for fifth-grade girls, you get a different answer. Assuming there are no siblings who are both in the fifth grade, the answer in this case is 1/2. The child in fifth grade is a girl, but the other child has probability 1/2 of being a girl. Situations of this kind arise in real life much more commonly than situations of the other kind, so the answer of 1/3 is quite nonintuitive.

33.

two children said one child four children said 2 child 12 children said 3 child calculate the mean of number of children per family

Answer»

Answer:

In a family with 2 CHILDREN there are four possibilities:

1) the first child is a boy and the SECOND child is a boy (bb)

2) the first child is a boy and the second child is a girl (bg)

3) the first child is a girl and the second child is a boy (gb)

4) the first child is a girl and the second child is a girl (gg)

Since we are given that at least one child is a girl there are THREE possibilities: bg, gb, or gg. Out of those three possibilities the only one with two girls is gg. Hence the probability is 13.

Step-by-step explanation:

I think this question CONFUSES a lot of people because there's a lack of intuitive context -- I'll try to supply that.

Suppose there is a birthday party to which all of the girls (and none of the boys) in a small town are invited. If you run into a mother who has dropped off a kid at this birthday party and who has two children, the chance that she has two girls is 1/3. Why? 3/4 of the mothers with two children will have a DAUGHTER at the birthday party, the ones with two girls (1/4 of the total mothers with two children) and the ones with one girl and one boy (1/2 of the total mothers with two children). Out of these 3/4 of the mothers, 1/3 have two girls.

On the other hand, if the birthday party is only for fifth-grade girls, you get a different answer. Assuming there are no siblings who are both in the fifth grade, the answer in this case is 1/2. The child in fifth grade is a girl, but the other child has probability 1/2 of being a girl. Situations of this kind arise in real life much more commonly than situations of the other kind, so the answer of 1/3 is quite nonintuitive.

Discussion

34.	(c) Write the given rational numbers in ascending order ?2/6, -4/12, -9/-27, -5/18
Answer» ANSWER: -9/27,-5/18,-4/12,2/6. Step-by-step explanation: 2/6=0.33 -4/12= - 0.25 -9/27 = -0.33 -5/18= -0.311 -0.33,-0.311,-0.25,0.33 -9/27,-5/18,-4/12, 2/6

34.

(c) Write the given rational numbers in ascending order ?2/6, -4/12, -9/-27, -5/18

Answer»

ANSWER:

-9/27,-5/18,-4/12,2/6.

Step-by-step explanation:

2/6=0.33

-4/12= - 0.25

-9/27 = -0.33

-5/18= -0.311

-0.33,-0.311,-0.25,0.33

-9/27,-5/18,-4/12, 2/6

Discussion

35.	find the smallest number by which of the following numbers must be multiplied to obtain a perfect cube 1)256
Answer» Answer: 2×2×2×2×2×2×2×2 = 256 hope it HELP you

35.

find the smallest number by which of the following numbers must be multiplied to obtain a perfect cube 1)256

Answer»

Answer:

2×2×2×2×2×2×2×2 = 256

hope it HELP you

Discussion

36.	प्रतिज्ञा गिफ्ट एंड मेड अप ऑफ सम सेमी सर्किल हाउ मेनी सेमी सर्किल कैन बी मेड फ्रॉम दम
Answer» PLEASE WRITE in ENGLISH

36.

प्रतिज्ञा गिफ्ट एंड मेड अप ऑफ सम सेमी सर्किल हाउ मेनी सेमी सर्किल कैन बी मेड फ्रॉम दम

Answer»

PLEASE WRITE in ENGLISH

Discussion

37.	Please answer fast it's important for me
Answer» ANSWER: SEE and in the FORM of IMAGE.

37.

Please answer fast it's important for me

Answer»

ANSWER:

SEE and in the FORM of IMAGE.

Discussion

38.	जांच कीजिए कि नियमित समीकरण युग्म संगत है या aसंगत 2x+3y=7 x+2y=3
Answer» ANSWER: it is RONG the CORRECT answer is GIVEN in STEP by step Step-by-step explanation: 2x+3y=3 2x+y=3/3=1 x+y=1/2

38.

जांच कीजिए कि नियमित समीकरण युग्म संगत है या aसंगत 2x+3y=7 x+2y=3

Answer»

ANSWER:

it is RONG the CORRECT answer is GIVEN in STEP by step

Step-by-step explanation:

2x+3y=3

2x+y=3/3=1

x+y=1/2

Discussion

39.	Which of the following sequences represents an arithmetic sequence?-7, -4, 1, 4, ...2, -4, 8, -16, ...1, 4, 9, 16, ...-5, -3, -1, 1, ...
Answer» Answer: d) -5,-3,-1,1,... represents an ARITHMETIC progression

39.

Which of the following sequences represents an arithmetic sequence?-7, -4, 1, 4, ...2, -4, 8, -16, ...1, 4, 9, 16, ...-5, -3, -1, 1, ...

Answer»

Answer:

d) -5,-3,-1,1,...

represents an ARITHMETIC progression

Discussion

40.	Convert 1% into decimal from
Answer» ANSWER: 0.01 Step-by-step explanation: 1%= 1/100 0.01 is the answer PLEASE MAKE me BRAINLIEST

40.

Convert 1% into decimal from

Answer»

ANSWER:

0.01

Step-by-step explanation:

1%= 1/100

0.01 is the answer

PLEASE MAKE me BRAINLIEST

Discussion

41.	0.15 (5x-2)=0.4 (x+1)
Answer» Answer: 2 Step-by-step explanation: 0.15 × 5X - 0.15 × 2 = 0.4 × X + 0.4 × 1 0.75x - 0.3 = 0.4x + 0.4 0.75x - 0.4x = 0.4 + 0.3 0.35x = 0.7 x = 0.7/0.35 = 70/35 = 2

41.

0.15 (5x-2)=0.4 (x+1)

Answer»

Answer:

2

Step-by-step explanation:

0.15 × 5X - 0.15 × 2 = 0.4 × X + 0.4 × 1

0.75x - 0.3 = 0.4x + 0.4

0.75x - 0.4x = 0.4 + 0.3

0.35x = 0.7

x = 0.7/0.35 = 70/35 = 2

Discussion

42.	2. Find the area of a rectangular plot, one side of which is 48 m and its diagonal is 50 m.
Answer» ANSWER: Your answer is up here HOPE it HELPS :)

42.

2. Find the area of a rectangular plot, one side of which is 48 m and its diagonal is 50 m.

Answer»

ANSWER:

Your answer is up here

HOPE it HELPS :)

Discussion

43.	Jee QuestionIfShow that
Answer» Consider the RHS. $\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\left(4^{n+4}-\sum_{t=0}^3\,^{n+4}C_t\,3^t\right)$ We KNOW that, $\longrightarrow (1+x)^n=\,^n\!C_0+\,^n\!C_1\,x+\,^n\!C_2\,x^2+\,^n\!C_3\,x^3+\,\dots\,+\,^n\!C_n\,x^n$ or, $\displaystyle\longrightarrow (1+x)^n=\sum_{t=0}^n\,^n\!C_t\,x^t$ TAKING $x=3$ and replacing $n$ by $n+4$ we get, $\displaystyle\longrightarrow4^{n+4}=\sum_{t=0}^{n+4}\,^{n+4}C_t\,3^t$ Then our sum becomes, $\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\left(\sum_{t=0}^{n+4}\,^{n+4}C_t\,3^t-\sum_{t=0}^3\,^{n+4}C_t\,3^t\right)$ $\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\sum_{t=4}^{n+4}\,^{n+4}C_t\,3^t$ PUT, $r=t-4$ $t=r+4$ $t=4\quad\implies\quad r=0$ $t=n+4\quad\implies\quad r=n$ Then our sum becomes, $\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\sum_{r=0}^n\,^{n+4}C_{r+4}\,3^{r+4}$ Taking $^{n+4}C_{r+4}=\dfrac{(n+4)!}{(r+4)(n-r)!},$ $\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\sum_{r=0}^n\dfrac{(n+4)!}{(r+4)!(n-r)!}\,3^{r+4}$ Take, $(n+4)!=n!(n+1)(n+2)(n+3)(n+4)$ $(r+4)!=r!(r+1)(r+2)(r+3)(r+4)$ Then, $\displaystyle\footnotesize\text{$\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\sum_{r=0}^n\dfrac{n!(n+1)(n+2)(n+3)(n+4)}{r!(r+1)(r+2)(r+3)(r+4)(n-r)!}\,3^{r+4}$}$ $\displaystyle\footnotesize\text{$\longrightarrow S=\dfrac{(n+1)(n+2)(n+3)(n+4)}{(n+1)(n+2)(n+3)(n+4)}\sum_{r=0}^n\dfrac{n!}{r!(r+1)(r+2)(r+3)(r+4)(n-r)!}\,3^{r+4}$}$ $\displaystyle\longrightarrow S=\sum_{r=0}^n\dfrac{n!}{r!(r+1)(r+2)(r+3)(r+4)(n-r)!}\,3^{r+4}$ $\displaystyle\longrightarrow S=\sum_{r=0}^n\dfrac{1}{(r+1)(r+2)(r+3)(r+4)}\cdot\dfrac{n!}{r!(n-r)!}\,3^{r+4}$ $\displaystyle\longrightarrow S=\sum_{r=0}^n\dfrac{1}{(r+1)(r+2)(r+3)(r+4)}\cdot\,^nC_r\,3^{r+4}$ Taking $^nC_r=C_r$ we get the LHS. $\displaystyle\longrightarrow S=\sum_{r=0}^n\dfrac{C_r\,3^{r+4}}{(r+1)(r+2)(r+3)(r+4)}$ Hence PROVED!

43.

Jee QuestionIfShow that

Answer»

Consider the RHS.

$\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\left(4^{n+4}-\sum_{t=0}^3\,^{n+4}C_t\,3^t\right)$

We KNOW that,

$\longrightarrow (1+x)^n=\,^n\!C_0+\,^n\!C_1\,x+\,^n\!C_2\,x^2+\,^n\!C_3\,x^3+\,\dots\,+\,^n\!C_n\,x^n$

or,

$\displaystyle\longrightarrow (1+x)^n=\sum_{t=0}^n\,^n\!C_t\,x^t$

TAKING $x=3$ and replacing $n$ by $n+4$ we get,

$\displaystyle\longrightarrow4^{n+4}=\sum_{t=0}^{n+4}\,^{n+4}C_t\,3^t$

Then our sum becomes,

$\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\left(\sum_{t=0}^{n+4}\,^{n+4}C_t\,3^t-\sum_{t=0}^3\,^{n+4}C_t\,3^t\right)$

$\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\sum_{t=4}^{n+4}\,^{n+4}C_t\,3^t$

PUT,

$r=t-4$

$t=r+4$

$t=4\quad\implies\quad r=0$

$t=n+4\quad\implies\quad r=n$

Then our sum becomes,

$\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\sum_{r=0}^n\,^{n+4}C_{r+4}\,3^{r+4}$

Taking $^{n+4}C_{r+4}=\dfrac{(n+4)!}{(r+4)(n-r)!},$

$\displaystyle\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\sum_{r=0}^n\dfrac{(n+4)!}{(r+4)!(n-r)!}\,3^{r+4}$

Take,

$(n+4)!=n!(n+1)(n+2)(n+3)(n+4)$

$(r+4)!=r!(r+1)(r+2)(r+3)(r+4)$

Then,

$\displaystyle\footnotesize\text{$\longrightarrow S=\dfrac{1}{(n+1)(n+2)(n+3)(n+4)}\sum_{r=0}^n\dfrac{n!(n+1)(n+2)(n+3)(n+4)}{r!(r+1)(r+2)(r+3)(r+4)(n-r)!}\,3^{r+4}$}$

$\displaystyle\footnotesize\text{$\longrightarrow S=\dfrac{(n+1)(n+2)(n+3)(n+4)}{(n+1)(n+2)(n+3)(n+4)}\sum_{r=0}^n\dfrac{n!}{r!(r+1)(r+2)(r+3)(r+4)(n-r)!}\,3^{r+4}$}$

$\displaystyle\longrightarrow S=\sum_{r=0}^n\dfrac{n!}{r!(r+1)(r+2)(r+3)(r+4)(n-r)!}\,3^{r+4}$

$\displaystyle\longrightarrow S=\sum_{r=0}^n\dfrac{1}{(r+1)(r+2)(r+3)(r+4)}\cdot\dfrac{n!}{r!(n-r)!}\,3^{r+4}$

$\displaystyle\longrightarrow S=\sum_{r=0}^n\dfrac{1}{(r+1)(r+2)(r+3)(r+4)}\cdot\,^nC_r\,3^{r+4}$

Taking $^nC_r=C_r$ we get the LHS.

$\displaystyle\longrightarrow S=\sum_{r=0}^n\dfrac{C_r\,3^{r+4}}{(r+1)(r+2)(r+3)(r+4)}$

Hence PROVED!

Discussion

44.	find the perimeter of triangle with given sides a ) 3x³ + 7x , 3x -4 and x³ - 6x B ) 3x⁴ + 4x , 3x -4 and x⁴ - 3x
Answer» 7x,3X-4 and x™ -6x B) 3x + 4X , 3x - 4 and x4 - 3x

Discussion

45.	Change 5 by 3 in the form of 1 hr 40 min
Answer» Answer: 1. CONVERT 45 minutes into hours. We KNOW, 60 minutes = 1 hour or, 1 minute = 1/60 hour Therefore, 45 minutes = 45/60 hour = ¾ hour. 2. Convert 25 minutes into hours. We know, 60 minutes = 1 hour or, 1 minute = 1/60 hour Therefore, 25 minutes = 25/60 hour = 5/12 hour.

45.

Change 5 by 3 in the form of 1 hr 40 min

Answer»

Answer:

1. CONVERT 45 minutes into hours.

We KNOW, 60 minutes = 1 hour

or, 1 minute = 1/60 hour

Therefore, 45 minutes = 45/60 hour = ¾ hour.

2. Convert 25 minutes into hours.

We know, 60 minutes = 1 hour

or, 1 minute = 1/60 hour

Therefore, 25 minutes = 25/60 hour = 5/12 hour.

Discussion

46.	6√2+4 is an irrational
Answer» ANSWER: YES it is IRRATIONAL

46.

6√2+4 is an irrational

Answer»

ANSWER:

YES it is IRRATIONAL

Discussion

47.	Find the least number of six digits which is a perfect square. Also, find itssquare root.TAလူမှုရန်
Answer» Answer: 100489 is your answer please MARK as BRAINLIEST

47.

Find the least number of six digits which is a perfect square. Also, find itssquare root.TAလူမှုရန်

Answer»

Answer:

100489 is your answer

please MARK as BRAINLIEST

Discussion

48.	The 17th term of an ap exceeds its 10th term by 7 find the common difference
Answer» ANSWER: GIVEN, a₁₇ = a₁₀ + 7 → a + (17 - 1)d = a + (10 - 1)d + 7 → 16d = 9d + 7 → 7d = 7 → d = 7 ÷ 7 → d = 1 Therefore, the common DIFFERENCE is 1.

48.

The 17th term of an ap exceeds its 10th term by 7 find the common difference

Answer»

ANSWER:

GIVEN,

a₁₇ = a₁₀ + 7

→ a + (17 - 1)d = a + (10 - 1)d + 7

→ 16d = 9d + 7

→ 7d = 7

→ d = 7 ÷ 7

→ d = 1

Therefore, the common DIFFERENCE is 1.

Discussion

49.	The graph respersented by a picture is know as ___________
Answer» ANSWER: PICTOGRAPHS hhhhhhhhhhhhh

49.

The graph respersented by a picture is know as ___________

Answer»

ANSWER:

PICTOGRAPHS

hhhhhhhhhhhhh

Discussion

50.	Forest in jammu and kashmir and tamil nadu bar graph
Answer» ANSWER: mountain FOREST Step-by-step explanation: IN J AND K only mountain forest are FOUNDED

50.

Forest in jammu and kashmir and tamil nadu bar graph

Answer»

ANSWER:

mountain FOREST

Step-by-step explanation:

IN J AND K only mountain forest are FOUNDED

Discussion

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Please answer fast it's important for me

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