1.

The 17th term of an ap exceeds its 10th term by 7 find the common difference​

Answer»

ANSWER:

GIVEN,

a₁₇ = a₁₀ + 7

→ a + (17 - 1)d = a + (10 - 1)d + 7

→ 16d = 9d + 7

→ 7d = 7

→ d = 7 ÷ 7

→ d = 1

Therefore, the common DIFFERENCE is 1.



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