332354 + Interview Questions in Secondary School in Math

1.	Evaluate3log10-½log4+log 25
Answer» Log10^3-log√4+log25 log1000-log2+log25 log500+log25 log5+log100+2log5 3log5+2

Discussion

2.	On 8th feb. 2005 it was tuesday. what was the day of the week on 08th feb. 2004?
Answer» Dear FRIEND , it was MONDAY on 8TH feb 2004

Discussion

3.	Ellipse of e = 2/3 incrible in a circle and point within a circle is chosen find the probability
Answer» The ANSWER is 1/√3 PLEASE CHECK I HOPE it HELPS

Discussion

4.	Use number line to evaluate the following (1) -5+(-3), (2) 4-(-4)
Answer» 1) -5-3= -8 2) 4+4=8 I THINK it is HELP you

Discussion

5.	Eigenvalues of positive definite matrix using cholesky decomposition
Answer» PLS we REALLY not ABLE to GET U

Discussion

6.	The mean of 25 observations is 20 if each observation is subtracted by 3 then find the new mean
Answer» No of observations = 25 mean = 20 sum of observations = mean * no of observations = 25*20 = 500 if three is subracted = 500 - 3= 497 no of observations after EXCLUDING = 19 new mean = sum of observations / no of observations mean = 497 / 19= 26.157

Discussion

7.	If P (5,r) = 2 X P(6, r-1) find r
Answer» Hi...☺ Here is your ANSWER....✌ GIVEN THAT, ${} ^{<klux>5</klux>}P_{r} = 2 \times {}^{6}P_{r - 1} \\ \\ = > \frac{5!}{(5 - r)!} = 2 \times \frac{6!}{(6 - (r - 1))!} \\ \\ \frac{5!}{(5 - r)!} = 2 \times \frac{6\times 5!}{(6 - r + 1)!} \\ \\ \frac{1}{(5 - r)!} = 2 \times \frac{6}{(7 - r)!} \\ \\ \frac{1}{(5 - r)!} = \frac{12}{(7 - r) \times (6 - r) \times (5 - r)!} \\ \\ 1 = \frac{12}{(7 - r) \times (6 - r) } \\ \\ (7 - r)(6 - r) = 12 \\ \\ 42 - 13r + r {}^{2} = 12 \\ \\ {r}^{2} - 13r + 30 = 0 \\ \\ {r}^{2} - 10r - 3r + 30 = 0 \\ \\ {r}(r - 10) - 3(r - 10) = 0 \\ \\ (r - 3)(r - 10) = 0 \\ \\ = > r = 3 \: \: or \: \: r = 10 \\ \\ => r = 3$ SINCE, Value of r can't be GREATER than 5 [ As we know r ≤ n ] HENCE, r = 3

Discussion

8.	Solve this problem you are brainy
Answer» ANSWER is 12 . PLS MARK this answer as BRAINLEAST

Discussion

9.	Name the successor of the greatest 3 digit number
Answer» The GREATEST 3 digit NUMBER is 999. The SUCCESSOR of 999 is 1000.

Discussion

10.	If 2a = 3b = 4c = 5d, then find a:b:c:d.
Answer» .....FRIEND the ANSWER is above...

Discussion

11.	Please solve fast and no spam please ans 15 question..
Answer» HOPE OT HELPS...........

Discussion

12.	Answerrrrr............bolo abb sbhi ki answer
Answer» Kyah... SAREE QUES BTAYE...??!!!

Discussion

13.	Find the median of 30 5 2 22 14 26 10
Answer» Median = (N + 1) / 2 = (7 +1) / 2 = 8 / 2 = 4 Hence 4th term 22 is the median. Thanks

Discussion

14.	Please answer fast and no spam ans please solve 14 question..
Answer» SORRY i DONT KNOW the ANSWERS

Discussion

15.	Give example of R is not transitive
Answer» I DONT KNOW so SORRY

Discussion

16.	Give answer dear..........
Answer» I THINK it is COMPLEX SALT

Discussion

17.	(4 root3 + 5 root2) / ( root48 + root18)
Answer» ____________________________________ (4√3+5√2)/(√48+√18) =[4√3++5√2] [4√3-3√2] /[4√3+3√2] [4√3-3√2] =[48-12√6+20√6-30] / [48-12√6+12√6-18] =[18+8√6] / 30 =[9+4√6]/15 ____________________________________

Discussion

18.	Name of publishers of eco. book of 1 of statics part
Answer» Publish the BOOK, Market it From the Best Publishing Company in INDIA now. 24/7 customer SERVICE. Book fairs and Lit FESTS. Comprehensive Markeing. Book Publisher In India \| Search Book Publisher In India \| zapmeta.co.in Adwww.zapmeta.co.in/Search Find Book Publisher In India. Search Faster, Better & Smarter at ZapMeta Now! The COMPLETE Overview. 100+ Million Visitors. Wiki, News & More. Web, Images & Video.

Discussion

19.	How we find circumcentre of triangle if angle are given?
Answer» Bhai if only three ANGLES are given of a triangle then there are infinite number of such possible triangles(similar) and HENCE there are many circumcentre, you must ALSO give one side so that the triangle can be fixed and also the circumcentre. Below I have given an IMAGE to SHOW that if only three angles are given and there are two different triangles and hence two different circumcentre The number of triangles can be increased by same logic

Discussion

20.	Naimish borrows rs 40000 from bank at rate of 7.50% per annum at compound interest for 3 years .at end of every year he pays rs 15000 which consist of interest and a part of loan payment . how much extra he has to pay at the end of third year to finish his loan maths solution?
Answer» PRINCIPLE AMOUNT = 40000 time = 3 rate of INTEREST = 7.5% amount = P ( 1+r/100)^n 40000(1 + 7.5/100)^3 40000 ( 1+ 0.075) ^3 40000(1.075)^3 40000 * 1.075 * 1.075 * 1.075 = 49691.875 thanks

Discussion

21.	Hybrid scheme for partial differential equations
Answer» I DONT know the ANSWER sorry bro it is very TOUGH

Discussion

22.	Find the value of 56 raise to 1/2.
Answer» Dont be confuse .... if power of any number is 1/2 it means you have to find its square root and if it is 1/ 3 then you have to find cube root of RESPECTIVE number

Discussion

23.	Give. me ........ answer bro
Answer» Hi dear here is ur ANSWER ✌✌ D ) {10} i HOPE it helps U buddy ✌✌

Discussion

24.	The weight of 6m long iron rod is 18kg. Find the length of the iron rod if its weight is 27kg?
Answer» THEREFORE the LENGTH of the rod when it's weight is 27KG is 9cm

Discussion

25.	Find the correct answer
Answer» I THINK so it's ANS should be(d) 1

Discussion

26.	A&B can do a piece of wprk in 6days&12days .find the time required to do it together?
Answer» TIME REQUIRED to COMPLETE it together--------------------------------------------------------------- 1/6+1/12-------------- =======1/4 So. they will do it together in 4 days.

Discussion

27.	What is the ans 5000/5 ( 567* 2)
Answer» 1134000 is the ANSWER...........

Discussion

28.	Square root of 245upto2 decimaL place inking division method
Answer» 15.65...........................

Discussion

29.	Solve: x square -5modx+6=0
Answer» EITHER X EQUALS 6 or 7/5

Discussion

30.	The additive inverse of a number divided by 12 is same as one less than 3 times its reciprocal. Find the number??
Answer» Hii dear dost!! here ur ANSWER!! _______________ ▪ Let the number be x. And it's additive inverse will be -x Now dividing it by 12 that is -x/12. Now one less than three times it RECIPROCAL is 3/x -1. As they both are equal X /12 = 1 - 3/x. X/12 = x -3/x. X^2 = 12x - 36. X^2 - 12x + 36 = 0. Therefore ( x -6 )^2 = 0. And hence x - 6 = 0. And x = 0 #hope HELP u ☺☺ plz mark brainlist # ______________________________

Discussion

31.	How to find the angle between two lines given their slopes?
Answer» USE this FORMULA U will GET an ANSWER.

Discussion

32.	How to find smallest and largest no. by l.c.m and h.c.f?
Answer» Hcf means highest COMMON FACTOR so largest L. C. M means L osest common factor so smallest

Discussion

33.	How to find sum of a number as two consecutive prime number?
Answer» Hii dear!! here ur answer!! _______________ >><<▪Let denote the sum of the n-th, (n+1)-th, (n+2)-th, and (n+3)-th prime NUMBERS. One can check that this function INCREASES monotonically. Therefore, if for some k, then x is not a sum of FOUR concecutive primes. >><< #hopr help u plz mrak brainlist☺ __________________________

Discussion

34.	In how many ways can the letters of MAHABHARAT be arranged so that i) B and T are never together ii) M, A, T, H occurs at first four places.
Answer» Here is your ANSWER PLEASE CHECK I HOPE it HELPS

Discussion

35.	Express the following numbers as the sum of two odd primes 42 and 98 Express the following numbers as the sum of two odd primes 42 and 98
Answer» Answer: $42 = 19+<klux>23</klux>$ $98= 19+79$ Step-by-step explanation: Given : NUMBERS 42 and 98. To find : Express the following numbers as the SUM of two odd primes 42 and 98 ? Solution : First of all we write all the prime numbers that lie between 1 and 98. 2, 3 ,5 ,7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83,89,97. Except 2 rest all are odd prime numbers. So, From the list we have to figure out two odd prime numbers whose sum is 42 and 98. $42 = 19+23$ $98= 19+79$

35.

Express the following numbers as the sum of two odd primes 42 and 98 Express the following numbers as the sum of two odd primes 42 and 98

Answer»

Answer:

$42 = 19+<klux>23</klux>$

$98= 19+79$

Step-by-step explanation:

Given : NUMBERS 42 and 98.

To find : Express the following numbers as the SUM of two odd primes 42 and 98 ?

Solution :

First of all we write all the prime numbers that lie between 1 and 98.

2, 3 ,5 ,7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83,89,97.

Except 2 rest all are odd prime numbers.

So, From the list we have to figure out two odd prime numbers whose sum is 42 and 98.

$42 = 19+23$

$98= 19+79$

Discussion

36.	2 metallic right circular cones having their height 4.1cm and 4.3cm respectively and the radii of their bases 2.1cm each have been melting together and recasted into a shpere determine the diameter of the sphere so formed
Answer» The diameter of the SPHERE so formed is 6.66 CM Step-by-step explanation: Cone 1 : HEIGHT of cone = 4.1 cm Radius of cone = 2.1 cm Volume of cone = $\frac{1}{3} \pi r^2 h =\frac{1}{3} \times \frac{22}{7} \times 2.1^2 \times 4.1 =18.942 cm^3$ Cone 2 : Height of cone = 4.3 cm Radius of cone = 2.1 cm Volume of cone = $\frac{1}{3} \times \frac{22}{7} \times 2.1^2 \times 4.3 =19.866 cm^3$ Volume of sphere = $\frac{4}{3} \pi r^3 =\frac{4}{3} \times \frac{22}{7} \times r^3$ Two CONES are melted to form sphere So, volume of two cones will be equal to the volume of sphere So, $\frac{1}{3} \times \frac{22}{7} \times 2.1^2 \times 4.1 +\frac{1}{3} \times \frac{22}{7} \times 2.1^2 \times 4.3 =\frac{4}{3} \times \frac{22}{7} \times r^3\\\\ 2.1^2 \times 4.1 + 2.1^2 \times 4.3 =r^3\\\\ \sqrt[3]{2.1^2 \times 4.1 + 2.1^2 \times 4.3 }=r\\\\3.33=r$ So, radius of sphere = 3.33 cm Diameter of sphere = $3.33 \times 2 = 6.66$ HENCE the diameter of the sphere so formed is 6.66 cm #Learn more : 2 metallic circular cones having their heights 4.1 cm and 4.3 cm and the radii of their bases 21 cm each have been melted together and recast into a sphere. Find the diameter of the sphere. brainly.in/question/2487748

36.

2 metallic right circular cones having their height 4.1cm and 4.3cm respectively and the radii of their bases 2.1cm each have been melting together and recasted into a shpere determine the diameter of the sphere so formed

Answer»

The diameter of the SPHERE so formed is 6.66 CM

Step-by-step explanation:

Cone 1 :

HEIGHT of cone = 4.1 cm

Radius of cone = 2.1 cm

Volume of cone = $\frac{1}{3} \pi r^2 h =\frac{1}{3} \times \frac{22}{7} \times 2.1^2 \times 4.1 =18.942 cm^3$

Cone 2 :

Height of cone = 4.3 cm

Radius of cone = 2.1 cm

Volume of cone = $\frac{1}{3} \times \frac{22}{7} \times 2.1^2 \times 4.3 =19.866 cm^3$

Volume of sphere = $\frac{4}{3} \pi r^3 =\frac{4}{3} \times \frac{22}{7} \times r^3$

Two CONES are melted to form sphere

So, volume of two cones will be equal to the volume of sphere

So, $\frac{1}{3} \times \frac{22}{7} \times 2.1^2 \times 4.1 +\frac{1}{3} \times \frac{22}{7} \times 2.1^2 \times 4.3 =\frac{4}{3} \times \frac{22}{7} \times r^3\\\\ 2.1^2 \times 4.1 + 2.1^2 \times 4.3 =r^3\\\\ \sqrt[3]{2.1^2 \times 4.1 + 2.1^2 \times 4.3 }=r\\\\3.33=r$

So, radius of sphere = 3.33 cm

Diameter of sphere = $3.33 \times 2 = 6.66$

HENCE the diameter of the sphere so formed is 6.66 cm

#Learn more :

2 metallic circular cones having their heights 4.1 cm and 4.3 cm and the radii of their bases 21 cm each have been melted together and recast into a sphere. Find the diameter of the sphere.

brainly.in/question/2487748

Discussion

37.	Simplify the rationalizing denominator of 1/2√7-√5
Answer» I HOPE it HELPS U........☺️☺️☺️ Thank You..................✌️✌️✌️

Discussion

38.	3-3-3-3+4+4+4+-38-x=386/7
Answer» HEY MATE.... Here's ur ans.⬇ 0 - 0 + 12-38 -X = 386/7 -26 - x = 386/7 - x = 386/7 + 26 - x = {386 +26 ×7} ÷ 7 -x ={ 386 + 182} ÷ 7 -x = 568/7 x = -586/7 ✌Hope it HELPS

Discussion

39.	Plz help me to find out no.17
Answer» I THINK this could be the SOLUTION ofyour QUESTION......CHECK it

Discussion

40.	If 5sinA+3cosA=4 find the value of 3sinA-5cosA
Answer» 5 Sin A+ 3COS A= 4 ----> eq 1 3 Sin A- 5 Cos A = x -----> eq 2 squaring and adding both the equations: (5 sin A+3 cos A)²+ (3SIN A-5Cos A)² = 4²+x² 25 sin²A+ 2×3×5 SinA cos A+ 9cos²A + 9²sinA - 2×3×5 sinA cos A + 25 Cos²A = 4² + x² rearranging : 25 sin ²A + 25Cos²A+9 sin²A +9cos²A+30 sinAcosA-30SinAcosA= 16+x² (since sin²A+cos²A = 1) 25+9 = 16+x² x² = 34 x =4.242

Discussion

41.	A sector of a circlr of radius 12cm has the angle 150 degree.It is rolled up so that two bounding radii are joined together to form a cone.The height of the cone is
Answer» I think something is wrong in the QUESTION since we have to FIND slant HEIGHT not the height and I am GETTING this as my answer..

Discussion

42.	How to calculate total distace when speeds are given?
Answer» S=ut +1/2 at^2 Where s=distance

Discussion

43.	Does rhombus have longer diagonals than square
Answer» No they have same LENGTH of DIAGONALS as I THINK so

Discussion

44.	if alpha and beta are roots of the quadratic equation 3 x 2 - 6 X + 2 = 0 then the value of Alpha 3 + beta 3 is....no spamming plzzz
Answer» We SIMPLY USE ALGEBRAIC IDENTITIES here..

Discussion

45.	Solve for x :- \| x +1\x \| ≤ 4
Answer» I don't KNOW this ANSWER

Discussion

46.	Plzz ans it plzzzzz I will mark u as brainest
Answer» ${a}^{2} + {b}^{2} - 5ab$ $= {(a - b)}^{2} - 3ab$ CALCULATE the RESULT of (a-b).It is (-4×6^(1/2)) and the result of ab is 1. $= {( - 4 \sqrt{6} )}^{2} - 3 \times 1$ $= 96 - 3$ $= 93$ PLEASE MARK THIS ANSWER BRAINLIEST.

Discussion

47.	Classify (3+√23)-√23 is rational or irrational from whole method
Answer» HOPE this ANSWER HELPS you!

Discussion

48.	3 root5+3 / root5-root3
Answer» (This is just to MAKE it 20 char long;;))) Hope it helps!!:) COMMENT me if it's CORRECT!

Discussion

49.	What is radion in trigonometry class 11 *
Answer» The RADIAN is a unit of measure for angles used mainly in trigonometry. It is used instead of degrees. WHEREAS a FULL circle is 360 degrees, a full circle is just over 6 radians. A full circle has 2π radians (Roughly 6.28) As seen in the figure above, a radian is defined by an ARC of a circle.

Discussion

50.	किसी सेना को 4 की गहराई के अंतः शून्य वर्ग में सजाने पर सामने की पंक्ति में जितने सैनिक रहते हैं उनसे 16 सैनिक सामने की पकति मे कम रहते हैं जब सैनिकों को ठोस वरग मे सजाया जाता है ा सैनिकों की संख्या निकाले
Answer» Given : किसी सेना को 4 की गहराई के अंतः शून्य वर्ग में सजाने पर सामने की पंक्ति में जितने सैनिक रहते हैं उनसे 16 सैनिक सामने की पकति मे कम रहते हैं जब सैनिकों को ठोस वरग मे सजाया जाता है To FIND : सैनिकों की संख्या Solution: 4 की गहराई के अंतः शून्य वर्ग में सजाने पर सामने की पंक्ति में सैनिक = S सैनिक = 16S - 4 * 16 = 16S - 64 = 16(S - 4) 16 सैनिक सामने की पकति मे कम रहते हैं जब सैनिकों को ठोस वरग मे सजाया जाता है => सैनिक = (S - 16)(S -16) (S - 16)(S -16) = 16S - 64 => S² -32S + 256 = 16S - 64 => S² - 48S + 320 = 0 => S² - 40S - 8S + 320 = 0 => S(S - 40) - 8(S - 40) = 0 => (S - 8) (S - 40) = 0 => S = 8 , S = 40 S = 8 संभव नहीं ∵ 8 - 16 = -8 S = 40 => सैनिक = (S - 16)(S -16) = 24 * 24 = 576 16(S - 4) = 16 * 36 = 576 सैनिकों की संख्या = 576 Learn more: 35. एक अधिकारी सैनिकों को 8:5:24 की रेखा में खड़ा ... brainly.in/question/16260195 एक किले में एक हजार जवानों के लिए 50 दिनों का ... brainly.in/question/9526921

50.

किसी सेना को 4 की गहराई के अंतः शून्य वर्ग में सजाने पर सामने की पंक्ति में जितने सैनिक रहते हैं उनसे 16 सैनिक सामने की पकति मे कम रहते हैं जब सैनिकों को ठोस वरग मे सजाया जाता है ा सैनिकों की संख्या निकाले

Answer»

Given : किसी सेना को 4 की गहराई के अंतः शून्य वर्ग में सजाने पर सामने की पंक्ति में जितने सैनिक रहते हैं उनसे 16 सैनिक सामने की पकति मे कम रहते हैं जब सैनिकों को ठोस वरग मे सजाया जाता है

To FIND : सैनिकों की संख्या

Solution:

4 की गहराई के अंतः शून्य वर्ग में सजाने पर सामने की पंक्ति में सैनिक = S

सैनिक = 16S - 4 * 16

= 16S - 64

= 16(S - 4)

16 सैनिक सामने की पकति मे कम रहते हैं जब सैनिकों को ठोस वरग मे सजाया जाता है

=> सैनिक = (S - 16)(S -16)

(S - 16)(S -16) = 16S - 64

=> S² -32S + 256 = 16S - 64

=> S² - 48S + 320 = 0

=> S² - 40S - 8S + 320 = 0

=> S(S - 40) - 8(S - 40) = 0

=> (S - 8) (S - 40) = 0

=> S = 8 , S = 40

S = 8 संभव नहीं ∵ 8 - 16 = -8

S = 40

=> सैनिक = (S - 16)(S -16) = 24 * 24 = 576

16(S - 4) = 16 * 36 = 576

सैनिकों की संख्या = 576

Learn more:

35. एक अधिकारी सैनिकों को 8:5:24 की रेखा में खड़ा ...

brainly.in/question/16260195

एक किले में एक हजार जवानों के लिए 50 दिनों का ...

brainly.in/question/9526921

Discussion

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