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It is the CORRECT ANSWER of your QUESTION

Here AB and CD are extended then they are intersecting at P.

Length of two TANGENTS drawn from external point to a CIRCLE are equal.

AP = CP ----------(1)
BP = DP ----------(2)

Substracting (2) from (1) we get

AP - BP = CP - DP

∴ AB = CD

ANSWER:

to FIND the SQUARE ROOT of 3481

3481-59

Clearly the difference between Rs. 578.40 and Rs.614.55 is the interest on Rs. 578.40 for 1 YEAR. 
∴ Interest on Rs. 578.40 for 1 year = Rs. 614.55 - Rs. 578.40 = Rs. 36.15 
∴ Interest on Rs.100 for 1 year = Rs. (36.15 x 100)/578.40 
= Rs. 3615/57840 x 100/1 
= Rs. 6.25 
= Rs. 61/4 


The required RATE is .61/4 percent

2a-2d=0
2a+5d=14

(simultaneous equation)

2a-2d=0
2a+5d=14
(-)  (-)  (-)
0   -7d=-14
      d=2

2a-2*2=0 ......(PLUGGING in d into the equation)
2a-4=0
2a=4
a=2
hope it HELPS!!!
this is simaltaneous equations.....so you have to LEARN it or search it up in the NET.

Hey!!!!

_________

Given,

=> 120km in 60 MINUTES

=> So X km in 45 minutes.

Thus

=> x = 120 x 45/60

=> x = 90km

Thus the TRAIN can cover 90km in 45 minutes

_____________

Hope this helps ✌️

Answer:

-1.25,-1.50,-1.75,-2.0,-2.25

Step-by-step explanation:

Write first FOUR term of AP whose first term =-1.25 and the common DIFFERENCE=- 0.25

Given :

NTH term of an A.P.

Hope it helps you.

That is your answer.....



 

 

Is this SUPPOSED to be: 

3cos(55°)/[7SIN(35°)] - 4[cos(70°)csc(20°)]/[7tan(5°)TAN(25°)tan...‡ 

If so, use: 

tan(90° - x) = cot(x) <==> cot(90° - x) = tan(x) 
sin(90° - x) = cos(x) <==> cos(90° - x) = sin(x). 

So we have: 

3cos(55°)/[7sin(35°)] 
=> 3sin(90° - 55°)/[7sin(35°)] 
= 3sin(35°)/[7sin(35°)] 
= 3/7. 

4 * [cos(70°)csc(20°)]/[7 * tan(5°) * tan(25°) * tan(45°) * tan(65°) * tan(85°)] 
=> (4/7)[cos(70°)/sin(20°)]/[tan(5°) * tan(25°) * tan(45°) * tan(65°) * tan(85°)] 
= (4/7)[sin(20°)/sin(20°)]/[tan(5°) * tan(25°) * tan(45°) * tan(65°) * tan(85°)] 
= (4/7)/[tan(5°) * tan(25°) * tan(45°) * tan(65°) * tan(85°)] 
= 4/[7 * tan(5°)tan(85°) * tan(25°)tan(65°) * tan(45°)] 
= 4/[7 * tan(5°)cot(5°) * tan(25°)cot(25°) * tan(45°)] 
= 4/(7 * 1 * 1 * 1) 
= 4/7. 

Thus, the EXPRESSION equals 3/7 - 4/7 = -1/7. 

I hope this helps!

Heya !!

here is ur ANSWER

================================


refer to the ATTACHMENT provided..

=================================

HOPE it helps u..!!

thnkq.

Your ANSWER in PICTURE

Hey Mate...!!!!
Here's ur answer.......

_____________
Use ATTACHMENT.........
....._______


HENCE ,
Theta = 24°

Hope it helps....!!!!

In geometry, Apollonius's theorem is a theorem relating the LENGTH of a MEDIAN of a triangle to the lengths of its side. It states that "the sum of the squares of any TWO sides of any triangle EQUALS TWICE the square on half the third side, together with twice the square on the median bisecting the third side".

Hi ,

Let x = 15.7121212.....----( 1 )

MULTIPLY equation ( 1 ) with 10, we get

10x = 157.121212....-----( 2 )


Multiply equation ( 2 ) with 100, we get

1000x = 15712.121212...----( 3 )

SUBTRACT equation ( 2 ) ,from ( 3 ),

990x = 15555

x = 15555/990

x = 3111/198

x = 1037/66

Therefore ,

x = 15.71212... = 1037/66 [ p/q form ]

I hope this HELPS you.

: )

The answer is GIVEN below :

RULE :

The two lines

a1x + b1y + c1 = 0
a2x + B2Y + c2 = 0

will REPRESENT two parallel lines, if

a1/a2 = b1/b2

SOLUTION :

The given lines are

kx - 3y + 6 = 0
4x - 6Y + 15 = 0

These two lines be parallel to each other, if

K/4 = (-3)/(-6)

⇒ k/4 = 1/2

⇒ k = 4/2

⇒ k = 2

Thus, when k = 2, the two given lines be parallel to each other.

Thank you for your question.

In the two pair of equations,
a1 = k-1. b1 = 3. c1 = 7
a2 = k+1. B2 = 6. c2 = 5k-1

As the pair of equations should have INFINITELY many solutions. the two LINES MUST be coincident...

Then, a1/a2 = b1/b2 = c1/c2

= k-1/k+1 = 3/6

= 2(k-1) = k+1

= 2k-2 = k+1

= k = 3...

There your have your solution..

A BINOMIAL DISTRIBUTION tends to be a POISSON distribution under the following conditions:

- Number of TRIALS is large, i.e., N tends to approach infinity
- Probability of each trial is very small, i.e., p tends to approach zero

Given:

Two NUMBERS differed by 3 and their product is 54.

To find out:

Find the numbers?

SOLUTION:

Let the two numbers be x and y .

★According to the FIRST CONDITION,

Difference if the two number = 3

➠ x - y = 3

➠ y = x - 3 ...............( i )

★ According to the second condition,

➠ xy = 54 ................( ii )

Substituting y = x - 3 from ( i ) and ( ii ), we get

x (x-3) = 54

➠ x² - 3x = 54

➠ x² - 3x - 54 = 0

➠ x² - 9x + 6x - 54 = 0

➠ x ( x - 9 ) + 6 ( x - 9 ) = 0

➠ ( x - 9 ) ( x + 6 ) = 0

➠ x = 9 and x = -6

On putting x = 9 in equation ( i ) , we have

y = 9 - 3 = 6

On putting x = -6 in equation ( i ) , we get

y = -6 - 3 = -9

Hence, the numbers are 9 and 6 or -9 and-6 .

Sum1=1138-1250=-112
sum2=1136-1272=-136
now sum2-sum1
=-136-(-112)
=-136+112
=-24

Sinx.sin(60-x).sin(60+x)

= sinx [ cos( 60 - x - 60 - x) - cos ( 60 - x + 60+ x ) /2

= sinx [ cos ( -2X ) - cos ( 120 ) ] /2

= sinx [ cos2x + 1/2 ] /2

= sinx [ ( 1 - 2sin²x) + 1/2 ] /2

= sinx [ 3/2 - 2sin²x ] / 2

= 3 sinx/4 - 2 sin³x /2

= 3SINX - 4sin³x / 4

= 1/4 ( sin3x )

Hope HELPED!

FORMULAE : sin3x = 3sinx - 4sin³x

2sinA* sinB = cos (A - B) - cos ( A + B)

Hello Friend__!!
Answer :

Given side of RHOMBUS  =  5.5 cm and one angle is 60° , As :

Refer to PIC above...

∠ BAD  = 60° , So BD is smaller diagonal 

And


∠ ABC  = 120°     , We know adjacent angle of rhombus are supplementary  .

And Diagonal of rhombus bisect it's angles , So

Diagonal BD bisect ∠ ABC  and ∠ ADC  , So

∠ ABD  =  ∠ ADB = 60° 

So,

In triangle  ABD  , all internal angles are at 60°   , So  triangle ABD is a equilateral triangle ,  So

AB  =  BD  =  DA  =  5.5 cm 

Then  ,

We can say LENGTH of smaller diagonal  =  5.5 cm                                    (  Ans )
Hope u FYND it helpful..
Mark brainlliest bro!!

Let the tens place digit be a

And Unit place digit be b

According to first condition,

a + b = 11 --------(1)

According to second condition

( 10a + b) - (10B +a) = 9

=> 10a + b - 10b - a = 9

=> 9a - 9b = 9

=> a - b = 1 ------(2)

On ADDING equation 1 and 2, we get

2a = 12

=> a = 6

Now,

On Substituting the value a in equation 1, we get

6 + b = 11

=> b = 5

Required number = 10 × 6 + 5

= 65

It can be EASILY find as follows
170= 2×5×17 (prime FACTORS)

238=2×7×17

Now fond common factors AMONG them ok,

2 and 17 Now multiply them
2×17 =34 .......(Ans)

Hope it helps you frend...

It will be -4/5
HOPE this HELPS you

On  dividing f(x) by G(x)
                ______x-7______
 x^2+x+1 ) x^3-6x^2+11x-6
                  x^3+x^2+x
                 (-)   (-)    (-)
                ___________
                      -7X^2+10x-6
                      -7x^2-  7x- 7
                      +      +     +
                      __________
                               17x +1
                          ________
using DIVISION algorithm
 
f(x)  = Q(x) g(x) + r(x)
=> x^3-6x^2+11x-6  =  (x-7) (x^2+x+1)  + (17x+1)
                                 x^3-6x^2+11x-6

hope it helps you:)!!!

Because LIGHT WAVES have more VACUUM then SOUND waves ...

Here is UR answer

plz BRAINLIEST

Hey!!!!

Let US SOLVE

=> 2x² - 50 = 0

=> 2x² = 50

=> x² = 25

=> x = √25

Thus x = 5 or x = -5

Hope this HELPS ✌️

Here is ur ANSWER by GIVING an EXAMPLE. here is SIMPLE WAY to solve

Here is your ANSWER my FRIEND i HOPE this will HELP you

The PRESENT age of ONE sister is 12YEARS and the present age of the SECOND sister is 18 years.

Distance covered in 12 hrs = 1236 km

Speed = distance / TIME

speed = 1236/12 = 103 km/hr

Distance = speed × time
distance = 103 × 10.5
distance = 1081.5 km

Hope it HELPS...!!!
THANKS...!!!!

The ANSWER is FAMOUS