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7/9×45
7×5
35 is your answer

Hope this HELPS you.....

HELLO DEAR,


sin38° + sin22° = sin82°


Now,


from , L.H.S,

sin38° + sin22° = 2sin(38 + 22)/2 * COS(38 - 22)/2
∴ [ sinA + sinB = 2sin(A + B)/2 * cos(A - B)/2 ]


⇒2sin(60/2) * cos(16/2)


⇒2sin30° * cos8°


⇒2 * 1/2 * cos8°
∴ [ sin30° = 1/2 ]

⇒ 2̶ * 1/ 2̶ * cos8°

⇒cos8°



we know that:-

cos(90 - Ф) = sinФ


now using here,


we GET,

cos8° = cos(90 - 82)°

⇒sin82°


hence,


sin38° + sin22° = sin82°




I HOPE ITS HELP YOU DEAR,
THANKS

to buy 7/2= 3.5litre
@45/2=22.5 rupees PER LITRE
Money REQUIRED to buy 3.5 litre
=3.5×22.5=78.75 rupees
left Money =100-78.75=21.75 rupees

X³-5x²-x+5
=X²(x-5) -1(x-5)
=(x-5) (x²-1)

Answer:

Step-by-step EXPLANATION:

Another answer for this question which is present here is WRONG it is the RIGHT answer check the attachment

We know that :

3% = 3/100 & 5% = 5/100

Asked : What percent is 3/100 of 5/100.

So, Solution will be :

[{(3/100) / (5/100)} X 100]%

=[{3/5} x 100]%

= 60%

We know the formula ,
   number of diagonals = N(n - 3)/2 ,where n is the number of SIDES .
here GIVEN,
  number of diagonals = 434 
  ⇒ n(n - 3)/2 = 434 
⇒ n² - 3n = 868 
⇒ n² - 3n - 868 = 0 
⇒ n² - 31n + 28n - 868 = 0
⇒ n( n - 31) + 28(n - 31) = 0
⇒ (n - 31)(n + 28) = 0
n = 31 and - 28 ,  n ≠ - 28 , number o sides can't be negative.
  hence, number of sides = 31

1.2 can be WRITTEN in RATIONAL FORM
12/10
6/5

If the compound ratio of 5 : 8 and 3 : 7 is 45 : x. FIND the value of x.

Compound ratio of 5:8 and 3:7 = 5/8 ? - 3/7 = 15/56.

Now product of extremes = Product of MEANS => 15:56 :: 45:x => 15X = 2520 => 2520/15 = 168.

x = 168.

Here is UR ANSWER

i HOPE it helpsvu

Answer:

The missing number of the series is 348.

Step-by-step EXPLANATION:

Hey Mate,

Given Series : 18, 36, 72, 132, 222, X

Logic behind this series is triple DIFFERENT base. So, we need to find the difference 3 TIMES in the series.

Diff (1) : 18,  36,  60, 90, 126

Diff (2) : 18,  24,  30, 36

Diff (3) : 6*3, 6*4, 6*5, 6*6

Missing number is  222 + 126 = 348

(#The solution of given series is attach with this answer.)

The Missing number of the series is 348

The answer is given below :

We KNOW that,

e^(logx) = X.

Now,

e^(2 log cotx)

= e^{log (cotx)²}

= e^(log cot²x)

= cot²x

= cosec²x - 1
since cosec²x - cot²x = 1

Now,

∫ e^(2 log cotx) dx

= ∫ (cosec²x - 1) dx

= ∫ cosec²x dx - ∫ dx

= - cotx - x + c, where c is INTEGRAL constant
which is the REQUIRED solution.

Thus, option (4) is correct.

RULE :

∫ cosec²x dx = - cotx

Thank you for your QUESTION.

Hey!!!!!

___________

By EUCLID's DIVISION ALGORITHM,

=> 297 = 216 x 1 + 81

=> 216 = 81 x 2 + 54

=> 81 = 54 x 1 + 27

=> 54 = 27 x 2 + 0


Thus HCF(216,297) = 27

Hope this helps you

1. Draw a line segment AB such that it is 7.5 CM long.
2. Now extend the line to a point C so that B is a point on the line segment AC and BC = 1 cm.
3. Find the MIDPOINT of AC and name it O. Now, with O as the centre and radius equal to OA, draw a semi circle with AC as the diameter.
4. At point B, MAKE an angle of 90 degrees such that the line INTERSECTS the semi-circle just drawn at a point D. Join DC.
5. With BD as the radius and B as the centre, draw an arc to cut the extended line segment AC at E. 

BE is the required line that is under ROOT 7.5 units long.

Refer to the attached image

Heya mate,

driver = 6*2 = 12. {six ALPHABET}

pedestrian = 10*2 = 20. {TEN alphabet}

so, now,

car = 3*2 = 6. { three alphabet}

#kevin

hope it will HELP you...

Heya ✋

Let see your ANSWER !!!!

Let the breadth be (x)cm. Then,

length = (x + 5)cm

Area = x × (x + 5)

= (x^2 + 5x)cm^2

New length = (x + 5 + 1)cm

= (x + 6)cm

New breadth = (x + 1)cm

New area formed = (x^2 + 5x + 34)cm^2

According to question ,

(x + 6) (x + 1) = x^2 + 5x + 34

=> x^2 + x + 6x + 6 = x^2 + 5x + 34

=> x^2 + 7x + 6 = x^2 + 5x + 34

=> x^2 - x^2 + 7x - 5x = 34 - 6

=> 2x = 28

=> x = 28/2

=> x = 14

Hence , breadth = 14cm

and length = (14 + 5)cm

= 19cm






Thanks :))))

Do you have a PICTURE?

The answer is given below :

2.

Given,

x = √(m+n) + √(m-n)}/{√(m+n) - √(m-n)}

Now, we RATIONALISE the DENOMINATOR by multiplying both the numerator and the denominator by {√(m+n) + √(m-n)}, we GET

x = [{√(m+n) + √(m-n)}{√(m+n) + √(m-n)}]/
{√(m+n) - √(m-n)}{√(m+n) + √(m-n)}

= [√(m+n) + √(m-n)]²/[{√(m+n)}² - {√(m-n)}²],
since (a+b)(a+b) = (a+b)²
and (a+b)(a-b) = a²-b²

= [(m+n) + 2√(m²-n²) + (m-n)]/[(m+n) - (m-n)],
since (a+b)² = a² + 2ab + b²

= [2m+2√(m²-n²)]/(m+n-m+n)

= [2m+2√(m²-n²)]/2n

= [m+√(m²-n²)]/n

⇒ nx = m+√(m²-n²)

⇒ nx - m = √(m²-n²)

Now, squaring both sides, we get

(nx - m)² = m² - n²

⇒ n²x² - 2mnx + m² = m² - n²

⇒ n²x² - 2mnx + n² = 0

⇒ nx² - 2mx + n = 0,
dividing both sides by n, n≠0.
(Ans.)

3.

Now,

9 + 4√5

= 5 + 4√5 + 4

= (√5)² + (2 × √5 × 2) + 2²

= (√5 + 2)²

So, √(9 + 4√5) = √5 + 2

Hence,

x = 1/√(9+4√5)

= 1/(√5 + 2)

= (√5 - 2){(√5 + 2)(√5 - 2),
by rationalising the denominator

= (√5 - 2)/(5 - 4),
since (a+b)(a-b) = a²-b²

= (√5 - 2)/1

= √5 - 2

Given that,

p(x) = x³ + 7x² + 16X + 7

So, p(√5 - 2)

= (√5 - 2)³ + 7(√5 - 2)² + 16(√5 - 2) + 7

= (√5)³ - {3 × (√5)² × 2} + (3 × √5 × 2²) - 2³
+ 7{(√5)² - (2 × √5 × 2) + 2²} + 16(√5 - 2) + 7,
using (a-b)³ = a³ - 3a²b + 3ab² - b³

= (5√5 - 30 + 12√5 - 8) + 7(5 - 4√5 + 4)
+ 16(√5 - 2) + 7

= 17√5 - 38 + 7(9 - 4√5) + 16(√5 - 2) + 7

= 17√5 - 38 + 63 - 28√5 + 16√5 + 32 + 7

= (17 - 28 + 16)√5 + (- 38 + 63 + 32 + 7)

= 5√5 + 0

= 5√5

So, option (4) is correct.

Thank you for your question.

Here
given
√5 = 2.236
√10 = 3.162
So,
PUTTING VALUES ,
√10+√20+√40+√5+√80 →↓
3.162+6.324+12.648+2.236+25.296 = 49.666

No, Because LCM of two NUMBER must be divisible by HCF of those two NUMBERS. as 380 is not divisible by 18 so this pair of HCF and LCM for any two number is not possible.

Here is your answer MATE.......

6 root 15 × 4 root 3 = 24 root 45

i.e. 6 × 4 = 24 and root(3×15) = root 45

☆☆☆HOPE IT HELPS ☆☆

2197 is not a PERFECT CUBE.

Question

Two adjacent ANGLES of a parallelogram are (2x+25) and (3x-5). The value of x is :

(1).32

(2).34

(3).36

(4).42

Hey !!!

a (first term ) = 7

d (common DIFFERENCE) = T2 -t1 = 13-7 = 6

n = 19

tn = a + ( n - 1 ) d

t19 = 7 + ( 19 - 1 ) 6

t19 = 7 + 108

t19 = 115 Answer

***********************************

Hope it HELPS you !!

@Rajukumar111

On SOLVING this equation
2y²-4y-16=0
y²-2y-8=0
(y²+2y)-(4y-8)=0
y(y+2)-4(y+2)=0
(y-4)(y+2)=0
y= 4 or y= - 2

Answer:

(2-x),(3+x) are factors of given quadratic expression 6-x-x²

Explanation:

Given QUADRATIC expression:

6-x-x²

Splitting the middle TERM, we GET

= 6 - 3x +2x - x²

= 3(2-x) + x(2-x)

Take (2-x) common, we get

= (2-x)(3+x)

Therefore,

6-x-x² = (2-x)(3+x)

••••

Hii FRND here's the ANSWER to the given question

hope ull get the answer to the given question and mark as BRAINLIEST ONE........

Here's your ANSWER for the QUESTION

-8√5 is the ANSWER to this QUESTION

(1/4)^1/2 + (0.01)^-1/2 - 27^2/3

= 1/2 + (100)^1/2 - 3^2

= 1/2 + 10 - 9

= 1/2 + 1 = 3/2 ( ans)

this is the CORRECT answer
pls thanks me and mark as brainlist
thanks for POSTING such questions

If the ratio is 7:5 and there are 42 girls, then you are multiplying by 6. 5 X 6 = 30. 30 BOYS PARTICIPATED.

6√15x4√3=24√45 or 72√5