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A cylindrical glass tube with radius 10 cm has water upto height 9 cm. A metal cube of 8 cm edge is immersed in it completely. By how much cm the water level rise in the glass tube? |
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Answer» SOLUTION:- H = 9 cm, diameter = 20 cm so, radius = 10 cm and side of the cube = 8 cm Total volume of the cylinder (after cube is immersed) = Volume of WATER in cylinder + Volume of water DISPLACED or volume of the cube = 22/7*10*10*9 + 8*8*8 = 19800/7 + 512 = 2828.57 + 512 = 3340.57 cu cm Now, height of water, h1 can be found by equating πr²h1 with this volume. So, 22/7*10*10*h1 = 3340.57 h1 = (3340.57 × 7)/2200 h1 = 23383.99/2200 Height = 10.63 cm Rise in the water LEVEL in the cylinder = h1 - h = 10.63 - 9 = 1.63 cm hope this helps...... |
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