This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The largest mountain in the world |
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| 2. |
Simplify (3/5)4(8/5)-12(32/5)6 |
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Answer» Hello Friend ✌ |
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| 3. |
What is called the figure which ends at the starting point |
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Answer» ACTUALLY we can SAY that FIGURE a CIRCLE ... CIRCLE |
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| 4. |
A number is exactly divisible by 3 if the sum of its digits isa..........Of 3 |
| Answer» MULTIPLE is the RIGHT ANSWER | |
| 5. |
What is the remainder when 2x^4+3x^3-x^2-2 is divided by x+2? |
| Answer» SEE UR question is not CORRECT whats thr upper SIGN | |
| 6. |
A box containes 2 black and 2 white ball then probablity of selecting 2 balls of the same colour |
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Answer» Total no. of BALLS= 4 |
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| 7. |
(a2+5) (a2-4)solve this question... |
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Answer» (a+b) (a-b) = a^2 b^2 |
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| 8. |
6x^2+x-2 by splitting |
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Answer» 6X |
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| 9. |
1/2 (10+6)*d=640. find the value of d |
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Answer» I have SOLVED this myself for you so |
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| 10. |
120 मीटर लंबे तथा 70 मीटर चोड़े खेल मैदान का परिमाप क्या होगा |
| Answer» PLEASE ask in English language so that EVERY KNOWS your QUESTION. | |
| 11. |
Able and bill are two friends. Able is carrying silver and bill is carrying gold. They prepare a mixture by mixing metals in proportions 7:2 and 7:11 respectively. If equal quantities of the two metals are melted to form an alloy , the proportion of silver and gold in the alloy will be? |
| Answer» PLEASE SEE the ATTACHMENT | |
| 12. |
A man buy 3 lemon for ruppes 5 and sell 2 for ruppes 4 .Find his gain or loss%. |
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Answer» ⚡Hey mate⚡ |
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| 13. |
a rectangular paper of dimensions 22cm×8cm is formed into a hollow cylinder by rolling ot along its length. find the radius of the cylinder. |
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Answer» Answer: 1.27 CM Step-by-step explanation: The PAPER is rolled along the length ⇒ the BREADTH of the paper is the circumference Find the radius Circumference = 2πr 8 = 2πr r = 8 ÷ 2π r = 14/11 or 1.27 cm Answer: The radius is 1.27 cm |
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| 15. |
Solve the equation of algebraic equations Q9 |
| Answer» PLEASE SEE the ATTACHMENT | |
| 16. |
area of rectanglar playground is 313/2squar metres and its breadth is 49/4m what is th length of the playground? |
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Answer» GIVEN AREA 313/2 breathe 49/4 length? length=a/b 313/2/49/4=313multiply 4/49multiply 2 =72.836 is the ANSWER |
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| 18. |
5%+7%+1.5%Help asap |
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Answer» ⭐Hey There⭐ Here's your answer ⤵ 5% ×7%+1.5%⬇ ________________________ ⭐Step 1: SIMPLIFY 5% to 0.05 ________________________________ 0.05×7%+1.5% ⭐Step 2: Simplify 7% to 0.07 _______________________________ 0.05×0.07+1.5% ⭐Step 3: Simplify 1.5% to 0.015 __________________________________ 0.05 × 0.07 + 0.015 ⭐Step 4: Simplify 0.05×0.07 to 0.0035 _________________________________________ 0.0035 + 0.015 ⭐Step 5: Simplify 0.0035+ 0.015 Answer=> 0.0185 Hope it helps you! ヅ ✪ Be Brainly ✪ |
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| 19. |
Manik earns rs 411120 in 9 month.how much does he earns in one year. |
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Answer» To find how MUCH he earns in 1 year,FIST v need to find how much he earns in 1 month: |
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| 20. |
A manufacturer's producers 5706 items in 3 days.how many items will manufacturer in 28 days |
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Answer» FIST of all,DIVIDE 3 with 5706 that will GIVE u: 1902 then MULTIPLY it with 28: 53,256 will b the ANSWER |
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| 21. |
Can u solve this problem for me ? 10–2+6c–2 |
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| 22. |
We have rs 100 we should buy 100 things at 5rs and 1rs and .25 paise rs how can we buy |
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Answer» Given : We have rs 100 we should buy 100 THINGS at 5rs and 1rs and .25 PAISE To find : Different ways to buy Solution: Lets Thing buy A rs 5 = x & thing buy at Rs 0.25 ( 25 Paise) = y then thing bought at Rs 1 = 100 - (x + y) AMOUNT for 5 Rs x thing = 5x Amount for Rs 0.25 y things = 0.25y Amount for Rs 1 (100 - (x + y)) things = 100 -(x + y) 5x + 0.25y + 100 - (x + y) = 100 => 4x - 0.75y = 0 =>4x = 0.75y => 16x = 3y Possible Values x = 0 & y = 0 x = 3 & y = 16 x = 6 & y = 32 x = 9 & y = 48 x = 12 & y = 64 x = 15 & y = 80 x = 18 & y = 96 ( not possible as x + y ≤ 100) Different ways to buy things Rs 5 Rs 1 Rs 0.25 0 100 0 3 81 16 6 62 32 9 43 48 12 24 64 15 5 80
Learn more: विचार करा आणि कोडं सोडवा 1 रुपयात 40 कासव 3 ... 1 रुपयात 40 कासव 3 रुपयात 1 मांजर 5 रुपयात 1 वाघ तर ... |
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| 23. |
0.25%×2Help me asap!! |
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Answer» ⭐Hey There⭐ Here's your answer ⤵ =>0.25%×2⬇ _________________ ⭐Step 1: SIMPLIFY 0.25% to 0.0025 ______________________________________ => 0.0025 × 2 ⭐Step 2: Simplify 0.0025×2 _____________________________________ Answer=> 0.005 Hope it helps you! ヅ ✪ Be BRAINLY ✪ |
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| 25. |
What is the formula of (a2+ b2) |
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Answer» A2+2ab+B2 this is the FORMULA for (a2+b2 |
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| 26. |
Who can solve this ?The ratio of land and water in whole Earth is 1 ratio 2 and the ratio of land and water in Northern hemisphere is 2 ratio 3 then find the ratio of land and water in the southern hemisphere . |
| Answer» HELLO MATE the ANSWER is 1/6 | |
| 27. |
Solve limit n tend to infinity n factorial? |
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Answer» I am not SURE but this can be |
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| 29. |
If two numbers are in the ratio 4:7 if the larger number is 63 find the smaller number |
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Answer» Given,the LARGER number is 63. |
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| 30. |
If two numbers are in the ratio 4:7 if the larger number is 63 find the smaller number. |
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Answer» I think so the smaller number will be 28 bcoz 7*9=63 and 7*4=28.just a guess HOPE it HELPS you |
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| 31. |
Please post some really hard trigonometry questions worksheet. |
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| 32. |
135%+15%Please help |
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Answer» HELLO MATE here's your ANSWER ¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤ ¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤ Hope it HELPS you |
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| 33. |
If ramu takes 6 marbles from somu the number of marbles with them will be equal. If somu takes one marble thatramu has.what is the total number of marble with both of them |
| Answer» RAMU take 6 marbel from Sony the no. of marbles with them will EQUAL when SOMU has 12 marbles | |
| 34. |
This is an arethmetic progression sum. in grade 10. Q 2 b |
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Answer» Here is the answer |
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| 35. |
Please solve 3rd question only |
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Answer» SMH Step-by-step EXPLANATION: |
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| 36. |
What is the relationship between a manager and operation specialist? |
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Answer» A relationship manager is a professional who WORKS to IMPROVE firm's relationships with PARTNER firms and CUSTOMERS. |
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| 37. |
A circle has a circumference of11,304 units.What is the diameter of the circle? |
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Answer» CIRCUMFERENCE FORMULA is 2x pi x r Where r is the radius By USING formula we can take out the value of r = 11304/(2 x pi ) Value of pi is 22/7 So r = (11304 x 7) /(2x 22 ) By this u can calculate radius Since DIAMETER is double of radius so u just have to multiply 2 with the radius That is 2r Now u can take out your value Hopefully u will be able to take out your answer by your own by this explanation HOPE this helps you |
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| 38. |
one of the exterior angle of a triangle is 105 degrees and the interior opposite angles are in the ratio 2 is to 5 find angles of the triangle |
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Answer» hey! is your answer exterior angle=105° let the INTERIOR OPPOSITE ANGLES be 2x and 5x exterior angle=sum of two opposite angles so,ACCORDING to question, 105°=2x+5x 105°=7x x=105°/7 x=15° 2x=2*15°=30° 5x=5*15°=75° hope it HELPS you! |
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| 39. |
There are two numbers such that if to 3 times the first,twice the other is added the sum is 72. Also if from 5 times the first number, 3 times the other is substracted, the result is 44. What are the numbers |
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Answer» The equations will be |
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| 40. |
34x+888=33444%3 find the value of x |
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Answer» 34x+888=33444/3 |
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| 41. |
a body is thrown vertically up with velocity u . it passes three points A B C in its upward journey with velocity u/2 u/3 u/4 respectively . the ratio of separation between point A & B and between B & C .I.e AB/BC is |
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Answer» answer : 20 : 7 A body is thrown vertically upward with speed u. Let point A is located at s distance from the ground initial VELOCITY = u velocity at point A ,v= u/2, using formula, v² = u² + 2as or, (u/2)² = u² + 2(-g)s or, u²/4 - u² = -2gs or, -3u²/4 = -2gs or, s = 3u²/8g .....(1) similarly, velocity at point B, v = u/3 then, (u/3)² = u² + 2(-g)s' or, -8u²/9 = -2gs' or , s' = 4u²/9g.....(2) and velocity at point C, v = u/4 then, (u/4)² = u² + 2(-g)s" or, -15u²/16 = -2gs" or, s" = 15u²/32g ....(3) so, seperation between point A and B , AB = s' - s = (4u²/9g) - (3u²/8g) = (32 - 27)u²/72g = 5u²/72g and seperation between B and C , BC = s" - s' = (15u²/32g) - (4u²/9g) = (135 - 128)u²/(288g) = 7u²/228g so, AB/BC = (5u²/72g)/(7u²/288g) = 5 × 288/72 × 7 = 20/7 |
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| 44. |
Express the following speeds in metres per second :(i)90 km/ hr |
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Answer» It EQUAL to 25m/s |
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| 45. |
Please do it quickly, it's very urgent Factorise :a) 2x³-6x⁴- 10x² |
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Answer» DETERMINE GCF GCF: 2 and x^2 Divide 2/2 = 1 -6/2 = -3 -10/2= -5 Answer |
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| 46. |
A plot is 110m long and 80m board is to be covered with grass leaving 5m all around. Find the area of the land to be laid with grass. |
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Answer» AREA of plot=length*BREADTH =110*80 =8800m area of grass leaving LAND =(side)^2 =(5)^2 =25m area of land=area of plot - area of grass with grass. leaving land =8800 - 25 =8775m |
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| 47. |
Draw the graph f=(9/5)C+32 |
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Answer» 56989959,756884585585 |
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| 48. |
The diagonal of a rhombus are 26cm and 12cm.find its area and perimeter. |
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Answer» _______________________ Let the DIAGONALS of the rhombus be P and Q. Given ; P = 26 cm and Q = 12 cm. Area of rhombus = Area of rhombus = 26 × 12 / 2 Area of rhombus = 312 / 2 Area of rhombus = 156 cm². Now, _______________________ Let us know first, the PROPERTIES of rhombus. 1. All sides of a rhombus are equal. 2. Diagonals of a rhombus bisect each other. _______________________ According to QUESTION, AC = 26 cm and BD = 12 cm. And, AE = EC = 13 cm. BE = ED = 6 cm. [see the above DIAGRAM] Now, In ΔAED, using pythagoras theorem, We have ; AD² = AE² + ED² AD² = 13² + 6² AD² = 169 + 36 AD² = 205 AD = √205 AD = 14. 31 As we know, Each side of a rhombus are equal. Therefore, Perimeter = AD + DC + CB + BA Perimeter = 14.31 × 4 Perimeter ≈ 57. 24 cm _______________________ Thanks for the question! ☺️❤️☺️ |
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| 49. |
The angle of a tringle are in the ratio 1 : 3 : 5. Find The measure of each of the angles. |
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Answer» LET the ANGLES be X 3X and 5x then x+3x+5x=180 9x=180 x=20 second angle=60 100 |
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| 50. |
There is an average of 3.5×10−2 kilograms of dissolved salt in each liter of seawater. The Pacific Ocean contains approximately 6.6×1020 liters of seawater. |
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Answer» GIVEN that there is AVERAGE 3.5*10^-2 kg salt in Each liter of seawater The Pacific ocean CONTAINS 6.6*1020 LITERS of water So, the total salt in the ocean would be 3.5*10^-2 * 6.6*1020 = 3.5*10^-2 * 6732 = 235.620 Ans: the Pacific ocean contains 235.620 KG of salt |
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