332354 + Interview Questions in Secondary School in Math

1.	7. The name of the quadrilateral isAABCDOACDBOADBC
Answer» ANSWER: *ABCD* Step-by-step EXPLANATION: PLEASE MARK it BRAINLIEST and folow me

1.

7. The name of the quadrilateral isAABCDOACDBOADBC

Answer»

ANSWER:

ABCD

Step-by-step EXPLANATION:

PLEASE MARK it BRAINLIEST and folow me

Discussion

2.	11. The harmonic mean of 2, 4, 8 be 24/7, then the value of a is(A) 9(B) 4(C) 6(D) 812. If y=-2x 5 and standard deviation of r is 12, then standard deviation of y is
Answer» ANSWER: answer is 9 Step-by-step EXPLANATION: eieurueuwuwu

2.

11. The harmonic mean of 2, 4, 8 be 24/7, then the value of a is(A) 9(B) 4(C) 6(D) 812. If y=-2x 5 and standard deviation of r is 12, then standard deviation of y is

Answer»

ANSWER:

answer is 9

Step-by-step EXPLANATION:

eieurueuwuwu

Discussion

3.	The roots of the equation 6x^2+bx+c are "alpha" and "1/alpha", then the value of 'c' in this equation is? Pls help dont spam
Answer» : Product of roots= ALPHA×1/alpha= c/a(according to the formula) So 1= c/a( here alpha MULTIPLIED with 1/alpha will give 1 and we have a= 6 GIVEN in the question) so 1=c/6 this gives c=6

Discussion

4.	OFind the valuethe value of2 sin 45 X COS 45
Answer» ANSWER: 1 is CORRECT answer,,,,,,,

4.

OFind the valuethe value of2 sin 45 X COS 45

Answer»

ANSWER:

1 is CORRECT answer,,,,,,,

Discussion

5.	3-4x/9 - 3x-2/3 = 2 - x/3
Answer» ANSWER: X = 3/10 Step-by-step explanation: 3-4x-(9x - 6) / 9 = 2-x /3 3-4x-9x-+6/3 =2-x -13X +9 = 6 - 3x 9-6 = 13x -3x 3 = 10x x = 3/10

5.

3-4x/9 - 3x-2/3 = 2 - x/3

Answer»

ANSWER:

X = 3/10

Step-by-step explanation:

3-4x-(9x - 6) / 9 = 2-x /3

3-4x-9x-+6/3 =2-x

-13X +9 = 6 - 3x

9-6 = 13x -3x

3 = 10x

x = 3/10

Discussion

6.	Cos 3A - cos 7A/sin 9A + sin A=cos 2A · tan 4A - sin 2A
Answer» ANSWER: GD shshwhhshshhshsshshjsbsjbs

6.

Cos 3A - cos 7A/sin 9A + sin A=cos 2A · tan 4A - sin 2A

Answer»

ANSWER:

GD shshwhhshshhshsshshjsbsjbs

Discussion

7.	What is tha range of tha data
Answer» The RANGE is the DIFFERENCE between the LOWEST and HIGHEST !! ___ !!

7.

What is tha range of tha data

Answer»

The RANGE is the DIFFERENCE between the LOWEST and HIGHEST

!!

___ !!

Discussion

8.	Find the perimeter of triangle if the diagonal is 10√2 cm.
Answer» ANSWER: the answer is:- 40cm i HOPE this is HELPFUL for you

8.

Find the perimeter of triangle if the diagonal is 10√2 cm.

Answer»

ANSWER:

the answer is:-

40cm

i HOPE this is HELPFUL for you

Discussion

9.	36 hours and 45 hours as a ratio in its simplest form
Answer» Answer: 36/45=4/5 is the answer Step-by-step EXPLANATION: HOPE it HELPS you PLEASE MARK me brainlist

9.

36 hours and 45 hours as a ratio in its simplest form

Answer»

Answer:

36/45=4/5 is the answer

Step-by-step EXPLANATION:

HOPE it HELPS you PLEASE MARK me brainlist

Discussion

10.	In fig-2, AB\|\|DE, BD\|\|EF. Prove that DC2-CFxAC
Answer» ANSWER: HII hii hii hiihgddtdhiisfhoiasdji

10.

In fig-2, AB||DE, BD||EF. Prove that DC2-CFxAC

Answer»

ANSWER:

HII hii hii hiihgddtdhiisfhoiasdji

Discussion

11.	Compare the following ratio 3:7 and5:8
Answer» HEY your ANSWER is here it's 3:7 > 5:8 Pls MARK me as BRAINLIEST

11.

Compare the following ratio 3:7 and5:8

Answer»

HEY your ANSWER is here it's 3:7 > 5:8

Pls MARK me as BRAINLIEST

Discussion

12.	Simplify:-[write the laws of exponents used]
Answer» *SORRY. You* *can* *solve* *this* *QUESTION* by *using* of *BODMAS* *Rule. I hope* it is *useful* *for* *you. PLZ* *MARK* me as *brainlist* *answer*.

12.

Simplify:-[write the laws of exponents used]

Answer»

SORRY.

You can solve this QUESTION by using of BODMAS Rule.

I hope it is useful for you.

PLZ MARK me as brainlist answer.

Discussion

13.	1+3+5+7+9+11+13+15= (__)²
Answer» ANSWER: (64)²= 8 Step-by-step EXPLANATION: hope it helps you

13.

1+3+5+7+9+11+13+15= (__)²

Answer»

ANSWER:

(64)²= 8

Step-by-step EXPLANATION:

hope it helps you

Discussion

14.	4.) Construct a quadrilateral MORE. In Which MO=3cmOR=4cm,RE=5cm,EM=4.5 cm and OE=6.5cm.
Answer» ANSWER: SORRY I didn't know how to send pics Step-by-step explanation: please MARK my BRAINLIST ♥️

14.

4.) Construct a quadrilateral MORE. In Which MO=3cmOR=4cm,RE=5cm,EM=4.5 cm and OE=6.5cm.

Answer»

ANSWER:

SORRY I didn't know how to send pics

Step-by-step explanation:

please MARK my BRAINLIST ♥️

Discussion

15.	Simplify using properties of multiplication 5670 X 353 + 810 x 7 x 677 - 5070 X 29 - 5670
Answer» Step-by-step explanation: 5670×353+810×7×677-5070×29-5670 2001510+3793230-147030-5670 5794740-147030-5670 5647710-5670 5642040

15.

Simplify using properties of multiplication 5670 X 353 + 810 x 7 x 677 - 5070 X 29 - 5670

Answer»

Step-by-step explanation:

5670×353+810×7×677-5070×29-5670

2001510+3793230-147030-5670

5794740-147030-5670

5647710-5670

5642040

Discussion

16.	4.PARMATMA Ltd. Delhi invoices goods to its Mumbai and Kolkata branch offices at 20% less than the list price which is costplus 50% with instructions that cash sales are to be made at invoice price and credit sales at list price. Opening Stock at Mumbai at its cost ₹ 1,53,600. Goods Sent to Mumbai (at cost to Delhi) ₹ 2,20,000. Cash Sales ₹ 1,49,600, Credit Sales ₹ 2,90,000. Goods returned by Credit Customers to Mumbai ₹ 90,000. Goods returned by Mumbai to Delhi ₹ 72,000. Loss of Goods by fire (at invoice price) ₹ 6,000 against which 80% of cost was recovered from the insurance Company. Loss of Goods at Mumbai through normal pilferage (at list price) ₹ 6,000. Debtors at Mumbai:Opening ₹ 10,000 Cash remitted by MumbaI Branch to HO: ₹ 3,24,870. Discount Allowed to Debtors ₹ 26,730. Goods received by Mumbai till close of the year ₹ 2,54,000. Provision is to be made for discount on Debtors at 15% on prompt payments at year end on the basis of year’s trend of prompt payments. Cash remitted by HO to Branch for Expenses: ₹ 18,000Branch Expenses still outstanding: ₹ 1,482Manager is entitled to a commission @ 6% of net profits after charging such commission.Required: Prepare Mumbai Branch Debtors A/c, Mumbai Branch Stock Account, Mumbai Branch Adjustment A/c, Mumbai Branch Expenses Account and Mumbai Branch Profit & Loss A/c under Stock & Debtors Method.
Answer» HMM IDK give short LOL Lol Lol Wanna report HAHAHA Just do it

Discussion

17.	Help me to draw a pie chart of this..plz do and send me the pic
Answer» ANSWER: a) Mobile. b) 20% HOPE it HELPS you..

17.

Help me to draw a pie chart of this..plz do and send me the pic

Answer»

ANSWER:

a) Mobile.

b) 20%

HOPE it HELPS you..

Discussion

18.	What percent of 80 m is 24 m.
Answer» Answer: 30 Step-by-step EXPLANATION: PERCENTAGE CALCULATOR: 24 is what PERCENT of 80? = 30.

18.

What percent of 80 m is 24 m.

Answer»

Answer:

30

Step-by-step EXPLANATION:

PERCENTAGE CALCULATOR: 24 is what PERCENT of 80? = 30.

Discussion

19.	ABC is a traingle in which AB = AC = 6cm and angle A =90° calculate the area of ABC
Answer» Step-by-step EXPLANATION: BJD jsjf djdjd djdjd cjfjd djskf rjdjjdjdj fknejdhhxbdjdiid djsidiid bdidb djidj yhuhh HGF uuuh HVG H

19.

ABC is a traingle in which AB = AC = 6cm and angle A =90° calculate the area of ABC

Answer»

Step-by-step EXPLANATION:

BJD jsjf djdjd djdjd cjfjd djskf rjdjjdjdj fknejdhhxbdjdiid djsidiid bdidb djidj yhuhh HGF uuuh HVG H

Discussion

20.	40. Find the roots of the following equation :11x ² - 4, 711x +4x - 730'
Answer» Answer: 25523923556646535523665

20.

40. Find the roots of the following equation :11x ² - 4, 711x +4x - 730'

Answer»

Answer:

25*523923556646*535523665

Discussion

21.	Find the perfect squares between100 and 150 i 150 and 200 with explanation
Answer» Answer: hhffty to you and your Step-by-step explanation: GUY to you and your family and FRIENDS and family and friendsuuuywrite the report of science EXHIBITION in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in SCHOOL

21.

Find the perfect squares between100 and 150 i 150 and 200 with explanation

Answer»

Answer:

hhffty to you and your

Step-by-step explanation:

GUY to you and your family and FRIENDS and family and friendsuuuywrite the report of science EXHIBITION in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in schoolwrite the report of science exhibition in SCHOOL

Discussion

22.	If p(x)=2x+3, then find p(x)+p(-x)
Answer» <P>Step-by-step EXPLANATION: hence DONE with answer that is p = 0

22.

If p(x)=2x+3, then find p(x)+p(-x)

Answer»

<P>Step-by-step EXPLANATION:

hence DONE with answer that is p = 0

Discussion

23.	Find the derivative of the following function ( it is to be understood that a, b, c and d are fixed non-zero constants and m and n are integers ) :-
Answer» Question : Find the derivative of the following function ( it is to be understood that a, B, c and d are fixed non-zero constants and m and n are INTEGERS ) :- $\sf \: (ax + b) ^{n} ( {cx + d})^{m}$ Solution : $:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(ax + b)^{n}\cdot(cx + d)^{m}]}{dx}} \\ \\ \\$ By applying the product rule of differentiation, we get : $\underline{\sf{\bigstar\:Product\:Rule\:of\: Differentiation :}} \\ \\ :\implies\sf{\dfrac{d(vu)}{dx} = v\cdot\dfrac{du}{dx} + u\cdot\dfrac{dv}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = [(cx + d)^{m}\cdot\dfrac{d[(ax + b)^{n}]}{dx} + [(ax + b)^{n}\cdot\dfrac{d[(cx + d)^{m}]}{dx}} \\ \\ \\$ First, let US find the derivative of (ax + b)^n : $:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(ax + b)^{n}]}{dx}} \\ \\$ By applying the chain rule of differentiation, we get : $\underline{\sf{\bigstar\: Chain\:Rule\:of\: Differentiation :}} \\ \\ :\implies \sf{\dfrac{dy}{dx} = \dfrac{dy}{du}\cdot\dfrac{du}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(ax + b)^{n}]}{d(ax + b)}\cdot\dfrac{d(ax + b)}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = n(ax + b)^{(n - 1)}\cdot\dfrac{d(ax + b)}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = n(ax + b)^{(n - 1)}\cdot\dfrac{d(ax)}{dx} + \dfrac{d(b)}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = n(ax + b)^{(n - 1)}\cdot(a + 0)} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = an(ax + b)^{(n - 1)}} \\ \\$ $\boxed{\therefore \sf{\dfrac{d[(ax + b)^{n}]}{dx} = an(ax + b)^{(n - 1)}}} \\ \\$ Now, the derivative of (cx + d)^m : $:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(cx + d)^{m}]}{dx}} \\ \\$ By applying the chain rule of differentiation, we get : $\underline{\sf{\bigstar\: Chain\:Rule\:of\: Differentiation :}} \\ \\ :\implies \sf{\dfrac{dy}{dx} = \dfrac{dy}{du}\cdot\dfrac{du}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(cx + d)^{m}]}{d(cx + d)}\cdot\dfrac{d(cx + d)}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = m(cx + d)^{(m - 1)}\cdot\dfrac{d(cx + d)}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = m(cx + d)^{(m - 1)}\cdot\dfrac{d(cx)}{dx} + \dfrac{d(d)}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = m(cx + d)^{(m - 1)}\cdot(c + 0)} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = cm(cx + d)^{(m - 1)}} \\ \\$ $\boxed{\therefore \sf{\dfrac{d[(cx + d)^{m}]}{dx} = cm(cx + d)^{(m - 1)}}} \\ \\$ Now by SUBSTITUTING the derivative of (ax + b)^n and (cx + d)^m in the EQUATION, we get : $:\implies \sf{\dfrac{dy}{dx} = [(cx + d)^{m}\cdot\dfrac{d[(ax + b)^{n}]}{dx} + [(ax + b)^{n}\cdot\dfrac{d[(cx + d)^{m}]}{dx}} \\ \\ \\$ $:\implies \sf{\dfrac{dy}{dx} = [(cx + d)^{m}\cdot an(ax + b)^{(n - 1)}] + [(ax + b)^{n}\cdot cm(cx + d)^{(m - 1)}]} \\ \\ \\$ By taking (ax + b)^(n - 1) and (cx + d)^(m - 1) common in the equation, we get : $:\implies \sf{\dfrac{dy}{dx} = [cm(cx + d)^{m}\cdot an(ax + b)^{n}] + [(ax + b)^{n - 1)}\cdot(cx + d)^{(m - 1)}]} \\ \\ \\$ $\underline{\therefore \sf{\dfrac{dy}{dx} = [cm(cx + d)^{m}\cdot an(ax + b)^{n}] + [(ax + b)^{n - 1)}\cdot(cx + d)^{(m - 1)}]}} \\ \\ \\$

23.

Find the derivative of the following function ( it is to be understood that a, b, c and d are fixed non-zero constants and m and n are integers ) :-

Answer»

Question :

Find the derivative of the following function ( it is to be understood that a, B, c and d are fixed non-zero constants and m and n are INTEGERS ) :-

$\sf \: (ax + b) ^{n} ( {cx + d})^{m}$

Solution :

$:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(ax + b)^{n}\cdot(cx + d)^{m}]}{dx}} \\ \\ \\$

By applying the product rule of differentiation, we get :

$\underline{\sf{\bigstar\:Product\:Rule\:of\: Differentiation :}} \\ \\ :\implies\sf{\dfrac{d(vu)}{dx} = v\cdot\dfrac{du}{dx} + u\cdot\dfrac{dv}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = [(cx + d)^{m}\cdot\dfrac{d[(ax + b)^{n}]}{dx} + [(ax + b)^{n}\cdot\dfrac{d[(cx + d)^{m}]}{dx}} \\ \\ \\$

First,

let US find the derivative of (ax + b)^n :

$:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(ax + b)^{n}]}{dx}} \\ \\$

By applying the chain rule of differentiation, we get :

$\underline{\sf{\bigstar\: Chain\:Rule\:of\: Differentiation :}} \\ \\ :\implies \sf{\dfrac{dy}{dx} = \dfrac{dy}{du}\cdot\dfrac{du}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(ax + b)^{n}]}{d(ax + b)}\cdot\dfrac{d(ax + b)}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = n(ax + b)^{(n - 1)}\cdot\dfrac{d(ax + b)}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = n(ax + b)^{(n - 1)}\cdot\dfrac{d(ax)}{dx} + \dfrac{d(b)}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = n(ax + b)^{(n - 1)}\cdot(a + 0)} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = an(ax + b)^{(n - 1)}} \\ \\$

$\boxed{\therefore \sf{\dfrac{d[(ax + b)^{n}]}{dx} = an(ax + b)^{(n - 1)}}} \\ \\$

Now, the derivative of (cx + d)^m :

$:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(cx + d)^{m}]}{dx}} \\ \\$

By applying the chain rule of differentiation, we get :

$\underline{\sf{\bigstar\: Chain\:Rule\:of\: Differentiation :}} \\ \\ :\implies \sf{\dfrac{dy}{dx} = \dfrac{dy}{du}\cdot\dfrac{du}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = \dfrac{d[(cx + d)^{m}]}{d(cx + d)}\cdot\dfrac{d(cx + d)}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = m(cx + d)^{(m - 1)}\cdot\dfrac{d(cx + d)}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = m(cx + d)^{(m - 1)}\cdot\dfrac{d(cx)}{dx} + \dfrac{d(d)}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = m(cx + d)^{(m - 1)}\cdot(c + 0)} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = cm(cx + d)^{(m - 1)}} \\ \\$

$\boxed{\therefore \sf{\dfrac{d[(cx + d)^{m}]}{dx} = cm(cx + d)^{(m - 1)}}} \\ \\$

Now by SUBSTITUTING the derivative of (ax + b)^n and (cx + d)^m in the EQUATION, we get :

$:\implies \sf{\dfrac{dy}{dx} = [(cx + d)^{m}\cdot\dfrac{d[(ax + b)^{n}]}{dx} + [(ax + b)^{n}\cdot\dfrac{d[(cx + d)^{m}]}{dx}} \\ \\ \\$

$:\implies \sf{\dfrac{dy}{dx} = [(cx + d)^{m}\cdot an(ax + b)^{(n - 1)}] + [(ax + b)^{n}\cdot cm(cx + d)^{(m - 1)}]} \\ \\ \\$

By taking (ax + b)^(n - 1) and (cx + d)^(m - 1) common in the equation, we get :

$:\implies \sf{\dfrac{dy}{dx} = [cm(cx + d)^{m}\cdot an(ax + b)^{n}] + [(ax + b)^{n - 1)}\cdot(cx + d)^{(m - 1)}]} \\ \\ \\$

$\underline{\therefore \sf{\dfrac{dy}{dx} = [cm(cx + d)^{m}\cdot an(ax + b)^{n}] + [(ax + b)^{n - 1)}\cdot(cx + d)^{(m - 1)}]}} \\ \\ \\$

Discussion

24.	How many days are between june 26 to may 22
Answer» Answer: 330 DAYS Step-by-step explanation: 330 days are between JUNE 26 to MAY 22.

24.

How many days are between june 26 to may 22

Answer»

Answer:

330 DAYS

Step-by-step explanation:

330 days are between JUNE 26 to MAY 22.

Discussion

25.	Evaluate each of the following ising suitable identities: (i) 104^3 (ii)999^3
Answer» I HOPE you LIKE the ANSWER...

25.

Evaluate each of the following ising suitable identities: (i) 104^3 (ii)999^3

Answer»

I HOPE you LIKE the ANSWER...

Discussion

26.	Sharmila had 5/6 portion of the cake. She gave 2/6 portion of the whole cake to her brother, then how much cake will remain with her? ( solve with the help of figure)
Answer» $\sf \underline \purple { Questions }$ SHARMILA had 5/6 portion of the cake. She gave 2/6 portion of the whole cake to her BROTHER, then how much cake will REMAIN with her? ( SOLVE with the help of figure) $\sf \underline \pink { Answer }$ Answer: 3/6 5/6 - 2/6 = 3/6

26.

Sharmila had 5/6 portion of the cake. She gave 2/6 portion of the whole cake to her brother, then how much cake will remain with her? ( solve with the help of figure)

Answer»

$\sf \underline \purple { Questions }$

SHARMILA had 5/6 portion of the cake. She gave 2/6 portion of the whole cake to her BROTHER, then how much cake will REMAIN with her? ( SOLVE with the help of figure)

$\sf \underline \pink { Answer }$

Answer: 3/6 5/6 - 2/6 = 3/6

Discussion

27.	2+tan 30°\1+tan 30°×tan 30
Answer» Step-by-step EXPLANATION: We know that, TAN 30⁰=1/3 so, 2tan30⁰/1+tan²30⁰ 2*(1/√3)/1+(1/√3)² 2/√3/1+1/3 Answer

27.

2+tan 30°\1+tan 30°×tan 30

Answer»

Step-by-step EXPLANATION:

We know that,

TAN 30⁰=1/3

so, 2tan30⁰/1+tan²30⁰

2*(1/√3)/1+(1/√3)²

2/√3/1+1/3 Answer

Discussion

28.	7. The point which lies on both axis .
Answer» Answer: The POINT at which the TWO axes INTERSECT is called the ORIGIN. The origin is at 0 on the x-axis and 0 on the y-axis. Therefore,(0,0) LIES on both the axis.

28.

7. The point which lies on both axis .

Answer»

Answer:

The POINT at which the TWO axes INTERSECT is called the ORIGIN. The origin is at 0 on the x-axis and 0 on the y-axis. Therefore,(0,0) LIES on both the axis.

Discussion

29.	obtain the quadratic polynomial with the following condition the sum of zeros=1/3;the product of zeros=1/2
Answer» ANSWER: fuy7uj8yi to 75ijyn97bk

29.

obtain the quadratic polynomial with the following condition the sum of zeros=1/3;the product of zeros=1/2

Answer»

ANSWER:

fuy7uj8yi to 75ijyn97bk

Discussion

30.	6x²÷3x is equal to how much
Answer» Answer: 2x Step-by-step EXPLANATION: $6 {x}^{2} \div 3x = \frac{6 {x}^{2} }{3x} = 2x$

30.

6x²÷3x is equal to how much

Answer»

Answer:

2x

Step-by-step EXPLANATION:

$6 {x}^{2} \div 3x = \frac{6 {x}^{2} }{3x} = 2x$

Discussion

31.	The heights (incm) of Students of a class are asfallows: 155,161.145,149.150.145.152.145,140 Find the mean median and made of this data.
Answer» ANSWER: the MEDIAN U have have to FIND VIA the

31.

The heights (incm) of Students of a class are asfallows: 155,161.145,149.150.145.152.145,140 Find the mean median and made of this data.

Answer»

ANSWER:

the MEDIAN U have have to FIND VIA the

Discussion

32.	(-3 4/9)additive inverse
Answer» Answer: 31/9 Step-by-step explanation: $- 3 \times \frac{4}{9}$ = - 31 / 9 Ka ADDITIVE inverse 31 /9 HAI. I *HOPE* it is *useful* *for* *you. PLZ* *MARK* me as *brainlist* *answer*.

32.

(-3 4/9)additive inverse

Answer»

Answer:

31/9

Step-by-step explanation:

$- 3 \times \frac{4}{9}$

= - 31 / 9

Ka ADDITIVE inverse

31 /9 HAI.

I HOPE it is useful for you.

PLZ MARK me as brainlist answer.

Discussion

33.	Challenge for just fully qualified answerers not for others!• A table top measures 2 m 25 cm by 1 m 50 cm. What is perimeter of the table. Give anser in both units one by one. • A rectangular piece of land measure 0.7 km by 0.5 km Each side is to be fenced with r rows of wires. What is length of wire needed? • The lid of rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of he tape required? • Show that perimeter of rectangle is 2(l+b) units. Note! • I need 100% qualitied answer. Need fully explained answer. It is ok if you miss any one step! • Questions are more that's why given more points than 5. answer properly. Request! • Moderators if "answers are qualitied and proper fully" then please verify them because it is easy to trust on them from my side. Please do that on answers.Advanced thanks to all!!
Answer» ANSWER: • Length of table = 2m 25cm Breadth of table = 1m 50cm Perimeter of table = 2 ( L + B ) = 2 ( 225 + 150 ) = 2 × 375 = 750 cm = 7m 50cm • Length of rectangular land = 700M Breadth of rectangular land = 500m Perimeter of rectangular land = 2( l + b ) = 2( 700 + 500) = 2 × 1200 = 2400m .°. Length of the wire = 2.4 km or 2400m. • Length of the rectangular box = 40 cm Breadth of the rectangular box = 10 cm Perimeter of rectangular box = 2 ( l + b ) = 2 ( 40 + 10 ) = 2 × 50 = 100 cm. .°. Length of tape = 100 cm. Be my follower. If this answer is helpful so mark my answer as brainlient answer.

33.

Challenge for just fully qualified answerers not for others!• A table top measures 2 m 25 cm by 1 m 50 cm. What is perimeter of the table. Give anser in both units one by one. • A rectangular piece of land measure 0.7 km by 0.5 km Each side is to be fenced with r rows of wires. What is length of wire needed? • The lid of rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of he tape required? • Show that perimeter of rectangle is 2(l+b) units. Note! • I need 100% qualitied answer. Need fully explained answer. It is ok if you miss any one step! • Questions are more that's why given more points than 5. answer properly. Request! • Moderators if "answers are qualitied and proper fully" then please verify them because it is easy to trust on them from my side. Please do that on answers.Advanced thanks to all!!

Answer»

ANSWER:

• Length of table = 2m 25cm

Breadth of table = 1m 50cm

Perimeter of table = 2 ( L + B )

= 2 ( 225 + 150 )

= 2 × 375

= 750 cm

= 7m 50cm

• Length of rectangular land = 700M

Breadth of rectangular land = 500m

Perimeter of rectangular land = 2( l + b )

= 2( 700 + 500)

= 2 × 1200

= 2400m

.°. Length of the wire = 2.4 km or 2400m.

• Length of the rectangular box = 40 cm

Breadth of the rectangular box = 10 cm

Perimeter of rectangular box = 2 ( l + b )

= 2 ( 40 + 10 )

= 2 × 50

= 100 cm.

.°. Length of tape = 100 cm.

Be my follower. If this answer is helpful so mark my answer as brainlient answer.

Discussion

34.	A water tank is 2 m long, 1 m wide and 50 cm deep. How many litres of water can it hold
Answer» Given, length of the tank = 2m BREATH of the tank = 1M height of the tank = 50cm or 0.5m according to the question, Volume of the tank = Length x Breath x Height = ( 2 X 1 X 0.5 )m = 1m CUBE we know that, 1 m cube = 1000 L Thus, the tank can hold UPTO 1000 L of water .

34.

A water tank is 2 m long, 1 m wide and 50 cm deep. How many litres of water can it hold

Answer»

Given,

length of the tank = 2m

BREATH of the tank = 1M

height of the tank = 50cm or 0.5m

according to the question,

Volume of the tank = Length x Breath x Height

= ( 2 X 1 X 0.5 )m

= 1m CUBE

we know that,

1 m cube = 1000 L

Thus, the tank can hold UPTO 1000 L of water .

Discussion

35.	In the following clock, draw the right angle,acute angle and obtuse angle
Answer» ANSWER: HOPEFULLY it will WORK ☺️☺️

35.

In the following clock, draw the right angle,acute angle and obtuse angle

Answer»

ANSWER:

HOPEFULLY it will WORK ☺️☺️

Discussion

36.	19. Find the least number by which 1800 should be multiplied sothat it becomes a perfect square. Also, find the square root ofthe perfect square thus obtained.
Answer» ANSWER: it is WRONG QUESTIOM because $42 \times 42 = 1764$

36.

19. Find the least number by which 1800 should be multiplied sothat it becomes a perfect square. Also, find the square root ofthe perfect square thus obtained.

Answer»

ANSWER:

it is WRONG QUESTIOM because

$42 \times 42 = 1764$

Discussion

37.	एक कोन व त्याचा कोटिकोन यांच्या मापांतील फरक 10° असल्यास मोठ्या कोनाचेमाप कती?
Answer» $x + x = 10 = 90$ $2x - 10 + 10 = 90 - 10$ $2x = 80$ $x = 40$ $x - 10 = 40 - 10$ $= - 30$

37.

एक कोन व त्याचा कोटिकोन यांच्या मापांतील फरक 10° असल्यास मोठ्या कोनाचेमाप कती?

Answer»

$x + x = 10 = 90$

$2x - 10 + 10 = 90 - 10$

$2x = 80$

$x = 40$

$x - 10 = 40 - 10$

$= - 30$

Discussion

38.	Sia, Mia, and Tia got together for a round-robin badminton tournament, where, as usual, the winner stays on after eachgame to play the person who sat out that game. At the end of their afternoon, Mia is exhausted, having played the lastseven straight games. Sia, who is less exhausted, tallies up the games played: Sia played eight games.Mia played 12 games. Tia played 14 games. Who won the fourth game against whom?(a) Tia beat Sia(b) Mia beat Tia(c) Sia beat Tia(d) Tia beat Mia
Answer» ANSWER:A yes a is it correct Step-by-step EXPLANATION:

38.

Sia, Mia, and Tia got together for a round-robin badminton tournament, where, as usual, the winner stays on after eachgame to play the person who sat out that game. At the end of their afternoon, Mia is exhausted, having played the lastseven straight games. Sia, who is less exhausted, tallies up the games played: Sia played eight games.Mia played 12 games. Tia played 14 games. Who won the fourth game against whom?(a) Tia beat Sia(b) Mia beat Tia(c) Sia beat Tia(d) Tia beat Mia

Answer»

ANSWER:A

yes

a

is it correct

Step-by-step EXPLANATION:

Discussion

39.	13. A man sold two watches for 5568 each, one at a profit of 16% and other at a loss of 20%.a.Find the cost price of the two watches.b. Does the man gain or lose in the whole transaction?C.How much is the gain or loss?
Answer» Step-by-step EXPLANATION: a) cp of WATCHES are 4800 and 6960 b) loss c)5.30 loss percentage or 624 rupees loss

39.

13. A man sold two watches for 5568 each, one at a profit of 16% and other at a loss of 20%.a.Find the cost price of the two watches.b. Does the man gain or lose in the whole transaction?C.How much is the gain or loss?

Answer»

Step-by-step EXPLANATION:

a) cp of WATCHES are 4800 and 6960

b) loss

c)5.30 loss percentage or 624 rupees loss

Discussion

40.	If the cost of 1 eraser is p and cost of 1 pencil is q, then cost of 2 eraser and 3 pencil is :
Answer» ANSWER: p×2 + q×3 Step-by-step EXPLANATION: hope you understand! N it HELPS U dear... thanks for ur question

40.

If the cost of 1 eraser is p and cost of 1 pencil is q, then cost of 2 eraser and 3 pencil is :

Answer»

ANSWER:

p×2 + q×3

Step-by-step EXPLANATION:

hope you understand!

N it HELPS U dear... thanks for ur question

Discussion

41.	The first four terms of an A-P. having thefirst term two 2 and the common difference
Answer» For a is 2 and d is d Ap is 2, 2+d, 2+2d, 2+3d ,2+4d

41.

The first four terms of an A-P. having thefirst term two 2 and the common difference

Answer»

For a is 2 and d is d

Ap is

2, 2+d, 2+2d, 2+3d ,2+4d

Discussion

42.	Solve the following questions.1) Use the factor theorem to determined whether x + 3 is a factor of x2 + 2x - 3 or not.
Answer» ANSWER: $x + 3 \: \: is \: \: a \: \: factor \: \: of \: \: {x}^{2} + 2x - 3 \\$ Step-by-step EXPLANATION: ${x}^{2} + 2x - 3 \\ {x}^{2} + 3x - x - 3 \\ x(x + 3) - 1(x + 3) \\ (x + 3)(x - 1)$

42.

Solve the following questions.1) Use the factor theorem to determined whether x + 3 is a factor of x2 + 2x - 3 or not.

Answer»

ANSWER:

$x + 3 \: \: is \: \: a \: \: factor \: \: of \: \: {x}^{2} + 2x - 3 \\$

Step-by-step EXPLANATION:

${x}^{2} + 2x - 3 \\ {x}^{2} + 3x - x - 3 \\ x(x + 3) - 1(x + 3) \\ (x + 3)(x - 1)$

Discussion

43.	On which axis or quadrant the (-5,-4) lies
Answer» Answer: -4 Step-by-step EXPLANATION: i HOPE it's HELP full by

43.

On which axis or quadrant the (-5,-4) lies

Answer»

Answer:

-4

Step-by-step EXPLANATION:

i HOPE it's HELP full

by

Discussion

44.	Koi Hai Jo Is Question ko solve karne me meri help kar sakta hai
Answer» Step-by-step EXPLANATION: have a WONDERFUL DAY ahead keep SPARKLING

44.

Koi Hai Jo Is Question ko solve karne me meri help kar sakta hai

Answer»

Step-by-step EXPLANATION:

have a WONDERFUL DAY ahead

keep SPARKLING

Discussion

45.	The length of the diagonal of a square is 12√2 cm. Find its area and perimeter
Answer» Step-by-step EXPLANATION: side=12cm area {12}^2=144 spcm perimeter=4×12=48 CM

45.

The length of the diagonal of a square is 12√2 cm. Find its area and perimeter

Answer»

Step-by-step EXPLANATION:

side=12cm

area {12}^2=144 spcm

perimeter=4×12=48 CM

Discussion

46.	Solution of simultaneousequations by Crammer's rule isconsistent ifसमीकरणों का हलक्रेमर रूल से कोन्सिस्टंट होगा यदि
Answer» from where do U GET this MUCH QUESTION

Discussion

47.	The total number of factors of prime number is
Answer» Answer: 2 Step-by-step EXPLANATION: A PRIME no. has only 2 factors-1 and the no. itself.

47.

The total number of factors of prime number is

Answer»

Answer:

2

Step-by-step EXPLANATION:

A PRIME no. has only 2 factors-1 and the no. itself.

Discussion

48.	Consider the arithmetic sequence 5,8 11...find the position of 302 in this sequence
Answer» Step-by-step explanation: a =5 d= 8-5=3 an = 302 N =? an = a+ (n-1) d 302= 5 +( n-1) 3 302 - 5 = (n - 1) 3 297 = (n-1) 3 297/3 = n-1 99 = n-1 N= 99+1 =100 Therefore n =100

48.

Consider the arithmetic sequence 5,8 11...find the position of 302 in this sequence

Answer»

Step-by-step explanation:

a =5

d= 8-5=3

an = 302

N =?

an = a+ (n-1) d

302= 5 +( n-1) 3

302 - 5 = (n - 1) 3

297 = (n-1) 3

297/3 = n-1

99 = n-1

N= 99+1 =100

Therefore n =100

Discussion

49.	Three times the sum of 4 and -2q
Answer» Answer: 3X+4-2Q Step-by-step EXPLANATION:

49.

Three times the sum of 4 and -2q

Answer»

Answer:

3X+4-2Q

Step-by-step EXPLANATION:

Discussion

50.	How many two digit numbers ae divisible by 4 ?
Answer» <P>Step-by-step EXPLANATION: the SERIES of 2-digit numbers which are divisible by 4 consists of a TOTAL 22 terms. Therefore, there are a total 22 two-digit numbers which are divisible by 4. :-P:-P

50.

How many two digit numbers ae divisible by 4 ?

Answer»

<P>Step-by-step EXPLANATION:

the SERIES of 2-digit numbers which are divisible by 4 consists of a TOTAL 22 terms. Therefore, there are a total 22 two-digit numbers which are divisible by 4.

:-P:-P

Discussion

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