332354 + Interview Questions in Secondary School in Math

1.	To construct a square, minimum measurement of how many sides should be given
Answer» ANSWER: OH my GOOOD I don't KNOW sorryyyyyyy

1.

To construct a square, minimum measurement of how many sides should be given

Answer»

ANSWER:

OH my GOOOD I don't KNOW sorryyyyyyy

Discussion

2.	19. Find the least number by which the following numbers mustbe divided so that the quotient is a perfect square. Also find thesquare root of the quotient.a. 1458
Answer» ANSWER: I don t KNOW answer . ... MARK as BRAINLIEST and THANKS

2.

19. Find the least number by which the following numbers mustbe divided so that the quotient is a perfect square. Also find thesquare root of the quotient.a. 1458

Answer»

ANSWER:

I don t KNOW answer

.

...

MARK as BRAINLIEST and THANKS

Discussion

3.	Find the greatest number of four digits which is exactly divisible by 10, 14, 16, 18
Answer» Answer: L C M Step-by-step explanation: We have to do L C M of 10, 14, 16, 18 and the ANS IS 5040

3.

Find the greatest number of four digits which is exactly divisible by 10, 14, 16, 18

Answer»

Answer:

L C M

Step-by-step explanation:

We have to do L C M of

10, 14, 16, 18 and the

ANS IS 5040

Discussion

4.	11. A rectangle is made up of 12 squares of side 1 cm.What possible dimensions can the rectangle have?1) A rectangle measures 30 cm hy 25
Answer» Step-by-step EXPLANATION: AREA of RECTANGLE - area of square 3025-11 75-1 74 is the ANSWER

4.

11. A rectangle is made up of 12 squares of side 1 cm.What possible dimensions can the rectangle have?1) A rectangle measures 30 cm hy 25

Answer»

Step-by-step EXPLANATION:

AREA of RECTANGLE - area of square

30*25-1*1

75-1

74 is the ANSWER

Discussion

5.	A trader allows two successive discounts of 50 % and 25 % on a pair of jeans . If its marked price is ₹ 3600 , find the selling price ? *
Answer» Answer: *SP after first discount=50% of 3600=530=150 SP market price minus discount=3600-150=3450 SP after second discount EQUALS to 25% of3450=862.5 SP SP equals to market price minus discount = 3450 - 8 6 2.5=2587.5 final price rupees 258 7.5**

5.

A trader allows two successive discounts of 50 % and 25 % on a pair of jeans . If its marked price is ₹ 3600 , find the selling price ? *

Answer»

Answer:

SP after first discount=50% of 3600=5*30=150

SP market price minus discount=3600-150=3450

SP after second discount EQUALS to 25% of3450=862.5

SP SP equals to market price minus discount = 3450 - 8 6 2.5=2587.5

final price rupees 258 7.5

Discussion

6.	4x²- 7x²+3 =0 quadratic equation
Answer» Given: 4x²- 7x²+3 =0 To Find: The ROOT of the equation Understanding the concept, How do we find it? so, firstly we factorise the QUADRACTIC equation into simple products with which make theem to linear equations so, that on further simplifing we get the roots of the quadratic equation $\\\\$ $\\$ here, As we can see that, it is a quadractic equation so, thee equation should have two solutions or two zeros. Simlarly a cubic polynomial has 3 solutions and a linear equation has 1 solution. Solution: $\longrightarrow \; \tt 4x^{2} - 7x^{2} + 3=0$ now, we subract the like terms in th eequation which are 4x^2 and 7x^2 $\\ \longrightarrow \; \tt 3x^{2} + 3 = 0$ here let's transpose the term 3 form L.H.S to R.H.S changing its singh from positive to negetive $\longrightarrow \; \tt - 3x^{2} = - 3$ Now let's transpose the NUMBER -3 which is multipliying the term x^ 2 in the left hadn SID of the equation similarly the sign here too changs from multplication to division $\longrightarrow \; \tt x^{2} = - 3 \div - 3\\ \\ \longrightarrow \; \tt x^{2} = 1 \;\;$ now lt's find the square root of 1 to fin th valu of x $\longrightarrow \; \tt x = \sqrt{1}$ case (i) $\dashrightarrow \; \tt x = 1$ case (ii) $\dashrightarrow \; \tt x = - 1$ Hence, th roots of the equation are 1 and -1 respctivly More To Know: Factorising Trinomials Of The Form ax^2 + bx + c Example ; 2x² + 7x + 5 whil factorising equations in such form we have to first multiply the first term with the last teerm in the polynomial and then chck to that w should find two numbers WHOSE sum is 7 and the product is 2 times 5 , which is the number 10 . so, the numbers are two and five now let's factorise, ↠ 2x² + 7x + 5 ↠ 2x² + 2x + 5x + 5 ↠ 2x( x + 1 ) + 5( x + 1 ) ↠ ( x + 1 ) ( 2x + 5 ) Now, let's find th roots ↠ x + 1 = 0 ↠ x = - 1 second root ↠ 2x + 5 = 0 ↠ 2x = - 5 ↠ x = - 5/2 hope this helps

6.

4x²- 7x²+3 =0 quadratic equation

Answer»

Given:

4x²- 7x²+3 =0

To Find:

The ROOT of the equation

Understanding the concept,

How do we find it?

so, firstly we factorise the QUADRACTIC equation into simple products with which make theem to linear equations so, that on further simplifing we get the roots of the quadratic equation

$\\\\$ $\\$

here,

As we can see that, it is a quadractic equation so, thee equation should have two solutions or two zeros. Simlarly a cubic polynomial has 3 solutions and a linear equation has 1 solution.

Solution:

$\longrightarrow \; \tt 4x^{2} - 7x^{2} + 3=0$

now, we subract the like terms in th eequation which are 4x^2 and 7x^2

$\\ \longrightarrow \; \tt 3x^{2} + 3 = 0$

here let's transpose the term 3 form L.H.S to R.H.S changing its singh from positive to negetive

$\longrightarrow \; \tt - 3x^{2} = - 3$

Now let's transpose the NUMBER -3 which is multipliying the term x^ 2 in the left hadn SID of the equation similarly the sign here too changs from multplication to division

$\longrightarrow \; \tt x^{2} = - 3 \div - 3\\ \\ \longrightarrow \; \tt x^{2} = 1 \;\;$

now lt's find the square root of 1 to fin th valu of x

$\longrightarrow \; \tt x = \sqrt{1}$

case (i)

$\dashrightarrow \; \tt x = 1$

case (ii)

$\dashrightarrow \; \tt x = - 1$

Hence,

th roots of the equation are 1 and -1 respctivly

More To Know:

Factorising Trinomials Of The Form ax^2 + bx + c

Example ;

2x² + 7x + 5

whil factorising equations in such form we have to first multiply the first term with the last teerm in the polynomial and then chck to that w should find two numbers WHOSE sum is 7 and the product is 2 times 5 , which is the number 10 .

so, the numbers are two and five

now let's factorise,

↠ 2x² + 7x + 5

↠ 2x² + 2x + 5x + 5

↠ 2x( x + 1 ) + 5( x + 1 )

↠ ( x + 1 ) ( 2x + 5 )

Now, let's find th roots

↠ x + 1 = 0

↠ x = - 1

second root

↠ 2x + 5 = 0

↠ 2x = - 5

↠ x = - 5/2

hope this helps

Discussion

7.	this is from 10th class ssc 7th chapter exercise 7.1 15th one 15 find a relation between x and y such that the point x , y is equidistant from the points (- 2,-8) and (- 3 ,-5)
Answer» Step-by-step EXPLANATION: I REALLY don't KNOW SORRY

7.

this is from 10th class ssc 7th chapter exercise 7.1 15th one 15 find a relation between x and y such that the point x , y is equidistant from the points (- 2,-8) and (- 3 ,-5)

Answer»

Step-by-step EXPLANATION:

I REALLY don't KNOW SORRY

Discussion

8.	Exercise 1.51.7-8 + (-2) + 3 * (- 4).3. - 11 - 1-6 - (3 - 5(8 - 4 - 1)]].6 14 = (3 of 2 - 3 + 4) - 9(5 – 3).2. 9 - 17 - 24 + (8 + 6 x 2 - 16)}.4. (-3) × (-12) + (-4) + 3 * 6.please ans fast i will mark him as brainlist
Answer» Answer: bhot EASY ya to him apna CLASS ma bhot ABA KYA

8.

Exercise 1.51.7-8 + (-2) + 3 * (- 4).3. - 11 - 1-6 - (3 - 5(8 - 4 - 1)]].6 14 = (3 of 2 - 3 + 4) - 9(5 – 3).2. 9 - 17 - 24 + (8 + 6 x 2 - 16)}.4. (-3) × (-12) + (-4) + 3 * 6.please ans fast i will mark him as brainlist

Answer»

Answer:

bhot EASY ya to him apna CLASS ma bhot ABA KYA

Discussion

9.	Find the height of cylinder if the volume of cylinder is 2816 cu.cm and radius of base is 8.
Answer» ANSWER: $h = 14 \: \: \: cm.$ Step-by-step EXPLANATION: $volume = \pi {r}^{2} h \\ \\ 2816 = \frac{22}{7} \times {8}^{2} \times h \\ \\ h = \frac{2816 \times 7}{22 \times {8}^{2} } \\ \\ h = 14 \: \: \: cm.$

9.

Find the height of cylinder if the volume of cylinder is 2816 cu.cm and radius of base is 8.

Answer»

ANSWER:

$h = 14 \: \: \: cm.$

Step-by-step EXPLANATION:

$volume = \pi {r}^{2} h \\ \\ 2816 = \frac{22}{7} \times {8}^{2} \times h \\ \\ h = \frac{2816 \times 7}{22 \times {8}^{2} } \\ \\ h = 14 \: \: \: cm.$

Discussion

10.	7a +3b = 10ab , find the error.
Answer» ANSWER: here 7and 3 both have DIFFERENT variables . so we can't add them. Step-by-step explanation: I HOPE THIS IS HELPFUL FOR YOU

10.

7a +3b = 10ab , find the error.

Answer»

ANSWER:

here 7and 3 both have DIFFERENT variables .

so we can't add them.

Step-by-step explanation:

I HOPE THIS IS HELPFUL FOR YOU

Discussion

11.	18. f(x) = (x-1) (x - 2) (x - 3)ன்பெருமமற்றும்மதிப்புகளை காண்க.andvaluesofFind the maximumf (x) = (x-1)(x-2) (x-3).6SNO 15953m
Answer» ANSWER: 9 is the answer Step-by-step EXPLANATION: MARK as BRAINLIEST and THANKS

11.

18. f(x) = (x-1) (x - 2) (x - 3)ன்பெருமமற்றும்மதிப்புகளை காண்க.andvaluesofFind the maximumf (x) = (x-1)(x-2) (x-3).6SNO 15953m

Answer»

ANSWER:

9 is the answer

Step-by-step EXPLANATION:

MARK as BRAINLIEST and THANKS

Discussion

12.	(4x+5y) - (3x+y ) simplify
Answer» ANSWER: x+6y Step-by-step EXPLANATION: (4x+5y) - (3x+y) = 4x+5y-3x+y = 4x-3x+5y+y = x+6y

12.

(4x+5y) - (3x+y ) simplify

Answer»

ANSWER:

x+6y

Step-by-step EXPLANATION:

(4x+5y) - (3x+y)

= 4x+5y-3x+y

= 4x-3x+5y+y

= x+6y

Discussion

13.	Write the algebraic expression for "3 less than twice a number of p"please give me a correct answer with solution
Answer» Answer: 2P-3 Step-by-step explanation: hello friend let the number be p twice the number p = 2p given 3 less than 2p = 2p-3 hope it helps you MARK me BRAINLIEST if you LIKE my explanation

13.

Write the algebraic expression for "3 less than twice a number of p"please give me a correct answer with solution

Answer»

Answer:

2P-3

Step-by-step explanation:

hello friend

let the number be p

twice the number p = 2p

given 3 less than 2p = 2p-3

hope it helps you

MARK me BRAINLIEST if you LIKE my explanation

Discussion

14.	Which of the following cannot be written as(-45)×108
Answer» ANSWER: -4860 this is CORRECT answer

14.

Which of the following cannot be written as(-45)×108

Answer»

ANSWER:

-4860 this is CORRECT answer

Discussion

15.	3. Find the number x if:(a) 150% of x is300
Answer» Step-by-step EXPLANATION: 200 is the ANSWER for above question pls CHECK my explanation above GIVEN

15.

3. Find the number x if:(a) 150% of x is300

Answer»

Step-by-step EXPLANATION:

200 is the ANSWER for above question

pls CHECK my explanation above GIVEN

Discussion

16.	Who are you ??
Answer» ANSWER: HI IAN KRISHNA who are you

16.

Who are you ??

Answer»

ANSWER:

HI IAN KRISHNA who are you

Discussion

17.	Find the zeroes of quadratic polynomial p(x)=x square-x-6
Answer» Answer: =X^2 -x -6 =x^2 +2x -3x -6 =x( x+2 )-3 (x +2 ) =( x+2 )( x -3 ) ZEROES of QUADRATIC polynomial p(x) is -2 and +3

17.

Find the zeroes of quadratic polynomial p(x)=x square-x-6

Answer»

Answer:

=X^2 -x -6

=x^2 +2x -3x -6

=x( x+2 )-3 (x +2 )

=( x+2 )( x -3 )

ZEROES of QUADRATIC polynomial p(x) is -2 and +3

Discussion

18.	From the given co-ordinate,state to which quardrant do the following points belong:A(-4,-1) B(5,-8)
Answer» ANSWER: co ORDINATE A belongs to 3RD QUADRANT, and B is 4th quadrant

18.

From the given co-ordinate,state to which quardrant do the following points belong:A(-4,-1) B(5,-8)

Answer»

ANSWER:

co ORDINATE A belongs to 3RD QUADRANT, and B is 4th quadrant

Discussion

19.	. Find the equation of a line parallel to y axis, at a distance of 5/2 units to the left of y axis
Answer» ANSWER: X= -5/2 or x= -2.5 Step-by-step EXPLANATION: PLEASE be my FOLLOWER

19.

. Find the equation of a line parallel to y axis, at a distance of 5/2 units to the left of y axis

Answer»

ANSWER:

X= -5/2 or x= -2.5

Step-by-step EXPLANATION:

PLEASE be my FOLLOWER

Discussion

20.	The sides of a triangle are in the ratio 13:14:15. If the perimeter of the triangle is 84cm Find the area of the Triangle.
Answer» Step-by-step EXPLANATION: this is ANS for your QUESTION

20.

The sides of a triangle are in the ratio 13:14:15. If the perimeter of the triangle is 84cm Find the area of the Triangle.

Answer»

Step-by-step EXPLANATION:

this is ANS for your QUESTION

Discussion

21.	Find the value ofif when
Answer» $\large\underline{\bold{Given \:Question - }}$ $\sf \: Find \: the \: value \: of \: (<klux>X</klux>^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - 1) \: when \: x = <klux>8</klux>.$ $\large\underline{\bold{Solution-}}$ We know that $\bf \: {x}^{3} + {y}^{3} = (x + y)( {x}^{2} + {y}^{2} - xy)$ $\tt \: Put \: x \: = \: {x}^{\frac{1}{3} } \: \: and \: \: y \: = \: {x}^{ - \frac{1}{3} } , \: we \: get$ $\bf \: {\bigg( {x}^{\frac{1}{3}}\bigg) }^{3} \:+\:{\bigg( {x}^{ \frac{ - 1}{3} } \bigg) }^{3} = (x^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - x^ \frac{1}{3} x^{ - \frac{1 }{3}} )$ $\bf \: x + {x}^{ - 1} = \sf \: (x^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - 1) \:$ $\bf \: <klux>HENCE</klux>, \: (x^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - 1) \: = x + \dfrac{1}{x}$ Put x = 8, we get $\therefore \: \sf \: x + \dfrac{1}{x} = 8 + \dfrac{1}{8} = \dfrac{64 + 1}{8} = \dfrac{65}{8}$ Hence, The value of $\sf \:\: (x^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - 1) \:, \: when \: x = 8 \: is \: \dfrac{65}{8}$ ADDITIONAL IMPORTANT Identities :- $\boxed{ \bf{ \: {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy}}$ $\boxed{ \bf{ \: {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy}}$ $\boxed{ \bf{ \: {x}^{2} - {y}^{2} = (x + y)(x - y)}}$ $\boxed{ \bf{ \: {(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)}}$ $\boxed{ \bf{ \: {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} }}$ $\boxed{ \bf{ \: {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + {3y}^{2} x - {y}^{3} }}$ $\boxed{ \bf{ \: {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} + xy}}$ $\boxed{ \bf{ \: {x}^{4} - {y}^{4} = (x - y)(x + y)( {x}^{2} + {y}^{2} )}}$

21.

Find the value ofif when

Answer»

$\large\underline{\bold{Given \:Question - }}$

$\sf \: Find \: the \: value \: of \: (<klux>X</klux>^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - 1) \: when \: x = <klux>8</klux>.$

$\large\underline{\bold{Solution-}}$

We know that

$\bf \: {x}^{3} + {y}^{3} = (x + y)( {x}^{2} + {y}^{2} - xy)$

$\tt \: Put \: x \: = \: {x}^{\frac{1}{3} } \: \: and \: \: y \: = \: {x}^{ - \frac{1}{3} } , \: we \: get$

$\bf \: {\bigg( {x}^{\frac{1}{3}}\bigg) }^{3} \:+\:{\bigg( {x}^{ \frac{ - 1}{3} } \bigg) }^{3} = (x^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - x^ \frac{1}{3} x^{ - \frac{1 }{3}} )$

$\bf \: x + {x}^{ - 1} = \sf \: (x^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - 1) \:$

$\bf \: <klux>HENCE</klux>, \: (x^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - 1) \: = x + \dfrac{1}{x}$

Put x = 8, we get

$\therefore \: \sf \: x + \dfrac{1}{x} = 8 + \dfrac{1}{8} = \dfrac{64 + 1}{8} = \dfrac{65}{8}$

Hence,

The value of

$\sf \:\: (x^ \frac{1}{3} + x ^\frac{ - 1}{3} )(x ^\frac{2}{3} + x ^\frac{ - 2}{3} - 1) \:, \: when \: x = 8 \: is \: \dfrac{65}{8}$

ADDITIONAL IMPORTANT Identities :-

$\boxed{ \bf{ \: {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy}}$

$\boxed{ \bf{ \: {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy}}$

$\boxed{ \bf{ \: {x}^{2} - {y}^{2} = (x + y)(x - y)}}$

$\boxed{ \bf{ \: {(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)}}$

$\boxed{ \bf{ \: {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} }}$

$\boxed{ \bf{ \: {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + {3y}^{2} x - {y}^{3} }}$

$\boxed{ \bf{ \: {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} + xy}}$

$\boxed{ \bf{ \: {x}^{4} - {y}^{4} = (x - y)(x + y)( {x}^{2} + {y}^{2} )}}$

Discussion

22.	A road roller takes 500 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 41 cm and its length ia 1 m. (use π = 22/7)
Answer» Answer: 1 REVOLUTION = 2\pi rh2πrh r\ =\ \frac{84}{2\ }cm\r = 2 84 cm = 42cm h = 1m = 100cm CSA = 2\times\frac{22}{7}\times42\times1002× 7 22 ×42×100 = 26400 cm\ ^2CM 2

22.

A road roller takes 500 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 41 cm and its length ia 1 m. (use π = 22/7)

Answer»

Answer:

1 REVOLUTION = 2\pi rh2πrh

r\ =\ \frac{84}{2\ }cm\r =

2

84

cm

= 42cm

h = 1m = 100cm

CSA = 2\times\frac{22}{7}\times42\times1002×

7

22

×42×100

= 26400 cm\ ^2CM

2

Discussion

23.	The surface area of cubiod is 1440sq.cm. The length and breadth of base is 20cm and 12cm respectively. Find the height of cubiod.
Answer» Answer: Sorry BRO but I DONT KNOW the answer. In which class are you

23.

The surface area of cubiod is 1440sq.cm. The length and breadth of base is 20cm and 12cm respectively. Find the height of cubiod.

Answer»

Answer:

Sorry BRO but I DONT KNOW the answer. In which class are you

Discussion

24.	Gsjsolalallakakjanajannanqnnana
Answer» Step-by-step explanation: What is your question Your TUITION in brainly Please GIVE your question

24.

Gsjsolalallakakjanajannanqnnana

Answer»

Step-by-step explanation:

What is your question Your TUITION in brainly Please GIVE your question

Discussion

25.	Using prime factirization. Find cube root of 5832
Answer» ANSWER: Here is your answer

25.

Using prime factirization. Find cube root of 5832

Answer»

ANSWER:

Here is your answer

Discussion

26.	Who ever like this question I will make you brainlist
Answer» ANSWER: what are you saying Step-by-step EXPLANATION: TELL it again

26.

Who ever like this question I will make you brainlist

Answer»

ANSWER:

what are you saying

Step-by-step EXPLANATION:

TELL it again

Discussion

27.	If the mode of the data 5 8 4 55 8 4 47 8 x is 5 then find the value of x
Answer» ANSWER: 5 maximum REPEATED number in data is known as mode. if X BECOME 5 then 5 repeated more and become more of the data Step-by-step explanation: hope it's helpful mark me brainlist please

27.

If the mode of the data 5 8 4 55 8 4 47 8 x is 5 then find the value of x

Answer»

ANSWER:

5 maximum REPEATED number in data is known as mode.

if X BECOME 5 then 5 repeated more and become more of the data

Step-by-step explanation:

hope it's helpful

mark me brainlist please

Discussion

28.	Represent 2/5 and - 4/5 on the same number line
Answer» Answer: REPRESENT the fractions: 2/5, 11/5, -8/5 and -3/5 on a number line. To mark 2/5; move two PARTS on the right-side of zero. To mark 11/5; move eleven parts on the right-side of zero. To mark -8/5; move EIGHT parts on the left-side of zero

28.

Represent 2/5 and - 4/5 on the same number line

Answer»

Answer:

REPRESENT the fractions: 2/5, 11/5, -8/5 and -3/5 on a number line. To mark 2/5; move two PARTS on the right-side of zero. To mark 11/5; move eleven parts on the right-side of zero. To mark -8/5; move EIGHT parts on the left-side of zero

Discussion

29.	खण्ड अ1. एक त्रिभुज की भुजाओं की विमाएं 3cm, 4cm और 5cm है। त्रिभुजका क्षेत्रफल होगाःa) 6cmc) 5cmb)d)8cm10cmक्षेत्रफलहोगा?CS T
Answer» उत्तर दिया है :- त्रिभुज की भुजाओं की विमाएं 3cm, 4cm और 5cm है। ज्ञात करना है :- त्रिभुज का क्षेत्रफल स्पष्टीकरण माना, ∆ABC एक त्रिभुज है ! उपयोगी सूत्र $\dag\boxed{\underline{\tt{\red{\: semiperimeter_{triangle}(S)\:=\:\dfrac{AB+BC+CA}{<klux>2</klux>}}}}}$ $\dag\boxed{\underline{\tt{\orange{\:Area_{triangle}\:=\:\sqrt{S(S-AB)(S-BC)(S-CA)}}}}}$ अब, ==> त्रिभुज की सेमीपेरीमीटर = (3 + 4 + 5)/2 ==> त्रिभुज की सेमीपेरीमीटर (S) = 12/2 ==> त्रिभुज की सेमीपेरीमीटर(S) = 6 cm अब, त्रिभुज का क्षेत्रफल ज्ञात करते हैं, ==> त्रिभुज का क्षेत्रफल = √[6(6-3)(6-4)(6-5)] ==> त्रिभुज का क्षेत्रफल = √[6×3×2×1] ==> त्रिभुज का क्षेत्रफल = √36 ==> त्रिभुज का क्षेत्रफल = 6 cm² अतः त्रिभुज का क्षेत्रफल = 6 cm² ___________________

29.

खण्ड अ1. एक त्रिभुज की भुजाओं की विमाएं 3cm, 4cm और 5cm है। त्रिभुजका क्षेत्रफल होगाःa) 6cmc) 5cmb)d)8cm10cmक्षेत्रफलहोगा?CS T

Answer»

उत्तर

दिया है :-

त्रिभुज की भुजाओं की विमाएं 3cm, 4cm और 5cm है।

ज्ञात करना है :-

त्रिभुज का क्षेत्रफल

स्पष्टीकरण

माना,

∆ABC एक त्रिभुज है !

उपयोगी सूत्र

$\dag\boxed{\underline{\tt{\red{\: semiperimeter_{triangle}(S)\:=\:\dfrac{AB+BC+CA}{<klux>2</klux>}}}}}$

$\dag\boxed{\underline{\tt{\orange{\:Area_{triangle}\:=\:\sqrt{S(S-AB)(S-BC)(S-CA)}}}}}$

अब,

==> त्रिभुज की सेमीपेरीमीटर = (3 + 4 + 5)/2

==> त्रिभुज की सेमीपेरीमीटर (S) = 12/2

==> त्रिभुज की सेमीपेरीमीटर(S) = 6 cm

अब, त्रिभुज का क्षेत्रफल ज्ञात करते हैं,

==> त्रिभुज का क्षेत्रफल = √[6(6-3)(6-4)(6-5)]

==> त्रिभुज का क्षेत्रफल = √[6×3×2×1]

==> त्रिभुज का क्षेत्रफल = √36

==> त्रिभुज का क्षेत्रफल = 6 cm²

अतः

त्रिभुज का क्षेत्रफल = 6 cm²

___________________

Discussion

30.	If n(A) - 15,n (AEB) - 29,n (ACB)=7 then n (B)?
Answer» Answer: MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS Step-by-step EXPLANATION: MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS

30.

If n(A) - 15,n (AEB) - 29,n (ACB)=7 then n (B)?

Answer»

Answer:

MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS

Step-by-step EXPLANATION:

MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS

Discussion

31.	Find the product and sum of the. given zero of a polynomial x2 -6x+5
Answer» Answer: (X - 5)(x - 1) Step-by-step EXPLANATION: x² - 6x + 5 x² - x - 5X + 5 x(x - 1) - 5(x - 1) (x - 5)(x - 1)

31.

Find the product and sum of the. given zero of a polynomial x2 -6x+5

Answer»

Answer:

(X - 5)(x - 1)

Step-by-step EXPLANATION:

x² - 6x + 5

x² - x - 5X + 5

x(x - 1) - 5(x - 1)

(x - 5)(x - 1)

Discussion

32.	The sides of a triangle are in the ratio 13:14:15. If the perimeter of the triangle is 32cm Find the area of the Triangle.
Answer» Answer: 13x+14x+15x = 32 32 x = 32 x= 32/32 x = 1 Sides are 13 ,14 and 15 AREA of triangle by USING HERON's formula = 4√6 Hence , 4√6 is the correct answer

32.

The sides of a triangle are in the ratio 13:14:15. If the perimeter of the triangle is 32cm Find the area of the Triangle.

Answer»

Answer:

13x+14x+15x = 32

32 x = 32

x= 32/32

x = 1

Sides are 13 ,14 and 15

AREA of triangle by USING HERON's formula = 4√6

Hence , 4√6 is the correct answer

Discussion

33.	Conjugate of surd a+ is what/
Answer» ANSWER: jghlmy ydlfjikliiflugipukflu g iiupclj of the correct u very much for your help and support you in whatever way you can get 16 is the best way you can get a nice day and I am not sure if I am going to you and your FAMILY a very happy and PROSPEROUS New year to you and your family a very happy and prosperous New year to you and your family a nice time ijfyokfchoc

33.

Conjugate of surd a+ is what/

Answer»

ANSWER:

jghlmy ydlfjikliiflugipukflu g iiupclj of the correct u very much for your help and support you in whatever way you can get 16 is the best way you can get a nice day and I am not sure if I am going to you and your FAMILY a very happy and PROSPEROUS New year to you and your family a very happy and prosperous New year to you and your family a nice time ijfyokfchoc

Discussion

34.	Ii) Which of the following is not a statementa) 2+2 =4b) 2 is the only even prime numberc) Come hered) Mumbai is not in Maharashtra
Answer» CCOME here MAKE me a PLAYLIST

Discussion

35.	gavin,colin and dan share some sweets in the ratio 2:4:3 gavin gets 24 sweets how many more does colin get over dan
Answer» ANSWER: eedrrrrrrrrdjdjdjdjf

35.

gavin,colin and dan share some sweets in the ratio 2:4:3 gavin gets 24 sweets how many more does colin get over dan

Answer»

ANSWER:

eedrrrrrrrrdjdjdjdjf

Discussion

36.	1. Find the value of the polynomial (5x - 4x7² + 7) at(1) x=0(ii) x = -1(iii) X=3
Answer» ANSWER: x=,0 Step-by-step explanation: 5x-7(28x+1)=0 5x=0 x=0

36.

1. Find the value of the polynomial (5x - 4x7² + 7) at(1) x=0(ii) x = -1(iii) X=3

Answer»

ANSWER:

x=,0

Step-by-step explanation:

5x-7(28x+1)=0 5x=0 x=0

Discussion

37.	The mean of following distribution is 21×1/7.Find value of f.class interval. frequency 0-10 810-20 2220-30 3130-40 f40-50 2Direct method formula :mean=Efx\nShort cut method:mean=A + Efd/EfStep deviation :mean =A+Eft/Ef ×iE is referred as sigma.
Answer» ANSWER: gdfhagjxkhh kvkhxjtxj kvkcjv jgkfubbcjcjvb .hchxh bchchcjnvyv jvj gdgjzfhg hcjchchchc. mblvjchxhxh. mvkvkvkvkvkbkbk Step-by-step EXPLANATION: jbjchxgxhc gjffjgihistdfxgdydudyduugo gjhggfhfjvbcjfjckbcjvjc. kvjvkv njvjc gcj ..BCJ jgjchstxncuf

37.

The mean of following distribution is 21×1/7.Find value of f.class interval. frequency 0-10 810-20 2220-30 3130-40 f40-50 2Direct method formula :mean=Efx\nShort cut method:mean=A + Efd/EfStep deviation :mean =A+Eft/Ef ×iE is referred as sigma.

Answer»

ANSWER:

gdfhagjxkhh kvkhxjtxj kvkcjv jgkfubbcjcjvb .hchxh bchchcjnvyv jvj gdgjzfhg hcjchchchc. mblvjchxhxh. mvkvkvkvkvkbkbk

Step-by-step EXPLANATION:

jbjchxgxhc

gjffjgihistdfxgdydudyduugo

gjhggfhfjvbcjfjckbcjvjc. kvjvkv njvjc

gcj ..BCJ jgjchstxncuf

Discussion

38.	If the egdage of a cube is 1 cm then which of the following is its volume?(A) 6m^3 (B)3m^3(C)1 m^3(D)none of these
Answer» ANSWER: C)1m^3 PLEASE MARK me as BRAINLIEST.

38.

If the egdage of a cube is 1 cm then which of the following is its volume?(A) 6m^3 (B)3m^3(C)1 m^3(D)none of these

Answer»

ANSWER:

C)1m^3

PLEASE MARK me as BRAINLIEST.

Discussion

39.	3. Find the number x if:(a) 150%of xis300
Answer» Answer: 450 Step-by-step explanation: 150%/100×300 x=450

39.

3. Find the number x if:(a) 150%of xis300

Answer»

Answer:

450

Step-by-step explanation:

150%/100×300

x=450

Discussion

40.	If y = (502² - 4x² - 8x) then dydx
Answer» ANSWER: $\bf \frac { dy}{dx} =-8x-8$ Step-by-step EXPLANATION: $y =502^2 -4x^2-8x\\\\\frac{dy}{dx} = \frac { d}{dx} ( 502^2-4x^2-8x)\\\\= 0-4(2x) -8\\\\\bf=-8x-8$

40.

If y = (502² - 4x² - 8x) then dydx

Answer»

ANSWER:

$\bf \frac { dy}{dx} =-8x-8$

Step-by-step EXPLANATION:

$y =502^2 -4x^2-8x\\\\\frac{dy}{dx} = \frac { d}{dx} ( 502^2-4x^2-8x)\\\\= 0-4(2x) -8\\\\\bf=-8x-8$

Discussion

41.	If the lines given by 3x + 2ky = 2 and 2x + 5y + 1 = 0 are parallel, then the vaAT 10. If the common difference of an A.P. is 5, then find the value of018 - 013-11 If we drawn line from the
Answer» Answer: orrect option is C 4 15 CONDITION for the lines to be parallel is a 2 a 1 = b 2 b 1  = c 2 c 1 Here the equations are 3x+2ky=2 and 2x+5y+1=0 So, a 1 =3,b 1 =2k,c 1 =−2 and a 2 =2,b 2 =5,c 2 =1 ∴ a 2 a 1 = 2 3 , b 2 b 1 = 5 2k and c 2 c 1 = 1 −2 =−2 ∴ 5 2k = 2 3 ∴k= 4 15

41.

If the lines given by 3x + 2ky = 2 and 2x + 5y + 1 = 0 are parallel, then the vaAT 10. If the common difference of an A.P. is 5, then find the value of018 - 013-11 If we drawn line from the

Answer»

Answer:

orrect option is

C

4

15

CONDITION for the lines to be parallel is

a

2

a

1

=

b

2

b

1



=

c

2

c

1

Here the equations are

3x+2ky=2 and 2x+5y+1=0

So, a

1

=3,b

1

=2k,c

1

=−2 and a

2

=2,b

2

=5,c

2

=1

∴

a

2

a

1

=

2

3

,

b

2

b

1

=

5

2k

and

c

2

c

1

=

1

−2

=−2

∴

5

2k

=

2

3

∴k=

4

15

Discussion

42.	अनिश्चित घटना की प्रायिकता क्या है?
Answer» ANSWER: yeh MATH Ka question hai KYA

42.

अनिश्चित घटना की प्रायिकता क्या है?

Answer»

ANSWER:

yeh MATH Ka question hai KYA

Discussion

43.	*If polynomial (2x²+2) is divided by (x +2) then the remainder is1️⃣ 82️⃣ 103️⃣ -104️⃣ -8
Answer» ANSWER: 8 is the RIGHT answer me PLEASE

43.

*If polynomial (2x²+2) is divided by (x +2) then the remainder is1️⃣ 82️⃣ 103️⃣ -104️⃣ -8

Answer»

ANSWER:

8 is the RIGHT answer me PLEASE

Discussion

44.	Write the polynomial (x2-2x+3) in coefficient form
Answer» Answer: The INDEX FORM of the polynomial is x² + 2x + 3. Therefore, the coefficient form of the polynomial is (1, 2, 3)

44.

Write the polynomial (x2-2x+3) in coefficient form

Answer»

Answer:

The INDEX FORM of the polynomial is x² + 2x + 3.

Therefore, the coefficient form of the polynomial is (1, 2, 3)

Discussion

45.	Find the value of sin o xcoseco
Answer» ANSWER: hhhuuvgxwssxesxchnko

45.

Find the value of sin o xcoseco

Answer»

ANSWER:

hhhuuvgxwssxesxchnko

Discussion

46.	The HCF of two numbers is 2 and 5 and their LCM is 200. Find the product ab
Answer» Answer: *HOPE* it HELPS!! *PLEASE* *mark* me as BRAINLIEST

46.

The HCF of two numbers is 2 and 5 and their LCM is 200. Find the product ab

Answer»

Answer:

HOPE it HELPS!!

PLEASE mark me as BRAINLIEST

Discussion

47.	2. Draw the diagrammatic representation of electronic configuration ofSodium (Atomic no = 11) atom.
Answer» Atomic NUMBER is given so we can make the electronic configuration very easily, K SHELL( the first shell, will only have two electrons) L shell it can have only 8 electrons not more than that. And M shell will have the leftover electrons. Hope it helped you. MARK it as brilliant.

Discussion

48.	Prom deforced form ofecond number5Find the reduced form of the ratio of the first quantity to second(1) 700, JOS(1) 14 %5 litre 2500 ml (iv) 3 years 4 months 5 years(3.8 kg. 1900 g (vi) 7 minutes 20 seconds 5 min0) Express the following percentages as ratios in the reduced form. sammany persons are required
Answer» Answer: here i don't know it's right or WRONG Step-by-step explanation: 5" (and any subsequent WORDS) was IGNORED because we LIMIT queries to 32 words.

48.

Prom deforced form ofecond number5Find the reduced form of the ratio of the first quantity to second(1) 700, JOS(1) 14 %5 litre 2500 ml (iv) 3 years 4 months 5 years(3.8 kg. 1900 g (vi) 7 minutes 20 seconds 5 min0) Express the following percentages as ratios in the reduced form. sammany persons are required

Answer»

Answer:

here i don't know it's right or WRONG

Step-by-step explanation:

5" (and any subsequent WORDS) was IGNORED because we LIMIT queries to 32 words.

Discussion

49.	9z^2-6zy+y^2 Factories it by using identitie
Answer» Given : kx² - kx + 1 = 0 is the equation. The above equation has equal roots. To find : Appropriate VALUE of K. Explanation : As we KNOW that, for a QUADRATIC equations having equal roots, the D ( discriminant ) must be 0. And, D = b² - 4ac ⇒ ( - k )² - 4 ( k )( 1 ) = 0 the pic's

49.

9z^2-6zy+y^2 Factories it by using identitie

Answer»

Given :

kx² - kx + 1 = 0 is the equation.

The above equation has equal roots.

To find :

Appropriate VALUE of K.

Explanation :

As we KNOW that, for a QUADRATIC equations having equal roots, the D ( discriminant ) must be 0.

And, D = b² - 4ac

⇒ ( - k )² - 4 ( k )( 1 ) = 0

the pic's

Discussion

50.	इमोशंस ओल्ड से 6 क्विंटल ऑफ राइस अट ए प्रॉफिट ऑफ़ से ₹1 क्विंटल ऑफ राइस कॉस्ट हैव टू फिफ्टी एंड हिस टोटल ओवरहेड चार्जेस फॉर ट्रांसलेशन154 रूपीस 1000 फाइंड हिस टोटल प्रॉफिट एंड द सेलिंग प्राइस ऑफ 60 क्विंटल ऑफ राइस
Answer» Answer: Given COST of 1 quintal of rice = Rs. 250 Cost of 600 quintals of rice = 600 x 250 = Rs. 150000 Overhead expenses = Rs. 1000 CP = Rs. (150000 + 1000) = Rs. 151000 Profit % = (Profit/CP) x 100 7 = (Profit /151000) x 100 Profit = 1510 x 7 Profit = Rs. 10570 Now SP = CP + profit = Rs. (151000 + 10570) SP = Rs. 161570Read more on Sarthaks.com - https://www.sarthaks.com/685679/grain-merchant-quintals-profit-quintal-rice-cost-total-overhead-charges-transportation?show=685680#a685680

50.

इमोशंस ओल्ड से 6 क्विंटल ऑफ राइस अट ए प्रॉफिट ऑफ़ से ₹1 क्विंटल ऑफ राइस कॉस्ट हैव टू फिफ्टी एंड हिस टोटल ओवरहेड चार्जेस फॉर ट्रांसलेशन154 रूपीस 1000 फाइंड हिस टोटल प्रॉफिट एंड द सेलिंग प्राइस ऑफ 60 क्विंटल ऑफ राइस

Answer»

Answer:

Given COST of 1 quintal of rice = Rs. 250 Cost of 600 quintals of rice = 600 x 250 = Rs. 150000 Overhead expenses = Rs. 1000 CP = Rs. (150000 + 1000) = Rs. 151000 Profit % = (Profit/CP) x 100 7 = (Profit /151000) x 100 Profit = 1510 x 7 Profit = Rs. 10570 Now SP = CP + profit = Rs. (151000 + 10570) SP = Rs. 161570Read more on Sarthaks.com - https://www.sarthaks.com/685679/grain-merchant-quintals-profit-quintal-rice-cost-total-overhead-charges-transportation?show=685680#a685680

Discussion

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उत्तर

दिया है :-

ज्ञात करना है :-

स्पष्टीकरण

अतः

___________________

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. Find the equation of a line parallel to y axis, at a distance of 5/2 units to the left of y axis

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Find the value ofif when

A road roller takes 500 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 41 cm and its length ia 1 m. (use π = 22/7)

The surface area of cubiod is 1440sq.cm. The length and breadth of base is 20cm and 12cm respectively. Find the height of cubiod.

Using prime factirization. Find cube root of 5832

Who ever like this question I will make you brainlist

If the mode of the data 5 8 4 55 8 4 47 8 x is 5 then find the value of x

Represent 2/5 and - 4/5 on the same number line

खण्ड अ1. एक त्रिभुज की भुजाओं की विमाएं 3cm, 4cm और 5cm है। त्रिभुजका क्षेत्रफल होगाःa) 6cmc) 5cmb)d)8cm10cmक्षेत्रफलहोगा?CS T

If n(A) - 15,n (AEB) - 29,n (ACB)=7 then n (B)?

Find the product and sum of the. given zero of a polynomial x2 -6x+5

The sides of a triangle are in the ratio 13:14:15. If the perimeter of the triangle is 32cm Find the area of the Triangle.

Ii) Which of the following is not a statementa) 2+2 =4b) 2 is the only even prime numberc) Come hered) Mumbai is not in Maharashtra

1. Find the value of the polynomial (5x - 4x7² + 7) at(1) x=0(ii) x = -1(iii) X=3

The mean of following distribution is 21×1/7.Find value of f.class interval. frequency 0-10 810-20 2220-30 3130-40 f40-50 2Direct method formula :mean=Efx\nShort cut method:mean=A + Efd/EfStep deviation :mean =A+Eft/Ef ×iE is referred as sigma.

If the egdage of a cube is 1 cm then which of the following is its volume?(A) 6m^3 (B)3m^3(C)1 m^3(D)none of these

3. Find the number x if:(a) 150%of xis300

If y = (502² - 4x² - 8x) then dydx

If the lines given by 3x + 2ky = 2 and 2x + 5y + 1 = 0 are parallel, then the vaAT 10. If the common difference of an A.P. is 5, then find the value of018 - 013-11 If we drawn line from the

अनिश्चित घटना की प्रायिकता क्या है?

*If polynomial (2x²+2) is divided by (x +2) then the remainder is1️⃣ 82️⃣ 103️⃣ -104️⃣ -8

Write the polynomial (x2-2x+3) in coefficient form

Find the value of sin o xcoseco

2. Draw the diagrammatic representation of electronic configuration ofSodium (Atomic no = 11) atom.

9z^2-6zy+y^2 Factories it by using identitie