332354 + Interview Questions in Secondary School in Math

1.	8 prinamo ka average 20 hai. pahale 6 ward ka average 19 hai and last 7 ward ka average 18 hai yadhi 7 ward 8 ward ka 2/3 ho, to un dono ward ko btao
Answer» OW the ANSWER here soo

Discussion

2.	FREee POINTTS
Answer» ong>Answer: Resistance is a MEASURE of the opposition to current flow in an electrical circuit. Resistance is MEASURED in ohms, SYMBOLIZED by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who STUDIED the relationship between voltage, current and resistance. $\\ \\ hope \: it \: will \: help \: u$

2.

FREee POINTTS

Answer»

ong>Answer:

Resistance is a MEASURE of the opposition to current flow in an electrical circuit. Resistance is MEASURED in ohms, SYMBOLIZED by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who STUDIED the relationship between voltage, current and resistance.

$\\ \\ hope \: it \: will \: help \: u$

Discussion

3.	The elementary function are not closed under
Answer» ONG>Step-by-step EXPLANATION: PLEASE MARK as brainilist please

Discussion

4.	Median of 3,2,3,4, 3, 3, 4
Answer» nding order = 2,3,3,3,3,4,4 median = 3 . . . i HOPE it helps you . . . KEEP smiling ALWAYS

4.

Median of 3,2,3,4, 3, 3, 4

Answer»

nding order = 2,3,3,3,3,4,4

median = 3

.

i HOPE it helps you

.

KEEP smiling ALWAYS

Discussion

5.	The least number which when divided by 35,leaves remainder of 25,when divided by 45 leaves a remainder of 35 and when divided by 55 leaves 45 as remainder, is
Answer» is your ANSWER HOPE it's HELPFUL

Discussion

6.	Rationalise the denominator.(a)1/3-2√2+√5
Answer» ong>Answer: ggyyq is this a GOOD day PLEASE tell us what is this a few things to nhi hogi to the WORLD to always to try ker rahe ho kya h bro please tell I will not receive any link below tft Yui to the fan page PR hi ho typing by flipkart is a

6.

Rationalise the denominator.(a)1/3-2√2+√5

Answer»

ong>Answer:

ggyyq is this a GOOD day PLEASE tell us what is this a few things to nhi hogi to the WORLD to always to try ker rahe ho kya h bro please tell I will not receive any link below tft Yui to the fan page PR hi ho typing by flipkart is a

Discussion

7.	Class 10 quad equation question plz helppppppp
Answer» ERE, on comparing with general equation ax 2 + bx + => c = 0, we get => a = 1 => b = - 3 => c = - m(m + 3) => Now, Discriminant = D = (b² – 4AC) ∴ D = [9 -4 × (-m(m + 3))] => [9 + 4m2 + 12 m] => (2m + 3)2 => Therefore roots of the equation are given by: => X = (-b ± √D)/2a ∴ x = (3 ± (2m + 3))/2 => [(6 + 2m)/2] or [-2m/2] => 3 + m or – m. => Thus the roots of the equation are: - m and m + 3. I hope this will help you DEAR.. Always stay safe and stay healthy..

7.

Class 10 quad equation question plz helppppppp

Answer» ERE, on comparing with general equation ax 2 + bx + => c = 0, we get

=> a = 1

=> b = - 3

=> c = - m(m + 3)

=> Now, Discriminant = D = (b² – 4AC)

∴ D = [9 -4 × (-m(m + 3))]

=> [9 + 4m2 + 12 m]

=> (2m + 3)2

=> Therefore roots of the equation are given by:

=> X = (-b ± √D)/2a

∴ x = (3 ± (2m + 3))/2

=> [(6 + 2m)/2] or [-2m/2]

=> 3 + m or – m.

=> Thus the roots of the equation are: - m and m + 3.

I hope this will help you DEAR..

Always stay safe and stay healthy..

Discussion

8.	What is the probability of the event that a number chosen from 1 to 10,is a prime number
Answer» ong>Answer: The probability will be 2/5 Step-by-step explanation: HERE IS YOUR ANSWER . I HOPE IT MAY HELP YOU . PLEASE MARK ME AS A BRAINLIEST . THANK YOU

8.

What is the probability of the event that a number chosen from 1 to 10,is a prime number

Answer»

ong>Answer:

The probability will be 2/5

Step-by-step explanation:

HERE IS YOUR ANSWER .

I HOPE IT MAY HELP YOU .

PLEASE MARK ME AS A BRAINLIEST .

THANK YOU

Discussion

9.	Find the acute angle between line represented by x^2+xy=0
Answer» ong>Answer: Equation can be WRITTEN as x 2 +y 2 −2xycscα=0 Comparing it with ax 2 +2hxy+by 2 =0 and m 1 +m 2 =− b 2h =2cscα m 1 m 2 = b a =1 tanθ= ∣ ∣ ∣ ∣ ∣ 1+m 1 m 2 m 1 −m 2 ∣ ∣ ∣ ∣ ∣ = ∣ ∣ ∣ ∣ ∣ ∣ 1+m 1 m 2 (m 1 +m 2 ) 2 −4m 1 m 2 ∣ ∣ ∣ ∣ ∣ ∣ = ∣ ∣ ∣ ∣ ∣ ∣ 1+1 (2cscα) 2 −4×1 ∣ ∣ ∣ ∣ ∣ ∣ = 2 2 CSC 2 α−1 =cotα ⇒θ=TAN −1 cotα=tan −1 tan(90 o −α) ⇒θ=90 o −α

9.

Find the acute angle between line represented by x^2+xy=0

Answer»

ong>Answer:

Equation can be WRITTEN as x

2

+y

2

−2xycscα=0

Comparing it with ax

2

+2hxy+by

2

=0

and

m

1

+m

2

=−

b

2h

=2cscα

m

1

m

2

=

b

a

=1

tanθ=

∣

1+m

1

m

2

m

1

−m

2

∣

=

∣

1+m

1

m

2

(m

1

+m

2

)

2

−4m

1

m

2

∣

=

∣

1+1

(2cscα)

2

−4×1

∣

=

2

CSC

2

α−1

=cotα

⇒θ=TAN

−1

cotα=tan

−1

tan(90

o

−α)

⇒θ=90

o

−α

Discussion

10.	Find variance and standard deviationof anyrondomvariable x
Answer» So the VARIANCE of X is the weighted average of the SQUARED deviations from the mean μ, where the weights are given by the probability FUNCTION pX(x) of X. The standard DEVIATION of X is defined to be the SQUARE root of the variance of X. That is, sd(X)=σX=√var(X).

Discussion

11.	If Priya's age is two times the age of her brother.If brother age is x years,then what is priya's age?
Answer» ONG>Answer: 2x Step-by-step explanation: PRIYA age is 2 times of his brother age so, priya age = 2x hope this helps

11.

If Priya's age is two times the age of her brother.If brother age is x years,then what is priya's age?

Answer» ONG>Answer:

2x

Step-by-step explanation:

PRIYA age is 2 times of his brother age

so, priya age = 2x

hope this helps

Discussion

12.	O. On what proposition must water be mixed with spirit to gain 1/6% duy sellingit at cast prices
Answer» the C.P of spirit be = Rs.10 PER litre Then S.P l litre of the MIXTURE = Rs. 11 Profit = 20% Therefore, C.P of the mixture = Rs. [100120×10] = Rs. 25/3 per litre Therefore, Ratio of water and spirit = 1 : 5

12.

O. On what proposition must water be mixed with spirit to gain 1/6% duy sellingit at cast prices

Answer»

the C.P of spirit be = Rs.10 PER litre

Then S.P l litre of the MIXTURE = Rs. 11

Profit = 20%

Therefore, C.P of the mixture = Rs. [100120×10] = Rs. 25/3 per litre

Therefore, Ratio of water and spirit = 1 : 5

Discussion

13.	2 24) The total surface area of a closed cylinder is 3872 cm If its radiusis 14cm, then find the height of the cylinder and the volume of thecylinder.
Answer» ong>Given: Total SURFACE area of a CLOSED cylinder = 3872 m. RADIUS of the cylinder = 14cm. To find: Height & VOLUME of the cylinder? SOLUTION: • Let's consider ABCD is a cylinder. Where, Radius = 14m TSA = 3872m • Let Height of cylinder be h m. ⠀⠀━━━━━━━━━━━━━━━━━━━⠀ « Now, By using the formula, → 2πr (r + h) = 3872 → 2 × 22/7 × 14(14 + h) = 3872 → 2 × 22 × 2(14 + h) = 3872 → 14 + h = 3872/88 → 14 + h = 44 → h = 44 - 14 → h = 30cm ⠀⠀━━━━━━━━━━━━━━━━━━━⠀ « Now, Let's find volume, As we know that, → Volume = πr²h → 22/7 × 14² × 30 → 22/7 × 196 × 30 → 22 × 28 × 30 → 18480cm³ ∴ Hence, Volume of the cylinder is 18480cm³.

13.

2 24) The total surface area of a closed cylinder is 3872 cm If its radiusis 14cm, then find the height of the cylinder and the volume of thecylinder.

Answer»

ong>Given:

Total SURFACE area of a CLOSED cylinder = 3872 m.
RADIUS of the cylinder = 14cm.

To find:

Height & VOLUME of the cylinder?

SOLUTION:

• Let's consider ABCD is a cylinder.

Where,

Radius = 14m
TSA = 3872m

• Let Height of cylinder be h m.

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, By using the formula,

→ 2πr (r + h) = 3872

→ 2 × 22/7 × 14(14 + h) = 3872

→ 2 × 22 × 2(14 + h) = 3872

→ 14 + h = 3872/88

→ 14 + h = 44

→ h = 44 - 14

→ h = 30cm

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, Let's find volume,

As we know that,

→ Volume = πr²h

→ 22/7 × 14² × 30

→ 22/7 × 196 × 30

→ 22 × 28 × 30

→ 18480cm³

∴ Hence, Volume of the cylinder is 18480cm³.

Discussion

14.	Find the ratio in which the segment joining the points (1, -3) and (4, 5) is divided by x-axis? Also, find the coordinates of this point on the x-axis.
Answer» ONG>Answer: I don't know the answer of this QUESTION WHETHER I am produce ready what is your name are you mad very BAD boy

Discussion

15.	The ratio of corresponding sides of Simlartriagles is 3; 5 ; then findthe ration of their areas
Answer» ong>Answer: ratio of their AREAS 9 : 25 Step-by-step EXPLANATION: If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides. This proves that the ratio of the area of two similar triangles is proportional to the squares of the corresponding sides of both the triangles. Area (∆ ABC) : area ( ∆ DEF) = AB² : DE² 3² : 5² = 9 : 25

15.

The ratio of corresponding sides of Simlartriagles is 3; 5 ; then findthe ration of their areas

Answer»

ong>Answer:

ratio of their AREAS 9 : 25

Step-by-step EXPLANATION:

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

This proves that the ratio of the area of two similar triangles is proportional to the squares of the corresponding sides of both the triangles.

Area (∆ ABC) : area ( ∆ DEF) = AB² : DE²

3² : 5²

= 9 : 25

Discussion

16.	9x^2 - 27x + 14 = 0
Answer» ong>Answer: 1. Use Euclid’s division algorithm to find the HCF of: i. 135 and 225 ii. 196 and 38220 iii. 867 and 225 Solutions: i. 135 and 225 As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have, 225 = 135 × 1 + 90 Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get, 135 = 90 × 1 + 45 Again, 45 ≠ 0, repeating the above step for 45, we get, 90 = 45 × 2 + 0 The remainder is now ZERO, so our method stops here. Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45. Hence, the HCF of 225 and 135 is 45. ii. 196 and 38220 In this GIVEN question, 38220>196, therefore the by applying Euclid’s division algorithm and taking 38220 as divisor, we get, 38220 = 196 × 195 + 0 We have already got the remainder as 0 here. Therefore, HCF(196, 38220) = 196. Hence, the HCF of 196 and 38220 is 196. iii. 867 and 225 As we know, 867 is greater than 225. Let us apply now Euclid’s division algorithm on 867, to get, 867 = 225 × 3 + 102 Remainder 102 ≠ 0, therefore taking 225 as divisor and applying the division lemma method, we get, 225 = 102 × 2 + 51 Again, 51 ≠ 0. Now 102 is the new divisor, so repeating the same step we get, 102 = 51 × 2 + 0 The remainder is now zero, so our procedure stops here. Since, in the last step, the divisor is 51, therefore, HCF (867,225) = HCF(225,102) = HCF(102,51) = 51. Hence, the HCF of 867 and 225 is 51.

16.

9x^2 - 27x + 14 = 0

Answer»

ong>Answer:

1. Use Euclid’s division algorithm to find the HCF of:

i. 135 and 225

ii. 196 and 38220

iii. 867 and 225

Solutions:

i. 135 and 225

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,

225 = 135 × 1 + 90

Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,

135 = 90 × 1 + 45

Again, 45 ≠ 0, repeating the above step for 45, we get,

90 = 45 × 2 + 0

The remainder is now ZERO, so our method stops here. Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45.

Hence, the HCF of 225 and 135 is 45.

ii. 196 and 38220

In this GIVEN question, 38220>196, therefore the by applying Euclid’s division algorithm and taking 38220 as divisor, we get,

38220 = 196 × 195 + 0

We have already got the remainder as 0 here. Therefore, HCF(196, 38220) = 196.

Hence, the HCF of 196 and 38220 is 196.

iii. 867 and 225

As we know, 867 is greater than 225. Let us apply now Euclid’s division algorithm on 867, to get,

867 = 225 × 3 + 102

Remainder 102 ≠ 0, therefore taking 225 as divisor and applying the division lemma method, we get,

225 = 102 × 2 + 51

Again, 51 ≠ 0. Now 102 is the new divisor, so repeating the same step we get,

102 = 51 × 2 + 0

The remainder is now zero, so our procedure stops here. Since, in the last step, the divisor is 51, therefore, HCF (867,225) = HCF(225,102) = HCF(102,51) = 51.

Hence, the HCF of 867 and 225 is 51.

Discussion

17.	(iii) Ajay is younger than Vijay by 5 years. The sum of their ages is 25 years. What is Ajay'sage ?(A) 20(B) 15(C) 10 (D) 5
Answer» ONG>Step-by-step explanation: d) 5 c)10 b)15 a)20 it's a CORRECT answer

17.

(iii) Ajay is younger than Vijay by 5 years. The sum of their ages is 25 years. What is Ajay'sage ?(A) 20(B) 15(C) 10 (D) 5

Answer» ONG>Step-by-step explanation:

d) 5

c)10

b)15

a)20 it's a CORRECT answer

Discussion

18.	Derivative of sin-1x + cos-1 w.r.t. x is :(A) −1 (B) 0 (C) 1 (D) 2
Answer» ONG>Answer: for what Step-by-step EXPLANATION: not INTERESTED SORRY

18.

Derivative of sin-1x + cos-1 w.r.t. x is :(A) −1 (B) 0 (C) 1 (D) 2

Answer» ONG>Answer:

for what

Step-by-step EXPLANATION:

not INTERESTED SORRY

Discussion

19.	The length of a rectangle is 15 cm and breadth is 5 cm .find its area...
Answer» ONG>Answer: 75 cm² Step-by-step EXPLANATION: length = 15 cm , BREADTH = 5 cm area of rectangle = length × breadth =15×5 =75 cm²

19.

The length of a rectangle is 15 cm and breadth is 5 cm .find its area...

Answer» ONG>Answer:

75 cm²

Step-by-step EXPLANATION:

length = 15 cm , BREADTH = 5 cm

area of rectangle = length × breadth

=15×5

=75 cm²

Discussion

20.	6 54321Write Fraction to show the colouredportions of the given figures and tellwhich fraction is bigger
Answer» the biggest FRACTION Step-by-step explanation: because if 6 is the biggest fraction so MANY small parts will be formed that is y 1 is the biggest fraction

20.

6 54321Write Fraction to show the colouredportions of the given figures and tellwhich fraction is bigger

Answer»

the biggest FRACTION

Step-by-step explanation:

because if 6 is the biggest fraction so MANY small parts will be formed that is y 1 is the biggest fraction

Discussion

21.	present age of seema's mother is 5 time and 1 year more then seema .four year before product of thire ages are 22 then find thire present age
Answer» Basic Concept Used :- Writing Systems of Linear Equations from WORD Problems 1. UNDERSTAND the problem. Understand all the words used in stating the problem. Understand what you are asked to find. 2. Translate the problem to an equation. Assign a variable (or variables) to REPRESENT the unknown. Clearly STATE what the variable represents. 3. Carry out the plan and solve the problem. Let's solve the problem now!! $\large\underline{\sf{Solution-}}$ Let present age of Seema be 'x' years So, MOTHER's present age be 5x + 1 years So, we have present ages of two as $\begin{gathered}\begin{gathered}\bf \:Age \:of-\begin{cases} &\sf{Seema = x \: years} \\ &\sf{Mother \: = 5x + 1 \: years} \end{cases}\end{gathered}\end{gathered}$ Now, 4 years ago, the ages are as follow :- $\begin{gathered}\begin{gathered}\bf \:Age \:of-\begin{cases} &\sf{Seema = x - 4\: years} \\ &\sf{Mother \: = 5x + 1 - 4 = 5x - 3 \: years} \end{cases}\end{gathered}\end{gathered}$ According to statement, The product of their ages 4 years ago is 22. $\rm :\longmapsto\:(5x - 3)(x - 4) = 22$ $\rm :\longmapsto\: {5x}^{2} - 20x - 3x + 12 = 22$ $\rm :\longmapsto\: {5x}^{2} - 23x - 10 = 0$ $\rm :\longmapsto\: {5x}^{2} - 25x + 2x - 10 = 0$ $\rm :\longmapsto\:5x(x - 5) - 2(x - 5) = 0$ $\rm :\longmapsto\:(x - 5)(5x - 2) = 0$ $\rm :\implies\:x = 5 \: \: \: or \: \: \: x = \dfrac{2}{5} \: \{rejected \}$ Hence, $\begin{gathered}\begin{gathered}\bf \:Age \:of-\begin{cases} &\sf{Seema = x = 5\: years} \\ &\sf{Mother \: = 5x + 1 = 5 \times 5 + 1 = 26\: years} \end{cases}\end{gathered}\end{gathered}$

21.

present age of seema's mother is 5 time and 1 year more then seema .four year before product of thire ages are 22 then find thire present age

Answer»

Basic Concept Used :-

Writing Systems of Linear Equations from WORD Problems

1. UNDERSTAND the problem.

Understand all the words used in stating the problem.

Understand what you are asked to find.

2. Translate the problem to an equation.

Assign a variable (or variables) to REPRESENT the unknown.

Clearly STATE what the variable represents.

3. Carry out the plan and solve the problem.

Let's solve the problem now!!

$\large\underline{\sf{Solution-}}$

Let present age of Seema be 'x' years

So,

MOTHER's present age be 5x + 1 years

So, we have present ages of two as

$\begin{gathered}\begin{gathered}\bf \:Age \:of-\begin{cases} &\sf{Seema = x \: years} \\ &\sf{Mother \: = 5x + 1 \: years} \end{cases}\end{gathered}\end{gathered}$

Now,

4 years ago, the ages are as follow :-

$\begin{gathered}\begin{gathered}\bf \:Age \:of-\begin{cases} &\sf{Seema = x - 4\: years} \\ &\sf{Mother \: = 5x + 1 - 4 = 5x - 3 \: years} \end{cases}\end{gathered}\end{gathered}$

According to statement,

The product of their ages 4 years ago is 22.

$\rm :\longmapsto\:(5x - 3)(x - 4) = 22$

$\rm :\longmapsto\: {5x}^{2} - 20x - 3x + 12 = 22$

$\rm :\longmapsto\: {5x}^{2} - 23x - 10 = 0$

$\rm :\longmapsto\: {5x}^{2} - 25x + 2x - 10 = 0$

$\rm :\longmapsto\:5x(x - 5) - 2(x - 5) = 0$

$\rm :\longmapsto\:(x - 5)(5x - 2) = 0$

$\rm :\implies\:x = 5 \: \: \: or \: \: \: x = \dfrac{2}{5} \: \{rejected \}$

Hence,

$\begin{gathered}\begin{gathered}\bf \:Age \:of-\begin{cases} &\sf{Seema = x = 5\: years} \\ &\sf{Mother \: = 5x + 1 = 5 \times 5 + 1 = 26\: years} \end{cases}\end{gathered}\end{gathered}$

Discussion

22.	The sum of two number is 35 and them ratio is 1:4. find the number
Answer» SOLUTION:- ━━━━━━━━━━━━━━━━━━━━━━━━━━ $\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$ $\implies$ Here it is given in the question that the sum of two numbers is 35 and their ratio is 1:4. Now, the question has asked us to find out the the numbers. So, to find the numbers, assume the numbers as 1x and 4x. And after that follow the steps shown below. ANSWER:- ⬤ 1ST number = 7 ⬤ 2nd number = 28 GIVEN:- ⟼ 1st number = 1x ⟼ 2nd number = 4x TO FIND:- ⟿ Numbers = ? HOW TO DO:- ➜ 1st number + 2nd number = Sum SOLVING BY APPLYING THE FORMULA:- ⟼ 1st number = 1x ⟼ 2nd number = 4x ➜ 1st number + 2nd number = Sum Finding the number:- Sum is 35. So, ➜ 1x + 4x = 35 Adding the terms:- 1x + 4x = 5x So, ➜ 5x = 35 Taking 5 to R.H.S:- 35 / 5 So, ➜ x = 35 / 5 Remainder after DIVIDING the terms:- 35 / 5 = 7 So, ➜ x = 7 Final Answer:- 7 So, ➜ x = 7 Numbers:- ➜ 1st number = 1x ⠀⠀⠀⠀⠀1x = 1 × 7 ⠀⠀⠀⠀⠀⠀⠀= 7 1st number is 7. ➜ 2nd = 4x ⠀⠀⠀⠀⠀⠀4x = 4 × 7 ⠀⠀⠀⠀⠀⠀ ⠀= 28 2nd number is 28. VERIFICATION:- ➜ 7 + 28 ➜ 7 + 28 = 35 ➜ 35 ∴ L.H.S = R.H.S Hence, verified. ━━━━━━━━━━━━━━━━━━━━━━━━━

22.

The sum of two number is 35 and them ratio is 1:4. find the number

Answer» SOLUTION:-

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$

$\implies$ Here it is given in the question that the sum of two numbers is 35 and their ratio is 1:4. Now, the question has asked us to find out the the numbers. So, to find the numbers, assume the numbers as 1x and 4x. And after that follow the steps shown below.

ANSWER:-

⬤ 1ST number = 7

⬤ 2nd number = 28

GIVEN:-

⟼ 1st number = 1x

⟼ 2nd number = 4x

TO FIND:-

⟿ Numbers = ?

HOW TO DO:-

➜ 1st number + 2nd number = Sum

SOLVING BY APPLYING THE FORMULA:-

⟼ 1st number = 1x

⟼ 2nd number = 4x

➜ 1st number + 2nd number = Sum

Finding the number:-

Sum is 35.

So,

➜ 1x + 4x = 35

Adding the terms:- 1x + 4x = 5x

So,

➜ 5x = 35

Taking 5 to R.H.S:- 35 / 5

So,

➜ x = 35 / 5

Remainder after DIVIDING the terms:- 35 / 5 = 7

So,

➜ x = 7

Final Answer:- 7

So,

➜ x = 7

Numbers:-

➜ 1st number = 1x

⠀⠀⠀⠀⠀1x = 1 × 7

⠀⠀⠀⠀⠀⠀⠀= 7

1st number is 7.

➜ 2nd = 4x

⠀⠀⠀⠀⠀⠀4x = 4 × 7

⠀⠀⠀⠀⠀⠀ ⠀= 28

2nd number is 28.

VERIFICATION:-

➜ 7 + 28

➜ 7 + 28 = 35

➜ 35

∴ L.H.S = R.H.S

Hence, verified.

━━━━━━━━━━━━━━━━━━━━━━━━━

Discussion

23.	_1_1
Answer» ONG>Step-by-step EXPLANATION: MINECRAFT POCKET ediction

Discussion

24.	Rewrite 6/4 as a percent
Answer» ong>Answer: 150% Step-by-step explanation: LATEST decimal numbers, FRACTIONS, rations or PROPORTIONS converted to PERCENTAGES

24.

Rewrite 6/4 as a percent

Answer»

ong>Answer:

150%

Step-by-step explanation:

LATEST decimal numbers, FRACTIONS, rations or PROPORTIONS converted to PERCENTAGES

Discussion

25.	What is 1 + 1 (this is a joke btw)
Answer»

Discussion

26.	Evaluate sin65/cos25
Answer» ONG>ANSWER: 1 Step-by-step EXPLANATION: sin65/cos25 =sin65/cos(90-65) =sin65/sin65 =1

26.

Evaluate sin65/cos25

Answer» ONG>ANSWER:

1

Step-by-step EXPLANATION:

sin65/cos25

=sin65/cos(90-65)

=sin65/sin65

=1

Discussion

27.	Lea, Paul, Tynos invests in a business in the ratio 1:3:5. If the profit from the business is R450 000, how much will each get?
Answer» ong>Answer: Chapter 3 Equivalence A Factor Approach 3-1 If you had $1,000 now and invested it at 6%, how much would it be worth 12 years from now? Solution F = 1,000(F/P, 6%, 12) = $2,012.00 3-2 Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank PAYS 8% interest, how much will he have in the account at the END of 10 years? Solution F = 200,000(F/P, 8%, 10) = $431,800 3-3 If you can EARN 6% interest on your money, how much is $1,000 paid to you 12 years in the future worth to you now? Solution P = 1,000(P/F, 6%, 12) = $497.00 3-4 Determine the value of P using the appropriate factor. Solution P = F(P/F, 6%, 5) = $500(0.7473) = $373.65 3-5 Downtown is experiencing an explosive population growth of 10% per YEAR. At the end of 2005 F = $500 i = 6% P 0 1 2 3 4 550 Chapter 3 Equivalence – A Factor Approach the population was 16,000. If the growth rate continues unabated, at the end of how many years will it take for the population to triple? Solution Use i = 10% to represent the growth rate. 48,000 = 16,000(F/P, 10%, n) (F/P, 10%, n) = 48,000/16,000 = 3.000

27.

Lea, Paul, Tynos invests in a business in the ratio 1:3:5. If the profit from the business is R450 000, how much will each get?

Answer»

ong>Answer: Chapter 3

Equivalence

A Factor Approach

3-1

If you had $1,000 now and invested it at 6%, how much would it be worth 12 years from now?

Solution

F = 1,000(F/P, 6%, 12) = $2,012.00

3-2

Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank PAYS 8% interest,

how much will he have in the account at the END of 10 years?

Solution

F = 200,000(F/P, 8%, 10) = $431,800

3-3

If you can EARN 6% interest on your money, how much is $1,000 paid to you 12 years in the future

worth to you now?

Solution

P = 1,000(P/F, 6%, 12) = $497.00

3-4

Determine the value of P using the appropriate factor.

Solution

P = F(P/F, 6%, 5) = $500(0.7473) = $373.65

3-5

Downtown is experiencing an explosive population growth of 10% per YEAR. At the end of 2005

F = $500

i = 6%

P

0 1 2 3 4 550 Chapter 3 Equivalence – A Factor Approach

the population was 16,000. If the growth rate continues unabated, at the end of how many years

will it take for the population to triple?

Solution

Use i = 10% to represent the growth rate.

48,000 = 16,000(F/P, 10%, n)

(F/P, 10%, n) = 48,000/16,000

= 3.000

Discussion

28.	Prove that √6 + √2 is an irrationalpls can you do with procedure
Answer» E here , your WELL WISHES

Discussion

29.	3JANUARY2017Tuesday20{(415) (1,414,611716) (311)R-OR
Answer» ONG>Answer: GOOD NIGHT dear. sweet dreams.

29.

3JANUARY2017Tuesday20{(415) (1,414,611716) (311)R-OR

Answer» ONG>Answer:

GOOD NIGHT dear.

sweet dreams.

Discussion

30.	on Saturday only 600 people went the zoo while on Sunday 1000 people what is the percent increase in the people visiting the zoo on Sunday
Answer» ong>Answer: 600 ×100/1000 60000/1000= 60% Step-by-step explanation: If ONE (1) person GOES to a cinema ... Another day two(2)persons WENT to cinema ... 1*10/100=10% so,40% INCREASE in the zoo ..

30.

on Saturday only 600 people went the zoo while on Sunday 1000 people what is the percent increase in the people visiting the zoo on Sunday

Answer»

ong>Answer:

600 ×100/1000

60000/1000=

60%

Step-by-step explanation:

If ONE (1) person GOES to a cinema ...

Another day two(2)persons WENT to cinema ...

1*10/100=10%

so,40% INCREASE in the zoo ..

Discussion

31.	there are 25 classes in school and each class has 40 students. The fee of each child is 2005 per month fee. Calculate the monthly fee collection of the school.
Answer» ong>Answer: 20,05,00 Step-by-step EXPLANATION: 25 × 40 = 1000 1000 × 2005 = 200500

31.

there are 25 classes in school and each class has 40 students. The fee of each child is 2005 per month fee. Calculate the monthly fee collection of the school.

Answer»

ong>Answer:

20,05,00

Step-by-step EXPLANATION:

25 × 40 = 1000

1000 × 2005 = 200500

Discussion

32.	F'If f(x)=\|cos x – sinx \|, thenf'( pi/6) =
Answer» ONG>Answer: Good NIGHT my FRIEND ❤️❤️

Discussion

33.	Find the domain of the real valued function f(x)=1/log(2-x)
Answer» ave to find domain of the given function :- $\rm \large f(x) = \dfrac{1}{log (<klux>2</klux>-x)}$ We KNOW that DENOMINATOR cannot be zero. $\rm \longrightarrow log (2-x) \ne0 \\ \\ \rm \longrightarrow (2-x) \ne {e}^{0} \\ \\ \rm \longrightarrow 2-x \ne 1\\ \\ \rm \longrightarrow 2 - 1 \ne x\\ \\ \rm \longrightarrow 1 \ne x\\ \\ \rm \longrightarrow x \ne 1 \: \: \: \: ...(1)$ Also, $\large \rm \longrightarrow 2 - x > 0 \\ \\ \large \rm \longrightarrow 2 > x \: \: ...(2)$ From EQUATION (1) and (2) :- $\rm D_f = x \in (- \infty, 2) - \{1 \} \\ or \\ \rm D_f = x \in (- \infty, 1) \cup (1,2) \\ \\ \rm \: where \: D_f \: is \: domain \: of \: the \: function$

33.

Find the domain of the real valued function f(x)=1/log(2-x)

Answer»

ave to find domain of the given function :-

$\rm \large f(x) = \dfrac{1}{log (<klux>2</klux>-x)}$

We KNOW that DENOMINATOR cannot be zero.

$\rm \longrightarrow log (2-x) \ne0 \\ \\ \rm \longrightarrow (2-x) \ne {e}^{0} \\ \\ \rm \longrightarrow 2-x \ne 1\\ \\ \rm \longrightarrow 2 - 1 \ne x\\ \\ \rm \longrightarrow 1 \ne x\\ \\ \rm \longrightarrow x \ne 1 \: \: \: \: ...(1)$

Also,

$\large \rm \longrightarrow 2 - x > 0 \\ \\ \large \rm \longrightarrow 2 > x \: \: ...(2)$

From EQUATION (1) and (2) :-

$\rm D_f = x \in (- \infty, 2) - \{1 \} \\ or \\ \rm D_f = x \in (- \infty, 1) \cup (1,2) \\ \\ \rm \: where \: D_f \: is \: domain \: of \: the \: function$

Discussion

34.	Class 10 quadratic equation question plz help
Answer» ong>Answer: it is very easy question so PLEASE do with you by the help of a QUADRATIC form put the value of AC means put the value of b square as a minus 3 and a is equals to 1 and CS am PLUS 3 so hope it will help you you can solve easily why this you KNOW that practice makes a man perfect so apply it to you

34.

Class 10 quadratic equation question plz help

Answer»

ong>Answer:

it is very easy question so PLEASE do with you by the help of a QUADRATIC form put the value of AC means put the value of b square as a minus 3 and a is equals to 1 and CS am PLUS 3 so hope it will help you you can solve easily why this you KNOW that practice makes a man perfect so apply it to you

Discussion

35.	Find the amount of 5000 payable at the 4year at 3% compound annually
Answer» ONG>Answer: i don't KNOW SORRY its an APRIL fool

Discussion

36.	22) Construct triangle XYZ in which YZ-7cm, ZY = 60° and XY+XZ =2cm (Write the steps)
Answer» ong>Answer: GOOD NIGHT my FRIEND ❤️❤️

36.

22) Construct triangle XYZ in which YZ-7cm, ZY = 60° and XY+XZ =2cm (Write the steps)

Answer»

ong>Answer:

GOOD NIGHT my FRIEND ❤️❤️

Discussion

37.	नीचे दिए गए चित्रों को निम्नांकित कीजिए वह संरचना के आधार पर दोनों मे तुलना कीजिए 4
Answer» ONG>Answer: ameba in rhe FIRST figure

Discussion

38.	A shadow in the shape of a square.(ii) The cube can cast a shadow inshape of a hexagon.PART-II (SECTION-II)Solve:5( 5X - 10) = 15Find the values of x and y.
Answer» ong>Step-by-step explanation: 5 × 5x = 25x , 25x - 10 = 15 . X = 25 ., y = 15

38.

A shadow in the shape of a square.(ii) The cube can cast a shadow inshape of a hexagon.PART-II (SECTION-II)Solve:5( 5X - 10) = 15Find the values of x and y.

Answer»

ong>Step-by-step explanation:

5 × 5x = 25x , 25x - 10 = 15 . X = 25 ., y = 15

Discussion

39.	Simplify 8 raised 2 × 8 raised 7
Answer» ong>Answer: 8^9 = 134217728 Step-by-step explanation: 8^2 × 8^7 When BASES are equal POWERS are added 8^2+7 8^9 Please mark as the brainliest

39.

Simplify 8 raised 2 × 8 raised 7

Answer»

ong>Answer:

8^9 = 134217728

Step-by-step explanation:

8^2 × 8^7

When BASES are equal POWERS are added

8^2+7

8^9

Please mark as the brainliest

Discussion

40.	Find the largest number which divided 70 and 225 leaving remainders 5 and 8
Answer» ong>Answer: H.C.F of 70 and 125 is 13. THEREFORE the greatest NUMBER that divides 70 and 125 by leaving remainder 5 and 8 is 13. NOTE: This is a direct problem with finding the greatest number by writing the factors. Step-by-step explanation: mark as BRAINLIEST

40.

Find the largest number which divided 70 and 225 leaving remainders 5 and 8

Answer»

ong>Answer:

H.C.F of 70 and 125 is 13. THEREFORE the greatest NUMBER that divides 70 and 125 by leaving remainder 5 and 8 is 13. NOTE: This is a direct problem with finding the greatest number by writing the factors.

Step-by-step explanation:

mark as BRAINLIEST

Discussion

41.	8x5x3=536x4x6=589x8x3=1205x4x10=
Answer» ONG>Answer: 853=53 646=58 983=120 5410=200

41.

8x5x3=536x4x6=589x8x3=1205x4x10=

Answer» ONG>Answer:

8*5*3=53

6*4*6=58

9*8*3=120

5*4*10=200

Discussion

42.	Find the derivative of f(x) =2x+3/x-2
Answer» ong>Step-by-step explanation: f(x) = (2X+ 3)/(x - 2) f'(x) = [(x-2)(2) - (2x+3)*1] / (x-2)² [ f'(u/v) = [v DU - u dv] / v² quotient rule ] => [2x - 4 - 2x - 3] / (x-2)² => -7/(x-2)²

42.

Find the derivative of f(x) =2x+3/x-2

Answer»

ong>Step-by-step explanation:

f(x) = (2X+ 3)/(x - 2)

f'(x) = [(x-2)(2) - (2x+3)*1] / (x-2)²

[ f'(u/v) = [v DU - u dv] / v² quotient rule ]

=> [2x - 4 - 2x - 3] / (x-2)²

=> -7/(x-2)²

Discussion

43.	(-12)×(-10)×6×(-1) with formula
Answer» $( - 12) \times ( - 10) \times 6 \times ( - 1) \\ \\ \\ \\ - - = + \\ \\ \\ \\ 120 \times 6 \times ( - 1) \\ 720 \times ( - 1) \\ - 720$

43.

(-12)×(-10)×6×(-1) with formula

Answer»

$( - 12) \times ( - 10) \times 6 \times ( - 1) \\ \\ \\ \\ - - = + \\ \\ \\ \\ 120 \times 6 \times ( - 1) \\ 720 \times ( - 1) \\ - 720$

Discussion

44.	Prove that Sin²A + cos² A =1
Answer» is a very SIMPLE question to solve it just use TRIGONOMETRIC identity we KNOW that sin²a+cos²a=1 therefore 1=1 LHS = RHS its aabhyaa thanks for reading PLS mark me BRAINLIEST

44.

Prove that Sin²A + cos² A =1

Answer»

is a very SIMPLE question to solve it just use TRIGONOMETRIC identity

we KNOW that

sin²a+cos²a=1

therefore

1=1

LHS = RHS

its aabhyaa

thanks for reading

PLS mark me BRAINLIEST

Discussion

45.	How much is 0.8/5 what is that
Answer» ong>Step-by-step EXPLANATION: This fraction is equivalent to 1.6/10 and it is EQUAL to 0.16 in DECIMALS

45.

How much is 0.8/5 what is that

Answer»

ong>Step-by-step EXPLANATION:

This fraction is equivalent to 1.6/10 and it is EQUAL to 0.16 in DECIMALS

Discussion

46.	21) Check whether each of the ordered pairs given is the solution of equation p(x) = 3x- 4y+12 =0 or not1. (4,0)2. (0,-3)3. (4,6)4. (4,0)And state in which quadrant does each point lie...
Answer» ONG>ANSWER: (3) =(4,6) Step-by-step EXPLANATION: answer is 3.(4,6)

46.

21) Check whether each of the ordered pairs given is the solution of equation p(x) = 3x- 4y+12 =0 or not1. (4,0)2. (0,-3)3. (4,6)4. (4,0)And state in which quadrant does each point lie...

Answer» ONG>ANSWER:

(3) =(4,6)

Step-by-step EXPLANATION:

answer is 3.(4,6)

Discussion

47.	Please see the question and answer it see the photo to see question
Answer» ong>Answer: A railway track goes around a CURVE having a radius of CURVATURE of 1 km. The DISTANCE between the rails is 1 m. Find the elevation of the outer rail above the inner rail so that there is no SIDE pressure against the rails when a train goes round the curve at 36 km / hr.

47.

Please see the question and answer it see the photo to see question

Answer»

ong>Answer:

A railway track goes around a CURVE having a radius of CURVATURE of 1 km. The

DISTANCE between the rails is 1 m. Find the elevation of the outer rail above the inner rail so that there is no SIDE pressure against the rails when a train goes round the curve

at 36 km / hr.

Discussion

48.	Solve: ax + by = a - b and bx - ay = a + b Please send the photo of it
Answer» ONG>Step-by-step explanation: $\huge\underline\mathcal{\red{Question:-}}$ $\implies$ SOLVE: ax + by = a - b and bx - ay = a + b Taking the LCM of the LEFT Hand SIDE we have; $\frac{ab - {b}^{2} - {b}^{2}y - {a}^{2} y }{a} = a + b$ Moving a to the RHS we have; $ab - {b}^{2} - {b}^{2} y - {a}^{2} y = a(a + b)$ $ab - {b }^{2} - {b}^{2} y - {a}^{2} y = {a}^{2} + ab$ $- {b}^{2} - {b}^{2} y - {a}^{2} y = {a}^{2} + ab - ab$ $- {b}^{2} - {b}^{2} y - {a}^{2} y = {a}^{2}$ Moving ${-b}^{2}$ to the RHS and taking y common in the LHS we have; $- y( {b}^{2} + {a}^{2} ) = {a}^{2} + {b}^{2}$ $- y = 1$ y = -1 Now, Putting the value of y in (3) We have; $x = \frac{a - b - b( - 1)}{a}$ $x = \frac{a - b + b}{a}$ $x = \frac{a}{a}$ x = 1

48.

Solve: ax + by = a - b and bx - ay = a + b Please send the photo of it

Answer» ONG>Step-by-step explanation:

$\huge\underline\mathcal{\red{Question:-}}$

$\implies$ SOLVE: ax + by = a - b and bx - ay = a + b

Taking the LCM of the LEFT Hand SIDE we have;

$\frac{ab - {b}^{2} - {b}^{2}y - {a}^{2} y }{a} = a + b$

Moving a to the RHS we have;

$ab - {b}^{2} - {b}^{2} y - {a}^{2} y = a(a + b)$

$ab - {b }^{2} - {b}^{2} y - {a}^{2} y = {a}^{2} + ab$

$- {b}^{2} - {b}^{2} y - {a}^{2} y = {a}^{2} + ab - ab$

$- {b}^{2} - {b}^{2} y - {a}^{2} y = {a}^{2}$

Moving ${-b}^{2}$ to the RHS and taking y common in the LHS we have;

$- y( {b}^{2} + {a}^{2} ) = {a}^{2} + {b}^{2}$

$- y = 1$

y = -1

Now,

Putting the value of y in (3) We have;

$x = \frac{a - b - b( - 1)}{a}$

$x = \frac{a - b + b}{a}$

$x = \frac{a}{a}$

x = 1

Discussion

49.	Divide 2220 in the ratio1/4:1/5:1/6
Answer» ONG>Step-by-step explanation: HOPE it helped you and thanks for ASKING and mark me BRAINLIEST

Discussion

50.	16. Rationalise the denominator.(a)1/3-2✓2+✓5
Answer» ong>Step-by-step explanation: HOPE it HELPED you and thanks for ASKING and mark me BRAINLIEST

50.

16. Rationalise the denominator.(a)1/3-2✓2+✓5

Answer»

ong>Step-by-step explanation:

HOPE it HELPED you and thanks for ASKING and mark me BRAINLIEST

Discussion

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नीचे दिए गए चित्रों को निम्नांकित कीजिए वह संरचना के आधार पर दोनों मे तुलना कीजिए 4

A shadow in the shape of a square.(ii) The cube can cast a shadow inshape of a hexagon.PART-II (SECTION-II)Solve:5( 5X - 10) = 15Find the values of x and y.

Find the largest number which divided 70 and 225 leaving remainders 5 and 8

8x5x3=536x4x6=589x8x3=1205x4x10=

Find the derivative of f(x) =2x+3/x-2

(-12)×(-10)×6×(-1) with formula

Prove that Sin²A + cos² A =1

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Please see the question and answer it see the photo to see question

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16. Rationalise the denominator.(a)1/3-2✓2+✓5