1.

Solve: ax + by = a - b and bx - ay = a + b Please send the photo of it​

Answer» ONG>Step-by-step explanation:

\huge\underline\mathcal{\red{Question:-}}

\impliesSOLVE: ax + by = a - b and bx - ay = a + b

Taking the LCM of the LEFT Hand SIDE we have;

\frac{ab - {b}^{2} - {b}^{2}y - {a}^{2} y }{a} = a + b

Moving a to the RHS we have;

ab - {b}^{2} - {b}^{2} y - {a}^{2} y = a(a + b)

ab - {b }^{2} - {b}^{2} y - {a}^{2} y = {a}^{2} + ab

- {b}^{2} - {b}^{2} y - {a}^{2} y = {a}^{2} + ab - ab

- {b}^{2} - {b}^{2} y - {a}^{2} y = {a}^{2}

Moving {-b}^{2} to the RHS and taking y common in the LHS we have;

- y( {b}^{2} + {a}^{2} ) = {a}^{2} + {b}^{2}

- y = 1

y = -1

Now,

Putting the value of y in (3) We have;

x = \frac{a - b - b( - 1)}{a}

x = \frac{a - b + b}{a}

x = \frac{a}{a}

x = 1


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