332354 + Interview Questions in Secondary School in Math

1.	Practice set 31Which of the following sequences areIf theyare A.p. findthe common difterה2,4,6.8.
Answer» ONG>ANSWER: a=2 t2-t1=2 t3-t2=2 t4-t3=2 d=2 this SEQUENCE is an a.p.

1.

Practice set 31Which of the following sequences areIf theyare A.p. findthe common difterה2,4,6.8.

Answer» ONG>ANSWER:

a=2

t2-t1=2

t3-t2=2

t4-t3=2

d=2

this SEQUENCE is an a.p.

Discussion

2.	Find the ratio of diagonal of a square to its side, if the length of side is 8 cm.
Answer» ong>ANSWER: d≈11.31 this ANS is right Step-by-step EXPLANATION: PLEASE MAKE me brainlist

2.

Find the ratio of diagonal of a square to its side, if the length of side is 8 cm.

Answer»

ong>ANSWER:

d≈11.31

this ANS is right

Step-by-step EXPLANATION:

PLEASE MAKE me brainlist

Discussion

3.	In the given figure degree of measure of the angles of ∆ ABC are given in x. The value of x is a)72 degreeb)44 degreec)36 degreed)30 degreewho answers first gets brainliest
Answer» ONG>Answer: C. 36 DEGREE ... Step-by-step explanation: 2x + 2x + x = 180 5x = 180 x = 36.

3.

In the given figure degree of measure of the angles of ∆ ABC are given in x. The value of x is a)72 degreeb)44 degreec)36 degreed)30 degreewho answers first gets brainliest

Answer» ONG>Answer:

C. 36 DEGREE ...

Step-by-step explanation:

2x + 2x + x = 180

5x = 180

x = 36.

Discussion

4.	Find coordinates of midpoint of line segment joining points (4,6) (8,2)
Answer» ONG>Answer: answer is (6,4) this is correct answer Step-by-step explanation: i HOPE this helps you thank you I am 10 the CLASS s.v.somanath

4.

Find coordinates of midpoint of line segment joining points (4,6) (8,2)

Answer» ONG>Answer:

answer is (6,4) this is correct answer

Step-by-step explanation:

i HOPE this helps you

thank you

I am 10 the CLASS s.v.somanath

Discussion

5.	Solve the following equations (1) 5+ 4(t - 7)=13 (2) 2b/3 - 5 = 3
Answer» ONG>ANSWER: *PLEASE MARK in brainleast* Step-by-step explanation: 1.ans 5+4t-28=13 5-28+4t=13 -23+4t=13 4t=13+23 4t=36. t=36/4 t=9 2.ans 2b/2=3 2b=3×2 2b=6 b=6/2 b=3

5.

Solve the following equations (1) 5+ 4(t - 7)=13 (2) 2b/3 - 5 = 3

Answer» ONG>ANSWER:

PLEASE MARK in brainleast

Step-by-step explanation:

1.ans 5+4t-28=13

5-28+4t=13

-23+4t=13

4t=13+23

4t=36.

t=36/4

t=9

2.ans 2b/2=3

2b=3×2

2b=6

b=6/2

b=3

Discussion

6.	Consider a single phase synchronous machine of cylindrical rotor type. A singlephase supply is given to the stator winding,and a voltmeter is connected across rotorwinding. For what value of Or the voltmeterreads a zero?
Answer» m JUG NHH KGF njfdd JH

Discussion

7.	Rs 12800 were distributed among Rama, Shyam and Bhima in the ratio 3:5:8. Find the amount Shyam has received.
Answer» t WAY to FIND it will be to MULTIPLE 12800 with (5/16) So ANSWER is 4000

Discussion

8.	the average of x number is y and average of y number is x. then the average of all these numbers taken together is
Answer» ong>Step-by-step explanation: the AVERAGE of x NUMBER is y and average of y number is x. then the average of all these NUMBERS taken together is

8.

the average of x number is y and average of y number is x. then the average of all these numbers taken together is

Answer»

ong>Step-by-step explanation:

the AVERAGE of x NUMBER is y and average of y number is x. then the average of all these NUMBERS taken together is

Discussion

9.	Q23. Six years ago the ages of A and B were in the ratio of 4: 3. Nine years from now, their ages will be in the ratio7:6. Find their presentage,
Answer» ong>Answer: x= 26yrs and y = 21yrs Step-by-step explanation: Let the PRESENT age of A be x yrs and the present age of B be y yrs. Acc. to QUESTION, (x-6)/(y-6) = 4/3 And (x+9)/(y+9) = 7/6 On solving these, u will GET:- x= 26yrs and y = 21yrs If u have any other problem, u can TELL

9.

Q23. Six years ago the ages of A and B were in the ratio of 4: 3. Nine years from now, their ages will be in the ratio7:6. Find their presentage,

Answer»

ong>Answer:

x= 26yrs and y = 21yrs

Step-by-step explanation:

Let the PRESENT age of A be x yrs and the present age of B be y yrs.

Acc. to QUESTION,

(x-6)/(y-6) = 4/3

And (x+9)/(y+9) = 7/6

On solving these, u will GET:-

x= 26yrs and y = 21yrs

If u have any other problem, u can TELL

Discussion

10.	B) Simplify the following algebraic expression:505 x 52 x a71252 x a4
Answer» ong>Answer: 26260×a⁷ 1252 X a⁴ wish you will DROP some thanks and mark it BRAINLIST

10.

B) Simplify the following algebraic expression:505 x 52 x a71252 x a4

Answer»

ong>Answer:

26260×a⁷
1252 X a⁴

wish you will DROP some thanks

and mark it BRAINLIST

Discussion

11.	Is on attitude of thinkingother5stateToveofalls eContinousplanning is aprocess3 2Self management is one broad concep-
Answer» ong>ANSWER: Which word in the PASSAGE means as a group? Step-by-step explanation: Which word in the passage means as a group?

11.

Is on attitude of thinkingother5stateToveofalls eContinousplanning is aprocess3 2Self management is one broad concep-

Answer»

ong>ANSWER:

Which word in the PASSAGE means as a group?

Step-by-step explanation:

Which word in the passage means as a group?

Discussion

12.	G) Pipe A can fill an empty tank in 8 hours while pipe B can empty the full tank in 6hours. If both are opened in the empty tank itwill be full in_ hour?
Answer» ong>Answer: 24 hours Step-by-step EXPLANATION: A -> 8 hrs B-> -6 hrs l.c.m. of A and B is 48 that A can fill 6 LTS in 1 hr and B can TAKE off 8 lts in 1 hr time taken to fill 48/(6-8) = 48/ -2 = 24 hours.

12.

G) Pipe A can fill an empty tank in 8 hours while pipe B can empty the full tank in 6hours. If both are opened in the empty tank itwill be full in_ hour?

Answer»

ong>Answer:

24 hours

Step-by-step EXPLANATION:

A -> 8 hrs

B-> -6 hrs

l.c.m. of A and B is 48

that A can fill 6 LTS in 1 hr

and B can TAKE off 8 lts in 1 hr

time taken to fill

48/(6-8) = 48/ -2 = 24 hours.

Discussion

13.	Determine the nature of roots for the quadratic equation 2x²2x²-2x+9=0
Answer» ong>Answer: imagery ROOTS Step-by-step EXPLANATION: here, ∆= b^2-4ac =(-2)^2-4×9×2 =-68 ∆<0 therefore both roots of given QUADRATIC equation are imagery

13.

Determine the nature of roots for the quadratic equation 2x²2x²-2x+9=0

Answer»

ong>Answer:

imagery ROOTS

Step-by-step EXPLANATION:

here,

∆= b^2-4ac

=(-2)^2-4×9×2

=-68

∆<0

therefore both roots of given QUADRATIC equation are imagery

Discussion

14.	What will be the answerplease help me
Answer» ong>Answer: 8sec2theta- 8 TAN2 THETA 8( SEC 2THETA- tan2 theta) 8(1) 8

14.

What will be the answerplease help me

Answer»

ong>Answer:

8sec2theta- 8 TAN2 THETA

8( SEC 2THETA- tan2 theta)

8(1)

8

Discussion

15.	Solve for X :- √3 2-2√2 x -2√3 =0
Answer» ONG>ANSWER: hsjjs Step-by-step EXPLANATION: Hhakkkj the EPIDERMIC the epidermic the epidermic the $\cot( \cot(\pi \cos( \beta ee \beta \pi \beta ee \beta e\pi\pi) ) ) log(e log(?) )$ sssfvbnnhhtwr

15.

Solve for X :- √3 2-2√2 x -2√3 =0

Answer» ONG>ANSWER:

hsjjs

Step-by-step EXPLANATION:

Hhakkkj the EPIDERMIC the epidermic the epidermic the

$\cot( \cot(\pi \cos( \beta ee \beta \pi \beta ee \beta e\pi\pi) ) ) log(e log(?) )$

sssfvbnnhhtwr

Discussion

16.	Find the cost of painting the four walls and the celling of a room at the rate of RS 14 Per m²if perimeter of the base with equal sides is80m and height of the room is 9.5m. Also findthe volume.
Answer» ong>ANSWER: your answer is in the pic.. HOPE this helps you DEAR..

16.

Find the cost of painting the four walls and the celling of a room at the rate of RS 14 Per m²if perimeter of the base with equal sides is80m and height of the room is 9.5m. Also findthe volume.

Answer»

ong>ANSWER:

your answer is in the pic..

HOPE this helps you DEAR..

Discussion

17.	Simplify:-(a2+2ab+b2)-3 (a2-b2)
Answer» $\huge\bf\green{❥solution}$ $=> ({a}^{2} + 2ab + {b}^{2} )- 3( {a}^{2} - {b}^{2})$ $=> {a}^{2} + 2ab + {b}^{2} - 3 {a}^{2} - 3 {b}^{2}$ $=> {a}^{2} - 3 {a}^{2} + 2ab + {b}^{2} - 3 {b}^{2}$ $=> - 2 {a}^{2} + 2ab - {b}^{2}$ $=> 2 {a}^{2} - 2ab + 2 {b}^{2}$ HOPE it will HELPFUL for you..

17.

Simplify:-(a2+2ab+b2)-3 (a2-b2)

Answer»

$\huge\bf\green{❥solution}$

$=> ({a}^{2} + 2ab + {b}^{2} )- 3( {a}^{2} - {b}^{2})$

$=> {a}^{2} + 2ab + {b}^{2} - 3 {a}^{2} - 3 {b}^{2}$

$=> {a}^{2} - 3 {a}^{2} + 2ab + {b}^{2} - 3 {b}^{2}$

$=> - 2 {a}^{2} + 2ab - {b}^{2}$

$=> 2 {a}^{2} - 2ab + 2 {b}^{2}$

HOPE it will HELPFUL for you..

Discussion

18.	Find x, if £fixi = 252 and £fi= 420
Answer» ong>Answer: as we KNOW that X bar = SUM fixi/ sum fi Step-by-step explanation: x\| = 0.6

18.

Find x, if £fixi = 252 and £fi= 420

Answer»

ong>Answer:

as we KNOW that X bar = SUM fixi/ sum fi

Step-by-step explanation:

x| = 0.6

Discussion

19.	Obtain the Eigen value and Eigen vector
Answer» ONG>Step-by-step EXPLANATION: this is the WAY to SOLVE this

Discussion

20.	Write constructive part of our body . QuestionHow can I write as you ?answer???I am fine what about you jiya sis
Answer» ONG>THANKS *for* *POINT. Sorry* *for* *SPAM*.

Discussion

21.	During a competition, numismatist Aditi has been given Rs. 200 in Rs.1 denominations. The judge asks Aditi to allocate the Rs. 1 denominations into a number of pouches such that any amount required between Rs.1 & Rs. 200 can be given by giving out a certain number of pouches without opening them. Aditi thinks and asks the judge to give her 'x' number of pouches to keep the money, where 'x' is the minimum number of bags required to keep the total money. Can you guess the value of 'x
Answer» ONG>Answer: OK U are GIRL please massage me on whats____app

Discussion

22.	One of the roots of a quadratic equation is 4 - √7. Find the equation.
Answer» ONG>Answer: 4\7= 62a by 125 it's FINISHED

22.

One of the roots of a quadratic equation is 4 - √7. Find the equation.

Answer» ONG>Answer:

4\7= 62a by 125 it's FINISHED

Discussion

23.	Which one is TRUE for the following data? * f:R + R, f(x) = cose, reRO onto but not one-oneO neither one-one nor ontoO one-one but not ontoO both one-one and onto
Answer» ONG>ANSWER: every THING is FALSE Step-by-step EXPLANATION: false

23.

Which one is TRUE for the following data? * f:R + R, f(x) = cose, reRO onto but not one-oneO neither one-one nor ontoO one-one but not ontoO both one-one and onto

Answer» ONG>ANSWER:

every THING is FALSE

Step-by-step EXPLANATION:

false

Discussion

24.	If x is the geometric mean of 25 & 4, then find the value of x
Answer» ong>Answer: 10 Step-by-step explanation: geometric mean : if TWO numbers a and b are GIVEN then geometric mean of these two number is square root of their product. e.g., geometric mean , G.M = \sqrt{ab} ab Here , x is geometric mean of 25 and 4 then, x =\sqrt{25\times4}=\sqrt{100}=10 25×4 = 100 =10 2nd method : x is geometric mean of 25 and 4 means, 25 , x , 4 are in Geometric progression. we know, common ratio of geometric progression always remains constant . so, x/25 =4/x x² = 25 × 4 x = 10

24.

If x is the geometric mean of 25 & 4, then find the value of x

Answer»

ong>Answer:

10

Step-by-step explanation:

geometric mean : if TWO numbers a and b are GIVEN then geometric mean of these two number is square root of their product.

e.g., geometric mean , G.M = \sqrt{ab}

ab

Here , x is geometric mean of 25 and 4

then, x =\sqrt{25\times4}=\sqrt{100}=10

25×4

=

100

=10

2nd method : x is geometric mean of 25 and 4

means, 25 , x , 4 are in Geometric progression.

we know, common ratio of geometric progression always remains constant .

so, x/25 =4/x

x² = 25 × 4

x = 10

Discussion

25.	Y=2x+24X+100+ax, differentiate with respect to x.
Answer» ong>ANSWER: dY/dx = 26 + a Step-by-step explanation: Y=2x+24X+100+ax Y = 26X + 100 + ax dY/dx = 26 + 0 + a = 26 + a

25.

Y=2x+24X+100+ax, differentiate with respect to x.

Answer»

ong>ANSWER:

dY/dx = 26 + a

Step-by-step explanation:

Y=2x+24X+100+ax

Y = 26X + 100 + ax

dY/dx = 26 + 0 + a

= 26 + a

Discussion

26.	1. The rain water from 22m x 20m roof drain into a cylindrical of diameter 2mand height 3.5m. if saw watercollected from droof fills 4/5 ofCylindrical then find the rainfallin cm.
Answer» align="absmiddle" ALT="\huge\mathcal\colorbox{black}{{\color{PINK}{Answer}}}" CLASS="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5Chuge%5Cmathcal%5Ccolorbox%7Bblack%7D%7B%7B%5Ccolor%7Bpink%7D%7BAnswer%7D%7D%7D" title="\huge\mathcal\colorbox{black}{{\color{pink}{Answer}}}">

26.

1. The rain water from 22m x 20m roof drain into a cylindrical of diameter 2mand height 3.5m. if saw watercollected from droof fills 4/5 ofCylindrical then find the rainfallin cm.

Answer»

align="absmiddle" ALT="\huge\mathcal\colorbox{black}{{\color{PINK}{Answer}}}" CLASS="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5Chuge%5Cmathcal%5Ccolorbox%7Bblack%7D%7B%7B%5Ccolor%7Bpink%7D%7BAnswer%7D%7D%7D" title="\huge\mathcal\colorbox{black}{{\color{pink}{Answer}}}">

Discussion

27.	A bag has cards with numbers 1 to 15. Write the outcome of the event that a number selected is amultiple of 2 or 3.
Answer» ong>Step-by-step EXPLANATION: S={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15} n(S)=15 event A A= {2,4,6,8,10,12,14,3,9,15} n(A)=10

27.

A bag has cards with numbers 1 to 15. Write the outcome of the event that a number selected is amultiple of 2 or 3.

Answer»

ong>Step-by-step EXPLANATION:

S={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

n(S)=15

event A

A= {2,4,6,8,10,12,14,3,9,15}

n(A)=10

Discussion

28.	Write in expanded form 57657560
Answer» ong>ANSWER: WRITE in expanded FORM is 5,76,57,560

28.

Write in expanded form 57657560

Answer»

ong>ANSWER:

WRITE in expanded FORM is 5,76,57,560

Discussion

29.	Prove that : tan theta / sec theta +1 = sec theta -1 / tan theta
Answer» $\large\underline{\bold{Given \:Question - }}$ $\sf \: Prove \: that \: \: \dfrac{tan \theta}{sec\theta + <klux>1</klux>} = \dfrac{sec\theta - 1}{tan\theta}$ $\large\underline{\sf{Solution-}}$ Consider, $\rm :\longmapsto\:\dfrac{tan\theta}{sec\theta + 1}$ $\: \: \: \: \: \: \: \: \: \boxed{ \sf \: on \: multiply \: and \: divide \: by \: sec\theta - 1}$ $\sf \: = \: \: \: :\dfrac{tan\theta}{sec\theta + 1} \times \dfrac{sec\theta - 1}{sec\theta - 1}$ $\sf \: = \: \: \: \dfrac{tan\theta(sec\theta - 1)}{ {sec}^{2}\theta - 1 }$ $\: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \because \: {x}^{2} - {y}^{2} = (x + y)(x - y)}$ $\sf \: = \: \: \: \dfrac{tan\theta(sec\theta - 1)}{ {tan}^{2} \theta}$ $\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \because \: {sec}^{2} \theta - 1 = {tan}^{2} \theta}$ $\sf \: = \: \: \: \dfrac{sec\theta - 1}{tan\theta}$ ${\boxed{\boxed{\bf{Hence, Proved}}}}$ ─━─━─━─━─━─━─━─━─━─━─━─━─ Additional Information:- Relationship between sides and T ratios sin θ = OPPOSITE Side/Hypotenuse cos θ = Adjacent Side/Hypotenuse tan θ = Opposite Side/Adjacent Side sec θ = Hypotenuse/Adjacent Side cosec θ = Hypotenuse/Opposite Side cot θ = Adjacent Side/Opposite Side Reciprocal Identities cosec θ = 1/sin θ sec θ = 1/cos θ cot θ = 1/tan θ sin θ = 1/cosec θ cos θ = 1/sec θ tan θ = 1/cot θ Co-function Identities sin (90°−x) = cos x cos (90°−x) = sin x tan (90°−x) = cot x cot (90°−x) = tan x sec (90°−x) = cosec x cosec (90°−x) = sec x Fundamental TRIGONOMETRIC Identities sin²θ + cos²θ = 1 sec²θ - tan²θ = 1 cosec²θ - cot²θ = 1

29.

Prove that : tan theta / sec theta +1 = sec theta -1 / tan theta

Answer»

$\large\underline{\bold{Given \:Question - }}$

$\sf \: Prove \: that \: \: \dfrac{tan \theta}{sec\theta + <klux>1</klux>} = \dfrac{sec\theta - 1}{tan\theta}$

$\large\underline{\sf{Solution-}}$

Consider,

$\rm :\longmapsto\:\dfrac{tan\theta}{sec\theta + 1}$

$\: \: \: \: \: \: \: \: \: \boxed{ \sf \: on \: multiply \: and \: divide \: by \: sec\theta - 1}$

$\sf \: = \: \: \: :\dfrac{tan\theta}{sec\theta + 1} \times \dfrac{sec\theta - 1}{sec\theta - 1}$

$\sf \: = \: \: \: \dfrac{tan\theta(sec\theta - 1)}{ {sec}^{2}\theta - 1 }$

$\: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \because \: {x}^{2} - {y}^{2} = (x + y)(x - y)}$

$\sf \: = \: \: \: \dfrac{tan\theta(sec\theta - 1)}{ {tan}^{2} \theta}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \because \: {sec}^{2} \theta - 1 = {tan}^{2} \theta}$

$\sf \: = \: \: \: \dfrac{sec\theta - 1}{tan\theta}$

${\boxed{\boxed{\bf{Hence, Proved}}}}$

─━─━─━─━─━─━─━─━─━─━─━─━─

Additional Information:-

Relationship between sides and T ratios

sin θ = OPPOSITE Side/Hypotenuse

cos θ = Adjacent Side/Hypotenuse

tan θ = Opposite Side/Adjacent Side

sec θ = Hypotenuse/Adjacent Side

cosec θ = Hypotenuse/Opposite Side

cot θ = Adjacent Side/Opposite Side

Reciprocal Identities

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

sin θ = 1/cosec θ

cos θ = 1/sec θ

tan θ = 1/cot θ

Co-function Identities

sin (90°−x) = cos x

cos (90°−x) = sin x

tan (90°−x) = cot x

cot (90°−x) = tan x

sec (90°−x) = cosec x

cosec (90°−x) = sec x

Fundamental TRIGONOMETRIC Identities

sin²θ + cos²θ = 1

sec²θ - tan²θ = 1

cosec²θ - cot²θ = 1

Discussion

30.	સાત પૈસા દશાંશ સંખ્યા ના રૂપિયા માં દર્શાવો ?
Answer» ONG>ANSWER: સાત પૈસા દશાંશ સંખ્યા ના રૂપિયા માં દર્શાવો ?

Discussion

31.	Simplify:do if you can
Answer» ong>Answer: 3 SQUARE into 2square that is 9*4= 36

31.

Simplify:do if you can

Answer»

ong>Answer:

3 SQUARE into 2square that is 9*4= 36

Discussion

32.	Please Solve this quick
Answer» ong>Answer: PERIMETER IS = 4 × SEMICIRCLE + PERIMETER OF SQUARE We have diameter of semicircle = 14 cm Radius = 7 cm Side of square is 14 cm Perimeter = 4 × πr + 4 × 14 = (4 × 22/7 × 7 ) + 56 = 88 + 56 = 144 cm (Ans.) HOPE it helps please mark as brainliest

32.

Please Solve this quick

Answer»

ong>Answer:

PERIMETER IS = 4 × SEMICIRCLE + PERIMETER OF SQUARE

We have diameter of semicircle = 14 cm

Radius = 7 cm

Side of square is 14 cm

Perimeter = 4 × πr + 4 × 14

= (4 × 22/7 × 7 ) + 56

= 88 + 56

= 144 cm (Ans.)

HOPE it helps

please mark as brainliest

Discussion

33.	What is the difference between 78.56 and 65.87.
Answer» DIFFERENCE between 78.56 and 65.87. 12.69

Discussion

34.	(15+1) (15-1) का मानहै
Answer» ONG>Answer: USING Indentity (a+b)(a-b)=a^2 - b^2 15^2-1^2 225-1 224 If it's helpful to you MARK it as BRAINLIEST Answer

34.

(15+1) (15-1) का मानहै

Answer» ONG>Answer:

USING Indentity (a+b)(a-b)=a^2 - b^2

15^2-1^2

225-1

224

If it's helpful to you MARK it as BRAINLIEST Answer

Discussion

35.	-7/4 write the equvation
Answer» ONG>ANSWER: The EQUIVALENT EQUATION are: -14/10 -21/15 -28/20 -35/25 -42/30

35.

-7/4 write the equvation

Answer» ONG>ANSWER:

The EQUIVALENT EQUATION are:

-14/10

-21/15

-28/20

-35/25

-42/30

Discussion

36.	(5-2x) (3+x) का गुणनफल ज्ञात कीजिए ।
Answer» ONG>Answer: 5(3+x)-2X(3+x) -> 15+5x-6x-2x² -> 15-x-2x² Hey! this is UR ANS..

36.

(5-2x) (3+x) का गुणनफल ज्ञात कीजिए ।

Answer» ONG>Answer:

5(3+x)-2X(3+x)

-> 15+5x-6x-2x²

-> 15-x-2x²

Hey! this is UR ANS..

Discussion

37.	Ii) Which of the following is the value of k if the roots of x2 + kx + k = 0 are real and equal?(A) O(B) 4(C) O or 4 (D) 2
Answer» ONG>ANSWER: what is your I didn't UNDERSTAND

Discussion

38.	A die is thrown twice find the probability that 5 will come up atleast once
Answer» ong>Answer: Probability is 1/5 or 2/10 if it is a FAIR DICE, if it is a BIASED dice WELL idk Step-by-step explanation:

38.

A die is thrown twice find the probability that 5 will come up atleast once

Answer»

ong>Answer:

Probability is 1/5 or 2/10 if it is a FAIR DICE, if it is a BIASED dice WELL idk

Step-by-step explanation:

Discussion

39.	Please give whole solution
Answer» ONG>Answer: HI bro PLEASE subscribe my Chanel please I will folow U its my promise

Discussion

40.	Is 4 2 + 9 3 = 51 a linear equation in two variables? Justify.
Answer» ong>Answer: no. it is not a linear EQUATION in two variables. Step-by-step explanation: because.. linear equation has "1" as the VALUE of that. in this equation the DEGREE of variables are 2and 3

40.

Is 4 2 + 9 3 = 51 a linear equation in two variables? Justify.

Answer»

ong>Answer:

no. it is not a linear EQUATION in two variables.

Step-by-step explanation:

because..

linear equation has "1" as the VALUE of that.

in this equation the DEGREE of variables are 2and 3

Discussion

41.	Who are the current president of India
Answer» ong>ANSWER: OK ok ok lam MIM minimumsincredibles

41.

Who are the current president of India

Answer»

ong>ANSWER:

OK ok ok lam MIM minimumsincredibles

Discussion

42.	Are the trigonometric ratios 0° and 90° deleted for class 10, 2020-2021
Answer» ong>Answer: No Step-by-step explanation: TRIGONOMETRIC RATIOS are not DELETED .

42.

Are the trigonometric ratios 0° and 90° deleted for class 10, 2020-2021

Answer»

ong>Answer:

No

Step-by-step explanation:

TRIGONOMETRIC RATIOS are not DELETED .

Discussion

43.	2 Lengthth = 15m:& Breadth = 16m
Answer» ong>Answer: 2l+ b 2(15+ 16 ) m 231 m = 62 m Step-by-step EXPLANATION:* In rectangle length are equal and breadth are equal . But l and b are not equal . perimeter mean boundary 15 is two TIMES 16 is two times . without adding 15 two times and 16 two times we add 15 and 16 and multiply with 2.

43.

2 Lengthth = 15m:& Breadth = 16m

Answer»

ong>Answer:

2*l+ b

2*(15+ 16 ) m

2*31 m

= 62 m

Step-by-step EXPLANATION:

In rectangle length are equal and breadth are equal . But l and b are not equal .

perimeter mean boundary

15 is two TIMES

16 is two times .

without adding 15 two times and 16 two times we add 15 and 16 and multiply with 2.

Discussion

44.	The ratio of curved surface area of cone and sphere having unit radius and unit height is
Answer» ong>Answer: the RATIO of curved surface AREA of CONE and sphere having unit radius and unit height is Step-by-step explanation: 4:4:√5

44.

The ratio of curved surface area of cone and sphere having unit radius and unit height is

Answer»

ong>Answer:

the RATIO of curved surface AREA of CONE and sphere having unit radius and unit height is

Step-by-step explanation:

4:4:√5

Discussion

45.	During a competition, numismatist Aditi has been given Rs. 200 in Rs.1 denominations. The judge asks Aditi to allocate the Rs. 1 denominations into a number of pouches such that any amount required between Rs.1 & Rs. 200 can be given by giving out a certain number of pouches without opening them. Aditi thinks and asks the judge to give her 'x' number of pouches to keep the money, where 'x' is the minimum number of bags required to keep the total money. Can you guess the value of 'x'?
Answer» ONG>Answer: you have taken this from VEDANTU VOTE DAILY challenge (2) I have also attempted this and I wrote 17

45.

During a competition, numismatist Aditi has been given Rs. 200 in Rs.1 denominations. The judge asks Aditi to allocate the Rs. 1 denominations into a number of pouches such that any amount required between Rs.1 & Rs. 200 can be given by giving out a certain number of pouches without opening them. Aditi thinks and asks the judge to give her 'x' number of pouches to keep the money, where 'x' is the minimum number of bags required to keep the total money. Can you guess the value of 'x'?

Answer» ONG>Answer:

you have taken this from VEDANTU VOTE DAILY challenge (2)

I have also attempted this and I wrote 17

Discussion

46.	a man's salary is 28800 a year.He gets an increase of rs.5040 a year.What percentage increase does he get?
Answer» en :- Salary = ₹28800 INCREASE in salary = ₹5040 Aim :- To FIND the increase percentage. Formula to use :- $\longrightarrow \sf{increase\% = \dfrac{increase}{original \: price} \times 100}$ SUBSTITUTING, Answer :- $\implies \sf{increase\% = \dfrac{5040}{28800} \times 100}$ CANCELLING, $\implies \sf{increase\% = \dfrac{5040}{288 \not0 \not0} \times 1 \not0\not0}$ $\implies \sf{increase\% = \dfrac{5040}{288} }$ By REDUCING to the lowest terms, we get :- $\implies \sf{increase\% = 17.5\%}$ Some more formulas :- $\longrightarrow \sf{selling \: price = \dfrac{100 + profit\%}{100} \times cost \: price}$ $\longrightarrow \sf{selling \: price = \dfrac{100 -loss\% }{100} \times cost \: price}$ $\longrightarrow \sf{ cost \: price = \dfrac{100}{100 + profit\%} \times \: selling \: price}$ $\longrightarrow \sf{cost \: price = \dfrac{100}{100 - loss\%} \times selling \: price}$

46.

a man's salary is 28800 a year.He gets an increase of rs.5040 a year.What percentage increase does he get?

Answer»

en :-

Salary = ₹28800
INCREASE in salary = ₹5040

Aim :-

To FIND the increase percentage.

Formula to use :-

$\longrightarrow \sf{increase\% = \dfrac{increase}{original \: price} \times 100}$

SUBSTITUTING,

Answer :-

$\implies \sf{increase\% = \dfrac{5040}{28800} \times 100}$

CANCELLING,

$\implies \sf{increase\% = \dfrac{5040}{288 \not0 \not0} \times 1 \not0\not0}$

$\implies \sf{increase\% = \dfrac{5040}{288} }$

By REDUCING to the lowest terms, we get :-

$\implies \sf{increase\% = 17.5\%}$

Some more formulas :-

$\longrightarrow \sf{selling \: price = \dfrac{100 + profit\%}{100} \times cost \: price}$

$\longrightarrow \sf{selling \: price = \dfrac{100 -loss\% }{100} \times cost \: price}$

$\longrightarrow \sf{ cost \: price = \dfrac{100}{100 + profit\%} \times \: selling \: price}$

$\longrightarrow \sf{cost \: price = \dfrac{100}{100 - loss\%} \times selling \: price}$

Discussion

47.	(3°+2°)×5° is equal to ? (a) 3(b) 2 (c) 1(d) 5please help me
Answer» ONG>Answer: B) is the correct option Step-by-step explanation: (3° + 2°) x 5° any number with POWER 0 is always 1 (1 + 1) x 1 = 2 x 1 = 2

47.

(3°+2°)×5° is equal to ? (a) 3(b) 2 (c) 1(d) 5please help me

Answer» ONG>Answer:

B) is the correct option

Step-by-step explanation:

(3° + 2°) x 5°

any number with POWER 0 is always 1

(1 + 1) x 1

= 2 x 1

= 2

Discussion

48.	) In a bag there are 3 red balls, 2 white balls and 5 yellow balls. The probability of getting a white ball isa) 35b)28c)15d)5
Answer» ong>Answer: b 2/5 because a CHANCE of gatting ot have 2 items inthi astyoe of thinv

48.

) In a bag there are 3 red balls, 2 white balls and 5 yellow balls. The probability of getting a white ball isa) 35b)28c)15d)5

Answer»

ong>Answer:

b 2/5

because a CHANCE of gatting ot have 2 items inthi astyoe of thinv

Discussion

49.	1. 7th term of an AP is 10, sum of first 7 terms in it is 40 then sum of first 6terms in that AP is A) 33 B) 30 C) 43 D) 47
Answer» ONG>ANSWER: 30 is the RIGHT answer I THINK huehuehuehuhuehuhiehuhuehuhehueheuehuheueheuehueheyehuehueheuehuehuehuehueh

Discussion

50.	Find common diffence of AP √18, 6, √72
Answer» ONG>ANSWER: A1 =a+d 6=√18+d 6√18=d 12√2= d

50.

Find common diffence of AP √18, 6, √72

Answer» ONG>ANSWER:

A1 =a+d

6=√18+d

6√18=d

12√2= d

Discussion

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