a man's salary is 28800 a year.He gets an increase of rs.5040 a year.W

1.	a man's salary is 28800 a year.He gets an increase of rs.5040 a year.What percentage increase does he get?
Answer» en :- Salary = ₹28800 INCREASE in salary = ₹5040 Aim :- To FIND the increase percentage. Formula to use :- $\longrightarrow \sf{increase\% = \dfrac{increase}{original \: price} \times 100}$ SUBSTITUTING, Answer :- $\implies \sf{increase\% = \dfrac{5040}{28800} \times 100}$ CANCELLING, $\implies \sf{increase\% = \dfrac{5040}{288 \not0 \not0} \times 1 \not0\not0}$ $\implies \sf{increase\% = \dfrac{5040}{288} }$ By REDUCING to the lowest terms, we get :- $\implies \sf{increase\% = 17.5\%}$ Some more formulas :- $\longrightarrow \sf{selling \: price = \dfrac{100 + profit\%}{100} \times cost \: price}$ $\longrightarrow \sf{selling \: price = \dfrac{100 -loss\% }{100} \times cost \: price}$ $\longrightarrow \sf{ cost \: price = \dfrac{100}{100 + profit\%} \times \: selling \: price}$ $\longrightarrow \sf{cost \: price = \dfrac{100}{100 - loss\%} \times selling \: price}$

a man's salary is 28800 a year.He gets an increase of rs.5040 a year.What percentage increase does he get?

Answer»

en :-

$\longrightarrow \sf{increase\% = \dfrac{increase}{original \: price} \times 100}$

$\implies \sf{increase\% = \dfrac{5040}{28800} \times 100}$

$\implies \sf{increase\% = \dfrac{5040}{288 \not0 \not0} \times 1 \not0\not0}$

$\implies \sf{increase\% = \dfrac{5040}{288} }$

By REDUCING to the lowest terms, we get :-

$\implies \sf{increase\% = 17.5\%}$

$\longrightarrow \sf{selling \: price = \dfrac{100 + profit\%}{100} \times cost \: price}$

$\longrightarrow \sf{selling \: price = \dfrac{100 -loss\% }{100} \times cost \: price}$

$\longrightarrow \sf{ cost \: price = \dfrac{100}{100 + profit\%} \times \: selling \: price}$

$\longrightarrow \sf{cost \: price = \dfrac{100}{100 - loss\%} \times selling \: price}$