332354 + Interview Questions in Secondary School in Math

1.	So, -1/2 would be marked at a pointhalf the distance between 0 and –1.Now represent the following rationals onnumber lines.(i) 3/5 (ii) -4/7 (iii)2/3anaser is -4/7 is
Answer» ong>ANSWER: 23 is the CORRECT answer please SET me Brainlist

1.

So, -1/2 would be marked at a pointhalf the distance between 0 and –1.Now represent the following rationals onnumber lines.(i) 3/5 (ii) -4/7 (iii)2/3anaser is -4/7 is

Answer»

ong>ANSWER:

23 is the CORRECT answer

please SET me Brainlist

Discussion

2.	Tan60/sin60+cos30 solution
Answer» ONG>ANSWER: $\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$ Step-by-step EXPLANATION: $\frac{Tan \: 60°}{Sin \: 60°+Cos \: 30°}$ $=> \frac{√3}{ \frac{√3}{2} + \frac{√3}{2} }$ $= \frac{√3}{ \frac{√3+√3}{2} }$ $= \frac{√3}{ \frac{2√3}{2} }$ $= \frac{ √3}{ √3}$ $= 1$ $please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$ $\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$ $\star \: i \: hope \: you \: will \: understand \: me\star$

2.

Tan60/sin60+cos30 solution

Answer» ONG>ANSWER:

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

Step-by-step EXPLANATION:

$\frac{Tan \: 60°}{Sin \: 60°+Cos \: 30°}$

$=> \frac{√3}{ \frac{√3}{2} + \frac{√3}{2} }$

$= \frac{√3}{ \frac{√3+√3}{2} }$

$= \frac{√3}{ \frac{2√3}{2} }$

$= \frac{ √3}{ √3}$

$= 1$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

$\star \: i \: hope \: you \: will \: understand \: me\star$

Discussion

3.	. Form a quadratie polynomial whose one zero is 6 and sum of the zeroes is 0.
Answer» ONG>ANSWER: MAY be it is HELPFUL for you.

Discussion

4.	Than three times the amount Rafik has. If 300 from the amount with Ratna are given to Rafik, amount with Ratna will beamount with Rafik. Find the initial amount with Rafik.To find the initial amount, complete the following acitivity.7times the4Solution: The amount with Ratna is 200 more than three times the amount withRafik.Let the initial amount with Rafik be 3x... Ratna has..*300 from Ratna are given to Rafik.:: Remaining amount with Ratna is... Now Rafik has ( x + 300)7Now the amount with Ratna is times the amount with Rafik4Amount with Ratna... 128-400 = 7x + 2100Amount with Rafik.. 12x - 7x =3r-100... 5.x =+300.. =4= 7.. Rafik initially haswith him
Answer» ONG>Answer: it's are easy when I became PROFESSOR

Discussion

5.	Subtract 4/5 - 1/8 Pls answer this question
Answer» - 1/8 =27/40 =0.675 Hope it helps. Pls MARK this BRAINLIEST

5.

Subtract 4/5 - 1/8 Pls answer this question

Answer»

- 1/8

=27/40

=0.675

Hope it helps.

Pls MARK this BRAINLIEST

Discussion

6.	Please give me a answer of 29 30 and 31
Answer» ONG>ANSWER: I don't KNOW answer for this SORRY

Discussion

7.	the ratio of the length of the parallel sides of a trapezium is 5:3 and the distance between them is 16 cm .if the area of the trapezium is 960 cm² , find the length of the part sides
Answer» > $\huge \fbox \green{❤Solution:}$ $Let \: the \: <klux>SIDES</klux> \: be \: 5x \: and \: 3x$ Given $H = 16 \: <klux>CM</klux>$ $A = 960 \: {cm}^{2}$ $\sf \colorbox{god} {Now Area is Given as }$ $⇒960 = \frac{1}{2} \times 16 \times (5x + 3x)$ $⇒960 = 8 \times 8x$ $⇒64x = 960$ $:x = 15$ $⇒5x = 5 \times 15 = 75$ $⇒3x = 3 \times 15 = <klux>45</klux>$ Therefore, the PARALLEL sides are 45 cm and 75 cm. $\\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

7.

the ratio of the length of the parallel sides of a trapezium is 5:3 and the distance between them is 16 cm .if the area of the trapezium is 960 cm² , find the length of the part sides

Answer»

>

$\huge \fbox \green{❤Solution:}$

$Let \: the \: <klux>SIDES</klux> \: be \: 5x \: and \: 3x$

Given

$H = 16 \: <klux>CM</klux>$

$A = 960 \: {cm}^{2}$

$\sf \colorbox{god} {Now Area is Given as }$

$⇒960 = \frac{1}{2} \times 16 \times (5x + 3x)$

$⇒960 = 8 \times 8x$

$⇒64x = 960$

$:x = 15$

$⇒5x = 5 \times 15 = 75$

$⇒3x = 3 \times 15 = <klux>45</klux>$

Therefore, the PARALLEL sides are 45 cm and 75 cm.

$\\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

Discussion

8.	The cost of a bowl is 324.50. Find the cost of 26 such bowls.
Answer» ONG>Answer: One BOWL COSTS= Rs.324.50 Therefore, COST of 26 such bowls=324.50×26 =Rs8424.50

8.

The cost of a bowl is 324.50. Find the cost of 26 such bowls.

Answer» ONG>Answer:

One BOWL COSTS= Rs.324.50

Therefore, COST of 26 such bowls=324.50×26

=Rs8424.50

Discussion

9.	The perimeter of a rectangle is 48m.The area of the rectangle is 44m^2.find the length and breadth of that rectangle
Answer» ong>ANSWER: u GLENN Flavio does too HALLO TAIL Soleil

9.

The perimeter of a rectangle is 48m.The area of the rectangle is 44m^2.find the length and breadth of that rectangle

Answer»

ong>ANSWER:

u GLENN Flavio does too HALLO TAIL Soleil

Discussion

10.	Rohan went to a park whose length was 2500 and with was 1200 hi to 5 round of the park at the same speed considering date he travelled along the boundary what is the perimeter of the park
Answer» ONG>ANSWER: BRO answer is 7,400 Perimeter formula is 2(l+b) 2(1200+2500) 2*3700 =7,400

10.

Rohan went to a park whose length was 2500 and with was 1200 hi to 5 round of the park at the same speed considering date he travelled along the boundary what is the perimeter of the park

Answer» ONG>ANSWER:

BRO answer is 7,400

Perimeter formula is 2*(l+b)

2*(1200+2500)

2*3700

=7,400

Discussion

11.	0.5x+0.3y=4.560.02x-0.9y=-0.912
Answer» ong>Answer: 23 is the CORRECT answer please SET me Brainlist

11.

0.5x+0.3y=4.560.02x-0.9y=-0.912

Answer»

ong>Answer:

23 is the CORRECT answer

please SET me Brainlist

Discussion

12.	1.00 IS! THE = 71 h) In Fig. 14, prove that AABD = ACDB.40 mH1 m11.5 mGTAB.Plot APlot B20 mDFig. 13-E아Fig. 14F please anyone answer don't spam
Answer»

Discussion

13.	Find the zero of polynomial p(x)=2x +3
Answer» ZERO of 2X + 3 is -32. by nivaskumar ♥️✌️

13.

Find the zero of polynomial p(x)=2x +3

Answer»

ZERO of 2X + 3 is -32.

by nivaskumar ♥️✌️

Discussion

14.	A train left a station at 8:35 am and arrived at its destination at 3:12 pm how long did the journey take
Answer» ong>Answer: so , simply we need to SUBTRACT them to get answer 8.35 -. 3.12 =5.23 it TOOK 5.23 hours

14.

A train left a station at 8:35 am and arrived at its destination at 3:12 pm how long did the journey take

Answer»

ong>Answer:

so , simply we need to SUBTRACT them to get answer

8.35

-. 3.12

=5.23

it TOOK 5.23 hours

Discussion

15.	Model of a boat is made on the scale of 1:8. The model is 160 cm long. The full size of the boat has a width of 240 cm. What is the width of the scale model ? i) 60 cm ii) 20 cm iii) 40 cm iv) 30 cm
Answer» ong>Answer: model of a BOAT is made on the SCALE of 1:8. The model is 160 cm long. The full size of the boat has a width of 240 cm. What is the width of the scale model ? i) 60 cm ii) 20 cm iii) 40 cm iv) 30 cm the answer is 15cm

15.

Model of a boat is made on the scale of 1:8. The model is 160 cm long. The full size of the boat has a width of 240 cm. What is the width of the scale model ? i) 60 cm ii) 20 cm iii) 40 cm iv) 30 cm

Answer»

ong>Answer:

model of a BOAT is made on the SCALE of 1:8. The model is 160 cm long. The full size of the boat has a width of 240 cm. What is the width of the scale model ?

i) 60 cm

ii) 20 cm

iii) 40 cm

iv) 30 cm

the answer is 15cm

Discussion

16.	25. The radius of the base of a cyclinder is 7cm and its height is 30cm Find the T.S.A. and volume.
Answer» ong>Answer: HOPE it helps you Step-by-step EXPLANATION: *PLZ* *follow* me

16.

25. The radius of the base of a cyclinder is 7cm and its height is 30cm Find the T.S.A. and volume.

Answer»

ong>Answer:

HOPE it helps you

Step-by-step EXPLANATION:

PLZ follow me

Discussion

17.	3/5,2/5,6/5 are _____triangle
Answer» ONG>Answer: 6/5 Step-by-step explanation: PLS MAKE me brainleast pls mark me brainleast

17.

3/5,2/5,6/5 are _____triangle

Answer» ONG>Answer:

6/5

Step-by-step explanation:

PLS MAKE me brainleast

pls mark me brainleast

Discussion

18.	6. Q3. A Projectile is Projected in to the air with initial velocity u & its direction makesan angle with the horizontal. Time oflight is equal to *(1 Point)u sin O/gu sin 20/gO2u sin O/gO u sin 0/2g
Answer» ong>Answer: Time of FLIGHT = 2u sinθ/ G Step-by-step explanation: time of ascent => V = u + at 0 = u sinθ - gt. ( component of u responsible for ascent is the VERTICAL ONE ) t = u sinθ/ g total time = time of ascent + time of descent = 2 × time of ascent ( time of ascent = time of descent ) = 2 × u sinθ / g

18.

6. Q3. A Projectile is Projected in to the air with initial velocity u & its direction makesan angle with the horizontal. Time oflight is equal to *(1 Point)u sin O/gu sin 20/gO2u sin O/gO u sin 0/2g

Answer»

ong>Answer:

Time of FLIGHT = 2u sinθ/ G

Step-by-step explanation:

time of ascent => V = u + at

0 = u sinθ - gt. ( component of u responsible for ascent is the VERTICAL ONE )

t = u sinθ/ g

total time = time of ascent + time of descent

= 2 × time of ascent ( time of ascent = time of descent )

= 2 × u sinθ / g

Discussion

19.	1. Find each of the following products:3÷5×15
Answer» ONG>Step-by-step explanation: 3÷5×5 3÷5= 0.6 phele is sum me ÷ HOTA he uske bad × ye math ka RUL he so, 0.6 × 5 = 3

19.

1. Find each of the following products:3÷5×15

Answer» ONG>Step-by-step explanation:

3÷5×5

3÷5= 0.6 phele is sum me ÷ HOTA he uske bad × ye math ka RUL he

so,

0.6 × 5 = 3

Discussion

20.	5(5*-10)=15
Answer» ONG>ANSWER: zygddydytutututicj Step-by-step EXPLANATION: HJ

20.

5(5*-10)=15

Answer» ONG>ANSWER:

zygddydytutututicj

Step-by-step EXPLANATION:

HJ

Discussion

21.	Solve : sin 30 × cos 30
Answer» -0.15240531055 HOPE it helps. Pls MARK this BRAINLIEST

21.

Solve : sin 30 × cos 30

Answer»

-0.15240531055

HOPE it helps.

Pls MARK this BRAINLIEST

Discussion

22.	Product of 2 number is 1728 if their hcf is 48 find their lcm
Answer» ONG>Answer: .HCF are given, we find the LCM by using the identity H x L = A x B. So, L = 1728 /12 = 144 LCM is always divisible by HCF. L/H = 144/12 = 12 Now 12 can be SPLIT only as 1x 12 or 2x6 or 3 x 4 We take each pair and multiply the NUMBERS in each pair by the HCF. We get now the pairs (12, 144), (24, 72) and (36, 48) We can OBSERVE that each pair except (2, 72) satisfies the criteria: Product of numbers = 1728, HCF = 12 and LCM = 144 (which we obtained) HOPE IT WILL BE HELPFUL PLEASE MARK ME AS BRAINLIEST

22.

Product of 2 number is 1728 if their hcf is 48 find their lcm

Answer» ONG>Answer:

.HCF are given, we find the LCM by using the identity H x L = A x B.

So, L = 1728 /12 = 144

LCM is always divisible by HCF.

L/H = 144/12 = 12

Now 12 can be SPLIT only as 1x 12 or 2x6 or 3 x 4

We take each pair and multiply the NUMBERS in each pair by the HCF.

We get now the pairs (12, 144), (24, 72) and (36, 48)

We can OBSERVE that each pair except (2, 72) satisfies the criteria: Product of numbers = 1728, HCF = 12 and LCM = 144 (which we obtained)

HOPE IT WILL BE HELPFUL

PLEASE MARK ME AS BRAINLIEST

Discussion

23.	1- Subtract the first-rational number from the second rational4number from5
Answer» ong>ANSWER: I will tell U answer Step-by-step explanation: hi OK.

23.

1- Subtract the first-rational number from the second rational4number from5

Answer»

ong>ANSWER:

I will tell U answer

Step-by-step explanation:

hi OK.

Discussion

24.	22If 3x+4y=18 and xy=6, find the value of 9x^+ 16y
Answer» ong>Answer: 23 is the CORRECT answer please SET me Brainlist

24.

22If 3x+4y=18 and xy=6, find the value of 9x^+ 16y

Answer»

ong>Answer:

23 is the CORRECT answer

please SET me Brainlist

Discussion

25.	If 32 is added to 80% of a number the result is the number itself. Find the number.
Answer» ong>Answer: 160 Step-by-step explanation: SINCE 100% of a number is the number itself, On adding 32 to 80% of a number to give the number itself, 32 must be 20% of the number. Therefore, 20% X Number = 32 Number = 32 x 5 = 160

25.

If 32 is added to 80% of a number the result is the number itself. Find the number.

Answer»

ong>Answer:

160

Step-by-step explanation:

SINCE 100% of a number is the number itself,

On adding 32 to 80% of a number to give the number itself, 32 must be 20% of the number.

Therefore, 20% X Number = 32

Number = 32 x 5 = 160

Discussion

26.	One The person ₹ 330000 to his daughter, wife and son in thisType divides 1/2 part of daughter, 1/4 of wifePart and son ka 1/5The parts are equal. What is the daughter's share?
Answer» ONG>Answer: 165000 Step-by-step EXPLANATION:

26.

One The person ₹ 330000 to his daughter, wife and son in thisType divides 1/2 part of daughter, 1/4 of wifePart and son ka 1/5The parts are equal. What is the daughter's share?

Answer» ONG>Answer:

165000

Step-by-step EXPLANATION:

Discussion

27.	write order of rotation and angle of rotation of (1)equilateral triangle,(2) circle,(3) regular hexagon
Answer» ONG>Answer: 1)equilateral TRIANGLE -120° 2)Circle- any angle 3)Regular HEXAGON- 60°

27.

write order of rotation and angle of rotation of (1)equilateral triangle,(2) circle,(3) regular hexagon

Answer» ONG>Answer:

1)equilateral TRIANGLE -120°

2)Circle- any angle

3)Regular HEXAGON- 60°

Discussion

28.	Class intervals like 0-10, 10-20, 20-30 _____ are called ?
Answer» ONG>Answer: 1 to 5, 5 to 15 , JOBS to jobs are CALLED life CYCLE .

Discussion

29.	(3⁰+2⁰)×5⁰ is equal to??
Answer» ONG>Answer: 25° Step-by-step EXPLANATION: (3+2)X5 =(5x5 =25 hshdnekejejdhbsbsbss

29.

(3⁰+2⁰)×5⁰ is equal to??

Answer» ONG>Answer:

25°

Step-by-step EXPLANATION:

(3+2)X5

=(5x5

=25

hshdnekejejdhbsbsbss

Discussion

30.	Question 10:tantan? 6+4 tan 6+3
Answer» ONG>ANSWER: dgzfdhfhfhfyfgfudgdgdgdgdgdgdgxfdgdgdghdugd

Discussion

31.	If a and b are rational numbers and 5+2root3 upon 7+4root3 = a-b root 3, find the value of a and b.
Answer» stion :- If a and B are RATIONAL numbers and $\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } = a - b \sqrt{3}$ , FIND the values of a and b. Required SOLUTION :- $\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } = \frac{5 + 2\sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } = \frac{35 - 20 \sqrt{3 } + 14 \sqrt{3} - 8 \times 3}{ {7}^{2} - (4 \sqrt{3}) ^{2} }$ $\frac{11 - 6 \sqrt{3} }{49 - 48} = \frac{11 - 6 \sqrt{3} }{1} = 11 - 6 \sqrt{3}$ ∴ a - b $\sqrt{3}$ = 11 - 6 $\sqrt{3}$ ⟹ A = 11 and B = 6 $\text{[math]}$

31.

If a and b are rational numbers and 5+2root3 upon 7+4root3 = a-b root 3, find the value of a and b.

Answer»

stion :-

If a and B are RATIONAL numbers and $\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } = a - b \sqrt{3}$ , FIND the values of a and b.

Required SOLUTION :-

$\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } = \frac{5 + 2\sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } = \frac{35 - 20 \sqrt{3 } + 14 \sqrt{3} - 8 \times 3}{ {7}^{2} - (4 \sqrt{3}) ^{2} }$

$\frac{11 - 6 \sqrt{3} }{49 - 48} = \frac{11 - 6 \sqrt{3} }{1} = 11 - 6 \sqrt{3}$

∴ a - b $\sqrt{3}$ = 11 - 6 $\sqrt{3}$

⟹ A = 11 and B = 6 $\text{[math]}$

Discussion

32.	Total cost of a product Rs 10.000. Profit 25% on selling price. Profit is
Answer» ONG>Answer: 2500 RUPEES is 25PERCENT of 10000

32.

Total cost of a product Rs 10.000. Profit 25% on selling price. Profit is

Answer» ONG>Answer:

2500 RUPEES is 25PERCENT of 10000

Discussion

33.	How many altitudes can a triangle have ? a) 1 b) 2 c) 3 d) 4
Answer» 3 is the answer in any TRIANGLE there is only 3 ALTITUDE

33.

How many altitudes can a triangle have ? a) 1 b) 2 c) 3 d) 4

Answer»

3 is the answer

in any TRIANGLE there is only 3 ALTITUDE

Discussion

34.	Rice is available at 50/kg. If a shopkeeper allows 10% discount then how much kgof rice will be purchased for 202.50 ?
Answer» ong>Answer: For example Step-by-step explanation: Total quantity = 80 kg COST of 80 kg rice = 8090 =7200 He got 1 kg extra rice on the purchase of 20 kg rice. So, he got 4 kg of extra rice on the purchase of 80 kg rice. so total quantity of rice = 80+4 = 84 kg cost PRICE of 84 kg rice is = 7200 selling price of 84 kg rice is = 84100= 8400 Profit = 8400 - 7200 = 1200 profit % = profit 100/ cost price profit % = 1200100/7200 = 1200/72 = 100/6 = 50/3=16^2/3 %

34.

Rice is available at 50/kg. If a shopkeeper allows 10% discount then how much kgof rice will be purchased for 202.50 ?

Answer»

ong>Answer:

For example

Step-by-step explanation:

Total quantity = 80 kg

COST of 80 kg rice = 80*90 =7200

He got 1 kg extra rice on the purchase of 20 kg rice. So, he got 4 kg of extra rice on

the purchase of 80 kg rice. so total quantity of rice = 80+4 = 84 kg

cost PRICE of 84 kg rice is = 7200

selling price of 84 kg rice is = 84*100= 8400

Profit = 8400 - 7200 = 1200

profit % = profit *100/ cost price

profit % = 1200*100/7200 = 1200/72 = 100/6 = 50/3=16^2/3 %

Discussion

35.	rectangular Park is 45 metres long and 30 metres wide a path 2.5 metre wide is constructed outside the park find the area of the path
Answer» ONG>Answer: answer is 203.75 m SQUARE Step-by-step explanation: AREA of RECTANGULAR PARK =45×30=1350 area of rectangular park and path=45+2.5×30+2.5 =1553.75 area of path = 203.75 m square

35.

rectangular Park is 45 metres long and 30 metres wide a path 2.5 metre wide is constructed outside the park find the area of the path

Answer» ONG>Answer:

answer is 203.75 m SQUARE

Step-by-step explanation:

AREA of RECTANGULAR PARK =45×30=1350

area of rectangular park and path=45+2.5×30+2.5

=1553.75

area of path = 203.75 m square

Discussion

36.	Solve it= 2.5×5.02 answer me
Answer» ONG>ANSWER: 12.55 will be the CORRECT answer

Discussion

37.	In the given figure, seg PA, seg QB and seg RC are perpendicular to seg AC.From the information given prove that 1/x + 1/z= 1/y
Answer» ong>Step-by-step explanation: CONSIDER △CAP and △CBQ ∠CAP=∠CBQ=90 ∘ ∠PCA=∠QCB (COMMON angle) So by AA, △CAP∼△CBQ Hence AP BQ = AC BC x y = AC BC (1) Now consider △ACR and △ABQ ∠ACR=∠ABQ=90 ∘ ∠QAB=∠RAC (common angle) So by AA, △ACR∼△ABQ Hence CR BQ = AC AB z y = AC AB (2) ADDING (1) and (2) x y + z y = AC BC + AC AB y( x 1 + z 1 )= AC BC+AB y( x 1 + z 1 )= AC AC y( x 1 + z 1 )=1 x 1 + z 1 = y 1 Hence proved. helpful to you

37.

In the given figure, seg PA, seg QB and seg RC are perpendicular to seg AC.From the information given prove that 1/x + 1/z= 1/y

Answer»

ong>Step-by-step explanation:

CONSIDER △CAP and △CBQ

∠CAP=∠CBQ=90

∘

∠PCA=∠QCB (COMMON angle)

So by AA, △CAP∼△CBQ

Hence

AP

BQ

=

AC

BC

x

y

=

AC

BC

(1)

Now consider △ACR and △ABQ

∠ACR=∠ABQ=90

∘

∠QAB=∠RAC (common angle)

So by AA, △ACR∼△ABQ

Hence

CR

BQ

=

AC

AB

z

y

=

AC

AB

(2)

ADDING (1) and (2)

x

y

+

z

y

=

AC

BC

+

AC

AB

y(

x

1

+

z

1

)=

AC

BC+AB

y(

x

1

+

z

1

)=

AC

y(

x

1

+

z

1

)=1

x

1

+

z

1

=

y

1

Hence proved.

helpful to you

Discussion

38.	The length of the side of a square(0.5*0.5cm)is increased by 1%.By what percentage the area of the square increase?
Answer» ONG>Answer: please question it PROPERLY

Discussion

39.	Mode of 10,12,15,10,17,19,10,22,12,10 is _____________ ?
Answer» ong>ANSWER: Mode of the given DATA is its HIGHEST frequency HENCE, mode of data is 10

39.

Mode of 10,12,15,10,17,19,10,22,12,10 is _____________ ?

Answer»

ong>ANSWER:

Mode of the given DATA is its HIGHEST frequency

HENCE, mode of data is 10

Discussion

40.	Find the value of 2sin245degree ampont cos230 degree + 4 sin 2 60degree ampont 3 tan230 degree
Answer» ONG>Answer: bhai MAJHA pata HA answer is question ka

Discussion

41.	प्रत्येक में से कौन सा बड़ा है?-2/3, -3/2
Answer» ong>ANSWER IS -2/3 *EXPLANATION=BECAUSE* *NEGATIVE* SMALL *NUMBERS* *ARE* *GREATER* *THAN* *THE* *BIG* *NEGATIVE* *NUMBERS* *PLEASE* *MARK* ME AS *BRAINLEST* *PLEASE*

41.

प्रत्येक में से कौन सा बड़ा है?-2/3, -3/2

Answer»

ong>ANSWER IS -2/3

EXPLANATION=BECAUSE NEGATIVE SMALL NUMBERS ARE GREATER THAN THE BIG NEGATIVE NUMBERS

PLEASE MARK ME AS BRAINLEST PLEASE

Discussion

42.	Verify the commutative property of addition for the following pairs of the rational numbers. b.-2/-5 and 1/3
Answer» ONG>Answer: no commutative PROPERTY is not USED here we have used associative property

Discussion

43.	Factorise: a - 36 2 − 8ab + 16b 2 c 2 .
Answer» ONG>Answer: prepare a Presentation on the topic: Effects of the CoviD-19 Pandemic the on Indian economy.about 400 word

43.

Factorise: a - 36 2 − 8ab + 16b 2 c 2 .

Answer» ONG>Answer:

prepare a Presentation

on the topic:

Effects of the CoviD-19 Pandemic

the on

Indian economy.about 400 word

Discussion

44.	Find the coordinates of points which trisect the line segment joining the point A(5,-3) and B (2,-9)
Answer» ong>Answer: (4, -5) A trisection point on a line segment trisects that line segment into THREE equal parts. Here, 1 : 2 A •------------•----------------------------• B C Given that, A = (5, -3) B = (2, -9) C = (x, y) Which means, The point c divides the line segment in the ratio 1 : 2 which is m : n Using the section formula, we can find the COORDINATE of the point C, ⇒ Cₓ = ( mx₂ + nx₁ ) / (m + n) ⇒ Cₓ = (1 × 2 + 2 × 5) / (2 + 1) ⇒ Cₓ = (2 + 10) / 3 ⇒ Cₓ = 12 / 3 ⇒ Cₓ = 4 Here, We got the abscissa of the point C to be 4. Let US find the ordinate now, ⇒ Cᵧ = ( my₂ + ny₁ ) / (m + n) ⇒ Cᵧ = ( 1 × -9 + 2 × -3 ) / (1 + 2) ⇒ Cᵧ = ( -9 - 6 ) / 3 ⇒ Cᵧ = -15/3 ⇒ Cᵧ = -5 So, we got the ordinate to be -5. Hence, The point C is (4, -5) Note:- Abscissa = x Ordinate = y Coordinate = (Abscissa, Ordinate)

44.

Find the coordinates of points which trisect the line segment joining the point A(5,-3) and B (2,-9)

Answer»

ong>Answer: (4, -5)

A trisection point on a line segment trisects that line segment into THREE equal parts.

Here,

1 : 2

A •------------•----------------------------• B

C

Given that,

A = (5, -3)

B = (2, -9)

C = (x, y)

Which means, The point c divides the line segment in the ratio 1 : 2 which is m : n

Using the section formula, we can find the COORDINATE of the point C,

⇒ Cₓ = ( mx₂ + nx₁ ) / (m + n)

⇒ Cₓ = (1 × 2 + 2 × 5) / (2 + 1)

⇒ Cₓ = (2 + 10) / 3

⇒ Cₓ = 12 / 3

⇒ Cₓ = 4

Here, We got the abscissa of the point C to be 4.

Let US find the ordinate now,

⇒ Cᵧ = ( my₂ + ny₁ ) / (m + n)

⇒ Cᵧ = ( 1 × -9 + 2 × -3 ) / (1 + 2)

⇒ Cᵧ = ( -9 - 6 ) / 3

⇒ Cᵧ = -15/3

⇒ Cᵧ = -5

So, we got the ordinate to be -5.

Hence, The point C is (4, -5)

Note:-

Abscissa = x

Ordinate = y

Coordinate = (Abscissa, Ordinate)

Discussion

45.	Calculate the number of unit cells in 0.3 g of a species having density of 8.5 g/cm' and unit cell edge length 3.25x10^-8 cm.
Answer» ONG>ANSWER: x/pa³ 0.3/(8.5×3.43×10^-24) 1.031×10^-22

45.

Calculate the number of unit cells in 0.3 g of a species having density of 8.5 g/cm' and unit cell edge length 3.25x10^-8 cm.

Answer» ONG>ANSWER:

x/pa³

0.3/(8.5×3.43×10^-24)

1.031×10^-22

Discussion

46.	Simplify (5x + 3)2 + (5x - 3)2
Answer» ONG>Answer: 20x Step-by-step EXPLANATION: (5x+3)2+(5x-3)2 10x+6+10x-6 10x+10x+6-6 20x+0 =20x

46.

Simplify (5x + 3)2 + (5x - 3)2

Answer» ONG>Answer:

20x

Step-by-step EXPLANATION:

(5x+3)2+(5x-3)2

10x+6+10x-6

10x+10x+6-6

20x+0

=20x

Discussion

47.	What rate gives Rs 300 as interest on a sum of Rs 60,000 in 2 years?
Answer» ONG>Given : ↴ $\sf \: SI \: = \: Rs. 300$ $\sf \: Principal \: = \: Rs. 60,000$ $\sf \: Time \: = \: 2 \: years$ To find : ↴ $\sf \: We \: have \: to \: find \: the \: rate \: of \: Interest.$ So, LET's Start : ↴ $\sf \: \longrightarrow \: Simple \: Interest : \: \cfrac{P \times R \times T }{100}$ $\sf \: \longrightarrow \: 300 \: : \: \cfrac{60000 \times R \times 2}{100}$ $\sf \longrightarrow \: Rate \: of \: Interest\: = \cfrac{300 \: \times \: 100 }{60000 \: \times \: 2}$ $\sf \longrightarrow \: Rate \: of \: Interest\: = \cfrac{3 \not0\not0 \: \times \: 1\not0\not0 }{6\not0\not0\not0\not0 \: \times \: 2}$ $\sf \longrightarrow \: Rate \: of \: Interest\: = \cfrac{3 \: \times \: 1 }{6 \: \times \: 2}$ $\sf \longrightarrow \: Rate \: of \: Interest\: = \cfrac{1 \: \times \: 1 }{2 \: \times \: 2}$ $\sf \longrightarrow \: Rate \: of \: Interest\: \:is \: \: \cfrac{1 \: \times \: 1 }{2 \: \times \: 2} \: = \: \cfrac{1}{4} \:$ $\sf \longrightarrow \: Rate \: of \: Interest\: is \: \: \: \cfrac{1}{4} \: \: = \: 0.25$ $\sf Hence,\: the\: rate \: of \: interest\: on\: sum\: is \: 0.25%.$

47.

What rate gives Rs 300 as interest on a sum of Rs 60,000 in 2 years?

Answer» ONG>Given : ↴

$\sf \: SI \: = \: Rs. 300$

$\sf \: Principal \: = \: Rs. 60,000$

$\sf \: Time \: = \: 2 \: years$

To find : ↴

$\sf \: We \: have \: to \: find \: the \: rate \: of \: Interest.$

So, LET's Start : ↴

$\sf \: \longrightarrow \: Simple \: Interest : \: \cfrac{P \times R \times T }{100}$

$\sf \: \longrightarrow \: 300 \: : \: \cfrac{60000 \times R \times 2}{100}$

$\sf \longrightarrow \: Rate \: of \: Interest\: = \cfrac{300 \: \times \: 100 }{60000 \: \times \: 2}$

$\sf \longrightarrow \: Rate \: of \: Interest\: = \cfrac{3 \not0\not0 \: \times \: 1\not0\not0 }{6\not0\not0\not0\not0 \: \times \: 2}$

$\sf \longrightarrow \: Rate \: of \: Interest\: = \cfrac{3 \: \times \: 1 }{6 \: \times \: 2}$

$\sf \longrightarrow \: Rate \: of \: Interest\: = \cfrac{1 \: \times \: 1 }{2 \: \times \: 2}$

$\sf \longrightarrow \: Rate \: of \: Interest\: \:is \: \: \cfrac{1 \: \times \: 1 }{2 \: \times \: 2} \: = \: \cfrac{1}{4} \:$

$\sf \longrightarrow \: Rate \: of \: Interest\: is \: \: \: \cfrac{1}{4} \: \: = \: 0.25$

$\sf Hence,\: the\: rate \: of \: interest\: on\: sum\: is \: 0.25%.$

Discussion

48.	three cubes of each volume 24cm^2 are joined end to end together find the total surface area of the resultant cuboid
Answer» ONG>ANSWER: total surface area of the resultant ccuboid is 168cm². Step-by-step explanation: PLEASE LIKE and brainlist the answer.

48.

three cubes of each volume 24cm^2 are joined end to end together find the total surface area of the resultant cuboid

Answer» ONG>ANSWER:

total surface area of the resultant ccuboid is 168cm².

Step-by-step explanation:

PLEASE LIKE and brainlist the answer.

Discussion

49.	If we subtract from a number and multiply the result by we get what is the number?12515
Answer» ong>Step-by-step explanation: LET us consider the number be X As per the given condition If we subtract 1/2 from a number and multiply the RESULT by 1/2, then we get 1/8. So the equation becomes ⇒ (1/2)(x – 1/2) = (1/8) ⇒ (x – 1/2) = (1/4) ⇒ 4X – 2 = 1 ⇒ 4x = 3 Hence x = 3/4 Therefore 3/4 is the number from which if we subtract 1/2 from a number and multiply the result by 1/2, we get 1/8.

49.

If we subtract from a number and multiply the result by we get what is the number?12515

Answer»

ong>Step-by-step explanation:

LET us consider the number be X

As per the given condition

If we subtract 1/2 from a number and multiply the RESULT by 1/2, then we get 1/8.

So the equation becomes

⇒ (1/2)(x – 1/2) = (1/8)

⇒ (x – 1/2) = (1/4)

⇒ 4X – 2 = 1

⇒ 4x = 3

Hence x = 3/4

Therefore 3/4 is the number from which if we subtract 1/2 from a number and multiply the result by 1/2, we get 1/8.

Discussion

50.	If sec theta+tan theta=p then find the value of sin theta in terms of p
Answer» WER: $\sin(theta) = \frac{ {p}^{2} - 1 }{ {p}^{2} + 1 }$

50.

If sec theta+tan theta=p then find the value of sin theta in terms of p

Answer» WER:

$\sin(theta) = \frac{ {p}^{2} - 1 }{ {p}^{2} + 1 }$

Discussion

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