6. Q3. A Projectile is Projected in to the air with initial velocity

1.	6. Q3. A Projectile is Projected in to the air with initial velocity u & its direction makesan angle with the horizontal. Time oflight is equal to *(1 Point)u sin O/gu sin 20/gO2u sin O/gO u sin 0/2g
Answer» ong>Answer: Time of FLIGHT = 2u sinθ/ G Step-by-step explanation: time of ascent => V = u + at 0 = u sinθ - gt. ( component of u responsible for ascent is the VERTICAL ONE ) t = u sinθ/ g total time = time of ascent + time of descent = 2 × time of ascent ( time of ascent = time of descent ) = 2 × u sinθ / g

6. Q3. A Projectile is Projected in to the air with initial velocity u & its direction makesan angle with the horizontal. Time oflight is equal to *(1 Point)u sin O/gu sin 20/gO2u sin O/gO u sin 0/2g

Answer»

ong>Answer:

Time of FLIGHT = 2u sinθ/ G

Step-by-step explanation:

time of ascent => V = u + at

0 = u sinθ - gt. ( component of u responsible for ascent is the VERTICAL ONE )

t = u sinθ/ g

total time = time of ascent + time of descent

= 2 × time of ascent ( time of ascent = time of descent )

= 2 × u sinθ / g

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6. Q3. A Projectile is Projected in to the air with initial velocity u & its direction makesan angle with the horizontal. Time oflight is equal to *(1 Point)u sin O/gu sin 20/gO2u sin O/gO u sin 0/2g​

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6. Q3. A Projectile is Projected in to the air with initial velocity u & its direction makesan angle with the horizontal. Time oflight is equal to *(1 Point)u sin O/gu sin 20/gO2u sin O/gO u sin 0/2g