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Let the distance covered by the train be x. Also ASSUME the TIME taken by the train when it is never late is t.

In the first CASE: the train gets late by 11 MIN i.e., 11/60 h.

t+(11/60) = x/40

In the second case the train gets late by 5 min i.e., 5/60 h.

t+5=x/50

Now subtract 2 eq from 1 eq,

(11/60) - (6/60) = x/40 - x/50

Solving we find, x=20km

So the VALUE of X is. .

we can USE here the property of successive percentage change

A + B + (AXB)/100

10 + 20 + 10.20/100

30 + 2

32

√10*√15=√10*15 = √2*5*3*5= 5√6 is your ANS

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Sheffield F.C. in Sheffield, England, is the world's oldest SURVIVING independent FOOTBALL CLUB .....

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The data HANDLING can HELP US by showing the data in better WAY

4/7=0.56
so 0.56/8=7.something

52Mondays will be there in an YEAR

2√2 IRRATIONAL
3√343=3√7*7*7=3*7√7=21√7 irrational
√4*3√273 =12√273. irrational
√64*√27 8*3√3=24√3. irrational
√2+√3. irrational
√4+2=2+2=4 rational
√48/27 =√16*3/27 =4*√3/27 irrational
√1 irrational

1) PICTURE ANSWER Of Q5 2) Picture Answer Of Q6.

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Given that, LOG base 5 of 5 ×log base 9 of 4 ×log base 2 of 3
=1×log base 3^2 of 2^2×log base 2 of 3
=1×(2/2) log base 3 of 2×(1/log base 3 of 2)
=1×(1)×1=1
Ans:1

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A MERCHANT buys FLOUR =1700.344 kg

He ADDED flour =594.656

Total flour =1700.344kg +594.656kg
=2300 kg flour
No . of packets =90

Weight in each packet = 2300÷90
=25 kg 670g

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5y-1=0
5y=0+1
y=1/5
y=0.2

Therefore P(y)=0.2 or 1/5

First school DONATED. _ 73475
second school donated _. 73475+2375(75850)
THIRD school donated_. 73475-2962(. 70513)
TOTAL FUND=. 73475+75850+70513=
219838

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-2+5d- -2+5d
4+10d and PLEASE to the BRANLIEST

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33.33% PROFIT is the ANSWER....

1.892 × 1022 micrometres


that's all

by SUJEET YADUVANSHI ☝

Aparimey SANKHYA MEANS???
Is it IRRATIONAL???

It is not FACTOR of 3xcube PLUS 7X

Hey!!!
________________________________
●999 × 999
(1000 - 1)(1000 - 1)
(1000 - 1)^2
(1000)^2 + 1^2 - 2× 1000 ×1
1000000 +1 -2000
1000001 - 2000
998001 Ans.
________________________________
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The CORRECT OPTION is B) 12

2,3,5,7,9 only they are PRIME NUMBER between 1 and 10.

<P>Let P be the POSITIVE NUMBER.

The actual value should have been :

P/6.

The value with the ERROR is 6p

Error = 6p - 1/6p = 35/6p

Percentage error :

35/6p ÷ 6p

35/6p × 1/6p = 35/36

35/36 × 100 = 97.22 %

But where is the ATTACHMENT

X-1=0
therefore X=1
Now,put value of X=1 in the given equation.

a^2(1)^2-3a(1)+3(1)-1=0
a^2(1)-3a+3-1=0
a^2-3a+2=0
Now USE the FACTORISATION METHOD of splitting the middle term...
So,
a^2 -2a-a+2=0
a(a-2)-1(a-2) =0
(a-2) and (a-1) =0
Putting both VALUES against zero.
so we will have
a-2=0 or a-1=0
so. a=2 or a=1. both can be true.

4x^2 - 5x + 3

=> 4( 1 / 2 )^2 - 5( 1 / 2 ) + 3

=> 4( 1 / 4 ) - 5 / 2 + 3

=> 2 / 2 - 5 / 2 + 3

=> ( 2 - 5 + 6 ) / 2

=> 3 / 2

Time PASS kyo KR RHI ho SISTER

Hi
supplementary angle is an angle when they are added they make up 180 degree.
so when a straight angle is BISECTED it BECOMES 90 degree.

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A zero can only OCCUR as RESULT of multiplying 5 with 2. so consider the FACTORS 5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100 now Tolal number of 5 that can be obtained from these factor are 24.so there wiil be 24 zero.

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Because when we SOLVE it we FACE both SITUATIONS LINEAR and SEPRATE

The ANSWER is in the ATTACHED PIC.