Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

A boys age is one fourth that of his father. after24year the boy will be half the age of his father. find their present ages

Answer»

Boy AGE at present =x/4
present age of father=x
by the GIVEN data
x/4 +24=x+24/2
[96+x /4]2 =x+24
96+x =2(x+24)
96-48= 2x-x
x=48

present age of father is x=48 YEARS
present age of son is x/4=48/4=12 years

2.

The sum of three consecutive odd numbers is 33. what are the numbers?

Answer»

Answer:

The numbers are 9,11 and 13.      

Step-by-step explanation:

Given : The SUM of three consecutive odd numbers is 33.

To find : What are the numbers?

SOLUTION :

Let the three consecutive odd numbers are x,x+2,x+4.

According to question,

The sum of three consecutive odd numbers is 33.

x+x+2+x+4=33

ADD LIKE TERMS,

3x+6=33

Subtract 6 both side,

3x=27

Divide by 3 both side,

\frac{3x}{3}=\frac{27}{3}

x=9

So, The consecutive odd numbers are

x=9

x+2=9+2=11

x+4=9+4=13

Therefore, The numbers are 9,11 and 13.

3.

Without actually calculating the cubes find the value of 48^3 - 30^3 - 18^3

Answer»

It will HELPFUL for U.....

4.

Prove that cos2A÷1+sin2A=tan (45°-A)

Answer»

Cos2A=(cosA^2-sinA^2)= cosA^2( 1-tanA^2) =1-tanA^2/(secA^2). =1-tanA^2/1+ tanA^2. 1+sin2A= sinA^2+ cosA^2+ 2 sinAcosA. hence 1+sin2A =(sinA+ cosA)^2 = cosA ^2((tanA+1)^2). cos2A/1+sin2A= (1-tanA)(1+tanA)/ (secA^2.cosA^2)(1+tanA)(1+tanA)=(1-tanA)/(1+tanA) hence TAN45-tanA/1+ tan45tanA since tan45 is 1 only it can be WRITTEN as TAN(45-A). hence PROVED . please mark it as brainliest

5.

Define(a) Juvenile phase,(b) Reproductive phase,(c) Senescent phase

Answer»

1. JUVENILE PHASE=> it is the period of growth in an individual organism after it's BIRTH before it reaches the reproductive phase.

2. Reproductive phase=> what is the period when an individual organism reproduces sexually.

3. Senescent phase=> it is the period when an organism grows old and loses its ability to REPRODUCE.

6.

all faces of a cube with an eight-meter edge are painted red. if the cube is cut into smaller cubes with a two-meter edge how many of the two-meter cubes have paint on exactly one face?

Answer»

if the 8 meter edge cube will be CUT into 2 meter edge smaller cubes then there will be total 64 such cubes


and only 4 cubes on each face will be having one painted face and there are 6 such faces so 4 X 6 = 24 such cubes will have only one painted face

7.

If one zero of the quadratic polynomial x square + 3 x + k is 2 find the value of k

Answer» P(2)=(2)^2+3(2)+K=0
4+6+k=0
k=(-10)
8.

Please solve this fast friends 2a²-ab - ac -3b²+4bc ; when a=1, b= -1 and c = 2

Answer» HELLO here is your ANSWER by SUJEET YADUVANSHI ☝☝☝☝☝☝☝☝☝

that's all
9.

LCM of 110592 in detail

Answer»

Here's your ANSWER.

HOPE it helps.

Mark me as BRAINLIEST

10.

If the area of a rectangle is 16s2t and the length is 8st2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

Answer» HEYA !!





Area of RECTANGLE = 16





LENGTH × Breadth = 16





8 × Breadth = 16





Breadth = 16/8 = 2 units.
11.

Verify that X3 +Y3+Z3-3XYZ=1/2 (X+Y+Z ) [(X+Y)2+(Y-Z)2+(Z-X)2]

Answer»

First We take R.H.S & use the Formula [( a-b)²= a²+b²-2ab] & simplify it then R.H.S becomes equal to L.H.S


R.H.S

⇒ 1/2×(x + y + z) (x²+ y²-2xy +y²+ z²-2yz+x²+z²-2xz)

[( a-b)²= a²+b²-2ab]

⇒ 1/2×(x + y + z) (2x²+ 2y²+2z²-2xy -2yz-2xz)

⇒ 1/2×(x + y + z) 2(x² + y²+ z² – XY – yz – XZ)

=(x + y + z) (x² + y²+ z² – xy – yz – xz)

= x³+y³+z³-3xyz
= L.H.S

We KNOW that,

[x³+ y³ + z³– 3xyz = (x + y + z)(x²+ y² + z² – xy – yz – xz)]

L.H.S = R.H.S

[x³+ y³ + z³– 3xyz = (x + y + z)(x²+ y² + z² – xy – yz – xz)]

================================================================

HOPE this will help you....

Please mark me as brainliest,Thank you and follow me.

12.

A die is thrown once.find the probability of getting a number less than 3

Answer» N(s)=6
n(E)=2
p=2/6=1/3
13.

How to find the diagonal of a square

Answer» DIAGONAL of a SQUARE = ROOT 2 × SIDE of square
14.

Find the quadratic polynomial whose zeroes are √2 and -1/3

Answer»

Here is SOLN BOY. OKK

15.

If 8.5 m of uniform rod weigh 30.6kg ,what will be the weight of 5m of the same rod

Answer»

Here

It's given that 8.5 m =30.6 kg
Therefore 1 m = 30.6/8.5 =3.6kg

Now 5 m = 3.6 * 5 =18 kg

Therefore the answer is 18 kg

Bye
Hope you LIKED it
Mark me BRAINLIEST

16.

In the adjacent figure a b is a straight line find the value of x hence find angle AOC and OD

Answer»

Sum angles lying on a straight line ( Linear Pair of Angles) = 180 °

ANGLE AOC + Angle COD + Angle DOB = 180 °

( 3x - 7) °+ 55 ° + ( X + 20) ° = 180°

4x +68 ° = 180 °

4x = 180 ° - 68 °

x = 112 ° / 4

x = 28 °

ANGLE AOC = ( 3* 28 ° - 7) = 84 - 7 = 77°

ANGLE BOD = 28° + 20° = 48 °

17.

9x2-12x+4 factorise it please help me the best answer will be marked as brainliest

Answer» HEY here your ANSWER don't FORGET to CONSIDER as BRAINLIEST
18.

9x^2-6x+1 factorise by splitting middle term

Answer»

Here is your ANSWER.....................

19.

Sin^6+cos^6+3sin²cos²

Answer»

USING SIMPLE FORMULA a³+b³=(a+b)(a²-ab+b²) and a²+b²=(a+b)²-2ab
And IDENTITY sin²x+cos²x=1

20.

If a point(x,y) is equidistant from the points (a+b, b-a) & (a-b, a+b), then prove bx = ay.

Answer»

(a+B+a-b/2,b-a+a+b/2)=(X,y)
(a,b)=(x,y)
a/b=x/y
ay=bx

21.

The cost of 6 chocolates is rupees 10 1/2. what is the cost of one chocolate

Answer»

the COST of ONE CHOCOLATE is RS 1.75.

22.

How to solve simplification

Answer»

By USING BODMAS RULE

23.

What is the method to do

Answer»

Here is ur ANSWER CHECK it.
hope it is HELPFUL plz mark as brainliest if you are satisfied

24.

The sum of three numbers in ap is 12 and the sum of there cube is 288 find the number

Answer»

Hey MATE!

LET the three nos. be a-d, a+d

so, a-d+a+a+d=12
3a=12
a=12/3
a=4
(a-d)^3+a^3+(a+d)^2=288


now you can substitute the VALUE of a in the equation and solve for d

hope it helps!!

25.

In a circle with centre P, chord AB is drawn of length 13 cm. seg PQ ⊥ chord AB, then find l(QB).

Answer»

A circle of CENTRE P is drawn , chord AB is drawn of length 13cm as shown in FIGURE. Let Q is the point on AB in such a way that PQ ⊥ AB.

we know, chord is bisected by LINE passing through centre and perpendicular UPON it. here , chord AB is perpendicular upon PQ. so, AQ = QB = AB/2
=> AQ = QB = 13cm/2 = 6.5 cm

hence, length of QB = 6.5 cm

26.

0.36 - Express the given decimals in p/q form where q≠0 and p, q are integers

Answer»

Your ANSWER is 36/100...

HOPE it HELPS you!!!

27.

Which are the only prime numbers that end with 2 and 5

Answer»

2 and 5 are the only two PRIME NUMBERS that END with 2 and 5

28.

Add -30 to the difference of - 9 and - 27.

Answer» DIFFERENCE of -9 & -27 = -9-(-27) = -9+27 = 18
now -30 +18 = -12
hence the required ANSWER is -12
29.

The denominator of a fraction is greater than its numerator by 12.If the numerator is decreased by 2 and the denominator is increased by 7, the new fraction is equivalent with 1/2. Find the fraction.

Answer» HOPE this HELPS you........
30.

6. If secA + tanA = m and secA - tanA = n, find the value ofStandard:- 10Content Quality Solution Required ❎ Don't Spamming ❎

Answer»

Heya !!!



SecA + TanA = M


And,


SecA - TanA = N




Therefore,



✓MN = ✓ ( SecA + TanA ) ( SecA - TanA )



=> ✓ ( Sec²A ) - ( Tan²A )



We know that,


Sec theta = 1/Cos theta


And,


TAN theta = Sin theta / Cos theta


So,


✓ ( Sec²A ) - ( Tan²A )



=> ✓1/Cos² A - Sin²A / Cos²A



=> ✓ ( 1 - Sin²A ) / Cos²A



=> ✓Cos²A/Cos²A



=> ✓1 = 1



Hence,



✓MN = 1



HOPE IT WILL HELP YOU ★

31.

What is the formula of area of triangle

Answer» HEY BUDDY, here's your ANSWER

\binom{1}{2}   \times base \times height
32.

find the value of k,if the following pair of linear equations has infinite number of solutions x+(k+1)y=5;(k+1)x+9y=(8k-1)

Answer» X+(k+1)×5;(k+1)x+9×5=(8×k-1)
here we CUT the
(k+1)and (k+1) therefore
leaves x×5;x+45=8k-1
5x;45x=7k
x=45/5 then cut them
so ANSWER leave=x=9
x×k=9×7
xk= 63
33.

The hcf of two numbers is 145 and their lcm is 2175 ofone no. is 125 fin the other no.

Answer»

We KNOW,


Product of numbers = LCM × HCF

=> 125 × other number = 145 × 2175

=>  \mathbf{other \: number \: } =  \frac{2175 \times145 }{125}  \\  \\  \\   \fcolorbox{red}{aqua} { => }\mathbf{other \: number} = 2523

34.

The tens digit of a no. Is five times the units digit . What is the no.

Answer» LET UNIT digit=x
so, TENS digit=5x
so, no. is OBTAINED 5x×10+x=50x+x=51x
so, no. is 51x
35.

Π

Answer»

√2+√2(1+cos2(2theeta))
√2+√2(2cos²2theeta)
[email PROTECTED]
√2([email protected])
√2(2cos²@[email protected]

36.

19 boys turn out for playing hockey, of these 11 boys has wearing shirt and 14 has wearing pants how many are in full uniform?

Answer»

Boys turning out for PLAYING hockey: 19

As PER the question, boys wearing shirt= 11 and boys wearing pant= 14

So, if we take boys wearing WHOLE uniform= x

then, x= (11+14) - 19

= 25- 19

= 06

37.

Find LCM of 84, 112, 196 by division method

Answer» 2 | 84,112,196
2 |42,56,98
2 |21,28,49
7 | 3,4, 7
2X2X2X7X3X4X7= 96X49 = 4704.
38.

Find the HCF of the following by using division method q. 44, 121,132

Answer» HCF of 44,121, 132
equal to 11 ANSWER
39.

Big bracket small bracket minus 1 upon 3 small bracket power2 to big brackets power 3

Answer»

The ANSWER for this is 1/729

40.

CosA.cos(90-A)-sinA.sin(90-A)=0

Answer» COSA . COS(90-A) - SINA . SIN(90-A) = LHS
cosA . sinA - sinA . cosA
cosA.sinA - cosA.sinA = 0
LHS = 0
Hence PROVED
41.

the speed of the boat in still water is 8km/hr.If it takes the same time in going 20km downstream as it takes in going 12km upstream,find the speed of the water

Answer»

Let the speed of water in the river be x km/hr
Speed of boat upstream = (8 – x) km/hr
Speed of boat downstream = (8 + x) km/hr
Distance travelled downstream = 20 km
Recall that TIME taken = (Distance)/(Speed)
Time taken to travel downstream = 20/(8 + x)
Distance travelled upstream = 12 km
Time taken to travel upstream = 12/(8 – x)
Given time taken to travel downstream = time taken to travel upstream

Thus speed of water in the river is 2 km/hr.

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clear
Let the speed of water in the river be x km/hr
Speed of boat upstream = (8 – x) km/hr
Speed of boat downstream = (8 + x) km/hr
Distance travelled downstream = 20 km
Recall that time taken = (Distance)/(Speed)
Time taken to travel downstream = 20/(8 + x)
Distance travelled upstream = 12 km
Time taken to travel upstream = 12/(8 – x)
Given time taken to travel downstream = time taken to travel upstream

Thus speed of water in the river is 2 km/h

42.

A flask weighs 64.27 g when empty and 150.35g when full of water. Find its weighs when. A.) 0.75 times full of water.

Answer» WEIGHT of FULL flasked WATER = 150.35 - 64.27 = 86.08
Weight of 0.75 full water = 0.75 X 86.08 = 64.56
Total weight (FLASK + water) = 64.27 + 64.56 = 128.83
43.

A shopkeeper bought a sewing machine for Rs.3500 if he wants to earn a profit of 20% after giving a discount of 20% what should be the marked price?

Answer»

3500×120/80=mp
mp=3500×3/2=1750×3=5250rs

44.

If radius of a circle is 21 cm then find its area.

Answer»

Hey!!!

GIVEN the radius of the CIRCLE = 21cm

hence, it's area = πr²
= 22/7 × 21 × 21
= 22 × 3 × 21
= 1386cm²

cheers!!!

45.

In which quadrant does the point ( -2, 4) and (3,-1) lie

Answer»

-2,3second QUADRANT
3,-1 FOURTH quadrant

46.

In a parallelogram pqrs the besictors of angle p and angle q meet at o find angle poq

Answer»

Now you can SEE this IMAGE. Here is your ANSWER.

47.

Square root of 7 upto 2 decimal places

Answer»

ANSWER:

\red {\sqrt{7}}\green {≈ 2.64}

Step-by-step explanation:

2 | 7.000000| 2.645...

*** 4

___________

46 | 300

×6| 276

___________

524| 2400

× 4 | 2094

___________

5285 | 30600

****× 5| 26425

____________

\sqrt{7} = 2.645\cdot\cdot\cdot

Rounding\: upto \: two \:decimals \sqrt{7} ≈ 2.64

Therefore.,

\red {\sqrt{7}}\green {≈ 2.64}

•••♪

48.

Rationalize the denominator 5 + root 3 by 5 minus root 3

Answer»

5+ROOT 3× 5+root3=25+5 root 3+5 root 3 +3 ==28+10 root 3

49.

In a family, the father took 1/4 of the cake and he had 3 times as much as each of the other members had. the total number of family members is

Answer»

Let the FAMILY members B x.

FATHER ate 1/4 of the cake; 
Rest members got 3/4x,
the father had 3 TIMES more than other members share i.e 3/4,
Now, 
3(3/4x) = 1/4,
3/4x = 1/12,
36 = 4x,
X = 9,
9 + 1(father) = 10 total family member.

50.

In ΔPQR the sides QP and RP have been produced to S and T such that PQ = PS and PR = PT. Prove that the segment QR || ST.

Answer»

HELLO, here is your answer.

Hope it HELPS you.