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find the value of k,if the following pair of linear equations has infinite number of solutions x+(k+1)y=5;(k+1)x+9y=(8k-1) |
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Answer» X+(k+1)×5;(k+1)x+9×5=(8×k-1) here we CUT the (k+1)and (k+1) therefore leaves x×5;x+45=8k-1 5x;45x=7k x=45/5 then cut them so ANSWER leave=x=9 x×k=9×7 xk= 63 |
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