332354 + Interview Questions in Secondary School in Math

1.	Formula of range in sats
Answer» Answer: The RANGE can be obtained by SUBTRACTING the lowest NUMBER in the set from the HIGHEST number in the set. The lowest number in the set is 2 and the highest number is 66. Therefore, is the range of the data set

1.

Formula of range in sats

Answer»

Answer:

The RANGE can be obtained by SUBTRACTING the lowest NUMBER in the set from the HIGHEST number in the set. The lowest number in the set is 2 and the highest number is 66. Therefore, is the range of the data set

Discussion

2.	The width of a field is 5m less than its length. If the area is 204 m^2, find the dimmensions of the field
Answer» Answer:- $\red{\bigstar}$ Dimensions of the field are $\large\leadsto\boxed{\tt\green{17 \times <klux>12</klux> \: m^2}}$ • Given:- Width of field is 5m less than its length. Area of the field is 204 m². ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ • To Find:- Dimensions of the field ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ • Solution:- Let the length of the field be 'x'. Now, given that the width is 5m less than the length. ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ Therefore, The width of the field will be 'x-5' ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ★ Figure:- $\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(2,3.5){\sf\large x m}\put(-1.4,1.4){\sf\large x-5 m}\put(2,1.4){\large\bf <klux>204</klux> $m^2$}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$ We know, $\pink{\bigstar}$ $\large\underline{\boxed{\bf\purple{Area = Length \times Width}}}$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\sf 204 = (x) \times (x-5)$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\sf 204 = x^2 - 5x$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\sf x^2 - 5x - 204 = 0$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ • Splitting the middle term:- ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\sf x^2 - 17x + 12x - 204 = 0$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\sf x(x - 17) + 12(x - 17) = 0$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\sf (x+12) (x-17) = 0$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ Now, ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ✴ $\sf x + 12 = 0$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\bf x = -12$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ✴ $\sf x - 17 = 0$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\bf x = 17$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ✯ Length cannot be negative. Hence, ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ★ $\large{\bf\pink{x = 17}}$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ Now, Width will be x - 5 ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ➪ $\sf 17 - 5$ ⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ★ $\large{\bf\pink{x = 12}}$ Hence, Length = 17m Width = 12m⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ Therefore, the dimensions of the the field are 17 × 12 m².

2.

The width of a field is 5m less than its length. If the area is 204 m^2, find the dimmensions of the field

Answer»

Answer:-

$\red{\bigstar}$ Dimensions of the field are $\large\leadsto\boxed{\tt\green{17 \times <klux>12</klux> \: m^2}}$

• Given:-

Width of field is 5m less than its length.

Area of the field is 204 m².

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• To Find:-

Dimensions of the field

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Solution:-

Let the length of the field be 'x'.

Now, given that the width is 5m less than the length.

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore,

The width of the field will be 'x-5'

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

★ Figure:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(2,3.5){\sf\large x m}\put(-1.4,1.4){\sf\large x-5 m}\put(2,1.4){\large\bf <klux>204</klux> $m^2$}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

We know,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\purple{Area = Length \times Width}}}$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf 204 = (x) \times (x-5)$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf 204 = x^2 - 5x$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf x^2 - 5x - 204 = 0$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Splitting the middle term:-

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf x^2 - 17x + 12x - 204 = 0$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf x(x - 17) + 12(x - 17) = 0$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf (x+12) (x-17) = 0$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Now,

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

✴ $\sf x + 12 = 0$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\bf x = -12$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

✴ $\sf x - 17 = 0$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\bf x = 17$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

✯ Length cannot be negative. Hence,

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

★ $\large{\bf\pink{x = 17}}$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Now,

Width will be x - 5

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf 17 - 5$

⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

★ $\large{\bf\pink{x = 12}}$

Hence,

Length = 17m

Width = 12m⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore, the dimensions of the the field are 17 × 12 m².

Discussion

3.	W10 ftarea=70 ft2w=feet
Answer» Step-by-step explanation: w= 10 FT area= 70 ft2 area= 10w 70 = 10w w= 70/10 w= 7 ft

3.

W10 ftarea=70 ft2w=feet

Answer»

Step-by-step explanation:

w= 10 FT

area= 70 ft2

area= 10*w

70 = 10*w

w= 70/10

w= 7 ft

Discussion

4.	Simplify the expression (-2-2i)(-4+6i)
Answer» Answer: 20-4i i DONT LIKE writing STEP it WOULD take a LONG time sorry

4.

Simplify the expression (-2-2i)(-4+6i)

Answer»

Answer:

20-4i

i DONT LIKE writing STEP it WOULD take a LONG time

sorry

Discussion

5.	Please Provide Explanation. Please don't write anything please else. And this is only the question there is no frequency table.
Answer» ANSWER: Step-by-step EXPLANATION:

5.

Please Provide Explanation. Please don't write anything please else. And this is only the question there is no frequency table.

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

6.	What is the solution for -10 -19x -1x < -1
Answer» ANSWER: -29 0 no it is INCORRECT

6.

What is the solution for -10 -19x -1x < -1

Answer»

ANSWER:

-29

0

no it is INCORRECT

Discussion

7.	Find the minimum distance between point 3,-5,12and x axus
Answer» ANSWER: FORGOT Step-by-step EXPLANATION: I forgot ........................

7.

Find the minimum distance between point 3,-5,12and x axus

Answer»

ANSWER:

FORGOT

Step-by-step EXPLANATION:

I forgot ........................

Discussion

8.	What is the range of the function y = \|x\|?a. all real numbersb. x ≥ 0c. y ≥ 0
Answer» ANSWER: All REAL NUMBERS because X is in mod . hope it help follow me to be INBOX

8.

What is the range of the function y = |x|?a. all real numbersb. x ≥ 0c. y ≥ 0

Answer»

ANSWER:

All REAL NUMBERS because X is in mod

.

hope it help

follow me to be INBOX

Discussion

9.	Each mathematical problem have unique solution true or false
Answer» ANSWER: TRUE.. HOPE THIS ANSWERS YOUR QUESTION

9.

Each mathematical problem have unique solution true or false

Answer»

ANSWER:

TRUE..

HOPE THIS ANSWERS YOUR QUESTION

Discussion

10.	There is a bag with only red marbles and blue marbles. The probability of randomly choosing a red marble is 5/ 12 . There are 84 marbles in total in the bag and each is equally likely to be chosen. Work out how many red marbles there must be.
Answer» ANSWER: There are 49 red marbles. Step-by-step explanation: 7x12=84 5/12x7 both up and down=35/84 so we get that there are 35 blue marbles out of 84 marbles red marbles=84-35 =49

10.

There is a bag with only red marbles and blue marbles. The probability of randomly choosing a red marble is 5/ 12 . There are 84 marbles in total in the bag and each is equally likely to be chosen. Work out how many red marbles there must be.

Answer»

ANSWER:

There are 49 red marbles.

Step-by-step explanation:

7x12=84

5/12x7 both up and down=35/84 so we get that there are 35 blue marbles out of 84 marbles

red marbles=84-35

=49

Discussion

11.	Could someone answer this? thank!
Answer» ANSWER: CORRECT answer Step-by-step EXPLANATION: red0—2-4-6-8-10-12-14-16 blue 0-5-10-15-20-25-30-35-40 this is a correct answer

11.

Could someone answer this? thank!

Answer»

ANSWER:

CORRECT answer

Step-by-step EXPLANATION:

red0—2-4-6-8-10-12-14-16

blue 0-5-10-15-20-25-30-35-40

this is a correct answer

Discussion

12.	Pratik Travels by boat 36 km down a river and back in 8 hours if the speed of boat in still water is 12 kilometre per hour find the speed of the river currentplz answer don't give irrelevant comment
Answer» Step-by-step explanation: ∴ SPEED of the boat in UPSTREAM = (12 – x) km/hr and speed of the boat in downstream = (12 + x) km/hr. ACCORDING to the GIVEN condition, ∴ The speed of the current is 6 km/hr. hope it helps mark me brainliest like it and FOLLOW me tooo.......

12.

Pratik Travels by boat 36 km down a river and back in 8 hours if the speed of boat in still water is 12 kilometre per hour find the speed of the river currentplz answer don't give irrelevant comment

Answer»

Step-by-step explanation:

∴ SPEED of the boat in UPSTREAM = (12 – x) km/hr and speed of the boat in downstream = (12 + x) km/hr. ACCORDING to the GIVEN condition, ∴ The speed of the current is 6 km/hr.

hope it helps

mark me brainliest

like it and FOLLOW me tooo.......

Discussion

13.	If cot x = 4Then sin x / cos x = ?
Answer» Answer: Question:- cot x = 4 Then SIN x / COS x = ? SOLUTION:- Given, Cot x = 4 We KNOW that, sin x => ──── = tan x cos x And , 1 => tan x = ──── Cot x then, 1 Tan x = ─── 4

13.

If cot x = 4Then sin x / cos x = ?

Answer»

Answer:

Question:-

cot x = 4

Then SIN x / COS x = ?

SOLUTION:-

Given,

Cot x = 4

We KNOW that,

sin x

=> ──── = tan x

cos x

And ,

1

=> tan x = ────

Cot x

then,

1

Tan x = ───

4

Discussion

14.	In the given figure find the percent coloured ?
Answer» ANSWER: where is the FIGURES to FIND the PERCENT COLOURED

14.

In the given figure find the percent coloured ?

Answer»

ANSWER:

where is the FIGURES to FIND the PERCENT COLOURED

Discussion

15.	Read the question and find the answer
Answer» ANSWER: FOLLOW me and MARK me as a BRAINLIST answer

15.

Read the question and find the answer

Answer»

ANSWER:

FOLLOW me and MARK me as a BRAINLIST answer

Discussion

16.	Please Provide Explanation.
Answer» X = 8 log81 base √31 = x 81 = (√3)^x [ log p base a = B =>p = a^b ] (√3) ^8 = (√3)^8 => x= 8

16.

Please Provide Explanation.

Answer»

X = 8

log81 base √31 = x

81 = (√3)^x

[ log p base a = B =>p = a^b ]

(√3) ^8 = (√3)^8

=> x= 8

Discussion

17.	Solve this question: Eric traveled to two cities on a single highway. The total distance one way was 200 miles. The distance from his original location to the first city was 40 miles less than the distance from the first city to the second city. Suppose that x represents the distance from the original location to the first city and y represents the distance from the first city to the second city. The following system of equations represents the given situation.x + y = 200x = y − 40Which pair of coordinates represents the solution (in miles) to this system of equations?A.(70, 130)B.(80, 120)C.(160, 120)D.(100, 100)E.(140, 60)
Answer» Step-by-step explanation: if x = y - 40 then, x + y = y - 40 + y = 200 ⇒2y - 40 = 200 ⇒2y = 240 ⇒y = 120 ⇒x = y - 40 = 120 - 40 = 80 x = 80 y = 120

17.

Solve this question: Eric traveled to two cities on a single highway. The total distance one way was 200 miles. The distance from his original location to the first city was 40 miles less than the distance from the first city to the second city. Suppose that x represents the distance from the original location to the first city and y represents the distance from the first city to the second city. The following system of equations represents the given situation.x + y = 200x = y − 40Which pair of coordinates represents the solution (in miles) to this system of equations?A.(70, 130)B.(80, 120)C.(160, 120)D.(100, 100)E.(140, 60)

Answer»

Step-by-step explanation:

if x = y - 40 then,

x + y = y - 40 + y = 200

⇒2y - 40 = 200

⇒2y = 240

⇒y = 120

⇒x = y - 40 = 120 - 40 = 80

x = 80

y = 120

Discussion

18.	Evaluate the expression if x =7 and y=1/2 and z=8. 4x-17
Answer» Step-by-step explanation: 4x-17 x=7 then 4x-17 = 4*7-17 = 28-17 = 11

18.

Evaluate the expression if x =7 and y=1/2 and z=8. 4x-17

Answer»

Step-by-step explanation:

4x-17

x=7

then 4x-17

= 4*7-17

= 28-17

= 11

Discussion

19.	Ind the gradient of the line segment between the points (0,6) and (2,16).
Answer» ANSWER: SORRY L don't KNOW so sorry

19.

Ind the gradient of the line segment between the points (0,6) and (2,16).

Answer»

ANSWER:

SORRY L don't KNOW so sorry

Discussion

20.	length of a wire is 120 cm. what will be the length of each side if this wire is used to form a regular decagon
Answer» ANSWER: DECAGON have 10 sides So, 120/10=12cm..Ans Then we have 12 cm each SIDE.

20.

length of a wire is 120 cm. what will be the length of each side if this wire is used to form a regular decagon

Answer»

ANSWER:

DECAGON have 10 sides

So, 120/10=12cm..Ans

Then we have 12 cm each SIDE.

Discussion

21.	A glass is full of milk mixed with water in which one-fourth of the mixture is water. How much of it must be taken away and equal quantity of water be poured into the glass so that milk and water will be equal?
Answer» According to your question, There are 2 IDENTICAL glasses i.e they have same shape and size. One is filled with 1/3rd of its capacity and other one is filled 1/4 th of its capacity. Now, remaining is filled with water in each glass. Now,contents of both the glasses are mixed in a pot. We NEED to find the ratio of milk to water in the pot in which contents of both the glasses are poured. Let the capacity of each of the two glasses be C Then, According to your question, 1st glass: 1/3rd milk,remaining water 2nd glass: 1/4th milk,remaining water So,in first glass, (Milk/Water ratio)1=((1/3)/(1-1/3))=((1/3)/(2/3))=1/2 So,in SECOND glass, (Milk/Water ratio)2=((1/4)/(1-1/4))=((1/4)/(3/4))=1/3 Now these 2 glasses are mixed in a pot (Milk/Water ratio)Pot=? So,Let Capacity=L.C.M.(2,3) be 6 liters Then,in first glass Milk=2 liters Water=4 liters Then,in second glass Milk=1.5 liters Water=4.5 liters Now these two glasses are mixed in a pot all QUANTITIES remaining constant Total milk in pot=2 liters+ 1.5 liters= 3.5 liters Total water in pot=4 liters+ 4.5 liters=8.5 liters (Milk/Water)pot=3.5/8.5 or 7/17

21.

A glass is full of milk mixed with water in which one-fourth of the mixture is water. How much of it must be taken away and equal quantity of water be poured into the glass so that milk and water will be equal?

Answer»

According to your question,

There are 2 IDENTICAL glasses i.e they have same shape and size.

One is filled with 1/3rd of its capacity and other one is filled 1/4 th of its capacity.

Now, remaining is filled with water in each glass.

Now,contents of both the glasses are mixed in a pot.

We NEED to find the ratio of milk to water in the pot in which contents of both the glasses are poured.

Let the capacity of each of the two glasses be C

Then,

According to your question,

1st glass: 1/3rd milk,remaining water

2nd glass: 1/4th milk,remaining water

So,in first glass,

(Milk/Water ratio)1=((1/3)/(1-1/3))=((1/3)/(2/3))=1/2

So,in SECOND glass,

(Milk/Water ratio)2=((1/4)/(1-1/4))=((1/4)/(3/4))=1/3

Now these 2 glasses are mixed in a pot

(Milk/Water ratio)Pot=?

So,Let Capacity=L.C.M.(2,3) be 6 liters

Then,in first glass

Milk=2 liters

Water=4 liters

Then,in second glass

Milk=1.5 liters

Water=4.5 liters

Now these two glasses are mixed in a pot all QUANTITIES remaining constant

Total milk in pot=2 liters+ 1.5 liters= 3.5 liters

Total water in pot=4 liters+ 4.5 liters=8.5 liters

(Milk/Water)pot=3.5/8.5 or 7/17

Discussion

22.	Find the value of Z for which the number 471Z8 is divisible by 9pls answer this question fast pls
Answer» $\huge\mathfrak{\bf{\underline{\underline{\blue{Answer \ :}}}}}$ $\longrightarrow$ тнε cση∂ítíση σғ тнε ησ. íѕ dívíѕívlє вч 9 íѕ thє ѕum σf ㅤㅤαll thє dígítѕ ѕhσuld вє α mutíplє σf 9 $\mathsf{4 + 7 + 1 + z + 8 = 20 + z}$ $\mathsf{27 \: is \: a \: multiple \: of \: 9}$ $\therefore \mathsf{20 + z = 27 } \ \mathsf{z = 27 - 20} \\ \mathsf{z = 7}$

22.

Find the value of Z for which the number 471Z8 is divisible by 9pls answer this question fast pls

Answer»

$\huge\mathfrak{\bf{\underline{\underline{\blue{Answer \ :}}}}}$

$\longrightarrow$ тнε cση∂ítíση σғ тнε ησ. íѕ dívíѕívlє вч 9 íѕ thє ѕum σf ㅤㅤαll thє dígítѕ ѕhσuld вє α mutíplє σf 9

$\mathsf{4 + 7 + 1 + z + 8 = 20 + z}$

$\mathsf{27 \: is \: a \: multiple \: of \: 9}$

$\therefore \mathsf{20 + z = 27 } \ \mathsf{z = 27 - 20} \\ \mathsf{z = 7}$

Discussion

23.	Find the radius of a circle if the chord length C is 24 cm and H is 12 cm
Answer» ANSWER: गई हमारी माता है हमको कुछ नहीं आता है

23.

Find the radius of a circle if the chord length C is 24 cm and H is 12 cm

Answer»

ANSWER:

गई हमारी माता है हमको कुछ नहीं आता है

Discussion

24.	Can you help me if you can thank you every much and you need to have 1 answer
Answer» ANSWER: there will be 4 and please mark my answer as brain LIST

24.

Can you help me if you can thank you every much and you need to have 1 answer

Answer»

ANSWER:

there will be 4 and please mark my answer as brain LIST

Discussion

25.	134 => 84178 => 78190 => 40290 => ?
Answer» Answer: Hope it helps!! Mark this answer as BRAINLIEST if u found it useful and follow me for quick and accurate answers... Step-by-step explanation: Given: 134 = 84, 178 = 78, 190 = 40 To find: 290 = ??? Solution: The series FOLLOWS the below technique. 134 = 84 134 - 84 = 50 ⇒ 50 × 1 = 50 178 = 78 178 - 78 = 100 ⇒ 50 × 2 = 100 190 = 40 190 - 40 = 150 ⇒ 50 × 3 = 150 As we can see, the successive subtraction results in multiple of 50. Therefore, the next series subtraction result must be 290 = ??? ⇒ 50 × 4 = 200 290 - x = 200 290 - 200 = 90 ∴ 290 = 90 is the missing series

25.

134 => 84178 => 78190 => 40290 => ?

Answer»

Answer:

Hope it helps!! Mark this answer as BRAINLIEST if u found it useful and follow me for quick and accurate answers...

Step-by-step explanation:

Given: 134 = 84, 178 = 78, 190 = 40

To find: 290 = ???

Solution:

The series FOLLOWS the below technique.

134 = 84

134 - 84 = 50 ⇒ 50 × 1 = 50

178 = 78

178 - 78 = 100 ⇒ 50 × 2 = 100

190 = 40

190 - 40 = 150 ⇒ 50 × 3 = 150

As we can see, the successive subtraction results in multiple of 50. Therefore, the next series subtraction result must be

290 = ???

⇒ 50 × 4 = 200

290 - x = 200

290 - 200 = 90

∴ 290 = 90 is the missing series

Discussion

26.	the ratio of finate difference of function values at two points to the distance between those points give an approximation to a derivative of the function . ture or false
Answer» The ratio of the FINITE difference of function values at two points to the distance between those points gives an approximation to a derivative of the function. True FALSE Elementary theory accurately approximates the cross-section warping of elliptical bars subjected to torsion loading. O True O False PES For LONG, slender columns, the critical stress for elastic buckling may be increased by using stiffer materials (increased E), but not by using a stronger material (increased Ou). True False Intermediate length columns fail by inelastic buckling at stress levels exceeding the ultimate strength O Truc O False It is generally OK to neglect shear in calculating deflection due to transverse loading of the beam is "slender" because the contribution is small. O True False There are no shear stresses on the PLANES on which principal stresses act. O True O False Get more help from Chegg

26.

the ratio of finate difference of function values at two points to the distance between those points give an approximation to a derivative of the function . ture or false

Answer»

The ratio of the FINITE difference of function values at two points to the distance between those points gives an approximation to a derivative of the function. True FALSE Elementary theory accurately approximates the cross-section warping of elliptical bars subjected to torsion loading. O True O False PES For LONG, slender columns, the critical stress for elastic buckling may be increased by using stiffer materials (increased E), but not by using a stronger material (increased Ou). True False Intermediate length columns fail by inelastic buckling at stress levels exceeding the ultimate strength O Truc O False It is generally OK to neglect shear in calculating deflection due to transverse loading of the beam is "slender" because the contribution is small. O True False There are no shear stresses on the PLANES on which principal stresses act. O True O False

Get more help from Chegg

Discussion

27.	Plz help will choose the brainliest
Answer» Answer: i am dying dying help me me i can't answer STEP-by-step EXPLANATION: step FINAL toss the coin 2 times and last 1 time your answer will be there believe me.

27.

Plz help will choose the brainliest

Answer»

Answer:

i am dying dying help me me i can't answer

STEP-by-step EXPLANATION:

step FINAL toss the coin 2 times and last 1 time your answer will be there believe me.

Discussion

28.	The Shinkansen, the fastest train in Japan, traveled 75 kilometers in 0.25 hours. What was its speed in kilometers per hour?A 300 kilometers per hourB 333 kilometers per hourC 3,000 kilometers per hourD 3,333 kilometers per hour
Answer» Answer: 300 KILOMETERS PER HOUR

28.

The Shinkansen, the fastest train in Japan, traveled 75 kilometers in 0.25 hours. What was its speed in kilometers per hour?A 300 kilometers per hourB 333 kilometers per hourC 3,000 kilometers per hourD 3,333 kilometers per hour

Answer»

Answer:

300 KILOMETERS PER HOUR

Discussion

29.	Which batch has the highest amount of honey to sesame paste
Answer» ANSWER: don't know Step-by-step EXPLANATION: bbaanannajansjsjsjsjsnsnsnsnjs

29.

Which batch has the highest amount of honey to sesame paste

Answer»

ANSWER:

don't know

Step-by-step EXPLANATION:

bbaanannajansjsjsjsjsnsnsnsnjs

Discussion

30.	frame a cubic polynomial whose zeroes are 2, 3, and ½. Also verify the relationship between zeroes and coefficient of the polynomials.
Answer» ANSWER: General form of QUADRATIC polynomial is AX 2 + bx +c where a ≠ 0. There are two zeroes of quadratic polynomial. Product of zeroes =ca = Constant term Coefficient of x2 Constant term Coefficient of x 2 . Step-by-step explanation: if it really HELPS you if you LIKE me follow me

30.

frame a cubic polynomial whose zeroes are 2, 3, and ½. Also verify the relationship between zeroes and coefficient of the polynomials.

Answer»

ANSWER:

General form of QUADRATIC polynomial is AX 2 + bx +c where a ≠ 0. There are two zeroes of quadratic polynomial. Product of zeroes =ca = Constant term Coefficient of x2 Constant term Coefficient of x 2 .

Step-by-step explanation:

if it really HELPS you if you LIKE me follow me

Discussion

31.	_____is the difference between the highest and the lowest observation of the data.a) Mode b) Range c) Median d)Data
Answer» ANSWER: B) RANGE is the answer thanks

31.

_____is the difference between the highest and the lowest observation of the data.a) Mode b) Range c) Median d)Data

Answer»

ANSWER:

B) RANGE is the answer

thanks

Discussion

32.	SECTION C16. Find the zeroes of the polynomial p (x) = 4✓3x ^2- 2✓3 x-2✓3 and verify therelationship between the zeroes and the coefficients.
Answer» Answer: 16.) 3^1/2 Step-by-step EXPLANATION: PLEASE FOLLOW me and MARK me BRAINLIEST

32.

SECTION C16. Find the zeroes of the polynomial p (x) = 4✓3x ^2- 2✓3 x-2✓3 and verify therelationship between the zeroes and the coefficients.

Answer»

Answer:

16.) 3^1/2

Step-by-step EXPLANATION:

PLEASE FOLLOW me and MARK me BRAINLIEST

Discussion

33.	If for 10 observation summation i up to 10 (Xi-23) = - 17 then find the mean and variance
Answer» Answer: PLZ mark me brainliest i will FOLLOW u Step-by-step EXPLANATION: cures the variation in the OBSERVATIONS about the middle value– mean or median etc(d) Standard DEVIATION: If σ2 is the variance, then σ, is called the standard Example 1 Find the mean deviation about the mean of the following data: Here h = 10.

33.

If for 10 observation summation i up to 10 (Xi-23) = - 17 then find the mean and variance

Answer»

Answer:

PLZ mark me brainliest i will FOLLOW u

Step-by-step EXPLANATION:

cures the variation in the OBSERVATIONS about the middle value– mean or median etc(d) Standard DEVIATION: If σ2 is the variance, then σ, is called the standard Example 1 Find the mean deviation about the mean of the following data: Here h = 10.

Discussion

34.	Find the degree measures corresponding to (1/2)^ c
Answer» ANSWER: ...........................

34.

Find the degree measures corresponding to (1/2)^ c

Answer»

ANSWER:

...........................

Discussion

35.	Sopt the error and correct the sentence is we are studied English
Answer» ANSWER: Always READ the entire sentence Always read the entire sentence. When looking for the error, examine each choice individually. Check verbs and pronouns first, since they're the most likely to include errors. When an answer choice contains more than one TYPE of WORD, check both.

35.

Sopt the error and correct the sentence is we are studied English

Answer»

ANSWER:

Always READ the entire sentence

Always read the entire sentence.

When looking for the error, examine each choice individually.

Check verbs and pronouns first, since they're the most likely to include errors.

When an answer choice contains more than one TYPE of WORD, check both.

Discussion

36.	Find 85percent of 400
Answer» ANSWER: CORRECT answer will be 340

36.

Find 85percent of 400

Answer»

ANSWER:

CORRECT answer will be 340

Discussion

37.	Plz Answer this..........
Answer» ANSWER: om^2=lm^2-ol^2 =9^2-5^2 =81-25 36 =6

37.

Plz Answer this..........

Answer»

ANSWER:

om^2=lm^2-ol^2

=9^2-5^2

=81-25

36

=6

Discussion

38.	Solve it...And send me ur answer on my instagram (Mr. shivam_4k)..so plzzz fast.. I want to complete it tonight only. ✌✌✌✌✌✌✌✌✌✌
Answer» Answer: question no. 8 Step-by-step EXPLANATION: putting P( 3 ) in the polynomial (3)^2 -5*3 +4 = 9-15+4 = -2 it is called remainder theorem. you will get -2 as remainder so for being 3 as a ZERO you should add +2 in polynomial answer - +2

38.

Solve it...And send me ur answer on my instagram (Mr. shivam_4k)..so plzzz fast.. I want to complete it tonight only. ✌✌✌✌✌✌✌✌✌✌

Answer»

Answer:

question no. 8

Step-by-step EXPLANATION:

putting P( 3 ) in the polynomial

(3)^2 -5*3 +4 = 9-15+4 = -2

it is called remainder theorem.

you will get -2 as remainder

so for being 3 as a ZERO you should add +2 in polynomial

answer - +2

Discussion

39.	540:360:180::?:?:?options-a)390:130:260b)400:260:140c)420:150:270d)460:160:300plz give me step by step solutions
Answer» ANSWER: I am not interested Step-by-step EXPLANATION: OKK hope। with helpss

39.

540:360:180::?:?:?options-a)390:130:260b)400:260:140c)420:150:270d)460:160:300plz give me step by step solutions

Answer»

ANSWER:

I am not interested

Step-by-step EXPLANATION:

OKK hope। with helpss

Discussion

40.	Find the sum which becomes rs.2700 after 3 1/2 years at 10 ...
Answer» Answer: ₹ 3645 Step-by-step EXPLANATION: Principle: ₹ 2700 Rate : 10% p.a Time : 5/2 YEARS Simple interest = (PRT)/100 = ₹ 945 Amount = SI + Principle = ₹(2700+945) =₹ 3645 I HOPE IT HELP YOU PLEASE FOLLOW AND BRAINLIST ME

40.

Find the sum which becomes rs.2700 after 3 1/2 years at 10 ...

Answer»

Answer:

₹ 3645

Step-by-step EXPLANATION:

Principle: ₹ 2700

Rate : 10% p.a

Time : 5/2 YEARS

Simple interest = (P*R*T)/100

= ₹ 945

Amount = SI + Principle

= ₹(2700+945)

=₹ 3645

I HOPE IT HELP YOU

PLEASE FOLLOW AND BRAINLIST ME

Discussion

41.	If a²+1/a² =38then the value of a-1/a = is
Answer» Answer: Answer: Here is ur answer. .... Ostrich has largest EGG. HOPE it HELPS

41.

If a²+1/a² =38then the value of a-1/a = is

Answer»

Answer:

Answer:

Here is ur answer. ....

Ostrich has largest EGG.

HOPE it HELPS

Discussion

42.	Simple interest on a sum of money at the end of 5 years is 4/5 of the sum itself. find the rate percent per annum.
Answer» $\huge\boxed{\fcolorbox{purple}{ink}{Answer}}$ GIVEN:- Simple INTEREST on a sum of money at the end of 5 years is 4/5 of the sum itself. Need to find out:- The rate percent per annum. Let us take sum ( PRINCIPAL ) as P. Here, Time = 5 years Simple Interest = 4/5 P Therefore:- P × R × T/100 = 4/5 P => P × R × 5/100 = 4/5 P => Rate of interest = 4/5 × 100/5 => Rate of interest = 16 Hence:- Rate of interest = 16% per annum.

42.

Simple interest on a sum of money at the end of 5 years is 4/5 of the sum itself. find the rate percent per annum.

Answer»

$\huge\boxed{\fcolorbox{purple}{ink}{Answer}}$

GIVEN:-

Simple INTEREST on a sum of money at the end of 5 years is 4/5 of the sum itself.

Need to find out:-

The rate percent per annum.

Let us take sum ( PRINCIPAL ) as P.

Here,

Time = 5 years

Simple Interest = 4/5 P

Therefore:-

P × R × T/100 = 4/5 P

=> P × R × 5/100 = 4/5 P

=> Rate of interest = 4/5 × 100/5

=> Rate of interest = 16

Hence:-

Rate of interest = 16% per annum.

Discussion

43.	A and B can do a piece of work in 4 days. B and C in 6 days and C and A in 2 days. In what time A, B and C will complete the work working together ?
Answer» Answer: 3 DAYS IS REQUIRED FOR A,B,C TO DO WORK!!! I HOPE YOU UNDERSTOOD THE QUESTION!!!

43.

A and B can do a piece of work in 4 days. B and C in 6 days and C and A in 2 days. In what time A, B and C will complete the work working together ?

Answer»

Answer:

3 DAYS IS REQUIRED FOR A,B,C TO DO WORK!!!

I HOPE YOU UNDERSTOOD THE QUESTION!!!

Discussion

44.	4x (-8) =__________
Answer» ANSWER: -32 Step-by-step EXPLANATION: its UR NSWER..........

44.

4x (-8) =__________

Answer»

ANSWER:

-32

Step-by-step EXPLANATION:

its UR NSWER..........

Discussion

45.	Page No.:4tooफा देशमलप स्वरूप प्राप्त कीजिए।
Answer» $\huge{ \orange{\boxed{\red{ \boxed{ \green{h} \purple{e}l \color{aqua}lo}}}}}$

Discussion

46.	By selling an article for rupees 475 Rahul lost 5% find CP of the article
Answer» ANSWER: HOPE it is HELPFUL MARK as BRAINLIEST

46.

By selling an article for rupees 475 Rahul lost 5% find CP of the article

Answer»

ANSWER:

HOPE it is HELPFUL

MARK as BRAINLIEST

Discussion

47.	Prove that tan+1/tanA= sec square A
Answer» Answer: 1+tanAtan(A/2)=1+2tan(A/2)/1-TAN^2(A/2)*tan(A/2)=1+2tan^2(A/2)/1-tan^2(A/2)=1+tan^2(A/2)/1-tan ^2(A/2)==1/cosA=secA

47.

Prove that tan+1/tanA= sec square A

Answer»

Answer:

1+tanAtan(A/2)=1+2tan(A/2)/1-TAN^2(A/2)*tan(A/2)=1+2tan^2(A/2)/1-tan^2(A/2)=1+tan^2(A/2)/1-tan ^2(A/2)==1/cosA=secA

Discussion

48.	In a parallelogram ABCD,DQ⊥BC , DQ = 9.3 cm and BC = 7.2 cm. Find out its area
Answer» ⭐⭐⭐Answer⭐⭐⭐ ✪Formula✪ Area of a PARALLELOGRAM is given by: Area = Base X Height ✪Process✪ It is given that DQ which is the height has a length 9.3 cm. BC which is the base has a length 7.2 cm. Thus, we can SAY that: Area = 9.3 x 7.2 = 66.96 cm SQUARE

48.

In a parallelogram ABCD,DQ⊥BC , DQ = 9.3 cm and BC = 7.2 cm. Find out its area

Answer»

⭐⭐⭐Answer⭐⭐⭐

✪Formula✪

Area of a PARALLELOGRAM is given by:

Area = Base X Height

✪Process✪

It is given that DQ which is the height has a length 9.3 cm.

BC which is the base has a length 7.2 cm.

Thus, we can SAY that:

Area = 9.3 x 7.2 = 66.96 cm SQUARE

Discussion

49.	If sec theta + tan theta = x, then find the value of cot theta.PLZ ANSWER IT FAST...I WILL MARK YOUR ANSWER AS "BRAINLIEST"
Answer» Step-by-step EXPLANATION: $\sec( \alpha ) + \tan( \alpha ) = x$ $(1 \div \cos( \alpha ) ) + (1 \div \cot( \alpha ) ) = x$ $1 \div \cot( \alpha ) = x - 1 \div \cos( \alpha )$ $\cot( \alpha ) =( 1 \div x) - \cos( \alpha )$ $\cot( \alpha ) = 1 - x \cos( \alpha ) \div x$ HOPE it HELPS

49.

If sec theta + tan theta = x, then find the value of cot theta.PLZ ANSWER IT FAST...I WILL MARK YOUR ANSWER AS "BRAINLIEST"

Answer»

Step-by-step EXPLANATION:

$\sec( \alpha ) + \tan( \alpha ) = x$

$(1 \div \cos( \alpha ) ) + (1 \div \cot( \alpha ) ) = x$

$1 \div \cot( \alpha ) = x - 1 \div \cos( \alpha )$

$\cot( \alpha ) =( 1 \div x) - \cos( \alpha )$

$\cot( \alpha ) = 1 - x \cos( \alpha ) \div x$

HOPE it HELPS

Discussion

50.	If any one have courage to solve all these questions then solve its a practice for u all with out any cheating 1. The height of a cone is 16 cm and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone (Use π = 3.14). (NCERT)11. The height of a cone is 15 cm. If its volume is 1570 cm3, find radius of the base. (π = 3.14)15. A conical tent is 10 m high and the radius of its base is 24 m. Find (NCERT)(i) slant height of the tent.(ii) cost of the canvas required to make the tent, if the cost of 1 m2canvas is Rs.70.16. The radius of the cone is 7 cm and the area of the curved surface is 176 cm2. Find the slant height.17. The height of the cone is 21 cm. Find the area of the base if the slant height is 28 cm.18. The area of the curved surface of the cone is 60  cm2. If the slant height of the cone be 8 cm, find the radius of the base.19. If volume of a right circular cone of height 9 cm is 48 π cm3, find diameter of its base. (NCERT)20. The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm, find (i) height of the cone (ii) slant height of the cone(iii) curved surface area of the cone (NCERT)21. The radius and slant height of a cone are in the ratio of 4:7. If the curved surface area is 792 cm2, find the radius. (Use = 22/7)22. The lateral surface of a cylinder is equal to the curved surface of the cone. If the radius be the same, find the ratio of the height of the cylinder and slant height of the cone.23. The radius and the height of a right circular cone are in the ratio of 5 : 12 and its volume is 2512 cu cm. Find the CSA and TSA of the cone. (Use  = 3.14)24. The curved surface of a cone is 156 cm2. If radius of its base is 12 cm, find the height of the cone and hence the volume of the cone.25. A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find its volume. Theheap is to be covered by canvas to protect it from rain. Find the area of the canvas required.26. A corn cob, shaped somewhat like a cone, has the radius of the broadcast end as 2.1 cm and length as 20 cm. if each 1 cm2 of the surface cob carries an average of four grains, find how many grains you would find on the entire cob? (NCERT)27. A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. find the area of the sheet required to make 10 such caps. (NCERT)28. The diameters of two cones are in the ratio 3 : 5 and their slant heights are in the ratio 5 : 13. Find the ratio of their curved surface areas29. The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white washing its curved surface at the rate of 210 per 100 m2. (NCERT)(NCERT)30. What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6 m? Assume that the extra length of material will be required for stitching margins and wastage in cutting is approximately 20 cm. (Use  = 3.14) (NCERT)Add: 2nd floor, 301/5, Near Jawahar Nagar Police station, Shanti Path, Jaipur. Ph: 0141-4036374 M: 9414063576Download our useful app on Playstore: (a centre of education)Elite(a centre of education)31. A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled card-board. Each cone has a base diameter of 40 cm and height 1m. If the outer side of each of the cones is to be painted and the cost of painting is Rs 12 per m2, what will be the cost of painting all these cones. (Use  = 3.14 and√1.04 = 1.02) (NCERT)32. How many meters of cloth 5 m wide will be require to make a conical tent, the radius of whose base is 7 m and height 24 m?33. How many meters of cloth 2.5 m wide will be required to make a conical tent whose base radius is 7 m and height 24 m?34. A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained. (NCERT)35. If the triangle ABC in the Question above is revolved about the side 5 cm, then find the volume of the solid so obtained. Find also the ratio of the volumes of the two solids obtained. (NCERT)36. A cylinder and a cone have equal radii of their bases are equal heights. If their curved surface areas are in the ratio 8:5, show that the radius of each is to the height of each as 3 : 4.37. Monica has a piece of canvas whose area is 551 m2. She uses it to have a conical tent made, with a base radius of 7 m. Assuming that all the stitching margins and the wastage incurred while cutting, amounts to approximately 1 m2, find the volume of the tent that can be made with it. (NCERT)38. Find the volume of the largest cone that can be cut out from a cube whose edge is 9 cm.39. Find the volume and curved surface area of the largest cone that can be cut from a cylinder whosediameter of base
Answer» Answer: 345 Step-by-step explanation: If any one have courage to solve all these questions then solve its a practice for u all with out any cheating 1. The height of a cone is 16 cm and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone (Use π = 3.14). (NCERT) 11. The height of a cone is 15 cm. If its volume is 1570 cm3, find radius of the base. (π = 3.14) 15. A conical tent is 10 m high and the radius of its base is 24 m. Find (NCERT) (i) slant height of the tent. (ii) cost of the canvas required to make the tent, if the cost of 1 m2canvas is Rs.70. 16. The radius of the cone is 7 cm and the area of the curved surface is 176 cm2. Find the slant height. 17. The height of the cone is 21 cm. Find the area of the base if the slant height is 28 cm. 18. The area of the curved surface of the cone is 60  cm2. If the slant height of the cone be 8 cm, find the radius of the base. 19. If volume of a right circular cone of height 9 cm is 48 π cm3, find diameter of its base. (NCERT) 20. The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm, find (i) height of the cone (ii) slant height of the cone (iii) curved surface area of the cone (NCERT) 21. The radius and slant height of a cone are in the ratio of 4:7. If the curved surface area is 792 cm2, find the radius. (Use = 22/7) 22. The LATERAL surface of a cylinder is equal to the curved surface of the cone. If the radius be the same, find the ratio of the height of the cylinder and slant height of the cone. 23. The radius and the height of a right circular cone are in the ratio of 5 : 12 and its volume is 2512 cu cm. Find the CSA and TSA of the cone. (Use  = 3.14) 24. The curved surface of a cone is 156 cm2. If radius of its base is 12 cm, find the height of the cone and hence the volume of the cone. 25. A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas required. 26. A corn cob, shaped somewhat like a cone, has the radius of the broadcast end as 2.1 cm and length as 20 cm. if each 1 cm2 of the surface cob carries an average of four GRAINS, find how many grains you would find on the entire cob? (NCERT) 27. A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. find the area of the sheet required to make 10 such caps. (NCERT) 28. The diameters of two cones are in the ratio 3 : 5 and their slant heights are in the ratio 5 : 13. Find the ratio of their curved surface areas 29. The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white washing its curved surface at the RATE of 210 per 100 m2. (NCERT) (NCERT) 30. What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6 m? Assume that the extra length of material will be required for stitching margins and wastage in cutting is approximately 20 cm. (Use  = 3.14) (NCERT) Add: 2nd floor, 301/5, Near Jawahar Nagar Police station, Shanti Path, Jaipur. Ph: 0141-4036374 M: 9414063576 Download our useful app on Playstore: (a centre of education) Elite (a centre of education) 31. A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled card-board. Each cone has a base diameter of 40 cm and height 1m. If the outer side of each of the cones is to be PAINTED and the cost of painting is Rs 12 per m2, what will be the cost of painting all these cones. (Use  = 3.14 and√1.04 = 1.02) (NCERT) 32. How many meters of cloth 5 m wide will be require to make a conical tent, the radius of whose base is 7 m and height 24 m? 33. How many meters of cloth 2.5 m wide will be required to make a conical tent whose base radius is 7 m and height 24 m? 34. A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained. (NCERT) 35. If the triangle ABC in the Question above is revolved about the side 5 cm, then find the volume of the solid so obtained. Find also the ratio of the volumes of the two solids obtained. (NCERT) 36. A cylinder and a cone have equal radii of their bases are equal heights. If their curved surface areas are in the ratio 8:5, show that the radius of each is to the height of each as 3 : 4. 37. Monica has a piece of canvas whose area is 551 m2. She uses it to have a conical tent made, with a base radius of 7 m. Assuming that all the stitching margins and the wastage incurred while cutting, amounts to approximately 1 m2, find the volume of the tent that can be made with it. (NCERT) 38. Find the volume of the largest cone that can be cut out from a cube whose edge is 9 cm. 39. Find the volume and curved surface area of the largest cone that can be cut from a cylinder whose diameter of base

50.

If any one have courage to solve all these questions then solve its a practice for u all with out any cheating 1. The height of a cone is 16 cm and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone (Use π = 3.14). (NCERT)11. The height of a cone is 15 cm. If its volume is 1570 cm3, find radius of the base. (π = 3.14)15. A conical tent is 10 m high and the radius of its base is 24 m. Find (NCERT)(i) slant height of the tent.(ii) cost of the canvas required to make the tent, if the cost of 1 m2canvas is Rs.70.16. The radius of the cone is 7 cm and the area of the curved surface is 176 cm2. Find the slant height.17. The height of the cone is 21 cm. Find the area of the base if the slant height is 28 cm.18. The area of the curved surface of the cone is 60  cm2. If the slant height of the cone be 8 cm, find the radius of the base.19. If volume of a right circular cone of height 9 cm is 48 π cm3, find diameter of its base. (NCERT)20. The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm, find (i) height of the cone (ii) slant height of the cone(iii) curved surface area of the cone (NCERT)21. The radius and slant height of a cone are in the ratio of 4:7. If the curved surface area is 792 cm2, find the radius. (Use = 22/7)22. The lateral surface of a cylinder is equal to the curved surface of the cone. If the radius be the same, find the ratio of the height of the cylinder and slant height of the cone.23. The radius and the height of a right circular cone are in the ratio of 5 : 12 and its volume is 2512 cu cm. Find the CSA and TSA of the cone. (Use  = 3.14)24. The curved surface of a cone is 156 cm2. If radius of its base is 12 cm, find the height of the cone and hence the volume of the cone.25. A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find its volume. Theheap is to be covered by canvas to protect it from rain. Find the area of the canvas required.26. A corn cob, shaped somewhat like a cone, has the radius of the broadcast end as 2.1 cm and length as 20 cm. if each 1 cm2 of the surface cob carries an average of four grains, find how many grains you would find on the entire cob? (NCERT)27. A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. find the area of the sheet required to make 10 such caps. (NCERT)28. The diameters of two cones are in the ratio 3 : 5 and their slant heights are in the ratio 5 : 13. Find the ratio of their curved surface areas29. The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white washing its curved surface at the rate of 210 per 100 m2. (NCERT)(NCERT)30. What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6 m? Assume that the extra length of material will be required for stitching margins and wastage in cutting is approximately 20 cm. (Use  = 3.14) (NCERT)Add: 2nd floor, 301/5, Near Jawahar Nagar Police station, Shanti Path, Jaipur. Ph: 0141-4036374 M: 9414063576Download our useful app on Playstore: (a centre of education)Elite(a centre of education)31. A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled card-board. Each cone has a base diameter of 40 cm and height 1m. If the outer side of each of the cones is to be painted and the cost of painting is Rs 12 per m2, what will be the cost of painting all these cones. (Use  = 3.14 and√1.04 = 1.02) (NCERT)32. How many meters of cloth 5 m wide will be require to make a conical tent, the radius of whose base is 7 m and height 24 m?33. How many meters of cloth 2.5 m wide will be required to make a conical tent whose base radius is 7 m and height 24 m?34. A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained. (NCERT)35. If the triangle ABC in the Question above is revolved about the side 5 cm, then find the volume of the solid so obtained. Find also the ratio of the volumes of the two solids obtained. (NCERT)36. A cylinder and a cone have equal radii of their bases are equal heights. If their curved surface areas are in the ratio 8:5, show that the radius of each is to the height of each as 3 : 4.37. Monica has a piece of canvas whose area is 551 m2. She uses it to have a conical tent made, with a base radius of 7 m. Assuming that all the stitching margins and the wastage incurred while cutting, amounts to approximately 1 m2, find the volume of the tent that can be made with it. (NCERT)38. Find the volume of the largest cone that can be cut out from a cube whose edge is 9 cm.39. Find the volume and curved surface area of the largest cone that can be cut from a cylinder whosediameter of base

Answer»

Answer:

345

Step-by-step explanation:

If any one have courage to solve all these questions then solve its a practice for u all with out any cheating

1. The height of a cone is 16 cm and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone (Use π = 3.14). (NCERT)

11. The height of a cone is 15 cm. If its volume is 1570 cm3, find radius of the base. (π = 3.14)

15. A conical tent is 10 m high and the radius of its base is 24 m. Find (NCERT)

(i) slant height of the tent.

(ii) cost of the canvas required to make the tent, if the cost of 1 m2canvas is Rs.70.

16. The radius of the cone is 7 cm and the area of the curved surface is 176 cm2. Find the slant height.

17. The height of the cone is 21 cm. Find the area of the base if the slant height is 28 cm.

18. The area of the curved surface of the cone is 60  cm2. If the slant height of the cone be 8 cm, find the radius of the base.

19. If volume of a right circular cone of height 9 cm is 48 π cm3, find diameter of its base. (NCERT)

20. The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm, find (i) height of the cone (ii) slant height of the cone

(iii) curved surface area of the cone (NCERT)

21. The radius and slant height of a cone are in the ratio of 4:7. If the curved surface area is 792 cm2, find the radius. (Use = 22/7)

22. The LATERAL surface of a cylinder is equal to the curved surface of the cone. If the radius be the same, find the ratio of the height of the cylinder and slant height of the cone.

23. The radius and the height of a right circular cone are in the ratio of 5 : 12 and its volume is 2512 cu cm. Find the CSA and TSA of the cone. (Use  = 3.14)

24. The curved surface of a cone is 156 cm2. If radius of its base is 12 cm, find the height of the cone and hence the volume of the cone.

25. A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find its volume. The

heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.

26. A corn cob, shaped somewhat like a cone, has the radius of the broadcast end as 2.1 cm and length as 20 cm. if each 1 cm2 of the surface cob carries an average of four GRAINS, find how many grains you would find on the entire cob? (NCERT)

27. A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. find the area of the sheet required to make 10 such caps. (NCERT)

28. The diameters of two cones are in the ratio 3 : 5 and their slant heights are in the ratio 5 : 13. Find the ratio of their curved surface areas

29. The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white washing its curved surface at the RATE of 210 per 100 m2. (NCERT)

(NCERT)

30. What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6 m? Assume that the extra length of material will be required for stitching margins and wastage in cutting is approximately 20 cm. (Use  = 3.14) (NCERT)

Add: 2nd floor, 301/5, Near Jawahar Nagar Police station, Shanti Path, Jaipur. Ph: 0141-4036374 M: 9414063576

Download our useful app on Playstore: (a centre of education)

Elite

(a centre of education)

31. A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled card-board. Each cone has a base diameter of 40 cm and height 1m. If the outer side of each of the cones is to be PAINTED and the cost of painting is Rs 12 per m2, what will be the cost of painting all these cones. (Use  = 3.14 and√1.04 = 1.02) (NCERT)

32. How many meters of cloth 5 m wide will be require to make a conical tent, the radius of whose base is 7 m and height 24 m?

33. How many meters of cloth 2.5 m wide will be required to make a conical tent whose base radius is 7 m and height 24 m?

34. A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained. (NCERT)

35. If the triangle ABC in the Question above is revolved about the side 5 cm, then find the volume of the solid so obtained. Find also the ratio of the volumes of the two solids obtained. (NCERT)

36. A cylinder and a cone have equal radii of their bases are equal heights. If their curved surface areas are in the ratio 8:5, show that the radius of each is to the height of each as 3 : 4.

37. Monica has a piece of canvas whose area is 551 m2. She uses it to have a conical tent made, with a base radius of 7 m. Assuming that all the stitching margins and the wastage incurred while cutting, amounts to approximately 1 m2, find the volume of the tent that can be made with it. (NCERT)

38. Find the volume of the largest cone that can be cut out from a cube whose edge is 9 cm.

39. Find the volume and curved surface area of the largest cone that can be cut from a cylinder whose

diameter of base

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