Prove that tan+1/tanA= sec square A

1.	Prove that tan+1/tanA= sec square A
Answer» Answer: 1+tanAtan(A/2)=1+2tan(A/2)/1-TAN^2(A/2)*tan(A/2)=1+2tan^2(A/2)/1-tan^2(A/2)=1+tan^2(A/2)/1-tan ^2(A/2)==1/cosA=secA

Answer»

Answer:

1+tanAtan(A/2)=1+2tan(A/2)/1-TAN^2(A/2)*tan(A/2)=1+2tan^2(A/2)/1-tan^2(A/2)=1+tan^2(A/2)/1-tan ^2(A/2)==1/cosA=secA

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Prove that tan+1/tanA= sec square A​

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Prove that tan+1/tanA= sec square A