332354 + Interview Questions in Secondary School in Math

1.	Mm.A ball is dropped from a height h1= 1200 mm. If the coefficient of restitution is 80, the height of 5threbound from a horizontal floor is h5=
Answer» 6667=-80-9 Step-by-step EXPLANATION:

1.

Mm.A ball is dropped from a height h1= 1200 mm. If the coefficient of restitution is 80, the height of 5threbound from a horizontal floor is h5=

Answer»

6667=-80-9

Step-by-step EXPLANATION:

Discussion

2.	2x2 −6x+4 = 0hhhhhhhhhhhhhhhhhhhhhh
Answer» Step-by-step EXPLANATION: sgMdnMyfhgshCbfxHtd jgdd7vzbg, 548/7/5'"5/"8

2.

2x2 −6x+4 = 0hhhhhhhhhhhhhhhhhhhhhh

Answer»

Step-by-step EXPLANATION:

sgMdnMyfhgshCbfxHtd jgdd7vzbg, 5*4*8/7/5'"5/"8

Discussion

3.	4. On Earth Day, 6 chief ministers of India plan to plant 565 trees in theirrespective states. How many trees will be planted across all the 6 states?
Answer» ANSWER: the TREES PLANTED are 3,309

3.

4. On Earth Day, 6 chief ministers of India plan to plant 565 trees in theirrespective states. How many trees will be planted across all the 6 states?

Answer»

ANSWER:

the TREES PLANTED are 3,309

Discussion

4.	Find two radius of a circle whose area of equal to the sum of the area of two circle of radii 24cm and 7cm
Answer» Step-by-step EXPLANATION: The radius of the circle is 7cm and 24 cm . Area of SMALLER circle is $\pi {r}^{2}$ $= \pi \times 7$ $= 49\pi$ Area of LARGER circle is $\pi {r}^{2}$ $=\pi \times {24}^{2}$ $= 576\pi$ Area of required circle $= 576\pi + 49\pi$ $= 625\pi$ Radius of circle is GIVEN by $\sqrt{625} = 25$

4.

Find two radius of a circle whose area of equal to the sum of the area of two circle of radii 24cm and 7cm

Answer»

Step-by-step EXPLANATION:

The radius of the circle is 7cm and 24 cm .

Area of SMALLER circle is

$\pi {r}^{2}$

$= \pi \times 7$

$= 49\pi$

Area of LARGER circle is

$\pi {r}^{2}$

$=\pi \times {24}^{2}$

$= 576\pi$

Area of required circle

$= 576\pi + 49\pi$

$= 625\pi$

Radius of circle is GIVEN by

$\sqrt{625} = 25$

Discussion

5.	Multiply the monomials: 7 pq and 4/3 p²q³
Answer» Answer: 28/3 p^3 q^4 Step-by-step EXPLANATION: if u LIKE my answer PLEASE give me 5 star

5.

Multiply the monomials: 7 pq and 4/3 p²q³

Answer»

Answer:

28/3 p^3 q^4

Step-by-step EXPLANATION:

if u LIKE my answer PLEASE give me 5 star

Discussion

6.	In ∆ ABC angle A = 90 and AD is perpendicular to BC. Prove that: AD2= BD × DC
Answer» Step-by-step EXPLANATION: HOPE ITS HELP YOU MARK ME ON BRAINLIST THANK U

6.

In ∆ ABC angle A = 90 and AD is perpendicular to BC. Prove that: AD2= BD × DC

Answer»

Step-by-step EXPLANATION:

HOPE ITS HELP YOU

MARK ME ON BRAINLIST

THANK U

Discussion

7.	Factorise (a) X4-(x-y) 4(b) 4x2+9-12x-a2-b2+2ab
Answer» ANSWER: answer is in the above photos I HOPE it will HELP you out *pls* *MARK* me as *BRAINLIEST*

7.

Factorise (a) X4-(x-y) 4(b) 4x2+9-12x-a2-b2+2ab

Answer»

ANSWER:

answer is in the above photos

I HOPE it will HELP you out

pls MARK me as BRAINLIEST

Discussion

8.	Find the value of thetha if sin4 thetha = cos thetha I need answer fast .... don't spam please
Answer» $\huge\blue{\mid{\fbox{\tt(answer)}\mid}}$ Critical Analysis of The Nightingale and the Glow-worm: In this poem, the poet tells us a story with a moral. However, he envisions a very noble role for the poet. He feels that the poet should be responsible for more than just teaching his readers a lesson. He should also indicate to them where that lesson should be applied. That is exactly what Cowper does in this poem. He tells us about the nightingale and the glow-worm to teach us about mutual respect. In addition to this, he tells us that it is warring factions that should learn this lesson. The nightingale and the glow-worm are THUS symbols for the leaders and followers of different political and RELIGIOUS groups. Such groups only serve to divide mankind on the basis of artificially created categories. They teach their adherents to discriminate against those whom we feel are different from us in their persuasion. However, this is not the correct attitude for one to adopt towards his fellow men. The poet feels that we should be ABLE to respect differences. Every man is unique and he has unique abilities. These abilities and talents should not be seen as a basis for alienating him. Instead, his uniqueness should be valued by his fellow men. All of us human BEINGS should be united n our efforts to make the world a better place. We should all aim for COMMUNAL harmony because if we all make the same amount of effort, then we will all reap the corresponding benefits equally as well. Life is short, and so we should not waste

Discussion

9.	What is the ratio of 30 minutes to 45 minutes
Answer» Answer: 6/9 Step-by-step EXPLANATION: please subscribe my CHANNEL white shadow RACER

9.

What is the ratio of 30 minutes to 45 minutes

Answer»

Answer:

6/9

Step-by-step EXPLANATION:

please subscribe my CHANNEL white shadow RACER

Discussion

10.	How to have complete family ?
Answer» Answer: A father, a mother and childrens Step-by-step EXPLANATION: PLEASE MARK as *BRAINLIST*

10.

How to have complete family ?

Answer»

Answer:

A father, a mother and childrens

Step-by-step EXPLANATION:

PLEASE MARK as BRAINLIST

Discussion

11.	6 4 71 2 57 8 ? find out missing no. logical question
Answer» Answer: 11 Step-by-step EXPLANATION: HOPES it will HELP you

11.

6 4 71 2 57 8 ? find out missing no. logical question

Answer»

Answer:

11

Step-by-step EXPLANATION:

HOPES it will HELP you

Discussion

12.	4X219 x 25-20x95 plz solve this problem with working plzzzzzz
Answer» Answer: the answers is 25........... Step-by-step explanation: please FOLLOW me please mark me as brainylist please THANK my all the answers

12.

4X219 x 25-20x95 plz solve this problem with working plzzzzzz

Answer»

Answer:

the answers is 25...........

Step-by-step explanation:

please FOLLOW me

please mark me as brainylist

please THANK my all the answers

Discussion

13.	If a cosø+bsinø=4and a sinø-b cosø=3, then find a²+b².
Answer» ANSWER: Jaiaijsjajksisisjjsnsjs

13.

If a cosø+bsinø=4and a sinø-b cosø=3, then find a²+b².

Answer»

ANSWER:

Jaiaijsjajksisisjjsnsjs

Discussion

14.	What is motion ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀⠀# DaCharmingPrincess
Answer» ANSWER: Motion is any movement of particles motion can be at REST or at MOVING

14.

What is motion ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀ ⠀⠀ ⠀ ⠀⠀⠀⠀⠀ ⠀⠀# DaCharmingPrincess

Answer»

ANSWER:

Motion is any movement of particles motion can be at REST or at MOVING

Discussion

15.	They saw him ;we didn't see him use only
Answer» ANSWER: THANKS for the FREE POINTS

15.

They saw him ;we didn't see him use only

Answer»

ANSWER:

THANKS for the FREE POINTS

Discussion

16.	The median of the data is 28 find the value of x and y if the total frequency is 50
Answer» ANSWER: Jwiwijdidihdhxhjzjsiwhsbsnjshz

16.

The median of the data is 28 find the value of x and y if the total frequency is 50

Answer»

ANSWER:

Jwiwijdidihdhxhjzjsiwhsbsnjshz

Discussion

17.	Please help mee fastt
Answer» Step-by-step EXPLANATION: i hope it will help you mark it BRAINLIST ANSWER if usefull OTHERWISE not

17.

Please help mee fastt

Answer»

Step-by-step EXPLANATION:

i hope it will help you mark it BRAINLIST ANSWER if usefull OTHERWISE not

Discussion

18.	If theta = 45° then sec theta cot theta - cosec theta tan theta is
Answer» <P>ANSWER: Sec2θ - tan2θ = 1 (secθ + tanθ)( secθ - tanθ) = 1 p( secθ - tanθ) = 1 ( secθ - tanθ) = 1/p and, ......-(1) ( secθ + tanθ) = p ..... - (2) (1) + (2), secθ = 1/2 (p + 1/p) , (2) - (1) tanθ = 1/2 (p-1/p) secθ / tanθ = cosecθ Hence, cosecθ = p +1/p / p-1/p = P2 +1 / p2 -1

18.

If theta = 45° then sec theta cot theta - cosec theta tan theta is

Answer»

<P>ANSWER:

Sec2θ - tan2θ = 1

(secθ + tanθ)( secθ - tanθ) = 1

p( secθ - tanθ) = 1

( secθ - tanθ) = 1/p and, ......-(1)

( secθ + tanθ) = p ..... - (2)

(1) + (2),

secθ = 1/2 (p + 1/p) ,

(2) - (1)

tanθ = 1/2 (p-1/p)

secθ / tanθ = cosecθ

Hence,

cosecθ = p +1/p / p-1/p = P2 +1 / p2 -1

Discussion

19.	Which of the following or not perfect cubes 216,128,11000,1000
Answer» Answer: 128 and 11000 is not a PERFECT CUBE.

19.

Which of the following or not perfect cubes 216,128,11000,1000

Answer»

Answer:

128 and 11000 is not a PERFECT CUBE.

Discussion

20.	6) find the area of a triangle whose ventices are(1, 1),( -4, 6), and (-3,-5)
Answer» Step-by-step EXPLANATION: Let the two points be A(1,-1), B(-4,6) and C(-3,-5) Area of triangle ABC = ½[x¹(y²-y³) + x²(y³-y¹) + x³(y¹-y²)] Here x¹= 1 , y¹ = -1 x²= -4 , y² = 6 x³=-3 , y³ = -5 Putting values Area of triangle ABC =½[1(6-(-5)) + (-4)(-5 -(-1)) + (-3)(-1-6)] =½[1(6+5) + (-4)(-5+1) + (-3)(-7)] =½ [1(11) + (-4)(-4) + (-3)(-7) ] =½[ 11 + 16 + 21 ] =½ [ 48 ] = 24 square meters

20.

6) find the area of a triangle whose ventices are(1, 1),( -4, 6), and (-3,-5)

Answer»

Step-by-step EXPLANATION:

Let the two points be A(1,-1), B(-4,6) and C(-3,-5)

Area of triangle ABC =

½[x¹(y²-y³) + x²(y³-y¹) + x³(y¹-y²)]

Here

x¹= 1 , y¹ = -1

x²= -4 , y² = 6

x³=-3 , y³ = -5

Putting values

Area of triangle ABC =½[1(6-(-5)) + (-4)(-5 -(-1)) + (-3)(-1-6)]

=½[1(6+5) + (-4)(-5+1) + (-3)(-7)]

=½ [1(11) + (-4)(-4) + (-3)(-7) ]

=½[ 11 + 16 + 21 ]

=½ [ 48 ]

= 24 square meters

Discussion

21.	This is my questionhall is 20cm long and 15 cm wide and 4m higha 20 litre tin of paint covers 40m^2 and cost 15$1m^2 floor tiles cost 3$ each work out total cost of paint
Answer» ANSWER: HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII DEAR have a nice DAY....... And GOOD afternoon ❤️❤️

21.

This is my questionhall is 20cm long and 15 cm wide and 4m higha 20 litre tin of paint covers 40m^2 and cost 15$1m^2 floor tiles cost 3$ each work out total cost of paint

Answer»

ANSWER:

HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII DEAR have a nice DAY.......

And GOOD afternoon ❤️❤️

Discussion

22.	3. If HCF of 14 and 180 is expressed in the form13m - 16. Find the value of m. A CBSE SQP, 2020]
Answer» Answer: 14)180(12 168 --------- 12)14(1 12 ------- 2)12(6 12 ------ 0 13m-16=2 13m=18 m=18/13

22.

3. If HCF of 14 and 180 is expressed in the form13m - 16. Find the value of m. A CBSE SQP, 2020]

Answer»

Answer:

14)180(12

168

---------

12)14(1

12

-------

2)12(6

12

------

0

13m-16=2

13m=18

m=18/13

Discussion

23.	वह छोटी से छोटी संख्या ज्ञात कीजिए, जिसे 5, 6, 7,8, से विभाजित करने पर 3 शेष बचता हो, और संख्या9 की गुणज भी हो
Answer» Answer: 1&2 I HOPE that is RIGHT ANS.

23.

वह छोटी से छोटी संख्या ज्ञात कीजिए, जिसे 5, 6, 7,8, से विभाजित करने पर 3 शेष बचता हो, और संख्या9 की गुणज भी हो

Answer»

Answer:

1&2 I HOPE that is RIGHT ANS.

Discussion

24.	The garden is beautiful, if it is well watered. A The garden is not beautiful. B it is well watered C The garden is beautiful. D it is not well watered
Answer» ANSWER: C.the GARDEN is BEAUTIFUL

24.

The garden is beautiful, if it is well watered. A The garden is not beautiful. B it is well watered C The garden is beautiful. D it is not well watered

Answer»

ANSWER:

C.the GARDEN is BEAUTIFUL

Discussion

25.	Q.1Find (-5)×(-4)× (-3).
Answer» Step-by-step explanation: 20×(-3) = -60 ..........

25.

Q.1Find (-5)×(-4)× (-3).

Answer»

Step-by-step explanation:

20×(-3)

= -60

..........

Discussion

26.	द लीव्स एंड द ग्रेटेस्ट नंबर ऑफ वन डिजिट आर
Answer» ANSWER: FOLLOW me and follow me

26.

द लीव्स एंड द ग्रेटेस्ट नंबर ऑफ वन डिजिट आर

Answer»

ANSWER:

FOLLOW me

and follow me

Discussion

27.	4. Rukhsar painted the outside of the cabinetomeasure 1 m x 2 m x 1.5 m. How muching the walls and ceiling of asurface area did she cover if she painted all except the bottom of the cabinet.
Answer» ANSWER: what is cabineto? I will DEFINITELY SOLVE your QUESTION

27.

4. Rukhsar painted the outside of the cabinetomeasure 1 m x 2 m x 1.5 m. How muching the walls and ceiling of asurface area did she cover if she painted all except the bottom of the cabinet.

Answer»

ANSWER:

what is cabineto? I will DEFINITELY SOLVE your QUESTION

Discussion

28.	1. Mayank's mother made a namkeen mixture for him using240-39 g of roasted chana, 135.9 g of roasted peanuts and239.46 g of rice puffs. How much namkeen did she make? Ifshe wants to make 1 kg namkeen, how many grams of wheatpuffs should she add to the namkeen?
Answer» NAMKEEN MEANS what is this

Discussion

29.	Find too Rational number between 1/3 and 3/4
Answer» ANSWER: $(5)113. \times \frac{e \beta \cos( \sec(?) ) }{?}$ EUUSOAWI JOIN the PARTY is a GREAT DAY of

29.

Find too Rational number between 1/3 and 3/4

Answer»

ANSWER:

$(5)113. \times \frac{e \beta \cos( \sec(?) ) }{?}$

EUUSOAWI JOIN the PARTY is a GREAT DAY of

Discussion

30.	Tomorrow was one the great day of my life
Answer» ANSWER: what's the QUESTION in this? Step-by-step EXPLANATION: I will TRY to SOLVE

30.

Tomorrow was one the great day of my life

Answer»

ANSWER:

what's the QUESTION in this?

Step-by-step EXPLANATION:

I will TRY to SOLVE

Discussion

31.	Do not spam solve asap plz
Answer» ANSWER: The answer is in the above attachment HOPE this was helpful.... MARK me brilliants...

31.

Do not spam solve asap plz

Answer»

ANSWER:

The answer is in the above attachment

HOPE this was helpful....

MARK me brilliants...

Discussion

32.	1 1 1 31 2 3 42 3 4 9Rank of matrix3x4
Answer» Answer: 1213 HO SAKTA HAI.....

32.

1 1 1 31 2 3 42 3 4 9Rank of matrix3x4

Answer»

Answer:

1213 HO SAKTA HAI.....

Discussion

33.	Give solution too please.
Answer» Step-by-step EXPLANATION: aaaazzzaaaaaaawqwqqqqas

33.

Give solution too please.

Answer»

Step-by-step EXPLANATION:

aaaazzzaaaaaaawqwqqqqas

Discussion

34.	E. Find the HCF of the following numbers using prime factorisationmethod.1. 25 and 352. 27, 63 and 543. 16, 32 and 48
Answer» ANSWER: SORRY I don't now the ANSWERS

34.

E. Find the HCF of the following numbers using prime factorisationmethod.1. 25 and 352. 27, 63 and 543. 16, 32 and 48

Answer»

ANSWER:

SORRY I don't now the ANSWERS

Discussion

35.	A force of 60 N acts at a point 4 pointsat an angle of 30° with thehorizontal, its component invertical direction is *O 51.96 N0 34.53 NO 25.43 NO 30 N
Answer» ANSWER: Hannan Ajax jwjwnwnwjsjwmms heje

35.

A force of 60 N acts at a point 4 pointsat an angle of 30° with thehorizontal, its component invertical direction is *O 51.96 N0 34.53 NO 25.43 NO 30 N

Answer»

ANSWER:

Hannan Ajax

jwjwnwnwjsjwmms

heje

Discussion

36.	Why cos has not negative sign
Answer» Signs (plus/minus) of SINE and COSINE in all Quadrants The number zero has no sign: 0 is not positive and 0 is not negative. Zero is NEUTRAL! For example, cosπ2=cos90∘=0 ⁡ π 2 = cos ⁡ 90 ∘ = 0 , hence has no sign. If a number is not defined, then (of course) it has no sign.

36.

Why cos has not negative sign

Answer»

Signs (plus/minus) of SINE and COSINE in all Quadrants

The number zero has no sign: 0 is not positive and 0 is not negative. Zero is NEUTRAL! For example, cosπ2=cos90∘=0 ⁡ π 2 = cos ⁡ 90 ∘ = 0 , hence has no sign. If a number is not defined, then (of course) it has no sign.

Discussion

37.	The equation form of the statement.The Sum of numbers x and 4 is 9_______
Answer» X + 4 = 9 x = 9 - 4 x = 5 Equation is x + 4 = 9.

37.

The equation form of the statement.The Sum of numbers x and 4 is 9_______

Answer»

X + 4 = 9

x = 9 - 4

x = 5

Equation is x + 4 = 9.

Discussion

38.	If the M.P. is 480and the discount offered is 2.5%, then sp is
Answer» ANSWER: bsmsopwjehtbdbwmmapspajdhbf ensnfkkf

38.

If the M.P. is 480and the discount offered is 2.5%, then sp is

Answer»

ANSWER:

bsmsopwjehtbdbwmmapspajdhbf ensnfkkf

Discussion

39.	If the amplitude of two sounds are in the ratio 2:3what is the ratio of their loudness
Answer» Step-by-step EXPLANATION: ਫਝਠਹਠੱਸਟ0ਆਗ9ਇਖਿ9ਸਟੇਸਨਸੈੲਨੈੲਨਸੈਸਨੲਐਨਸ8ਇਝੋਇਝਿਐਇਖ4ਐ477474647474755

39.

If the amplitude of two sounds are in the ratio 2:3what is the ratio of their loudness

Answer»

Step-by-step EXPLANATION:

ਫਝਠਹਠੱਸਟ0ਆਗ9ਇਖਿ9ਸਟੇਸਨਸੈੲਨੈੲਨਸੈਸਨੲਐਨਸ8ਇਝੋਇਝਿਐਇਖ4ਐ477474647474755

Discussion

40.	check if triangle stu can be constructed if angle a =90 degree , st = 3 cm and tu = 4 cm . explain your answer.
Answer» I don’t KNOW ANSWER so I can’t EXPLAIN

Discussion

41.	Sec a + tan apls help me
Answer» ANSWER: very very DIFFICULT QUESTION HAI YEE

41.

Sec a + tan apls help me

Answer»

ANSWER:

very very DIFFICULT QUESTION HAI YEE

Discussion

42.	How many dots lie opposite to the face having three dots on a dice?
Answer» ANSWER there is 5dots in the DICE OPPOSITE 3

42.

How many dots lie opposite to the face having three dots on a dice?

Answer»

ANSWER

there is 5dots in the DICE OPPOSITE 3

Discussion

43.	In figure BD = 10 cm Ac = 12 cm and bc = 26 cm A) find area of abc b) Calculate the height AEin figure BD = 10 cm Ac = 12 cm and bc = 26 cm A) find area of abc b) Calculate the height AE ( Figure given below)
Answer» Given: In FIGURE BD = 10 cm AC = 12 cm and BC = 26 cm To find: A) Area of ABC B) The height AE Solution: Finding the value of AD: In Δ BDC, using Pythagoras theorem, we get $BC^2 = CD^2 + BD^2$ $\implies 26^2 = (12 + AD)^2 + 10^2$ $\implies 676 = (12 + AD)^2 + 100$ $\implies 576 = (12 + AD)^2$ $\implies 24 = 12 + AD$ $\implies \bold{AD = 12 \:cm}$ Finding the value of AB: In Δ ABD, using Pythagoras theorem, we get $AB^2 = AD^2 + BD^2$ $\implies AB = \sqrt{AD^2 + AD^2}$ $\implies AB = \sqrt{12^2 + 10^2}$ $\implies \bold{ AB = 15.62\:cm}$ Finding the area of Δ ABC: Using Heron's formula in Δ ABC, we have a = 15.62 cm, b = 12 cm & c = 26 cm Semi-perimeter, S = $\frac{a+b+c}{2} = \frac{15.62 + 12 + 26}{2} = \frac{53.62}{2} = 26.81 \:cm$ ∴ Area of Δ ABC, = $\sqrt{s (s - a) (s -b)(s-c)}$ = $\sqrt{26.81 (26.81 - 15.62) (26.81 - 12)(26.81-26)}$ = $\sqrt{26.81 \times 11.19 \times 14.81 \times 0.81}$ = $59.99$ ≈ $\boxed{\bold {60 \: cm}}$ Finding the height AE: We know, $\boxed{\bold{Area \:of\:a\:triangle = \frac{1}{2} \times base \times height}}$ ∴ Area of Δ ABC = $\frac{1}{2} \times BC \times AE$ $\implies 60 = \frac{1}{2} \times 26 \times AE$ $\implies 60 = 13 \times AE$ $\implies AE = \frac{60}{13}$ $\implies \boxed{\bold{AE =4.6\: cm}}$ -------------------------------------------------------------------------------------- Also View: In the ADJOINING figure, find the area of triangle ABC brainly.in/question/11964151 Find the area of triangle ABC, right-angled at B and AB and BC measuring 16cm and 10 cm respectively. brainly.in/question/6755539 Determine the area of triangle ABC with AC=5cm and height DB=30mm brainly.in/question/12182933 Find BC if the area of the triangle ABC is 36 CM square and the height it is 3 cm brainly.in/question/7425494

43.

In figure BD = 10 cm Ac = 12 cm and bc = 26 cm A) find area of abc b) Calculate the height AEin figure BD = 10 cm Ac = 12 cm and bc = 26 cm A) find area of abc b) Calculate the height AE ( Figure given below)

Answer»

Given:

In FIGURE BD = 10 cm AC = 12 cm and BC = 26 cm

To find:

A) Area of ABC

B) The height AE

Solution:

Finding the value of AD:

In Δ BDC, using Pythagoras theorem, we get

$BC^2 = CD^2 + BD^2$

$\implies 26^2 = (12 + AD)^2 + 10^2$

$\implies 676 = (12 + AD)^2 + 100$

$\implies 576 = (12 + AD)^2$

$\implies 24 = 12 + AD$

$\implies \bold{AD = 12 \:cm}$

Finding the value of AB:

In Δ ABD, using Pythagoras theorem, we get

$AB^2 = AD^2 + BD^2$

$\implies AB = \sqrt{AD^2 + AD^2}$

$\implies AB = \sqrt{12^2 + 10^2}$

$\implies \bold{ AB = 15.62\:cm}$

Finding the area of Δ ABC:

Using Heron's formula in Δ ABC, we have

a = 15.62 cm, b = 12 cm & c = 26 cm

Semi-perimeter, S = $\frac{a+b+c}{2} = \frac{15.62 + 12 + 26}{2} = \frac{53.62}{2} = 26.81 \:cm$

∴ Area of Δ ABC,

= $\sqrt{s (s - a) (s -b)(s-c)}$

= $\sqrt{26.81 (26.81 - 15.62) (26.81 - 12)(26.81-26)}$

= $\sqrt{26.81 \times 11.19 \times 14.81 \times 0.81}$

= $59.99$

≈ $\boxed{\bold {60 \: cm}}$

Finding the height AE:

We know,

$\boxed{\bold{Area \:of\:a\:triangle = \frac{1}{2} \times base \times height}}$

∴ Area of Δ ABC = $\frac{1}{2} \times BC \times AE$

$\implies 60 = \frac{1}{2} \times 26 \times AE$

$\implies 60 = 13 \times AE$

$\implies AE = \frac{60}{13}$

$\implies \boxed{\bold{AE =4.6\: cm}}$

--------------------------------------------------------------------------------------

Also View:

In the ADJOINING figure, find the area of triangle ABC

brainly.in/question/11964151

Find the area of triangle ABC, right-angled at B and AB and BC measuring 16cm and 10 cm respectively.

brainly.in/question/6755539

Determine the area of triangle ABC with AC=5cm and height DB=30mm

brainly.in/question/12182933

Find BC if the area of the triangle ABC is 36 CM square and the height it is 3 cm

brainly.in/question/7425494

Discussion

44.	Sᴛᴀᴛᴇ ᴛʜᴇ ɢᴀsᴇᴏᴜs ᴘʀᴏᴅᴜᴄᴛ ғᴏʀᴍᴇᴅ ᴡʜᴇɴ ᴀ ᴍᴇᴛᴇʟʟɪᴄ ɴɪᴛʀᴀᴛᴇ ᴜɴᴅᴇʀɢᴏᴇs ᴛʜʀ ᴛʜᴇʀᴍᴀʟ ᴅᴇᴄᴏᴍᴘᴏsɪᴛɪᴏɴ ɢɪᴠɪɴɢ ᴀ ᴄᴏʟᴏᴜʀᴇᴅ ɢᴀs.....ᴋɪɴᴅʟʏ sᴘᴀᴍ ☝️☝️☝️☝️☝️☝️☝️☝️☝️☝️☝️
Answer» ANSWER: NITROGEN DIOXIDE....!!

44.

Sᴛᴀᴛᴇ ᴛʜᴇ ɢᴀsᴇᴏᴜs ᴘʀᴏᴅᴜᴄᴛ ғᴏʀᴍᴇᴅ ᴡʜᴇɴ ᴀ ᴍᴇᴛᴇʟʟɪᴄ ɴɪᴛʀᴀᴛᴇ ᴜɴᴅᴇʀɢᴏᴇs ᴛʜʀ ᴛʜᴇʀᴍᴀʟ ᴅᴇᴄᴏᴍᴘᴏsɪᴛɪᴏɴ ɢɪᴠɪɴɢ ᴀ ᴄᴏʟᴏᴜʀᴇᴅ ɢᴀs.....ᴋɪɴᴅʟʏ sᴘᴀᴍ ☝️☝️☝️☝️☝️☝️☝️☝️☝️☝️☝️

Answer»

ANSWER:

NITROGEN DIOXIDE....!!

Discussion

45.	Find the square root of 1.44
Answer» √1.44 = 1.2 HOPE IT HELPS U..

45.

Find the square root of 1.44

Answer»

√1.44 = 1.2

HOPE IT HELPS U..

Discussion

46.	The height of acone is 3ocm. A small coneis cut off at the top bya Plane parallel toits base. If its volume be 1\27of the volume ofgiven cone at what heightht above the baseis the section made.
Answer» Answer: 20cm Step-by- i HOPE it HELPS

46.

The height of acone is 3ocm. A small coneis cut off at the top bya Plane parallel toits base. If its volume be 1\27of the volume ofgiven cone at what heightht above the baseis the section made.

Answer»

Answer:

20cm

Step-by-

i HOPE it HELPS

Discussion

47.	Is 254790 divisible by 40? Check using divisibility rule.
Answer» 254790 / 40 CANCEL ZEROS 25479/4 79 IS NOT DIVISIBLE BY 4 (DIVISIBILITY TEST) HENCE 25790 IS NOT DIVISIBLE BY 40. HENCE PROVED

47.

Is 254790 divisible by 40? Check using divisibility rule.

Answer»

254790 / 40

CANCEL ZEROS

25479/4

79 IS NOT DIVISIBLE BY 4 (DIVISIBILITY TEST)

HENCE 25790 IS NOT DIVISIBLE BY 40.

HENCE PROVED

Discussion

48.	The graph of r5 is a linie
Answer» ANSWER: HLO have a WONDERFUL DAY Step-by-step explanation: NICE day

48.

The graph of r5 is a linie

Answer»

ANSWER:

HLO have a WONDERFUL DAY

Step-by-step explanation:

NICE day

Discussion

49.	If -3x+17
Answer» ANSWER: -3x=-13-17 -3x= - 30 x = -30/-3 x = 10

49.

If -3x+17

Answer»

ANSWER:

-3x=-13-17

-3x= - 30

x = -30/-3

x = 10

Discussion

50.	The 11 th term and the 21 st term of an AP are 16 and 29 respectively then the 41 term of that AP
Answer» Solution:- Given => T₁₁ = 16 =>T₂₁ = 29 To find =>T₄₁ =? Formula => Tₙ = a + ( n - 1 )d Now take => T₁₁ = 16 => 16 = a + ( 11 - 1 )d => a + 10d = 16 .......(i)st eq T₂₁ = 29 => 29 = a + ( 21 - 1 )d => a + 20D = 29 .....(ii)ND eq Now subtract (i)eq from (ii)eq => a + 20d - a - 10d = 29 - 16 => 10d = 13 => d = 13/10 Now put the value of 10d on first equation => a + 10d = 16 => a + 13 = 16 => a = 3 Now we have to find T₄₁ => T₄₁ = a + ( 41 - 1 )d => T₄₁ = 3 + 40 × 13/10 => T₄₁ = 3 + 4 × 13 => T₄₁ = 3 + 52 => T₄₁ = 55

50.

The 11 th term and the 21 st term of an AP are 16 and 29 respectively then the 41 term of that AP

Answer»

Solution:-

Given

=> T₁₁ = 16

=>T₂₁ = 29

To find

=>T₄₁ =?

Formula

=> Tₙ = a + ( n - 1 )d

Now take

=> T₁₁ = 16

=> 16 = a + ( 11 - 1 )d

=> a + 10d = 16 .......(i)st eq

T₂₁ = 29

=> 29 = a + ( 21 - 1 )d

=> a + 20D = 29 .....(ii)ND eq

Now subtract (i)eq from (ii)eq

=> a + 20d - a - 10d = 29 - 16

=> 10d = 13 => d = 13/10

Now put the value of 10d on first equation

=> a + 10d = 16

=> a + 13 = 16

=> a = 3

Now we have to find T₄₁

=> T₄₁ = a + ( 41 - 1 )d

=> T₄₁ = 3 + 40 × 13/10

=> T₄₁ = 3 + 4 × 13

=> T₄₁ = 3 + 52

=> T₄₁ = 55

Discussion

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