1.

6) find the area of a triangle whose ventices are(1, 1),( -4, 6), and (-3,-5)​

Answer»

Step-by-step EXPLANATION:

Let the two points be A(1,-1), B(-4,6) and C(-3,-5)

Area of triangle ABC =

½[x¹(y²-y³) + x²(y³-y¹) + x³(y¹-y²)]

Here

x¹= 1 , y¹ = -1

x²= -4 , y² = 6

x³=-3 , y³ = -5

Putting values

Area of triangle ABC =½[1(6-(-5)) + (-4)(-5 -(-1)) + (-3)(-1-6)]

=½[1(6+5) + (-4)(-5+1) + (-3)(-7)]

=½ [1(11) + (-4)(-4) + (-3)(-7) ]

=½[ 11 + 16 + 21 ]

=½ [ 48 ]

= 24 square meters



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