332354 + Interview Questions in Secondary School in Math

1.	Mr. Dubey borrows rs100000 from a bank at 10%p.a compound interest. what amount will he have to pay to the bank
Answer» COMPLETE Question : Mr. Dubey borrows Rs. 100000 from a bank at 10%p.a compound INTEREST. what amount will he have to pay to the bank after 3 years. ⠀ ⠀ ⠀ ━━━━━━━━━━━━━━━━⠀ ⠀ AnswEr : The amount he will pay to the bank after 3 years = Rs. 133100. ⠀ Explanation : We are given with the principal, rate and time, that is, Principal, P = Rs. 100000. ⠀ Rate of interest, R = 10% per annum. ⠀ Time, N = 3 years. ⠀ We have to find out the amount he will pay to the bank after 3 years. ⠀ As we are given with principal, rate and time we KNOW that, if we are given with the principal, rate and time, we have the required formula, that is, ⠀ ⠀ $\sf{:\implies A = P \bigg\lgroup 1 + \dfrac{R}{100} \bigg\rgroup ^n}$ ⠀ ⠀ Substituting the given VALUES in the formula : ⠀ $\sf{:\implies A = 100000 \bigg\lgroup 1 + \dfrac{1 \cancel0}{10 \cancel0} \bigg\rgroup ^3}$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup 1 + \dfrac{1}{10} \bigg\rgroup ^3}$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{10 + 1}{10} \bigg\rgroup ^3}$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{11}{10} \bigg\rgroup ^3}$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{ {11}^{3} }{ {10}^{3} } \bigg\rgroup }$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{1331}{ {10}^{3} } \bigg\rgroup }$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{1331}{1000} \bigg\rgroup }$ ⠀ $\sf{:\implies A = 100 \cancel{000 } \times \dfrac{1331}{1 \cancel{000}}}$ ⠀ $\sf{:\implies A = 100 \times 1331}$ ⠀ $\sf{:\implies \boxed{ \pink{ \frak{A = 133100}}}}$ ⠀ Hence, the amount he will pay to the bank after 3 years = Rs. 133100.

1.

Mr. Dubey borrows rs100000 from a bank at 10%p.a compound interest. what amount will he have to pay to the bank

Answer»

COMPLETE Question :

Mr. Dubey borrows Rs. 100000 from a bank at 10%p.a compound INTEREST. what amount will he have to pay to the bank after 3 years.

⠀ ⠀ ⠀ ━━━━━━━━━━━━━━━━⠀

⠀

AnswEr :

The amount he will pay to the bank after 3 years = Rs. 133100.

⠀

Explanation :

We are given with the principal, rate and time, that is,

Principal, P = Rs. 100000.

⠀

Rate of interest, R = 10% per annum.

⠀

Time, N = 3 years.

⠀

We have to find out the amount he will pay to the bank after 3 years.

⠀

As we are given with principal, rate and time we KNOW that, if we are given with the principal, rate and time, we have the required formula, that is,

⠀

$\sf{:\implies A = P \bigg\lgroup 1 + \dfrac{R}{100} \bigg\rgroup ^n}$

⠀

Substituting the given VALUES in the formula :

⠀

$\sf{:\implies A = 100000 \bigg\lgroup 1 + \dfrac{1 \cancel0}{10 \cancel0} \bigg\rgroup ^3}$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup 1 + \dfrac{1}{10} \bigg\rgroup ^3}$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{10 + 1}{10} \bigg\rgroup ^3}$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{11}{10} \bigg\rgroup ^3}$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{ {11}^{3} }{ {10}^{3} } \bigg\rgroup }$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{1331}{ {10}^{3} } \bigg\rgroup }$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{1331}{1000} \bigg\rgroup }$

⠀

$\sf{:\implies A = 100 \cancel{000 } \times \dfrac{1331}{1 \cancel{000}}}$

⠀

$\sf{:\implies A = 100 \times 1331}$

⠀

$\sf{:\implies \boxed{ \pink{ \frak{A = 133100}}}}$

⠀

Hence, the amount he will pay to the bank after 3 years = Rs. 133100.

Discussion

2.	If 20%+4) =64., X = ?
Answer» Answer: 29 Step-by-step EXPLANATION: .... . . .. . ................

2.

If 20%+4) =64., X = ?

Answer»

Answer:

29

Step-by-step EXPLANATION:

....

.

.. . ................

Discussion

3.	Prove that in a parallelogram the inspectors of any two consecutive angles intersect at right angles.
Answer» Note: For better understanding refer to the attachment. To prove: In a parallelogram the inspectors of any two consecutive angles intersect at right angles. Proof: LETS CONSIDER, ABCD is a parallelogram. We know that, AB \|\| CD and AB is a transversal . . . . ( i ) Now, As we know that, $\angle$ ADB + $\angle$ BCD = 180° ( From ( i ) ) So, = $\dfrac{1}{2}$ $\angle$ ADB + $\dfrac{1}{2}$ $\angle$ BCD = $\dfrac{1}{2}$ × 180 = $\dfrac{1}{2}$ $\angle$ ADB + $\dfrac{1}{2}$ $\angle$ BCD = 90° That is, = $\angle$ 1 + $\angle$ 2 = 90 . . .(ii) Now, in $\triangle$ COD = $\angle$ 1 + $\angle$ 2 + $\angle$ COD = 180° { Prop. of triangle } = 90 + $\angle$ COD = 180° = $\angle$ COD = 180° - 90 = $\angle$ COD = 90° Hence PROVED!!

3.

Prove that in a parallelogram the inspectors of any two consecutive angles intersect at right angles.

Answer»

Note: For better understanding refer to the attachment.

To prove: In a parallelogram the inspectors of any two consecutive angles intersect at right angles.

Proof:

LETS CONSIDER,

ABCD is a parallelogram.

We know that,

AB || CD and AB is a transversal . . . . ( i )

Now,

As we know that, $\angle$ ADB + $\angle$ BCD = 180° ( From ( i ) )

So,

= $\dfrac{1}{2}$ $\angle$ ADB + $\dfrac{1}{2}$ $\angle$ BCD = $\dfrac{1}{2}$ × 180

= $\dfrac{1}{2}$ $\angle$ ADB + $\dfrac{1}{2}$ $\angle$ BCD = 90°

That is,

= $\angle$ 1 + $\angle$ 2 = 90 . . .(ii)

Now, in $\triangle$ COD

= $\angle$ 1 + $\angle$ 2 + $\angle$ COD = 180° { Prop. of triangle }

= 90 + $\angle$ COD = 180°

= $\angle$ COD = 180° - 90

= $\angle$ COD = 90°

Hence PROVED!!

Discussion

4.	2-4xlim1 8x -42questions:
Answer» Answer: 7r39845 8475 94 84 8357dj . 98852 aabad

4.

2-4xlim1 8x -42questions:

Answer»

Answer:

7r39845 8475 94

84

8357dj .

98852

aabad

Discussion

5.	- 2700 =а) -2.3b) -ЗrЗас2
Answer» ANSWER: ACCORDING ......to..,.......me......the........ CORRECT........answer is B

5.

- 2700 =а) -2.3b) -ЗrЗас2

Answer»

ANSWER:

ACCORDING ......to..,.......me......the........ CORRECT........answer is B

Discussion

6.	a train 270m long is running at a speed of 80 km per hour. how much time will it take to cross a platform 130 metre long
Answer» Answer: Speed of the train = 80 km/hr = 80 x 1000/3600 80 x 5/18 = 200/9 m/sec Distance = LENGTH of the trian + length of the platform = 130 m + 270 m = 400 m Time = Distance / Speed = 400x9 / 200 = 2 x 9 = 18 sec. pls FOLLOW me I will follow you

6.

a train 270m long is running at a speed of 80 km per hour. how much time will it take to cross a platform 130 metre long

Answer»

Answer:

Speed of the train = 80 km/hr = 80 x 1000/3600 80 x 5/18 = 200/9 m/sec

Distance = LENGTH of the trian + length of the platform = 130 m + 270 m = 400 m

Time = Distance / Speed

= 400x9 / 200

= 2 x 9

= 18 sec.

pls FOLLOW me I will follow you

Discussion

7.	- If a and b are parallel vectors,then [ á,c,b] is equal to
Answer» ANSWER: a,B,C, are = 1,4,2

7.

- If a and b are parallel vectors,then [ á,c,b] is equal to

Answer»

ANSWER:

a,B,C, are = 1,4,2

Discussion

8.	X-5
Answer» Step-by-step explanation: Add 5 on both side of the equation we get X<0 It means all the x less than 0 is the solution of INEQUALITY. Thank you so much for the points.

8.

X-5

Answer»

Step-by-step explanation:

Add 5 on both side of the equation we get

X<0

It means all the x less than 0 is the solution of INEQUALITY.

Thank you so much for the points.

Discussion

9.	A square and a rectangle have the sameperimeter. If the side of the square is 16 mand the length of the rectangle is 18 m, thebreadth of the rectangle is:15 m
Answer» Answer: THANKS for free points Step-by-step explanation: PLEASE FOLLOW me please follow me please follow me

9.

A square and a rectangle have the sameperimeter. If the side of the square is 16 mand the length of the rectangle is 18 m, thebreadth of the rectangle is:15 m

Answer»

Answer:

THANKS for free points

Step-by-step explanation:

PLEASE FOLLOW me please follow me please follow me

Discussion

10.	Pls answer me.....pls...its urgent....pls....don't spam....
Answer» 6) 11 , 18 7 ) 0:13/3 option 1 for both the ANSWERS

10.

Pls answer me.....pls...its urgent....pls....don't spam....

Answer»

6) 11 , 18

7 ) 0:13/3

option 1 for both the ANSWERS

Discussion

11.	The lattice method is an alternative to long multiplication for numbers................. true or false
Answer» Answer: The lattice method is an alternative to long multiplication for numbers. In this approach, a lattice is first constructed, sized to fit the numbers being multiplied. If we are multiplying an m-digit NUMBER by an n-digit number, the size of the lattice is m×n. The multiplicand is placed along the top of the lattice so that each digit is the header for one column of cells (the most significant digit is put at the left). The multiplier is placed along the right side of the lattice so that each digit is a (TRAILING) header for one row of cells (the most significant digit is put at the top). Illustrated above is the lattice configuration for computing 948×827. LatticeMethod2 Before the actual multiplication can begin, lines must be drawn for every diagonal path in the lattice from upper right to lower left to bisect each cell. There will be 5 diagonals for our 3×3 lattice array. LatticeMethod3 Now we calculate a product for each cell by multiplying the digit at the top of the column and the digit at the right of the row. The tens digit of the product is placed above the diagonal that passes through the cell, and the units digit is put below that diagonal. If the product is less than 10, we enter a ZERO above the diagonal. Now we are ready to calculate the digits of the product. We sum the numbers between every pair of diagonals and also between the first (and LAST) diagonal and the corresponding corner of the lattice. We START at the bottom half of the lower right corner cell (6). This number is bounded by the corner of the lattice and the first diagonal. Since this is the only number below this diagonal, the first sum is 6. We place the sum along the bottom of the lattice below the rightmost column. LatticeMethod4 Next we sum the numbers between the previous diagonal and the next higher diagonal: 6+5+8=19. We place the 9 just below the bottom of the lattice and carry the 1 into the sum for the next diagonal group. (The diagonals are extended for clarity.) We continue summing the groups of numbers between adjacent diagonals, and also between the top diagonal and the upper left corner. The final product is composed of the digits outside the lattice which were just calculated. We read the digits down the left side and then towards the right on the bottom to generate the final answer: 783996. Although the process at first glance appears quite different from long multiplication, the lattice method is actually algorithmically equivalent. False

11.

The lattice method is an alternative to long multiplication for numbers................. true or false

Answer»

Answer:

The lattice method is an alternative to long multiplication for numbers. In this approach, a lattice is first constructed, sized to fit the numbers being multiplied. If we are multiplying an m-digit NUMBER by an n-digit number, the size of the lattice is m×n. The multiplicand is placed along the top of the lattice so that each digit is the header for one column of cells (the most significant digit is put at the left). The multiplier is placed along the right side of the lattice so that each digit is a (TRAILING) header for one row of cells (the most significant digit is put at the top). Illustrated above is the lattice configuration for computing 948×827.

LatticeMethod2

Before the actual multiplication can begin, lines must be drawn for every diagonal path in the lattice from upper right to lower left to bisect each cell. There will be 5 diagonals for our 3×3 lattice array.

LatticeMethod3

Now we calculate a product for each cell by multiplying the digit at the top of the column and the digit at the right of the row. The tens digit of the product is placed above the diagonal that passes through the cell, and the units digit is put below that diagonal. If the product is less than 10, we enter a ZERO above the diagonal.

Now we are ready to calculate the digits of the product. We sum the numbers between every pair of diagonals and also between the first (and LAST) diagonal and the corresponding corner of the lattice. We START at the bottom half of the lower right corner cell (6). This number is bounded by the corner of the lattice and the first diagonal. Since this is the only number below this diagonal, the first sum is 6. We place the sum along the bottom of the lattice below the rightmost column.

LatticeMethod4

Next we sum the numbers between the previous diagonal and the next higher diagonal: 6+5+8=19. We place the 9 just below the bottom of the lattice and carry the 1 into the sum for the next diagonal group. (The diagonals are extended for clarity.)

We continue summing the groups of numbers between adjacent diagonals, and also between the top diagonal and the upper left corner. The final product is composed of the digits outside the lattice which were just calculated. We read the digits down the left side and then towards the right on the bottom to generate the final answer: 783996.

Although the process at first glance appears quite different from long multiplication, the lattice method is actually algorithmically equivalent.

False

Discussion

12.	If a and 6 are two positivenumbers and Hand L are theirHCF and LCM respectively.Then *O a) a x b = H x LO (b) a = b xHO (c) a = x/O (d) H = N/Hx
Answer» ANSWER: B) a=bxh............

12.

If a and 6 are two positivenumbers and Hand L are theirHCF and LCM respectively.Then *O a) a x b = H x LO (b) a = b xHO (c) a = x/O (d) H = N/Hx

Answer»

ANSWER:

B) a=bxh............

Discussion

13.	1122a2b - 9ab2+ 6ab
Answer»

Discussion

14.	1+22224934485859-944490
Answer»

Discussion

15.	Find the number is 15% more than 340
Answer» Answer: 391 Step-by-step EXPLANATION: HOPE it will HELP you

15.

Find the number is 15% more than 340

Answer»

Answer:

391

Step-by-step EXPLANATION:

HOPE it will HELP you

Discussion

16.	How many vertices does each of the following solids have?(a) Cone (b) Cylinder (c) Tetrahedron (d) Hexagonal Prism
Answer» Answer: 1 Three 2 four 4 SIX RADHE KRISHNA

16.

How many vertices does each of the following solids have?(a) Cone (b) Cylinder (c) Tetrahedron (d) Hexagonal Prism

Answer»

Answer:

1 Three

2 four

4 SIX

RADHE KRISHNA

Discussion

17.	One meter is equal to how many centimeter
Answer» Answer: 100CM=1M Step-by-step EXPLANATION: PLS MARK BRAINLIST

17.

One meter is equal to how many centimeter

Answer»

Answer:

100CM=1M

Step-by-step EXPLANATION:

PLS MARK BRAINLIST

Discussion

18.	The radius of the sector is 14cm and the center angle is 120°.find perimeter of sector
Answer» ANSWER: the radius of the SECTOR is 14 cm centre ANGLE is-----_-____120 DEGREE 120 degree-14 cm answer is 106 degree cm

18.

The radius of the sector is 14cm and the center angle is 120°.find perimeter of sector

Answer»

ANSWER:

the radius of the SECTOR is 14 cm

centre ANGLE is-----_-____120 DEGREE

120 degree-14 cm

answer is

106 degree cm

Discussion

19.	Find the value of x : (√3)^x=3^6
Answer» ANSWER: x=12 Step-by-step EXPLANATION: ${3}^{ \frac{x}{2} } = {3}^{6} \\ \\ comparing \: the \: powers \: \: when \: are \: equal \\ \frac{x}{2 } = 6 \\ x = 12$ i HOPE , U can UNDERSTAND

19.

Find the value of x : (√3)^x=3^6

Answer»

ANSWER:

x=12

Step-by-step EXPLANATION:

${3}^{ \frac{x}{2} } = {3}^{6} \\ \\ comparing \: the \: powers \: \: when \: are \: equal \\ \frac{x}{2 } = 6 \\ x = 12$

i HOPE , U can UNDERSTAND

Discussion

20.	X? +19. (i)dxx²+x²+1m+1+
Answer» Answer: sorry couldn't UNDERSTAND QUESTION.....have a great DAY AHEAD ✌ ^ω^

20.

X? +19. (i)dxx²+x²+1m+1+

Answer»

Answer:

sorry couldn't UNDERSTAND QUESTION.....have a great DAY AHEAD ✌ ^ω^

Discussion

21.	Resolve x^3/(2x-1)(x-1)^2 into partial fractions
Answer» ANSWER: qwertyuiopasdfghjklzxcvbnmmnbvcxzlkjhgfdsapoiuytreeq

21.

Resolve x^3/(2x-1)(x-1)^2 into partial fractions

Answer»

ANSWER:

qwertyuiopasdfghjklzxcvbnmmnbvcxzlkjhgfdsapoiuytreeq

Discussion

22.	Apply the divisibility rule of 13 and 7 on 14025.
Answer» Answer: Test for divisibility by 13. Add four TIMES the last digit to the remaining leading TRUNCATED number. If the result is divisible by 13, then so was the first number. Apply this rule over and over again as necessary. Divisibility by 7. ... To CHECK if a number is evenly divisible by 7: Take the last digit of the number, DOUBLE it Then subtract the result from the rest of the number If the resulting number is evenly divisible by 7, so is the ORIGINAL number.

22.

Apply the divisibility rule of 13 and 7 on 14025.

Answer»

Answer:

Test for divisibility by 13.

Add four TIMES the last digit to the remaining leading TRUNCATED number. If the result is divisible by 13, then so was the first number. Apply this rule over and over again as necessary.

Divisibility by 7. ... To CHECK if a number is evenly divisible by 7: Take the last digit of the number, DOUBLE it Then subtract the result from the rest of the number If the resulting number is evenly divisible by 7, so is the ORIGINAL number.

Discussion

23.	Write four negative integer smaller than -50.
Answer» ANSWER: -10 -20 -30 -40............

23.

Write four negative integer smaller than -50.

Answer»

ANSWER:

-10

-20

-30

-40............

Discussion

24.	Of a project is the differencebetween the total cost and the totalincome over the life of a project
Answer» ANSWER: A project's cash FLOW is BASICALLY the difference between the project's income and its expense. The difference between a company's total income and its total expense over a period of time is the company cash flow. At the project level, a project's cash flow is the difference between the project's expense and income. Step-by-step explanation: Hope it helps you DEAR friend

24.

Of a project is the differencebetween the total cost and the totalincome over the life of a project

Answer»

ANSWER:

A project's cash FLOW is BASICALLY the difference between the project's income and its expense. The difference between a company's total income and its total expense over a period of time is the company cash flow. At the project level, a project's cash flow is the difference between the project's expense and income.

Step-by-step explanation:

Hope it helps you DEAR friend

Discussion

25.	Simplify216-56+294-36
Answer» Answer: 418 Step-by-step explanation: I SOLVED it..incase any DOUBTS .. Comment' on it ...or else if any method if you know please share .. or if it is WRONG please correct it .... THANK you...

25.

Simplify216-56+294-36

Answer»

Answer:

418

Step-by-step explanation:

I SOLVED it..incase any DOUBTS .. Comment' on it ...or else if any method if you know please share .. or if it is WRONG please correct it ....

THANK you...

Discussion

26.	Simplify and expresse
Answer» ANSWER: (1/6 + 2/3) `¹ (1+4/6) `1 5/6 6/5 answer

26.

Simplify and expresse

Answer»

ANSWER:

(1/6 + 2/3) `¹

(1+4/6) `1

5/6

6/5 answer

Discussion

27.	8. When two lines intersect the vertically opposite angles thus formed are equalsum of all the angles at a pom7. The sum of all the angles at a point is 360°1. Find the measures of the acute angles, obtuse angles and reflex angles in the figures beR605060°20S(1) At 2 o'clock, what are the acute angle and the reflex angle between the minand the hour hand of a clock?(1) At 5 o'clock, what are the obtuse angle and the reflex angle between the miand the hour hand of a clock?Write the complement (complementary angle) of each of the following,(1) 36(11) 56°(111) 78(iv) 30°45
Answer» Answer: meet PR ha kiya MEETING

27.

8. When two lines intersect the vertically opposite angles thus formed are equalsum of all the angles at a pom7. The sum of all the angles at a point is 360°1. Find the measures of the acute angles, obtuse angles and reflex angles in the figures beR605060°20S(1) At 2 o'clock, what are the acute angle and the reflex angle between the minand the hour hand of a clock?(1) At 5 o'clock, what are the obtuse angle and the reflex angle between the miand the hour hand of a clock?Write the complement (complementary angle) of each of the following,(1) 36(11) 56°(111) 78(iv) 30°45

Answer»

Answer:

meet PR ha kiya MEETING

Discussion

28.	Solve 6 into minus 1 is equal 3 into plus 8
Answer» Answer: 6-1=38 -6=24 Step-by-step EXPLANATION:

28.

Solve 6 into minus 1 is equal 3 into plus 8

Answer»

Answer:

6*-1=3*8

-6=24

Step-by-step EXPLANATION:

Discussion

29.	Two tangents PA and PB are drawn to a circle with centre O such that OP=2AP, find AOP.
Answer» ANSWER: SORRY but i don't KNOW the answer for this QUESTION.

29.

Two tangents PA and PB are drawn to a circle with centre O such that OP=2AP, find AOP.

Answer»

ANSWER:

SORRY but i don't KNOW the answer for this QUESTION.

Discussion

30.	Find the volume of right circular cone with the radius 6 cm and hieght 7cm
Answer» ✮ Question : Find the VOLUME of right circular cone with the radius 6 cm and HEIGHT 7cm ✮ GIVEN : Radius = 6 cm and height = 7cm ✮ To Find : Volume of right circular cone ✮ Answer : Volume of Right Circular Cone = 792 cm³ ____________________________________________ ✮ Explanation : Volume of Right Circular Cone = πr²h ⇒ Volume of Right Circular Cone = π × r² × h ⇒ Volume of Right Circular Cone = 22/7 × r² × h ⇒ Volume of Right Circular Cone = 22/7 × (6 cm)² × 7 cm ⇒ Volume of Right Circular Cone = 22/7 × 36 cm² × 7 cm ⇒ Volume of Right Circular Cone = 22/1 × 36 cm² × 1 cm ⇒ Volume of Right Circular Cone = 22 × 36 cm³ ⇒ Volume of Right Circular Cone = 792 cm³ ____________________________________________ ✮ DIAGRAM : $\setlength{\unitlength}{1.2mm}\begin{picture}(5,5)\thicklines\put(0,0){\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\put(-0.5,-1){\line(1,2){13}}\put(25.5,-1){\line(-1,2){13}}\multiput(12.5,-1)(2,0){7}{\line(1,0){1}}\multiput(12.5,-1)(0,4){7}{\line(0,1){2}}\put(18,1.6){\sf{6 cm}}\put(9.5,10){\sf{7 cm}}\end{picture}$ ____________________________________________ ✮ Note : SEE this answer at web to view the diagram given ✮ See The Answer at : brainly.in/question/30491094

30.

Find the volume of right circular cone with the radius 6 cm and hieght 7cm

Answer»

✮ Question : Find the VOLUME of right circular cone with the radius 6 cm and HEIGHT 7cm

✮ GIVEN : Radius = 6 cm and height = 7cm

✮ To Find : Volume of right circular cone

✮ Answer : Volume of Right Circular Cone = 792 cm³

____________________________________________

✮ Explanation :

Volume of Right Circular Cone = πr²h

⇒ Volume of Right Circular Cone = π × r² × h

⇒ Volume of Right Circular Cone = 22/7 × r² × h

⇒ Volume of Right Circular Cone = 22/7 × (6 cm)² × 7 cm

⇒ Volume of Right Circular Cone = 22/7 × 36 cm² × 7 cm

⇒ Volume of Right Circular Cone = 22/1 × 36 cm² × 1 cm

⇒ Volume of Right Circular Cone = 22 × 36 cm³

⇒ Volume of Right Circular Cone = 792 cm³

____________________________________________

✮ DIAGRAM :

$\setlength{\unitlength}{1.2mm}\begin{picture}(5,5)\thicklines\put(0,0){\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\put(-0.5,-1){\line(1,2){13}}\put(25.5,-1){\line(-1,2){13}}\multiput(12.5,-1)(2,0){7}{\line(1,0){1}}\multiput(12.5,-1)(0,4){7}{\line(0,1){2}}\put(18,1.6){\sf{6 cm}}\put(9.5,10){\sf{7 cm}}\end{picture}$

____________________________________________

✮ Note :

SEE this answer at web to view the diagram given

✮ See The Answer at :

brainly.in/question/30491094

Discussion

31.	Choose the correct option which of the following number is not a factor of 15
Answer» ANSWER: U have not GIVEN OPTION

31.

Choose the correct option which of the following number is not a factor of 15

Answer»

ANSWER:

U have not GIVEN OPTION

Discussion

32.	What is the ratio of 497
Answer» Step-by-step EXPLANATION: DOWNLOAD the ASK TOPPER for the ANSWER

32.

What is the ratio of 497

Answer»

Step-by-step EXPLANATION:

DOWNLOAD the ASK TOPPER for the ANSWER

Discussion

33.	First term and common difference of an A.P are 6 and 3 respectively find s 27
Answer» S O L U T I O N : GIVEN, First term (a) = 6 Common difference (d) = 3 To Find, SUM of 27 terms. Explanation, We know that, Sum of nth terms, => Sn = n/2 × (2a + (n - 1)d) [ Here, n = 27 ] => S_27 = 27/2 × (2 × 6 + (27 - 1) × 3) => S_27 = 27/2 × (12 + 26 × 3) => S_27 = 27/2 × (12 + 78) => S_27 = 27/2 × (90) => S_27 = 27 × 45 => S_27 = 1215 Therefore, The sum of 27 terms is 1215.

33.

First term and common difference of an A.P are 6 and 3 respectively find s 27

Answer»

S O L U T I O N :

GIVEN,

First term (a) = 6
Common difference (d) = 3

To Find,

SUM of 27 terms.

Explanation,

We know that,

Sum of nth terms,

=> Sn = n/2 × (2a + (n - 1)d)

[ Here, n = 27 ]

=> S_27 = 27/2 × (2 × 6 + (27 - 1) × 3)

=> S_27 = 27/2 × (12 + 26 × 3)

=> S_27 = 27/2 × (12 + 78)

=> S_27 = 27/2 × (90)

=> S_27 = 27 × 45

=> S_27 = 1215

Therefore,

The sum of 27 terms is 1215.

Discussion

34.	Please give the answer..... no need of explanation
Answer» ANSWER: EQUAL and RECTANGLE....

34.

Please give the answer..... no need of explanation

Answer»

ANSWER:

EQUAL and RECTANGLE....

Discussion

35.	One meter is equal to how many centemeter
Answer» Answer: 1etre = 100 cm Step-by-step EXPLANATION: PLZZ MARK me as a BRAINLIST

35.

One meter is equal to how many centemeter

Answer»

Answer:

1etre = 100 cm

Step-by-step EXPLANATION:

PLZZ MARK me as a BRAINLIST

Discussion

36.	The solution of 3 + x / 5 = 6 is
Answer» ✮ Question : (3 + x)/5 = 6 ✮ Answer : x = 27 ________________________ ✮ EXPLANATION : (3 + x)/5 = 6 ⇒ (3 + x) = 6 × 5 ⇒ 3 + x = 30 ⇒ x = 30 - 3 ⇒ x = 27

36.

The solution of 3 + x / 5 = 6 is

Answer»

✮ Question : (3 + x)/5 = 6

✮ Answer : x = 27

________________________

✮ EXPLANATION :

(3 + x)/5 = 6

⇒ (3 + x) = 6 × 5

⇒ 3 + x = 30

⇒ x = 30 - 3

⇒ x = 27

Discussion

37.	In method of undetemined coefficients, to find the P. I Of Fcontaining unknown constants which are determined by substituA) A functionB) An equationC) A Trial solutionD) An expression
Answer» Answer: containing UNKNOWN CONSTANT which are DETERMINED by substitu -- A FUNCTION

37.

In method of undetemined coefficients, to find the P. I Of Fcontaining unknown constants which are determined by substituA) A functionB) An equationC) A Trial solutionD) An expression

Answer»

Answer:

containing UNKNOWN CONSTANT which are DETERMINED by substitu -- A FUNCTION

Discussion

38.	Calculate how long it will take for the following amounts of interest to be earned at the given ratePrincipal=500 dollars Rate(yearly)=6%S.I.= 150 dollars
Answer» ANSWER: SORRY but i don't KNOW the answer for this QUESTION.

38.

Calculate how long it will take for the following amounts of interest to be earned at the given ratePrincipal=500 dollars Rate(yearly)=6%S.I.= 150 dollars

Answer»

ANSWER:

SORRY but i don't KNOW the answer for this QUESTION.

Discussion

39.	Q.11.What is the cost of 600 pins if the cost of 12dozen pins is Rs.36
Answer» Answer: SOLUTIONS:− ________________________________ [1 GROSS = 144 unit] We have, Rs 36 = 144 pin So, COST of 1 pin = 36/144 = Rs 0.25 Now, Cost of 600 pins = Rs 0.25 × 600 = Rs 150 Hence, Cost 600 pins = Rs 150 Step-by-step explanation: hope it helps dear...........

39.

Q.11.What is the cost of 600 pins if the cost of 12dozen pins is Rs.36

Answer»

Answer:

SOLUTIONS:−

________________________________

[1 GROSS = 144 unit]

We have,

Rs 36 = 144 pin

So,

COST of 1 pin = 36/144 = Rs 0.25

Now,

Cost of 600 pins = Rs 0.25 × 600 = Rs 150

Hence,

Cost 600 pins = Rs 150

Step-by-step explanation:

hope it helps dear...........

Discussion

40.	(0,0) and (0,a) two points between distance ?
Answer» Step-by-step EXPLANATION: This is the explanation DEAR

40.

(0,0) and (0,a) two points between distance ?

Answer»

Step-by-step EXPLANATION:

This is the explanation DEAR

Discussion

41.	Cos theta/cot theta =
Answer» Answer: The reciprocal cosine function is secant: SEC(theta)=1/cos(theta). The reciprocal sine function is cosecant, csc(theta)=1/sin(theta). The reciprocal TANGENT function is cotangent, expressed TWO ways: cot(theta)=1/tan(theta) or cot(theta)=cos(theta)/sin(theta).

41.

Cos theta/cot theta =

Answer»

Answer:

The reciprocal cosine function is secant: SEC(theta)=1/cos(theta). The reciprocal sine function is cosecant, csc(theta)=1/sin(theta). The reciprocal TANGENT function is cotangent, expressed TWO ways: cot(theta)=1/tan(theta) or cot(theta)=cos(theta)/sin(theta).

Discussion

42.	Find the length of major axis minor axis length of latest rectum and eccentricity of following ellipse 9x^2 +4y^2=36
Answer» Solutions:- The GIVEN is the ellipse x²/36 + y²/16 = 1. Here, The denominator of x²/36 is greater than the denominator of y²/16 Therefore, the major axis is along the x - axis. the minor axis is along the y - axis. On comparing the given equation with x²/a² + y²/b² = 1 We obtain a = 6 and b = 4 => c = √a² - b² = √(6)² - (4)² = √36 - 16 = √20 = 2√5 Therefore, The coordinates of the fouc are (2√5, 0) and (-2√5, 0) The coordinates of the vertices are (6, 0) and (-6, 0). Length of majar axis => 2A = 2 × 6 = 12 Length of minor axis => 2B = 2 × 4 = 8 Eccentricity , e = c/a => 2√5/6 => √5/3 Length of Latus rectum => 2b²/a => 2 × 16/6 => 16/3 Hence, the coordinates of the fouc are (2√5, 0) and (-2√5, 0), The coordinates of the vertices are (6, 0) and (-6, 0). Length of majar axis = 12. Length of minor axis = 8, Eccentricity = √5/3, And Length of Latus rectum = 16/3.

42.

Find the length of major axis minor axis length of latest rectum and eccentricity of following ellipse 9x^2 +4y^2=36

Answer»

Solutions:-

The GIVEN is the ellipse x²/36 + y²/16 = 1.

Here,

The denominator of x²/36 is greater than the denominator of y²/16

Therefore,

the major axis is along the x - axis.

the minor axis is along the y - axis.

On comparing the given equation with x²/a² + y²/b² = 1

We obtain

a = 6 and b = 4

=> c = √a² - b²

= √(6)² - (4)²

= √36 - 16

= √20

= 2√5

Therefore,

The coordinates of the fouc are (2√5, 0) and (-2√5, 0)

The coordinates of the vertices are (6, 0) and (-6, 0).

Length of majar axis => 2A = 2 × 6 = 12

Length of minor axis => 2B = 2 × 4 = 8

Eccentricity , e = c/a

=> 2√5/6

=> √5/3

Length of Latus rectum => 2b²/a

=> 2 × 16/6

=> 16/3

Hence, the coordinates of the fouc are (2√5, 0) and (-2√5, 0), The coordinates of the vertices are (6, 0) and (-6, 0). Length of majar axis = 12. Length of minor axis = 8, Eccentricity = √5/3, And Length of Latus rectum = 16/3.

Discussion

43.	Thrice x added to y squared
Answer» Answer: (XII) Thrice X ADDED to y squared is (3×x)+(y×y)=3x+y2.

43.

Thrice x added to y squared

Answer»

Answer:

(XII) Thrice X ADDED to y squared is (3×x)+(y×y)=3x+y2.

Discussion

44.	Find multiplied and divided number for 200 to make aPerfectCube
Answer» ANSWER: The smallest number is 5 In ORDER to find the perfect cube, the exponent of 5 must be 3. Thus we multiply 200 by 5 Step-by-step explanation: have a GREAT day ahead

44.

Find multiplied and divided number for 200 to make aPerfectCube

Answer»

ANSWER:

The smallest number is 5

In ORDER to find the perfect cube, the exponent of 5 must be 3. Thus we multiply 200 by 5

Step-by-step explanation:

have a GREAT day ahead

Discussion

45.	kartik and pravin start cycling from some point A. kartik travels from east and pravin travels from north . after 1hour ,pravin covers 12km and kartik covers 5km.how far are they from each other
Answer» Answer: they are 13 KM FAR from eachother Step-by-step explanation: hope it HELPS

45.

kartik and pravin start cycling from some point A. kartik travels from east and pravin travels from north . after 1hour ,pravin covers 12km and kartik covers 5km.how far are they from each other

Answer»

Answer:

they are 13 KM FAR from eachother

Step-by-step explanation:

hope it HELPS

Discussion

46.	TanA =4/3 find the value of tan2A
Answer» ANSWER: SORRY i didn't KNOW PLZ SEE it

46.

TanA =4/3 find the value of tan2A

Answer»

ANSWER:

SORRY i didn't KNOW PLZ SEE it

Discussion

47.	Pair of equation x=5 y=5 is
Answer» Answer: (5,5) Step-by-step explanation: pair of EQUATIONS is (5,5) BCZ (x,y) = (5,5) ACCORDING to UR question

47.

Pair of equation x=5 y=5 is

Answer»

Answer:

(5,5)

Step-by-step explanation:

pair of EQUATIONS is (5,5) BCZ (x,y) = (5,5) ACCORDING to UR question

Discussion

48.	(root7+1) and (root 5+ root3)which one is grater
Answer» Step-by-step EXPLANATION: I HOPE it MAY HELP you .....

48.

(root7+1) and (root 5+ root3)which one is grater

Answer»

Step-by-step EXPLANATION:

I HOPE it MAY HELP you .....

Discussion

49.	7) If q tan Ap, then find the value of (p sin A - q cos A) / (p sin A+q cos A)
Answer» Step-by-step EXPLANATION: SOMEWHAT EASY U can do it

49.

7) If q tan Ap, then find the value of (p sin A - q cos A) / (p sin A+q cos A)

Answer»

Step-by-step EXPLANATION:

SOMEWHAT EASY

U can do it

Discussion

50.	4 किलोग्राम चाय का मूल्य 420 है तो 12 किलोग्राम का मूल्य कितना होगा
Answer» ANSWER: , PLEASE LIKE and FOLLOW me

50.

4 किलोग्राम चाय का मूल्य 420 है तो 12 किलोग्राम का मूल्य कितना होगा

Answer»

ANSWER:

, PLEASE LIKE and FOLLOW me

Discussion

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