Mr. Dubey borrows rs100000 from a bank at 10%p.a compound interest. wh

1.	Mr. Dubey borrows rs100000 from a bank at 10%p.a compound interest. what amount will he have to pay to the bank
Answer» COMPLETE Question : Mr. Dubey borrows Rs. 100000 from a bank at 10%p.a compound INTEREST. what amount will he have to pay to the bank after 3 years. ⠀ ⠀ ⠀ ━━━━━━━━━━━━━━━━⠀ ⠀ AnswEr : The amount he will pay to the bank after 3 years = Rs. 133100. ⠀ Explanation : We are given with the principal, rate and time, that is, Principal, P = Rs. 100000. ⠀ Rate of interest, R = 10% per annum. ⠀ Time, N = 3 years. ⠀ We have to find out the amount he will pay to the bank after 3 years. ⠀ As we are given with principal, rate and time we KNOW that, if we are given with the principal, rate and time, we have the required formula, that is, ⠀ ⠀ $\sf{:\implies A = P \bigg\lgroup 1 + \dfrac{R}{100} \bigg\rgroup ^n}$ ⠀ ⠀ Substituting the given VALUES in the formula : ⠀ $\sf{:\implies A = 100000 \bigg\lgroup 1 + \dfrac{1 \cancel0}{10 \cancel0} \bigg\rgroup ^3}$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup 1 + \dfrac{1}{10} \bigg\rgroup ^3}$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{10 + 1}{10} \bigg\rgroup ^3}$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{11}{10} \bigg\rgroup ^3}$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{ {11}^{3} }{ {10}^{3} } \bigg\rgroup }$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{1331}{ {10}^{3} } \bigg\rgroup }$ ⠀ $\sf{:\implies A = 100000 \bigg\lgroup \dfrac{1331}{1000} \bigg\rgroup }$ ⠀ $\sf{:\implies A = 100 \cancel{000 } \times \dfrac{1331}{1 \cancel{000}}}$ ⠀ $\sf{:\implies A = 100 \times 1331}$ ⠀ $\sf{:\implies \boxed{ \pink{ \frak{A = 133100}}}}$ ⠀ Hence, the amount he will pay to the bank after 3 years = Rs. 133100.

Mr. Dubey borrows rs100000 from a bank at 10%p.a compound interest. what amount will he have to pay to the bank

Answer»

COMPLETE Question :

Mr. Dubey borrows Rs. 100000 from a bank at 10%p.a compound INTEREST. what amount will he have to pay to the bank after 3 years.

⠀ ⠀ ⠀ ━━━━━━━━━━━━━━━━⠀

⠀

AnswEr :

The amount he will pay to the bank after 3 years = Rs. 133100.

⠀

Explanation :

We are given with the principal, rate and time, that is,

Principal, P = Rs. 100000.

⠀

Rate of interest, R = 10% per annum.

⠀

Time, N = 3 years.

⠀

We have to find out the amount he will pay to the bank after 3 years.

⠀

As we are given with principal, rate and time we KNOW that, if we are given with the principal, rate and time, we have the required formula, that is,

⠀

$\sf{:\implies A = P \bigg\lgroup 1 + \dfrac{R}{100} \bigg\rgroup ^n}$

⠀

Substituting the given VALUES in the formula :

⠀

$\sf{:\implies A = 100000 \bigg\lgroup 1 + \dfrac{1 \cancel0}{10 \cancel0} \bigg\rgroup ^3}$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup 1 + \dfrac{1}{10} \bigg\rgroup ^3}$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{10 + 1}{10} \bigg\rgroup ^3}$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{11}{10} \bigg\rgroup ^3}$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{ {11}^{3} }{ {10}^{3} } \bigg\rgroup }$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{1331}{ {10}^{3} } \bigg\rgroup }$

⠀

$\sf{:\implies A = 100000 \bigg\lgroup \dfrac{1331}{1000} \bigg\rgroup }$

⠀

$\sf{:\implies A = 100 \cancel{000 } \times \dfrac{1331}{1 \cancel{000}}}$

⠀

$\sf{:\implies A = 100 \times 1331}$

⠀

$\sf{:\implies \boxed{ \pink{ \frak{A = 133100}}}}$

⠀

Hence, the amount he will pay to the bank after 3 years = Rs. 133100.