Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Find p(2)for the polynomial p(x)=(x-1)(x+1)​

Answer»

<P>Answer:

p(2)= (2-1) (2+1)

p(2)= (1) (3)

p(2) = 3

hope it helps you

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2.

For what values of P are the roots of the equation 4x2+pX+3=0 real and equal ?8. Two tangents PA and PB are drawn to a circle with centre O such that OP=2AP, findLAOP​

Answer»

ANSWER:

SORRY but i don't KNOW the answer for this QUESTION.

3.

4A and B are two given matrices such that the order of A is 3x4, if A'B and B'A are both defined then​

Answer»

ANSWER:

‌‌‍

order if B is 4x3.✌️

4.

Find amount on 8000Rs @ 5%per annum for 3 years compounded yearly?​

Answer»

Answer:

PRINCIPAL for the first YEAR = Rs.8000, Rate = 5% per annum, T = 1 year

INTEREST for the first year = =100P×R×T=Rs.[1008000×5×1]=Rs.400

∴ Amount at the end of the first year = Rs. (8000 + 400) = Rs. 8400

Now principal for the second year = Rs.8400

 Interest for the second year = 100P×R×T=Rs.[1008400×5×1]=Rs.420

∴ Amount at the end of the second year = Rs. (8400 + 420) =Rs.8820

Interest for the third year = 100P×R×T=Rs.1008820×5×1=Rs.441

∴ Amount at the end of the third year = Rs.(8820 + 441) = Rs. 9261

Now we know that total C.I. = Amount - Principal = Rs. (9261 - 8000) = Rs. 1261 

we can also FIND the C.I. as follows

Total C.I. = Interest for the first year + Interest for the second year + Interest for third year = Rs. (400 + 420 + 441) = Rs.1261

Step-by-step explanation:

hope this helps mark me as brilliant

5.

Perimeter of a rhombus is 20cm find the length of its side.​

Answer»

6 CM.......... . . . . . .

6.

SECTION-ABABEFill in the blanks.a) The perimeter of a rectangle of length 14 cm and breadth, 6cm isbiof 24 balloonsballoonse) Ahas unlimited lines of symmetry,d) An eight-sided closed figure is calledey A rectangle made of 15 squares of side lem has areaA.2Match the followinga) 100 tens1 1 lakhb) 10 lakhsii) 100 lakhc) 1000 tensii) 1 ten lakhd) 100 thousandsIV) I thousandel crorev) I ten thousand​

Answer»

Answer:

24²+6²+9⁴=⁵²

perimeter of the SQUARE FIELD =20

7.

Why does the Alaskan Coast remain ice-free in winter?Plzz answer fastt..Its important... ​

Answer»

Answer:

In this way,warm currents along the coast make the COASTAL areas WARMER and cold currents make them cooler than usual. ... The PARTS of WESTERN Europe remains ICE free during winter.

8.

X2 + 4 x + 4 factorise ​

Answer»

x2+4+4

4(x+4)

4x+8

answer is this

Step-by-step EXPLANATION:

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9.

021)व्यायाम न करण्यात२)02शालदासयताबददल एक मात्रा निकामारोप कारीiDरखताची कामे स्वतः करणारा ।1)C C​

Answer»

Step-by-step EXPLANATION:

THANKS for FREE POINTS have been a long TIME

10.

CH4 +2O2 = CO2+2H2O IS THIS combination reaction ???​

Answer»

ANSWER:

No it is a DISPLACEMENT REACTION

11.

Simplify:(3x square+2x) (2x square+3)​

Answer»

Answer:

6x² + 9X + 4x³ + 6x

hope it HELPS you ✨✌

12.

5. If 2x, x + 10, 3x + 2 are in AP, find the value of x.​

Answer»

ANSWER:

x=6

Step-by-step EXPLANATION:

d=x+10-2x=10-x

d=3x+2-x-10=2x-8

10-x=2x-8

3x=18

x=6

13.

A whole is 15 m long and 10 m wide find the area of carpeting​

Answer»

Answer:

150 m×m

Step-by-step EXPLANATION:

area=l×b

area=15×10

area=150 m.sq

14.

Find the HCE using the primefactorisation method. Check it again bydivision methode.32,128,272​

Answer»

Answer:

2

Step-by-step EXPLANATION:

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15.

Plz plz help me frnds and give step by step explanation plz ​

Answer»

Answer:

1) (x + 3)(x - 4)

= x^2 - 4X + 3X - 12

= x^2 - x - 12

2)  x^3 - 3x^2 + 5

   degree of the above POLYNOMIAL is 3

16.

5. in diagonal matrix allmembers except the membersif principal diagonal are........​

Answer»

ANSWER:

MATRIX...............

HOPE this HELPS you

17.

What will be the area of a rectangle , made from 100 m wire ?​

Answer»

ANSWER:  100*5=500 m MIGHT be the AREA of rectangle

Step-by-step EXPLANATION:

18.

The pair of equation x=5,y=5 has

Answer»

ANSWER:

The pair of EQUATIONS x = 5 and y = 5 has. infinite SOLUTION...

19.

Find the area of the figure ​

Answer»

Question :- find the area of the figure

Answer :-

         your ans is 495 cm^2

constuction :-

                draw DC ⊥ AE .

∴ ABCD is a rectangle

∴ BC = AD

∴   AD = 25

∴   BD = 30-25=5 cm

therefore ,

               Area of ABCD

                        = 18* 25 cm^2

                        = 450 cm^2

AB = DC      [ as ABCD is a rectangle ]

so,

    DC = 18 cm

as,

      DCE is a Right angle Δ .

∴ Area of ΔDEC  

                = = \frac{1}{2} * DE * DC\\= \frac{1}{2} *5 *18\\= <klux>45</klux> cm^2

∴ Area of given figure is 45 + 450 = 495cm^2

our answer is 495cm^2.

thank you.

20.

COMPREHENSION : (Q. 1 to Q. 2)1Between two numbers whose sum is 26an even number of arithmatic means are inserted. If the sum of1these means exceeds their number by unity, then the number of means is t., then answer the followingquestions.1.The value of t is(A) 12(B)11(C) 15(D) 162.The third term of a G.P. is the square of the first term. If the second term is 8, then the 6th term is(in terms of t)(A) 10-8(B) 10t + 8(C) 8t + 10(D) 8t - 10​

Answer»

ANSWER:

nnvjcjgyfbgtgfnfubnufgggcbfdhbbkgdbfybbhfrsnrvntdhdhu

21.

Simplify 4a-7(5a-7) = 3(2a-1) + 7​

Answer»

Answer:

9the 492u2hwhsjwiwjsjsjsjjsjshshhshshshahhahahabhahahahahahhahahahahahhaqhqhhqhahqhahhahahaha

22.

1. In figure, PQRS is a quadrilateral and T and U are respectively points on PS and RS such that PQ =RO. 2PQT = ARQU and ZTOS = 2 UQS. Prove that QT = QU.b. Show that the quadrilateral, formed by joining the mid-points of the consecutive sides of a rectangleis a rhombus.2. show the quadrilateral formed by joining the mid points of the consecutive sides of rectangle in a rhombus ​

Answer»

ANSWER:

jjjjuiiijkkkikkkkkgftfdohdf

23.

(b) If the pth term of an A.P. is q and the qth term is p. prove that its nth term is (p+q-n) and (p+q)? (CBSE Delhi 2017)​

Answer»

Step-by-step EXPLANATION:

kjvpugibisotepy24udlgsitfafsitdoyclhxlgchlclhxmvzktzlgstixotsoue5xfkziyfoyclhdoufiydigckhcouhohsfjdtk

24.

A ladder 5m long is place against a wall . if its foot is 3 m away from the wall, how high up the wall does it reach? ​

Answer»

Answer:

4M because USING PYTHAGORAS THEOREM we GET 4m

25.

which graph would be best to represent quantitative data ? a) vertical bar chart b) pie chart c) histogram d) horizontal bar chart. pls give the answer for this mcq ​

Answer»

Answer:

OPTION C

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26.

The product of a and b added to their sum​

Answer»

ANSWER:

AB + (a +B)

Step-by-step EXPLANATION:

27.

What is difference between mass weight of an object​

Answer»

ANSWER:

The mass of an object is a MEASURE of the object's inertial property, or the amount of matter it contains. The WEIGHT of an object is a measure of the force exerted on the object by gravity, or the force needed to SUPPORT it.

28.

9 identical boxes weight 48 kg 852 g. What is the weight of 1 book​

Answer»

ANSWER:

5.428

Step-by-step EXPLANATION:

if 9 boxes is 48.852 the WEIGHT of one BOX is

48.852/9

so the answer is 5.428

29.

Whats lhs rhs in math

Answer»

Answer:

LHS = Left HAND SIDE

RHS = Right hand side

It is informal SHORTHAND for the left-hand side and right-hand side of an equation.

30.

40B10010.B1525एक सममीटरसमचतकिसीऔरऔर11.नि12.1.0.12 सेमी.13 सेमी.कीजिए।13.52.प्रश्नावली13.2एक समलम्ब चतुर्भुज PQRS के ZP और ZS20 सेमी.समकोण है। इसकी भुजाओं की माप चित्र मेंदर्शाई गई है, समलम्ब चतुर्भुज का क्षेत्रफल ज्ञात25 सेमी.एक समलम्ब चतुर्भुज ABCD में AB, CD कासमान्तर है AB = 30 सेमी., BC = 15 सेमी., DC = 44 सेमी., और AD = 13 सेमी.।समलम्ब चतुर्भुज का क्षेत्रफल ज्ञात कीजिए।किसी समलम्ब चतुर्भुज की समानान्तर भुजाएं 52 सेमी. और 27 सेमी. है तथा अन्य दोभुजाएं 25 सेमी. और 30 सेमी. की हैं। समलम्ब चतुर्भुज का क्षेत्रफल ज्ञात कीजिए।अमर3.गणित-3226​

Answer»

Answer:

PLEASE type the QUESTION CORRECTLY as NOTHING is understandable........

31.

Pls answer this....pls....its urgent.....don't spam ​

Answer»

ANSWER is

4) -3-3

5) 1

hope this will HELP you

32.

Amit drives a car daily to his office from his home. The distance is 24km. On a particular day, he left his home at 8 :15 AM, drove for 5km at a speed of 60kmph. After that he was stuck in a traffic jam of 1km during this stretch he could drive only at a speed of 15kmph.Which of these is the closest to the minimum speed at which he should drive after the traffic jam to ensure that he reaches the office by 8:45 AM? ( Assuming that he can drive the way he wants to, without any traffic jams)

Answer»

GIVEN:

Distance of office

case-1:

AMIT drove 5 km at 60 kmph

case-2:

He was struck in traffic of 1 km at a speed of 15 kmph

Solution:

We have Speed=\frac{Distance}{Time}

CASE-1:

speed=60×5/18  m/s = 50/3 m/s

distance=5000 m

so, \frac{50}{3} =\frac{5000}{time}

time=300 seconds = 5 minutes

So he travelled 5 km distance in 5 minutes i.e., by 8:20 AM

CASE-2:

speed=15×5/18 =25/6 m/s

distance = 1000m

so,  \frac{25}{6} =\frac{1000}{time}

time = 240 seconds = 4 minutes

So now by 8:24 AM he travelled a distance of 6 km

Now the distance to be travelled = (24-6)km = 18 km= 18000 m

And time left = 21 minutes = 1260 seconds

Now , Speed=\frac{18000}{1260}

         Speed = 14.28 m/s

         Speed = 14.28 × 18/5  kmph

         Speed = 51.42 kmph

Here after traffic JAM Amit has to drive with a minimum speed of 51.42 kmph

So 60kmph is CLOSEST to the minimum speed he should drive after the traffic jam.

33.

X + 2y, 3x+ 5y, 7x- 3y​

Answer»

Step-by-step explanation:

x + 2y + 3x + 5y + 7x - 3y

or = 11x - (7y - 3y)

or = 11x - 4y = 7(x + y)

or = 7 + 2 = 9

9 is ANSWER

34.

1. The radius of a circular grass land is 35 m. There is a foot-path of width 7 m.around in it. Find the area of the foot path​

Answer»

Answer:

1694m2

Step-by-step EXPLANATION:

GIVEN, r=35 m

Therefore, R=35+7=72 m

Area of CIRCULAR PATH =π(R+r)(R−r)

=  

7

22

​  

(42+35)(42−35)

=1694m  

2

PLS MARK AS BRAINLIEST

35.

angle of 120,60,45and 130 degrees please help me i am out of mind i am 5th class and first time with geometry ​

Answer»

ANSWER:

angle of 120,60,45and 130 degrees please help me i am out of mind i am 5th class and FIRST TIME with geometry

36.

क्या सभी घनत्व पूर्णांकों के वर्गमूल अपरिमेय होते हैं यदि नहीं तो एक ऐसी संख्या के वर्गमूल का उदाहरण दीजिए जो एक परिमेय संख्या है ​

Answer»

Can you imagine a world without merchants, where we are left to our own devices to acquire GOODS and services without middlemen? Sounds LIKE a harsh PLACE to be. The sale and trade of goods defines much of the development and HISTORY of the world.

Please mark me as Brainlist.

37.

In a triangle ABC, if AB=BC and LB-70°, what would be the value of LC?​

Answer»

Step-by-step EXPLANATION:

Since, AB = BC, therefore, ∠A=∠C

By angle sum PROPERTY of TRIANGLE,

∠A+∠B+∠C=180°

2∠A+70°=180°

∠A=55°

HENCE,∠A=∠C=55°

38.

The Factor of: 15ab-6a+5b-2 is __________​

Answer»

ANSWER:

12 ab

Step-by-step EXPLANATION:

I HOPE this answer will HELP you

39.

Find the trigonometric function of 45°​

Answer»

ANSWER:

angle α is equal to the RATIO of the opposite side(PERPENDICULAR)

Step-by-step EXPLANATION:

40.

Find the volume of cube if its edge is 10cm​

Answer»

Step-by-step EXPLANATION:

VOLUME = 10 ^3

= 10×10×10

=1000

41.

Р(d)11002 cm3 cm4 cm40°110°3 cm30°4 cm30°CR40°5 cmBFig. 12.12​

Answer»

ANSWER:

where

Step-by-step EXPLANATION:

is the FIGURE SHOW it FIRST

42.

In a given A.P., a = 8, Tn=38, Sn = 123. Find d and n.​

Answer»

ANSWER:

d=20 and N =124

Step-by-step EXPLANATION:

43.

How will you check if your solution is correct??????say me

Answer»

i will ASK to my TEACHER SIMPLE..............

44.

A²-1 উৎপাদকে বিশ্লেষণ​

Answer»

ANSWER:

can u PLEASE l

telll me the language NAME PLSSS my FRIEND

45.

If 20 is subtracted from 4 times a number, we get 20. find the number​

Answer»

PLEASE MARK me as BRANILIEST and FOLLOW me

...

.

.

....

..... .. .

46.

In the figure,Rp:PK=11:8,then​

Answer»

WHERE IS THE FIGURE FRIEND

47.

How many fives are there in 625 and 125?​

Answer»

Answer:

625 has 4 TIME 5

625=5×5×5×5

125=5×5×5.

48.

Maddy reads three-fifth of 75 pages of his lesson. How many more pages he need to read to complete the lesson?

Answer»

Answer:

30

Step-by-step EXPLANATION:

because 3/5×75 is 45 which is the NUMBER of PAGES he has read.Remaining number of pages is 75-45=30

49.

Indicate the quadrants in which the following points lie. (2)(a) (-4 , -10). (b). (1, 7/4) ​

Answer»

Answer:

1)3RD QUADRANT 2)1ST quadrant

Step-by-step EXPLANATION:

50.

Factorise x² + 4x + 4​

Answer»

Step-by-step EXPLANATION:

PLEASE MAKE me BRAINLIST