332354 + Interview Questions in Secondary School in Math

1.	To get an intrest on Rupees 280 per year ，how much money should be deposited.
Answer» Answer: 122.93 บาท Step-by-step explanation: 280 รูปีอินเดีย เท่ากับ 122.93 บาท

1.

To get an intrest on Rupees 280 per year ，how much money should be deposited.

Answer»

Answer:

122.93 บาท

Step-by-step explanation:

280 รูปีอินเดีย เท่ากับ

122.93 บาท

Discussion

2.	5. Hari Ram finished 25 days of his leave on 2 May. When did hestart his leave?
Answer» Answer: the answer is 6th feb Step-by-step explanation: 25 -2 =23 february has 29 DAY 29-23= 6

2.

5. Hari Ram finished 25 days of his leave on 2 May. When did hestart his leave?

Answer»

Answer:

the answer is 6th feb

Step-by-step explanation:

25 -2 =23

february has 29 DAY

29-23= 6

Discussion

3.	Find the sum of the following series to n terms 1+2x+3x^2+4x^3.........
Answer» THATS how far i GOT HOPE this HELPS somehow

Discussion

4.	17. In the given figure angleOAC = 30 and angleOBC = 40° then, findvalue of angleAOB
Answer» PLSS ATTACH the FIGURE.... :-)

4.

17. In the given figure angleOAC = 30 and angleOBC = 40° then, findvalue of angleAOB

Answer»

PLSS ATTACH the FIGURE....

:-)

Discussion

5.	Point B and C lie on tangent to the circle drawn at point A . Chord AD = Chord ED .If m (arc EPF) =1/2 m (arc AQD) and m (arc DRE) = 84 ; then determine. 1 ) DAC 2 ) FDA 3) FED 4 ) BAF
Answer» Point B and C lie on tangent to the circle drawn at point A . Chord AD = Chord ED . If m (arc EPF) =1/2 m (arc AQD) and m (arc DRE) = 84 ; then determine. 1 ) DAC 2 ) FDA 3) FED 4 ) BAF Construction: Join OD, OE, OA, OF, FD and AF. 1 ) DAC In △EOD and △AOD, we have: AO=EO (RADII of the circle) OD=OD (Common) ED=AD (Given) ∴△EOD ≅ △AOD (By SSS congruency) i.e., ∠DEO=∠DAO (CPCT) ALSO, ∠DOE=∠AOD=84° (CPCT, m(arcDRE) = 84°) Now, in△EOD, we have: ∠EOD+∠ODE+∠OED=180° (Angle sum property) ⇒2∠OED=180°−84° ⇒∠OED=48° Hence, ∠OED=∠DAO=48° ∠EAC=90° (Radius is PERPENDICULAR to tangent) ∠DAC=∠EAC−∠DAO=90°−48°=42° ∠EOF=12∠AOD=42° In △EOD and △AOD, we have: AO=EO (Radii of the circle) OD=OD (Common) ED=AD (Given) ∴△EOD ≅ △AOD (By SSS congruency) i.e., ∠DEO=∠DAO (CPCT) Also, ∠DOE=∠AOD=84° (CPCT, m(arcDRE) = 84°) Now, in△EOD, we have: ∠EOD+∠ODE+∠OED=180° (Angle sum property) ⇒2∠OED=180°-84° ⇒∠OED=48° Hence, ∠OED=∠DAO=48° ∠EAC=90° (Radius is perpendicular to tangent) ∠DAC=∠EAC-∠DAO=90°-48°=42° ∠EOF=12 ∠AOD=42° 2 ) FDA ∠EOF+∠EOD+∠DOA+∠AOF=360° (Complete angle) ⇒∠AOF=360°− ∠EOF−∠EOD−∠DOA ⇒∠AOF=360°−42°−84°−84°=150° ∠EOF+∠EOD+∠DOA+∠AOF=360° (Complete angle) ⇒∠AOF=360°- ∠EOF-∠EOD-∠DOA ⇒∠AOF=360°-42°-84°-84°=150° We know that the angle subtended by an arc at the CENTRE is twice the angle subtended at any part of the circle. i.e., ∠FDA=12∠AFO=75°∠FDA=12∠AFO=75° 3) FED In△EOF, we have: ∠EOF+∠FEO+∠EFO=180° (Angle sum property) ⇒2∠FEO=180°−42° ⇒∠FEO=69° So, ∠FED=∠OED+∠FEO=48°+69°=117° In△EOF, we have: ∠EOF+∠FEO+∠EFO=180° (Angle sum property) ⇒2∠FEO=180°-42° ⇒∠FEO=69° So, ∠FED=∠OED+∠FEO=48°+69°=117° 4 ) BAF In△AOF, we have: ∠AOF+∠FAO+∠OFA=180° (Angle sum property) ⇒2∠OAF=180°−150° ⇒∠OED=15° So, ∠OAB=90° (Radius is perpendicular to tangent)∴∠FAB=∠OAB−∠OAF=90°−15°=75°

5.

Point B and C lie on tangent to the circle drawn at point A . Chord AD = Chord ED .If m (arc EPF) =1/2 m (arc AQD) and m (arc DRE) = 84 ; then determine. 1 ) DAC 2 ) FDA 3) FED 4 ) BAF

Answer»

Point B and C lie on tangent to the circle drawn at point A . Chord AD = Chord ED .

If m (arc EPF) =1/2 m (arc AQD) and m (arc DRE) = 84 ; then determine.

1 ) DAC 2 ) FDA 3) FED 4 ) BAF

Construction: Join OD, OE, OA, OF, FD and AF.
1 ) DAC
In △EOD and △AOD, we have:
AO=EO (RADII of the circle)
OD=OD (Common)
ED=AD (Given)
∴△EOD ≅ △AOD (By SSS congruency)
i.e., ∠DEO=∠DAO (CPCT)
ALSO, ∠DOE=∠AOD=84° (CPCT, m(arcDRE) = 84°)
Now, in△EOD, we have:
∠EOD+∠ODE+∠OED=180° (Angle sum property)
⇒2∠OED=180°−84°
⇒∠OED=48°
Hence, ∠OED=∠DAO=48°
∠EAC=90° (Radius is PERPENDICULAR to tangent)
∠DAC=∠EAC−∠DAO=90°−48°=42°
∠EOF=12∠AOD=42°
In △EOD and △AOD, we have:
AO=EO (Radii of the circle)
OD=OD (Common)
ED=AD (Given)
∴△EOD ≅ △AOD (By SSS congruency)
i.e., ∠DEO=∠DAO (CPCT)
Also, ∠DOE=∠AOD=84° (CPCT, m(arcDRE) = 84°)
Now, in△EOD, we have:
∠EOD+∠ODE+∠OED=180° (Angle sum property)
⇒2∠OED=180°-84°
⇒∠OED=48°
Hence, ∠OED=∠DAO=48°
∠EAC=90° (Radius is perpendicular to tangent)
∠DAC=∠EAC-∠DAO=90°-48°=42°
∠EOF=12
∠AOD=42°
2 ) FDA
∠EOF+∠EOD+∠DOA+∠AOF=360° (Complete angle)
⇒∠AOF=360°− ∠EOF−∠EOD−∠DOA
⇒∠AOF=360°−42°−84°−84°=150°
∠EOF+∠EOD+∠DOA+∠AOF=360° (Complete angle)
⇒∠AOF=360°- ∠EOF-∠EOD-∠DOA
⇒∠AOF=360°-42°-84°-84°=150°
We know that the angle subtended by an arc at the CENTRE is twice the angle subtended at any part of the circle.
i.e., ∠FDA=12∠AFO=75°∠FDA=12∠AFO=75°
3) FED
In△EOF, we have:
∠EOF+∠FEO+∠EFO=180° (Angle sum property)
⇒2∠FEO=180°−42°
⇒∠FEO=69°
So, ∠FED=∠OED+∠FEO=48°+69°=117°
In△EOF, we have:
∠EOF+∠FEO+∠EFO=180° (Angle sum property)
⇒2∠FEO=180°-42°
⇒∠FEO=69°
So, ∠FED=∠OED+∠FEO=48°+69°=117°
4 ) BAF
In△AOF, we have:
∠AOF+∠FAO+∠OFA=180° (Angle sum property)
⇒2∠OAF=180°−150°
⇒∠OED=15°
So, ∠OAB=90° (Radius is perpendicular to tangent)∴∠FAB=∠OAB−∠OAF=90°−15°=75°

Discussion

6.	Find the sum of the following series to n terms 1+2x+3x^2+4^3.........
Answer» 3x^2 + 2X + 4^3 + 1 3x^2 + 2x + 65

6.

Find the sum of the following series to n terms 1+2x+3x^2+4^3.........

Answer»

3x^2 + 2X + 4^3 + 1

3x^2 + 2x + 65

Discussion

7.	The value of 2.6 -0.9 is
Answer» ANSWER: 1.7 Step-by-step explanation: 2.6-0.9 = 1.7 Please MARK this as BRAINLIEST..and FOLLOW me

7.

The value of 2.6 -0.9 is

Answer»

ANSWER:

1.7

Step-by-step explanation:

2.6-0.9

= 1.7

Please MARK this as BRAINLIEST..and FOLLOW me

Discussion

8.	Integration one upon 2 + cos x minus sin x into DX
Answer» Step-by-step EXPLANATION: kitna simple SA question he yar

8.

Integration one upon 2 + cos x minus sin x into DX

Answer»

Step-by-step EXPLANATION:

kitna simple SA question he yar

Discussion

9.	If 4x-3y-2z = 0 and 2x + 5y-3z = 0 then what is the value of x: y: z
Answer» Answer: Step-by-step explanation: 0=0 4x-3y-2z = 2x+5y-3z 2x-8y+z =0 2x+z = 8y -----(1) 2(4x-3y-2z) -4(2x+5y-3z)=0 =>8X -6y -4z -8x -20y +12z=0 =>8z -26y=0 8z = 26y 4z = 13y z =13y/4 -------(2) PUTTING value of z (2) in eq (1) 2x +13y/4 = 8y 2x = 32y -13y /4 2x = 19y/4 x = 19y/8 ---------(3) Puttinf value of xyz in 4x-3y-2z = 0 19y/2 - 3y - 13y/2 = 0 19y -6y -13y =0 First set of values is x=y=z=0

9.

If 4x-3y-2z = 0 and 2x + 5y-3z = 0 then what is the value of x: y: z

Answer»

Answer:

Step-by-step explanation:

0=0

4x-3y-2z = 2x+5y-3z

2x-8y+z =0

2x+z = 8y -----(1)

2(4x-3y-2z) -4(2x+5y-3z)=0

=>8X -6y -4z -8x -20y +12z=0

=>8z -26y=0

8z = 26y

4z = 13y

z =13y/4 -------(2)

PUTTING value of z (2) in eq (1)

2x +13y/4 = 8y

2x = 32y -13y /4

2x = 19y/4

x = 19y/8 ---------(3)

Puttinf value of xyz in

4x-3y-2z = 0

19y/2 - 3y - 13y/2 = 0

19y -6y -13y =0

First set of values is

x=y=z=0

Discussion

10.	A toy car is sold at a gain of 16% has it been sold for ₹ 100 more the gain would have been 20% find the cp of the toy car
Answer» CP let 100% GAIN = 16% means SP = 116% if 100₹more then gain = 20% means 120% i.e, 116% +100= 120% or 4% = 100₹ if 4% = 100₹ then 100% = (100/4)×100 = 2500₹

10.

A toy car is sold at a gain of 16% has it been sold for ₹ 100 more the gain would have been 20% find the cp of the toy car

Answer»

CP let 100%

GAIN = 16% means SP = 116%

if 100₹more then gain = 20% means 120%

i.e, 116% +100= 120% or 4% = 100₹

if 4% = 100₹ then 100% = (100/4)×100 = 2500₹

Discussion

11.	two circle touch internally at point P chord ab of the larger circle intersect the smaller circle in C prove that angle CPA is congruent to angle DPB
Answer» ANSWER: *HEYAA* ♥♥ *Here* is *the* *answer. HOPE* it *HELPED* *you*.

11.

two circle touch internally at point P chord ab of the larger circle intersect the smaller circle in C prove that angle CPA is congruent to angle DPB

Answer»

ANSWER:

HEYAA ♥♥

Here is the answer.

HOPE it HELPED you.

Discussion

12.	What fraction of an hour is 4 minutes?Give your answer in its simplest form.
Answer» Answer: 1hr/15 mins=60 mins/15 mins=4 MINUTES.

12.

What fraction of an hour is 4 minutes?Give your answer in its simplest form.

Answer»

Answer:

1hr/15 mins=60 mins/15 mins=4 MINUTES.

Discussion

13.	A rectangle has the same area as another,whose length om more and breadth is 4m lessIt has also the same area as the thirdwhose length is in more and breadth is smless find the length and breadth ofthe orgonal triangle
Answer» ANSWER: SORRY I don't KNOW the answer..

13.

A rectangle has the same area as another,whose length om more and breadth is 4m lessIt has also the same area as the thirdwhose length is in more and breadth is smless find the length and breadth ofthe orgonal triangle

Answer»

ANSWER:

SORRY I don't KNOW the answer..

Discussion

14.	The annual rate of growth in population of a town is 10% it is present population is 33,275 what was 3 years ago
Answer» Step-by-step EXPLANATION: POPULATION 3 YEARS= 33275(1 +10/100)^3 =33275 (11/10)^3 =44289.025

14.

The annual rate of growth in population of a town is 10% it is present population is 33,275 what was 3 years ago

Answer»

Step-by-step EXPLANATION:

POPULATION 3 YEARS= 33275*(1 +10/100)^3

=33275 *(11/10)^3

=44289.025

Discussion

15.	63248644874?given options are. A. 13. B. 42• C. 18• D. 30
Answer» Step-by-step explanation: Be concentrated on first and last member. 6x2 = 12 12x3 =36 36-12= 24 8x2= 16 16x4= 64 64-16= 48 In same manner : 72= 14 144= 56 56*14 = 42 I HOPE this may help you please mark me as a brainliest

15.

63248644874?given options are. A. 13. B. 42• C. 18• D. 30

Answer»

Step-by-step explanation:

Be concentrated on first and last member.

6x2 = 12 12x3 =36 36-12= 24

8x2= 16 16x4= 64 64-16= 48

In same manner :

7*2= 14 14*4= 56 56*14 = 42

I HOPE this may help you

please mark me as a brainliest

Discussion

16.	Simplify 3/7^6×7/3^4×1/7^-2
Answer» 3 1/3 ÷ 5/3 - 1/10 of 2 ½ + 7/4 = (3 × 3 + 1)/3 ÷ 5/3 – 1/10 of (2 × 2 + 1)/2 + 7/4 = 10/3 ÷ 5/3 - 1/10 of 5/2 + 7/4 [‘of’ SIMPLIFIED] = 10/3 × 3/5 – ½ × ½ + 7/4 [‘÷’ simplified] = 2/1 - ¼ + 7/4 [‘×’ simplified] = (2 × 4)/1 × 4) - (1 × 1)/4 × 1) + (7 × 1)/4 × 1) = 8/4 - ¼ + 7/4 [Now the denominators are same of all the FRACTIONS] = (8 – 1 + 7)/4 [‘+’ and ‘-‘ simplified] = 14/4 = 7/2

Discussion

17.	18^5×(5^2)^-4×(3^-4)^2 simplify
Answer» Answer: 3² × 2⁵ ÷ 5⁸ Step-by-step EXPLANATION: SOLUTION is in the ATTACHMENT

17.

18^5×(5^2)^-4×(3^-4)^2 simplify

Answer»

Answer:

3² × 2⁵ ÷ 5⁸

Step-by-step EXPLANATION:

SOLUTION is in the ATTACHMENT

Discussion

18.	radhika sells a washing machine for ₹8800 at a loss of 20% what was the price at which she bought it
Answer» REFER to the ATTACHED IMAGE

18.

radhika sells a washing machine for ₹8800 at a loss of 20% what was the price at which she bought it

Answer»

REFER to the ATTACHED IMAGE

Discussion

19.	Mrs.gupta walks her dogs twice everyday down to end of the street. it is 15 minutes to go to up and down the street. how many minutes does she spend walking her dog in four weeks.
Answer» Answer: 840 Step-by-step explanation: as she take 15minutes to go up and down . she do this TWICE a day so in 1 day she spend 30 minutes so in 1 week =30×7 =210 minutes and in 4week=4 ×210 =840 minutes

19.

Mrs.gupta walks her dogs twice everyday down to end of the street. it is 15 minutes to go to up and down the street. how many minutes does she spend walking her dog in four weeks.

Answer»

Answer:

840

Step-by-step explanation:

as she take 15minutes to go up and down .

she do this TWICE a day

so in 1 day she spend 30 minutes

so in 1 week =30×7

=210 minutes

and in 4week=4 ×210

=840 minutes

Discussion

20.	Two baskets Contain 77 and 121 fruits. These are to bePacked in different baskets Containing Equal no.find the greatest no. that can be packed in eachbasket?
Answer» Step-by-step EXPLANATION: the GREATEST NUMBER will be 11

20.

Two baskets Contain 77 and 121 fruits. These are to bePacked in different baskets Containing Equal no.find the greatest no. that can be packed in eachbasket?

Answer»

Step-by-step EXPLANATION:

the GREATEST NUMBER will be 11

Discussion

21.	The false statement among the following is(A) Set of Real numbers is not finite (B) Set of Whole numbers is not infinite (C) Set of Natural numbers is infinite (D) Set of Integers is not finite
Answer» ANSWER: B is the FALSE STATEMENT

21.

The false statement among the following is(A) Set of Real numbers is not finite (B) Set of Whole numbers is not infinite (C) Set of Natural numbers is infinite (D) Set of Integers is not finite

Answer»

ANSWER:

B is the FALSE STATEMENT

Discussion

22.	Solve the differential equation dy/dx=x2y+y
Answer» We're given to solve the DIFFERENTIAL equation, $\longrightarrow\dfrac{dy}{dx}=x^2y+y$ or, $\longrightarrow\dfrac{dy}{dx}=\left(x^2+1\right)y$ $\longrightarrow\dfrac{1}{y}\,dy=\left(x^2+1\right)\ dx$ Integrating, $\displaystyle\longrightarrow\int\dfrac{1}{y}\,dy=\int\left(x^2+1\right)\ dx$ $\displaystyle\longrightarrow\log\|y\|-\log\|<klux>C</klux>\|=\dfrac{x^3}{3}+x$ $\displaystyle\longrightarrow\log\left\|\dfrac{y}{C}\right\|=\dfrac{x^3}{3}+x$ TAKING antilog, $\displaystyle\longrightarrow\dfrac{y}{C}=e^{\frac{x^3}{3}+x}$ $\displaystyle\longrightarrow\underline{\underline{y=Ce^{\frac{x^3}{3}+x}}}$ This is the SOLUTION to the differential equation, where C is an arbitrary CONSTANT.

22.

Solve the differential equation dy/dx=x2y+y

Answer»

We're given to solve the DIFFERENTIAL equation,

$\longrightarrow\dfrac{dy}{dx}=x^2y+y$

or,

$\longrightarrow\dfrac{dy}{dx}=\left(x^2+1\right)y$

$\longrightarrow\dfrac{1}{y}\,dy=\left(x^2+1\right)\ dx$

Integrating,

$\displaystyle\longrightarrow\int\dfrac{1}{y}\,dy=\int\left(x^2+1\right)\ dx$

$\displaystyle\longrightarrow\log|y|-\log|<klux>C</klux>|=\dfrac{x^3}{3}+x$

$\displaystyle\longrightarrow\log\left|\dfrac{y}{C}\right|=\dfrac{x^3}{3}+x$

TAKING antilog,

$\displaystyle\longrightarrow\dfrac{y}{C}=e^{\frac{x^3}{3}+x}$

$\displaystyle\longrightarrow\underline{\underline{y=Ce^{\frac{x^3}{3}+x}}}$

This is the SOLUTION to the differential equation, where C is an arbitrary CONSTANT.

Discussion

23.	The length and breadth of a rectangular Sheet are16cm and 12cm resp. A square of max. Size is to becut without wasting the sheet. What will be the sideof a such a square
Answer» area of rectengular sheet =16×12 =192 Step-by-step explanation: Length of a rectangular sheet = 16cm BREADTH of a rectangular sheet = 12 cm *Area of rectangular sheet = length breadth = 16 * 12 = 192 cm We KNOW that in a square all sides are EQUAL. In the given rectangular sheet, length < breadth Therefore maximum length of square can be equal to the length of the rectangular sheet. So Square of maximum SIZE having side 12 cm can be cut WITHOUT wasting the sheet.**

23.

The length and breadth of a rectangular Sheet are16cm and 12cm resp. A square of max. Size is to becut without wasting the sheet. What will be the sideof a such a square

Answer»

area of rectengular sheet =16×12

=192

Step-by-step explanation:

Length of a rectangular sheet = 16cm

BREADTH of a rectangular sheet = 12 cm

Area of rectangular sheet = length * breadth = 16 * 12 = 192 cm

We KNOW that in a square all sides are EQUAL.

In the given rectangular sheet, length < breadth

Therefore maximum length of square can be equal to the length of the rectangular sheet.

So Square of maximum SIZE having side 12 cm can be cut WITHOUT wasting the sheet.

Discussion

24.	Compound interest on 6250 at 8% p.a for 1 year compounded half yearly
Answer» Step-by-step explanation: PRINCIPAL = 6250 rate = 8% TIME = 1 YEAR

24.

Compound interest on 6250 at 8% p.a for 1 year compounded half yearly

Answer»

Step-by-step explanation:

PRINCIPAL = 6250

rate = 8%

TIME = 1 YEAR

Discussion

25.	15% of 45% of a number is 105.3 .What is 24% of that number
Answer» Answer: 374.4 Step-by-step EXPLANATION: Let NUMBER be "y" according to Qn, 15 x 45 x y / 10000 = 105.3 675y = 1053000 y = 1560 Then 24% of y 24y/100 = 24x1560/100 = 374.4

25.

15% of 45% of a number is 105.3 .What is 24% of that number

Answer»

Answer: 374.4

Step-by-step EXPLANATION:

Let NUMBER be "y"

according to Qn,

15 x 45 x y / 10000 = 105.3

675y = 1053000

y = 1560

Then 24% of y

24y/100 = 24x1560/100

= 374.4

Discussion

26.	Oder of constant is
Answer» Step-by-step EXPLANATION: B C d F ...,............

26.

Oder of constant is

Answer»

Step-by-step EXPLANATION:

B C d F ...,............

Discussion

27.	At a birthday function chocotates were distributed as 6 or 12 or 15 chocolates to each person.What is the least no.of choolates required?
Answer» The LEAST NUMBER of CHOCOLATES REQUIRED is 6

Discussion

28.	An open challenge. The person who will answer it will gain a follower
Answer» Answer: Please refer to the picture The FINAL answer n=0 Hope this HELPS. Please follow me and MARK me as the BRAINLIEST answer.

28.

An open challenge. The person who will answer it will gain a follower

Answer»

Answer:

Please refer to the picture

The FINAL answer n=0

Hope this HELPS.

Please follow me and MARK me as the BRAINLIEST answer.

Discussion

29.	For a manufacturer A, the list price of an article is rupees 9000, which he sales to dealer B at a some discounted price . Further, the dealer B sales the same article to the customer at it's list price. If the rate of the GST is 18% and dealer B paid the SGST rupees 160 , find the amount ( including GST)paid by dealer B
Answer» Answer: RS 8522.22 For B, SGST payable will be Output SGST- INPUT SGST. OUTPUT SGST= 9% of 9000 (as B is SELLING at list PRICE) let the price at which B buys = x Therefore, INPUT SGST= 9% of x Hence, 9%of 9000 - 9% of x= 160 On solving, we get x= Rs 7222.22 Therefore, amount payable by B is 7222.22+ 18% of 7222.22 = 7222.22+ 1300= Rs 8522.22 Hope this helps.

29.

For a manufacturer A, the list price of an article is rupees 9000, which he sales to dealer B at a some discounted price . Further, the dealer B sales the same article to the customer at it's list price. If the rate of the GST is 18% and dealer B paid the SGST rupees 160 , find the amount ( including GST)paid by dealer B

Answer»

Answer: RS 8522.22

For B, SGST payable will be Output SGST- INPUT SGST.

OUTPUT SGST= 9% of 9000 (as B is SELLING at list PRICE)

let the price at which B buys = x

Therefore, INPUT SGST= 9% of x

Hence, 9%of 9000 - 9% of x= 160

On solving, we get x= Rs 7222.22

Therefore, amount payable by B is 7222.22+ 18% of 7222.22 =

7222.22+ 1300=

Rs 8522.22

Hope this helps.

Discussion

30.	Using small cubes if enlarged it by changing the length the width and the height by a scale factor of 3 , how many cubes were in the enlarged object
Answer» ANSWER: SOLUTION is in the ATTACHMENT

30.

Using small cubes if enlarged it by changing the length the width and the height by a scale factor of 3 , how many cubes were in the enlarged object

Answer»

ANSWER:

SOLUTION is in the ATTACHMENT

Discussion

31.	\| b = = 0,E (UTUI)35 x 105 x 25b)Simplify:57 x 654P.T.O.
Answer» Answer: 1+2+3+4+5+6+7+8+9+10=54

31.

| b = = 0,E (UTUI)35 x 105 x 25b)Simplify:57 x 654P.T.O.

Answer»

Answer:

1+2+3+4+5+6+7+8+9+10=54

Discussion

32.	Compound interest on 10000 at 12% p.a for 1.5 years
Answer» Solution: Amount with CI = 10000 [1+ (12/2 * 100)]2 = Rs. 11236 Therefore, CI = 11236 – 10000 = Rs. 1236 I HOPE this may HELP you PLEASE mark as brainliest

32.

Compound interest on 10000 at 12% p.a for 1.5 years

Answer»

Solution:

Amount with CI = 10000 [1+ (12/2 * 100)]2 = Rs. 11236

Therefore, CI = 11236 – 10000 = Rs. 1236

I HOPE this may HELP you

PLEASE mark as brainliest

Discussion

33.	A box contains 28 bulbs of which 7 bulbs are defective , a bulb is drawn randomly from the box.find the probability of picking a non-defective bulb.
Answer» ANSWER: Step-by-step EXPLANATION:

33.

A box contains 28 bulbs of which 7 bulbs are defective , a bulb is drawn randomly from the box.find the probability of picking a non-defective bulb.

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

34.	meenakshi is making a quilt from square pieces of cloth. she fits 10 pieces along one side and 15 pieces along the other. how many pieces does she need?
Answer» ANSWER: your answer :- 150 piece mark me as the BEST

34.

meenakshi is making a quilt from square pieces of cloth. she fits 10 pieces along one side and 15 pieces along the other. how many pieces does she need?

Answer»

ANSWER:

your answer :- 150 piece

mark me as the BEST

Discussion

35.	To find X,y,z it's also given ab\|\|cd and ef is the transversal
Answer» Answer: 65+25+z=180 z=90 30+y=180-(25+90) y=65-30 y=35 x=180-(90+35) x=55

35.

To find X,y,z it's also given ab||cd and ef is the transversal

Answer»

Answer:

65+25+z=180

z=90

30+y=180-(25+90)

y=65-30

y=35

x=180-(90+35)

x=55

Discussion

36.	in a month of August last year lot of people lost their homes in Kerala due to floods and touch 1 lakh people had shifted to 988 relief camp there are sufficient food for 1 lakh people for 60 days after 30 days 40 thousand people leave the camp then find how many days will the rest of food last for the rest of people
Answer» SINCE the food was sufficient for the 1 lakh people for 60 days, the 1 lakh people have consumed 50% of the food for the FIRST 30 days. But given that the camp was remained with 60 thousand people after 30 days. Mathematically saying, if the no. of people for consuming food is CONSTANT, then the amount of food is directly proportional to the time taken for consumption. if the amount of food is constant, the no. of people consuming the food is inversely proportional to the no. of days or time required for the consumption. No. of days required for 1 lakh people to consume 100% of food = 60 days Amount of food consumed by the 1 lakh people in first 30 days = 50% of the total amount. ALSO, no. of days required for 1 lakh people to consume the remaining 50% of food = 30 days. No. of days required for 1 person to consume 50% of food = 30 × 1 lakh = 30 lakh days Then, no. of days required for the remaining 60 thousand people to consume 50% of food = 30 lakh / 60 thousand = 50 days. $\quad$

36.

in a month of August last year lot of people lost their homes in Kerala due to floods and touch 1 lakh people had shifted to 988 relief camp there are sufficient food for 1 lakh people for 60 days after 30 days 40 thousand people leave the camp then find how many days will the rest of food last for the rest of people

Answer»

SINCE the food was sufficient for the 1 lakh people for 60 days, the 1 lakh people have consumed 50% of the food for the FIRST 30 days. But given that the camp was remained with 60 thousand people after 30 days.

Mathematically saying,

if the no. of people for consuming food is CONSTANT, then the amount of food is directly proportional to the time taken for consumption.

if the amount of food is constant, the no. of people consuming the food is inversely proportional to the no. of days or time required for the consumption.

No. of days required for 1 lakh people to consume 100% of food = 60 days

Amount of food consumed by the 1 lakh people in first 30 days = 50% of the total amount.

ALSO, no. of days required for 1 lakh people to consume the remaining 50% of food = 30 days.

No. of days required for 1 person to consume 50% of food = 30 × 1 lakh = 30 lakh days

Then, no. of days required for the remaining 60 thousand people to consume 50% of food = 30 lakh / 60 thousand = 50 days. $\quad$

Discussion

37.	Plz ans this question it is urgent
Answer» Step-by-step EXPLANATION: your ANSWER attached in the photo please CHECK your qsn.

37.

Plz ans this question it is urgent

Answer»

Step-by-step EXPLANATION:

your ANSWER attached in the photo

please CHECK your qsn.

Discussion

38.	26. Arun lent 25,000 to Balaji for 2 years and 3,000 to Charles for 4 years on simple interest atthe same rate of interest and received 2,200 in all from both of them as interest. Find therate of interest per year.
Answer» Answer: 89u iv8f KF I J g p Step-by-step explanation: kfkg7 JRU ksy ..m.m.

38.

26. Arun lent 25,000 to Balaji for 2 years and 3,000 to Charles for 4 years on simple interest atthe same rate of interest and received 2,200 in all from both of them as interest. Find therate of interest per year.

Answer»

Answer:

89u iv8f KF I J g p

Step-by-step explanation:

kfkg7 JRU ksy ..m.m.

Discussion

39.	Saranshofthipoeminhindi
Answer» Answer: heya mate..PLZZ CLARIFY UR que✌

39.

Saranshofthipoeminhindi

Answer»

Answer:

heya mate..PLZZ CLARIFY UR que✌

Discussion

40.	@it is given that APOR ANYZ. I 20 = (-5) and 2Y = 550, and the value of a
Answer» Answer: SORRY Sis yet not in this class Sorry please ARRANGE it from somewhere else please Step-by-step EXPLANATION: Please follow me

40.

@it is given that APOR ANYZ. I 20 = (-5) and 2Y = 550, and the value of a

Answer»

Answer:

SORRY Sis yet not in this class

Sorry please ARRANGE it from somewhere else please

Step-by-step EXPLANATION:

Please follow me

Discussion

41.	What is the score dividing the entirr frequency distribution in two equal called?
Answer» ANSWER: CLASS mark mark me as the BEST

41.

What is the score dividing the entirr frequency distribution in two equal called?

Answer»

ANSWER:

CLASS mark

mark me as the BEST

Discussion

42.	Tan2A/(secA-1)^2=1+cosA/1-cosA
Answer» 1 + cos A/ 1 - cos A = tan²A/(SECA - 1)² LHS = (1 + cos A)/ (1 - cos A) RHS = tan²A/(secA - 1)² = [TANA/(sec-1)]^2 = [tanA/((1/cosA)-1)]^2 = [tanA/(1-cosA)/cosA]^2 = [(tanAcosA)/(1-cosA)]^2 = [sinA/(1-cosA)]^2 = sinA^2/(1-cosA)^2 = (1-cosA^2)/(1-cosA)^2 = [(1-cosA)(1+cosA)]/[(1-cosA)*(1-cosA)] = (1+cosA)/(1-cosA) LHS = RHS

42.

Tan2A/(secA-1)^2=1+cosA/1-cosA

Answer»

1 + cos A/ 1 - cos A = tan²A/(SECA - 1)²

LHS = (1 + cos A)/ (1 - cos A)

RHS = tan²A/(secA - 1)²

= [TANA/(sec-1)]^2

= [tanA/((1/cosA)-1)]^2

= [tanA/(1-cosA)/cosA]^2

= [(tanA*cosA)/(1-cosA)]^2

= [sinA/(1-cosA)]^2

= sinA^2/(1-cosA)^2

= (1-cosA^2)/(1-cosA)^2

= [(1-cosA)*(1+cosA)]/[(1-cosA)*(1-cosA)]

= (1+cosA)/(1-cosA)

LHS = RHS

Discussion

43.	If root 2304=48 and root 1764=42 then find the value of root 0.2304+root 0.1764÷root 0.2304-root0.1764
Answer» ANSWER: Step-by-step explanation: 0.2304+root 0.1764=0.9 root 0.2304-root0.1764=0.06 0.9/0.06=15 Please MARK BRAINLIEST

43.

If root 2304=48 and root 1764=42 then find the value of root 0.2304+root 0.1764÷root 0.2304-root0.1764

Answer»

ANSWER:

Step-by-step explanation:

0.2304+root 0.1764=0.9

root 0.2304-root0.1764=0.06

0.9/0.06=15

Please MARK BRAINLIEST

Discussion

44.	Amit opened a recurring deposit account for 10 months. The rate of interest is 8%per annum and Amit receives Rs. 221 as interest at the time of maturity. Find theamount Amit deposited each month.
Answer» Answer: Rs. 603 Step-by-step explanation : Given, n = 10 months r = 8% p.a. I = Rs. 221 To FIND, PRINCIPAL AMOUNT (P) Solution, $I = \frac{P * n(n+1) * r}{2 * 12 * 100}$ $221 = \frac{P * 10 * 11 * 8}{2 * 12 * 100}$ $P = \frac{221 * 2 * 12 * 100}{10 * 11 * 8}$ $P = Rs. 602.72$ THEREFORE, P = Rs. 603

44.

Amit opened a recurring deposit account for 10 months. The rate of interest is 8%per annum and Amit receives Rs. 221 as interest at the time of maturity. Find theamount Amit deposited each month.

Answer»

Answer:

Rs. 603

Step-by-step explanation :

Given,

n = 10 months

r = 8% p.a.

I = Rs. 221

To FIND,

PRINCIPAL AMOUNT (P)

Solution,

$I = \frac{P * n(n+1) * r}{2 * 12 * 100}$

$221 = \frac{P * 10 * 11 * 8}{2 * 12 * 100}$

$P = \frac{221 * 2 * 12 * 100}{10 * 11 * 8}$

$P = Rs. 602.72$

THEREFORE,

P = Rs. 603

Discussion

45.	Sec 0 -tan 0sec 0 + tan 0cos²0(1 + sin o)?
Answer» Answer: HEY.....plz ask YR question clearly..... Step-by-step explanation: I can't UNDERSTAND yr question.....

45.

Sec 0 -tan 0sec 0 + tan 0cos²0(1 + sin o)?

Answer»

Answer:

HEY.....plz ask YR question clearly.....

Step-by-step explanation:

I can't UNDERSTAND yr question.....

Discussion

46.	(3) Yash scored 40 marks in a test, getting3 marks for each right answer and losing1 mark for each wrong answer. Had4 marks been awarded for each correctanswer and 2 marks been deducted foreach incorrect answer, then Yash wouldhave scored 50 marks. How manyquestions were there in the test?
Answer» Number of Questions in the test are 20 Step-by-step explanation: let the number of right ANSWERS = x let the number of wrong answers = y We can FORM two EQUATIONS, 3x - y = 40 ...(1) 4x - 2y =50...(2) Solving the two equations, multiply 1. by 2 we get, 6x - 2y = 80 subtract 2. from 1. (6x-2y=40) - (4x-2y=50) thus, x = 15 substitute the value of x in either1 1. or 2. y=5 thus total questions (x+y) = 20

46.

(3) Yash scored 40 marks in a test, getting3 marks for each right answer and losing1 mark for each wrong answer. Had4 marks been awarded for each correctanswer and 2 marks been deducted foreach incorrect answer, then Yash wouldhave scored 50 marks. How manyquestions were there in the test?

Answer»

Number of Questions in the test are 20

Step-by-step explanation:

let the number of right ANSWERS = x

let the number of wrong answers = y

We can FORM two EQUATIONS,

3x - y = 40 ...(1)

4x - 2y =50...(2)

Solving the two equations,

multiply 1. by 2

we get, 6x - 2y = 80

subtract 2. from 1.

(6x-2y=40) - (4x-2y=50)

thus, x = 15

substitute the value of x in either1 1. or 2.

y=5

thus total questions (x+y) = 20

Discussion

47.	The solution of the equation x minus 1 equal to 2 if value of x is 2 what is the answer
Answer» ANSWER: From the question we can write x-1=2 Step-by-step EXPLANATION: GIVEN, The value of x=2 So, putting the value of x in the given EQUATION, we get x-1=2 2-1=2 1=2 1-2=0 -1=0

47.

The solution of the equation x minus 1 equal to 2 if value of x is 2 what is the answer

Answer»

ANSWER:

From the question we can write x-1=2

Step-by-step EXPLANATION:

GIVEN, The value of x=2

So, putting the value of x in the given EQUATION, we get

x-1=2

2-1=2

1=2

1-2=0

-1=0

Discussion

48.	1Areas of square and rhombus are equal. A diagonal of rhombus is two times of its otherdiagonal. lf area of rhombus is 64 sq.cm. Find ratio of perimeters of square and rhombus.
Answer» Answer: 1:√5 Step-by-step EXPLANATION: DIAGONALS of rhombus are 8, 16cm. It's side is 8√5 CM. P of rhombus is 32√5 P of square is 32cm So ratio is 1:√5

48.

1Areas of square and rhombus are equal. A diagonal of rhombus is two times of its otherdiagonal. lf area of rhombus is 64 sq.cm. Find ratio of perimeters of square and rhombus.

Answer»

Answer: 1:√5

Step-by-step EXPLANATION: DIAGONALS of rhombus are 8, 16cm. It's side is 8√5 CM.

P of rhombus is 32√5

P of square is 32cm

So ratio is 1:√5

Discussion

49.	find the common tangent of the circles is Xsquare + Y square + 4 x + 2 Y + 4 = 0 and X square + Y square - 4 x - 2 Y + 4 = 0
Answer» ANSWER: XRatioY is answer of this QUESTION

49.

find the common tangent of the circles is Xsquare + Y square + 4 x + 2 Y + 4 = 0 and X square + Y square - 4 x - 2 Y + 4 = 0

Answer»

ANSWER:

XRatioY is answer of this QUESTION

Discussion

50.	Write all trigonometric ratios and their formula?
Answer» HII there here is your answer SIN(x+2πn) = sin x. cos(x+2πn) = cos x. TAN(x+πn) = tan x. cot(x+πn) = cot x. sec(x+2πn) = sec x. csc(x+2πn) = csc x. HOPE IT HELPED U PLZ MARK AS BRIANLIEST

50.

Write all trigonometric ratios and their formula?

Answer»

HII there

here is your answer

SIN(x+2πn) = sin x.
cos(x+2πn) = cos x.
TAN(x+πn) = tan x.
cot(x+πn) = cot x.
sec(x+2πn) = sec x.
csc(x+2πn) = csc x.

HOPE IT HELPED U

PLZ MARK AS BRIANLIEST

Discussion

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