332354 + Interview Questions in Secondary School in Math

1.	This is long division of Algebra
Answer» Answer: 6x³y²z²/3x²yz 3x²yz) 6x³y²z²(2XYZ 6x³y²z² _ =0

1.

This is long division of Algebra

Answer»

Answer:

6x³y²z²/3x²yz

3x²yz) 6x³y²z²(2XYZ

6x³y²z²

_

=0

Discussion

2.	In the given figure, ABCD is a rectangle with length (pq-5) and breadth (q + 4p).Find the area of shaded triangle PAB.
Answer» Attach the PICTURE of the figure so we can KNOW what the SHADED REGION EXACTLY looks like.

Discussion

3.	2 of the length of an auc of a sector is 20cm andif its radius is fom find the area of a sector.
Answer» Answer: 39w9299299282737367484940474y749300273646

3.

2 of the length of an auc of a sector is 20cm andif its radius is fom find the area of a sector.

Answer»

Answer:

39w9299299282737367484940474y749300273646

Discussion

4.	Which pen is best for exam*(I know that pen doesn't matter but presentation matters )
Answer» hyy mate ✌️ you have to use only BLUE pen.....XD!!! make sure that Ball blue is ALSO compulsory to FILL OMR sheet... you can take trimax. royal blue Hauser.....etc... HOPE it will help you ❣️❣️ please mark as brainliest.....

4.

Which pen is best for exam*(I know that pen doesn't matter but presentation matters )

Answer»

hyy mate ✌️

you have to use only BLUE pen.....XD!!!

make sure that Ball blue is ALSO compulsory to FILL OMR sheet...

you can take trimax.

royal blue

Hauser.....etc...

HOPE it will help you ❣️❣️

please mark as brainliest.....

Discussion

5.	Write the number in international place value system.....1.four million six hundred forty thousand
Answer» Answer: FOUR million SIX hundred forty thousand is : 4,640,000 Hope it helps you. And if it does PLEASE MARK as BRAINLIEST.

5.

Write the number in international place value system.....1.four million six hundred forty thousand

Answer»

Answer:

FOUR million SIX hundred forty thousand is :

4,640,000

Hope it helps you. And if it does PLEASE MARK as BRAINLIEST.

Discussion

6.	Wa tangent segment of length 12 cm to the circle with centre 0 and radius 2 cmpassing through the point P which lies in the exterior of the circle.
Answer» Answer: tangent segment of length √12 cm RADIUS = 2 cm Distance of point p from CENTER = √ ((√12)² + 2²) = √(12 + 4) = √16 = 4 Cos θ= 2/4 = 1/2 => θ = 60° Step 1 : Draw a circle with radius = 2 cm USING COMPASS taking o as center Step 2 : Draw a Line OP of length = 4 cm Step 3 : Draw an angle of 60 ° at O on OP and intersect circle at A Step 4 : Join PA PA is tangent to circle of length = √12 cm

6.

Wa tangent segment of length 12 cm to the circle with centre 0 and radius 2 cmpassing through the point P which lies in the exterior of the circle.

Answer»

Answer:

tangent segment of length √12 cm

RADIUS = 2 cm

Distance of point p from CENTER = √ ((√12)² + 2²)

= √(12 + 4)

= √16

= 4

Cos θ= 2/4 = 1/2

=> θ = 60°

Step 1 : Draw a circle with radius = 2 cm USING COMPASS taking o as center

Step 2 : Draw a Line OP of length = 4 cm

Step 3 : Draw an angle of 60 ° at O on OP and intersect circle at A

Step 4 : Join PA

PA is tangent to circle of length = √12 cm

Discussion

7.	Please explain it question for me
Answer» HOPE it HELPS ✌️ ✌️✌️✌️

7.

Please explain it question for me

Answer»

HOPE it HELPS ✌️ ✌️✌️✌️

Discussion

8.	3. The cost of 3 metres of cloth is 168. Find the cost of 17 metres of the cloth.
Answer» Step-by-step explanation: COST of 3 meter cloth = 168 RUPEES cost of 1 meter cloth = 56 rupees So , Cost of 17 meter cloth = 56*17 = 952 rupees

8.

3. The cost of 3 metres of cloth is 168. Find the cost of 17 metres of the cloth.

Answer»

Step-by-step explanation:

COST of 3 meter cloth = 168 RUPEES

cost of 1 meter cloth = 56 rupees

So , Cost of 17 meter cloth = 56*17 = 952 rupees

Discussion

9.	Cost of p11. In the adjoining Athe adjoining figure, ABCD is a square of sidecm. Find the area of the shaded region.Take 1 =
Answer» ANSWER: can you GIVE the DIAGRAM PLEASE

9.

Cost of p11. In the adjoining Athe adjoining figure, ABCD is a square of sidecm. Find the area of the shaded region.Take 1 =

Answer»

ANSWER:

can you GIVE the DIAGRAM PLEASE

Discussion

10.	6. A well with 10m inside diameter is dug 8.4m deep. Earthtaken out of it is spread all around it to a width of 7.5m toform an embankment. find the height of the embankment. 4
Answer» ANSWER: such a EASY QUESTION cannot SOLVE this from EXAMPLE

10.

6. A well with 10m inside diameter is dug 8.4m deep. Earthtaken out of it is spread all around it to a width of 7.5m toform an embankment. find the height of the embankment. 4

Answer»

ANSWER:

such a EASY QUESTION cannot SOLVE this from EXAMPLE

Discussion

11.	I)In a circle with centre 'o', seg AB is a diameter. Point M is in the exterior of thecircle. Which type of angle is ZAMB? Draw the figure & write proof to justify youranswer.
Answer» GIVEN Centre of the CIRCLE is 'O' and segment AB is a diameter . Point M is an exterior point of the Circle. Join A and B to M . AM intersecting circle at point C . Join B to C . <ACB = 90° ( Angle in semicircle ). ∆BCM is a right angled triangle . Now, <AMB < 90° . Therefore., <AMB is an acute angle . •••♪

11.

I)In a circle with centre 'o', seg AB is a diameter. Point M is in the exterior of thecircle. Which type of angle is ZAMB? Draw the figure & write proof to justify youranswer.

Answer»

GIVEN Centre of the CIRCLE is 'O' and segment AB is a diameter .

Point M is an exterior point of the Circle.

Join A and B to M .

AM intersecting circle at point C . Join B to C .

<ACB = 90° ( Angle in semicircle ).

∆BCM is a right angled triangle .

Now, <AMB < 90° .

Therefore.,

<AMB is an acute angle .

•••♪

Discussion

12.	(C) Mandeep has a Recurring Deposit Account in a bank. She deposits 800 per month and gets 15198maturity value. If the rate of interest is 7% p.a., find the total time for which the account washeld.
Answer» on solving that EQUATION u may GET the answer hope it HELPS you ☺️☺️

12.

(C) Mandeep has a Recurring Deposit Account in a bank. She deposits 800 per month and gets 15198maturity value. If the rate of interest is 7% p.a., find the total time for which the account washeld.

Answer»

on solving that EQUATION u may GET the answer

hope it HELPS you ☺️☺️

Discussion

13.	How to solve this some
Answer» Answer: factrise it MAN or WOMEN so EASY peasy lemon SQUEAKY

13.

How to solve this some

Answer»

Answer:

factrise it MAN or WOMEN so EASY peasy lemon SQUEAKY

Discussion

14.	Volume of cuboid measuring 4m , 2.5m , 35 cm
Answer» Answer: Volume of cuboid = length × BREADTH × height. Here, length = 14 cm, breadth = 12 cm and height = 8 cm. Volume of cuboid = 14 × 12 × 8 CUBIC cm. = 1344 cubic cm.

14.

Volume of cuboid measuring 4m , 2.5m , 35 cm

Answer»

Answer:

Volume of cuboid = length × BREADTH × height. Here, length = 14 cm, breadth = 12 cm and height = 8 cm. Volume of cuboid = 14 × 12 × 8 CUBIC cm. = 1344 cubic cm.

Discussion

15.	Please solve fast it's urgent.
Answer» *Hey mate* *here* is *your* *answer*: LET the point at a distance of 4 cm be PO Given: PA=8 cm and PO=4 cm, <POA=90°[Line joining centre of circle to a chord are perpendicular BISECTOR] APPLY PYTHAGORAS THEOREM: $(8) {}^{2} = (4) {}^{2} + ao$ $= = > 64 - 16 = (ao) {}^{2}$ $ao = \sqrt{48}$ $ao = 4 \sqrt{3cm}$ Now, area of SEMI circle**= $\frac{1}{2} \times \pi \times r {}^{2}$ $\frac{1}{2} \times 3.14 \times (4 \sqrt{3} ) {}^{2} = area$ $area = 75cm^2$

15.

Please solve fast it's urgent.

Answer»

Hey mate here is your answer:

LET the point at a distance of 4 cm be PO

Given:

PA=8 cm and PO=4 cm,

<POA=90°[Line joining centre of circle to a chord are perpendicular BISECTOR]

APPLY PYTHAGORAS THEOREM:

$(8) {}^{2} = (4) {}^{2} + ao$

$= = > 64 - 16 = (ao) {}^{2}$

$ao = \sqrt{48}$

$ao = 4 \sqrt{3cm}$

Now, area of SEMI circle=

$\frac{1}{2} \times \pi \times r {}^{2}$

$\frac{1}{2} \times 3.14 \times (4 \sqrt{3} ) {}^{2} = area$

$area = 75cm^2$

Discussion

16.	Find FGH in from the figure
Answer» Step-by-step EXPLANATION: :⟹4×34y−7y=−50 : \implies \sf \dfrac{16Y}{3}-7y = -50:⟹316y−7y=−50 : \implies \sf \dfrac{16y-21y}{3}=-50:⟹316y−21y=−50 : \implies \sf 16y-21y = -50 \TIMES 3:⟹16y−21y=−50×3 : \implies \sf -5y = -150:⟹−5y=−150 : \implies \bf y = 30:⟹y=30

16.

Find FGH in from the figure

Answer»

Step-by-step EXPLANATION:

:⟹4×34y−7y=−50

: \implies \sf \dfrac{16Y}{3}-7y = -50:⟹316y−7y=−50

: \implies \sf \dfrac{16y-21y}{3}=-50:⟹316y−21y=−50

: \implies \sf 16y-21y = -50 \TIMES 3:⟹16y−21y=−50×3

: \implies \sf -5y = -150:⟹−5y=−150

: \implies \bf y = 30:⟹y=30

Discussion

17.	Sin 45 degree+cos 45 degree is
Answer» 1/√2 + 1/√2 = 1 + 1 /√2 = 2/√2 = √2

Discussion

18.	Anyone pls...do solve it...pls....
Answer» Answer: 5.33 or 5 1/3 Step-by-step EXPLANATION: the SOLUTION is GIVEN in the PICTURE

18.

Anyone pls...do solve it...pls....

Answer»

Answer:

5.33 or 5 1/3

Step-by-step EXPLANATION:

the SOLUTION is GIVEN in the PICTURE

Discussion

19.	Find the value of 't' in equation 10 t-square+ 25t=100
Answer» Step-by-step EXPLANATION: 25T = 100 t = 100/25 t = 4 mar as BRANLIST

19.

Find the value of 't' in equation 10 t-square+ 25t=100

Answer»

Step-by-step EXPLANATION:

25T = 100

t = 100/25

t = 4

mar as BRANLIST

Discussion

20.	Sin 45 degree+cos 45degree is
Answer»

Discussion

21.	2 upon 3 n how come here?
Answer» ANSWER: it is WRONG anwser there is a MISTAKE in it

21.

2 upon 3 n how come here?

Answer»

ANSWER:

it is WRONG anwser

there is a MISTAKE in it

Discussion

22.	What is the value of cos180°
Answer» ANSWER: svahsvsd DBSBS s shaken w NJ was as SWEET hi asvsj

22.

What is the value of cos180°

Answer»

ANSWER:

svahsvsd DBSBS s shaken w NJ was as SWEET hi asvsj

Discussion

23.	If a:b=2:3 and b:c=4:5 then find a:b:c. Explain please
Answer» Answer: 8:12:15 Step-by-step explanation: By TAKING LCM of 3 and 4 as B we GET b = 12

23.

If a:b=2:3 and b:c=4:5 then find a:b:c. Explain please

Answer»

Answer:

8:12:15

Step-by-step explanation:

By TAKING LCM of 3 and 4 as B we GET b = 12

Discussion

24.	Solve for x, up to 2 decimal place :
Answer» hope this HELPS U... mark it as BRAINLIEST and PLZ follow me...

Discussion

25.	A man invests Rs. 3200 in shares of a company which is paying 5% dividend. If Rs.200 shares are available at a discount of 20%. Find: [3](i) Number of shares he purchases.(ii) His annual income.
Answer» Answer: investment=3200 d%=5% NV=200 discount=20% ans MV=200(1-20/100) MV=160 i) N= investment/MV n=3200/160 n=20 ii) D or ANNUAL income = d%/100 NV *n D= 200

25.

A man invests Rs. 3200 in shares of a company which is paying 5% dividend. If Rs.200 shares are available at a discount of 20%. Find: [3](i) Number of shares he purchases.(ii) His annual income.

Answer»

Answer:

investment=3200

d%=5%

NV=200

discount=20%

ans

MV=200*(1-20/100)

MV=160

i) N= investment/MV

n=3200/160

n=20

ii) D or ANNUAL income = d%/100 * NV *n

D= 200

Discussion

26.	Square root of 420 is?
Answer» Answer: 20.4939015319 Step-by-step EXPLANATION: It does not have a PERFECT SQUARE root... pls MARK me as the brainlist... also pls FOLLOW me....✌️

26.

Square root of 420 is?

Answer»

Answer:

20.4939015319

Step-by-step EXPLANATION:

It does not have a PERFECT SQUARE root...

pls MARK me as the brainlist...

also pls FOLLOW me....✌️

Discussion

27.	Un call weeuIU WILLto fill 750 litres of oil?. The ratio of income to the saving of a famısaving is 780.Check whether 20, 18, 3, 4 are in proportion-3. Find the value of x if 36:45::: 15.Find the value of x if x : 92:: 87: 116.6. Find the value of x if 27:*::X:3.In a fort, 550 men had food provisions for 2long for 700 men?7. A tea merchant mixes two variety of tea co
Answer» ANSWER: I can't UNDERSTAND your QUESTION

27.

Un call weeuIU WILLto fill 750 litres of oil?. The ratio of income to the saving of a famısaving is 780.Check whether 20, 18, 3, 4 are in proportion-3. Find the value of x if 36:45::: 15.Find the value of x if x : 92:: 87: 116.6. Find the value of x if 27:*::X:3.In a fort, 550 men had food provisions for 2long for 700 men?7. A tea merchant mixes two variety of tea co

Answer»

ANSWER:

I can't UNDERSTAND your QUESTION

Discussion

28.	Find FGH in this figure please
Answer» ANSWER: not CLEAR PICTURE SORRY FRIEND

28.

Find FGH in this figure please

Answer»

ANSWER:

not CLEAR PICTURE SORRY FRIEND

Discussion

29.	Find the first term and common difference for each of the A.P.- 1.25, - 1.50,- 1.75, -2, ...
Answer» ANSWER: Pls mark as brainliest Step-by-step explanation: First TERM = a = -1.25. Common DIFFERENCE = d = a2-a1 = -1.50-(-1.25) = -1.50+1.25 = -0.25

29.

Find the first term and common difference for each of the A.P.- 1.25, - 1.50,- 1.75, -2, ...

Answer»

ANSWER:

Pls mark as brainliest

Step-by-step explanation:

First TERM = a = -1.25.

Common DIFFERENCE = d =

a2-a1 = -1.50-(-1.25)

= -1.50+1.25

= -0.25

Discussion

30.	Factorise 1). X + 3 - 6 Y - 18
Answer» Step-by-step EXPLANATION: $x + 3 - 6y - 18 = 0 \\ x - 6y - 18 + 3 = 0 \\ x - 6y - 15 = 0$

30.

Factorise 1). X + 3 - 6 Y - 18

Answer»

Step-by-step EXPLANATION:

$x + 3 - 6y - 18 = 0 \\ x - 6y - 18 + 3 = 0 \\ x - 6y - 15 = 0$

Discussion

31.	Pls. Help and solve thisGiven that a=2i-3j+k, b=4i+j-3k and c=-i+j-3kFind(i) (a.b)c(ii) a.(b x c) (i.e., calculate the scalar triple product)(iii) a x (bc) (i.e., calculate the vector triple product)
Answer» ANSWER: ashskdpcgmpdnskdvfmpv

31.

Pls. Help and solve thisGiven that a=2i-3j+k, b=4i+j-3k and c=-i+j-3kFind(i) (a.b)c(ii) a.(b x c) (i.e., calculate the scalar triple product)(iii) a x (bc) (i.e., calculate the vector triple product)

Answer»

ANSWER:

ashskdpcgmpdnskdvfmpv

Discussion

32.	(d) 3698Find the smallest four digit number which is a perfect squale. -Find the smallest number by which the given number must be multiplied to make it a perfect square. 3,698
Answer» ANSWER: SMALLEST FOUR DIGIT no. is 1000

32.

(d) 3698Find the smallest four digit number which is a perfect squale. -Find the smallest number by which the given number must be multiplied to make it a perfect square. 3,698

Answer»

ANSWER:

SMALLEST FOUR DIGIT no. is 1000

Discussion

33.	Q.3B) Solve the following questions(any-2)1) Solve the quadratic equation 5x²+13+80 = 0 by using formula
Answer» Step-by-step EXPLANATION: ANSWER I HOPE it will HELP you

33.

Q.3B) Solve the following questions(any-2)1) Solve the quadratic equation 5x²+13+80 = 0 by using formula

Answer»

Step-by-step EXPLANATION:

ANSWER

I HOPE it will HELP you

Discussion

34.	The sum of areas of two squares is 468m²If the difference of their perimeter is 24cm.find the sides of two square ..
Answer» Answer: Sides of two squares are 18 & 12 Step-by-step explanation: Let sides of two squares be X & y given sum of areas of two squares = 468 => x^2+y^2 = 468 Difference of. their perimeters = 24cm => 4x-4y = 24 => x-y = 24/4 => x-y = 6...............(1) we know that (x-y)^2 = x^2+y^2-2XY => (6)^2 = 468-2xy => 36 = 468-2xy => 2xy = 468-36 => 2xy = 432 => XY = 216 Let (x+y)^2 = x^2+y^2+2xy = 468+(2×216) = 468+432 = 900 x+y = (900)^(1/2) x+y = 30..............(2) ADD (1) & (2) (x-y)+(x+y) = 6+30 2x = 36 x = 36/2 = 18 from (2) 18+y = 30 y = 30-18 = 12 .·. Sides of two squares are 18 & 12

34.

The sum of areas of two squares is 468m²If the difference of their perimeter is 24cm.find the sides of two square ..

Answer»

Answer:

Sides of two squares are 18 & 12

Step-by-step explanation:

Let sides of two squares be X & y

given sum of areas of two squares = 468

=> x^2+y^2 = 468

Difference of. their perimeters = 24cm

=> 4x-4y = 24 => x-y = 24/4

=> x-y = 6...............(1)

we know that (x-y)^2 = x^2+y^2-2XY

=> (6)^2 = 468-2xy

=> 36 = 468-2xy

=> 2xy = 468-36

=> 2xy = 432

=> XY = 216

Let (x+y)^2 = x^2+y^2+2xy

= 468+(2×216)

= 468+432

= 900

x+y = (900)^(1/2)

x+y = 30..............(2)

ADD (1) & (2)

(x-y)+(x+y) = 6+30

2x = 36

x = 36/2 = 18

from (2)

18+y = 30

y = 30-18 = 12

.·. Sides of two squares are 18 & 12

Discussion

35.	Relation of x and y x∝1 / y ^ 2. If x = 5 is y = 2, then x = 20, then what will be the value of y.
Answer» ANSWER: ±1 Step-by-step EXPLANATION:

35.

Relation of x and y x∝1 / y ^ 2. If x = 5 is y = 2, then x = 20, then what will be the value of y.

Answer»

ANSWER:

±1

Step-by-step EXPLANATION:

Discussion

36.	A is a dealer in Meerut (U.P.). He supplies goods/services, worth Rs. 15,000 to a dealer Bin Ratlam (M.P.). Dealer B, in turn, supplies the same goods/services to dealer C in Jabalpur(M.P.) at a profit of Rs. 3000. If rate of tax (under GST system) is 18%, find1. The cost of goods/services to the dealer C in Jabalpur.ii. Net tax payable by dealer B.
Answer» 21240 Rs is The cost of goods/services to the dealer C in Jabalpur , Net tax payable by dealer B = Rs 540 Step-by-step EXPLANATION: A is a dealer in Meerut (U.P.). He supplies goods/services, worth Rs. 15,000 to a dealer B in Ratlam (M.P.) Selling price WITHOUT GST = 15000 18% IGST = (18/100) 15000 = Rs 2700 Cost INCLUDING GST = 15000 + 2700 = 17700 Dealer B, SALES at a profit of Rs. 3000 Selling price without GST = 15000 + 3000 = Rs 18000 CGST = SGST = (9/100) * 18000 = 1620 Rs Cost to Dealer = 18000 + 1620 + 1620 = 21240 Rs Net tax payable by dealer B = 1620 + 1620 - 2700 = 540 Rs Learn more: a toy is purchased at rs. 1320 including 5%SGST and 5% CGST. the ... brainly.in/question/7977637 The printed price of an article is 40000. A wholesaler in Uttar ... brainly.in/question/13600745

36.

A is a dealer in Meerut (U.P.). He supplies goods/services, worth Rs. 15,000 to a dealer Bin Ratlam (M.P.). Dealer B, in turn, supplies the same goods/services to dealer C in Jabalpur(M.P.) at a profit of Rs. 3000. If rate of tax (under GST system) is 18%, find1. The cost of goods/services to the dealer C in Jabalpur.ii. Net tax payable by dealer B.

Answer»

21240 Rs is The cost of goods/services to the dealer C in Jabalpur , Net tax payable by dealer B = Rs 540

Step-by-step EXPLANATION:

A is a dealer in Meerut (U.P.). He supplies goods/services, worth Rs. 15,000 to a dealer B in Ratlam (M.P.)

Selling price WITHOUT GST = 15000

18% IGST = (18/100) 15000 = Rs 2700

Cost INCLUDING GST = 15000 + 2700 = 17700

Dealer B, SALES at a profit of Rs. 3000

Selling price without GST = 15000 + 3000 = Rs 18000

CGST = SGST = (9/100) * 18000 = 1620 Rs

Cost to Dealer = 18000 + 1620 + 1620

= 21240 Rs

Net tax payable by dealer B = 1620 + 1620 - 2700

= 540 Rs

Learn more:

a toy is purchased at rs. 1320 including 5%SGST and 5% CGST. the ...

brainly.in/question/7977637

The printed price of an article is 40000. A wholesaler in Uttar ...

brainly.in/question/13600745

Discussion

37.	Mr. pankaj took Health insurance policy for his family and paid $ 900 as SGST. find the total annual premium paid by him for this policy, rate of GST being 18 percent.
Answer» ANSWER: This is the answer to the QUESTION

37.

Mr. pankaj took Health insurance policy for his family and paid $ 900 as SGST. find the total annual premium paid by him for this policy, rate of GST being 18 percent.

Answer»

ANSWER:

This is the answer to the QUESTION

Discussion

38.	Hari has 11/2L of milk he uses 4/5 of the total milk and gives 1/3 of the remaining to his friend. how much milk was he left with?answer is 22/30 please solve i don't know the method
Answer» Answer: Answer is 2/30 not 22/30. Step-by-step explanation: Firstly hari has=11/2L MILK Milk he used= 4/5L so, 11/24/5=22/5 (4 cancelled by 2) so, hari used 4/5 of TOTAL milk. so, remaining milk= 11/2-22/5=1/10 milk is remaining. then, 1/3 of remaining he gaves to his FRIEND. so, 1/101/3=1/30 1/30 is used by his friend. so the remaining milk will be, 1/10-1/30=2/30 here's your answer... THANK you

38.

Hari has 11/2L of milk he uses 4/5 of the total milk and gives 1/3 of the remaining to his friend. how much milk was he left with?answer is 22/30 please solve i don't know the method

Answer»

Answer:

Answer is 2/30 not 22/30.

Step-by-step explanation:

Firstly hari has=11/2L MILK

Milk he used= 4/5L

so,

11/2*4/5=22/5 (4 cancelled by 2)

so, hari used 4/5 of TOTAL milk.

so, remaining milk= 11/2-22/5=1/10 milk is remaining.

then, 1/3 of remaining he gaves to his FRIEND.

so,

1/10*1/3=1/30

1/30 is used by his friend.

so the remaining milk will be,

1/10-1/30=2/30

here's your answer...

THANK you

Discussion

39.	PL help me to find out ❤️❤️
Answer» Step-by-step EXPLANATION: ANSWER SHI HAI KYA

39.

PL help me to find out ❤️❤️

Answer»

Step-by-step EXPLANATION:

ANSWER SHI HAI KYA

Discussion

40.	(sinA-cosA+1)/(sinA+cosA-1)=(cosA)/(1-sinA)someone prove it...i will mark u as a brainliest
Answer» ANSWER: The answer is GIVEN in the above pictures. Step-by-step EXPLANATION: IMPORTANT : sin²Q+cos²Q = 1

40.

(sinA-cosA+1)/(sinA+cosA-1)=(cosA)/(1-sinA)someone prove it...i will mark u as a brainliest

Answer»

ANSWER:

The answer is GIVEN in the above pictures.

Step-by-step EXPLANATION:

IMPORTANT : sin²Q+cos²Q = 1

Discussion

41.	if the dimensions of a cuboid are 1cm 2cm and 3cm respectively and the dimensions are increased three times .what will be the new volume?
Answer» Step-by-step explanation: given, dimensions LENGTH= 1cm breadth= 2cm height =3cm volume= lbh = 1x2x3= 6cm3 if the dimensions are increased 3 times i. E. lbhx3 now new volume = ? l=1cmx3= 3cm b=2cmx3=6cm h=3cmx3=9cm new volume =lbh =3x6x9=162cm3

41.

if the dimensions of a cuboid are 1cm 2cm and 3cm respectively and the dimensions are increased three times .what will be the new volume?

Answer»

Step-by-step explanation:

given,

dimensions

LENGTH= 1cm

breadth= 2cm

height =3cm

volume= lbh

= 1x2x3= 6cm3

if the dimensions are increased 3 times

i. E. lbhx3

now new volume = ?

l=1cmx3= 3cm

b=2cmx3=6cm

h=3cmx3=9cm

new volume =lbh

=3x6x9=162cm3

Discussion

42.	7. Find the integral w.r.t. x of the following by thesubstitution rule:(1) e423x +14x-62-3x+775+23200*(azz.ba)S.
Answer» Step-by-step EXPLANATION: *All* *ANSWERS* *are* *RIGHT* *THANK* *you*

42.

7. Find the integral w.r.t. x of the following by thesubstitution rule:(1) e423x +14x-62-3x+775+23200*(azz.ba)S.

Answer»

Step-by-step EXPLANATION:

All ANSWERS are RIGHT

THANK you

Discussion

43.	IF THE CP OF A FRIDGE IS rupees 300.if the shopkeeper takes profit%40.what is the SP??YR. GAME BEGANS NOWW!!!HAHA
Answer» Answer: 40÷100×300 120 this can HELP you

43.

IF THE CP OF A FRIDGE IS rupees 300.if the shopkeeper takes profit%40.what is the SP??YR. GAME BEGANS NOWW!!!HAHA

Answer»

Answer:

40÷100×300

120

this can HELP you

Discussion

44.	Sin4θ+cosθ=0 solve for θ
Answer» ANSWER: Step-by-step EXPLANATION: QUESTION is WRONG

44.

Sin4θ+cosθ=0 solve for θ

Answer»

ANSWER:

Step-by-step EXPLANATION:

QUESTION is WRONG

Discussion

45.	If p+q+r =0 ,Prove that [{1/(1+p+q-¹)}+{1/(1+q+r-¹)}+{1/(1+r+p-¹)}]=1.
Answer» ANSWER: eurrugjxjjfgikKodjc Step-by-step EXPLANATION: fhjfkgljg

45.

If p+q+r =0 ,Prove that [{1/(1+p+q-¹)}+{1/(1+q+r-¹)}+{1/(1+r+p-¹)}]=1.

Answer»

ANSWER:

eurrugjxjjfgikKodjc

Step-by-step EXPLANATION:

fhjfkgljg

Discussion

46.	If sin alpha =½ and cos beta =½ then alpha +beta =
Answer» SIN alpha = 1/2 = Sin 30 degree Therefore , alpha = 30 And, Cos BETA = 1/2 = Cos 60 degree Therefore, beta = 60 Hence, alpha + beta = 30 + 60 = 90

Discussion

47.	???? ii)find y in equation??????????????
Answer» Step-by-step explanation: 3(2p-1) = 5-(3p-2) 6p-1=5-3p+2 6p-1-5+3p-2=0 6p+3p-5-1-2=0 9p-8=0 9p=8 p=8/9

47.

???? ii)find y in equation??????????????

Answer»

Step-by-step explanation:

3(2p-1) = 5-(3p-2)

6p-1=5-3p+2

6p-1-5+3p-2=0

6p+3p-5-1-2=0

9p-8=0

9p=8

p=8/9

Discussion

48.	A shopkeeper bought an article with marked price rupees 1200 from the wholesaler at a discount of 10% the shopkeeper sells his article to the customer on the Marked price printed on end if the rate of GST is 6% find theI)GST paid the wholesaler ii) amount paid by customer to buy the item
Answer» ANSWER: HOPE this HELPS you Step-by-step EXPLANATION: ANWERS is 648 1728

48.

A shopkeeper bought an article with marked price rupees 1200 from the wholesaler at a discount of 10% the shopkeeper sells his article to the customer on the Marked price printed on end if the rate of GST is 6% find theI)GST paid the wholesaler ii) amount paid by customer to buy the item

Answer»

ANSWER:

HOPE this HELPS you

Step-by-step EXPLANATION:

ANWERS is

648
1728

Discussion

49.	How to prepare for nata
Answer» 1)Studyudy & Practice Every DAY. The candidates must study the preparation books and study MATERIALS every day without failing. 2)Practice on Old Question Papers. The older version of the test will provide a very IMPORTANT insight regarding the format of the NATA exams. 3)Consult your Teachers/Tutors. 4)Prepare a BETTER Time-Table. Thanks ❤️

49.

How to prepare for nata

Answer»

1)Studyudy & Practice Every DAY. The candidates must study the preparation books and study MATERIALS every day without failing.

2)Practice on Old Question Papers. The older version of the test will provide a very IMPORTANT insight regarding the format of the NATA exams.

3)Consult your Teachers/Tutors.

4)Prepare a BETTER Time-Table.

Thanks ❤️

Discussion

50.	2+3x-x²-3x³ draw the graph
Answer» Step-by-step EXPLANATION: if x=0 2+3(0)-(0)^2-3(0)^3 2+0-0-0 2 answer =2 mark it as BRILLIANT

50.

2+3x-x²-3x³ draw the graph

Answer»

Step-by-step EXPLANATION:

if x=0

2+3(0)-(0)^2-3(0)^3

2+0-0-0

2

answer =2

mark it as BRILLIANT

Discussion

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