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The sum of areas of two squares is 468m²If the difference of their perimeter is 24cm.find the sides of two square .. |
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Answer» Answer: Sides of two squares are 18 & 12 Step-by-step explanation: Let sides of two squares be X & y given sum of areas of two squares = 468 => x^2+y^2 = 468 Difference of. their perimeters = 24cm => 4x-4y = 24 => x-y = 24/4 => x-y = 6...............(1) we know that (x-y)^2 = x^2+y^2-2XY => (6)^2 = 468-2xy => 36 = 468-2xy => 2xy = 468-36 => 2xy = 432 => XY = 216 Let (x+y)^2 = x^2+y^2+2xy = 468+(2×216) = 468+432 = 900 x+y = (900)^(1/2) x+y = 30..............(2) ADD (1) & (2) (x-y)+(x+y) = 6+30 2x = 36 x = 36/2 = 18 from (2) 18+y = 30 y = 30-18 = 12 .·. Sides of two squares are 18 & 12
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