332354 + Interview Questions in Secondary School in Math

1.	Find perimeter and area of rectangle whose length=55.5cm & breadth=43.6 cm
Answer» ANSWER: perimeter of RECTANGLE whose length=55.5cm & breadth=43.6 cm =178.2 cm area of rectangle whose length=55.5cm & breadth=43.6 cm=2419.8 SQ cm Step-by-step explanation: perimeter of rectangle whose length=55.5cm & breadth=43.6 cm =2(l+b) =2(55.5+43.6) =289.1 =178.2 cm area of rectangle whose length=55.5cm & breadth=43.6 cm* *= lb =55.5 43.6* =2419.8 sq cm

1.

Find perimeter and area of rectangle whose length=55.5cm & breadth=43.6 cm

Answer»

ANSWER:

perimeter of RECTANGLE whose length=55.5cm & breadth=43.6 cm =178.2 cm

area of rectangle whose length=55.5cm & breadth=43.6 cm=2419.8 SQ cm

Step-by-step explanation:

perimeter of rectangle whose length=55.5cm & breadth=43.6 cm

=2(l+b)

=2(55.5+43.6)

=2*89.1

=178.2 cm

area of rectangle whose length=55.5cm & breadth=43.6 cm

= l*b

=55.5 *43.6

=2419.8 sq cm

Discussion

2.	If you give the correct answer I will surely mark you BRAINLIEST.When a polynomial f(x) is divided by (x - 1), the remainder is 5 and when it is dividedby (x - 2), the remainder is 7. Find the remainder when it is divided by (x - 1) (x - 2).
Answer» Step-by-step explanation: We know that the remainder from (x-1) is 5 => P(1) = 5 We know that the remainder from (x-2) is 7 => P(2) = 7 We need to ánd out the remainder of polynomial P(x) when divided by (x-1)(x-2) Let us say D = (x-1)(x-2), the quotient is Q and the remainder is R The remainder will be of the format Ax + B, because it is the remainder after division by a QUADRATIC. P(x) = QD + Ax + B P(1) = Q0 + A + B => 5 = A + B P(2) = Q*0 + 2A + B => 7 = 2A + B Solving these EQUATIONS, we get A =2 and B = 3 => R = Ax + B => Remainder is 2x + 3 Mark As Brainest Plzz It's Correct

2.

If you give the correct answer I will surely mark you BRAINLIEST.When a polynomial f(x) is divided by (x - 1), the remainder is 5 and when it is dividedby (x - 2), the remainder is 7. Find the remainder when it is divided by (x - 1) (x - 2).

Answer»

Step-by-step explanation:

We know that the remainder from (x-1) is 5

=> P(1) = 5

We know that the remainder from (x-2) is 7

=> P(2) = 7

We need to ánd out the remainder of polynomial P(x) when divided by (x-1)(x-2)

Let us say D = (x-1)(x-2), the quotient is Q and the remainder is R

The remainder will be of the format Ax + B, because it is the remainder after division by a QUADRATIC.

P(x) = Q*D + Ax + B

P(1) = Q*0 + A + B

=> 5 = A + B

P(2) = Q*0 + 2A + B

=> 7 = 2A + B

Solving these EQUATIONS, we get A =2 and B = 3

=> R = Ax + B

=> Remainder is 2x + 3

Mark As Brainest Plzz It's Correct

Discussion

3.	2. In the triangleABC, DE is the perpendicular bisector of AC.If angleAED=70, what is the measure of angleBCA?
Answer» ANSWER: this question is wrong because ANGLE AED WIL be 90°

3.

2. In the triangleABC, DE is the perpendicular bisector of AC.If angleAED=70, what is the measure of angleBCA?

Answer»

ANSWER:

this question is wrong because ANGLE AED WIL be 90°

Discussion

4.	If 5tan A=4, then the value of5sin A-4cos A5sin A+ 4 cos A
Answer» ANSWER: sinA=L÷K cosA=A÷K tanA=L÷A and FIND

4.

If 5tan A=4, then the value of5sin A-4cos A5sin A+ 4 cos A

Answer»

ANSWER:

sinA=L÷K

cosA=A÷K

tanA=L÷A

and FIND

Discussion

5.	What length of canvas 3m wide will be required to make a conical tent of height 8m & radius of base 6m ? (Use pie = 3.14)
Answer» ANSWER: pie are so. Step-by-step explanation: PLEASE marks as brainlist

5.

What length of canvas 3m wide will be required to make a conical tent of height 8m & radius of base 6m ? (Use pie = 3.14)

Answer»

ANSWER:

pie are so.

Step-by-step explanation:

PLEASE marks as brainlist

Discussion

6.	2X - S +452 = 6x2-3 + 10.2 ty
Answer» ANSWER: ANS is divided Step-by-step explanation: 2x -s +452=6x2-3+10.2ty is it OK

6.

2X - S +452 = 6x2-3 + 10.2 ty

Answer»

ANSWER:

ANS is divided

Step-by-step explanation:

2x -s +452=6x2-3+10.2ty

is it OK

Discussion

7.	36 raise to 3 by 2 is equal to
Answer» ANSWER: ======≠======================

7.

36 raise to 3 by 2 is equal to

Answer»

ANSWER:

======≠======================

Discussion

8.	a wire is in the form of a rectangle and the perimeter of that rectangle is 176 m. the wire is straightened and bent in the form of a circle. find the radius of the circle and area of the circle
Answer» Step-by-step EXPLANATION: LENGTH of wire = CIRCUMFERENCE of circle circumference of circle = 176 2pieR = 176 2×22/7×R = 176 44/7×R =176 R = 176×7/44 R = 28 So , RADIUS of circle = 28 Area of circle = pie×R×R = 22/7×28×28 = 2464 square cm

8.

a wire is in the form of a rectangle and the perimeter of that rectangle is 176 m. the wire is straightened and bent in the form of a circle. find the radius of the circle and area of the circle

Answer»

Step-by-step EXPLANATION:

LENGTH of wire = CIRCUMFERENCE of circle

circumference of circle = 176

2pieR = 176

2×22/7×R = 176

44/7×R =176

R = 176×7/44

R = 28

So , RADIUS of circle = 28

Area of circle = pie×R×R

= 22/7×28×28

= 2464 square cm

Discussion

9.	Find length of rectangular field is 4 times it's breadth
Answer» Answer: 4x Step-by-step EXPLANATION: let breadth be x A/Q length = 4 TIMES breadth = 4 multiply by x = 4x plz............BRAINLIEST

9.

Find length of rectangular field is 4 times it's breadth

Answer»

Answer:

4x

Step-by-step EXPLANATION:

let breadth be x

A/Q

length = 4 TIMES breadth

= 4 multiply by x

= 4x

plz............BRAINLIEST

Discussion

10.	Answer these two questions
Answer» ANSWER: I SEND answer SEE it see now PLEASE

10.

Answer these two questions

Answer»

ANSWER:

I SEND answer SEE it see now PLEASE

Discussion

11.	X+ 10 > 4x – 5, xe I
Answer» Answer: iska dkho sab CHIJ galat hai que galat hai Step-by-step explanation: PLZZ marks as BRAINLIST

11.

X+ 10 > 4x – 5, xe I

Answer»

Answer:

iska dkho sab CHIJ galat hai que galat hai

Step-by-step explanation:

PLZZ marks as BRAINLIST

Discussion

12.	Chhayadon aadhi bat krke kha gayab
Answer» ANSWER: KAUN...................... HII

12.

Chhayadon aadhi bat krke kha gayab

Answer»

ANSWER:

KAUN...................... HII

Discussion

13.	- 7: Sunny started for his sister's house at 8:30 a.m. and walked for half an hourto reach the bus stop. He took the bus from there and travelled for anotherone hour. What time did Sunny finally reach his destination?s. Aci6. Sar11
Answer» Answer: At 10 am. Step-by-step explanation: Started from his sisters HOUSE at 8:30 am and WALKED half an hour. He REACH the bus STOP at 8:30+0:30= 9:00 am. He TRAVEL one hour He reach the destination at 9:00+1:00 =10:00 am.

13.

- 7: Sunny started for his sister's house at 8:30 a.m. and walked for half an hourto reach the bus stop. He took the bus from there and travelled for anotherone hour. What time did Sunny finally reach his destination?s. Aci6. Sar11

Answer»

Answer:

At 10 am.

Step-by-step explanation:

Started from his sisters HOUSE at 8:30 am and WALKED half an hour.

He REACH the bus STOP at 8:30+0:30= 9:00 am.

He TRAVEL one hour

He reach the destination at 9:00+1:00 =10:00 am.

Discussion

14.	How I got answer as
Answer» ANSWER: I didn't UNDERSTAND the QUESTION

14.

How I got answer as

Answer»

ANSWER:

I didn't UNDERSTAND the QUESTION

Discussion

15.	A can do piece of work in 80 days. He work at it for 10 days and them B alone finishes the remaining work in 42 days. In how many days could both do it?
Answer» Answer: If they worked together from the beginning, they would NEED 30 DAYS to complete the WORK. Step-by-step explanation: Let the total amount of work is 1 UNIT. In 80 days A alone does 1 unit amount of work. In 1 day A alone does 1/80 unit amount of work. So, in 10 days A alone does 10/80 unit = 1/8 unit amount of work. After 10 days of working of A alone the REMAINING amount of work is (1 - 1/8) = 7/8 unit of work. In 42 days B alone does 7/8 unit amount of work. So, in 1 day B alone does 7/(8*42) unit = 1/48 unit amount of work. In 1 day A and B together do [(1/80) + (1/48)] unit = 1/30 unit amount of work. 1/30 unit amount of work is done in 1 day when A and B work together. So, total work = 1 unit amount of work is done in 30 days when A and B work together.

15.

A can do piece of work in 80 days. He work at it for 10 days and them B alone finishes the remaining work in 42 days. In how many days could both do it?

Answer»

Answer:

If they worked together from the beginning, they would NEED 30 DAYS to complete the WORK.

Step-by-step explanation:

Let the total amount of work is 1 UNIT.

In 80 days A alone does 1 unit amount of work.

In 1 day A alone does 1/80 unit amount of work.

So, in 10 days A alone does 10/80 unit = 1/8 unit amount of work.

After 10 days of working of A alone the REMAINING amount of work is (1 - 1/8) = 7/8 unit of work.

In 42 days B alone does 7/8 unit amount of work.

So, in 1 day B alone does 7/(8*42) unit = 1/48 unit amount of work.

In 1 day A and B together do [(1/80) + (1/48)] unit = 1/30 unit amount of work.

1/30 unit amount of work is done in 1 day when A and B work together.

So, total work = 1 unit amount of work is done in 30 days when A and B work together.

Discussion

16.	Total vale if 96 coins
Answer» Answer: 96 RUPEES Step-by-step EXPLANATION: I can't understand the concept properly

16.

Total vale if 96 coins

Answer»

Answer:

96 RUPEES

Step-by-step EXPLANATION:

I can't understand the concept properly

Discussion

17.	16x12-672÷21= ?-211
Answer» Answer: 16×12-672÷21=160-211=-51.

17.

16x12-672÷21= ?-211

Answer»

Answer:

16×12-672÷21=160-211=-51.

Discussion

18.	Find the Perimeter of Rectangle Solve this Question
Answer» i HOPE so i am ryt Answer: 120.32m Step-by-step EXPLANATION: P=2(l+w) =2(40+2/3+19+1/2) =2(122/3+39/2) =2(244+117/6) =2(361/6) =2(60.16) =120.32m

18.

Find the Perimeter of Rectangle Solve this Question

Answer»

i HOPE so i am ryt

Answer:

120.32m

Step-by-step EXPLANATION:

P=2(l+w)

=2(40+2/3+19+1/2)

=2(122/3+39/2)

=2(244+117/6)

=2(361/6)

=2(60.16)

=120.32m

Discussion

19.	The sub triplicate ratio of 1000:512 is
Answer» ANSWER: SolutionHelp Solution PROBLEM: subtriplicate ratio 8:27 [ Calculator, Method and EXAMPLES ] Solution: Your problem → subtriplicate ratio 8:27 For ratio a:b, 3 √ a :3 √ b is called sub TRIPLICATE ratio. ∴ sub triplicate ratio of 8:27 is 3 √ 8 :3 √ 27 =2:3

19.

The sub triplicate ratio of 1000:512 is

Answer»

ANSWER:

SolutionHelp

Solution

PROBLEM: subtriplicate ratio 8:27 [ Calculator, Method and EXAMPLES ]

Solution:

Your problem → subtriplicate ratio 8:27

For ratio a:b, 3

√

a

:3

√

b

is called sub TRIPLICATE ratio.

∴ sub triplicate ratio of 8:27 is 3

√

8

:3

√

27

=2:3

Discussion

20.	1. Convert the following temperatures to the celsius scale.(a) 293 K(b) 470 K.
Answer» $\huge{\boxed{\underline{\mathcal{\purple{Ques}\green{tion}}}}}$ Convert the following TEMPERATURES to the CELSIUS SCALE. (a) 293 K (b) 470 K. Step-by-step explanation: $\huge{\boxed{\underline{\mathcal{\purple{Ans}\green{Wer}}}}}$ Conversion We know the formula that K=C+273. So. ATQ, a) 293=C+273 C=293-273 a) Answer is 20°C b) 470=C+273 C=470-273 C=197°C HOPE IT HELPS AND PLZ MARK IT AS BRAINLIEST AND FOLLOW ME

20.

1. Convert the following temperatures to the celsius scale.(a) 293 K(b) 470 K.

Answer»

$\huge{\boxed{\underline{\mathcal{\purple{Ques}\green{tion}}}}}$

Convert the following TEMPERATURES to the CELSIUS SCALE.

(a) 293 K

(b) 470 K.

Step-by-step explanation:

$\huge{\boxed{\underline{\mathcal{\purple{Ans}\green{Wer}}}}}$

Conversion

We know the formula that

K=C+273.

So. ATQ,

a) 293=C+273

C=293-273

a) Answer is 20°C

b) 470=C+273

C=470-273

C=197°C

HOPE IT HELPS AND PLZ MARK IT AS BRAINLIEST AND FOLLOW ME

Discussion

21.	The angle of elevation and depression are usually measured by a device called
Answer» ANSWER: iclinometer or CLINOMETER is the device USED for measuring the ANGLE of elevation and depression.

21.

The angle of elevation and depression are usually measured by a device called

Answer»

ANSWER:

iclinometer or CLINOMETER is the device USED for measuring the ANGLE of elevation and depression.

Discussion

22.	A field is in the form of a circle. The cost of ploughing is 57,750 at rate of rs.15/sq.m. Find the radius of the circular field.
Answer» Answer: HEY MATE here is your answer.... Refer to the attachment I hope it helps you... Thnku for giving me a chance to help you.. FOLLOW me for more answers... If it helps then PLEASE dear MARK my answer brainliest

22.

A field is in the form of a circle. The cost of ploughing is 57,750 at rate of rs.15/sq.m. Find the radius of the circular field.

Answer»

Answer:

HEY MATE here is your answer....

Refer to the attachment

I hope it helps you...
Thnku for giving me a chance to help you..

FOLLOW me for more answers...

If it helps then PLEASE dear MARK my answer brainliest

Discussion

23.	ToWhich one of the following green house gases is a contributor due to incomplete combustion of coal and petroleuma) Oxides of nitrogenb) Methanec) Carbon monooxided) Carbon dioxide
Answer» Answer: Carbon mono-oxide is the CONTRIBUTOR DUE to incomplete COMBUSTION.

23.

ToWhich one of the following green house gases is a contributor due to incomplete combustion of coal and petroleuma) Oxides of nitrogenb) Methanec) Carbon monooxided) Carbon dioxide

Answer»

Answer:

Carbon mono-oxide is the CONTRIBUTOR DUE to incomplete COMBUSTION.

Discussion

24.	Seema and Tina attended a meeting at aclient's office. Seema left from the client'soffice for the factory in her car, driving ata speed of 60 km/hr. Tina left after sometime for the factory, driving at the speed of80 km/hr. Tina drove for 3 hours before shecould catch up with Seema. For how long didSeema drive before Tina caught up?
Answer» ANSWER: for 48hrs Step-by-step EXPLANATION: i GUESS ....................

24.

Seema and Tina attended a meeting at aclient's office. Seema left from the client'soffice for the factory in her car, driving ata speed of 60 km/hr. Tina left after sometime for the factory, driving at the speed of80 km/hr. Tina drove for 3 hours before shecould catch up with Seema. For how long didSeema drive before Tina caught up?

Answer»

ANSWER:

for 48hrs

Step-by-step EXPLANATION:

i GUESS ....................

Discussion

25.	A body is exicute simple harmonic motion at emplytitude its velocity while passing through the mean position is 10m/sec. .find its frequency.
Answer» Answer: good MORNING friend Step-by-step EXPLANATION: UR answer is f=1/T f= .001*(multiple) 10–²9 .......it helps! yaar mujhe 2 brainlist CHAIYE so plz HELP me.

25.

A body is exicute simple harmonic motion at emplytitude its velocity while passing through the mean position is 10m/sec. .find its frequency.

Answer»

Answer:

good MORNING friend

Step-by-step EXPLANATION:

UR answer is

f=1/T

f= .001*(multiple) 10–²9

.......it helps!

yaar mujhe 2 brainlist CHAIYE

so plz HELP me.

Discussion

26.	After 20% hike the cost of refrigerator is 15300 what was the original price of this refrigerator
Answer» Answer: 12750 Step-by-step EXPLANATION: LET, ORIGINAL PRICE of refrigerator=x ∴x+x(20/100)=15300 5x+x=76500 6x=76500 x=12750 original price of refrigerator=12750

26.

After 20% hike the cost of refrigerator is 15300 what was the original price of this refrigerator

Answer»

Answer:

12750

Step-by-step EXPLANATION:

LET,

ORIGINAL PRICE of refrigerator=x

∴x+x(20/100)=15300

5x+x=76500

6x=76500

x=12750

original price of refrigerator=12750

Discussion

27.	PILIR B2)WD 2,9,0,0,...."Column-IIp) onto1) 2424 1221 1231Matrix Match Type:10. Column-1a) A = {1,2,3,4,5), B ={1,4,7,10,13).IF F:A → B defined by f(x)=3x-2 then f isb) A= (0,1,2,3), B = -7,-2,3,8,11),If f: A - B defined by f(x) = 5x-7, then fisc A= (-1,0,2,5,6,11), B = {2,-1,1,0,11,108)and flz) = 2z2. - X-2 then f: A - B not ontod) A = (-1,0,1,2), B = 2,3,6} & f(x) = x + 2then f: A - B is sg) not a functionI) a function buts) one-one & on toNarayana Group of Schools160Scanned by Can
Answer» ANSWER: d is answer dear Step-by-step explanation: May it HELP u .............. ........XD

27.

PILIR B2)WD 2,9,0,0,...."Column-IIp) onto1) 2424 1221 1231Matrix Match Type:10. Column-1a) A = {1,2,3,4,5), B ={1,4,7,10,13).IF F:A → B defined by f(x)=3x-2 then f isb) A= (0,1,2,3), B = -7,-2,3,8,11),If f: A - B defined by f(x) = 5x-7, then fisc A= (-1,0,2,5,6,11), B = {2,-1,1,0,11,108)and flz) = 2z2. - X-2 then f: A - B not ontod) A = (-1,0,1,2), B = 2,3,6} & f(x) = x + 2then f: A - B is sg) not a functionI) a function buts) one-one & on toNarayana Group of Schools160Scanned by Can

Answer»

ANSWER:

d is answer dear

Step-by-step explanation:

May it HELP u ..............

........XD

Discussion

28.	Q.2. A big locker is above a small locker. They are both 0.5 m wide and0.6 m deep. The big locker is 1.2 m tall and the small locker is half ofthe height of the big locker. What is the total volume of one big lockerand one small locker?Small locker
Answer» Step-by-step EXPLANATION: big locker lbh h=0.6m b=0.5m l=1.2m volume=1.20.60.5 =0.36m^3 small locker l=1.2/2 =0.6 volume=0.60.60.5 =0.18m^3 *hope* *this* *HELPS* *you* *and* *PLZ* *mark* me as *brainliest* *and* *plz* *FOLLOW* me

28.

Q.2. A big locker is above a small locker. They are both 0.5 m wide and0.6 m deep. The big locker is 1.2 m tall and the small locker is half ofthe height of the big locker. What is the total volume of one big lockerand one small locker?Small locker

Answer»

Step-by-step EXPLANATION:

big locker

l*b*h

h=0.6m

b=0.5m

l=1.2m

volume=1.2*0.6*0.5

=0.36m^3

small locker

l=1.2/2

=0.6

volume=0.6*0.6*0.5

=0.18m^3

hope this HELPS you and PLZ mark me as brainliest and plz FOLLOW me

Discussion

29.	If the perimeter of triangle is 53 cm and its equal side are 12 CM
Answer» the question is wrong either it Should be : The perimeter is 53 cm OR:it's equal side is 12CM because if the SIDES are equal it is called EQUILATERAL triangle and the MEASUREMENT should come as 36(12+12+12)cm

29.

If the perimeter of triangle is 53 cm and its equal side are 12 CM

Answer»

the question is wrong either it Should be : The perimeter is 53 cm OR:it's equal side is 12CM

because if the SIDES are equal it is called EQUILATERAL triangle and the MEASUREMENT should come as 36(12+12+12)cm

Discussion

30.	A factory produces 570 toy- car a day.How many cars did it produce in the year 2018, if there are 76 holiday?
Answer» Answer: Total no. of days in 2018 = 365 days Total no. of Holidays in 2018 = 76 days so, Total no. of Working Days = ( 365 - 76 ) days = 289 days In 1 day factory produce = 570 toy cars so, In 289 days factory produce = 289 × 570 toy cars = 164,730 toy cars ans. HOPE IT WILL HELP YOU MAKE ME BRAINLIEST

30.

A factory produces 570 toy- car a day.How many cars did it produce in the year 2018, if there are 76 holiday?

Answer»

Answer:

Total no. of days in 2018 = 365 days

Total no. of Holidays in 2018 = 76 days

so, Total no. of Working Days = ( 365 - 76 ) days

= 289 days

In 1 day factory produce = 570 toy cars

so, In 289 days factory produce = 289 × 570 toy cars

= 164,730 toy cars ans.

HOPE IT WILL HELP YOU MAKE ME BRAINLIEST

Discussion

31.	MATHSSSS FASTTTIf the lines 3x-5y=7 and 4x+ay+9=0 areperpendicular to each other, find the value of 'a'
Answer» ANSWER: a1=3, a2=4&b1=5, b2=a &c1=7, c2=9 Step-by-step EXPLANATION: a1/a2 the not EQUAL a=5=b1/b2=c1/c2 3/4=5/a=7/9

31.

MATHSSSS FASTTTIf the lines 3x-5y=7 and 4x+ay+9=0 areperpendicular to each other, find the value of 'a'

Answer»

ANSWER:

a1=3, a2=4&b1=5, b2=a &c1=7, c2=9

Step-by-step EXPLANATION:

a1/a2

the not EQUAL a=5=b1/b2=c1/c2 3/4=5/a=7/9

Discussion

32.	Factorize-x^2+2ax+(a+b)(a-b)
Answer» \|\|✪✪ CORRECT QUESTION ✪✪\|\| factorize :- x^2+2ax+(a+b)(a-b) = 0 \|\| ✰✰ ANSWER ✰✰ \|\| → x^2+2ax+(a+b)(a-b) = 0 Using (a+b)(a-b) = a² - b² now, → x² + 2ax + (a² - b²) = 0 → (x² + 2ax + a²) - b² = 0 COMPARING it with a² + b² + 2ab = (a+b)² now, we get, → (x + a)² - b² = 0 again, using a² - b² = (a+b)(a-b) now, → (x + a + b) ( x +a - b) = 0 Putting both Equal to ZERO now, → (x + a + b) = 0 → x = -(a+b) Or, → (x + a - b) = 0 → x = (b - a) HENCE, value of x will be -(a+b) or (b-a).

32.

Factorize-x^2+2ax+(a+b)(a-b)

Answer»

||✪✪ CORRECT QUESTION ✪✪||

factorize :- x^2+2ax+(a+b)(a-b) = 0

|| ✰✰ ANSWER ✰✰ ||

→ x^2+2ax+(a+b)(a-b) = 0

Using (a+b)(a-b) = a² - b² now,

→ x² + 2ax + (a² - b²) = 0

→ (x² + 2ax + a²) - b² = 0

COMPARING it with a² + b² + 2ab = (a+b)² now, we get,

→ (x + a)² - b² = 0

again, using a² - b² = (a+b)(a-b) now,

→ (x + a + b) ( x +a - b) = 0

Putting both Equal to ZERO now,

→ (x + a + b) = 0

→ x = -(a+b)

Or,

→ (x + a - b) = 0

→ x = (b - a)

HENCE, value of x will be -(a+b) or (b-a).

Discussion

33.	A jar contain 3red 4 blue 5 white and 2 green marble lf a marble is drawn at random from the jar What will be probability of ? a.Ball drown is white b. Either Red or Blue c. A green ball
Answer» Step-by-step explanation: HERE Total outcomes = 14 ANSWER (a) Probability of DROWN white marble= 5/14 ANSWER (B) Probability of drown EITHER RED or Blue = 7/14 ANSWER (c) Probability of drown green marbles = 2/14

33.

A jar contain 3red 4 blue 5 white and 2 green marble lf a marble is drawn at random from the jar What will be probability of ? a.Ball drown is white b. Either Red or Blue c. A green ball

Answer»

Step-by-step explanation:

HERE

Total outcomes = 14

ANSWER (a)

Probability of DROWN white marble= 5/14

ANSWER (B)

Probability of drown EITHER RED or Blue = 7/14

ANSWER (c)

Probability of drown green marbles = 2/14

Discussion

34.	If X=3 is one root of quadratic equation x square - kx = 0 find value of K
Answer» ANSWER: X^2-kx=0 put the VALUE of X in above equation 3^2-3k=0 9-3k=0 3k=9 k=3

34.

If X=3 is one root of quadratic equation x square - kx = 0 find value of K

Answer»

ANSWER:

X^2-kx=0

put the VALUE of X in above equation

3^2-3k=0

9-3k=0

3k=9

k=3

Discussion

35.	A motor boat goes down the stream 30 km and again returns to thestarting point in a total time of 4 hours and 30 minutes. If the speed of thestream is 5 km/hr, then find the speed of the motor boat in still water.
Answer» Step-by-step EXPLANATION: the SPEED of the motor BOAT in STILL water is 15km/h

35.

A motor boat goes down the stream 30 km and again returns to thestarting point in a total time of 4 hours and 30 minutes. If the speed of thestream is 5 km/hr, then find the speed of the motor boat in still water.

Answer»

Step-by-step EXPLANATION:

the SPEED of the motor BOAT in STILL water is

15km/h

Discussion

36.	B. If tan theta + sec theta=r then prove that sec theta= r^2+1/2r
Answer» I HOPE you UNDERSTAND my SOLUTION

36.

B. If tan theta + sec theta=r then prove that sec theta= r^2+1/2r

Answer»

I HOPE you UNDERSTAND my SOLUTION

Discussion

37.	24. सिद्ध कीजिए √3 एक अपरिमेय संख्या है।
Answer» ANSWER: hxbdbrhrhdhdbrbrbrbbrbfbrbrbrbbb

37.

24. सिद्ध कीजिए √3 एक अपरिमेय संख्या है।

Answer»

ANSWER:

hxbdbrhrhdhdbrbrbrbbrbfbrbrbrbbb

Discussion

38.	Please solve this math question using triangle similarity
Answer» Answer: FIRST, In TRIANGLES ABC AND ADE, ANGLE B=ANGLE D AND, ANGLE BAD=ANGLE CAE OR, ANGLE(BAD+CAD) =ANGLE(CAE+CAD) (ADDING SAME THING) OR, ANGLE BAC=ANGLE CAE THUS, THESE ARE SIMILAR ACCORDING TO AA SIMILARITY THUS, AB/AD=AC/AE AND, ANGLE ADB=ANGLE AEC

38.

Please solve this math question using triangle similarity

Answer»

Answer:

FIRST, In TRIANGLES ABC AND ADE, ANGLE B=ANGLE D

AND, ANGLE BAD=ANGLE CAE

OR, ANGLE(BAD+CAD) =ANGLE(CAE+CAD) (ADDING SAME THING)

OR, ANGLE BAC=ANGLE CAE

THUS, THESE ARE SIMILAR ACCORDING TO AA SIMILARITY

THUS, AB/AD=AC/AE

AND, ANGLE ADB=ANGLE AEC

Discussion

39.	the area of an equilateral triangle is 16 root 3 square centimetre then find the perimeter of the triangle
Answer» YOUR ANSWER PLZ BE CAREFUL AND UNDERSTAND IF ANY PROBLEM ASK ME..

39.

the area of an equilateral triangle is 16 root 3 square centimetre then find the perimeter of the triangle

Answer»

YOUR ANSWER

PLZ BE CAREFUL AND UNDERSTAND IF ANY PROBLEM ASK ME..

Discussion

40.	Find the area of a sector of a circle with radius 6 CM if angle of the sector is 60
Answer» $\huge\mathbb{\underline{SOLUTION:-}}$ $\sf\underline{\underline{\purple{\:\:\: Given:-\:\:\:}}}$ $\sf\bullet angle \:of\: <klux>SECTOR</klux>=60{}^{\circ}\\ \\ \sf\bullet Radius=6cm$ We have to FIND the AREA of sector $\boxed{\sf{Area\:of\:sector=\dfrac{ \theta}{360{}^{\circ}}\pi r{}^{2}}}$ $\sf\implies Area=\dfrac{\cancel{60}}{\cancel{360}}\times \dfrac{22}{7}\times (6){}^{2}\\ \\ \sf\implies Area=\dfrac{1}{6}\times \dfrac{22}{7}\times \cancel{36}\\ \\ \sf\implies Area=\dfrac{22\times 6}{7}\\ \\ \sf\implies Area=\cancel{\dfrac{132}{7}}\\ \\ \sf\implies Area=18.85cm{}^{2}$ $\boxed{\sf{\purple{Area\:of\:sector=18.85cm{}^{2}}}}$

40.

Find the area of a sector of a circle with radius 6 CM if angle of the sector is 60

Answer»

$\huge\mathbb{\underline{SOLUTION:-}}$

$\sf\underline{\underline{\purple{\:\:\: Given:-\:\:\:}}}$

$\sf\bullet angle \:of\: <klux>SECTOR</klux>=60{}^{\circ}\\ \\ \sf\bullet Radius=6cm$

We have to FIND the AREA of sector

$\boxed{\sf{Area\:of\:sector=\dfrac{ \theta}{360{}^{\circ}}\pi r{}^{2}}}$

$\sf\implies Area=\dfrac{\cancel{60}}{\cancel{360}}\times \dfrac{22}{7}\times (6){}^{2}\\ \\ \sf\implies Area=\dfrac{1}{6}\times \dfrac{22}{7}\times \cancel{36}\\ \\ \sf\implies Area=\dfrac{22\times 6}{7}\\ \\ \sf\implies Area=\cancel{\dfrac{132}{7}}\\ \\ \sf\implies Area=18.85cm{}^{2}$

$\boxed{\sf{\purple{Area\:of\:sector=18.85cm{}^{2}}}}$

Discussion

41.	Evaluate:--8×(-21/4)
Answer» ANSWER: $- 8 \times \frac{ - 21}{4}$ $- 2 \times - 21$ $42$

41.

Evaluate:--8×(-21/4)

Answer»

ANSWER:

$- 8 \times \frac{ - 21}{4}$

$- 2 \times - 21$

$42$

Discussion

42.	Prove Prove that 2 + square root of 3 is an irrational number
Answer» Answer: becoz sum of an irrational number and a RATIONAL is 5 HENCE we hv a CONTRADICTION

42.

Prove Prove that 2 + square root of 3 is an irrational number

Answer»

Answer:

becoz sum of an irrational number and a RATIONAL is 5

HENCE we hv a CONTRADICTION

Discussion

43.	100x²-80xy+16y²Factorise it
Answer» Answer: (10x - 4Y)² Step-by-step explanation: Given : 100x² - 80xy + 16y² We can write this as : → (10x)² - 80xy + (4y)² On comparing the equation with an identity MENTIONED below : • { Identity : a² - 2ab + b² = (a - b)² Here, a = 10X, b = 4 } Therefore, we can write this as again : → (10x)² - 2(10x)(4y) + (4y)² → (10x - 4y)² Other identities which are frequently USED : • (a + b)² = a² + 2ab + b² • (a + b)(a - b) = a² - b² • (x + a)(x + b) = x² + (a + b)x + ab

43.

100x²-80xy+16y²Factorise it

Answer»

Answer:

(10x - 4Y)²

Step-by-step explanation:

Given : 100x² - 80xy + 16y²

We can write this as :

→ (10x)² - 80xy + (4y)²

On comparing the equation with an identity MENTIONED below :

• { Identity : a² - 2ab + b² = (a - b)²

Here, a = 10X, b = 4 }

Therefore, we can write this as again :

→ (10x)² - 2(10x)(4y) + (4y)²

→ (10x - 4y)²

Other identities which are frequently USED :

• (a + b)² = a² + 2ab + b²

• (a + b)(a - b) = a² - b²

• (x + a)(x + b) = x² + (a + b)x + ab

Discussion

44.	281 If A = [ 3 x and B: [ 16 ] findwhere A²-B.and y
Answer» ANSWER: y to QUESTION mein HAI HI NHI

44.

281 If A = [ 3 x and B: [ 16 ] findwhere A²-B.and y

Answer»

ANSWER:

y to QUESTION mein HAI HI NHI

Discussion

45.	In triangle pqr PQ is equal to PR and angle Q is equal to 80 degree find angle p
Answer» Answer: PQ = PR ... (Given) ∴ ∠Q = ∠R ... (Angles opposite to equal SIDES are equal) ∴ ∠R = 80° ∠P + ∠Q +∠R = 180° ... (Angle SUM property of a TRIANGLE) ∴ ∠P + 80 +80 = 180° ∴ ∠P + 160 = 180 ∴ ∠P = 20°

45.

In triangle pqr PQ is equal to PR and angle Q is equal to 80 degree find angle p

Answer»

Answer:

PQ = PR ... (Given)

∴ ∠Q = ∠R ... (Angles opposite to equal SIDES are equal)

∴ ∠R = 80°

∠P + ∠Q +∠R = 180° ... (Angle SUM property of a TRIANGLE)

∴ ∠P + 80 +80 = 180°

∴ ∠P + 160 = 180

∴ ∠P = 20°

Discussion

46.	If 2,5,8 ,x are in proportion,the value of x is
Answer» Answer: 11 is UR answer Step-by-step EXPLANATION: MARK as BRILLIANT

46.

If 2,5,8 ,x are in proportion,the value of x is

Answer»

Answer:

11 is UR answer

Step-by-step EXPLANATION:

MARK as BRILLIANT

Discussion

47.	MensurationWorksheetAnswer the following questions:1. From a rectangular sheet of paper two circles of equal diameter 4 cm and a triabase 3 cm and height 2 cm are cut. Find the area of the remaining ect.Area = 12011 cm19 cm2. Find the surface area of a box having dimensions 40 cm x 22cm x 18 cm.Thow many cubical blocks of edge 8 inch can be cut from another cubicalT
Answer» Answer: 458475466646 Step-by-step EXPLANATION: X GM idy75745665456636744jgsfhzjfsjgdjgjxugzgixjgxjgjgxufxguxguxugxi

47.

MensurationWorksheetAnswer the following questions:1. From a rectangular sheet of paper two circles of equal diameter 4 cm and a triabase 3 cm and height 2 cm are cut. Find the area of the remaining ect.Area = 12011 cm19 cm2. Find the surface area of a box having dimensions 40 cm x 22cm x 18 cm.Thow many cubical blocks of edge 8 inch can be cut from another cubicalT

Answer»

Answer:

458475466646

Step-by-step EXPLANATION:

X GM idy75745665456636744jgsfhzjfsjgdjgjxugzgixjgxjgjgxufxguxguxugxi

Discussion

48.	Answer the 2nd question
Answer» Length * breadth = AREA Let the length be x So, x × 15units = 465 UNIT square X =465/15 X=31 units So length = 31 units

48.

Answer the 2nd question

Answer»

Length * breadth = AREA

Let the length be x

So, x × 15units = 465 UNIT square

X =465/15

X=31 units

So length = 31 units

Discussion

49.	47 mm convert cm, km and metre
Answer» Answer: 4.7cm,0.047m,0.000047km Step-by-step explanation: 1cm=10mm So, 47/10cm =4.7cm 1m=1000mm So, 47/1000m =0.047m 1km=1000000mm So, 47/1000000km =0.000047km

49.

47 mm convert cm, km and metre

Answer»

Answer:

4.7cm,0.047m,0.000047km

Step-by-step explanation:

1cm=10mm

So, 47/10cm

=4.7cm

1m=1000mm

So, 47/1000m

=0.047m

1km=1000000mm

So, 47/1000000km

=0.000047km

Discussion

50.	If 'b' is the mean proportion between 'a' and 'c', prove that:(a²-b²+c²)/(a-¹+b-²+c-²) = b⁴
Answer» Answer: Since, B is the MEAN proportional between a and c. So b2 = ac. L.H.S. = a2 – b2 + C2/a-2 – b-2 + c-2 = a2 – b2 + c2/1/a2 – 1/b2 + 1/c2 = (a2 – b2 + c2)/B2C2 – a2c2 + a2b2/a2b2c2 = a2b2c2 (a2 – b2 + c2)/b2c2 – b4 + a2b2 = b4 × b2(a2 – b2 + c2)/b2(c2 – b2 + a2) b4 = R.H.S. Hence proved. *PLEASE* *MARK* ME AS *BRAINLIST*

50.

If 'b' is the mean proportion between 'a' and 'c', prove that:(a²-b²+c²)/(a-¹+b-²+c-²) = b⁴

Answer»

Answer:

Since, B is the MEAN proportional between a and c. So b2 = ac.

L.H.S. = a2 – b2 + C2/a-2 – b-2 + c-2

= a2 – b2 + c2/1/a2 – 1/b2 + 1/c2

= (a2 – b2 + c2)/B2C2 – a2c2 + a2b2/a2b2c2

= a2b2c2 (a2 – b2 + c2)/b2c2 – b4 + a2b2

= b4 × b2(a2 – b2 + c2)/b2(c2 – b2 + a2)

b4 = R.H.S.

Hence proved.

PLEASE MARK ME AS BRAINLIST

Discussion

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