1.

Factorize-x^2+2ax+(a+b)(a-b)​

Answer»

||✪✪ CORRECT QUESTION ✪✪||

factorize :- x^2+2ax+(a+b)(a-b) = 0

|| ✰✰ ANSWER ✰✰ ||

→ x^2+2ax+(a+b)(a-b) = 0

Using (a+b)(a-b) = a² - b² now,

→ x² + 2ax + (a² - b²) = 0

→ (x² + 2ax + a²) - b² = 0

COMPARING it with a² + b² + 2ab = (a+b)² now, we get,

→ (x + a)² - b² = 0

again, using a² - b² = (a+b)(a-b) now,

→ (x + a + b) ( x +a - b) = 0

Putting both Equal to ZERO now,

→ (x + a + b) = 0

→ x = -(a+b)

Or,

→ (x + a - b) = 0

→ x = (b - a)

HENCE, value of x will be -(a+b) or (b-a).



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