This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
How to find completing square in easy way? |
|
Answer» Step-by-step explanation: Step 1 DIVIDE all terms by a (the COEFFICIENT of x2). Step 2 MOVE the number term (c/a) to the right side of the EQUATION. Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation. |
|
| 3. |
How do we identify the problem is quadratic equations or pair of linear pair. in 10 std |
|
Answer» while forming the EQUATION if you are getting ONE VARIABLE and a DEGREE of 2 then it's quadratic, otherwise it would be linear..... forming the equation if you are getting one variable and a degree of 2 then it's quadratic, otherwise it would be linear.....hope this helps you if so then don't forget to THANK and mark as brainliest |
|
| 4. |
A) In the given figure, AB =6, BC =8,then find AC |
|
Answer» no figure Step-by-step EXPLANATION: |
|
| 5. |
A and B individualy can do a work in 6 days and 12 days respectively. A worked for first 2 days and then left. In how many days will B finish the remaining part of the work? |
|
Answer» Answer: A left his work for = 4 days B's speed is 2 TIMES less than that of A so A's work DONE by B was in (4*2)days = 8 days B completed the work in (12+8)days =20 days . Ans.) B completed the work in 20 days. |
|
| 6. |
Draw an isosceles triangle ABc inwhich AB = AC = 6 cm and BC = 5 cm. Constructtriangle PQR similar to triangle ABC inwhich PQ = 8 cm. Also justify the constructiion. |
|
Answer» MARK as BRAINLIEST |
|
| 7. |
Please solve and explain properly:1. The area of a trapezium is 119 sq. cm and its altitude is 7 cm. If one of the paralle sides is 8 cm longer than the other, find the parallel sides.2. A rectangular paper of length 66 cm and breadth 14 cm is rolled into a cylinder along the length . Fid the total surface area nd the volume of the cylinder |
|
Answer» Step-by-step EXPLANATION: hey mate here is your ANSWER PLZ mark me as BRAINLIEST |
|
| 8. |
6The cost price of 30 articles is equal to theselling price of 25 articles. Find the loss orgain percent. |
Answer» Answer:
Step-by-step EXPLANATION:Given:
To Find:
Let each articles price is Rs. 1. So, => CP of 30 articles = Rs. 30 = SP => SP of 25 articles = Rs. 25 = CP So, Gain = SP - CP => Gain = 30 - 25 => Gain = Rs. 5 Now, we will find Gain Percentage, => Gain % = Gain/SP × 100 => Gain % = 5/25 × 100 => Gain % = 0.2 × 100 => Gain % = 20% Hence, Gain % = 20%. |
|
| 9. |
Triangle ABC , angle A =30 degree, angle B = 90 degree AC (hypotnuse) = 16 cm . What Is the length of BC ( base) |
|
Answer»
|
|
| 10. |
A corn cob shaped somewhat like a cone has the radius of its broadest and as 2.1cm and length as 20 cm. If each 1cm^2 of the surface of the cob carries an average of four grains, find how many grains you would find on the entire cob?give the answer plz❤❤ |
| Answer» | |
| 11. |
If tan alfa =x/x+1 and tan beta =1/2x+1 find the value of alfa + beta |
|
Answer» Thankyou |
|
| 12. |
Plzz help me with step by step answer |
|
Answer» Answer: Your correct answer is = 4 cm If you LOOK at the HYPOTENUSE of triangle abc & def. You observe that hypotenuse of triangle abc is haff of the hypotenuse triangle def. So all other sides will be also half. This is the only way to answer the questions. Thanks |
|
| 13. |
find the ratio of the areas of an eqalator tringle abc and squre efgc if g is the centroid of the tringle abc |
| Answer» | |
| 14. |
If the value of machine is Rs. P and depreciates at R% per annum then its value after 5 yearsis |
|
Answer» VALUE of the machine after 2 years = RS.[40500*(1- 10/100)^2] = Rs.40500*9*9/10*10 = Rs. 32805 Value of the machine 2 years ago = Rs.40500/(1-1/100)^2 = Rs.40500*10*10/9*9 = Rs.50000 |
|
| 15. |
2/10+8/20+3/60 find lcm |
|
Answer» 2/10+8/20+3/60=12+24+3/60=39/60 |
|
| 18. |
She bought a blanket yesterday change into passive voice. |
|
Answer» The blanket was brought by her yesterday Step-by-step EXPLANATION: hope it helps please mark me down as a BRAINLIEST |
|
| 19. |
Answers for the above photo. PLEASE |
|
Answer» Answer: it is true as diagonal of rectangle are ALWAYS congruent the POINT o is ALSO equidistant say thanks |
|
| 20. |
In ABC, AD, BE, CF are the perpendicular drawn on opposite sides and they intersect eachother atO BOC = 110, find. BAC(A) 100(B) 9570(D) 105 |
| Answer» | |
| 21. |
(-a) (-c) - (b) d2 when a=-32, b. = 96, c = -3, d= -1 |
|
Answer» Answer: Step-by-step EXPLANATION: (-a)(-c)-(B)d2 96-(-196) 96+196 292 |
|
| 22. |
If x =5, y = -3 find |x+y| , | x|+|y| |
|
Answer» |X+Y|=2 |X|+|Y|=8 Step-by-step explanation: x+y= 5+(-3) = 5-3 = 2 |x+y|= |2| = 2 ************* |x|=|5| = 5 |y|=|-3| =3 |x|+|y|=5+3 = 8 ************** -------------------------------------------------- PLS MARK AS BRAINLIEST <3 |
|
| 23. |
Marked price of a table is 50% more than its cost price what discount percentage should be offered by the shopkeeper to sell his table at no profit no loss |
|
Answer» he should SELL it at a DISCOUNT of 50% Step-by-step EXPLANATION: |
|
| 24. |
using congruence of triangles show that the altitude of an equilateral triangle is also the angle bisector |
|
Answer» hence PROVED ,the altitude of equilateral triangle is ALSO BISECTS the angle |
|
| 26. |
If an alloy contains 4% of silver, then 9 kg of silver is contained in___kg of that alloy. Correct answer will be marked as brainliest ! |
|
Answer» 225 kg is the weight of that alloy therefore 4% of x = 9 =4/100 of x =9 x= 100/4*9 x=25*9 x=225 hence the total weight of the alloy is 225 thank you. pls MARK this as the BRAINLIEST answer |
|
| 27. |
6. Cost of 5 books and 4 note-books is Rs. 100. If the cost of one bookRs. 12, find the cost of one note-book |
|
Answer» Answer: 0fyfys5 Step-by-step EXPLANATION: ydrdyctdtgi hvybig7hp |
|
| 28. |
6 મીટર ઉચી એક નિસરણી ઓરડાની એક દિવાલને ટેકવીને મુકેલી છે, ત્યારે તે ભોંયતળિયા સાથે45° નો ખૂણો રચે છે. જો નીસરણીનો નીચેનો છેડો ભોંયતળિયા સાથે ફીટ કરી દેવામાં આવે અનેનીસરણીને તે ઓરડા સામેની દિવાલ સાથે ટેકવવામાં આવે ત્યારે તે ભોંયતળિયા સાથે 60નો- - - - - 0 2 દિવાલો વચ્ચેનું અંતર શોધો. |
| Answer» | |
| 29. |
4. What should be added to 4x2 - 5xy + 7 to get- 3x2 + 4xy – 5?if you dont know the answer then please dont give answer.let me tell that give answer step by step |
|
Answer» Answer: The required expression can be GOT by subtracting XY – 3yz + 4ZX from 4XY – 3zx + 4yz + 7. Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx) = 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx = 4xy – xy – 3zx – 4zx + 4yz + 3yz + 7 = 3xy – 7zx + 7yz + 7 |
|
| 30. |
Factorise:(p+q)(3a-b)+6(p+q)(2b-3a) |
|
Answer» Step-by-step EXPLANATION: |
|
| 32. |
What is the meaning of Aditya |
|
Answer» MARK IT AS A BRAINLIEST |
|
| 33. |
If the weight of 5 books is 7.5 kg then what will be the weight of 3 books |
|
Answer» Answer:4.5kg Step-by-step EXPLANATION: WEIGHT of 1 BOOK =7.5/5=1.5 kg Weight of 3 book =1.5*3=4.5kg |
|
| 34. |
Out of the concentric circles, the raidus of the outer circle is 5 cm and the chord AC oflength 8 cm is a tangent to the inner circle. Find the radius of the inner circle.i f he distribution given belowie 14 Aind the Holofondif the total |
|
Answer» Step-by-step explanation: LETS say centre O OA=5cm,AC/2=4cm, DIST of O fromAC =SQRT(5^2-4^2)=3 tangent to the2 inner circle so RADIUS= 3cm |
|
| 35. |
No matter what the value of s, 152 is equal to the ____value of s. |
|
Answer» Step-by-step explanation: |
|
| 36. |
A cone is 8.4 cm high and the radius of its base is 2.1 cm. It is melted and recast into a sphere. The radius of the spherel is?❤❤ |
| Answer» | |
| 37. |
In the given figure 1 = 55°, 2 = 20°, 3 = 35°, 4 = 145Prove that AB | CDDeM |
|
Answer» Answer: c ko extend kar jo angle upar banega VO angle cmn se corresponding HOGA toh cd aur mn parallel proved aurangle b 55 diya hai aur angle m ka pura sum hua 35+25 = 55 degree toh anyle b aur m altenate toh vo dono LINES bhi parallel proved to line ab is parllel to cd and mn |
|
| 38. |
How many tiles measuring 20cm.20cm each will be required to pave a 1.5m wide footpath around a grassy plot of 25m.16m? |
|
Answer» Answer: 3300 tiles Step-by-step explanation: first find the area of the footpath it will be theatres of grassy plot SUBTRACTED from the total area(plot and FOOT path) area of plot is 25×16 which is 400m square total area is 28×19 (25+3 is the length with the footpath and 16+3 is the breath with footpath) which is 532m square area of foot path is 532-400=132m square now to convert it into cm square we multiply the area with10000 so the area in cm square is 1320000 cm square now LET us find the area of the tiles area of tiles is 20×20=400cm square to find the NUMBER of tiles required we should divide the area of footpath by the area of tiles 1320000cm square ÷ 400cm square so the number of tiles required is 3300 |
|
| 39. |
Find the area of a square whose diagonal is 8 root 2 centimetre |
|
Answer» Step-by-step explanation: |
|
| 40. |
a person has Rs 280 in the form 5 rupee notes and 2 rupee notes.He gave away Rs 152 oit of this amount.Then he finds he has exactly as many five rupee notes as he gave 2 rupee notes and as many two rupee notes as he gave 5 rupee notes .How many notes of each kind he had in the beginning? |
|
Answer» Answer: Step-by-step explanation: LET the number of 10 RS note be x then no of 5 rs note = x+3 value of 10 rs note= 10x value of 5 rs note= 5(x+3) = 5X + 15 a/q 10x + 5x + 15 = 195 ⇒ 15X = 195 - 15 ⇒ x = 180/15 ∴ x = 12 so number of 10 rs note = 12 no. of 5 rs note = 12+3= 15 Read more on Brainly.in - brainly.in/question/681586#readmore |
|
| 41. |
1.2304 + 1.176425. Simplify: 5.2304 - 1.1764can you explain this question briefly |
|
Answer» Step-by-step explanation: 1.2304+1.1764=2.4068. 5.2304-1.1764=4.0540 |
|
| 42. |
I need these questions solutions |
|
Answer» Step-by-step explanation: |
|
| 43. |
A3 + b3 + c3 _ 3abe, when a=-4, b = -6) (= -2 |
|
Answer» Answer: 12-18-6 12-24 -12 |
|
| 44. |
Let us write by calculating compound interest 6250for 9 months at the rate of 10% compound interestper annum compounded at the interval of 3 months |
|
Answer» Answer: Step-by-step explanation: We know that if the rate of compound INTEREST is r% per annum and the interest is COMPOUNDED quarterly, the number of phase of compound interest in a year is 4, then the amount for n years From given, p = ₹6250, r = 10 and years ∴ Amount for 9 MONTHS or 3/4 year = ₹6730.56 ∴ Compound interest for 9 months = ₹6730.56 - ₹6250 = ₹480.56 |
|
| 45. |
The sides of a quadrilateral taken in order are 5m,12m,14mand |
| Answer» | |
| 46. |
Answer fast correctly in detail |
|
Answer» Answer: 10×10×10×10 Step-by-step EXPLANATION: mmmmmmmmmm |
|
| 47. |
AB and DC are two vertical poles placedopposite to each other at a distance of 63m from each other such that the points Band D are at ground level. If the length ofAB is 30 m and the length of CD is 14 m,find AC. (Hint: Draw CE LAB and join AC.) |
|
Answer» MARK ME BRAINLIEST FOLLOW ME |
|
| 48. |
the class mark of a frequency distribution are 15, 20, 25,...... find the class corresponding to the class mark 20 |
Answer» ANSWER:5×3=15, 5×4=20 5×5=25 5×6=30Requirement/Request: |
|
| 49. |
If , , then both the roots of the equation a. are real and negativeb. have negative real partsc. are rational numbersd. none of the above |
|
Answer» Answer: Are real and NEGATIVE. It's not always rational. |
|
| 50. |
find area of a path that rums aroumd outside a rectamgular field with a breath of 1.7 whose length and breath are 26m and 14m |
|
Answer» Answer:127.56 m sq. Step-by-step explanation:AREA of inner rectangle=24*14=384m sq. OUTER area =29.4*17.4=511.56 Area of PATH =inner -outer area 511.56-384=127.56m sq. Answer |
|