Saved Bookmarks
| 1. |
A and B individualy can do a work in 6 days and 12 days respectively. A worked for first 2 days and then left. In how many days will B finish the remaining part of the work? |
|
Answer» Answer: A left his work for = 4 days B's speed is 2 TIMES less than that of A so A's work DONE by B was in (4*2)days = 8 days B completed the work in (12+8)days =20 days . Ans.) B completed the work in 20 days. |
|