332354 + Interview Questions in Secondary School in Math

1.	Write the cofficient of x2 (2+3x2+4x )
Answer» Answer: 2 is the COEFFICIENT of above QUESTION as it is ALONE and do not CONTAIN any VARIABLE

1.

Write the cofficient of x2 (2+3x2+4x )

Answer»

Answer:

2 is the COEFFICIENT of above QUESTION as it is ALONE and do not CONTAIN any VARIABLE

Discussion

2.	Subtract 5 multiplied by 30 from 9
Answer» ANSWER: if you MULTIPLY 5×30 = 150 then 9 - 150 = -141

2.

Subtract 5 multiplied by 30 from 9

Answer»

ANSWER:

if you MULTIPLY 5×30 =

150

then 9 - 150 =

-141

Discussion

3.	What is the answer of a 22+22
Answer» Step-by-step EXPLANATION: when we ADD 22 in 22 we GET 44

3.

What is the answer of a 22+22

Answer»

Step-by-step EXPLANATION:

when we ADD 22 in 22 we GET 44

Discussion

4.	The no of roots of the equation Sinx+2sin2x=3+sin3x
Answer» we have to find the no of roots of the EQUATION, sinx + 2sin2x = 3 + sin3x solution : sinx + 2sin2x = 3 + sin3x ⇒sinx + 2sin2x = 3 + 3sinx - 4sin³x [ we know, sin3A = 3sinA - 4sin³A ] ⇒- 2sinx + 2sin2x + 4sin³x = 3 ⇒-2sinx (1 - 2sin²x) + 2sin2x = 3 using formula, COS2A = 1 - 2sin²A and sin2A = 2SINA cosA ⇒-2sinx (cos2x) + 2(2sinx cosx) = 3 ⇒-2sinx(cos2x - 2cosx) = 3 ⇒2sinx (2cosx - cos2x) = 3 here 2sinx(2cosx - cos2x) takes maximum value at X = π/3 let f(x) = 2sinx(2cosx - 2cos2x) f(π/3) = 2 × √3/2 (2 × 1/2 + 2 × 1/2) = 3√3/2 here f(π/3) = 3√3/2 < 3 it means, y = 3 never cuts at any point of graph of f(x) as you can see in figure. hence it is clear that there is no root possible of equation, sinx + 2sin2x = 3 + sin3x

4.

The no of roots of the equation Sinx+2sin2x=3+sin3x

Answer»

we have to find the no of roots of the EQUATION,

sinx + 2sin2x = 3 + sin3x

solution : sinx + 2sin2x = 3 + sin3x

⇒sinx + 2sin2x = 3 + 3sinx - 4sin³x

[ we know, sin3A = 3sinA - 4sin³A ]

⇒- 2sinx + 2sin2x + 4sin³x = 3

⇒-2sinx (1 - 2sin²x) + 2sin2x = 3

using formula, COS2A = 1 - 2sin²A

and sin2A = 2SINA cosA

⇒-2sinx (cos2x) + 2(2sinx cosx) = 3

⇒-2sinx(cos2x - 2cosx) = 3

⇒2sinx (2cosx - cos2x) = 3

here 2sinx(2cosx - cos2x) takes maximum value at X = π/3

let f(x) = 2sinx(2cosx - 2cos2x)

f(π/3) = 2 × √3/2 (2 × 1/2 + 2 × 1/2) = 3√3/2

here f(π/3) = 3√3/2 < 3

it means, y = 3 never cuts at any point of graph of f(x) as you can see in figure.

hence it is clear that there is no root possible of equation, sinx + 2sin2x = 3 + sin3x

Discussion

5.	It is given that angle XYZ =64degree and XY is produced to point P. Draw the figure from given information. If Ray YQ bisects angle ZYP,find XYQ and reflex angle QYP
Answer» Given : - It is given that angle XYZ = 64° and XY is produced to point P. DRAW the figure from given INFORMATION. If Ray YQ bisects angle ZYP. To Find : - XYQ and reflex angle QYP . Step-by-step Explanation : - XYP is a Line. ( Refer to the Attachment ) On Calculating : - y + y + 64 = 180° 2y + 64 = 180 2y = 180 - 64 2y = 116 y = 116/2 y = 58 Now : - ∠XYQ = y + 64 58 + 64 122° Reflex ∠QYP = 360° - ∠QYP 360° - 58 302°

5.

It is given that angle XYZ =64degree and XY is produced to point P. Draw the figure from given information. If Ray YQ bisects angle ZYP,find XYQ and reflex angle QYP

Answer»

Given : -

It is given that angle XYZ = 64° and XY is produced to point P. DRAW the figure from given INFORMATION. If Ray YQ bisects angle ZYP.

To Find : -

XYQ and reflex angle QYP .

Step-by-step Explanation : -

XYP is a Line.

( Refer to the Attachment )

On Calculating : -

y + y + 64 = 180°

2y + 64 = 180

2y = 180 - 64

2y = 116

y = 116/2

y = 58

Now : -

∠XYQ = y + 64

58 + 64

122°

Reflex ∠QYP = 360° - ∠QYP

360° - 58

302°

Discussion

6.	Express (2/5) as rational number with dinominator 40.
Answer» Answer: 16/40 Step-by-step EXPLANATION: $\frac{2}{5} \times \frac{8}{8}$

6.

Express (2/5) as rational number with dinominator 40.

Answer»

Answer:

16/40

Step-by-step EXPLANATION:

$\frac{2}{5} \times \frac{8}{8}$

Discussion

7.	The least and the greatest value of f(x) =x³-6x²+9x in[0,6] are
Answer» REFER to the solution and , let me KNOW if U got it right. Pls follow me .

7.

The least and the greatest value of f(x) =x³-6x²+9x in[0,6] are

Answer»

REFER to the solution and , let me KNOW if U got it right.

Pls follow me .

Discussion

8.	Add the following decamils . 3.009,0.592 ,17.5921
Answer» Answer: 3.009 +0.592 +17.5921 = 21.1932 ✌️✌️✌️✌️ check it

8.

Add the following decamils . 3.009,0.592 ,17.5921

Answer»

Answer:

3.009

+0.592

+17.5921

= 21.1932

✌️✌️✌️✌️

check it

Discussion

9.	Two adjacent angles always form a linear pair this sentence is true or false ?
Answer» It is false that, two adjacent angles always FORM a linear pair. The linear pair of angles is a pair of angles which is created by the intersection of two straight lines and the sum of a linear pair of angles is 180°. Now, if we take an angle which is LESS than 180° and bisect that angle with the help of a straight LINE, then we will get two adjacent angles. And, the sum of those two adjacent angles isn't 180°. In this WAY, we can come to a conclusion that every pair of adjacent angles will be not considered as the linear pair of angles.

9.

Two adjacent angles always form a linear pair this sentence is true or false ?

Answer»

It is false that, two adjacent angles always FORM a linear pair.

The linear pair of angles is a pair of angles which is created by the intersection of two straight lines and the sum of a linear pair of angles is 180°.
Now, if we take an angle which is LESS than 180° and bisect that angle with the help of a straight LINE, then we will get two adjacent angles. And, the sum of those two adjacent angles isn't 180°.
In this WAY, we can come to a conclusion that every pair of adjacent angles will be not considered as the linear pair of angles.

Discussion

10.	Coefficient of correlation is significant if.r>5 P.Er6 P.Er=6 P.E
Answer» ANSWER: WISH you a HAPPY NEW YEAR

10.

Coefficient of correlation is significant if.r>5 P.Er6 P.Er=6 P.E

Answer»

ANSWER:

WISH you a HAPPY NEW YEAR

Discussion

11.	5. Evaluate :(1) √441 + √169 √7441 - √169
Answer» ANSWER: USE SCIENTIFIC CALCULATOR for SHORT

11.

5. Evaluate :(1) √441 + √169 √7441 - √169

Answer»

ANSWER:

USE SCIENTIFIC CALCULATOR for SHORT

Discussion

12.	In triangle ABC BC=AB and angle B=70degree. Then angle A is equal to?
Answer» Answer: a=55 Step-by-step explanation: we know that the sum of interior angle EQUAL to 180 DEGREES so 70 minus 180 equal to 110 so divide by 2 So, we GET 55 degrees on both angles

12.

In triangle ABC BC=AB and angle B=70degree. Then angle A is equal to?

Answer»

Answer:

a=55

Step-by-step explanation:

we know that the sum of interior angle EQUAL to 180 DEGREES so 70 minus 180 equal to 110 so divide by 2

So, we GET 55 degrees on both angles

Discussion

13.	(sinA-sin2A)/(1-cosA+cos2A)
Answer» Step-by-step EXPLANATION: =( 2sinAcosA)/ COS^(2)A. = 2sinA/cosA. =2tanA ... (2sinAcosA)/(1+2cos^(2)A-1)=(2sinAcosA)/ cos ^(2)A.

13.

(sinA-sin2A)/(1-cosA+cos2A)

Answer»

Step-by-step EXPLANATION:

=( 2sinAcosA)/ COS^(2)A. = 2sinA/cosA. =2tanA ... (2sinAcosA)/(1+2cos^(2)A-1)=(2sinAcosA)/ cos ^(2)A.

Discussion

14.	A:B=3:4 B:C=6:8 find A:B:C
Answer» Answer: 9:12:16 Step-by-step EXPLANATION: The answer os GIVEN above..... PLEASE MARK it as the brainliest.

14.

A:B=3:4 B:C=6:8 find A:B:C

Answer»

Answer:

9:12:16

Step-by-step EXPLANATION:

The answer os GIVEN above..... PLEASE MARK it as the brainliest.

Discussion

15.	Can you proove 0= 1 .....
Answer» Answer: HEY BUD BRAINLIEST PLEASE ! Step-by-step explanation: There are many was to prove this : 1> Let us CONSIDER some examples : 5! = 54321 = {654321} ÷ 6 = 6! ÷ 6 4! = 4321 = {54321} ÷ 5 = 5! ÷ 5 3! = 321 = {4321} ÷ 4 = 4! ÷ 4 DID YOU NOTICE THE PATTERN? n! = (n+1)! ÷ (n+1) GOT IT ? Following this pattern, when we put n=0, we get : 0! = (0+1)! ÷ (0+1) = 1! ÷ 1 = 1 ÷ 1 = 1 → 0! = 1 (proved) 2> Let us consider some examples : 4! = 4321 = 4 * 3! 3! = 321 = 3 * 2! 2! = 21 = 2 1! DID YOU NOTICE THE PATTERN? n! =n * (n-1)! GOT IT ? putting n = 1, we get 1! = 1 * (1–1)! = 1 * 0! → 0! = (1! / 1) = (1 / 1) = 1 → 0! = 1 (proved)

15.

Can you proove 0= 1 .....

Answer»

Answer:

HEY BUD BRAINLIEST PLEASE !

Step-by-step explanation:

There are many was to prove this :

1> Let us CONSIDER some examples :

5! = 5*4*3*2*1 = {6*5*4*3*2*1} ÷ 6 = 6! ÷ 6

4! = 4*3*2*1 = {5*4*3*2*1} ÷ 5 = 5! ÷ 5

3! = 3*2*1 = {4*3*2*1} ÷ 4 = 4! ÷ 4

DID YOU NOTICE THE PATTERN?

n! = (n+1)! ÷ (n+1) GOT IT ?

Following this pattern,

when we put n=0, we get :

0! = (0+1)! ÷ (0+1) = 1! ÷ 1 = 1 ÷ 1 = 1

→ 0! = 1 (proved)

2> Let us consider some examples :

4! = 4*3*2*1 = 4 * 3!

3! = 3*2*1 = 3 * 2!

2! = 2*1 = 2 * 1!

DID YOU NOTICE THE PATTERN?

n! =n * (n-1)! GOT IT ?

putting n = 1, we get

1! = 1 * (1–1)! = 1 * 0!

→ 0! = (1! / 1) = (1 / 1) = 1

→ 0! = 1 (proved)

Discussion

16.	आठ टॉफी के तीन हिस्सों में कैसे बाटे
Answer» Answer: 2.66 Step-by-step explanation: simply DIVIDE it bro...WHATEVER u R....bro or SIS

16.

आठ टॉफी के तीन हिस्सों में कैसे बाटे

Answer»

Answer:

2.66

Step-by-step explanation:

simply DIVIDE it bro...WHATEVER u R....bro or SIS

Discussion

17.	the sum of first 4 terms of GP is 30 and that of last 4 terms is 960. If first term an last term are 2 and 512 ,find common ratio
Answer» ANSWER: Given that Sum of LAST FOUR terms is 960 and last term of GP is 512. ⇒ r = 2. Therefore, Common RATIO is 2.

17.

the sum of first 4 terms of GP is 30 and that of last 4 terms is 960. If first term an last term are 2 and 512 ,find common ratio

Answer»

ANSWER:

Given that Sum of LAST FOUR terms is 960 and last term of GP is 512. ⇒ r = 2. Therefore, Common RATIO is 2.

Discussion

18.	Using an appropriate method, find the mean of the following frequencydistribution:Classinterval84-9090-9696-102 102-108 108-114 114-120Frequency81016231211Which method did you use, and why?
Answer» Answer: Here the simplest METHOD if you DONT wanna calculate big numbers.You can use Step-deviation method i.e MEAN ( X ) = a+ (ΣFiUi/ΣFI)h where a=assumed mean , h=class SIZE,ui=Xi-a/h where a is the assumed mean, h is the class size. Hope you find this easy

18.

Using an appropriate method, find the mean of the following frequencydistribution:Classinterval84-9090-9696-102 102-108 108-114 114-120Frequency81016231211Which method did you use, and why?

Answer»

Answer:

Here the simplest METHOD if you DONT wanna calculate big numbers.You can use Step-deviation method i.e

MEAN ( X ) = a+ (ΣFiUi/ΣFI)h

where a=assumed mean , h=class SIZE,ui=Xi-a/h

where a is the assumed mean, h is the class size.

Hope you find this easy

Discussion

19.	24,5, 18.0, 12.5, 8.0,______, 2.0(1) 3.5 (2) 4.0 (3) 4.5 (4) 5.0
Answer» Answer: 1)3.5 Step-by-step explanation: 24.5-18 = 6.5 18-12.5 = 6.5 12.5-8 = 4.5 DIFFERENCE between the no.s is same TWICE , so we have to REDUCE 4.5 so , 8-4.5 = 3.5 Now , 3.5-2=1.5 So , The PATTERN is 6.5 , 6.5 , 4.5 , 4.5 , 1.5 , 1.5

19.

24,5, 18.0, 12.5, 8.0,______, 2.0(1) 3.5 (2) 4.0 (3) 4.5 (4) 5.0

Answer»

Answer:

1)3.5

Step-by-step explanation:

24.5-18 = 6.5

18-12.5 = 6.5

12.5-8 = 4.5

DIFFERENCE between the no.s is same TWICE , so we have to REDUCE 4.5

so ,

8-4.5 = 3.5

Now ,

3.5-2=1.5

So ,

The PATTERN is 6.5 , 6.5 , 4.5 , 4.5 , 1.5 , 1.5

Discussion

20.	2x-3/3 -(x- 5)/1=x/3
Answer» Step-by-step EXPLANATION: take LCM then cross multiply and find VALUE of X

20.

2x-3/3 -(x- 5)/1=x/3

Answer»

Step-by-step EXPLANATION:

take LCM then cross multiply and find VALUE of X

Discussion

21.	Base of a triangle is 9 & height is 5. Base ofanother triangle is 20 & height is 6. Findthe ratio ofof areas of these trianglesOption:(1) 3/8(2) 8/3(3) 4/10(4) 10/4
Answer» Answer: dimensions of first TRIANGLE : $b_{1}$ = 9 units $h_{1}$ = 5 units dimension of SECOND triangle: $b_{2}$ = 20 units $h_{2}$ = 6 units AREA of first triangle: $\frac{1}{2}$ * $b_{1}$ * $h_{1}$ = $\frac{1}{2}$ 95= $\frac{45}{2}$ . area of second triangle: $\frac{1}{2}$ * $b_{2}$ * $h_{2}$ = $\frac{1}{2}$ 206= $\frac{120}{2}$ . RATION of area of triangle= $\frac{area of first triangle}{area of second triangle}$ = $\frac{45/2}{120/2}$ = $\frac{45}{120}$ = $\frac{3}{8}$ therefore the right option is (1).

21.

Base of a triangle is 9 & height is 5. Base ofanother triangle is 20 & height is 6. Findthe ratio ofof areas of these trianglesOption:(1) 3/8(2) 8/3(3) 4/10(4) 10/4

Answer»

Answer:

dimensions of first TRIANGLE : $b_{1}$ = 9 units

$h_{1}$ = 5 units

dimension of SECOND triangle: $b_{2}$ = 20 units

$h_{2}$ = 6 units

AREA of first triangle: $\frac{1}{2}$ * $b_{1}$ * $h_{1}$ = $\frac{1}{2}$ 95= $\frac{45}{2}$ .

area of second triangle: $\frac{1}{2}$ * $b_{2}$ * $h_{2}$ = $\frac{1}{2}$ 206= $\frac{120}{2}$ .

RATION of area of triangle= $\frac{area of first triangle}{area of second triangle}$ = $\frac{45/2}{120/2}$ = $\frac{45}{120}$ = $\frac{3}{8}$

therefore the right option is (1).

Discussion

22.	Please help me 8+8+8+8+8+8+8+8= 1000. solve karo ans 1000 aana chaiye
Answer» Answer: 888888 I HOPE this HELPS are the ANSWERS

22.

Please help me 8+8+8+8+8+8+8+8= 1000. solve karo ans 1000 aana chaiye

Answer»

Answer:

888888 I HOPE this HELPS are the ANSWERS

Discussion

23.	Cosec^2a-cot^2a=?!dkskallaamsxnbxhdhdjfjjfkckfmdkdkelwl
Answer» ANSWER: the CORRECT answer is one Step-by-step EXPLANATION: this is a TRIGONOMETRIC FORMULA

23.

Cosec^2a-cot^2a=?!dkskallaamsxnbxhdhdjfjjfkckfmdkdkelwl

Answer»

ANSWER:

the CORRECT answer is one

Step-by-step EXPLANATION:

this is a TRIGONOMETRIC FORMULA

Discussion

24.	4/7 aur5/7 me tin parimey sankha batayie
Answer» ANSWER: I am not UNDERSTANDING what you have WRITTEN

24.

4/7 aur5/7 me tin parimey sankha batayie

Answer»

ANSWER:

I am not UNDERSTANDING what you have WRITTEN

Discussion

25.	If is a pair of linear equation 5 x minus 3 Y equal 11 - 10 X + 6 Y = -1 - 22 is a consistent
Answer» Step-by-step explanation: 5x-3y=11-10 5x-3y=1 -------(I) x+6y=-1-22 x+6y= -23 -----(II) Equating them, 5x-3y= 1 x+6y= -23 Multiplying equation ii by 5, 5x-3y=1-----(i) 5x+30y= -115 ----(III) SUBTRACTING, -33y= 116 y= - 116/33 y= - 3.51 5x- 3* (-3.51)=1 5x= 1- 10.53 5x= 9.53 x= 1.906

25.

If is a pair of linear equation 5 x minus 3 Y equal 11 - 10 X + 6 Y = -1 - 22 is a consistent

Answer»

Step-by-step explanation:

5x-3y=11-10

5x-3y=1 -------(I)

x+6y=-1-22

x+6y= -23 -----(II)

Equating them,

5x-3y= 1

x+6y= -23

Multiplying equation ii by 5,

5x-3y=1-----(i)

5x+30y= -115 ----(III)

SUBTRACTING, -33y= 116

y= - 116/33

y= - 3.51

5x- 3* (-3.51)=1

5x= 1- 10.53

5x= 9.53

x= 1.906

Discussion

26.	What is mod of x?plz ans it fast
Answer» The graph of MODULUS FUNCTION is continuous having a corner at X=0. It means that graph is differentiable at all points except at x=0 (we can not draw a tangent at a corner). Since graph is symmetric about y-axis, modulus function is even function. We also see that there are PAIR of x values for non-zero values of y. follow me

26.

What is mod of x?plz ans it fast

Answer»

The graph of MODULUS FUNCTION is continuous having a corner at X=0. It means that graph is differentiable at all points except at x=0 (we can not draw a tangent at a corner). Since graph is symmetric about y-axis, modulus function is even function. We also see that there are PAIR of x values for non-zero values of y.

follow me

Discussion

27.	If (-2,5) is a solution of 2x + my = 11, then the value of 'm' isNOO -2O O 2 23O-3
Answer» ANSWER: don't KNOW don't WANT to know

27.

If (-2,5) is a solution of 2x + my = 11, then the value of 'm' isNOO -2O O 2 23O-3

Answer»

ANSWER:

don't KNOW don't WANT to know

Discussion

28.	Factorise 2x^3 + 5x^2 + x - 2
Answer» ANSWER: ⇢ (x + 1) (2x - 1) (x + 2) Step-by-step explanation: Given:- ⇢ 2x³ + 5x² + x - 2 Find:- ⇢ Factorise the GIVE expression. Calculations:- ⇢ 2x³ + 5x² + x - 2 ⇢ (x + 1) (2x - 1) (x + 2) THEREFORE, this is the required answer.

28.

Factorise 2x^3 + 5x^2 + x - 2

Answer»

ANSWER:

⇢ (x + 1) (2x - 1) (x + 2)

Step-by-step explanation:

Given:-

⇢ 2x³ + 5x² + x - 2

Find:-

⇢ Factorise the GIVE expression.

Calculations:-

⇢ 2x³ + 5x² + x - 2

⇢ (x + 1) (2x - 1) (x + 2)

THEREFORE, this is the required answer.

Discussion

29.	When the subtracting of 2 numbers from a number is divided by 3 we get 6 then that number is what
Answer» Answer: 20 Step-by-step explanation: It is easy only. LET's TAKE the UNKNOWN number as x. According to the question:- (x-2)÷3=6 x-2=6×3 x-2=18 x=18+2 x=20 Hope it helps you. If you like it you can Mark me as the brainliest. Thank you for giving me this opportunity. if you WANT to know more answers from me means follow me. Bye

29.

When the subtracting of 2 numbers from a number is divided by 3 we get 6 then that number is what

Answer»

Answer:

20

Step-by-step explanation:

It is easy only. LET's TAKE the UNKNOWN number as x.

According to the question:-

(x-2)÷3=6

x-2=6×3

x-2=18

x=18+2

x=20

Hope it helps you.

If you like it you can Mark me as the brainliest.

Thank you for giving me this opportunity.

if you WANT to know more answers from me means follow me.

Bye

Discussion

30.	A bank pays interest of 11%. Mr. Olsen puts $5000in the bank.How much has he afterOne year Two yearThree year
Answer» Answer: SIMPLE INTEREST $5550, 6100, 6650 COMPOUND INTEREST $5550, 6160.50, 6838.16 Step-by-step explanation: As you have not mentioned whether interest is simple or compound, I have SOLVED for both. You can choose the correct one. SIMPLE INTEREST P=5000, R=11%, T= 1, 2 & 3 SI=PRT/100 SI1=5000 x 11 x 1/100 =550 A1= P + SI1 = 5000 + 550 = 5550 SI2 = 5000 x 11 x 2/100 =1100 A2=5000 + 1100 = 6100 SI3 = 5000 x 11 x 3/100 = 1650 A3= 5000 + 1650 = 6650 COMPOUND INTEREST R=11%, P = 5000, n= 1, 2 & 3 A=P(1+R/100)^n A1=5000(1+11/100)^1 = 5000x1.11 = 5550 TWO years A2=5000(1+11/100)^2 =5000 x 1.2321 = 6160.50 THREE years A3=5000(1+11/100)^3 =5000 x 1.367631 = 6838.155 ≈6838.16

30.

A bank pays interest of 11%. Mr. Olsen puts $5000in the bank.How much has he afterOne year Two yearThree year

Answer»

Answer:

SIMPLE INTEREST $5550, 6100, 6650

COMPOUND INTEREST $5550, 6160.50, 6838.16

Step-by-step explanation:

As you have not mentioned whether interest is simple or compound, I have SOLVED for both.

You can choose the correct one.

SIMPLE INTEREST

P=5000, R=11%, T= 1, 2 & 3

SI=PRT/100

SI1=5000 x 11 x 1/100

=550

A1= P + SI1 = 5000 + 550 = 5550

SI2 = 5000 x 11 x 2/100

=1100

A2=5000 + 1100 = 6100

SI3 = 5000 x 11 x 3/100 = 1650

A3= 5000 + 1650 = 6650

COMPOUND INTEREST

R=11%, P = 5000, n= 1, 2 & 3

A=P(1+R/100)^n

A1=5000(1+11/100)^1

= 5000x1.11 = 5550

TWO years

A2=5000(1+11/100)^2

=5000 x 1.2321 = 6160.50

THREE years

A3=5000(1+11/100)^3

=5000 x 1.367631 = 6838.155 ≈6838.16

Discussion

31.	In the circuit given below would anyone blue one plug key is in
Answer» ANSWER: HEY I THINK you forgot to give the diagram of circuit here is no FIGURE.

31.

In the circuit given below would anyone blue one plug key is in

Answer»

ANSWER:

HEY I THINK you forgot to give the diagram of circuit here is no FIGURE.

Discussion

32.	If ∆SDP, angle S =72°, angle D=28°, angle P=?
Answer» PLEASE BRAINLIST my ANSWER

Discussion

33.	One obtuse angle and one acute angle can make a pair of complementary anglesTrue or FalsePlease answer the question
Answer» ANSWER: THE ANSWER IS FALSE

33.

One obtuse angle and one acute angle can make a pair of complementary anglesTrue or FalsePlease answer the question

Answer»

ANSWER:

THE ANSWER IS FALSE

Discussion

34.	-10Simplify:xX Х21x(-69सिंपलीफाई माइनस 3 बाय 5 * - 10 बाय 9 * 15 - 4 * - 6
Answer» Answer: did not MATCH any documents. Suggestions: Make SURE that all words are spelled correctly. Try different KEYWORDS. Try more GENERAL keywords. Try fewer keywords.

34.

-10Simplify:xX Х21x(-69सिंपलीफाई माइनस 3 बाय 5 * - 10 बाय 9 * 15 - 4 * - 6

Answer»

Answer:

did not MATCH any documents.

Suggestions:

Make SURE that all words are spelled correctly.

Try different KEYWORDS.

Try more GENERAL keywords.

Try fewer keywords.

Discussion

35.	a rectangular sheet of paper of dimensions 25cm×22cm is rolled along its width to form a cylinde.find the volume of the cylinder so formed
Answer» PLEASE MARK as brainliest if the answer is HELPFUL :) KEEP learning!

Discussion

36.	Is theWhich of the followingadditivejpurse of -39?
Answer» ANSWER: The ADDITIVE jpures of-39 is 39

36.

Is theWhich of the followingadditivejpurse of -39?

Answer»

ANSWER:

The ADDITIVE jpures of-39 is 39

Discussion

37.	Find six rational numbers between 3 and 4.
Answer» ANSWER: 1/9 2/9 2/9 4/9 5/9 6/9 mutiply by 3

37.

Find six rational numbers between 3 and 4.

Answer»

ANSWER: 1/9
2/9
2/9
4/9
5/9
6/9

mutiply by 3

Discussion

38.	Y=\|x+3\| solution moduler answer
Answer» ANSWER: y-x=3 y+x=3 USING both equaequat2y=6 y=3 & x=0

38.

Y=|x+3| solution moduler answer

Answer»

ANSWER:

y-x=3

y+x=3

USING both equaequat2y=6

y=3 & x=0

Discussion

39.	Simplify:(i) (4x + 2y)³ +(4x – 2y)³
Answer» If my ANSWER is SATISFIED you then PLEASE MARK me as BRAINLIEST

39.

Simplify:(i) (4x + 2y)³ +(4x – 2y)³

Answer»

If my ANSWER is SATISFIED you then PLEASE MARK me as BRAINLIEST

Discussion

40.	3 ti bognagser jogfol koto
Answer» ANSWER: gadffdeewswdryipogvjki

40.

3 ti bognagser jogfol koto

Answer»

ANSWER:

gadffdeewswdryipogvjki

Discussion

41.	a postman delivered 28573 letters in January and 12391 letters in febuary .how many letters did he deliever in two months . ans is 41144he iska ans
Answer» Step-by-step EXPLANATION: POSTMAN DELIVERS 40964in TWO MONTHS

41.

a postman delivered 28573 letters in January and 12391 letters in febuary .how many letters did he deliever in two months . ans is 41144he iska ans

Answer»

Step-by-step EXPLANATION:

POSTMAN DELIVERS 40964in TWO MONTHS

Discussion

42.	7/3 ÷ 2 is equal to
Answer» $= \frac{7}{3} \div 2 \\ = \frac{7}{3} \div \frac{2}{1} \\ = \frac{7}{3} \times \frac{1}{2} = \frac{7}{6}$ $ItzCottonCandy❤$

42.

7/3 ÷ 2 is equal to

Answer»

$= \frac{7}{3} \div 2 \\ = \frac{7}{3} \div \frac{2}{1} \\ = \frac{7}{3} \times \frac{1}{2} = \frac{7}{6}$

$ItzCottonCandy❤$

Discussion

43.	If 4 girls takes 2(1/2) hours to complete a job, how much time is required for 3 girls to finish the job, working at the same rate of performance?
Answer» Answer: ANS =1day Step-by-step explanation: Time taken by 5 CHILDREN to COMPLETE the job = 5 20 days =4 days ∴ Time taken by 4 men to complete the job =(4×2) days =8 days Time taken by 4 women to the complete the job =(8×2) days =16 days Therefore, 5 children's 1 day's work = 4 1 4 men's 1 day's work = 8 1 4 women's 1 day's work = 16 1 ∴ (12 men's + 10 children's + 8 women's ) 1 day's work =3× (4 men's 1 day's work) +2× (5 children's 1 day's work) +2× (4 women's 1 day's work) =3× 8 1 +2× 4 1 +2× 16 1 = 8 3 + 2 1 + 8 1 = 8 8 =1 ∴ Required time =1 day. mark me brainliest

43.

If 4 girls takes 2(1/2) hours to complete a job, how much time is required for 3 girls to finish the job, working at the same rate of performance?

Answer»

Answer:

ANS =1day

Step-by-step explanation:

Time taken by 5 CHILDREN to COMPLETE the job =

5

20

days =4 days

∴ Time taken by 4 men to complete the job =(4×2) days =8 days

Time taken by 4 women to the complete the job =(8×2) days =16 days

Therefore, 5 children's 1 day's work =

4

1

4 men's 1 day's work =

8

1

4 women's 1 day's work =

16

1

∴ (12 men's + 10 children's + 8 women's )

1 day's work =3× (4 men's 1 day's work) +2× (5 children's 1 day's work) +2× (4 women's 1 day's work)

=3×

8

1

+2×

4

1

+2×

16

1

=

8

3

+

2

1

+

8

1

=

8

=1

∴ Required time =1 day.

mark me brainliest

Discussion

44.	The length of a rectangularn
Answer» ANSWER: MARK me as BRAINLEAST...

44.

The length of a rectangularn

Answer»

ANSWER:

MARK me as BRAINLEAST...

Discussion

45.	2(x^2-6)=3(x-4)solution plzz
Answer» ANSWER: x= 3/4 Step-by-step explanation: 4x²-12=3x-12 4x²-3x = -12+12 4x²-3x= 0 4x²=3x 4x²/x = 3 4x = 3 x = 3/4 Hope this answer HELPED you buddy Please mark my answer as brainliest Please follow me... I will follow you back

45.

2(x^2-6)=3(x-4)solution plzz

Answer»

ANSWER:

x= 3/4

Step-by-step explanation:

4x²-12=3x-12

4x²-3x = -12+12

4x²-3x= 0

4x²=3x

4x²/x = 3

4x = 3

x = 3/4

Hope this answer HELPED you buddy

Please mark my answer as brainliest

Please follow me... I will follow you back

Discussion

46.	Find the roots using method of completing the square 6x²+7x-10=0
Answer» Step-by-step EXPLANATION: I HOPE this ANSWER MAY HELP you

46.

Find the roots using method of completing the square 6x²+7x-10=0

Answer»

Step-by-step EXPLANATION:

I HOPE this ANSWER MAY HELP you

Discussion

47.	volume of cube is 5832 m³ cube find the cost of painting its total surface at rate of rupees 3.50 per metre
Answer» Answer: rupees 378 Step-by-step explanation: volume = a^3 = 5832 side=a=18 total SURFACE area = 6a = 618= 108m^2 COST of painting per metre = 3.50 cost of painting 108m^2 = 108 *3.50 =rupees 378

47.

volume of cube is 5832 m³ cube find the cost of painting its total surface at rate of rupees 3.50 per metre

Answer»

Answer:

rupees 378

Step-by-step explanation:

volume = a^3 = 5832

side=a=18

total SURFACE area = 6*a

= 6*18= 108m^2

COST of painting per metre = 3.50

cost of painting 108m^2 = 108 *3.50 =rupees 378

Discussion

48.	99 7603write in word
Answer» NINE LAKHS ninty SEVEN THOUSAND SIX hundred and three

48.

99 7603write in word

Answer»

NINE LAKHS ninty SEVEN THOUSAND SIX hundred and three

Discussion

49.	Which of the following is theadditive jrvcse of -32 ?7
Answer» Answer: 32 is ADDITIVE INVERSE of -32 b/C IF WE ADD both we get 0 which is additive inverse RULE

49.

Which of the following is theadditive jrvcse of -32 ?7

Answer»

Answer:

32 is ADDITIVE INVERSE of -32 b/C IF WE ADD both we get 0 which is additive inverse RULE

Discussion

50.	Out of given triplets, which is notPythagoreantripletOption:(1) 3,4,5(2) 24,70,74(3) 10,24,27(4) 11,60,61
Answer» Answer: 3rd option is not a PYTHAGOREAN TRIPLET Step-by-step EXPLANATION: Since 27² = 729 And 24² + 10² = 576 + 100 = 676 ∴ 676≠729 ∴ 10,24,27 is not a Pythagorean triplet

50.

Out of given triplets, which is notPythagoreantripletOption:(1) 3,4,5(2) 24,70,74(3) 10,24,27(4) 11,60,61

Answer»

Answer:

3rd option is not a PYTHAGOREAN TRIPLET

Step-by-step EXPLANATION:

Since 27² = 729

And 24² + 10² = 576 + 100 = 676

∴ 676≠729

∴ 10,24,27 is not a Pythagorean triplet

Discussion

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