1.

Base of a triangle is 9 & height is 5. Base ofanother triangle is 20 & height is 6. Findthe ratio ofof areas of these trianglesOption:(1) 3/8(2) 8/3(3) 4/10(4) 10/4​

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Answer:

dimensions of first TRIANGLE : b_{1} = 9 units

                                                  h_{1}= 5 units

dimension of SECOND triangle: b_{2}= 20 units

                                                    h_{2}= 6 units

AREA of first triangle: \frac{1}{2} * b_{1}* h_{1} = \frac{1}{2} *9*5= \frac{45}{2}.

area of second triangle:  \frac{1}{2} *b_{2}* h_{2}=  \frac{1}{2}*20*6= \frac{120}{2}.

RATION of area of triangle= \frac{area of first triangle}{area of second triangle} = \frac{45/2}{120/2} =\frac{45}{120} =\frac{3}{8}

therefore the right option is (1).


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