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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Any point in the bisector of an angle |
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Answer» Step-by-step explanation: The ANGLE bisector theorem STATES that if a point is on the bisector of an angle, then the point is equidistant from the SIDES of the angle. The angle bisector theorem converse states that if a point is in the INTERIOR of an angle and equidistant from the sides, then it lies on the bisector of that angle. Hope it helps you |
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| 4. |
Plz plz plz plz help anyone answer this its urgent. |
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Answer» ANGLE QAC=180-127=53 angle A=180-50-53=77 DEGREE |
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| 5. |
# Tagent XY at a point X of a circle of readius 5 cmmeets a line through the center o at a point Y sothat oy = 13cm. find the length of xy. |
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Answer» Answer: Step-by-step explanation: DeterminePS A. 2Ö3cm B. 4Ö6cm C. 2Ö6cm D. 8Ö6cm E. 8cm 8. Given that cos z = L, where z is an acute angle find an expression for CO +Z - cosecz sec Z + tan z A. l - L B. L2-Ö1-L2 C. -L-Ö1-L 1+L L2+L-1 (C1+L) +Ö1-L2 D. ÖL-1. E. L-(L2-1) (L1+L2) +Ö1-L2 1+ Ö1 - L2+ Ö1 - L2 9. If 0.0000152 x 0.00042 =Ax108,where 1 £A< 10, findAand B. A. A= 9, B= 6`.38 B. A= 6.38, B = -9 C. A= 6.38, B = 9 D. A= 6.38, B = -1 E. A= 6.38, B= 1 10. If x + 2 and x – 1 are factors of the expressions lx + 2kx2 + 24, find the VALUES of l and k A. l=-6,k=-9 B. l=-2,k= 1 C. l=-2,k=-1 D. l=0,k= 1 E. l=6,k= 0 11. Make T the subject of the equation av = 3 2V + T 1- V a 2T A. 3av/(1-v) B. 2v(1-v)2 - a2v2/2a2v2 - (1-V)2 C. 2v(1 - v)2 + a3v2/ 2a2v2 + (1 - v)2 D. 2v(1 - v)2 - a4v3/2a3v3 - (1 - v)3 E. 2v(1-v)3 - a4v3/2a3v3 + (1-v)3 12. In a class of 60 pupils, the statisticahope it helps:) |
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| 6. |
550 me se 316 number 550 me se 302 number ab 550 me se mark obtain kya hoga |
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Answer» what IDONT UNDERSTAND your QUESTION |
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| 7. |
Factorise using idenrtity (a+b)^2 and (a-b)^2 x^2+2+1/x^2 |
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Answer» |
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| 8. |
The additive inverse of -3/4 |
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Answer» Answer: 3/4 here's the answer FRIEND PLS FOLLOW me and MARK as brainliest |
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| 9. |
Find the value of and choose the correct option |
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Answer» Answer: |
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| 10. |
95. Measures of three angles of a Ale are 2x",( 3x + 15 ) and ( 8x - 30 ) then the measures of angles are ---a. 30, 60, 90 b. 45, 45, 90 c. 60, 60, 60 d. none of these. |
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Answer»
13x+(-15)=180 13x=180+15 13x=195 x=195÷13 x=15 .°.2x, 3x+15, 8x-30 = 30, 60, 90 |
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| 11. |
Represent the following number inthe scientific notation. (1) 0.0000005 |
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Answer» Answer: 5*10^-7hope u GOT ur answer PLZZ MARK me as the BRAINLIEST |
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| 12. |
What is the uper limit of the modal (10-30) |
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| 13. |
Please tell the solution of the above question.....pelae please please..... I request u to all I mark as brain list and follow, like...... and I rate ur answer also.....thanks in advance who gave me answer of this question.... |
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Answer» A=60 180-120=60 by CORRESPONDING ANGLE A=60° |
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| 14. |
3km using an interval of 10m |
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Answer» Step-by-step explanation: 13m please FOLLOW mepleaseplease |
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| 15. |
5 numbers between 3/4. 4/5 expansi |
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Answer» Answer: 3/3.5,3/4.1,3/4.2,3/4.3,/3/4.4 |
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| 16. |
The graph of the equation2x + 3y = 5 which line |
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Answer» do yourself and MAKE me BRAINLIEST |
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| 18. |
18-(+36)+(-20) |
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Answer» So what is the QUESTION then DEAR ?? |
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| 19. |
Comprehension of the poetry keeping quiet |
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Answer» Answer: ANS. The poet wants to SAY that we should stop our WORLDLY activities for a few moments and do some QUIET introspection. ... The poet wants us to stop all our activities for a few moments - only for as long as it will TAKE to count to twelve. |
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| 20. |
Find the difference between the simple interest and compound interest on Rs. 22,000 for 2 years at6% per annum, compound interest being reckoned semi-annually. |
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Answer» Step-by-step explanation: The difference between the compound interest and the simple interest on Rs.42000 for two years is Rs.105 at the same RATE of interest per annum. FIND (i) the rate of interest (ii) the compound interest EARNED in second year. MEDIUM Help best friend Study later ANSWER P = Rs 42000 T=2 years Let rate = r % S.I= 100 PRT
= 100 42000×r×2
=840 Rs For C.I A=P(1+ 100 r
) n
=42000(1+ 100 r
) 2
=42000(1+ 10000 r 2
+ 50 r
) =42000+ 10 42r 2
+840r C.I = A - P =42000+ 10 42r 2
+840r−42000 = 10 42r 2
+840r Given C.I−S.I=105 = 10 42r 2
+840r−840r=105 = 10 42r 2
=105 =42r 2 =1050 =r 2 =25 r=5% C.I at 2nd year = 42000(1+ 100 5
) 2 −42000 =42000(1.1025−1)=4305 Rs |
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| 23. |
Recall,π is defined as the ratio of the circumference (say c) of a circle to its diameter (say d) . that is,π=c/d. this seems to contradict the fact that π is irrational. how will you resolve this contradiction? |
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Answer» Answer: SOLUTION:c/d=22/7 is the APPROXIMATE value of π and ALSO it is non TERMINATING |
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| 24. |
3(x+y)-9(x+y)^2 factorise |
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Answer» |
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| 25. |
Solve factorisation method2 x 2 + 7 x +5√2=0 |
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Answer» x=7.64 Step-by-step explanation: 4+7x+5√2=0 7x=(-5√2)-4 x= -5√2-4/7 x=7.64 |
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| 27. |
सहा विकप(i) 2/5 एवं 3/7 के बीच उपस्थित परिमेय संख्यायें हैं-(a) एक(d) असंख्य(b) दो(c) पांच |
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Answer» (d) असंख्य . |
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| 29. |
The lines 2x-3y = 5 and 3x-4ydiameters of a circle of area 1Then equation of circle is1) (x + 1)2 +(y+1)2 = 492) (x - 1)2 + (y – 1)2 = 493) (x - 1)2 +(y + 1)2 = 494) (x+1)2 +(y – 1)2 = 49 |
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Answer» Center is the point of intersection of diagonals. ⇒2x−3y=5 ⇒3x−4y=7 Solving SIMULTANEOUS EQUATION, x=1,y=−1 Center =(1,−1) For radius r ( LET ) ⇒r=π154 ⇒22154×7=7 Equation - ⇒(x−1)2+(y+1)2=72 ⇒x2+1−2x+y2+1+2y=49 ⇒x2+y2−2x+2y=49−2 ⇒x2+y2−2x+2y=47 Hence, the answer is x2+y2−2x+2y=47. |
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| 30. |
Find the value of k if one of the zeroes of a quadratic polynomial x*2+3x+k is 4 |
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Answer» answer is -20 hope this HELPS you |
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| 31. |
find the sign of product ifwe multiply together .[ A] 8 positive and 5 negaive integers .[ B] 5 positive and 6 negative integegers [C] 7 negative and 4 positive integers . gyss please tell me the right answer of this |
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Answer» (A) NEGATIVE, (C) Negative. |
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| 32. |
After rational sing the denominator of 2/√5-√3, we get1. 2√5+ 2√32.√10+ √63. √5+ √34. √5- √3 |
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Answer» Step-by-step EXPLANATION: |
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| 33. |
X/2-2=4+1/4 please tell answer |
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Answer» Let's SOLVE your equation step-by-step. Step 1: Simplify the equation. ⇒ ⇒ ⇒ ⇒ Step 2: ADD 2 to both sides. ⇒ ⇒ ⇒ ⇒ Step 3: Cross Multiply ⇒ ⇒ Step 4: Divide both sides by 4. ⇒ ⇒ ⇒ ⇒ ⇒ Verification if x = 12.5 ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ Additional Information :)What is an equation? A mathematical statement which CONSISTS of an equal sign between two ALGEBRAIC expressions is known as an algebraic equation. What does an equation consist of? An equation mainly consists of three parts. They are =>
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| 34. |
इस p(x)इक्वल टू एक्स प्लस 5 then p(x) +p(-x)= |
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Answer» |
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| 35. |
Plz help me out in this question |
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Answer» 32 Step-by-step explanation:
dhvdcsgshhxubes hxhhebbdj
ujghjjj
plz mark me as brainlist plz ur the great person plz thank my answer by pressing the HEART |
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| 36. |
What kind of day dose the poetPrefer sailing in the poemSea Feven,? |
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Answer» Along with windy day what does the poet want during his sea voyage? Ans. During his sea voyage the poet along with a windy day wants to ENJOY white CLOUDS flying, SCATTERED water particles, foam and FROTH and the cry of the sea-gulls. |
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| 37. |
The non terminating recurringdecimal form of7/6 is |
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Answer» Answer: 1.166666....... it should be your answer please FOLLOW me and MARK me as BRAINLIEST |
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| 38. |
Find the value of the given number (198)² |
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Answer» me as BRAINLIEST |
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| 39. |
لغو عفت وعن جي پی و3x + y = 10. then the value of a isYour answer |
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Answer» I couldn't UNDERSTAND what you WANT to SAY about it. |
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| 40. |
Using prime factorization find the HCF and LCM 144 198 |
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Answer» Answer: The prime FACTORIZATION of 144 is 2 x 2 x 2 x 2 x 3 x 3 The prime factorization of 198 is 2 x 3 x 3 x 11 It's LCM is 2 x 2 x 2 x 2 x 3 x3 x 11 = 1,584 It's HCF is 2 x 3 x 3 = 18. Step-by-step explanation: |
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| 41. |
What as the 30th term of 15, 12.9 |
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| 42. |
875900cancellation |
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Answer» Answer: -25 Step-by-step explanation: its very SIMPLE FIRST of all cancel 875 from 900 so the answer is 25 then TURN it into -25 |
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| 43. |
The Present value of a car is R 70,000 .Its value depreciates every year by 10%.what will be its value after 2years |
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Answer» Step-by-step EXPLANATION: I feel this machine is depreciated using the REDUCING BALANCE Method. If the value of the machine at the beginning of year 1 is 10,000 and then it reduces by 10%, the value of the machine at the end of year 1 is: 10,000 * (100%-10%) = 9,000 And again, at the end of Year 2, we follow a SIMILAR route: 9000 *(100%-10%) = 8,100 i hope this is helpfull for you so please follow me and mark me as brainlist |
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| 44. |
No.2 and no.5 and no.8 sentence making |
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Answer» HI friends to you as well but we can get it DONE today for a notes from last NIGHT so much fun day of my life my collection is an important factor is an important factorbsihejsbsjhsuzh sbsjbdv nshd BD bdhr the day ಹೇ ರಾಮ್ ಗೋಪಾಲ್ ಾಯ್ |
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| 45. |
Find the median of the following data 27, 39, 49, 20, 21, 28 and 38 . |
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Answer» Answer: Step-by-step explanation: MEDIAN=middle observation of the DATA. =Arrange the data in ASCENDING or descending order. =28 HOPE IT HELPS! PLZ MARK BRAINLIEST! |
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| 46. |
Factorisation6. (i) 6x2 + 11x - 10(ii) 5 - 4x - 12x2(ii) 12x2 - x - 35(ii) 3x2 - 5xy - 12y2(ii) 10p2q2 - 21pq + 9(ii) x(12x + 7) - 105. (1) 14x2 – 23x + 87. (1) 1 - 18y - 63y28. (1) x2 – 3xy - 40y29. (1) 2a2b2 + ab - 45[Hint. (ii) x(12x + 7) - 10 = 12x2 + 7x - 1)10. (1) (a + b)2 – 11(a + b) – 4211. (i) (x - 2y)2 – 6(x – 2y) + 5(ii) 8 + 6(p+q) - 5(p+q)2(ii) 7 + 10(2x – 3y) - 8(2x - 3y)2 |
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Answer» Answer: (2) x= -5/6or x= 1/2 |
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| 47. |
+sec²40°-cot²50°)/(sin²40°+sin²50°)-2cos60°sin20°sec70° |
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| 48. |
Plz plz plz plz help anyone answer this its urgent. i think option 1 |
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| 49. |
Write down a pair of integer whose b) differrnce is -10 |
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Answer» Answer: 10, 20 Step-by-step EXPLANATION: 10-20= -10 |
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