1.

The lines 2x-3y = 5 and 3x-4ydiameters of a circle of area 1Then equation of circle is1) (x + 1)2 +(y+1)2 = 492) (x - 1)2 + (y – 1)2 = 493) (x - 1)2 +(y + 1)2 = 494) (x+1)2 +(y – 1)2 = 49​

Answer»

ANSWER:

Center is the point of intersection of diagonals.

⇒2x−3y=5

⇒3x−4y=7

Solving SIMULTANEOUS EQUATION, x=1,y=−1

Center =(1,−1)

For radius r ( LET )

⇒r=π154  ⇒22154×7=7

Equation -

⇒(x−1)2+(y+1)2=72

⇒x2+1−2x+y2+1+2y=49

⇒x2+y2−2x+2y=49−2

⇒x2+y2−2x+2y=47

Hence, the answer is x2+y2−2x+2y=47.


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