332354 + Interview Questions in Secondary School in Math

1.	What sholud be subtracted from 1 to get -3/16
Answer» Answer: $x=\frac{19}{16}$ or $1.1875$ Step-by-step explanation: LET the NUMBER be 'x' $1-x=\frac{-3}{16}$ $16(1-x)=-3$ $16-16x=-3$ $-16x=-3-16$ $-16x=-19$ $x=\frac{-19}{-16}$ $x=\frac{19}{16}$ or $1.1875$ Thank You Plz mark my answer as BRAINLIEST

1.

What sholud be subtracted from 1 to get -3/16

Answer»

Answer:

$x=\frac{19}{16}$ or $1.1875$

Step-by-step explanation:

LET the NUMBER be 'x'

$1-x=\frac{-3}{16}$

$16(1-x)=-3$

$16-16x=-3$

$-16x=-3-16$

$-16x=-19$

$x=\frac{-19}{-16}$

$x=\frac{19}{16}$ or $1.1875$

Thank You

Plz mark my answer as BRAINLIEST

Discussion

2.	If cos 2A = tan-B, then show that cos 2B = tan-A.In ABC, prove that
Answer» ANSWER: ......mmmmggngtfcgbg H

2.

If cos 2A = tan-B, then show that cos 2B = tan-A.In ABC, prove that

Answer»

ANSWER:

......mmmmggngtfcgbg H

Discussion

3.	If 2x² + 2y² - 2x + 2y +1 = 0. Find x+y
Answer» Answer: x² + y² - 14x + 2y + 2xy + 17 = 0 4x² + y² - 4XY + 104x + 148y - 124 = 0 Step-by-step explanation: (1) Given Equation is x = y - 1 It can be written as, x - y = -1 ---- (i) -y = -x - 1 y = x + 1 ∴ Slope = 1. ∴ Slope of axis = -1. Equation of axis is y - 1 = -1(x - 2) y - 1 = -x + 2 y - 1 + x - 2 = 0 x + y - 3 = 0 ---- (ii) On solving (i) & (ii), we get x - y = -1 x + y = 3 ------------ 2X = 2 x = 1 Substitute x = 1 in (i), we get x - y = -1 1 - y = -1 y = 2 ∴ The directrix and axis intersects at A(1,2) LET h(s,k) be the focus of parabola. ∴ V(2,1) is the mid-point of AS. ∴ 2 = 1 + h/2 and 1 = 2 + k/2 h = 3, k = 0. ∴ Focus is S(3,0). Let P(x,y) be any point on parabola. PS = PM ⇒√(x - 3)² + (y - 0)² = \|x -y + 1/√1 + 1\| On Squaring both sides, we get ⇒ (x - 3)² + y² = (x - y + 1)^2/2) ⇒ x² + 9 - 6y + y² = x² + y² + 1 - 2xy - 2y + 2x/2 ⇒ 2x² + 18 - 12y + 2y² = x² + y² + 1 - 2xy - 2y + 2x ⇒ x² + y² - 14x + 2y + 2xy + 17 = 0 -------------------------------------------------------------------------------------------- (2) Let the focus be S(-6,-6) and vertex be A(-2,2) Let z(x,y) be the projection of S on directrix. A is the mid-point of SZ. ⇒ (-2,2) = (-6 + x/2, -6 + y/2) ⇒ x = 2, y = 10. ∴ Z = (2,10) Slope of directrix = -1/(-6 - 2/-6 + 2) = -1/2.. Equation of directrix is y - 10 = -1/2(x - 2) ⇒ 2y - 20 = -x + 2 ⇒ 2y - 20 + x - 2 = 0 ⇒ x + 2y - 22 = 0. Let P(x,y) be any point on the parabola, then SP = PM SP² = PM²{PM is the perpendicular from P to the directrix} ⇒ (x + 6)² + (y + 6)² = (x+ 2y - 22)²/1² + 4 ⇒ x² + 36 + 12x + y² + 36 + 12y = x² + 4xy - 44x + 4y² - 88y + 484/5 ⇒ 5(x² + 36 + 12x + y² + 36 + 12y) = x² + 4xy - 44x + 4y² - 88y + 484 ⇒ 5x² + 60x + 5y² + 60Y + 360 = x² + 4xy - 44x + 4y² - 88y + 484 ⇒ 5x² + 104x - 4yx + y² + 148y - 124 - x² = 0 ⇒ 4x² + y² - 4xy + 104x + 148y - 124 = 0 (or) (2x - y)² + 104x + 148y - 124 = 0 Hope it helps!

3.

If 2x² + 2y² - 2x + 2y +1 = 0. Find x+y

Answer»

Answer:

x² + y² - 14x + 2y + 2xy + 17 = 0

4x² + y² - 4XY + 104x + 148y - 124 = 0

Step-by-step explanation:

(1)

Given Equation is x = y - 1

It can be written as, x - y = -1 ---- (i)

-y = -x - 1

y = x + 1

∴ Slope = 1.

∴ Slope of axis = -1.

Equation of axis is y - 1 = -1(x - 2)

y - 1 = -x + 2

y - 1 + x - 2 = 0

x + y - 3 = 0 ---- (ii)

On solving (i) & (ii), we get

x - y = -1

x + y = 3

------------

2X = 2

x = 1

Substitute x = 1 in (i), we get

x - y = -1

1 - y = -1

y = 2

∴ The directrix and axis intersects at A(1,2)

LET h(s,k) be the focus of parabola.

∴ V(2,1) is the mid-point of AS.

∴ 2 = 1 + h/2 and 1 = 2 + k/2

h = 3, k = 0.

∴ Focus is S(3,0).

Let P(x,y) be any point on parabola.

PS = PM

⇒√(x - 3)² + (y - 0)² = |x -y + 1/√1 + 1|

On Squaring both sides, we get

⇒ (x - 3)² + y² = (x - y + 1)^2/2)

⇒ x² + 9 - 6y + y² = x² + y² + 1 - 2xy - 2y + 2x/2

⇒ 2x² + 18 - 12y + 2y² = x² + y² + 1 - 2xy - 2y + 2x

⇒ x² + y² - 14x + 2y + 2xy + 17 = 0

--------------------------------------------------------------------------------------------

(2)

Let the focus be S(-6,-6) and vertex be A(-2,2)

Let z(x,y) be the projection of S on directrix. A is the mid-point of SZ.

⇒ (-2,2) = (-6 + x/2, -6 + y/2)

⇒ x = 2, y = 10.

∴ Z = (2,10)

Slope of directrix = -1/(-6 - 2/-6 + 2)

= -1/2..

Equation of directrix is y - 10 = -1/2(x - 2)

⇒ 2y - 20 = -x + 2

⇒ 2y - 20 + x - 2 = 0

⇒ x + 2y - 22 = 0.

Let P(x,y) be any point on the parabola, then

SP = PM

SP² = PM²{PM is the perpendicular from P to the directrix}

⇒ (x + 6)² + (y + 6)² = (x+ 2y - 22)²/1² + 4

⇒ x² + 36 + 12x + y² + 36 + 12y = x² + 4xy - 44x + 4y² - 88y + 484/5

⇒ 5(x² + 36 + 12x + y² + 36 + 12y) = x² + 4xy - 44x + 4y² - 88y + 484

⇒ 5x² + 60x + 5y² + 60Y + 360 = x² + 4xy - 44x + 4y² - 88y + 484

⇒ 5x² + 104x - 4yx + y² + 148y - 124 - x² = 0

⇒ 4x² + y² - 4xy + 104x + 148y - 124 = 0

(or)

(2x - y)² + 104x + 148y - 124 = 0

Hope it helps!

Discussion

4.	Find the product using suitable rearrangement (-17 ) × (-10) × 9
Answer» ANSWER: 170*9=153 CHECK the answer

4.

Find the product using suitable rearrangement (-17 ) × (-10) × 9

Answer»

ANSWER:

170*9=153

CHECK the answer

Discussion

5.	Cycle parts tools in photos
Answer» ANSWER: this is a CYCLE PARTS TOOLS

5.

Cycle parts tools in photos

Answer»

ANSWER:

this is a CYCLE PARTS TOOLS

Discussion

6.	There is a narrow rectangular plot reserved for a school, in a city. The length & breadth of the plot are in the ratio 15:7.at the the rate of Rs. 100per metre it will cost Rs. 44000 to fence the plot. What are the dimensions of the plot
Answer» Step-by-step explanation: Let, the TOTAL cost of fencing plot=Rs..44000. and the rate of fencing =Rs..100/m^2. thus, the area of a plot =total cost of fencing. ÷ rate of fencing. => 44000/100 =440m^2. then, their dimension of plot = length=15X and breadth=7x. thus, the aera of plot =440m^2. 15x × 7x =440m^2. 105x^2 =440m^2. x^2=440/105 =88/21=4.19m. x=√4.19 =2.04m. hence, length=152.04=30.6m. and breadth=72.04=14.28m. proved.... Thanks❤❤❤. follow me....

6.

There is a narrow rectangular plot reserved for a school, in a city. The length & breadth of the plot are in the ratio 15:7.at the the rate of Rs. 100per metre it will cost Rs. 44000 to fence the plot. What are the dimensions of the plot

Answer»

Step-by-step explanation:

Let, the TOTAL cost of fencing plot=Rs..44000.

and the rate of fencing =Rs..100/m^2.

thus, the area of a plot =total cost of fencing. ÷ rate of fencing.

=> 44000/100 =440m^2.

then, their dimension of plot =

length=15X and breadth=7x.

thus, the aera of plot =440m^2.

15x × 7x =440m^2.

105x^2 =440m^2.

x^2=440/105 =88/21=4.19m.

x=√4.19 =2.04m.

hence, length=15*2.04=30.6m.

and breadth=7*2.04=14.28m. proved....

Thanks❤❤❤.

follow me....

Discussion

7.	EXPERIMENT TO DETERMINE RADIUS OF EARTH(USING 10th STD TRIGNOMETRY)TO BE CONDUCTED ON ZERO SHADOW DAYMaterials required : Ruler, Pencil,Method: Eratostenes, a Mathematician at Alexandria performed this experiment during 250BC .• Let us assume a student at GULBARGA is performing this experiment.• Find out the date of Zero shadow day for a place say Bangalore (not your Town). It is 18thAugust. Identify distance of your place from Bangalore.(GULBARGA-BANGALORE – 600Km)• Select a flat surface in your school/house/terrace.• Fix the Ruler vertically. Measure the length of the ruler. Let it be 15cm.• At 12 noon on ZERO SHADOW DAY (at Bangalore), measure the length of the shadow of theruler (in GULBARGA). Let it be 1.5cm.• Angle made by SUNs rays with the ruler at your place is
Answer» ANSWER: Yaar i am in 10th std.but i didnt do any such a problem LIKE this. i am SORRY for IRRELEVANT answer

7.

EXPERIMENT TO DETERMINE RADIUS OF EARTH(USING 10th STD TRIGNOMETRY)TO BE CONDUCTED ON ZERO SHADOW DAYMaterials required : Ruler, Pencil,Method: Eratostenes, a Mathematician at Alexandria performed this experiment during 250BC .• Let us assume a student at GULBARGA is performing this experiment.• Find out the date of Zero shadow day for a place say Bangalore (not your Town). It is 18thAugust. Identify distance of your place from Bangalore.(GULBARGA-BANGALORE – 600Km)• Select a flat surface in your school/house/terrace.• Fix the Ruler vertically. Measure the length of the ruler. Let it be 15cm.• At 12 noon on ZERO SHADOW DAY (at Bangalore), measure the length of the shadow of theruler (in GULBARGA). Let it be 1.5cm.• Angle made by SUNs rays with the ruler at your place is

Answer»

ANSWER:

Yaar i am in 10th std.but i didnt do any such a problem LIKE this.

i am SORRY for IRRELEVANT answer

Discussion

8.	(-1)×(-3)×(-5)×(-10) how to do this promblem please show
Answer» Answer: 150 Step-by-step EXPLANATION: (-1) × (-3) = 3. SINCE (-) × (-) = (+) and 1×3 =3 (-5) × (-10) = 50. since (-) × (-) = (+) and 5 × 10 = 50 3 × 50 = 150

8.

(-1)×(-3)×(-5)×(-10) how to do this promblem please show

Answer»

Answer:

150

Step-by-step EXPLANATION:

(-1) × (-3) = 3. SINCE (-) × (-) = (+)

and 1×3 =3

(-5) × (-10) = 50. since (-) × (-) = (+)

and 5 × 10 = 50

3 × 50 = 150

Discussion

9.	What is the value of cosec^2A-cot^2A?
Answer» ANSWER: ANSWER cosec 2A−cot2A−tanA sin2A 1 − sin2A cos2A −tanA SIN 2 A 1−cos2A −tanA 2sinAcosA 1−(1−2sin 2 A) −tanA = 2sinAcosA 2sin 2 A −tanA =tanA−tanA =0 plz FOLLOW me

9.

What is the value of cosec^2A-cot^2A?

Answer»

ANSWER:

ANSWER

cosec 2A−cot2A−tanA

sin2A

1

−

sin2A

cos2A

−tanA

SIN

2

A

1−cos2A

−tanA

2sinAcosA

1−(1−2sin

2

A)

−tanA

=

2sinAcosA

2sin

2

A

−tanA

=tanA−tanA

=0

plz FOLLOW me

Discussion

10.	SYat Iy4Y+yastyti23 = y²y30423-51-X2076ut 8x²02x² +1 144/17-4/112xY2
Answer» ANSWER: FOLLOW me and LIKE my answer and MARK as BRAINLIST.

10.

SYat Iy4Y+yastyti23 = y²y30423-51-X2076ut 8x²02x² +1 144/17-4/112xY2

Answer»

ANSWER:

FOLLOW me and LIKE my answer and MARK as BRAINLIST.

Discussion

11.	What we will write 4z in words
Answer» ANSWER: FOUR zed is the WORD form of 4Z.

11.

What we will write 4z in words

Answer»

ANSWER:

FOUR zed is the WORD form of 4Z.

Discussion

12.	Find the value of xFig 6.29 from class 7th chapter triangles and its properties
Answer» Buddy, mention your complete question. Do you want only your 7th class *FRNDS* only 2 answer this. Mention the entire question, not it's details.

12.

Find the value of xFig 6.29 from class 7th chapter triangles and its properties

Answer»

Buddy, mention your complete question.

Do you want only your 7th class FRNDS only 2 answer this.

Mention the entire question, not it's details.

Discussion

13.	In ∆ ABC and ∆ PQR, it is given that AB = AC, ∠C =∠P and ∠B =∠Q. Then the two triangles are
Answer» ANSWER: Congruent Hope U FIND it helpfull

13.

In ∆ ABC and ∆ PQR, it is given that AB = AC, ∠C =∠P and ∠B =∠Q. Then the two triangles are

Answer»

ANSWER:

Congruent

Hope U FIND it helpfull

Discussion

14.	A rectangular field is 15by2/3long and12by4/5m wide find its perimeter
Answer» Answer: Length of the field=15 by 2/3=45/2m Breadth of the field=12 by 4/5 m=60/4=15 m Perimeter of rectangle=2(length+breadth) =2(45/2+15) m =2x75/2 =75 m Hope this HELPS.... Thank You....

14.

A rectangular field is 15by2/3long and12by4/5m wide find its perimeter

Answer»

Answer:

Length of the field=15 by 2/3=45/2m

Breadth of the field=12 by 4/5 m=60/4=15 m

Perimeter of rectangle=2(length+breadth)

=2(45/2+15) m

=2x75/2

=75 m

Hope this HELPS....

Thank You....

Discussion

15.	two trains are running in opposite direction with a speed of 62km/hr and 40km/hr respectively .if the length of one train is250 meters and they cross each other in 18 seconds then what is the length of the other train
Answer» Step-by-step explanation: in the question given is that Two trains are RUNNING in opposite directions with speeds of 62 km/h and 40 km/h respectively. whenever we have a problem to be solved with the two moving objects we should USE the concept of relative speed. “Relative” means “in comparison to”. which says if the two moving objects are moving To make things simpler, one body can be made stationary (i.e. Speed =ZERO) and take the Speed of the other body with respect to the stationary body, which is the sum of the Speeds if the bodies are moving in the opposite DIRECTION and the difference if they are moving in the same direction. This Speed of the moving body with respect to the stationary body is called the Relative Speed. two trains are moving with speed 62 km/h consider train A train b with 40 km/h relative speed of train A is = 62 + 40 =102 km/h= (102 * 5) / 18 = 28.33 m/s speed = distance / time two trains require 18 sec to cross each other distance would be sum of LENGTH of trains consider the train a ha s length 260 m so train be length Y speed = distance / time 102 km/h = ( 260 + Y) m/ 18 y= 250 reative speed s1+s2=62+40=102kmph or 28.33 mps total distance=length of train one+train of length of two=260+x. (x=length of train two) time 18 sec 260+x=(1025)/1818 260+x=510 x=510–260 x=250 ans

15.

two trains are running in opposite direction with a speed of 62km/hr and 40km/hr respectively .if the length of one train is250 meters and they cross each other in 18 seconds then what is the length of the other train

Answer»

Step-by-step explanation:

in the question given is that Two trains are RUNNING in opposite directions with speeds of 62 km/h and 40 km/h respectively.

whenever we have a problem to be solved with the two moving objects we should USE the concept of relative speed.

“Relative” means “in comparison to”.

which says if the two moving objects are moving To make things simpler, one body can be made stationary (i.e. Speed =ZERO) and take the Speed of the other body with respect to the stationary body, which is the sum of the Speeds if the bodies are moving in the opposite DIRECTION and the difference if they are moving in the same direction. This Speed of the moving body with respect to the stationary body is called the Relative Speed.

two trains are moving with speed 62 km/h consider train A

train b with 40 km/h

relative speed of train A is = 62 + 40 =102 km/h= (102 * 5) / 18 = 28.33 m/s

speed = distance / time

two trains require 18 sec to cross each other

distance would be sum of LENGTH of trains consider the train a ha s length 260 m so train be length Y

speed = distance / time

102 km/h = ( 260 + Y) m/ 18

y= 250

reative speed s1+s2=62+40=102kmph or 28.33 mps

total distance=length of train one+train of length of two=260+x.

(x=length of train two)

time 18 sec

260+x=(102*5)/18*18

260+x=510

x=510–260

x=250 ans

Discussion

16.	Simply 0.63×0.012/0.09×0.24
Answer» ANSWER: OMIT the POINTS and DIVIDE by NUMBERS

16.

Simply 0.63×0.012/0.09×0.24

Answer»

ANSWER:

OMIT the POINTS and DIVIDE by NUMBERS

Discussion

17.	Q9 find the value of angle x*
Answer» Answer: I think 60. Step-by-step EXPLANATION: FOLLOW me and like my answer and MARK as brainlist.

17.

Q9 find the value of angle x*

Answer»

Answer:

I think 60.

Step-by-step EXPLANATION:

FOLLOW me and like my answer and MARK as brainlist.

Discussion

18.	6pipes are require to fill a trank in 1hour 20minutes. How will it take it only 4pipes of same type are used?
Answer» ANSWER: xfkujvymyrcgvkydvuxdg TS too X HJC G

18.

6pipes are require to fill a trank in 1hour 20minutes. How will it take it only 4pipes of same type are used?

Answer»

ANSWER:

xfkujvymyrcgvkydvuxdg TS too X HJC G

Discussion

19.	Tomas needs exactly 6 potatoes to make 12 potato pancakes.
Answer» Step-by-step EXPLANATION: YES.............................

19.

Tomas needs exactly 6 potatoes to make 12 potato pancakes.

Answer»

Step-by-step EXPLANATION:

YES.............................

Discussion

20.	35467 divisible by 11 or not
Answer» Answer: No Step-by-step explanation: Digits at ODD PLACES= 7+4+3=14 Digits at even places= 6+5 =-11 = 3 So therefore,35467 is not divisible by 11. Hope it HELPS, PLEASE mark me as Brainliest

20.

35467 divisible by 11 or not

Answer»

Answer:

No

Step-by-step explanation:

Digits at ODD PLACES= 7+4+3=14

Digits at even places= 6+5 =-11

= 3

So therefore,35467 is not divisible by 11.

Hope it HELPS, PLEASE mark me as Brainliest

Discussion

21.	(X+1), 3x and(4x+2) are the first 3 terms of ap then x =?
Answer» $\huge\underline{\underline { \bf \bigstar ANSWER \bigstar }}$ Given , 1st term = ( x + 1 ) 2nd term = 3x 3rd term = ( 4x + 2 ) ________________________________ → 2nd term - 1st term = 3x - ( x + 1 ) = 3x - x - 1 = 2X - 1 → 3rd term - 2nd term = 4x + 2 - 3x = x + 2 ________________________________ These two DIFFERENCES are same because common difference is the same . → 2x -1 = x + 2 → 2x -x = 2 + 1 → x = 3 The THREE terms of the a.p. are 4 , 9 and 14 . HOPE IT HELPS U ........... :)

21.

(X+1), 3x and(4x+2) are the first 3 terms of ap then x =?

Answer»

$\huge\underline{\underline { \bf \bigstar ANSWER \bigstar }}$

Given ,

1st term = ( x + 1 )

2nd term = 3x

3rd term = ( 4x + 2 )

________________________________

→ 2nd term - 1st term = 3x - ( x + 1 )

= 3x - x - 1

= 2X - 1

→ 3rd term - 2nd term = 4x + 2 - 3x

= x + 2

________________________________

These two DIFFERENCES are same because common difference is the same .

→ 2x -1 = x + 2

→ 2x -x = 2 + 1

→ x = 3

The THREE terms of the a.p. are 4 , 9 and 14 .

HOPE IT HELPS U ........... :)

Discussion

22.	The constant term of x^2 + 7x + 12 is ______
Answer» ANSWER: CONSTANT term=12 Step-by-step explanation: I HOPE this answer may HELP you

22.

The constant term of x^2 + 7x + 12 is ______

Answer»

ANSWER:

CONSTANT term=12

Step-by-step explanation:

I HOPE this answer may HELP you

Discussion

23.	-x-y+z ka whole square formula
Answer» ANSWER: (X-y-Z)². = [x+(-y)+(-z)]². = x²+(- y)²+(-z)²+2x(-y)+2(-y)(-z)+2(-z)x. /* By ALGEBRAIC IDENTITY: (a+b+c)²=a²+b²+c²+2ab+2bc+2ca */.

23.

-x-y+z ka whole square formula

Answer»

ANSWER:

(X-y-Z)². = [x+(-y)+(-z)]². = x²+(- y)²+(-z)²+2x(-y)+2(-y)(-z)+2(-z)x. /* By ALGEBRAIC IDENTITY: (a+b+c)²=a²+b²+c²+2ab+2bc+2ca */.

Discussion

24.	Two numbers are in the ratio of 3:5 if their sum 64 than numbers are
Answer» $\huge\underline{\underline{\bf \bigstar ANSWER \bigstar }}$ Let the two numbers be 3X and 5x . Their sum = 64 $\Longrightarrow \sf 3x+5x = 64 \\\\\Longrightarrow 8x = 64 \\\\\Longrightarrow x = \dfrac{64}{8} \\\\\Longrightarrow \bf\underline {x = 8 }$ _____________________________________ The two numbers are 24 and 40 . HOPE IT HELPS U .............. :)

24.

Two numbers are in the ratio of 3:5 if their sum 64 than numbers are

Answer»

$\huge\underline{\underline{\bf \bigstar ANSWER \bigstar }}$

Let the two numbers be 3X and 5x .

Their sum = 64

$\Longrightarrow \sf 3x+5x = 64 \\\\\Longrightarrow 8x = 64 \\\\\Longrightarrow x = \dfrac{64}{8} \\\\\Longrightarrow \bf\underline {x = 8 }$

_____________________________________

The two numbers are 24 and 40 .

HOPE IT HELPS U .............. :)

Discussion

25.	5x/3+2/5-1 ans ans ans ans ans
Answer» Answer: 25..............................

25.

5x/3+2/5-1 ans ans ans ans ans

Answer»

Answer:

25..............................

Discussion

26.	Subtract the sum of - 3 upon 10 and - 2 upon 3 from the sum of 3 upon 5 and 7 upon 3
Answer» Step-by-step explanation: 3/5+7/3-(-3/10)+(-2/3) 3/5+7/3=44/15-(-29/30)=88+29/30. (LCM) =117/30 (-3/10)+(-2/3)=(-9+(-20))/30. (LCM) =-29/30 117/30-(-29/30) = 146/30= 4.86

26.

Subtract the sum of - 3 upon 10 and - 2 upon 3 from the sum of 3 upon 5 and 7 upon 3

Answer»

Step-by-step explanation:

3/5+7/3-(-3/10)+(-2/3)

3/5+7/3=44/15-(-29/30)=88+29/30. (LCM) =117/30

(-3/10)+(-2/3)=(-9+(-20))/30. (LCM) =-29/30

117/30-(-29/30) = 146/30= 4.86

Discussion

27.	Last three days of a week. it call sets, why
Answer» ANSWER: Last three DAYS of a WEEK is a set because they are finite Step-by-step explanation: I hope this answer MAY HELP you

27.

Last three days of a week. it call sets, why

Answer»

ANSWER:

Last three DAYS of a WEEK is a set because they are finite

Step-by-step explanation:

I hope this answer MAY HELP you

Discussion

28.	What should be subtracted from 8314 to make it a perfect square?
Answer» ANSWER: how??????????????????????

28.

What should be subtracted from 8314 to make it a perfect square?

Answer»

ANSWER:

how??????????????????????

Discussion

29.	If ( 5 , 0 ) is a solution of x -5y = 2k , then value of k is
Answer» ANSWER: k=2.5 Step-by-step explanation: (X,y)=(5,0) 5-5(0)=2k 5-0=2k 2k=5 k=5/2 k=2.5 I hope this answer MAY help you

29.

If ( 5 , 0 ) is a solution of x -5y = 2k , then value of k is

Answer»

ANSWER:

k=2.5

Step-by-step explanation:

(X,y)=(5,0)

5-5(0)=2k

5-0=2k

2k=5

k=5/2

k=2.5

I hope this answer MAY help you

Discussion

30.	Ascending order of -106,107,-320,-7,185 in integers
Answer» Answer: ascending order is -7185,-320,-106,107 Step-by-step EXPLANATION: I HOPE this answer MAY HELP you

30.

Ascending order of -106,107,-320,-7,185 in integers

Answer»

Answer:

ascending order is -7185,-320,-106,107

Step-by-step EXPLANATION:

I HOPE this answer MAY HELP you

Discussion

31.	1 लिफ्ट में 12 बड़े अथवा 20 बच्चों को ले जाने की छमता है यदि 5 बचो के साथ लिफ्ट में जाना हो तो कितने बड़े व्यक्ति जा सकते है
Answer» Answer: 18 PEOPLE's Step-by-step explanation: 18 people's TAKE in LIFT

31.

1 लिफ्ट में 12 बड़े अथवा 20 बच्चों को ले जाने की छमता है यदि 5 बचो के साथ लिफ्ट में जाना हो तो कितने बड़े व्यक्ति जा सकते है

Answer»

Answer:

18 PEOPLE's

Step-by-step explanation:

18 people's TAKE in LIFT

Discussion

32.	Which term of an A.P 3,8,13,18..........,93
Answer» Answer: Step-by-step explanation: 6th TERM in given A.P is 78 Step-by-step explanation: Given A.P : 3,8,13,18,....,78 First term (a) = 3 , COMMON difference (d)= = $8-3$ = $5$ a+(n-1)d=78 (n-1)5=75 n-1=15 n=16 Therefore, 16th term in given A.P is 78

32.

Which term of an A.P 3,8,13,18..........,93

Answer»

Answer:

Step-by-step explanation:

6th TERM in given A.P is 78

Step-by-step explanation:

Given A.P : 3,8,13,18,....,78

First term (a) = 3 ,

COMMON difference (d)=

= $8-3$

= $5$

a+(n-1)d=78

(n-1)5=75

n-1=15

n=16

Therefore,

16th term in given A.P is 78

Discussion

33.	Subtract 1 + x^2 + y^2 from the sum of x^2 - y^2 and 1 - x^2 - y^2
Answer» Step-by-step explanation: Hope this HELPS please MARK as the Brainliest Follow me please

33.

Subtract 1 + x^2 + y^2 from the sum of x^2 - y^2 and 1 - x^2 - y^2

Answer»

Step-by-step explanation:

Hope this HELPS

please MARK as the Brainliest

Follow me please

Discussion

34.	1355 divide by 15 with solution
Answer» ANSWER: here is UR answer PLEASE MARK me as a BRAINIEST

34.

1355 divide by 15 with solution

Answer»

ANSWER:

here is UR answer

PLEASE MARK me as a BRAINIEST

Discussion

35.	Sum of the natural no and thrice its square is 154.Find the no by factorisation
Answer» ANSWER: ecosystem of people and energy boxes so many have to the ecosystem I am the energy BARS to do so many times it is the 15 August 2017 August and added to buy day of the ccr so many people I will leave the collected for sound I will have pppthe body was found in the box to the country and my people I place my dearto have called you better believe in even a and so many people of the acceleration of the remaining after delivery for sound boxes to the country and my people I will devotion and thereafter the cultivated FOREST found in the box to the country and my paypal IPN my device and the so many people have to cultivated for the device in

35.

Sum of the natural no and thrice its square is 154.Find the no by factorisation

Answer»

ANSWER:

ecosystem of people and energy boxes so many have to the ecosystem I am the energy BARS to do so many times it is the 15 August 2017 August and added to buy day of the ccr so many people I will leave the collected for sound I will have pppthe body was found in the box to the country and my people I place my dearto have called you better believe in even a and so many people of the acceleration of the remaining after delivery for sound boxes to the country and my people I will devotion and thereafter the cultivated FOREST found in the box to the country and my paypal IPN my device and the so many people have to cultivated for the device in

Discussion

36.	Help please who one anwer right i will mark brainleast
Answer» ANSWER: ANYONE can INBOX me I don't have inbox POWER

36.

Help please who one anwer right i will mark brainleast

Answer»

ANSWER:

ANYONE can INBOX me I don't have inbox POWER

Discussion

37.	2For warrantypurposeWO
Answer» ..............What ?

37.

2For warrantypurposeWO

Answer»

..............What ?

Discussion

38.	Find two rational numbers between 1and 2
Answer» Answer: 3 by 2 and 5 by 4 are the two rational numbers between 1 and 2 Step-by-step EXPLANATION: FIRST number- 1/2(1+2)=3/2 Second number- 1/2(1+3/2)=5/4 Hope you will understand and Thank you....

38.

Find two rational numbers between 1and 2

Answer»

Answer:

3 by 2 and 5 by 4 are the two rational numbers between 1 and 2

Step-by-step EXPLANATION:

FIRST number- 1/2(1+2)=3/2

Second number- 1/2(1+3/2)=5/4

Hope you will understand and Thank you....

Discussion

39.	X-3y = 84x - y = 21
Answer» ANSWER: saimultanius EQVATION he Step-by-step EXPLANATION: TUCH KARR

39.

X-3y = 84x - y = 21

Answer»

ANSWER:

saimultanius EQVATION he

Step-by-step EXPLANATION:

TUCH KARR

Discussion

40.	5. Factorise :1. x³- 2x²- x+22.2y³+y²-2y-1
Answer» <P>ANSWER: Answer: (i) Let the given POLYNOMIAL be, p(x)=x3−2x2−x+2 By trial method, p(1)=(1)3−2(1)2−1+2=1−2−1+2=0 So, (x−1) is the FACTOR of the given polynomial. Divide the given polynomial by (x−1) by long division. x−1x2−x−2x3−2x2−x+2x3−x2−−−−−− −x2−x −x2+x−−−−−−−−− −2x+2 −2x+2−−−−−−−−−−− 0−−−−−−−− It is known that, Dividend=Divisor×Quotient+Remainderx3−2x2−x+2=(x−1)(x2−x−2)+0=(x−1)(x2−2x+x−2)=(x−1)[x(x−2)+1(x−2)] Further simplify, x3−2x2−x+2=(x−1)(x+1)(x−2) (ii) Let the given polynomial be, p(y)=2y3+y2−2y−1 By trial method, p(1)=2(1)3+(1)2−2(1)−1=2+1−2−1=0 So, (y−1) is the factor of the given polynomial. Divide the given polynomial by (y−1) by long division. y−12y2+3y+12y3+y2−2y−12y3−2y2−−−−−−−− 3y2−2y 3y2−3y−−−−−−−−−− y−1 y−1−−−−−−−−−− 0−−−−−−−− It is known that, Dividend=Divisor×Quotient+Remainder2y3+y2−2y−1=(y−1)(2y2+3y+1)+0=(y−1)(2y2+2y+y+1)=(y−1)[2y(y+1)+1(y+1)] Further simplify, 2y3+y2−2y−1=(y−1)(y+1)(2y+1)

40.

5. Factorise :1. x³- 2x²- x+22.2y³+y²-2y-1

Answer»

<P>ANSWER:

Answer:

(i)

Let the given POLYNOMIAL be,

p(x)=x3−2x2−x+2

By trial method,

p(1)=(1)3−2(1)2−1+2=1−2−1+2=0

So, (x−1) is the FACTOR of the given polynomial.

Divide the given polynomial by (x−1) by long division.

x−1x2−x−2x3−2x2−x+2x3−x2−−−−−− −x2−x −x2+x−−−−−−−−− −2x+2 −2x+2−−−−−−−−−−− 0−−−−−−−−

It is known that,

Dividend=Divisor×Quotient+Remainderx3−2x2−x+2=(x−1)(x2−x−2)+0=(x−1)(x2−2x+x−2)=(x−1)[x(x−2)+1(x−2)]

Further simplify,

x3−2x2−x+2=(x−1)(x+1)(x−2)

(ii)

Let the given polynomial be,

p(y)=2y3+y2−2y−1

By trial method,

p(1)=2(1)3+(1)2−2(1)−1=2+1−2−1=0

So, (y−1) is the factor of the given polynomial.

Divide the given polynomial by (y−1) by long division.

y−12y2+3y+12y3+y2−2y−12y3−2y2−−−−−−−− 3y2−2y 3y2−3y−−−−−−−−−− y−1 y−1−−−−−−−−−− 0−−−−−−−−

It is known that,

Dividend=Divisor×Quotient+Remainder2y3+y2−2y−1=(y−1)(2y2+3y+1)+0=(y−1)(2y2+2y+y+1)=(y−1)[2y(y+1)+1(y+1)]

Further simplify,

2y3+y2−2y−1=(y−1)(y+1)(2y+1)

Discussion

41.	Divide (3-x + 2x²) by (2-x) and verify the division algorithm
Answer» 3x⁴+x³-x²+x+3 this is the CORRECT ANSWER and FOLLOW me and MAKE me as BRAINLIST

41.

Divide (3-x + 2x²) by (2-x) and verify the division algorithm

Answer»

3x⁴+x³-x²+x+3 this is the CORRECT ANSWER and FOLLOW me and MAKE me as BRAINLIST

Discussion

42.	6. ABCD is a parallelogram. BX is the perpendicular on CD and BY is the perpendicular on AD. If the area ofthe parallelogram is 1500 cm?, find the lengths of BX and BY.50 cmАBYO30 cmDХсdil1 Appoihin19
Answer» Answer: *Given* *that : ABCD is a parallelogram. BX is the perpendicular on CD. BY is the perpendicular on AD. Area of Parallelogram is 1500 cm². AB = 50 cm DX = 30 cm. Solution*** : Area of Parallelogram = BASE × Height 1500 = AB × BX 1500 = 50 × z ( z is the height ) 1500 ÷ 50 = z ( on transposing ) Therefore z = 30 cm = BX... ________________________________ Now we have to find BY. To find BY We have to find the length of BC. To find the length of BC we have to find the length of AQ. Now ABXQ a rectangle. ( As all the angles are 90° ) Area of Rectangle = length × breadth ( length = 50cm. breadth = m. and the area is 1500cm² as the rectangle is lying on the same base of the parallelogram, so the area of Parallelogram is equal to the area of Rectangle. ) 1500 = 50 × m 1500 ÷ 50 = m Therefore m = 30 cm So AQ = BC = 30 cm ________________________________ Now we can find BY.. BCPY is a rectangle as all the sides are of 90° and PC = BY and BC = PY = n. Area of Rectangle = Length × Breadth. 1500 = n × 30 1500 ÷ 30 = n 50 = n Therefore BY = 50 cm ________________________________

42.

6. ABCD is a parallelogram. BX is the perpendicular on CD and BY is the perpendicular on AD. If the area ofthe parallelogram is 1500 cm?, find the lengths of BX and BY.50 cmАBYO30 cmDХсdil1 Appoihin19

Answer»

Answer:

Given that :

ABCD is a parallelogram.

BX is the perpendicular on CD.

BY is the perpendicular on AD.

Area of Parallelogram is 1500 cm².

AB = 50 cm

DX = 30 cm.

Solution :

Area of Parallelogram = BASE × Height

1500 = AB × BX

1500 = 50 × z ( z is the height )

1500 ÷ 50 = z ( on transposing )

Therefore z = 30 cm = BX...

________________________________

Now we have to find BY.

To find BY We have to find the length of BC.

To find the length of BC we have to find the length of AQ.

Now ABXQ a rectangle. ( As all the angles are 90° )

Area of Rectangle = length × breadth

( length = 50cm. breadth = m. and the area is 1500cm² as the rectangle is lying on the same base of the parallelogram,

so the area of Parallelogram is equal to the area of Rectangle. )

1500 = 50 × m

1500 ÷ 50 = m

Therefore m = 30 cm

So AQ = BC = 30 cm

________________________________

Now we can find BY..

BCPY is a rectangle as all the sides are of 90°

and PC = BY and BC = PY = n.

Area of Rectangle = Length × Breadth.

1500 = n × 30

1500 ÷ 30 = n

50 = n

Therefore BY = 50 cm

________________________________

Discussion

43.	Find 4 rational numbers between 4 ans 5
Answer» ANSWER: WELL 13/3 and 14/3 are both RATIONAL and are between 4 and 5.

43.

Find 4 rational numbers between 4 ans 5

Answer»

ANSWER:

WELL 13/3 and 14/3 are both RATIONAL and are between 4 and 5.

Discussion

44.	Sin 36° sin54cos54° cos38
Answer» ANSWER: DEAR the QUESTION is not FULL

44.

Sin 36° sin54cos54° cos38

Answer»

ANSWER:

DEAR the QUESTION is not FULL

Discussion

45.	Classify rational and irrational numbers from the given numbers below.22- 21.6713C219714.37125.....0.08213125Rational NumbersIrrational Numbers-21.6714.37.25......
Answer» the QUESTION is not clear please MAKE SURE that question is CORRECT

45.

Classify rational and irrational numbers from the given numbers below.22- 21.6713C219714.37125.....0.08213125Rational NumbersIrrational Numbers-21.6714.37.25......

Answer»

the QUESTION is not clear

please MAKE SURE that question is CORRECT

Discussion

46.	If (2m-1,m) is thesolutions of the equation5x +4 y-13= 0 Find thevalue of m
Answer» => 5(2m-1) + 4(m) - 13 = 0 => 10m - 5 + 4M - 13 = 0 => 14m - 18 = 0 => 7M - 9 = 0 => m = 9/7

46.

If (2m-1,m) is thesolutions of the equation5x +4 y-13= 0 Find thevalue of m

Answer»

=> 5(2m-1) + 4(m) - 13 = 0

=> 10m - 5 + 4M - 13 = 0

=> 14m - 18 = 0

=> 7M - 9 = 0

=> m = 9/7

Discussion

47.	Evaluate 3
Answer» Answer: 6 Step-by-step EXPLANATION: $\sqrt4$ = 2 3 ×2 = 6 PLS MARK IT BRAINLIEST

47.

Evaluate 3

Answer»

Answer:

6

Step-by-step EXPLANATION:

$\sqrt4$ = 2

3 ×2 = 6

PLS MARK IT BRAINLIEST

Discussion

48.	Find two rational numbers between 2 and 3
Answer» Step-by-step EXPLANATION: It can be SIMPLY 2.5 ANE 2.6 or 2.55 or 2.79

48.

Find two rational numbers between 2 and 3

Answer»

Step-by-step EXPLANATION:

It can be SIMPLY 2.5 ANE 2.6 or 2.55 or 2.79

Discussion

49.	Co-ordinate geometry chapter 10th class with proper explanation answer pls
Answer» ANSWER: 28 is the answer Step-by-step EXPLANATION: Answer is FULLY EXPLAINED in the PICTURE

49.

Co-ordinate geometry chapter 10th class with proper explanation answer pls

Answer»

ANSWER:

28 is the answer

Step-by-step EXPLANATION:

Answer is FULLY EXPLAINED in the PICTURE

Discussion

50.	Find the value of x,pls,pls,pls,pls,pls!!!!!
Answer» ANSWER: HEY DEAR here your answer Step-by-step explanation: 108° HOPE IT WILL HELP YOU

50.

Find the value of x,pls,pls,pls,pls,pls!!!!!

Answer»

ANSWER:

HEY DEAR here your answer

Step-by-step explanation:

108°

HOPE IT WILL HELP YOU

Discussion

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