Answer:

Given that :

ABCD is a parallelogram.

BX is the perpendicular on CD.

BY is the perpendicular on AD.

Area of Parallelogram is 1500 cm².

AB = 50 cm

DX = 30 cm.

Solution :

Area of Parallelogram = BASE × Height

1500 = AB × BX

1500 = 50 × z ( z is the height )

1500 ÷ 50 = z ( on transposing )

Therefore z = 30 cm = BX...

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Now we have to find BY.

To find BY We have to find the length of BC.

To find the length of BC we have to find the length of AQ.

Now ABXQ a rectangle. ( As all the angles are 90° )

Area of Rectangle = length × breadth

( length = 50cm. breadth = m. and the area is 1500cm² as the rectangle is lying on the same base of the parallelogram,

so the area of Parallelogram is equal to the area of Rectangle. )

1500 = 50 × m

1500 ÷ 50 = m

Therefore m = 30 cm

So AQ = BC = 30 cm

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Now we can find BY..

BCPY is a rectangle as all the sides are of 90°

and PC = BY and BC = PY = n.

Area of Rectangle = Length × Breadth.

1500 = n × 30

1500 ÷ 30 = n

50 = n

Therefore BY = 50 cm

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