332354 + Interview Questions in Secondary School in Math

1.	Total surface of cuboid is 22 m²,it's height is 1 m and breath 2m .find its length and volumepls give step by step answer...and a correct answer...
Answer» Answer: LENGTH=6.7m volume=13.4m^3 Step-by-step explanation: LET length = l GIVEN = b = 2M h = 1m T.S.A. of CUBOID = 22m^2 - (given) (lb+bh+hl) = 22m^2 (l×2+2×1+1×l) = 22m^2 (2l+2+1l) = 22m^2 3l+2. = 22m^2 3l. = 22 - 2 l = 20/3 l. = 6.7m Volume of cuboid = l×b×h = 6.7×2×1 = 13.4m^3

1.

Total surface of cuboid is 22 m²,it's height is 1 m and breath 2m .find its length and volumepls give step by step answer...and a correct answer...

Answer»

Answer:

LENGTH=6.7m

volume=13.4m^3

Step-by-step explanation:

LET length = l

GIVEN = b = 2M

h = 1m

T.S.A. of CUBOID = 22m^2 - (given)

(lb+bh+hl) = 22m^2

(l×2+2×1+1×l) = 22m^2

(2l+2+1l) = 22m^2

3l+2. = 22m^2

3l. = 22 - 2

l = 20/3

l. = 6.7m

Volume of cuboid = l×b×h

= 6.7×2×1

= 13.4m^3

Discussion

2.	Complete the given : 625,676,729,784,?
Answer» Answer: 841 Step-by-step explanation: 625=25² 676=26² 729=27² 784=28² So we NEED to FIND the SQ of 29. 29²=841

2.

Complete the given : 625,676,729,784,?

Answer»

Answer:

841

Step-by-step explanation:

625=25²

676=26²

729=27²

784=28²

So we NEED to FIND the SQ of 29.

29²=841

Discussion

3.	please give 5 min to me - (1) Collect the data of COVID positive patients in all the districts of Madhya Pradesh till 15 th August 2020 . (2) Represent the data collected in tabular form (grouped frequency distribution series) by taking suitable scale. (3) Express the data by histogram
Answer» ANSWER: SORRY but I can't HELP U

3.

please give 5 min to me - (1) Collect the data of COVID positive patients in all the districts of Madhya Pradesh till 15 th August 2020 . (2) Represent the data collected in tabular form (grouped frequency distribution series) by taking suitable scale. (3) Express the data by histogram

Answer»

ANSWER:

SORRY but I can't HELP U

Discussion

4.	ANGLES Ans Me Pls
Answer» Answer: 252572, I was GOING to ASK you to PLEASE you and what is the COST of the PERSON who is this and what is the cost of the person who

4.

ANGLES Ans Me Pls

Answer»

Answer:

252572, I was GOING to ASK you to PLEASE you and what is the COST of the PERSON who is this and what is the cost of the person who

Discussion

5.	Solve this............
Answer» ANSWER: HCF(X,y) is ab^2 mark me BRANLIEST

5.

Solve this............

Answer»

ANSWER:

HCF(X,y) is ab^2

mark me BRANLIEST

Discussion

6.	1. Prove that if one angle of a triangle is equalto the sum of the other two angles the triangleis right angled
Answer» Step-by-step explanation: Given :- ONE angle = Sum of other two angles To PROVE :- It is a RIGHT ANGLED triangle Solution :- Let, 1st angle - ∠A 2nd angle - ∠B 3rd angle - ∠C --------------------- ∠A + ∠B = ∠C -- Given --------------------- We know that, ∠A + ∠B + ∠C = 180° → ∠C + ( ∠A + ∠B ) = 180° → ∠C + ∠C = 180° → 2∠C = 180° → ∠C = 180/2 → ∠C = 90° ------------------ ∠C = 90° , Therefore the triangle is right angled. Please mark me as brainliest if it HELPS and follow me

6.

1. Prove that if one angle of a triangle is equalto the sum of the other two angles the triangleis right angled

Answer»

Step-by-step explanation:

Given :-

ONE angle = Sum of other two angles

To PROVE :-

It is a RIGHT ANGLED triangle

Solution :-

Let,

1st angle - ∠A

2nd angle - ∠B

3rd angle - ∠C

---------------------

∠A + ∠B = ∠C -- Given

---------------------

We know that,

∠A + ∠B + ∠C = 180°

→ ∠C + ( ∠A + ∠B ) = 180°

→ ∠C + ∠C = 180°

→ 2∠C = 180°

→ ∠C = 180/2

→ ∠C = 90°

------------------

∠C = 90° , Therefore the triangle is right angled.

Please mark me as brainliest if it HELPS and follow me

Discussion

7.	Complete the given:127,132,126,133,125,134,?
Answer» 124,135,123,136,122,137

Discussion

8.	आठ को आठ बार लिखो और हजार बनाओ
Answer» 888 88 8 8 + 8 ___ 1000 It's your answer I HOPE it is BENEFICIAL for you

8.

आठ को आठ बार लिखो और हजार बनाओ

Answer»

888

88

8

+ 8

___

1000

It's your answer

I HOPE it is BENEFICIAL for you

Discussion

9.	SECTION: Math LogicGROUP Analytical AbilityQUESTION 20Mark(s): 16Sushmita bought a painting for Rs. 10,598. She sold it for Rs. 9,487. What is the amount she lost on that painting?Rs. 1,111Rs. 1,121Rs. 991Rs. 1,100
Answer» ANSWER: RS. 1,111 Step-by-step EXPLANATION: 10,598 - 9,487 = 1,111

9.

SECTION: Math LogicGROUP Analytical AbilityQUESTION 20Mark(s): 16Sushmita bought a painting for Rs. 10,598. She sold it for Rs. 9,487. What is the amount she lost on that painting?Rs. 1,111Rs. 1,121Rs. 991Rs. 1,100

Answer»

ANSWER:

RS. 1,111

Step-by-step EXPLANATION:

10,598 - 9,487 = 1,111

Discussion

10.	The solution of the equation 4p-3=-15 is
Answer» Answer: 4p-3=-15 4p=-15+3 4p=-12 P=-12/4=-3

10.

The solution of the equation 4p-3=-15 is

Answer»

Answer:

4p-3=-15

4p=-15+3

4p=-12

P=-12/4=-3

Discussion

11.	Finc the prodyct of greatest 3 digit number and smallest 2 digit number
Answer» Answer: 9990 Step-by-step explanation: GREATEST 3 digit number=999 Smallest 2 digit number=10 So 999 x 10 = 9990 Pls mark me as Brainliest

11.

Finc the prodyct of greatest 3 digit number and smallest 2 digit number

Answer»

Answer:

9990

Step-by-step explanation:

GREATEST 3 digit number=999

Smallest 2 digit number=10

So 999 x 10 = 9990

Pls mark me as Brainliest

Discussion

12.	Construct quadrilateral MORE , where MO = 6 cm OR = 4.5 cm angle M = 60°. angle O = 105°. angle R = 105° Length of ME is.
Answer» ANSWER: THAT IS YOUR ANSWER !!!!!

12.

Construct quadrilateral MORE , where MO = 6 cm OR = 4.5 cm angle M = 60°. angle O = 105°. angle R = 105° Length of ME is.

Answer»

ANSWER:

THAT IS YOUR ANSWER !!!!!

Discussion

13.	THE TABLE BELOW SHOWS THE DAILY EXPENDITURE ON FOOD OF 25 HOSEHOLD IN A LOCALITY
Answer» where is the table???????)

Discussion

14.	Factories 3 x square _ x _ 4
Answer» Answer: given 3x²-x-4 let it be EQUAL to 0 so 3x²-x-4=0 now by splitting middle term we get 3x² - 4x + 3X -4= 0 or 3x² + 3x -4x -4 =0 on taking terms common 3x(x+1) -4(x+1) =0 (3x-4) (x+1) =0 HENCE it is solution if u want further explanation then MSG to my WHATSAPP no. 7830909817

14.

Factories 3 x square _ x _ 4

Answer»

Answer:

given 3x²-x-4

let it be EQUAL to 0

so 3x²-x-4=0

now by splitting middle term we get

3x² - 4x + 3X -4= 0

or

3x² + 3x -4x -4 =0

on taking terms common

3x(x+1) -4(x+1) =0

(3x-4) (x+1) =0

HENCE it is solution

if u want further explanation then MSG to my WHATSAPP no. 7830909817

Discussion

15.	In figure a b is equal to CD find the value of x
Answer» ANSWER: don't KNOW this answer SORRY now I can't TELL you the answer

15.

In figure a b is equal to CD find the value of x

Answer»

ANSWER:

don't KNOW this answer SORRY now I can't TELL you the answer

Discussion

16.	The distance between any two points is a non-negative _______ number
Answer» Answer: The DISTANCE between any two POINTS is a non-negative ___real____ NUMBER

16.

The distance between any two points is a non-negative _______ number

Answer»

Answer:

The DISTANCE between any two POINTS is a non-negative ___real____ NUMBER

Discussion

17.	If tan ( A + B) = and tan (A – B) = , 00 B, find A and B
Answer» Step-by-step explanation: IN THIS WAY YOU CAN FIND YOUR ANSWER.... HOPE THIS WILL HELP U MATE... MARK ME BRAINLIEST ❤️

17.

If tan ( A + B) = and tan (A – B) = , 00 B, find A and B

Answer»

Step-by-step explanation:

IN THIS WAY YOU CAN FIND YOUR ANSWER....

HOPE THIS WILL HELP U MATE...

MARK ME BRAINLIEST ❤️

Discussion

18.	Write 10 consecutive odd natural numbers
Answer» Answer: 0,1,3,5,7,9,11,13,15,17

18.

Write 10 consecutive odd natural numbers

Answer»

Answer:

0,1,3,5,7,9,11,13,15,17

Discussion

19.	The mass of a jar of sugar is 1.9 kg.What is the total mass of 4 jars of suger
Answer» ANSWER: MASS of one jar = 1.9 kg therefore mass if 4 JARS= 1.9× 4 = 7.6kg

19.

The mass of a jar of sugar is 1.9 kg.What is the total mass of 4 jars of suger

Answer»

ANSWER:

MASS of one jar = 1.9 kg

therefore mass if 4 JARS= 1.9× 4

= 7.6kg

Discussion

20.	All the medians of a triangle are equal in case of a
Answer» ANSWER: EQUILATERAL TRIANGLE

20.

All the medians of a triangle are equal in case of a

Answer»

ANSWER:

EQUILATERAL TRIANGLE

Discussion

21.	Solve the following quadratic equation for x:x2 - 4ax - b2 + 4a2 = 0 by factorisation
Answer» ANSWER: X^2-4ax+4a^2-B^2=0 x^2-22Ax+(2a)^2-(b)^2=0 (x-2a)^2-(b)^2=0 (x-2a-b)(x-2a+b)=0 x-2a-b=0 x-2a+b=0 x=b+2a x=2a-b Therefore, x= 2a+b or 2a-b

21.

Solve the following quadratic equation for x:x2 - 4ax - b2 + 4a2 = 0 by factorisation

Answer»

ANSWER:

X^2-4ax+4a^2-B^2=0

x^2-2*2A*x+(2a)^2-(b)^2=0

(x-2a)^2-(b)^2=0

(x-2a-b)(x-2a+b)=0

x-2a-b=0 x-2a+b=0

x=b+2a x=2a-b

Therefore, x= 2a+b or 2a-b

Discussion

22.	What should be added to -7/16 to get 3/20
Answer» Answer: 3/20-(-7/16) = 47/80 therefore we have to ADD 47/80 to (-7/16) to GET 3/20

22.

What should be added to -7/16 to get 3/20

Answer»

Answer:

3/20-(-7/16)

= 47/80

therefore we have to ADD 47/80 to (-7/16) to GET 3/20

Discussion

23.	Rajesh starts his job with a monthly salary of ₹20,000 and he get a fixed annual increment of ₹4000. What will be his salary 10th years? *
Answer» Answer: 20000 multiply 10 = 200000 NEXT step 200000/40000 = 5 40000+20000 = 60000

23.

Rajesh starts his job with a monthly salary of ₹20,000 and he get a fixed annual increment of ₹4000. What will be his salary 10th years? *

Answer»

Answer:

20000 multiply 10 = 200000

NEXT step

200000/40000 = 5

40000+20000

= 60000

Discussion

24.	Interior angles are what to each other
Answer» ANSWER: if the lines are parallel then ALTERNATE INTERIOR angle are equal. In triangle all interior angles SUM is 180°

24.

Interior angles are what to each other

Answer»

ANSWER:

if the lines are parallel then ALTERNATE INTERIOR angle are equal.

In triangle all interior angles SUM is 180°

Discussion

25.	Two circles of radii 5.7 cm and 3.5 cm touch each other externally. Find the distance between their centres. 11) दोन बाह्यर्स्पशी वर्तुळांच्या त्रिज्या 5.7सेमी आणि 3.5 सेमी आहे तर त्याच्या केंद्रांमधील अंतर किती ?. *2.2 cm4.3 cm9.2 cm10.5 cm
Answer» ANSWER: 9.2 hope it will HELP you MARK as BRAINLIST answer PLZ

25.

Two circles of radii 5.7 cm and 3.5 cm touch each other externally. Find the distance between their centres. 11) दोन बाह्यर्स्पशी वर्तुळांच्या त्रिज्या 5.7सेमी आणि 3.5 सेमी आहे तर त्याच्या केंद्रांमधील अंतर किती ?. *2.2 cm4.3 cm9.2 cm10.5 cm

Answer»

ANSWER:

9.2

hope it will HELP you MARK as BRAINLIST answer PLZ

Discussion

26.	X+2/5x ka answer 7/5x kaise aaya
Answer» Answer: you have to stable (make EQUAL) the denominators. hope you like the answer please MARK me as BRAINLIEST and please FOLLOW me so that I can answer your QUESTIONS quickly ☺️☺️

26.

X+2/5x ka answer 7/5x kaise aaya

Answer»

Answer:

you have to stable (make EQUAL) the denominators.

hope you like the answer please MARK me as BRAINLIEST and please FOLLOW me so that I can answer your QUESTIONS quickly ☺️☺️

Discussion

27.	Evaluate the following five cube + four cube
Answer» ANSWER:Remember that x3 = X •x •x so what does - x3 REPRESENT? It MEANS (-1) •x •x •x Step-by-step explanation:

27.

Evaluate the following five cube + four cube

Answer»

ANSWER:Remember that x3 = X •x •x so what does - x3 REPRESENT? It MEANS (-1) •x •x •x

Step-by-step explanation:

Discussion

28.	Simplify : (-15) - (-15) = ? A -30 B 30 C 0 D None
Answer» Answer: 0 Step-by-step EXPLANATION: (-15) - (-15) -15+15 0

28.

Simplify : (-15) - (-15) = ? A -30 B 30 C 0 D None

Answer»

Answer:

0

Step-by-step EXPLANATION:

(-15) - (-15)

-15+15

0

Discussion

29.	7 Use the formula F= ma to work out f when:m = 6 and a = 2
Answer» ANSWER: 12 is the answer............ ..

29.

7 Use the formula F= ma to work out f when:m = 6 and a = 2

Answer»

ANSWER:

12 is the answer............

..

Discussion

30.	A man buys eggs at Rs 7 for 20 and sales them at Rs 7.20 dozen . If the profit is Rs 30 . The no of eggs bought by him is
Answer» COST of 20 egg is RS. 7 So, cost of 60 eggs= 21 Means, cost of 5 DOZEN eggs = 21 Cost of 1 dozen = 4.2 Let no. Of dozen of eggs = x So, total COST Price = 4.2x Total selling price = 7.2x Profit= SP-CP 30 = 7.2x - 4.2x 30 = 3.0x, 3x x = 30/3 x = 10 That means total no. Of eggs is 10 dozen means 10x12 =120 eggs

30.

A man buys eggs at Rs 7 for 20 and sales them at Rs 7.20 dozen . If the profit is Rs 30 . The no of eggs bought by him is

Answer»

COST of 20 egg is RS. 7

So, cost of 60 eggs= 21

Means, cost of 5 DOZEN eggs = 21

Cost of 1 dozen = 4.2

Let no. Of dozen of eggs = x

So, total COST Price = 4.2x

Total selling price = 7.2x

Profit= SP-CP

30 = 7.2x - 4.2x

30 = 3.0x, 3x

x = 30/3

x = 10

That means total no. Of eggs is 10 dozen means 10x12 =120 eggs

Discussion

31.	A wire is (7x-3) metres long. a length of (3x-4) is cut for use. How much wire is left?
Answer» Answer: 4x+1 METRES is LEFT in the END

31.

A wire is (7x-3) metres long. a length of (3x-4) is cut for use. How much wire is left?

Answer»

Answer:

4x+1 METRES is LEFT in the END

Discussion

32.	जम्मु एकसप्रेस जम्मु हुन सकाळी 8:20 ला सुटते दिल्ली ला पोहचण्या साठी ती 8 तास 35 मिनटे घेते जर ती ला25 मिनटे विलंब झाला तर ती किती वाजता दिल्लीला पोहचेल
Answer» ANSWER: okkkkkkkkkkkkkmkkkkkkkkk

32.

जम्मु एकसप्रेस जम्मु हुन सकाळी 8:20 ला सुटते दिल्ली ला पोहचण्या साठी ती 8 तास 35 मिनटे घेते जर ती ला25 मिनटे विलंब झाला तर ती किती वाजता दिल्लीला पोहचेल

Answer»

ANSWER:

okkkkkkkkkkkkkmkkkkkkkkk

Discussion

33.	State true or flase c) 4/7 × 1 /7 is greater than 1/7
Answer» ANSWER: false because after MULTIPLYING 4/7 and 1/7 we get 4/49 which is EQUAL to 0.08 and 1/7 is equal to 0.14 HENCE it is false as 1/7 is greater

33.

State true or flase c) 4/7 × 1 /7 is greater than 1/7

Answer»

ANSWER:

false

because after MULTIPLYING 4/7 and 1/7 we get 4/49 which is EQUAL to 0.08 and 1/7 is equal to 0.14 HENCE it is false as 1/7 is greater

Discussion

34.	Sum of the zeros of the polynomial p(x) = -3x2 + k is
Answer» ANSWER: okkkkkkkkkkkkkkkkkkk

34.

Sum of the zeros of the polynomial p(x) = -3x2 + k is

Answer»

ANSWER:

okkkkkkkkkkkkkkkkkkk

Discussion

35.	There is an arithmetic sequence with first term 18 and common difference 3 , write term of the sequence and write term which are perfect square
Answer» Step-by-step explanation: What would you LIKE to ask? 11th Maths Sequences and Series Arithmetic Progression First term of an arithmetic... MATHS avatar Asked on OCTOBER 15, 2019 by Ådìtÿå Bakal First term of an arithmetic sequence is 10 and its common difference 3. Write the first three TERMS of the sequence. VERIFY whether 100 is a term of this sequence. MEDIUM Share Study later VIDEO EXPLANATION ANSWER First term of the sequence is 10 and common difference is 3. a 1 = 10 and d = 3 Next term = a 2 =a 1 +d=10+3=13 a 3 =a 2 +d=13+3=16 Thus, first three terms of the sequence are 10, 13 and 16. Let 100 be the NTH term of the sequence. a n =a 1 +(n−1)d 100=10+(n−1)3 90=(n−1)3 n−1=30 n=31, which is a whole number. Therefore, 100 is the 31 st term of the sequence

35.

There is an arithmetic sequence with first term 18 and common difference 3 , write term of the sequence and write term which are perfect square

Answer»

Step-by-step explanation:

What would you LIKE to ask?

11th

Maths

Sequences and Series

Arithmetic Progression

First term of an arithmetic...

MATHS

avatar

Asked on OCTOBER 15, 2019 by

Ådìtÿå Bakal

First term of an arithmetic sequence is 10 and its common difference 3. Write the first three TERMS of the sequence. VERIFY whether 100 is a term of this sequence.

MEDIUM

Share

Study later

VIDEO EXPLANATION

ANSWER

First term of the sequence is 10 and common difference is 3.

a

1

= 10 and d = 3

Next term = a

2

=a

1

+d=10+3=13

a

3

=a

2

+d=13+3=16

Thus, first three terms of the sequence are 10, 13 and 16.

Let 100 be the NTH term of the sequence.

a

n

=a

1

+(n−1)d

100=10+(n−1)3

90=(n−1)3

n−1=30

n=31, which is a whole number.

Therefore, 100 is the 31

st

term of the sequence

Discussion

36.	(2a-8) (3a+4)please answer this
Answer» Answer: 2a ( 3a+4) = 3×2= 6A 2a×4= 8a -8 ( 3a+4) -8×3a= -24A -8×4= -32 8a + 6a -24a - 32 14a -24a -32 -10a -32

36.

(2a-8) (3a+4)please answer this

Answer»

Answer:

2a ( 3a+4)

= 3×2= 6A

2a×4= 8a

-8 ( 3a+4)

-8×3a= -24A

-8×4= -32

8a + 6a -24a - 32

14a -24a -32

-10a -32

Discussion

37.	For month 700 means for day how much
Answer» ANSWER: Step-by-step explanation: 22.998 is your answer

37.

For month 700 means for day how much

Answer»

ANSWER:

Step-by-step explanation:

22.998 is your answer

Discussion

38.	the 17th term of an AP exceeds it's 10th term by 7 . find the common difference.please give step by step
Answer» $\huge\underline{\underline{\bf \bigstar ANSWER \bigstar }}$ LET the first term be a and the common difference be d . → 17 th term = a + 16d → 10 th term = a + 9d ______________________________________________ GIVEN that 17 th term of an AP exceeds its 10 th term by 7 . $\Longrightarrow \sf 17^{th} \ term - 10^{th } \ term = 7 \\\\\Longrightarrow ( a+16d) - (a+9d) = 7 \\\\\Longrightarrow a+16d-a-9d = 7 \\\\\Longrightarrow 7d = 7 \\\\\Longrightarrow \bf d = 1$ ______________________________________________ Common Difference = 1 HOPE IT HELPS U ......... :)

38.

the 17th term of an AP exceeds it's 10th term by 7 . find the common difference.please give step by step

Answer»

$\huge\underline{\underline{\bf \bigstar ANSWER \bigstar }}$

LET the first term be a and the common difference be d .

→ 17 th term = a + 16d

→ 10 th term = a + 9d

______________________________________________

GIVEN that 17 th term of an AP exceeds its 10 th term by 7 .

$\Longrightarrow \sf 17^{th} \ term - 10^{th } \ term = 7 \\\\\Longrightarrow ( a+16d) - (a+9d) = 7 \\\\\Longrightarrow a+16d-a-9d = 7 \\\\\Longrightarrow 7d = 7 \\\\\Longrightarrow \bf d = 1$ ______________________________________________

Common Difference = 1

HOPE IT HELPS U ......... :)

Discussion

39.	Ek college mein 40 bacche the jismein se a 28 bacche Aaye Tu kitne percent Nahin Aaye
Answer» Step-by-step EXPLANATION: follow back" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%3Cmarquee%20bgcolor%3D%22red%22%20width%3D%22100%25%22%3Efollow%20me%3C%2Fmarquee%3E%3C%2Fp%3E%3Cp%3E%224%22%3Efollow%20back%3C%2Fmarquee%3E%20" title="follow me"4">follow back">

39.

Ek college mein 40 bacche the jismein se a 28 bacche Aaye Tu kitne percent Nahin Aaye

Answer»

Step-by-step EXPLANATION:

follow back" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%3Cmarquee%20bgcolor%3D%22red%22%20width%3D%22100%25%22%3Efollow%20me%3C%2Fmarquee%3E%3C%2Fp%3E%3Cp%3E%224%22%3Efollow%20back%3C%2Fmarquee%3E%20" title="follow me"4">follow back">

Discussion

40.	The measure of an angle of a pertologram 1 timethan its odjacent angle Find the measure of eachangles
Answer» Step-by-step explanation: Hello, We know that parallelogram is a MATHEMATICAL figure in which all the opposite SIDES are parallel and equal. Also, The opposite angles are equal to each other. Also, One more property SUM of The adjacent angles of parallelogram is equal to 180 In other words The sum of the Co interior angles is 180 degrees. Now, We will use these properties to obtain the answer. Let the angle of the parallelogram be x So, The adjacent angles will be x+30 Now From am of co interior angles we get $$\BEGIN{lgathered}x + x + 30 = 180 \\ \\ 2x = 180 - 30 \\ \\ 2x = 150 \\ \\ x = \frac{150}{2} = 75\end{lgathered}$$ So, The angle of the parallelogram is 75 degrees And, The adjacent angles of the parallelogram is 75+30 = 105 degrees. Hope it helps U frnd

40.

The measure of an angle of a pertologram 1 timethan its odjacent angle Find the measure of eachangles

Answer»

Step-by-step explanation:

Hello,

We know that parallelogram is a MATHEMATICAL figure in which all the opposite SIDES are parallel and equal.

Also,

The opposite angles are equal to each other.

Also,

One more property

SUM of The adjacent angles of parallelogram is equal to 180

In other words

The sum of the Co interior angles is 180 degrees.

Now,

We will use these properties to obtain the answer.

Let the angle of the parallelogram be x

So,

The adjacent angles will be x+30

Now

From am of co interior angles we get

$$\BEGIN{lgathered}x + x + 30 = 180 \\ \\ 2x = 180 - 30 \\ \\ 2x = 150 \\ \\ x = \frac{150}{2} = 75\end{lgathered}$$

So,

The angle of the parallelogram is 75 degrees

And,

The adjacent angles of the parallelogram is 75+30 = 105 degrees.

Hope it helps U frnd

Discussion

41.	Factorisation method :25x² - 70x + 49=0
Answer» ANSWER: x=41/25 or x=1 Step-by-step explanation: 25x^2-70x+49=0 25x^2-25x-49x+49=0 25x(x-1)-49(x-1)=0 (25x-41)(x-1)=0 x=41/25 or x=1

41.

Factorisation method :25x² - 70x + 49=0

Answer»

ANSWER:

x=41/25 or x=1

Step-by-step explanation:

25x^2-70x+49=0

25x^2-25x-49x+49=0

25x(x-1)-49(x-1)=0

(25x-41)(x-1)=0

x=41/25 or x=1

Discussion

42.	X^2 - 2xy + y^2 = ?
Answer» ANSWER: (x-y)² plz MARK my answer as BRAINLIST

42.

X^2 - 2xy + y^2 = ?

Answer»

ANSWER:

(x-y)²

plz MARK my answer as BRAINLIST

Discussion

43.	5. Complete the series: 1, 1, 8, 4, 27, 9,(A) 64(C) 60(B) 20(D) 16
Answer» Answer: 64 Step-by-step explanation: 1³ ,1², 2³,2²,3³,3², 4³

43.

5. Complete the series: 1, 1, 8, 4, 27, 9,(A) 64(C) 60(B) 20(D) 16

Answer»

Answer:

64

Step-by-step explanation:

1³ ,1², 2³,2²,3³,3², 4³

Discussion

44.	Anyone preparing for jee mains in 11?
Answer» ANSWER:YES me at the age of 15 !!! By the WAY THANKU for free POINTS

44.

Anyone preparing for jee mains in 11?

Answer»

ANSWER:YES me at the age of 15 !!!

By the WAY THANKU for free POINTS

Discussion

45.	FIND THE ANSWERS urgent plz
Answer» ANSWER: r7yneyeurjfrhsah6s Step-by-step EXPLANATION: ttsnvhkk hkw5ia

45.

FIND THE ANSWERS urgent plz

Answer»

ANSWER:

r7yneyeurjfrhsah6s

Step-by-step EXPLANATION:

ttsnvhkk hkw5ia

Discussion

46.	If altitude of two similar triangles are in the ratio 1:√3, what is the ratio of their areas ? 13) जर दोन समरूप त्रिकोणाची उंची 1: √3 चे गुणोत्तरआहे तर त्या त्रिकोणांच्या क्षेत्रफळांचे गुणोत्तर किती ? *1:√3√3:11:33:1
Answer» ANSWER: CHECK in a GUIDE mister Step-by-step EXPLANATION:

46.

If altitude of two similar triangles are in the ratio 1:√3, what is the ratio of their areas ? 13) जर दोन समरूप त्रिकोणाची उंची 1: √3 चे गुणोत्तरआहे तर त्या त्रिकोणांच्या क्षेत्रफळांचे गुणोत्तर किती ? *1:√3√3:11:33:1

Answer»

ANSWER:

CHECK in a GUIDE mister

Step-by-step EXPLANATION:

Discussion

47.	BCDE is a rectangle, ZOCD = 47°. Findangles x, y and z. If BD = 5a – 3 and EC =a + 5. Find a, length of EC.
Answer» Given : BCDE is a rectangle, ∠OCD = 47°. BD = 5a – 3 and EC = a + 5. To Find : angles x, y and z. length of EC. Solution: BCDE is rectangle Diagonals of rectangle are equal in length and bisect each other => BD = CE => 5a - 3 = a + 5 => 4a = 8 => a = 2 5a - 3 = 5(2) - 3 = 7 a + 5 = 2 + 5 = 7 Length of EC = 7 OD = OC => x = 47° z =x + 47° ( exterior angle of triangle = Sum of opposite TWO interior angles) => z = 47° + 47° => z = 94° y = x ( alternate interior angle) => y = 47° x = 47° , y = 47° , z = 94° , EC = 7 Learn More : BCDE is a rectangle, brainly.in/question/31894274 13. In Fig. 16.10, BCDE is a rectangle , ED = 3.88 cm,AD= 10 cm ... brainly.in/question/19749562

47.

BCDE is a rectangle, ZOCD = 47°. Findangles x, y and z. If BD = 5a – 3 and EC =a + 5. Find a, length of EC.

Answer»

Given : BCDE is a rectangle, ∠OCD = 47°.

BD = 5a – 3 and EC = a + 5.

To Find : angles x, y and z.

length of EC.

Solution:

BCDE is rectangle

Diagonals of rectangle are equal in length and bisect each other

=> BD = CE

=> 5a - 3 = a + 5

=> 4a = 8

=> a = 2

5a - 3 = 5(2) - 3 = 7

a + 5 = 2 + 5 = 7

Length of EC = 7

OD = OC

=> x = 47°

z =x + 47° ( exterior angle of triangle = Sum of opposite TWO interior angles)

=> z = 47° + 47°

=> z = 94°

y = x ( alternate interior angle)

=> y = 47°

x = 47° , y = 47° , z = 94° , EC = 7

Learn More :

BCDE is a rectangle,

brainly.in/question/31894274

13. In Fig. 16.10, BCDE is a rectangle , ED = 3.88 cm,AD= 10 cm ...

brainly.in/question/19749562

Discussion

48.	Write 0.625 in simplest form in fraction
Answer» Answer: 5/8 Step-by-step explanation: 625/1000 625=5.5.5.5 1000 = 5.5.5.2.2.2 comman FACTOR =5.5.5 =125 DIVIDE 125 by 625/1000 = 5/8

48.

Write 0.625 in simplest form in fraction

Answer»

Answer:

5/8

Step-by-step explanation:

625/1000

625=5.5.5.5

1000 = 5.5.5.2.2.2

comman FACTOR =5.5.5

=125

DIVIDE 125 by 625/1000

= 5/8

Discussion

49.	IFfast plz
Answer» $\boxed {\mathbb{ \red{G} \blue{I} \pink{V} \purple{E} \orange{ N}}}$ ${m}^{2} + {m ' }^{2} + 2mm' \cos \theta = 1$ $\boxed {\mathtt{ \red S \blue O \orange L \purple U \green T \pink I \red ON}}$ ${m'}^{2} + 2mm' \cos \theta = 1 - {m}^{2}$ $add \: {m}^{2} { \cos }^{2} \theta \: both \: sides$ ${m ' }^{2} + 2mm' + {m}^{2} { \cos }^{2} \theta = 1 - {m}^{2} + {m}^{2} { \cos}^{2} \theta$ $(m' + {m}^{2} { \cos }^{2} \theta) = 1 - {m}^{2} { \sin}^{2} \theta...(i)$ ${n}^{2} + {n' }^{2} + 2nn' \cos \theta = 1 \: \: \: \: \: \: (n' + n \cos \theta {)}^{2} = 1 - {n}^{2} { \sin }^{2} \theta.....(ii)$ $eq(i) \times (ii)$ $(m' + m \cos \theta {)}^{2} (n' + n \cos \theta {)}^{2} = (1 - {m}^{2} { \sin }^{2} \theta)(1 - {n}^{2} { \sin }^{2} \theta)(1 - {n}^{2} { \sin }^{2} \theta).....(iii)$ $(m' + m \cos \theta) (n' + n \cos \theta) = m'n' + (m'n + mn') \cos \theta + mn \: { \cos }^{2} \theta....(iv)$ $but \: mn + m'n' + (mn' + nm') \cos \theta = 1 \: in \: eq(iv)$ $(m' + m \cos \theta)(n'n \cos \theta) = 1 - mn + mn { \cos }^{2} \theta$ $= > 1 - mn(1 - { \cos }^{2} \theta)$ $= > 1 - mn \: { \sin }^{2} \theta...(v)$ $eq(v {)}^{2} \: we \: get$ $(m' + m \cos \theta)(n' + n \cos \theta) = 1 - mn + mn \: { \sin}^{2} \theta {)}^{2} .....(vi)$ $from \: eq(iii) \: and \: (vi)$ ${m}^{2} {n}^{2} { \sin}^{2} \theta = (1 - {m}^{2} { \sin }^{2} \theta)(1 - {n}^{2} { \sin }^{2} \theta)$ $\cancel{{m}^{2} {n}^{2} { \sin }^{4} \theta }= 1 - {n}^{2} { \sin }^{2} \theta - {m}^{2} { \sin}^{2} \theta + \cancel{ {m}^{2} {n}^{2} { \sin }^{4} }$ ${m}^{2} { \sin }^{2} \theta + {m}^{2} { \sin }^{2} \theta = 1$ ${ \sin }^{2} \theta( {m}^{2} + {n}^{2} ) = 1$ ${m}^{2} + {n}^{2} = \frac{1}{ { \sin }^{2} \theta }$ $\boxed{ {m}^{2} + {n}^{2} = { \cosec }^{2} \theta}$ *HENCE* *PROVED*.........

49.

IFfast plz

Answer»

$\boxed {\mathbb{ \red{G} \blue{I} \pink{V} \purple{E} \orange{ N}}}$

${m}^{2} + {m ' }^{2} + 2mm' \cos \theta = 1$

$\boxed {\mathtt{ \red S \blue O \orange L \purple U \green T \pink I \red ON}}$

${m'}^{2} + 2mm' \cos \theta = 1 - {m}^{2}$

$add \: {m}^{2} { \cos }^{2} \theta \: both \: sides$

${m ' }^{2} + 2mm' + {m}^{2} { \cos }^{2} \theta = 1 - {m}^{2} + {m}^{2} { \cos}^{2} \theta$

$(m' + {m}^{2} { \cos }^{2} \theta) = 1 - {m}^{2} { \sin}^{2} \theta...(i)$

${n}^{2} + {n' }^{2} + 2nn' \cos \theta = 1 \: \: \: \: \: \: (n' + n \cos \theta {)}^{2} = 1 - {n}^{2} { \sin }^{2} \theta.....(ii)$

$eq(i) \times (ii)$

$(m' + m \cos \theta {)}^{2} (n' + n \cos \theta {)}^{2} = (1 - {m}^{2} { \sin }^{2} \theta)(1 - {n}^{2} { \sin }^{2} \theta)(1 - {n}^{2} { \sin }^{2} \theta).....(iii)$

$(m' + m \cos \theta) (n' + n \cos \theta) = m'n' + (m'n + mn') \cos \theta + mn \: { \cos }^{2} \theta....(iv)$

$but \: mn + m'n' + (mn' + nm') \cos \theta = 1 \: in \: eq(iv)$

$(m' + m \cos \theta)(n'n \cos \theta) = 1 - mn + mn { \cos }^{2} \theta$

$= > 1 - mn(1 - { \cos }^{2} \theta)$

$= > 1 - mn \: { \sin }^{2} \theta...(v)$

$eq(v {)}^{2} \: we \: get$

$(m' + m \cos \theta)(n' + n \cos \theta) = 1 - mn + mn \: { \sin}^{2} \theta {)}^{2} .....(vi)$

$from \: eq(iii) \: and \: (vi)$

${m}^{2} {n}^{2} { \sin}^{2} \theta = (1 - {m}^{2} { \sin }^{2} \theta)(1 - {n}^{2} { \sin }^{2} \theta)$

$\cancel{{m}^{2} {n}^{2} { \sin }^{4} \theta }= 1 - {n}^{2} { \sin }^{2} \theta - {m}^{2} { \sin}^{2} \theta + \cancel{ {m}^{2} {n}^{2} { \sin }^{4} }$

${m}^{2} { \sin }^{2} \theta + {m}^{2} { \sin }^{2} \theta = 1$

${ \sin }^{2} \theta( {m}^{2} + {n}^{2} ) = 1$

${m}^{2} + {n}^{2} = \frac{1}{ { \sin }^{2} \theta }$

$\boxed{ {m}^{2} + {n}^{2} = { \cosec }^{2} \theta}$

HENCE PROVED.........

Discussion

50.	Give the answer fast
Answer» Answer: 10000023 is the answer Step-by-step EXPLANATION: plz MARK me as brainliest

50.

Give the answer fast

Answer»

Answer:

10000023 is the answer

Step-by-step EXPLANATION:

plz MARK me as brainliest

Discussion

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