1.

the 17th term of an AP exceeds it's 10th term by 7 . find the common difference.please give step by step​

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LET the first term be a and the common difference be d .

→  17 th term = a + 16d

→  10 th term = a + 9d

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GIVEN that 17 th term of an AP exceeds its 10 th term by 7 .

\Longrightarrow \sf 17^{th} \ term - 10^{th } \ term = 7 \\\\\Longrightarrow ( a+16d) - (a+9d) = 7 \\\\\Longrightarrow a+16d-a-9d = 7 \\\\\Longrightarrow 7d = 7 \\\\\Longrightarrow \bf d = 1______________________________________________

      Common Difference = 1

HOPE IT HELPS U ......... :)


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