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ANSWER:

The VALUE of x is 1+b+a.

Step-by-step explanation:

Please MARK as BRAIN list.

Please

Please

a² - 3A -1= 0

a² - 1 = 3a

(a² - 1)/a = 3a/a. {DIVIDING the equation by a}

a - 1/a = 3

a² + 1/a² - 2 = (a-1/a)²

a² + 1/a² - 2 = (3)²

a² + 1/a² - 2 = 9

a² + 1/a² = 11

Step-by-step explanation:

Sum of squares of first 11 NATURAL numbers

n ( n + 1 ) ( 2n + 1 )

S = ------------------------

6

11 ( 11 + 1 ) ( 22 + 1 )

= ------------------------

6

11 (12) (23)

= --------------

6

= 506

Step-by-step EXPLANATION:

x÷31/6=31/20

x=31/20×6/31

x=3/10

Answer:

draw a line m. above line m give a point as x. with x draw an arc on both SIDES . with both sides ALSO draw an arc such that both arc cut TOGETHER. with the HELP of arc draw a PERPENDICULAR line. Now a perpendicular line will be constructed.

hopes it's help

ANSWER:

which CLASS QUESTIONS is this

Answer:

Please find below the SOLUTION for it:

CONSIDER:

(a+b+c)3 - a3-b3-c3 = [(a+b)+c]3 – a3-b3-c3

(a+b)3+c3+3c(a+b)(a+b+c)-a3-b3-c3

a3+b3+3ab(a+b)+c3+3c(a+b)(a+b+c)-a3-b3-c3

a3+b3+c3+3ab(a+b)+3c(a+b)(a+b+c)-a3-b3-c3

3ab(a+b)+3c(a+b)(a+b+c) 3(a+b)[ab+c(a+b+c)]

3(a+b)[ab+ac+bc+c2] 3(a+b)[a(b+c)+c(b+c)]

3(a+b)(b+c)(c+a)

HENCE Proved.

⚡Hope it will help you.⚡

Step-by-step explanation:

LET the numbers be X, x + 2 and X + 4.

Then, x(x + 2)(x +4) / 8 = 720 => x(x + 2)(x +4) = 5760.

√x * √(x + 2) * √(x +4) = √x(x +2)(x + 4 ) = √5760 = 24√10.

Answer:

+20 is the answer because we have to OPPOSITE the SIGNS in absolute VALUE

Step-by-step EXPLANATION:

your ANSWER is in the above ATTACHMENT

ANSWER:

SORRY its so TRICKY QUESTION

ANSWER:

this QUESTION is GIVEN in NCERT

ANSWER:

ABSOLUTE VALUE of-156is 156

as we KNOW in this QUESTION we have to find the value of a

by SOLVING this question we get the value of a =5

Answer:

1. when x=5 then

|5|=-5

2. x=-10 then

|-10|=10

3.when x=-12 then

|-12|=12

i hope that you understand

it is ADDITIVE inverse

in these SUMS we have to just CHANGE their

symbol

like if it is positive then it will change into negative and when negative it changes to positive

by SOLVING this question we get the VALUE of NUMBER IS10

I THINK it WOULD be 6

ANSWER:

have u tried SOLVING by USING AP

ANSWER:

HELLO Dear User__________

Here is Your Answer...!!

____________________

Step by step solution:

HOPE it is clear to you.

(x + a)² + b² = (x + 4)² + (√3)², value of a = 4 and value of B = √3

x² + 8x + 19

To get it in the form of (x + a)² + b²

First we need to write 8x as 2ab

So, 8x = 2(x)(4)

[Since 8 = 2 * 4]

We got 8x as 2(x)(4)

Now substitute 8x as 2(x)(4)

= x² + 2(x)(4) + 19

So, by (p + q)² = p² + 2pq + q²

We came to know that,

In the above expression p = x and q = 4

So now according to that identity we should get q² after 2(x)(4). we know the value of b i.e, 4. We can FIND the value of q² by squaring the value of q.

i.e, q² = (4)²

q² = 16

But according to the expression last term is 19 instead of 16 i.e, 4².

So, we need to split the the last term into two such that we can get 16.

i.e, 19 - 16 = 3

So, 19 = (16 + 3)

Substitute value of 19 as (16 + 3)

= x² + 2(x)(4) + (16 + 3)

= x² + 2(x)(4) + 16 + 3

Again 16 can be written as (4)²

= (x)² + 2(x)(4) + (4)² + 3

= [(x)² + 2(x)(4) + (4)²] + 3

We know that (p + q)² = p² + 2pq + q²

Here p = x and q = 4

By substituting the VALUES in the identity we have,

= (x + 4)² + 3

Now here x = x, a = 4,

So, b² = 3

b = √3

x² + 8x + 19 = (x + 4)² + (√3)²

Now the expression is is the form of (x + a)² + b²

Therefore, (x + a)² + b² = (x + 4)² + (√3)², value of a = 4 and value of b = √3.

(p + q)² = p² + 2pq + q²

Step-by-step EXPLANATION:

SUM of SQUARES of'n'natural number=n(n+1)(2n+1)/6

Step-by-step EXPLANATION:

-30+9

-21............................

ANSWER:

do it on CALCULATER because it is very EASY

Answer:

S.I.= (sum*time*RATE)/100

( 15000*15*3)/100

Rs.6750

So, the SIMPLE interest is Rs.6750

PLEASE MARK MY ANSWER AS BRAINLIEST IF IT SATISFIED YOU!

Step-by-step explanation:

Let the number be xy.

x + y = 5

(10x + y) - 9 = 10y + x (I multiplied by 10 because of place values)

10x + y - 9 = 10y + x

9X - 9y = 9

x - y = 1

So, now we know x+y = 5 and x - y = 1

x + y = 5

x - y = 1

+_________

2x = 6

x = 3

x + y = 5

3 + y = 5

y = 2

The number is 32.

Heyaa☺

______________

Given,

_/3 - 2.

let us assume that _/3 - 2 is not an IRRATIONAL NUMBER.

Now, let _/3 - 2 = a / B. (where a and b are ci-primes)

=》 _/3 = a / b + 2

=》 _/3 = 2b + a /2

=》 _/3 is an irrational number and 2b + a / 2 is a rational number.

Therefore, irrational = rational

This is a contradiction to our assumption.

So we CONCLUDE that _/3 - 2 is an irrational number.

_______________________

Hope you understand...✌

Step-by-step EXPLANATION:

i THINK ( 1 / 49 ) is the ANSWER

ANSWER

❍ त्रिभुज का क्षेत्रफल = 1/2

आधार × ऊंचाई ×

❍ आयत का क्षेत्रफल= लंबाई × चौड़ाई

❍ वर्ग का क्षेत्रफल =( भुजा)2

❍ समांतर चतुर्भुज का क्षेत्रफल = आधार × ऊंचाई

❍ समचतुर्भुज का क्षेत्रफल =1/2

× विकर्णों का गुणनफल

❍ समलंब चतुर्भुज का क्षेत्रफल =1/2

× समांतर भुजाओं का योग × ऊंचाई

❍ समलंब चतुर्भुज का क्षेत्रफल = समांतर भुजाओं के योग का आधा × उनके बीच की लंबवत दूरी

❍ वृत्त का क्षेत्रफल = π r2

❍ अर्द्धवृत्त का क्षेत्रफल = 1/2

× πr2

❍ वृत्त के चतुर्थांश का क्षेत्रफल = 1/4

× πr2

❍ दो संकेंद्री वृत्तों के बीच का क्षेत्रफल = π (r12 - r22)

❍ समबाहु त्रिभुज का क्षेत्रफल = √3/4

× भुजा2

❍ समद्विबाहु त्रिभुज का क्षेत्रफल = b/4

× √4a2- b2

❍ लघु त्रिज्यखंड का क्षेत्रफल =

πr2θ

360

या 1/2

L × R

❍ दीर्घ त्रिज्यखंड का क्षेत्रफल = πr2 [

360 - θ

360]

❍ लघु वृत्तखंड का क्षेत्रफल =

πr2θ

360-1/2

r2 Sinθ

❍ दीर्घ वृत्तखंड का क्षेत्रफल = वृत्त का क्षेत्रफल - लघु वृत्त खंड का क्षेत्रफल

❍ घनाभ का संपूर्ण पृष्ठीय क्षेत्रफल = 2(lb+bh+hl)

❍ घन का संपूर्ण पृष्ठीय क्षेत्रफल = 6 × भुजा 2

❍ घन के एक पृष्ठ का क्षेत्रफल = भुजा 2

❍ फर्श या छत का क्षेत्रफल का क्षेत्रफल = लम्बाई × चौड़ाई

❍ बेलन का वक्र पृष्ठ का क्षेत्रफल = 2 πrh

❍ बेलन का संपूर्ण पृष्ठीय क्षेत्रफल = 2 πr(r+h)

❍ बेलन के दोनों सिरों का क्षेत्रफल = 2 πr2

❍ खोखले बेलन का संपूर्ण पृष्ठीय क्षेत्रफल = 2 π (r1 + r2) (h+r1 - r2)

❍ शंकु का वक्र (ढालू) पृष्ठ का क्षेत्रफल = πrl

❍ शंकु का संपूर्ण पृष्ठीय क्षेत्रफल = πr(r+l)

❍ शंकु के ढालू भाग की लंबाई (l) = √r2+ h2

❍ शंकु के आधार का क्षेत्रफल = πr2

❍ शंकु के आधार का परिमाप = 2πr

I hope it helps you

plz MARK as brainliest

Step-by-step explanation:

50-5

=45...................................,,,,,,

ANSWER:

When electrostatic demonstrations are first PRESENTED to students, the demonstrator will often touch a piece of conducting material to the ground (earth) and declare that the EXCESS charge has been REMOVED. In fact, though, what has happened is that the potential has been set, by definition, to zero. Usually, but not always, this means that the excess charge has been removed. In the case of an isolated conductor, it's true that the excess charge has been removed, but if there are other charged objects nearby, the grounded conductor can still retain some excess charge. In this case we REFER to it as induced charge. A capacitor is a pair of conductors.

Answer:

0

Step-by-step explanation:

0 MULTIPLIED by ANYTHING is 0

Answer:

आंतरिक वक्र पृष्ठीय क्षेत्रफल 968 सेमी² है।

बाहरी वक्र पृष्ठीय क्षेत्रफल 1064.8 सेमी² है।

कुल पृष्ठीय क्षेत्रफल 2038.08 सेमी² है ।  

Step-by-step EXPLANATION:

माना, पाइप की बाहरी त्रिज्या R तथा आंतरिक त्रिज्या r है।

दिया है : आंतरिक व्यास = 4 सेमी और बाहरी व्यास = 4.4 सेमी  

बाहरी त्रिज्या ,R  = 4.4/2  

R = 2.2 सेमी

आंतरिक त्रिज्या, r = 4/2  

r = 2 सेमी

पाइप की लंबाई ,h = 77 CM

(i) आंतरिक वक्र पृष्ठीय क्षेत्रफल = 2πrh

= 2 × 22/7 × 2 × 77

= 968 सेमी²

अतः, आंतरिक वक्र पृष्ठीय क्षेत्रफल 968 सेमी² है।

(II) बाहरी वक्र पृष्ठीय क्षेत्रफल = 2πRh

= 2 × 22/7 × 2.2 × 77  

= 1064.8 सेमी²

अतः , बाहरी वक्र पृष्ठीय क्षेत्रफल 1064.8 सेमी² है।

(iii) कुल पृष्ठीय क्षेत्रफल = आंतरिक वक्र पृष्ठीय क्षेत्रफल + बाहरी वक्र पृष्ठीय क्षेत्रफल + दो आधारों का क्षेत्रफल

= 2πrh + 2πRh + 2π(R² – r²)

= [968 + 1064.8 + (2 × 22/7) ((2.2)² – 2²)]  

= [968 + 1064.8 + (2 × 22/7) (4.84 – 4)]  

= (2032.8 + 44/7 × 0.84)  

= (2032.8 + 44 × 0.12)  

= (2032.8 + 5.28)  

= 2038.08 सेमी²

अतः,कुल पृष्ठीय क्षेत्रफल 2038.08 सेमी² है ।  

आशा है कि यह उत्तर आपकी मदद करेगा।

इस पाठ से संबंधित कुछ और प्रश्न :

धातु की एक चादर से 1 m ऊँची और 140 cm व्यास के आधार वाली एक बंद बेलनाकार टंकी बनाई जानी है। इस कार्य के लिए कितने वर्ग मीटर चादर की आवश्यकता होगी?

brainly.in/question/10350294

ऊँचाई 14 cm वाले एक लम्ब वृत्तीय बेलन का वक्र पृष्ठीय क्षेत्रफल 88 है। बेलन के आधार का व्यास ज्ञात कीजिए।  

brainly.in/question/10350044

Answer:

to read 7/10 books TIME TAKEN =3/2 hrs

to read 1 BOOK tike will take= 3/2/7/10

=3/2 MULTIPLY 10/7

= 2.5 hrs need to complete one book

Step-by-step EXPLANATION:

COEFFICIENT of X= 5, 1

coefficient of x^2=1

GIVEN,

Principal amount = Rs. 6250

Rate = 16%

Time = 3 years

To find,

The COMPOUND interest if the given money is compounded ANNUALLY.

Solution,

We can easily solve this mathematical problem by using the following mathematical formula.

A = P (1+R/100)^n

Here,

A = Final amount = Compound Interest + Principal amount

R = Rate

n = number of years

(This formula is applicable, when the principal amount is compounded annually.)

A = 6250 ( 1+ 16/100)³

A = 6250 (116/100)³

A = 6250 (29/25)³

A = 6250 × (24389/15625)

A = 24389/2.5

A = 9755.6

Compound Interest = Final amount - Principal amount = 9755.6-6250 = Rs. 3505.6

Hence, the compound interest is Rs. 3505.6

Answer:

Step-by-step explanation:

Your answer is GIVEN in the attachment.

HOPE it will HELP you

PLEASE mark me as BRANLIEST

ANSWER:

No, both are POSITIVE INTEGER

Answer:

810

Step-by-step EXPLANATION:

Here, a=12, d=15-12=3, n =20.

now, S=n/2(2a+(n-1)d)

           =20/2(2×12+(20-1)3)

            =10(24+57)

             =810.

Answer:

Step-by-step explanation:

A's INCOME is 10 less than B's income how MUCH PERCENTAGE is B's income more than A's income

A's income is 10 more than b's income. how many percent is b's income less than a's

Step-by-step EXPLANATION:

☑ let us CONSIDER the ages of two BROTHERS are X and y (present ages) therefor present ages are

x / y = 1/2

here, y = 2x ..........(1)

☑ 5 years back the ratio was 1:3

➡(x - 5)/ ( y - 5) = 1/3

➡(x - 5) 3 = 1 ( y - 5)

➡3x - 15 = y - 5

➡3x - 15 =( 2x)- 5

➡3x - 2x = -5 + 15

x = 10

☑ PUT x = 10 in equation (1)

➡y = 2(10)

y = 20

☑ so, the present ages are x = 10 and y = 20

we have to find ratio of their ages after 5 years

therefor,

(x + 5 )/ ( y + 5) =( 10 + 5)/ (20+ 5)

= 15 / 25

= 3 /5

c option is correct 3:5

ANSWER:

HOPEFULLY it will HELP U

.

EXPLAINED CLEARLY IN THE PICTURE

HOPE IT HELPS....

PLS MARK AS BRAINLIEST

Answer:

rational no. b/w them are:

1.415,1.416,1.417,1.418.....

hope it will HELPFUL...

MARK me as BRAINLIEST..

Let the digits be X and y

The no is 10x+y

ATQ x+y=15

Also 10y+x-9=10x+y

9x-9y=-9

By solving this we GET x =7 and y=8 and the no is 78

Answer:

NEGATIVE multiplied with POSITIVE gives negative

the answer is -110

hope this helps you

mark it as brainliest and THANK me and FOLLOW me

This is the ANSWER just ✖ it BHAI

ANSWER:

This is your answer.

Your QUOTIENT is (X^2+X+1)

Answer:10 cm or 0.1 METRE(in S.I. units)

Step-by-step explanation:

1 cm=10 mm

So 1mm =0.1 cm

Therefore

1*100 mm=0.1*100 cm=10 cm or 0. 1 m (in S.I. units)

Answer:

LET us consider that the two DIGITS are a and B.

Then the NUMBER is (10a + b).

When the digits are interchanged, the new number is (10b + a).

By the given condition :

a + b = 13 .....(i)

and

10b + a = (10a + b) + 27

=> 9b = 9a + 27

=> b = a + 3 .....(ii)

Putting b = a + 3 in (i), we get :

a + a + 3 = 13

=> 2a = 10

=> a = 5

From (ii), putting a = 5, we get :

b = 5 + 3 = 8

Therefore, the number is 58.

✨Hope it will be helpful.✨

ANSWER:

GIVEN BELOW ........

Step-by-step explanation:

First expanse the the TWO RATIONAL NUMBER....

1/5=0.2

1/6=0.16666667

1/5>1/6

The five irrational between 1/5 and

1/6 are-

• 0.17170170017000......
• 0.172017200172000....
• 0.173017300173000....
• 0.180180018000.....
• 0.190190019000......

HOPED IT HELP YOU.

THANKS......