332354 + Interview Questions in Secondary School in Math

1.	if alpha and beta are the zeros of the quadratic polynomial x square - 2 X + 3 then find a quadratic polynomial whose zeros are alpha + 2 and beta + 2
Answer» ANSWER:SEE the ATTACHMENT below

1.

if alpha and beta are the zeros of the quadratic polynomial x square - 2 X + 3 then find a quadratic polynomial whose zeros are alpha + 2 and beta + 2

Answer»

ANSWER:SEE the ATTACHMENT below

Discussion

2.	A cinema hall is to be constructed in which eachrow must have 36 seats. Determine the minimumnumber of rows required to seat 600 persons at atime.(1) 18 (2) 17 (3) 20 (4) 16
Answer» Answer: 18 is the SOLUTION of your QUESTION

2.

A cinema hall is to be constructed in which eachrow must have 36 seats. Determine the minimumnumber of rows required to seat 600 persons at atime.(1) 18 (2) 17 (3) 20 (4) 16

Answer»

Answer:

18 is the SOLUTION of your QUESTION

Discussion

3.	Factorise 3x cube-x square-3x+1
Answer» Step-by-step EXPLANATION: ${x}^{2} - 1$ can STILL be DIVIDED as(x-1)(X+1)(3x-1)

3.

Factorise 3x cube-x square-3x+1

Answer»

Step-by-step EXPLANATION:

${x}^{2} - 1$

can STILL be DIVIDED as(x-1)(X+1)(3x-1)

Discussion

4.	Square of any positive integer in the form of 5q,5q+1,5q+4 for some integer q
Answer» Step-by-step EXPLANATION: TRY this in this way thanks

4.

Square of any positive integer in the form of 5q,5q+1,5q+4 for some integer q

Answer»

Step-by-step EXPLANATION:

TRY this in this way

thanks

Discussion

5.	CosA/1+sinA+cosA/1+sinA
Answer» ANSWER: I don't KNOW buddy Step-by-step explanation: *Sorry...I don't* *know* *buddy* *but* I *know* *you* *NEED* *your* *answer* *Very* *Very* *Sorry* *Buddy*...

5.

CosA/1+sinA+cosA/1+sinA

Answer»

ANSWER:

I don't KNOW buddy

Step-by-step explanation:

Sorry...I don't know buddy but I know you NEED your answer

Very Very Sorry Buddy...

Discussion

6.	How many sides does the polygon have if it is of 58.4 cm and lengthof each side is 7.3 cm
Answer» ANSWER: i DONT know thanks Step-by-step EXPLANATION: lol s7hshwhdhwhdhwhhdhe

6.

How many sides does the polygon have if it is of 58.4 cm and lengthof each side is 7.3 cm

Answer»

ANSWER:

i DONT know

thanks

Step-by-step EXPLANATION:

lol

s7hshwhdhwhdhwhhdhe

Discussion

7.	what must be addedvto 4x^4 + 2x^3 - 2x^2 + x - 1 so that the resulting polynomial is divisible by x^2 - 2x - 3
Answer» ANSWER: $x {}^{2} - 2x - 3 \: ) \: 4x {}^{4} + 2x {}^{3} - 2x {}^{2} + x - 1 \: (4x { }^{2} + 10x + 21\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 4x {}^{4} + 8x {}^{3} + 3x {}^{2} \\ - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 10x {}^{3} + x {}^{2} + x - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 10x {}^{3} + 20x {}^{2} + 60x \\ - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 21x {}^{2} + 61x - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 21x{}^{2} + 42x + 63 \\ - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 103x + 62$ this is your answer by DIVISION METHOD .

7.

what must be addedvto 4x^4 + 2x^3 - 2x^2 + x - 1 so that the resulting polynomial is divisible by x^2 - 2x - 3

Answer»

ANSWER:

$x {}^{2} - 2x - 3 \: ) \: 4x {}^{4} + 2x {}^{3} - 2x {}^{2} + x - 1 \: (4x { }^{2} + 10x + 21\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 4x {}^{4} + 8x {}^{3} + 3x {}^{2} \\ - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 10x {}^{3} + x {}^{2} + x - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 10x {}^{3} + 20x {}^{2} + 60x \\ - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 21x {}^{2} + 61x - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 21x{}^{2} + 42x + 63 \\ - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 103x + 62$

this is your answer by DIVISION METHOD .

Discussion

8.	Please help is neededwrite the HCF of 3³×5 and 3²×5
Answer» 9 is the HIGHEST common Factor Of the GIVEN QUESTION! Follow Me!

8.

Please help is neededwrite the HCF of 3³×5 and 3²×5

Answer»

9 is the HIGHEST common Factor Of the GIVEN QUESTION!

Follow Me!

Discussion

9.	A woman sold 15 bed sheets for rs.15000 hence gaining the cost price of 5 bed sheets the cost per sheet is
Answer» Answer: 5000 Step-by-step explanation: COST of 15 BEDSHEETS =15000 cost of 1 bedsheet =15000÷15 1000 cost of 5 bedsheets=1000×5 5000

9.

A woman sold 15 bed sheets for rs.15000 hence gaining the cost price of 5 bed sheets the cost per sheet is

Answer»

Answer:

5000

Step-by-step explanation:

COST of 15 BEDSHEETS =15000

cost of 1 bedsheet =15000÷15

1000

cost of 5 bedsheets=1000×5

5000

Discussion

10.	Half of the herd of deer are grazing In the field and three fourth of remaining are playing nearby. the rest 9 are drinking water from the pond . findthe number of deer in the herd Hint let the number if deer in the herd be x Number of those who are grazing = x upon 2 Remaining = x upon 2 Number of those who are playing = (3/4× x/2 = 3x/8 X/2 +3x/8=9=x find x
Answer» Step-by-step EXPLANATION: let x be the no. of deers HALF of the heard=x/2 3/4 of REMAINING =3/4x/2 remaining =9 x/2+3/4x/2+9=x x/2+3x/8+9=x LCM=8 (4x+3x+72)/8=x (7x+72)=8x 72=8x-7x 72=x There are 72 deers in the heard

10.

Half of the herd of deer are grazing In the field and three fourth of remaining are playing nearby. the rest 9 are drinking water from the pond . findthe number of deer in the herd Hint let the number if deer in the herd be x Number of those who are grazing = x upon 2 Remaining = x upon 2 Number of those who are playing = (3/4× x/2 = 3x/8 X/2 +3x/8=9=x find x

Answer»

Step-by-step EXPLANATION:

let x be the no. of deers

HALF of the heard=x/2

3/4 of REMAINING =3/4*x/2

remaining =9

x/2+3/4*x/2+9=x

x/2+3x/8+9=x

LCM=8

(4x+3x+72)/8=x

(7x+72)=8x

72=8x-7x

72=x

There are 72 deers in the heard

Discussion

11.	Find the number of terms of the following series 3+5+7+...........=624
Answer» Answer: 609 Step-by-step explanation: 3+5+7=15 624-15=609 3+5+7+609=624

11.

Find the number of terms of the following series 3+5+7+...........=624

Answer»

Answer:

609

Step-by-step explanation:

3+5+7=15

624-15=609

3+5+7+609=624

Discussion

12.	Find the ratio of 250 ml to 4 litre
Answer» ANSWER: SINCE 1 Lt.=1000 ml hence 4 Lt. =4000 ml ratio=250ml/4000ml=1/16 1:16

12.

Find the ratio of 250 ml to 4 litre

Answer»

ANSWER:

SINCE 1 Lt.=1000 ml

hence 4 Lt. =4000 ml

ratio=250ml/4000ml=1/16

1:16

Discussion

13.	Solve equation s-7t+42 =0 and 2s -t =1
Answer» ANSWER: I HOPE this HELPS you. the ATTACHMENT is GIVEN above

13.

Solve equation s-7t+42 =0 and 2s -t =1

Answer»

ANSWER:

I HOPE this HELPS you.

the ATTACHMENT is GIVEN above

Discussion

14.	The hcf of two equal positive integers k,k is
Answer» The HCF of two equal positive INTEGERS K,k is k. Step-by-step explanation: To find : The HCF of two equal positive integers k,k ? Solution : The Highest Common FACTOR (H.C.F) of two (or more) numbers is the largest number that divides EVENLY into both numbers. If we factor the number, $k=1\times k$ As numbers are same. The highest common factor of k and k is k. Therefore, the HCF of two equal positive integers k,k is k. #Learn more If a and b are any two positive integers then HCF(a,b)*lcm(a,b)is equal to brainly.in/question/8995967

14.

The hcf of two equal positive integers k,k is

Answer»

The HCF of two equal positive INTEGERS K,k is k.

Step-by-step explanation:

To find : The HCF of two equal positive integers k,k ?

Solution :

The Highest Common FACTOR (H.C.F) of two (or more) numbers is the largest number that divides EVENLY into both numbers.

If we factor the number,

$k=1\times k$

As numbers are same.

The highest common factor of k and k is k.

Therefore, the HCF of two equal positive integers k,k is k.

#Learn more

If a and b are any two positive integers then HCF(a,b)*lcm(a,b)is equal to

brainly.in/question/8995967

Discussion

15.	1 million ______ hundred thousand1 crore _______ ten lackh1 million ______ lackh
Answer» Answer: 10,10,10 Step-by-step explanation: 1 MILLION =10 hundred thousands 1 CRORE= 100 lakhs or 10 TEN lakhs 1 million=10 lakhs

15.

1 million __ hundred thousand1 crore _ ten lackh1 million ____ lackh

Answer»

Answer:

10,10,10

Step-by-step explanation:

1 MILLION =10 hundred thousands

1 CRORE= 100 lakhs or 10 TEN lakhs

1 million=10 lakhs

Discussion

16.	Show that r*=r/0 is a group under the operation of multiplication
Answer» ANSWER: under the OPERATION of MULTIPLICATION

16.

Show that r*=r/0 is a group under the operation of multiplication

Answer»

ANSWER:

under the OPERATION of MULTIPLICATION

Discussion

17.	PLEASE SOLVE THE ABOVE QUESTION!
Answer» HOPE it HELP u plz MARK as brainlist Step-by-step EXPLANATION: -63/8

17.

PLEASE SOLVE THE ABOVE QUESTION!

Answer»

HOPE it HELP u

plz MARK as brainlist

Step-by-step EXPLANATION:

-63/8

Discussion

18.	If Sina - Cosa is equal to zero then find the value of sina,cosa and tana
Answer» ANSWER: SIN a=Cos a, Tan a= Sin a/Cos a Step-by-step EXPLANATION: sin a- cos a=0 sin a=cos a tan a=sin a/ cos a hope it helpful pls mark as BRAINLEIST

18.

If Sina - Cosa is equal to zero then find the value of sina,cosa and tana

Answer»

ANSWER:

SIN a=Cos a, Tan a= Sin a/Cos a

Step-by-step EXPLANATION:

sin a- cos a=0

sin a=cos a

tan a=sin a/ cos a

hope it helpful pls mark as BRAINLEIST

Discussion

19.	An=5n-3, find the common difference
Answer» 5n-an=3 n(5-a)=3 5-a=3/n

19.

An=5n-3, find the common difference

Answer»

5n-an=3

n(5-a)=3

5-a=3/n

Discussion

20.	1234567890134567777+62625652525226262 zwzwzwzwzwzwzww-562&52&625625=
Answer» ANS=>*hjejwjjwijqcwfjqkqvss* *HOPE* IT *HELPS* U *ALOT.*...

20.

1234567890134567777+62625652525226262 zwzwzwzwzwzwzww-562&52&625625=

Answer»

ANS=>hjejwjjwijqcwfjqkqvss

HOPE IT HELPS U ALOT....

Discussion

21.	Find the equivalent resistance if the value of R in the circuit is 1.1ohn
Answer» Answer: 0.6 Ohm Step-by-step explanation: According to the given FIG, There are 3 parallel combination along with series. First solving the series combination we GET, Series combination FORMULA, R = R1 + R2 Where R is the EQUIVALENT resistance of R1 and R2 connected in series. Thus for 1st row, R1 eq = R R2 eq = 2R R3 eq = 3R Where R1 eq , R2 eq and R3 eq are the equivalent resistance of first , second and third row. Now, these equivalent resistors are in parallel combination. Parallel combination formula, 1/R' eq = 1/R1 + 1/R2 Where R' eq is the equivalent resistance of R1 and R2 connected in parallel. Thus final combination of resistance is, 1/R' = 1/R + 1/2R + 1/3R Where R' is the final equivalent resistance. 1/R' =6R^2+3R^2+2R^2/3R×2R×R 1/R' = 11R^2/6R^3 1/R' = 11/6R R' = 6R/11 Putting the values we get, R' = 6×1.1/11 R' = 6.6/11 R' = 0.6 ohm Thus final equivalent resistance is 0.6 ohm.

21.

Find the equivalent resistance if the value of R in the circuit is 1.1ohn

Answer»

Answer:

0.6 Ohm

Step-by-step explanation:

According to the given FIG,

There are 3 parallel combination along with series.

First solving the series combination we GET,

Series combination FORMULA,

R = R1 + R2

Where R is the EQUIVALENT resistance of R1 and R2 connected in series.

Thus for 1st row,

R1 eq = R

R2 eq = 2R

R3 eq = 3R

Where R1 eq , R2 eq and R3 eq are the equivalent resistance of first , second and third row.

Now, these equivalent resistors are in parallel combination.

Parallel combination formula,

1/R' eq = 1/R1 + 1/R2

Where R' eq is the equivalent resistance of R1 and R2 connected in parallel.

Thus final combination of resistance is,

1/R' = 1/R + 1/2R + 1/3R

Where R' is the final equivalent resistance.

1/R' =6R^2+3R^2+2R^2/3R×2R×R

1/R' = 11R^2/6R^3

1/R' = 11/6R

R' = 6R/11

Putting the values we get,

R' = 6×1.1/11

R' = 6.6/11

R' = 0.6 ohm

Thus final equivalent resistance is 0.6 ohm.

Discussion

22.	A =14 -6root5 find root a+1/roota
Answer» ANSWER: SEE image Step-by-step EXPLANATION: for explanation

22.

A =14 -6root5 find root a+1/roota

Answer»

ANSWER:

SEE image

Step-by-step EXPLANATION:

for explanation

Discussion

23.	Divide the sum of 3/7 and 7/3 by their difference.
Answer» ANSWER: $\frac{3}{7} + \frac{7}{3} = \frac{58}{21} \\ \frac{7}{3} - \frac{3}{7} = \frac{40}{21} \\ as \: per \: question \\ \frac{ \frac{58}{21} }{ \frac{40}{21} } = \frac{58}{40} = \frac{29}{20} \: this \: is \: your \: answer$

23.

Divide the sum of 3/7 and 7/3 by their difference.

Answer»

ANSWER:

$\frac{3}{7} + \frac{7}{3} = \frac{58}{21} \\ \frac{7}{3} - \frac{3}{7} = \frac{40}{21} \\ as \: per \: question \\ \frac{ \frac{58}{21} }{ \frac{40}{21} } = \frac{58}{40} = \frac{29}{20} \: this \: is \: your \: answer$

Discussion

24.	Evaluate 15 multiply 8358 multiply 4
Answer» Answer: 501480 Step-by-step explanation: = 15 X 8358 x 4 = 8358 x 15 x 4 = 8358 x 60 = 501480 Plz MARK it as the Brainliest

24.

Evaluate 15 multiply 8358 multiply 4

Answer»

Answer:

501480

Step-by-step explanation:

= 15 X 8358 x 4

= 8358 x 15 x 4

= 8358 x 60

= 501480

Plz MARK it as the Brainliest

Discussion

25.	) A sum of Rs. 30000 is invested for 3 years at 7.5%compound interest, what is the sum after one year?A) Rs.32250 B) Rs.32200 C) Rs.32100 D) Rs.30500
Answer» <P> COMPOUND AMOUNT = P(1+R/100)^T = Rs.30000(1+7.5/100)^1 = Rs.30000(1+75/1000)^1 = 30000×43/40 = Rs.750×43 = Rs.32250 hence ANSWER is Rs.32250 (A)

25.

) A sum of Rs. 30000 is invested for 3 years at 7.5%compound interest, what is the sum after one year?A) Rs.32250 B) Rs.32200 C) Rs.32100 D) Rs.30500

Answer»

<P>

COMPOUND AMOUNT

= P(1+R/100)^T

= Rs.30000(1+7.5/100)^1

= Rs.30000(1+75/1000)^1

= 30000×43/40

= Rs.750×43

= Rs.32250

hence ANSWER is Rs.32250 (A)

Discussion

26.	Plz guys answer this question.3/4×8/9-3/4×5
Answer»

Discussion

27.	Find value of 10 5 multiply 8358 multiply 4
Answer» Answer: 10585384 896490*4 3585960

27.

Find value of 10 5 multiply 8358 multiply 4

Answer»

Answer:

105*8538*4

896490*4

3585960

Discussion

28.	Five year ago a man was seven times as old as his son. Five year hence, the father will be three times as old as his son. Fins their present age.
Answer» Solution Let the past age of son = 'x' Let the past age of father = 7x So, Present ages are x + 5 and 7x + 5 Future age of son = x + 10 Future age of father = 7x + 10 Given, ⇒ 7x + 10 = 3 (x + 10) ⇒ 7x + 10 = 3X + 30 ⇒ 7x - 3x = 30 - 16 ⇒ 4x = 20 ⇒ x = 5 Let US verify our answer, ⇒ 7 × 5 + 10 = 3 (5 + 10) ⇒ 35 + 10 = 3×5 + 3×10 ⇒ 45 = 15 + 30 ⇒ 45 = 45 LHS = RHS Hence it is verified. ⇒ 7x = 7 × 5 = 35 ⇒ x+5 = 5 + 5 = 10 ⇒ 7x + 5 = (7 × 5)+ 5 = 35 + 5 = 40

28.

Five year ago a man was seven times as old as his son. Five year hence, the father will be three times as old as his son. Fins their present age.

Answer»

Solution

Let the past age of son = 'x'

Let the past age of father = 7x

So,

Present ages are x + 5 and 7x + 5

Future age of son = x + 10

Future age of father = 7x + 10

Given,

⇒ 7x + 10 = 3 (x + 10)

⇒ 7x + 10 = 3X + 30

⇒ 7x - 3x = 30 - 16

⇒ 4x = 20

⇒ x = 5

Let US verify our answer,

⇒ 7 × 5 + 10 = 3 (5 + 10)

⇒ 35 + 10 = 3×5 + 3×10

⇒ 45 = 15 + 30

⇒ 45 = 45

LHS = RHS

Hence it is verified.

⇒ 7x = 7 × 5 = 35

⇒ x+5 = 5 + 5 = 10

⇒ 7x + 5 = (7 × 5)+ 5 = 35 + 5 = 40

Discussion

29.	Find the value of m and n for which the followingsystem of linear equations has infinity or manysolution.3x + 4y = 12(m + n) x + 2(m -n)y = 5 m-1
Answer» Step-by-step explanation: 3m-12n-3=0 m-4n-1=0-----1 4m-24n+4=0 m-6n+1=0------2 on SOLVING 1&2; n=1 m=5

29.

Find the value of m and n for which the followingsystem of linear equations has infinity or manysolution.3x + 4y = 12(m + n) x + 2(m -n)y = 5 m-1

Answer»

Step-by-step explanation:

3m-12n-3=0

m-4n-1=0-----1

4m-24n+4=0

m-6n+1=0------2

on SOLVING 1&2;

n=1

m=5

Discussion

30.	Find means 82,76,70,64,58,52,46
Answer» ANSWER: Mean The formula of mean = SUM of all the NUMBERS / TOTAL numbers 82+76+70+64+58+52+46/ 7 448/7 64 Hope it helps

30.

Find means 82,76,70,64,58,52,46

Answer»

ANSWER:

Mean

The formula of mean =

SUM of all the NUMBERS / TOTAL numbers

82+76+70+64+58+52+46/ 7

448/7

64

Hope it helps

Discussion

31.	Find value of 25 multiple 8358 multiple 4
Answer» Answer: 835,800 Step-by-step explanation: 25×8358=208,950 208,950×4=835,800

31.

Find value of 25 multiple 8358 multiple 4

Answer»

Answer:

835,800

Step-by-step explanation:

25×8358=208,950

208,950×4=835,800

Discussion

32.	Pls help, picture included.
Answer» C is RIGHT option. PLEASE mark as BRAINLIST.

32.

Pls help, picture included.

Answer»

C is RIGHT option.

PLEASE mark as BRAINLIST.

Discussion

33.	Find AP whose sum and product of 3 adjacent terms are 39 and 1560 respectively nth term of a sequence is given by the formula an = 10-3n ,find the sum of its 20 terms .
Answer» Step-by-step explanation: Given: Sum of 3 adjacent terms=39 Product of 3 adjacent terms=1560 an=10-3n To find: A.P FORMED Sum of its 20 terms solution: Let 3 adjacent terms be a-d, a, a+d sum=a-d+a+a+d=3a but it is given that sum = 39 therefore, 3a=39 a=13 - - - - 1 Product= (a-d)(a)(a+d) =(a^2-ad)(a+d) =a^3+a^2d-a^2d-ad^2 =a^3-ad^2 but it is given that product = 1560 therefore, a^3-ad^2=1560 a(a^2-d^2)=1560- - - - 2 from 1 a= 13 putting in 2, we get, 13(13^2-d^2)=1560 169-d^2=1560/13 -d^2=1560/13-169 -d^2=1560/13-2197/13 -d^2=-637/13 d^2=49 d=7 Now A.P formed: =a,a+d,a+2d- - - =13,20,27- - - sum of its 20 terms=n/2(2a+(n-1)d) here n=20 (given) a=13(find above) d=7(find above) putting values we get =20/2(213+(20-1)7) =10(26+133) =10159 =1590

33.

Find AP whose sum and product of 3 adjacent terms are 39 and 1560 respectively nth term of a sequence is given by the formula an = 10-3n ,find the sum of its 20 terms .

Answer»

Step-by-step explanation:

Given:

Sum of 3 adjacent terms=39

Product of 3 adjacent terms=1560

an=10-3n

To find:

A.P FORMED

Sum of its 20 terms

solution:

Let 3 adjacent terms be

a-d, a, a+d

sum=a-d+a+a+d=3a

but it is given that sum = 39

therefore,

3a=39

a=13 - - - - 1

Product= (a-d)(a)(a+d)

=(a^2-ad)(a+d)

=a^3+a^2d-a^2d-ad^2

=a^3-ad^2

but it is given that product = 1560

therefore,

a^3-ad^2=1560

a(a^2-d^2)=1560- - - - 2

from 1 a= 13

putting in 2, we get,

13(13^2-d^2)=1560

169-d^2=1560/13

-d^2=1560/13-169

-d^2=1560/13-2197/13

-d^2=-637/13

d^2=49

d=7

Now A.P formed:

=a,a+d,a+2d- - -

=13,20,27- - -

sum of its 20 terms=n/2(2a+(n-1)d)

here

n=20 (given)

a=13(find above)

d=7(find above)

putting values we get

=20/2(2*13+(20-1)7)

=10(26+133)

=10*159

=1590

Discussion

34.	(1) what is the length of PB in PQR if A is the mid-point ofPR and ABII QR and PQ = 6cm
Answer» Step-by-step explanation: In traingle PQR, B is the MIDPOINT of PQ PB=1/2PQ =6/2 =3 HOPE IT HELPS PLEASE MARK ME AS BRAINLEAST

34.

(1) what is the length of PB in PQR if A is the mid-point ofPR and ABII QR and PQ = 6cm

Answer»

Step-by-step explanation:

In traingle PQR,

B is the MIDPOINT of PQ

PB=1/2PQ

=6/2

=3

HOPE IT HELPS

PLEASE MARK ME AS BRAINLEAST

Discussion

35.	A car covers a distance of 45.6 km in 2.4 hours. How much distance will it cover in 1 hour. Answer with full solution
Answer» Answer: 19 KM Step-by-step explanation: 2.4 hours =45.6 km what about 1 HOUR = (1 h ˣ 45.6 km)/2.4 hours = 19 km

35.

A car covers a distance of 45.6 km in 2.4 hours. How much distance will it cover in 1 hour. Answer with full solution

Answer»

Answer:

19 KM

Step-by-step explanation:

2.4 hours =45.6 km

what about 1 HOUR

= (1 h ˣ 45.6 km)/2.4 hours

= 19 km

Discussion

36.	Solve cos ( sec^-1 x)
Answer» Step-by-step EXPLANATION: COS(sec^-1). sec^-1=TAN^ cos(tan^) cos X sin^/cos^ =sin^/cos ANS

36.

Solve cos ( sec^-1 x)

Answer»

Step-by-step EXPLANATION:

COS(sec^-1). sec^-1=TAN^

cos(tan^)

cos X sin^/cos^

=sin^/cos ANS

Discussion

37.	Which of the following are scalar quantities - mass, velocity, speed, length, distance, displacement, temperature, force, weight, power, work and energy
Answer» Answer: MASS, VELOCITY, speed, LENGTH, distance, Temperature,force, weight,POWER, energy Hope this help...... Mark as a brainlist please

37.

Which of the following are scalar quantities - mass, velocity, speed, length, distance, displacement, temperature, force, weight, power, work and energy

Answer»

Answer:

MASS, VELOCITY, speed, LENGTH, distance, Temperature,force, weight,POWER, energy

Hope this help......

Mark as a brainlist

please

Discussion

38.	In a school, there are 500 students.For practice they have been asked to stand in such a manner that the no. Of columns is the same as the no. Of rows.Find out how many students will be left out.
Answer» Answer: 22........................

38.

In a school, there are 500 students.For practice they have been asked to stand in such a manner that the no. Of columns is the same as the no. Of rows.Find out how many students will be left out.

Answer»

Answer:

22........................

Discussion

39.	(c) 4 months 2 weeks to days
Answer» what is this.....??????

Discussion

40.	Find a and b 1. a+b
Answer» ANSWER: Step-by-step EXPLANATION: BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

40.

Find a and b 1. a+b

Answer»

ANSWER:

Step-by-step EXPLANATION:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

Discussion

41.	Simplify using property -3/10 +7/15 +3/-20 +-9/20 +13/15 +13/-20
Answer» this SIMPLIFY is TRICKY it's ANSWER is -0.2166

Discussion

42.	Find the least number that should be subtracted from 2050 so tha the difference is exactly divisible by 57
Answer» ANSWER: 35 Step-by-step explanation: 35 TIMES 57=1995 36 times 57=2052 1995 DIVIDED by 57=35 35 is your answer

42.

Find the least number that should be subtracted from 2050 so tha the difference is exactly divisible by 57

Answer»

ANSWER:

35

Step-by-step explanation:

35 TIMES 57=1995

36 times 57=2052

1995 DIVIDED by 57=35

35 is your answer

Discussion

43.	14, 18 ,9 25, 0, ? Wht is the value of this ?
Answer» ANSWER: i THINK so -36 Step-by-step explanation: because its DIFFERENCE is -4,9.-16 .25 then -36

43.

14, 18 ,9 25, 0, ? Wht is the value of this ?

Answer»

ANSWER:

i THINK so -36

Step-by-step explanation:

because its DIFFERENCE is -4,9.-16 .25 then -36

Discussion

44.	A car travels 15.5. in a litre. how much km it goes in 12.5 litreAnswer is 193.75Does there is conversion of km or litre needed
Answer» Answer: No Step-by-step explanation: No CONVERSION is required. If the data GIVEN in the question is 15.5 kms/litre. Then the answer can be DIRECTLY OBTAINED by multiplying 15.5 and 12.5 which gives the answer 193.75

44.

A car travels 15.5. in a litre. how much km it goes in 12.5 litreAnswer is 193.75Does there is conversion of km or litre needed

Answer»

Answer:

No

Step-by-step explanation:

No CONVERSION is required. If the data GIVEN in the question is 15.5 kms/litre. Then the answer can be DIRECTLY OBTAINED by multiplying 15.5 and 12.5 which gives the answer 193.75

Discussion

45.	Find the wrong term 8,15,29,50,77,113
Answer» 77 i THINK 8+7 GIVE 15,15+7+7 gives 29,29+7+7+7 gives 50,50+7+7+7+7 gives 78 and 78+7+7+7+7+7 gives 113

45.

Find the wrong term 8,15,29,50,77,113

Answer»

77 i THINK 8+7 GIVE 15,15+7+7 gives 29,29+7+7+7 gives 50,50+7+7+7+7 gives 78 and 78+7+7+7+7+7 gives 113

Discussion

46.	By how much is 4792821 greater than one crore
Answer» ANSWER: Because this no is GREATER than CRORE

46.

By how much is 4792821 greater than one crore

Answer»

ANSWER:

Because this no is GREATER than CRORE

Discussion

47.	52 as sum of two odd prime number
Answer» the ANSWER is 25+27= 52

47.

52 as sum of two odd prime number

Answer»

the ANSWER is 25+27= 52

Discussion

48.	Z^3 -6z^2 +11z -6 find the zero of the polynomial
Answer» ANSWER: (z-1) z=1 (z-2) z=2 (z-3) z=3 are the ZERO of the POLYNOMIAL

48.

Z^3 -6z^2 +11z -6 find the zero of the polynomial

Answer»

ANSWER:

(z-1) z=1

(z-2) z=2

(z-3) z=3

are the ZERO of the POLYNOMIAL

Discussion

49.	Represent root 6.5 on the number line
Answer» ANSWER: in which CLASS do you READ

49.

Represent root 6.5 on the number line

Answer»

ANSWER:

in which CLASS do you READ

Discussion

50.	(x-y) whole square = 4- 4y+y square, so find the value of x??
Answer» ${(x - y)}^{2} = 4 - 4y + {y}^{2} \\ {x}^{2} - 2xy + {y}^{2} = {2}^{2} - 2 \times 2 \times y + {y}^{2} \\ x = 2$

50.

(x-y) whole square = 4- 4y+y square, so find the value of x??

Answer»

${(x - y)}^{2} = 4 - 4y + {y}^{2} \\ {x}^{2} - 2xy + {y}^{2} = {2}^{2} - 2 \times 2 \times y + {y}^{2} \\ x = 2$

Discussion

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