332354 + Interview Questions in Secondary School in Math

1.	Subtract 7root5 +2root3 from 6root3 - 4 root5
Answer» Answer: -808 - 16815 = -17623 Step-by-step explanation: 7root5 + 2root3 can be WRITTEN as 16807 + 8 = 16815 6root3 - 4root5 can be written as 216 - 1024 = -808 If you SUBTRACT 16815 from -808 you get- -17623 because when you subtract a POSITIVE from a negative, the answer will be a negative Therefore -808 - 16815 = -17623 Hope this helps :)

1.

Subtract 7root5 +2root3 from 6root3 - 4 root5

Answer»

Answer:

-808 - 16815 = -17623

Step-by-step explanation:

7root5 + 2root3 can be WRITTEN as

16807 + 8 = 16815

6root3 - 4root5 can be written as

216 - 1024 = -808

If you SUBTRACT 16815 from -808 you get- -17623 because when you subtract a POSITIVE from a negative, the answer will be a negative

Therefore -808 - 16815 = -17623

Hope this helps :)

Discussion

2.	The perimeter of a rectangular piece of paper is 100cm. It is cut into 4 equal rectangles. What is the perimeter of the four smaller rectangles?
Answer» ANSWER: 50 is the answer ASSUME the SIDES to be X and y and SOLVE

2.

The perimeter of a rectangular piece of paper is 100cm. It is cut into 4 equal rectangles. What is the perimeter of the four smaller rectangles?

Answer»

ANSWER:

50 is the answer ASSUME the SIDES to be X and y and SOLVE

Discussion

3.	Find the product by breaking the multiplicand into addends 9641×107.
Answer» ANSWER: The answer is 1031587. R

3.

Find the product by breaking the multiplicand into addends 9641×107.

Answer»

ANSWER:

The answer is 1031587.

R

Discussion

4.	A father is age is three times the sum ofthe ages of his two children After5 years he age will be the timethe sum of their cages find the presentages of the father
Answer» Step-by-step EXPLANATION: LET FATHER AND SUM OF HIS SONS PRESENT AGE BE X AND Y YEARS RESPECTIVELY. X=3*Y ......................1 AFTER 5 YEARS X + 5 = 2(Y+ 5) X-2Y= 5....................................................2 USING EQ 1 AND 2 Y=5 X=15

4.

A father is age is three times the sum ofthe ages of his two children After5 years he age will be the timethe sum of their cages find the presentages of the father

Answer»

Step-by-step EXPLANATION:

LET FATHER AND SUM OF HIS SONS PRESENT AGE BE X AND Y YEARS RESPECTIVELY.

X=3*Y ......................1

AFTER 5 YEARS

X + 5 = 2(Y+ 5)

X-2Y= 5....................................................2

USING EQ 1 AND 2

Y=5

X=15

Discussion

5.	Find the factors of 3 x^2+x
Answer» ♦️ FACTORS OF 3x^2 + X will be......................... $x(3x + 1)$ where x and (3x+1) are the factors. HOPE_IT_HELPS_✌✌✌ FOLLOW_ME_IF_U_CAN_❤

5.

Find the factors of 3 x^2+x

Answer»

♦️ FACTORS OF 3x^2 + X

will be.........................

$x(3x + 1)$

where x and (3x+1) are the factors.

HOPE_IT_HELPS_✌✌✌

FOLLOW_ME_IF_U_CAN_❤

Discussion

6.	Find the median for class 10th urgent pllzzz
Answer» MEDIAN of no. of students will be 10. To find median arrange the data in ASCENDING ORDER and make PAIRS of 2-2 no. and the middle no. will be the median.

6.

Find the median for class 10th urgent pllzzz

Answer»

MEDIAN of no. of students will be 10.

To find median arrange the data in ASCENDING ORDER and make PAIRS of 2-2 no. and the middle no. will be the median.

Discussion

7.	15 → 15x3 = 458 3039fare gergesag niepabeslorodone ya ago the walio of ages of A and Bwas 4:3. Dne you hence their ages wouldofde 5:4 nohat would be the forcether Sresent ages?2018 2019Here;3),151Safura1 Imbies=y?4+
Answer» ANSWER: FIRST WRITE it CLEARLY PLEASE.....

7.

15 → 15x3 = 458 3039fare gergesag niepabeslorodone ya ago the walio of ages of A and Bwas 4:3. Dne you hence their ages wouldofde 5:4 nohat would be the forcether Sresent ages?2018 2019Here;3),151Safura1 Imbies=y?4+

Answer»

ANSWER:

FIRST WRITE it CLEARLY PLEASE.....

Discussion

8.	Books in the library must not be taken away. change in active voice
Answer» ANSWER: Dinot TAKE BOOKS from the LIBRARY

8.

Books in the library must not be taken away. change in active voice

Answer»

ANSWER:

Dinot TAKE BOOKS from the LIBRARY

Discussion

9.	a point lie on negative side of y axis it's distance from origin is 3units write the CO ordinate of points
Answer» Answer: since the POINT LIES on negative SIDE of y-axis so x coordination will be zero so the point is (0,-3)

9.

a point lie on negative side of y axis it's distance from origin is 3units write the CO ordinate of points

Answer»

Answer:

since the POINT LIES on negative SIDE of y-axis so x coordination will be zero so the point is (0,-3)

Discussion

10.	A) PageCOPY8) If the day before yesterday is two days after Monday then what day is it today?(a) Monday (b) Tuesday (c) Wednesday (d) Saturday
Answer» THE ANSWER IS WEDNESDAY.....

Discussion

11.	2. Simplify:3-5 x10-5 x 1255-2 x6-5
Answer» ANSWER: (i)3-5×10-5×125 =-2×5×125 =-10×125 =-1250 (II)5-2×6-5 =3×1 =3 hope it HELPS U

11.

2. Simplify:3-5 x10-5 x 1255-2 x6-5

Answer»

ANSWER:

(i)3-5×10-5×125

=-2×5×125

=-10×125

=-1250

(II)5-2×6-5

=3×1

=3

hope it HELPS U

Discussion

12.	In a city, there are 575968 men, 685492 children and 495732 women. Find the total population of the city
Answer» ANSWER: Step-by-step EXPLANATION: The TOTAL poulation of CITY is 575968+685492+495732=1757192

12.

In a city, there are 575968 men, 685492 children and 495732 women. Find the total population of the city

Answer»

ANSWER:

Step-by-step EXPLANATION:

The TOTAL poulation of CITY is 575968+685492+495732=1757192

Discussion

13.	Set is a well-defind collection of destinct objects give a example of sets
Answer» Answer: N(the SET of all natural nos.) or W (the set of all WHOLE nos.)

13.

Set is a well-defind collection of destinct objects give a example of sets

Answer»

Answer:

N(the SET of all natural nos.) or W (the set of all WHOLE nos.)

Discussion

14.	What is the HCF of 24 and 864
Answer» Step-by-step explanation: 24 is the h.c.god 24 and 864

14.

What is the HCF of 24 and 864

Answer»

Step-by-step explanation:

24 is the h.c.god 24 and 864

Discussion

15.	A shop keeper mixing two verities of tea powder one casting rs.35/kg and other at rs. 45/kg. The ratio is 3:2. If he sells the mixture at rs. 41.6/kg what would be the gain %?
Answer» ANSWER: I don't know Hope you UNDERSTOOD

15.

A shop keeper mixing two verities of tea powder one casting rs.35/kg and other at rs. 45/kg. The ratio is 3:2. If he sells the mixture at rs. 41.6/kg what would be the gain %?

Answer»

ANSWER:

I don't know

Hope you UNDERSTOOD

Discussion

16.	9. Show that the points A(7, 10), B(-2,5) and C(3,-4) are the vertices of anisosceles right-angled triangle.
Answer» Answer: FIND the DISTANCE between any side.... after that U will see that 2 side will have same distance

16.

9. Show that the points A(7, 10), B(-2,5) and C(3,-4) are the vertices of anisosceles right-angled triangle.

Answer»

Answer:

FIND the DISTANCE between any side.... after that U will see that 2 side will have same distance

Discussion

17.	A shoe rack has n" different pairs of shoes. The least number of shoes to be selected from the rack so as to ensure that a pair is included in the selection is
Answer» ANSWER: PLEASE WRITE QUESTION CORRECT

17.

A shoe rack has n" different pairs of shoes. The least number of shoes to be selected from the rack so as to ensure that a pair is included in the selection is

Answer»

ANSWER:

PLEASE WRITE QUESTION CORRECT

Discussion

18.	Explain why 47 19 11 + 19 is a composite number?
Answer» Given : 47 * 19 * 11 + 19 is a composite NUMBER To Find : Explain why Solution: a composite number is a number which have atleast one factor other than number itself and 1. 47 * 19 * 11 + 19 Taking 19 as common = 19 ( 47 * 11 + 1) = 19 k Hence number is FORM 19 * k where 19 and k ≠ 1 and 19k Hence number has atleast 4 FACTORS , 1 , 19 , k , 19k where k = 47 * 11 + 1 Hence 47 * 19 * 11 + 19 is a composite number Learn More: Is 385 a coprime and 621 is also a coprime SHOW how they are ... brainly.in/question/12213634 If p,q are two co-prime number then HCF of (p,q) brainly.in/question/1691019

18.

Explain why 47 19 11 + 19 is a composite number?

Answer»

Given : 47 * 19 * 11 + 19 is a composite NUMBER

To Find : Explain why

Solution:

a composite number is a number which have atleast one factor other than number itself and 1.

47 * 19 * 11 + 19

Taking 19 as common

= 19 ( 47 * 11 + 1)

= 19 k

Hence number is FORM 19 * k where 19 and k ≠ 1 and 19k

Hence number has atleast 4 FACTORS , 1 , 19 , k , 19k

where k = 47 * 11 + 1

Hence 47 * 19 * 11 + 19 is a composite number

Learn More:

Is 385 a coprime and 621 is also a coprime SHOW how they are ...

brainly.in/question/12213634

If p,q are two co-prime number then HCF of (p,q)

brainly.in/question/1691019

Discussion

19.	If a year has 360 days all months with 30 days probability
Answer» ANSWER: the answer is of UR QUESTION is 1/3

19.

If a year has 360 days all months with 30 days probability

Answer»

ANSWER:

the answer is of UR QUESTION is 1/3

Discussion

20.	If a b c are in ap prove that b+c c+a a+b are also in ap
Answer» A, B and C are in AP Let B = A + d C = A + 2d , d = common difference Let 2A + d = X So A + B = A + A + d = 2A + d = X A + C = A + A + 2d = 2A + 2d = X + d B + C = A + d + A + 2d = 2A + 3d = X + 2d Now see that X, X+d and X+2d are in AP. That is A+B, A+C and B+C are in AP HOPE THIS HELPS YOU........

20.

If a b c are in ap prove that b+c c+a a+b are also in ap

Answer»

A, B and C are in AP

Let B = A + d

C = A + 2d , d = common difference

Let 2A + d = X

So A + B = A + A + d = 2A + d = X

A + C = A + A + 2d = 2A + 2d = X + d

B + C = A + d + A + 2d = 2A + 3d = X + 2d

Now see that X, X+d and X+2d are in AP.

That is A+B, A+C and B+C are in AP

HOPE THIS HELPS YOU........

Discussion

21.	If a² + b² = 5ab, then the value of (a²/b² + b²/a²) is
Answer» *Here* is *the* *SOLUTION* to *your* *QUESTION*...!!!

21.

If a² + b² = 5ab, then the value of (a²/b² + b²/a²) is

Answer»

Here is the SOLUTION to your QUESTION...!!!

Discussion

22.	How to find minimal polynomial of block diagonal matrices?
Answer» Step-by-step explanation: To calculate the STANDARD deviation for a SAMPLE of N measurements: SUM all the measurements and divide by N to get the average, or mean. Now, subtract this average from each of the N measurements to obtain N "deviations". SQUARE each of these N deviations and add them all up. Divide this RESULT by. (N − 1)

22.

How to find minimal polynomial of block diagonal matrices?

Answer»

Step-by-step explanation:

To calculate the STANDARD deviation for a SAMPLE of N measurements:

SUM all the measurements and divide by N to get the average, or mean.

Now, subtract this average from each of the N measurements to obtain N "deviations".

SQUARE each of these N deviations and add them all up.

Divide this RESULT by. (N − 1)

Discussion

23.	Find the least value of 1/5cosx+12sinx+5
Answer» Step-by-step explanation: Difference between monford reform and govt. Of india act 1919Rigidity it is the property of matter to ressit the CHANGE of its SHAPE. 2compressibility it is the property of matter in which its volume is decreased by applying FORCE. 3 fluidityit is the ability of matter to flow. ... 6kinetic energy it is the energypossessed by the PARTICLES of matter due to its motion.

23.

Find the least value of 1/5cosx+12sinx+5

Answer»

Step-by-step explanation:

Difference between monford reform and govt. Of india act 1919Rigidity it is the property of matter to ressit the CHANGE of its SHAPE. 2compressibility it is the property of matter in which its volume is decreased by applying FORCE. 3 fluidityit is the ability of matter to flow. ... 6kinetic energy it is the energypossessed by the PARTICLES of matter due to its motion.

Discussion

24.	Find the greatest 4-digit number which when divied by 36,30,24,16
Answer» Answer: 9360 Step-by-step explanation: Greatest FOUR digit no: 9999 LCM of 36, 30, 24, 16= 720 On DIVIDING 9999/720 we GET, Remainder= 639 9999-639= 9360 =9360

24.

Find the greatest 4-digit number which when divied by 36,30,24,16

Answer»

Answer:

9360

Step-by-step explanation:

Greatest FOUR digit no: 9999

LCM of 36, 30, 24, 16= 720

On DIVIDING 9999/720 we GET,

Remainder= 639

9999-639= 9360

=9360

Discussion

25.	Find the greatest number of five digit that exactly divisible by9 12 15 18 24
Answer» Answer: 99720 Step-by-step explanation: GREATEST no. of five DIGITS= 99999 LCM of 9,12,15,18,24 = 360 On dividing 99999/360, we get: REMAINDER= 279 99999-279=99720 =99720

25.

Find the greatest number of five digit that exactly divisible by9 12 15 18 24

Answer»

Answer:

99720

Step-by-step explanation:

GREATEST no. of five DIGITS= 99999

LCM of 9,12,15,18,24 = 360

On dividing 99999/360, we get:

REMAINDER= 279

99999-279=99720

=99720

Discussion

26.	Find the harmonic mean age and no. Of persons
Answer» ANSWER: please WRITE the full question bro

26.

Find the harmonic mean age and no. Of persons

Answer»

ANSWER:

please WRITE the full question bro

Discussion

27.	write the greatest and smallest 4-digit numbers using four different digits such that 5 occurs at tens place
Answer» ANSWER: s-1235 and g-8765 Step-by-step EXPLANATION: THANKX...PLZ FOLLOWS

27.

write the greatest and smallest 4-digit numbers using four different digits such that 5 occurs at tens place

Answer»

ANSWER:

s-1235 and g-8765

Step-by-step EXPLANATION:

THANKX...PLZ FOLLOWS

Discussion

28.	The 10th term of given AP :
Answer» a=√3 d=√3 =a+(n-1)d =√3+(10-1)√3 =√3+9×√3 =√246 ✍️✍️ PLEASE MARK it BRAINLIST ANSWER..

28.

The 10th term of given AP :

Answer»

a=√3

d=√3

=a+(n-1)d

=√3+(10-1)√3

=√3+9×√3

=√246

✍️✍️ PLEASE MARK it BRAINLIST ANSWER..

Discussion

29.	Please anyone can explain
Answer» ANSWER: DIRECT and INVERSE PROPOTION

29.

Please anyone can explain

Answer»

ANSWER:

DIRECT and INVERSE PROPOTION

Discussion

30.	Short note on Indian desert
Answer» $\huge{\sf{\orange{\: \: \: \: \: \: \: The\:Indian\:Desert-}}}$ The Indian desert is in western margins of the aravili hills. The largest river of this region is luni. The Indian desert receive Low rainfall. The land is covered with the sand dunes in that region. The climate of Indian desert has low vegetation. This desert is also KNOWN as Thar dearest. The streams convert into sand because they do not have enough water to reach at the sea. The crescent shaped dunes are CALLED barchans. The longitudinal dunes BECOME prominent near the Indo PAKISTAN border.

30.

Short note on Indian desert

Answer»

$\huge{\sf{\orange{\: \: \: \: \: \: \: The\:Indian\:Desert-}}}$

The Indian desert is in western margins of the aravili hills.

The largest river of this region is luni.

The Indian desert receive Low rainfall.

The land is covered with the sand dunes in that region.

The climate of Indian desert has low vegetation.

This desert is also KNOWN as Thar dearest.

The streams convert into sand because they do not have enough water to reach at the sea.

The crescent shaped dunes are CALLED barchans.

The longitudinal dunes BECOME prominent near the Indo PAKISTAN border.

Discussion

31.	If the polynomial p
Answer» ANSWER: PLZ COMPLETE the QUESTION

31.

If the polynomial p

Answer»

ANSWER:

PLZ COMPLETE the QUESTION

Discussion

32.	What are the latest discoveries in mathematics
Answer» Answer: 10. Mochizuki’s claimed proof of the abc conjecture. The countdown kicks off on an awkward note. If Shinichi Mochizuki’s 2012 claimed proof of the abc conjecture had gained widespread acceptance, it would definitely top this list. As it is, it remains in LIMBO, to the enormous frustration of everyone involved. 9. The weak Goldbach conjecture. “From 7 onwards, every odd number is the sum of three PRIMES.” We have known since 1937 that this holds for all large enough odd numbers, but in 2013 Harald Helfgott brought the threshold down to 1030, and separately with David Platt checked odd numbers up to that limit by computer. 8. Ngô Bảo Châu’s proof of the Fundamental Lemma. Bending the rules to scrape in (time-wise) is this 2009 proof of a terrifyingly technical but highly important plank of the Langlands Program. 7. Seventeen Sudoku Clues. In 2012, McGuire, Tugemann, and Civario proved that the smallest number of clues which uniquely determine a Sudoku puzzle is 17. (Although not every collection of 17 clues yields a unique solution, their theorem establishes that there can never be a valid Sudoku puzzle with only 16 clues.) 6. The Growth of Univalent Foundations/ Homotopy Type Theory. This new approach to the foundations of mathematics, led by Vladimir Voevodsky, is attracting huge attention. Apart from its inherent mathematical appeal, it promises to recast swathes of higher mathematics in a language more accessible to computerised proof-assistants. 5. Untriangulatable spaces. In sixth position is the stunning discovery, by Ciprian Manolescu, of untriangilatable manifolds in all dimensions from 5 upwards. 4. The Socolar–Taylor tile. Penrose tiles, famously, are sets of tiles which can tile the plane, but only aperiodically. It was an open question, for many years, whether it is possible to achieve the same effect with just one tile. Then Joan Taylor and Joshua Socolar found one (PICTURED above). 3. Completion of the Flyspeck project. In 1998, Thomas Hales announced a proof of the classic Kepler conjecture on the most efficient way to stack cannon-balls. Unfortunately, his proof was so long and computationally involved that the referees assigned to verify it couldn’t complete the task. So Hales and his team set about it themselves, using the Isabelle and HOL Light COMPUTATIONAL proof assistants. The result is not only a milestone in discrete geometry, but also in automated reasoning. 2. Partition numbers. In how many ways can a positive integer be written as a sum of smaller integers? In 2011, KEN Ono and Jan Bruinier provided the long-sought answer. 1. Bounded gaps between primes. It’s no real surprise to find that the top spot is taken by Yitang Zhang’s wonderful 2013 result that there is some number n, below 70 million, such that there are infinitely many pairs of consecutive primes exactly n apart. The subsequent flurry of activity saw James Maynard, and a Polymath Project organised by Terence Tao, bring the bound down to 246.

32.

What are the latest discoveries in mathematics

Answer»

Answer:

10. Mochizuki’s claimed proof of the abc conjecture. The countdown kicks off on an awkward note. If Shinichi Mochizuki’s 2012 claimed proof of the abc conjecture had gained widespread acceptance, it would definitely top this list. As it is, it remains in LIMBO, to the enormous frustration of everyone involved.

9. The weak Goldbach conjecture. “From 7 onwards, every odd number is the sum of three PRIMES.” We have known since 1937 that this holds for all large enough odd numbers, but in 2013 Harald Helfgott brought the threshold down to 1030, and separately with David Platt checked odd numbers up to that limit by computer.

8. Ngô Bảo Châu’s proof of the Fundamental Lemma. Bending the rules to scrape in (time-wise) is this 2009 proof of a terrifyingly technical but highly important plank of the Langlands Program.

7. Seventeen Sudoku Clues. In 2012, McGuire, Tugemann, and Civario proved that the smallest number of clues which uniquely determine a Sudoku puzzle is 17. (Although not every collection of 17 clues yields a unique solution, their theorem establishes that there can never be a valid Sudoku puzzle with only 16 clues.)

6. The Growth of Univalent Foundations/ Homotopy Type Theory. This new approach to the foundations of mathematics, led by Vladimir Voevodsky, is attracting huge attention. Apart from its inherent mathematical appeal, it promises to recast swathes of higher mathematics in a language more accessible to computerised proof-assistants.

5. Untriangulatable spaces. In sixth position is the stunning discovery, by Ciprian Manolescu, of untriangilatable manifolds in all dimensions from 5 upwards.

4. The Socolar–Taylor tile. Penrose tiles, famously, are sets of tiles which can tile the plane, but only aperiodically. It was an open question, for many years, whether it is possible to achieve the same effect with just one tile. Then Joan Taylor and Joshua Socolar found one (PICTURED above).

3. Completion of the Flyspeck project. In 1998, Thomas Hales announced a proof of the classic Kepler conjecture on the most efficient way to stack cannon-balls. Unfortunately, his proof was so long and computationally involved that the referees assigned to verify it couldn’t complete the task. So Hales and his team set about it themselves, using the Isabelle and HOL Light COMPUTATIONAL proof assistants. The result is not only a milestone in discrete geometry, but also in automated reasoning.

2. Partition numbers. In how many ways can a positive integer be written as a sum of smaller integers? In 2011, KEN Ono and Jan Bruinier provided the long-sought answer.

1. Bounded gaps between primes. It’s no real surprise to find that the top spot is taken by Yitang Zhang’s wonderful 2013 result that there is some number n, below 70 million, such that there are infinitely many pairs of consecutive primes exactly n apart. The subsequent flurry of activity saw James Maynard, and a Polymath Project organised by Terence Tao, bring the bound down to 246.

Discussion

33.	For what value of ‘a’ is 4x4(power of x)+ 2x3(power of x)– 3x2power of x) + 8x + 5a exactly divisible by x + 2?
Answer» Answer: a = -4 Step-by-step EXPLANATION: p(x) = 4x⁴ + 2x³ - 3x² + 8x + 5a g(x) = x + 2 0 = x + 2 x = -2 p(-2) = 4(-2)⁴ + 2(-2)³ - 3(-2)² + 8(-2) + 5a 0 = 64 - 16 - 12 - 16 + 5a 0 = 20 + 5a 5a = -20 a = -4

33.

For what value of ‘a’ is 4x4(power of x)+ 2x3(power of x)– 3x2power of x) + 8x + 5a exactly divisible by x + 2?

Answer»

Answer:

a = -4

Step-by-step EXPLANATION:

p(x) = 4x⁴ + 2x³ - 3x² + 8x + 5a

g(x) = x + 2

0 = x + 2

x = -2

p(-2) = 4(-2)⁴ + 2(-2)³ - 3(-2)² + 8(-2) + 5a

0 = 64 - 16 - 12 - 16 + 5a

0 = 20 + 5a

5a = -20

a = -4

Discussion

34.	How much is 3/8 of a day ?
Answer» ANSWER: DEAR Friend, You asked what is 3/8th of a day. We know that a day consists of 24 HOURS so we multiply it by 24. 3/824 (8 and 24 CANCEL out to give 3) 33=9 So your answer is 9 Hope it helps Have a nice day Smit Please do not FORGET to mark as Brainliest... ☻☻☻ THANK YOU

34.

How much is 3/8 of a day ?

Answer»

ANSWER:

DEAR Friend,

You asked what is 3/8th of a day. We know that a day consists of 24 HOURS so we multiply it by 24.

3/8*24

(8 and 24 CANCEL out to give 3)

3*3=9

So your answer is 9

Hope it helps

Have a nice day

Smit

Please do not FORGET to mark as Brainliest...

☻☻☻

THANK YOU

Discussion

35.	What is [a'u b']-a? I will mark u as brainliest
Answer» ANSWER. It's a DASH UNION B dash.

Discussion

36.	9.3x4 + 5x3 - 7x2 + 2x + 2 by x2 + 3x + 1
Answer» HEY here is your answer $\frac{201 + 10x}{25x + 5}$ Hope that it was helpful PLEASE MARK ME BRAINLIEST IF THE ANSWER IS CORRECT

36.

9.3x4 + 5x3 - 7x2 + 2x + 2 by x2 + 3x + 1

Answer»

HEY here is your answer

$\frac{201 + 10x}{25x + 5}$

Hope that it was helpful

PLEASE MARK ME BRAINLIEST IF THE ANSWER IS CORRECT

Discussion

37.	Given log x = m + n and log y = m - n,express the value of log 10x/y² in terms of m and n. The answer in my book is 1-m+3n and I can't get that. can someone pls help
Answer» Answer: Same as u know Step-by-step EXPLANATION: log10x/y2 (y2 is y square) = log10x-logy2 =log10+logx-2logy =1+m+n-2m+2n =1-m+3n log of 10 to base 10 is 1 it should have been MENTIONED

37.

Given log x = m + n and log y = m - n,express the value of log 10x/y² in terms of m and n. The answer in my book is 1-m+3n and I can't get that. can someone pls help

Answer»

Answer:

Same as u know

Step-by-step EXPLANATION:

log10x/y2 (y2 is y square) = log10x-logy2

=log10+logx-2logy

=1+m+n-2m+2n

=1-m+3n

log of 10 to base 10 is 1

it should have been MENTIONED

Discussion

38.	Prove that (1+1/tan²A) (1+1/cot²A) = 1/sin²A-sin⁴A
Answer» Answer: LHS = RHS Step-by-step explanation: LHS = $[1 +\sf\dfrac{1}{tan^{2}A}] [1 + \sf\dfrac{1}{cot^{2}A}]$ RHS = $\sf\dfrac{1}{sin^{2}A - sin^{4}A}$ SIMPLIFYING the LHS: $\longrightarrow$ $[1 +\sf\dfrac{1}{tan^{2}A}] \ [1 + \sf\dfrac{1}{cot^{2}A}]$ We know that, $\boxed{\sf{\frac{1}{tan^{2}A} = cot^{2}A}}$ $\boxed{\sf{\frac{1}{cot^{2}A} = tan^{2}A}}$ Substituing these FORMULAS in the equation we GET, $\longrightarrow$ $\sf{[1 + cot^{2}A] [1 + tan^{2}A]}$ We know that $\large\boxed{\sf{1 + cot^{2}A = cosec^{2}A}}$ $\large\boxed{\sf{1 + tan^{2}A = sec^{2}A}}$ Substituing these formulas in the equation we get $\longrightarrow$ $\sf{[cosec^{2}A] [1 + sec^{2}A]}$ We know that, $\boxed{\sf{cosec^{2}A = \dfrac{1}{sin^{2}}}}$ $\boxed{\sf{sec^{2}A = \dfrac{1}{cos^{2}}}}$ Substituing these formulas in the equation we get $\longrightarrow$ $\sf\dfrac{1}{sin^{2}A} \times \dfrac{1}{cos^{2}A}$ $\longrightarrow$ $\sf\dfrac{1}{sin^{2}A \times cos^{2}}$ $\longrightarrow$ $\sf\dfrac{1}{sin^{2}A \times [1 - sinA^{2}]}$ $\longrightarrow$ $\sf\dfrac{1}{sin^{2}A - sin^{4}A}$ ∴ LHS = RHS Hence Proved.

38.

Prove that (1+1/tan²A) (1+1/cot²A) = 1/sin²A-sin⁴A

Answer»

Answer:

LHS = RHS

Step-by-step explanation:

LHS = $[1 +\sf\dfrac{1}{tan^{2}A}] [1 + \sf\dfrac{1}{cot^{2}A}]$

RHS = $\sf\dfrac{1}{sin^{2}A - sin^{4}A}$

SIMPLIFYING the LHS:

$\longrightarrow$ $[1 +\sf\dfrac{1}{tan^{2}A}] \ [1 + \sf\dfrac{1}{cot^{2}A}]$

We know that,

$\boxed{\sf{\frac{1}{tan^{2}A} = cot^{2}A}}$

$\boxed{\sf{\frac{1}{cot^{2}A} = tan^{2}A}}$

Substituing these FORMULAS in the equation we GET,

$\longrightarrow$ $\sf{[1 + cot^{2}A] [1 + tan^{2}A]}$

We know that

$\large\boxed{\sf{1 + cot^{2}A = cosec^{2}A}}$

$\large\boxed{\sf{1 + tan^{2}A = sec^{2}A}}$

Substituing these formulas in the equation we get

$\longrightarrow$ $\sf{[cosec^{2}A] [1 + sec^{2}A]}$

We know that,

$\boxed{\sf{cosec^{2}A = \dfrac{1}{sin^{2}}}}$

$\boxed{\sf{sec^{2}A = \dfrac{1}{cos^{2}}}}$

Substituing these formulas in the equation we get

$\longrightarrow$ $\sf\dfrac{1}{sin^{2}A} \times \dfrac{1}{cos^{2}A}$

$\longrightarrow$ $\sf\dfrac{1}{sin^{2}A \times cos^{2}}$

$\longrightarrow$ $\sf\dfrac{1}{sin^{2}A \times [1 - sinA^{2}]}$

$\longrightarrow$ $\sf\dfrac{1}{sin^{2}A - sin^{4}A}$

∴ LHS = RHS

Hence Proved.

Discussion

39.	38. If x-1= 3, then find the value of x-
Answer» ANSWER: PLS complete the QUESTION mate pls then I ABLE to solve your PROBLEMS

39.

38. If x-1= 3, then find the value of x-

Answer»

ANSWER:

PLS complete the QUESTION mate pls then I ABLE to solve your PROBLEMS

Discussion

40.	Plz solve this. ....
Answer» ANSWER: Just PUT on the VARIABLES and the answer will COME out EASILY

40.

Plz solve this. ....

Answer»

ANSWER:

Just PUT on the VARIABLES and the answer will COME out EASILY

Discussion

41.	2x[-5x+7y] simplify
Answer» Step-by-step explanation: 2x[-5x+7y] 2x.-5x+2x.7y -15x²+14xy this is your ANSWER....

41.

2x[-5x+7y] simplify

Answer»

Step-by-step explanation:

2x[-5x+7y]

2x.-5x+2x.7y

-15x²+14xy

this is your ANSWER....

Discussion

42.	is 7 sin square theta + cos square theta equals to 44 show that tan theta is equals to 1 by under root 3
Answer» ANSWER: Step-by-step explanation: 7sin²a+3cos²a=4 Dividing throughou by cos²a 7tan²a+3=41/cos²a 7tan²a+3=4sec²a 7tan²a+3=4(1+tan²a) 7tan²a+3=4+4tan²a 7tan²a-4tan²a=4-3 3tan²a=1 Tan²a=1/3 Tana=1/√3

42.

is 7 sin square theta + cos square theta equals to 44 show that tan theta is equals to 1 by under root 3

Answer»

ANSWER:

Step-by-step explanation:

7sin²a+3cos²a=4

Dividing throughou by cos²a

7tan²a+3=41/cos²a

7tan²a+3=4sec²a

7tan²a+3=4(1+tan²a)

7tan²a+3=4+4tan²a

7tan²a-4tan²a=4-3

3tan²a=1

Tan²a=1/3

Tana=1/√3

Discussion

43.	Represent 12/5 on the nuber line
Answer» HOPE you UNDERSTAND it NICELY.

43.

Represent 12/5 on the nuber line

Answer»

HOPE you UNDERSTAND it NICELY.

Discussion

44.	7. If 8% of x = 4% of y, then find 20% of x.
Answer» ANSWER: Answer :10Y??

44.

7. If 8% of x = 4% of y, then find 20% of x.

Answer»

ANSWER:

Answer :10Y??

Discussion

45.	Rationalise the denominator 1/root5-root3+root2
Answer» I *HOPE* *THIS* *WILL* *HELP* *YOU. MARK* AS *BRAINLIEST. PLEASE*...

45.

Rationalise the denominator 1/root5-root3+root2

Answer»

I HOPE THIS WILL HELP YOU.

MARK AS BRAINLIEST.

PLEASE...

Discussion

46.	Find the smallest number which must be added to 5600 to make it a perfect square
Answer» Answer: 25 Plzzzzz MARK it as BRAINLIST and FOLLOW me

46.

Find the smallest number which must be added to 5600 to make it a perfect square

Answer»

Answer:

25

Plzzzzz MARK it as BRAINLIST and FOLLOW me

Discussion

47.	5./A point lies on theONTS TromWhat will be the coordinates if it lies on y-axis at a distanceDraw the graph of equation 3x + y = 6. Also find the pand y-axis.Af the polynomial p(x) = x - 2x + 3x? - ax + 8 is divNo. Find the value of a.& Find the value of x + y - 12xy + 64, when x + y = 4.Points A(3, 3), B (-2, 3) and D(5,-4) are three verticon a graph paper and hence find the coordinates of the ve
Answer» ANSWER: 6 3= 6!= /6 * 6 6 5,4,4 1 2 6 64 56 5* 5* 5* 5'15 5' 2 2' '2 5' /522⅝55⅝ 2/ 5/2''5'1/ 45'5!5 5 ?/5=53' 4* 4+!1 =41+=

47.

5./A point lies on theONTS TromWhat will be the coordinates if it lies on y-axis at a distanceDraw the graph of equation 3x + y = 6. Also find the pand y-axis.Af the polynomial p(x) = x - 2x + 3x? - ax + 8 is divNo. Find the value of a.& Find the value of x + y - 12xy + 64, when x + y = 4.Points A(3, 3), B (-2, 3) and D(5,-4) are three verticon a graph paper and hence find the coordinates of the ve

Answer»

ANSWER:

*6 3= 6!= /6 * * 6 6 5,4,4 1 2 6 64 56 5* 5* 5* 5'15 5' 2 2' '2 5' /522⅝55⅝ 2/ 5/2''5'1/ *45'5!5 5* ?/5=53' 4* 4+!1 =41+=

Discussion

48.	Goo gogoa gani3 one yo ago the ratio of ages of A and Bages wouldI was 4:3 Done you hence theirde 5:4 nohat would be the Gorsem ofther Gresent ages?Here2018 2019
Answer» *Hey* *mate* I am *not* *UNDERSTAND* *your* *QUESTION. Please* *RETAIN* *it.*

48.

Goo gogoa gani3 one yo ago the ratio of ages of A and Bages wouldI was 4:3 Done you hence theirde 5:4 nohat would be the Gorsem ofther Gresent ages?Here2018 2019

Answer»

Hey mate I am not UNDERSTAND your QUESTION. Please RETAIN it.

Discussion

49.	prove that c-(b-a) =(c intersection a) u(c intersection b')prove that C minus b minus A equal to C intersection b union c dash intersection b dash
Answer» SOLUTION TO PROVE $\sf{C - (B - A) =(C \cap A) \cup (C \cap B ') \: }$ PROOF $\sf{C - (B - A) \: }$ $= \sf{C - (B \cap A ' ) \: }(by \: property \: of \: difference)$ $= \sf{C \cap (B \cap A ' )' \: }(by \: property \: of \: difference)$ $= \sf{C \cap \bigg(B ' \cup (A ' )' \bigg)\: }(by \: de \: morgan's \: law)$ $= \sf{C \cap (B ' \cup A )\: }$ $= \sf{(C \cap B ' )\cup (C \cap A )\: } \: (by \: distributive \: property)$ $= \sf{(C \cap A ) \cup (C \cap B ' ) \: } \: (by \:commutative \: property)$ Hence PROVED ━━━━━━━━━━━━━━━━ LEARN MORE FROM BRAINLY If A is an empty set and B is set of VOWELS, then A∩B is brainly.in/question/24041704

49.

prove that c-(b-a) =(c intersection a) u(c intersection b')prove that C minus b minus A equal to C intersection b union c dash intersection b dash

Answer»

SOLUTION

TO PROVE

$\sf{C - (B - A) =(C \cap A) \cup (C \cap B ') \: }$

PROOF

$\sf{C - (B - A) \: }$

$= \sf{C - (B \cap A ' ) \: }(by \: property \: of \: difference)$

$= \sf{C \cap (B \cap A ' )' \: }(by \: property \: of \: difference)$

$= \sf{C \cap \bigg(B ' \cup (A ' )' \bigg)\: }(by \: de \: morgan's \: law)$

$= \sf{C \cap (B ' \cup A )\: }$

$= \sf{(C \cap B ' )\cup (C \cap A )\: } \: (by \: distributive \: property)$

$= \sf{(C \cap A ) \cup (C \cap B ' ) \: } \: (by \:commutative \: property)$

Hence PROVED

━━━━━━━━━━━━━━━━

LEARN MORE FROM BRAINLY

If A is an empty set and B is set of VOWELS,

then A∩B is

brainly.in/question/24041704

Discussion

50.	Find the value of (-100-100)÷{-100-(-100-100})
Answer» Step-by-step EXPLANATION: -200÷(-300) -(3/2) ANS MAY be ALSO - (2/3)

50.

Find the value of (-100-100)÷{-100-(-100-100})

Answer»

Step-by-step EXPLANATION:

-200÷(-300)

-(3/2)

ANS MAY be ALSO - (2/3)

Discussion

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