Given log x = m + n and log y = m - n,express the value of log 10x/y²

1.	Given log x = m + n and log y = m - n,express the value of log 10x/y² in terms of m and n. The answer in my book is 1-m+3n and I can't get that. can someone pls help
Answer» Answer: Same as u know Step-by-step EXPLANATION: log10x/y2 (y2 is y square) = log10x-logy2 =log10+logx-2logy =1+m+n-2m+2n =1-m+3n log of 10 to base 10 is 1 it should have been MENTIONED

Given log x = m + n and log y = m - n,express the value of log 10x/y² in terms of m and n. The answer in my book is 1-m+3n and I can't get that. can someone pls help

Answer»

Answer:

Same as u know

Step-by-step EXPLANATION:

log10x/y2 (y2 is y square) = log10x-logy2

=log10+logx-2logy

=1+m+n-2m+2n

=1-m+3n

log of 10 to base 10 is 1

it should have been MENTIONED

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Given log x = m + n and log y = m - n,express the value of log 10x/y² in terms of m and n. The answer in my book is 1-m+3n and I can't get that. can someone pls help​

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Given log x = m + n and log y = m - n,express the value of log 10x/y² in terms of m and n. The answer in my book is 1-m+3n and I can't get that. can someone pls help