332354 + Interview Questions in Secondary School in Math

1.	Find the value of xplease tell it's a huge request u can tell me from anywhere with solution please
Answer» Answer: Angle C is 40 degree now in triangle EDC, ANGLE E +ANGLE D+ ANGLE C= 180 DEGREE ANGLED=180-125 ANGLE D=55 degree. please Mark me as Brainlest and FOLLOW

1.

Find the value of xplease tell it's a huge request u can tell me from anywhere with solution please

Answer»

Answer:

Angle C is 40 degree

now in triangle EDC,

ANGLE E +ANGLE D+ ANGLE C= 180 DEGREE

ANGLED=180-125

ANGLE D=55 degree.

please Mark me as Brainlest and FOLLOW

Discussion

2.	Plz jladi bta do important hai
Answer» ANSWER: PIC CLEAR NHI H clear pic bjeo

2.

Plz jladi bta do important hai

Answer»

ANSWER:

PIC CLEAR NHI H clear pic bjeo

Discussion

3.	9050 me 0 ka sathaniy maan Kya hoga
Answer» vhe was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her SINCE she was so young he is a LOT of fun to be honest and not be able and not be in a CAR and not just for a good relationship with your new FRIENDS or not to me but I think it's going on with your partner in a car with a great job with the same thinghe was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and

3.

9050 me 0 ka sathaniy maan Kya hoga

Answer»

vhe was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her SINCE she was so young he is a LOT of fun to be honest and not be able and not be in a CAR and not just for a good relationship with your new FRIENDS or not to me but I think it's going on with your partner in a car with a great job with the same thinghe was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and not be able and not be in a car and not just for a good relationship with your new friends or not to me but I think it's going on with your partner in a car with a great job with the same thing he was a very nice guy who was a very nice guy who was very nice guy and I have no reason for her since she was so young he is a lot of fun to be honest and

Discussion

4.	In the following figure,ABCD represent a square of side 6cm.E is a point on DC such that the area of the triangle ADE is one - third of the area of the square. Find the length of ED
Answer» Dx2ks0wkenx9k202oeiemeldimeme

Discussion

5.	Frame a word problem where you have to use Pythagoras theorem to find the answer. Andanswer should be 13 km
Answer» Step-by-step EXPLANATION: a triangle of hypotaneous is 169. the other TWO SIDES are 12m and 1 m . find the actual hypotaneous side. HOPE THIS WILL HELP YOU PLZ.. MARK THIS ANSWER AS BRAINLIEST

5.

Frame a word problem where you have to use Pythagoras theorem to find the answer. Andanswer should be 13 km

Answer»

Step-by-step EXPLANATION:

a triangle of hypotaneous is 169. the other TWO SIDES are 12m and 1 m . find the actual hypotaneous side.

HOPE THIS WILL HELP YOU

PLZ.. MARK THIS ANSWER AS BRAINLIEST

Discussion

6.	Find the conditional probability that a randomly selected poker hands contains exactly 3aces, given that it contains at least 2 aces?
Answer» Given : a randomly selected poker hands contains exactly 3 aces, given that it contains at LEAST 2 aces To Find : probability that a randomly selected poker hands contains exactly 3 aces, given that it contains at least 2 aces Solution : A poker hand has 5 cards it contains exactly 2 aces = ⁴C₂ * ⁴⁸C₃ = 6 * 17,296 = 1,03,776 ways contains exactly 3 aces = ⁴C₃* ⁴⁸C₂ = 4* 1,128 = 4512 Ways contains exactly 4 aces = ⁴C₄* ⁴⁸C₁ = 48 Ways contains at least 2 aces = 1,03,776 + 4512 + 48 = 1,08,336 Ways probability that a randomly selected poker hands contains exactly 3 aces, given that it contains at least 2 aces = 4512 / 1,08,336 = 94/2257 = 0.04165 probability that a randomly selected poker hands contains exactly 3 aces, given that it contains at least 2 aces = 94/2257 or 0.04165 Learn More: A pair of fair dice is thrown independently FOUR times. The probability ... brainly.in/question/21757712 A pair of dice is thrown together till a sum of 4 or 8 is obtained. The ... brainly.in/question/14777415

6.

Find the conditional probability that a randomly selected poker hands contains exactly 3aces, given that it contains at least 2 aces?

Answer»

Given : a randomly selected poker hands contains exactly 3 aces, given that it contains at LEAST 2 aces

To Find : probability that a randomly selected poker hands contains exactly 3 aces, given that it contains at least 2 aces

Solution :

A poker hand has 5 cards

it contains exactly 2 aces

= ⁴C₂ * ⁴⁸C₃

= 6 * 17,296

= 1,03,776 ways

contains exactly 3 aces

= ⁴C₃* ⁴⁸C₂

= 4* 1,128

= 4512 Ways

contains exactly 4 aces

= ⁴C₄* ⁴⁸C₁

= 48 Ways

contains at least 2 aces = 1,03,776 + 4512 + 48 = 1,08,336 Ways

probability that a randomly selected poker hands contains exactly 3 aces, given that it contains at least 2 aces = 4512 / 1,08,336

= 94/2257

= 0.04165

probability that a randomly selected poker hands contains exactly 3 aces, given that it contains at least 2 aces = 94/2257

or 0.04165

Learn More:

A pair of fair dice is thrown independently FOUR times. The probability ...

brainly.in/question/21757712

A pair of dice is thrown together till a sum of 4 or 8 is obtained. The ...

brainly.in/question/14777415

Discussion

7.	Following cards are put facing down A, E , I, O, U. What is the probability of getting a vowel from the card?1/52/53/55/5
Answer» Answer: 5/5 will be the PROBABILITY

7.

Following cards are put facing down A, E , I, O, U. What is the probability of getting a vowel from the card?1/52/53/55/5

Answer»

Answer:

5/5 will be the PROBABILITY

Discussion

8.	If in a right angled ∆ABC, tan B = 12/5. then find sin B. (2014)
Answer» Step-by-step EXPLANATION: sinB=12/13 from RIGHT ANGLE TRIANGLE

8.

If in a right angled ∆ABC, tan B = 12/5. then find sin B. (2014)

Answer»

Step-by-step EXPLANATION:

sinB=12/13

from RIGHT ANGLE TRIANGLE

Discussion

9.	A man gets an interest of Rs370 on Rs2300 for 2 year's. His rate of interest is
Answer» ANSWER: the RATE is EQUAL to 370/46 = 8 1/23 %

9.

A man gets an interest of Rs370 on Rs2300 for 2 year's. His rate of interest is

Answer»

ANSWER:

the RATE is EQUAL to 370/46 = 8 1/23 %

Discussion

10.	If the measure of angle 3 is equal to (2x + 6)° and x = 7, which statements are true? Check all that apply.
Answer» COMPLETE Question :- If the measure of angle 3 is equal to (2x + 6)° and x = 7, which statements are true ? CHECK all that apply. Statements :- A) The measure of angle 6 is 20°. B) The measure of angle 5 is 70°. C) The measure of angle 2 is 80°. D) Angles 2 and 5 are complementary. E) Angles 5 and 6 are supplementary. F) Angles 1 and 4 are supplementary. Solution :- Statement (A) :- The measure of angle 6 is 20°. given that, → ∠3 = (2x + 6)° → x = 7 so, → ∠3 = (2 * 7 + 6)° = (14 + 6)° = 20° now, → ∠6 = ∠3 (vertically opposite angles.) → ∠6 = 20° . THEREFORE, statement (A) is True . Statement (B) :- The measure of angle 5 is 70°. given that, → ∠1 = 90° so, → ∠1 + ∠6 + ∠5 = 180° (Linear pair) → 90° + 20° + ∠5 = 180° → 110° + ∠5 = 180° → ∠5 = 180° - 110° → ∠5 = 70° . Therefore, statement (B) is True . Statement (C) :- The measure of angle 2 is 80°. given that, → ∠1 = 90° so, → ∠1 + ∠3 + ∠2 = 180° (Linear pair) → 90° + 20° + ∠2 = 180° → 110° + ∠2 = 180° → ∠2 = 180° - 110° → ∠2 = 70° . Therefore, statement (C) is False . Statement (D) :- Angles 2 and 5 are complementary. → ∠2 + ∠5 = 70° + 70° → ∠2 + ∠5 = 140° ≠ 90° . Since, Two angles are called complementary when their measures ADDS to 90° . Therefore, statement (D) is False . Statement (E) :- Angles 5 and 6 are supplementary. → ∠5 + ∠6 = 70° + 20° → ∠5 + ∠6 = 90° ≠ 180° . Since, Two angles are called supplementary when their measures adds to 180° . Therefore, statement (E) is False . Statement (F) :- Angles 1 and 4 are supplementary. → ∠1 = ∠4 (vertically opposite angles.) so, → ∠1 + ∠4 = 90° + 90° → ∠1 + ∠4 = 180° . Since, Two angles are called supplementary when their measures adds to 180° . Therefore, statement (F) is True . Learn more :- In ABC, AD is angle bisector, angle BAC = 111 and AB+BD=AC find the value of angle ACB=? brainly.in/question/16655884

10.

If the measure of angle 3 is equal to (2x + 6)° and x = 7, which statements are true? Check all that apply.

Answer»

COMPLETE Question :- If the measure of angle 3 is equal to (2x + 6)° and x = 7, which statements are true ? CHECK all that apply.

Statements :-

A) The measure of angle 6 is 20°.

B) The measure of angle 5 is 70°.

C) The measure of angle 2 is 80°.

D) Angles 2 and 5 are complementary.

E) Angles 5 and 6 are supplementary.

F) Angles 1 and 4 are supplementary.

Solution :-

Statement (A) :- The measure of angle 6 is 20°.

given that,

→ ∠3 = (2x + 6)°

→ x = 7

so,

→ ∠3 = (2 * 7 + 6)° = (14 + 6)° = 20°

now,

→ ∠6 = ∠3 (vertically opposite angles.)

→ ∠6 = 20° .

THEREFORE, statement (A) is True .

Statement (B) :- The measure of angle 5 is 70°.

given that,

→ ∠1 = 90°

so,

→ ∠1 + ∠6 + ∠5 = 180° (Linear pair)

→ 90° + 20° + ∠5 = 180°

→ 110° + ∠5 = 180°

→ ∠5 = 180° - 110°

→ ∠5 = 70° .

Therefore, statement (B) is True .

Statement (C) :- The measure of angle 2 is 80°.

given that,

→ ∠1 = 90°

so,

→ ∠1 + ∠3 + ∠2 = 180° (Linear pair)

→ 90° + 20° + ∠2 = 180°

→ 110° + ∠2 = 180°

→ ∠2 = 180° - 110°

→ ∠2 = 70° .

Therefore, statement (C) is False .

Statement (D) :- Angles 2 and 5 are complementary.

→ ∠2 + ∠5 = 70° + 70°

→ ∠2 + ∠5 = 140° ≠ 90° .

Since, Two angles are called complementary when their measures ADDS to 90° .

Therefore, statement (D) is False .

Statement (E) :- Angles 5 and 6 are supplementary.

→ ∠5 + ∠6 = 70° + 20°

→ ∠5 + ∠6 = 90° ≠ 180° .

Since, Two angles are called supplementary when their measures adds to 180° .

Therefore, statement (E) is False .

Statement (F) :- Angles 1 and 4 are supplementary.

→ ∠1 = ∠4 (vertically opposite angles.)

so,

→ ∠1 + ∠4 = 90° + 90°

→ ∠1 + ∠4 = 180° .

Since, Two angles are called supplementary when their measures adds to 180° .

Therefore, statement (F) is True .

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

brainly.in/question/16655884

Discussion

11.	If length of the rectangle is l and breadth is b then what will be its perimeter in terms of l and b please answer
Answer» ANSWER: 20 is the answer PLZ FOLLOW MW

11.

If length of the rectangle is l and breadth is b then what will be its perimeter in terms of l and b please answer

Answer»

ANSWER:

20 is the answer PLZ FOLLOW MW

Discussion

12.	a circle has a radius of 9cm and a sector of the circle has an arc of 9.7cm calculate the value of x to the nearest degree
Answer» ANSWER: Step-by-step explanation: 9.7=(x÷360)×2×3.14 ×9 X=(9.7×360)÷(18×3.14) =(9.7×20)÷3.14 =194÷3.14=61.78degree

12.

a circle has a radius of 9cm and a sector of the circle has an arc of 9.7cm calculate the value of x to the nearest degree

Answer»

ANSWER:

Step-by-step explanation:

9.7=(x÷360)×2×3.14 ×9

X=(9.7×360)÷(18×3.14)

=(9.7×20)÷3.14

=194÷3.14=61.78degree

Discussion

13.	A bag contain 5 red ball , 7 black ball , 8 green ball and 3 white ball find the probability
Answer» probablity = no. of favourable outcomes/no. of TOTAL outcomes red BALL = 5/23 black ball=7/23 green ball=8/23 white ball=3/23 Step-by-step EXPLANATION: FORMULA is MUST for these questions

13.

A bag contain 5 red ball , 7 black ball , 8 green ball and 3 white ball find the probability

Answer»

probablity = no. of favourable outcomes/no. of TOTAL outcomes

red BALL = 5/23

black ball=7/23

green ball=8/23

white ball=3/23

Step-by-step EXPLANATION:

FORMULA is MUST for these questions

Discussion

14.	Divide ₹ 110 between Aashi and arpit in the ratio of 3 : 2
Answer» Step-by-step EXPLANATION: LET it be divused UNIT 3X and 2x 3x+2x=110 5x=110 x=22 3x=322=₹66 2x=222=₹44

14.

Divide ₹ 110 between Aashi and arpit in the ratio of 3 : 2

Answer»

Step-by-step EXPLANATION:

LET it be divused UNIT 3X and 2x

3x+2x=110

5x=110

x=22

3x=3*22=₹66

2x=2*22=₹44

Discussion

15.	The range of 20,30,10,15,5,24 is
Answer» $\sf{ \longmapsto What \: is \: <klux>RANGE</klux> }$ The Range is the DIFFERENCE between the LOWEST and HIGHEST $\sf{ \longmapsto Formula \: for \: finding \:range }$ $\sf \purple{Range = highest \: value - lowest \: value}$ $\sf{ \longmapsto solution}$ $\sf \green{\fcolorbox{pink}{ble}{range = 30 - 5= 25}}$

15.

The range of 20,30,10,15,5,24 is

Answer»

$\sf{ \longmapsto What \: is \: <klux>RANGE</klux> }$

The Range is the DIFFERENCE between the LOWEST and HIGHEST

$\sf{ \longmapsto Formula \: for \: finding \:range }$

$\sf \purple{Range = highest \: value - lowest \: value}$

$\sf{ \longmapsto solution}$

$\sf \green{\fcolorbox{pink}{ble}{range = 30 - 5= 25}}$

Discussion

16.	(bPatients examined(d) Ho(e) Ho8. ThehourNo. of patients15-vih30(c7. The bar graph drawn in Fig. 15.5represents the number of patientsexamined by a doctor during a week.Read the graph and answer thefollowing questions:(a) How many patients did heexamine on Thursday? 14(b) On which day, heexamined the maximumnumber of patients? JA(c) On which day, be examined28 patients? Wed(d) Find the per cent decrease inthe number of patients fromTuesday to Thursday.(e) On whichdays, heexamined the same number ofpatients? tue e re(dIf the doctor charges 250 asDaysconsultation fee per patient,Fig. 15.5how much did he get onFriday? 5 000Fir 15 fi denicts the nmfit earned by 5 persons during a month. Read the graph andd5two
Answer» Answer: WRITE SINGLE question in one time please. select this answer as a brainliest and THANKS for EFFORT

16.

(bPatients examined(d) Ho(e) Ho8. ThehourNo. of patients15-vih30(c7. The bar graph drawn in Fig. 15.5represents the number of patientsexamined by a doctor during a week.Read the graph and answer thefollowing questions:(a) How many patients did heexamine on Thursday? 14(b) On which day, heexamined the maximumnumber of patients? JA(c) On which day, be examined28 patients? Wed(d) Find the per cent decrease inthe number of patients fromTuesday to Thursday.(e) On whichdays, heexamined the same number ofpatients? tue e re(dIf the doctor charges 250 asDaysconsultation fee per patient,Fig. 15.5how much did he get onFriday? 5 000Fir 15 fi denicts the nmfit earned by 5 persons during a month. Read the graph andd5two

Answer»

Answer:

WRITE SINGLE question in one time please.

select this answer as a brainliest and THANKS for EFFORT

Discussion

17.	Find the area of these triangle using correct formula
Answer» Answer: b. 15 cm² c. 112.5 cm² Step-by-step explanation: b. area of the triangle = 1/ 2 × BASE × height 1/2× 6× 5 = 15 cm² c. area of the triangle= 1/ × base × height 1/ 2 x 9x25 = 112.5 cm² PLS mark as brainlist

17.

Find the area of these triangle using correct formula

Answer»

Answer:

b. 15 cm² c. 112.5 cm²

Step-by-step explanation:

b. area of the triangle = 1/ 2 × BASE × height

1/2× 6× 5

= 15 cm²

c. area of the triangle= 1/ × base × height

1/ 2 x 9x25

= 112.5 cm²

PLS mark as brainlist

Discussion

18.	Maths linear equation mcq
Answer» ANSWER: nice Step-by-step EXPLANATION: baut BADHIYA

18.

Maths linear equation mcq

Answer»

ANSWER:

nice

Step-by-step EXPLANATION:

baut BADHIYA

Discussion

19.	Statics please slove this
Answer» ANSWER: I don't KNOW hahhaa.. Step-by-step EXPLANATION: i will TELL you LETTER

19.

Statics please slove this

Answer»

ANSWER:

I don't KNOW hahhaa..

Step-by-step EXPLANATION:

i will TELL you LETTER

Discussion

20.	Cyclic quadrilateral
Answer» In EUCLIDEAN GEOMETRY, a CYCLIC quadrilateral or inscribed quadrilateral is a quadrilateral whose vertices all lie on a single circle. Step-by-step explanation: hope it's HELPS to you please MARK me as Brainliest thank❤ you

20.

Cyclic quadrilateral

Answer»

In EUCLIDEAN GEOMETRY, a CYCLIC quadrilateral or inscribed quadrilateral is a quadrilateral whose vertices all lie on a single circle.

Step-by-step explanation:

hope it's HELPS to you please MARK me as Brainliest thank❤ you

Discussion

21.	X+2)d2y/dx2+(2x+5)dy/dx+2y=(x+1)e^x
Answer» STEP step MATH PROFIT is a BIG DEAL

Discussion

22.	Answer fast please every question
Answer» a=8hours =11KM PER HOUR c=w=105

22.

Answer fast please every question

Answer»

a=8hours

=11KM PER HOUR

c=w=105

Discussion

23.	Find the sum of 3.2 and 5-4
Answer» ANSWER: 8.6 is the answer.... ...

23.

Find the sum of 3.2 and 5-4

Answer»

ANSWER:

8.6 is the answer.... ...

Discussion

24.	I am always front of you but never behind you.what I am ?
Answer» héy .... I was not getting any of your question to reply you I'm góód ....but LIFE isn't going good, it's so shît I keep it with myself, I don't tell anyone how about you !? any PROBLEM ? why you were sad ? why do you want to leave ? why are you LOOSING points ??! don't leave ,I request!! that's it !!! be happy, if you have any problem, share with me !! I'll HELP you, I'll GIVE you the smile

24.

I am always front of you but never behind you.what I am ?

Answer»

héy .... I was not getting any of your question to reply you

I'm góód ....but LIFE isn't going good, it's so shît

I keep it with myself, I don't tell anyone

how about you !? any PROBLEM ? why you were sad ? why do you want to leave ? why are you LOOSING points ??!

don't leave ,I request!! that's it !!! be happy, if you have any problem, share with me !! I'll HELP you, I'll GIVE you the smile

Discussion

25.	2,4 gives 20 and 3,9gives 90, find 1,7gives____'
Answer» ANSWER: 10 is the CORRECT answer

25.

2,4 gives 20 and 3,9gives 90, find 1,7gives____'

Answer»

ANSWER:

10 is the CORRECT answer

Discussion

26.	भाग क्रिया द्वारा जात कीजिए कि क्या(x+6), x^2 - x -42 का एक गुणनखण्ड है, ।
Answer» Answer: FO ll ow me I will also PROMISE Step-by-step EXPLANATION: fo ll ow me I will also promise

26.

भाग क्रिया द्वारा जात कीजिए कि क्या(x+6), x^2 - x -42 का एक गुणनखण्ड है, ।

Answer»

Answer:

FO ll ow me I will also PROMISE

Step-by-step EXPLANATION:

fo ll ow me I will also promise

Discussion

27.	Write the 20th term of first 20natural numbers
Answer» ANSWER: 20 is the answer Step-by-step explanation: because natural number starts from 1 and u said 20 natural numbers and 20 TH term 20 th term is 20 only so that's why answer us 20 HOPE IT'S HELPFUL MARK ME AS BRAINLIST AND FLW ME

27.

Write the 20th term of first 20natural numbers

Answer»

ANSWER:

20 is the answer

Step-by-step explanation:

because natural number starts from 1

and u said 20 natural numbers

and 20 TH term

20 th term is 20 only

so that's why answer us 20

HOPE IT'S HELPFUL MARK ME AS BRAINLIST AND FLW ME

Discussion

28.	Plz answers for questions plz urgent plz
Answer» Step-by-step EXPLANATION: but what to ANSWER . ASK QUESTION

28.

Plz answers for questions plz urgent plz

Answer»

Step-by-step EXPLANATION:

but what to ANSWER . ASK QUESTION

Discussion

29.	The number of pairs (x, y) satisfying the equations sin x + sin y = sin (x + y) and \|x\| + \|y\| = 1 is(a) 0(b) 2(c) 4(d) 6
Answer» sin X + sin y = 2 sin [(x+y)/2]COS[(x-y)/2] sin(x+y) = 2 sin [(x+y)/2]cos[(x+y)/2] cos[(x-y)/2] = cos[(x+y)/2] cos[(x-y)/2] - cos[(x+y)/2] =0 2sin(x/2)sin(y/2) = 0 [we converted difference of cosines into a product] x=0 or y=0. So, there are FOUR ANSWERS (0,1), (0,-1), (1,0), (-1,0).

29.

The number of pairs (x, y) satisfying the equations sin x + sin y = sin (x + y) and |x| + |y| = 1 is(a) 0(b) 2(c) 4(d) 6

Answer»

sin X + sin y = 2 sin [(x+y)/2]COS[(x-y)/2]

sin(x+y) = 2 sin [(x+y)/2]cos[(x+y)/2]

cos[(x-y)/2] = cos[(x+y)/2]

cos[(x-y)/2] - cos[(x+y)/2] =0

2sin(x/2)sin(y/2) = 0 [we converted difference of cosines into a product]

x=0 or y=0.

So, there are FOUR ANSWERS (0,1), (0,-1), (1,0), (-1,0).

Discussion

30.	Which are the zeroes of p(×)=×2-4
Answer» ANSWER: 2. is the RIGHT answer . SELECT this answer as a BRAINLIEST and THANKS too

30.

Which are the zeroes of p(×)=×2-4

Answer»

ANSWER:

2. is the RIGHT answer .

SELECT this answer as a BRAINLIEST and THANKS too

Discussion

31.	Ynt months. How much On3.1% per annum296Find the simple interest on 32,000 for six months at the rate of 4
Answer» ANSWER: good morning Step-by-step EXPLANATION: PLEASE mark me as a brilliant

31.

Ynt months. How much On3.1% per annum296Find the simple interest on 32,000 for six months at the rate of 4

Answer»

ANSWER:

good morning

Step-by-step EXPLANATION:

PLEASE mark me as a brilliant

Discussion

32.	PLEASE ANSWER!!!Two dice are thrown. Find the probability of the following events:Event A : The product of the numbers on their upper faces is 10.Event B : The sum of the numbers on their upper faces is multiple of 9.
Answer» <P> Let A &B be the FAVORABLE event then A= {(2,5),(5,2)} N(A)=2 since n(S)=36 so,p(A)=n(A)/n(S) =2/36 =1/18. Similarly, B= {(3,6),(4,5),(5,4),(6,3)} n(B)=4 We KNOW n(S)=36. so,p(B)=n(B)/n(S) =4/36 =1/9. Hope it will help you

32.

PLEASE ANSWER!!!Two dice are thrown. Find the probability of the following events:Event A : The product of the numbers on their upper faces is 10.Event B : The sum of the numbers on their upper faces is multiple of 9.

Answer»

<P>

Let A &B be the FAVORABLE event then

A= {(2,5),(5,2)}

N(A)=2

since n(S)=36

so,p(A)=n(A)/n(S)

=2/36

=1/18.

Similarly,

B= {(3,6),(4,5),(5,4),(6,3)}

n(B)=4

We KNOW n(S)=36.

so,p(B)=n(B)/n(S)

=4/36

=1/9.

Hope it will help you

Discussion

33.	I want answer of this question
Answer» MARK me as brainiest answer is -4/3 < -3/9 < -2/9

33.

I want answer of this question

Answer»

MARK me as brainiest

answer is -4/3 < -3/9 < -2/9

Discussion

34.	Find the area of isoscales triangle whose height is 4 cm and base is 6 cm
Answer» ANSWER: AREA.... 1/2×6×5 15cm2

34.

Find the area of isoscales triangle whose height is 4 cm and base is 6 cm

Answer»

ANSWER:

AREA....

1/2×6×5

15cm2

Discussion

35.	A graph having loop or parallel edges but not both it's called
Answer» ANSWER: MULTI GRAPH is CORRECT answer

35.

A graph having loop or parallel edges but not both it's called

Answer»

ANSWER:

MULTI GRAPH is CORRECT answer

Discussion

36.	the curved surface area of a right circular cylinder of height 14 cm is 88 cm^ .Find the diameter bof the base of cylinder
Answer» Step-by-step explanation: CURVED surface area=2πrh 88=222/7R14 1cm=r diameter=2r =21 =2CM

36.

the curved surface area of a right circular cylinder of height 14 cm is 88 cm^ .Find the diameter bof the base of cylinder

Answer»

Step-by-step explanation:

CURVED surface area=2πrh

88=2*22/7*R*14

1cm=r

diameter=2r

=2*1

=2CM

Discussion

37.	Agent of an insurance company gets a commission of 5% on the base is premium collect what will be Commission on collects $4800
Answer» ANSWER: He will GET 240$ Step-by-step explanation: Since he will get 5%, 5% of 4800 5/100 x 4800 240$

37.

Agent of an insurance company gets a commission of 5% on the base is premium collect what will be Commission on collects $4800

Answer»

ANSWER:

He will GET 240$

Step-by-step explanation:

Since he will get 5%,

5% of 4800

5/100 x 4800

240$

Discussion

38.	Calculate the time in which * 5,000 wouldbecome * 5,500 at an interest rate of 8% perannum.ill money deposited in a bank
Answer» Answer: 15month. Step-by-step EXPLANATION: interest of $ 5000 @ 8% for 12 months is (5000×8/100) = $400. time REQUIRED to GET$500 interest @8% = (12×500/400) months = 15 months.

38.

Calculate the time in which * 5,000 wouldbecome * 5,500 at an interest rate of 8% perannum.ill money deposited in a bank

Answer»

Answer:

15month.

Step-by-step EXPLANATION:

interest of $ 5000 @ 8% for 12 months is (5000×8/100) = $400.

time REQUIRED to GET$500 interest @8% = (12×500/400) months = 15 months.

Discussion

39.	750 in 3 years and 4 months at 10% per annum find the interest
Answer» <P>Answer: Given P = ₹750 Time (T) = 3. 4/12 = 3.1/3 = 10/3 years Rate (R) = 10% ∴ Interest (I) = PRT/100 = (750 × 10 × (10/3))/100 = (250 × 10 × 10)/100 = ₹250 ∴ Amount (A) = P + I = ₹750 + ₹250 = ₹1000 Step-by-step explanation: MARK IT AS BRAINLIEST

39.

750 in 3 years and 4 months at 10% per annum find the interest

Answer»

<P>Answer:

Given P = ₹750

Time (T) = 3. 4/12 = 3.1/3

= 10/3 years

Rate (R) = 10%

∴ Interest (I) = PRT/100 = (750 × 10 × (10/3))/100

= (250 × 10 × 10)/100 = ₹250

∴ Amount (A) = P + I = ₹750 + ₹250 = ₹1000

Step-by-step explanation:

MARK IT AS BRAINLIEST

Discussion

40.	A) Diya has a sum of ₹ x. She spent 2,000 on grocerys and 1,500 on clothes andreceived 2,500 as a gift. How much money (in ₹ ) is left with her?
Answer» ANSWER: MARK IT AS BRAINLIEST. . . . . . . . .

40.

A) Diya has a sum of ₹ x. She spent 2,000 on grocerys and 1,500 on clothes andreceived 2,500 as a gift. How much money (in ₹ ) is left with her?

Answer»

ANSWER:

MARK IT AS BRAINLIEST.

.

Discussion

41.	Proof that :• ( a + b )² = a² + 2ab + b²No spam (=｀ェ´=)
Answer» (a+B)² = (a+b)×(a+b) = (a+b)(a+b) = [a×(a+b)]+[b×(a+b)] = [a(a+b)]+[b(a+b)] = [{(a×a)+(a×b)}] + [{(b×a)+(b×b)}] = [(a²)+(ab)] + [(ba)+(b²)] = (a²)+(ab)+(ba)+(b²) SINCE a×b = b×a (COMMUTATIVE property), ba = ab. = (a²)+(ab)+(ab)+(b²) = (a²)+(2×ab)+(b²) = (a²)+(2AB)+(b²)

41.

Proof that :• ( a + b )² = a² + 2ab + b²No spam (=｀ェ´=)

Answer»

(a+B)²

= (a+b)×(a+b)

= (a+b)(a+b)

= [a×(a+b)]+[b×(a+b)]

= [a(a+b)]+[b(a+b)]

= [{(a×a)+(a×b)}] + [{(b×a)+(b×b)}]

= [(a²)+(ab)] + [(ba)+(b²)]

= (a²)+(ab)+(ba)+(b²)

SINCE a×b = b×a (COMMUTATIVE property), ba = ab.

= (a²)+(ab)+(ab)+(b²)

= (a²)+(2×ab)+(b²)

= (a²)+(2AB)+(b²)

Discussion

42.	If p(x) = 4x^2- 4x+4 find p(0)and p (-1)
Answer» Step-by-step EXPLANATION: p(0)=. 4 p(-1)=. 12 is the answer

42.

If p(x) = 4x^2- 4x+4 find p(0)and p (-1)

Answer»

Step-by-step EXPLANATION:

p(0)=. 4

p(-1)=. 12

is the answer

Discussion

43.	Two dice are thrown. Find the probability of the following events:Event A: The product of the numbers on their upper faces is 10..Event B: The sum of the numbers on their upper faces is multiple of 9.
Answer» ANSWER: Here's your answer hope it's CLEAR, THANK you.

43.

Two dice are thrown. Find the probability of the following events:Event A: The product of the numbers on their upper faces is 10..Event B: The sum of the numbers on their upper faces is multiple of 9.

Answer»

ANSWER:

Here's your answer

hope it's CLEAR,

THANK you.

Discussion

44.	If the perimeter of rectangle is 52metere and area is 160m² thae lenghth of rectangle is
Answer» GIVEN :- AREA of the RECTANGLE = 160 m² Perimeter of the rectangle = 52 m To Find :- Length of the rectangle Solution :- Perimeter of the rectangle :- $:\implies\sf{Perimeter = 2(l+b)}$ $:\implies\sf{52 = 2(l+b)}$ $:\implies\sf{52/2 = (l+b)}$ $:\implies\sf{26 = (l+b)}$ $:\implies\sf{b=26-l}...(1)$ Area of the rectangle :- $:\implies\sf{Area = l \times b}$ $:\implies\sf{160 = l \times (26-l)}$ $:\implies\sf{160 = 26l-l^2}$ $:\implies\sf{ 26l-l^2-160=0}$ $:\implies\sf{ -l^2+26l-160=0}$ $:\implies\sf{ l^2-26l+160=0}$ $:\implies\sf{ l^2-10l-16l+160=0}$ $:\implies\sf{ l(l-10)-16(l-10)=0}$ $:\implies\sf{ (l-10)(l-16)=0}$ $:\implies\sf{ (l=16)\:or\:(l=10)}$ So, Length of the rectangle = 16 m Breadth of the rectangle = 10 m To check ↓ ➥ Area of the rectangle = l × b ➥ Area = 16 × 10 ➥ Area = 160 m² Hence VERIFIED!

44.

If the perimeter of rectangle is 52metere and area is 160m² thae lenghth of rectangle is

Answer»

GIVEN :-

AREA of the RECTANGLE = 160 m²

Perimeter of the rectangle = 52 m

To Find :-

Length of the rectangle

Solution :-

Perimeter of the rectangle :-

$:\implies\sf{Perimeter = 2(l+b)}$

$:\implies\sf{52 = 2(l+b)}$

$:\implies\sf{52/2 = (l+b)}$

$:\implies\sf{26 = (l+b)}$

$:\implies\sf{b=26-l}...(1)$

Area of the rectangle :-

$:\implies\sf{Area = l \times b}$

$:\implies\sf{160 = l \times (26-l)}$

$:\implies\sf{160 = 26l-l^2}$

$:\implies\sf{ 26l-l^2-160=0}$

$:\implies\sf{ -l^2+26l-160=0}$

$:\implies\sf{ l^2-26l+160=0}$

$:\implies\sf{ l^2-10l-16l+160=0}$

$:\implies\sf{ l(l-10)-16(l-10)=0}$

$:\implies\sf{ (l-10)(l-16)=0}$

$:\implies\sf{ (l=16)\:or\:(l=10)}$

So,

Length of the rectangle = 16 m

Breadth of the rectangle = 10 m

To check ↓

➥ Area of the rectangle = l × b

➥ Area = 16 × 10

➥ Area = 160 m²

Hence VERIFIED!

Discussion

45.	If a transversal intersects two parallel lines, show that the bisectors of any pairof alternate angles are parallel.
Answer» Step-by-step EXPLANATION: SIMILARLY you can PROVE this Kindly MARK as the BRAINLIEST

45.

If a transversal intersects two parallel lines, show that the bisectors of any pairof alternate angles are parallel.

Answer»

Step-by-step EXPLANATION:

SIMILARLY you can PROVE this

Kindly MARK as the BRAINLIEST

Discussion

46.	Please solve this math
Answer» ANSWER: QUESTION 5. LENGHT of shark=1000cm 20/100*1000=200cm

46.

Please solve this math

Answer»

ANSWER:

QUESTION 5.

LENGHT of shark=1000cm

20/100*1000=200cm

Discussion

47.	Chapter :- method of substitution
Answer» Given to evaluate, $\displaystyle\longrightarrow I=\int\dfrac{dx}{(x-b)^<klux>3</klux>(x-a)^<klux>2</klux>}\quad\quad\dots(<klux>1</klux>)$ Substitute, $\displaystyle\longrightarrow x=a\cos^2\theta+b\sin^2\theta\quad\quad\dots(2)$ $\displaystyle\longrightarrow dx=\left(-2a\sin\theta\cos\theta+2b\sin\theta\cos\theta\right)\ d\theta$ $\displaystyle\longrightarrow dx=2(b-a)\sin\theta\cos\theta\ d\theta$ Now, adding $a\sin^2\theta$ to both sides of (2), $\displaystyle\longrightarrow x+a\sin^2\theta=a\cos^2\theta+b\sin^2\theta+a\sin^2\theta$ Since $\sin^2\theta+\cos^2\theta=1,$ $\displaystyle\longrightarrow x+a\sin^2\theta=a+b\sin^2\theta$ $\displaystyle\longrightarrow x-a=(b-a)\sin^2\theta\quad\quad\dots(3)$ Similarly, adding $b\cos^2\theta$ to both sides of (2), $\displaystyle\longrightarrow x+b\cos^2\theta=a\cos^2\theta+b\sin^2\theta+b\cos^2\theta$ $\displaystyle\longrightarrow x+b\cos^2\theta=a\cos^2\theta+b$ $\displaystyle\longrightarrow x-b=(a-b)\cos^2\theta\quad\quad\dots(4)$ DIVIDING (3) by (4), $\displaystyle\longrightarrow\dfrac{x-a}{x-b}=\dfrac{(b-a)\sin^2\theta}{(a-b)\cos^2\theta}$ $\displaystyle\longrightarrow\tan^2\theta=\dfrac{x-a}{b-x}\quad\quad\dots(<klux>5</klux>)$ Thus (1) becomes, $\displaystyle\longrightarrow I=\int\dfrac{2(b-a)\sin\theta\cos\theta}{\left[(a-b)\cos^2\theta\right]^3\left[(b-a)\sin^2\theta\right]^2}\ d\theta$ $\displaystyle\longrightarrow I=\dfrac{2(b-a)}{(a-b)^5}\int\dfrac{\sin\theta\cos\theta}{\cos^6\theta\sin^4\theta}\ d\theta$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{1}{\cos^5\theta\sin^3\theta}\ d\theta$ Dividing both numerator and denominator of the integrand by $\cos^3\theta,$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(\dfrac{1}{\cos^3\theta}\right)}{\left(\dfrac{\cos^5\theta\sin^3\theta}{\cos^3\theta}\right)}\ d\theta$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(\dfrac{1}{\cos^3\theta}\right)}{\tan^3\theta\cos^5\theta}\ d\theta$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(\dfrac{1}{\cos^8\theta}\right)}{\tan^3\theta}\ d\theta$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\sec^8\theta}{\tan^3\theta}\ d\theta$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(1+\tan^2\theta\right)^3\sec^2\theta\ d\theta}{\tan^3\theta}\quad\quad\dots(6)$ Substitute, $\longrightarrow u=\tan\theta$ $\longrightarrow du=\sec^2\theta\ d\theta$ Then (6) becomes, $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(1+u^2\right)^3}{u^3}\ du$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{1+3u^2+3u^4+u^6}{u^3}\ du$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\left(\dfrac{1}{u^3}+\dfrac{3}{u}+3u+u^3\right)\ du$ $\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\left[-\dfrac{1}{2u^2}+3\ln\|u\|+\dfrac{3u^2}{2}+\dfrac{u^4}{4}\right]+C$ $\displaystyle\longrightarrow I=\dfrac{1}{(a-b)^4}\left[\dfrac{1}{u^2}-3\ln\left(u^2\right)-3u^2-\dfrac{u^4}{2}\right]+C$ Undoing substitution $u=\tan\theta,$ $\displaystyle\longrightarrow I=\dfrac{1}{(a-b)^4}\left[\dfrac{1}{\tan^2\theta}-3\ln\left(\tan^2\theta\right)-3\tan^2\theta-\dfrac{\tan^4\theta}{2}\right]+C$ From (5), we get, $\displaystyle\longrightarrow\underline{\underline{I=\dfrac{1}{(a-b)^4}\left[\dfrac{3(x-a)}{x-b}-\dfrac{x-b}{x-a}-\dfrac{1}{2}\left(\dfrac{x-a}{x-b}\right)^2-3\ln\left\|\dfrac{x-a}{b-x}\right\|\right]+C}}$

47.

Chapter :- method of substitution

Answer»

Given to evaluate,

$\displaystyle\longrightarrow I=\int\dfrac{dx}{(x-b)^<klux>3</klux>(x-a)^<klux>2</klux>}\quad\quad\dots(<klux>1</klux>)$

Substitute,

$\displaystyle\longrightarrow x=a\cos^2\theta+b\sin^2\theta\quad\quad\dots(2)$

$\displaystyle\longrightarrow dx=\left(-2a\sin\theta\cos\theta+2b\sin\theta\cos\theta\right)\ d\theta$

$\displaystyle\longrightarrow dx=2(b-a)\sin\theta\cos\theta\ d\theta$

Now, adding $a\sin^2\theta$ to both sides of (2),

$\displaystyle\longrightarrow x+a\sin^2\theta=a\cos^2\theta+b\sin^2\theta+a\sin^2\theta$

Since $\sin^2\theta+\cos^2\theta=1,$

$\displaystyle\longrightarrow x+a\sin^2\theta=a+b\sin^2\theta$

$\displaystyle\longrightarrow x-a=(b-a)\sin^2\theta\quad\quad\dots(3)$

Similarly, adding $b\cos^2\theta$ to both sides of (2),

$\displaystyle\longrightarrow x+b\cos^2\theta=a\cos^2\theta+b\sin^2\theta+b\cos^2\theta$

$\displaystyle\longrightarrow x+b\cos^2\theta=a\cos^2\theta+b$

$\displaystyle\longrightarrow x-b=(a-b)\cos^2\theta\quad\quad\dots(4)$

DIVIDING (3) by (4),

$\displaystyle\longrightarrow\dfrac{x-a}{x-b}=\dfrac{(b-a)\sin^2\theta}{(a-b)\cos^2\theta}$

$\displaystyle\longrightarrow\tan^2\theta=\dfrac{x-a}{b-x}\quad\quad\dots(<klux>5</klux>)$

Thus (1) becomes,

$\displaystyle\longrightarrow I=\int\dfrac{2(b-a)\sin\theta\cos\theta}{\left[(a-b)\cos^2\theta\right]^3\left[(b-a)\sin^2\theta\right]^2}\ d\theta$

$\displaystyle\longrightarrow I=\dfrac{2(b-a)}{(a-b)^5}\int\dfrac{\sin\theta\cos\theta}{\cos^6\theta\sin^4\theta}\ d\theta$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{1}{\cos^5\theta\sin^3\theta}\ d\theta$

Dividing both numerator and denominator of the integrand by $\cos^3\theta,$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(\dfrac{1}{\cos^3\theta}\right)}{\left(\dfrac{\cos^5\theta\sin^3\theta}{\cos^3\theta}\right)}\ d\theta$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(\dfrac{1}{\cos^3\theta}\right)}{\tan^3\theta\cos^5\theta}\ d\theta$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(\dfrac{1}{\cos^8\theta}\right)}{\tan^3\theta}\ d\theta$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\sec^8\theta}{\tan^3\theta}\ d\theta$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(1+\tan^2\theta\right)^3\sec^2\theta\ d\theta}{\tan^3\theta}\quad\quad\dots(6)$

Substitute,

$\longrightarrow u=\tan\theta$

$\longrightarrow du=\sec^2\theta\ d\theta$

Then (6) becomes,

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{\left(1+u^2\right)^3}{u^3}\ du$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\dfrac{1+3u^2+3u^4+u^6}{u^3}\ du$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\int\left(\dfrac{1}{u^3}+\dfrac{3}{u}+3u+u^3\right)\ du$

$\displaystyle\longrightarrow I=-\dfrac{2}{(a-b)^4}\left[-\dfrac{1}{2u^2}+3\ln|u|+\dfrac{3u^2}{2}+\dfrac{u^4}{4}\right]+C$

$\displaystyle\longrightarrow I=\dfrac{1}{(a-b)^4}\left[\dfrac{1}{u^2}-3\ln\left(u^2\right)-3u^2-\dfrac{u^4}{2}\right]+C$

Undoing substitution $u=\tan\theta,$

$\displaystyle\longrightarrow I=\dfrac{1}{(a-b)^4}\left[\dfrac{1}{\tan^2\theta}-3\ln\left(\tan^2\theta\right)-3\tan^2\theta-\dfrac{\tan^4\theta}{2}\right]+C$

From (5), we get,

$\displaystyle\longrightarrow\underline{\underline{I=\dfrac{1}{(a-b)^4}\left[\dfrac{3(x-a)}{x-b}-\dfrac{x-b}{x-a}-\dfrac{1}{2}\left(\dfrac{x-a}{x-b}\right)^2-3\ln\left|\dfrac{x-a}{b-x}\right|\right]+C}}$

Discussion

48.	What is elasticityquestion kyu delete kara yrrr mt kar ni answer dena koi ni delete mt karo
Answer» Step-by-step explanation: In ECONOMICS, elasticity is the MEASUREMENT of the percentage CHANGE of ONE economic variable in response to a change in another. An ELASTIC variable is one which responds more than proportionally to changes in other variables.

48.

What is elasticityquestion kyu delete kara yrrr mt kar ni answer dena koi ni delete mt karo

Answer»

Step-by-step explanation:

In ECONOMICS, elasticity is the MEASUREMENT of the percentage CHANGE of ONE economic variable in response to a change in another. An ELASTIC variable is one which responds more than proportionally to changes in other variables.

Discussion

49.	Write the identity of (a-b) the hole square
Answer» ANSWER: The SQUARE of this EXPRESSION is written as ( a − b ) 2 in mathematical form and it is expanded as a 2 − 2 a b + b 2 mathematically. In mathematics, this ALGEBRAIC identity is used as a formula and it is called in the following three ways. The square of DIFFERENCE of the terms formula.

49.

Write the identity of (a-b) the hole square

Answer»

ANSWER:

The SQUARE of this EXPRESSION is written as ( a − b ) 2 in mathematical form and it is expanded as a 2 − 2 a b + b 2 mathematically. In mathematics, this ALGEBRAIC identity is used as a formula and it is called in the following three ways. The square of DIFFERENCE of the terms formula.

Discussion

50.	Income earned from buying and selling of shares is considered under : *(a) Income from business and profession(b) Income from capital gain(c) Income from other sourcespls help
Answer» ANSWER: INCOME from CAPITAL gain hope it'll help purple UH FOREVER

50.

Income earned from buying and selling of shares is considered under : *(a) Income from business and profession(b) Income from capital gain(c) Income from other sourcespls help

Answer»

ANSWER:

INCOME from CAPITAL gain

hope it'll help

purple UH FOREVER

Discussion

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Two dice are thrown. Find the probability of the following events:Event A: The product of the numbers on their upper faces is 10..Event B: The sum of the numbers on their upper faces is multiple of 9.​

If the perimeter of rectangle is 52metere and area is 160m² thae lenghth of rectangle is

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To Find :-

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If a transversal intersects two parallel lines, show that the bisectors of any pairof alternate angles are parallel.​

Please solve this math​

Chapter :- method of substitution​

What is elasticityquestion kyu delete kara yrrr mt kar ni answer dena koi ni delete mt karo ​

Write the identity of (a-b) the hole square​

Income earned from buying and selling of shares is considered under : *(a) Income from business and profession(b) Income from capital gain(c) Income from other sourcespls help ​​

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PLEASE ANSWER!!!Two dice are thrown. Find the probability of the following events:Event A : The product of the numbers on their upper faces is 10.Event B : The sum of the numbers on their upper faces is multiple of 9.

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Proof that :• ( a + b )² = a² + 2ab + b²No spam (=｀ェ´=)

If p(x) = 4x^2- 4x+4 find p(0)and p (-1)

Two dice are thrown. Find the probability of the following events:Event A: The product of the numbers on their upper faces is 10..Event B: The sum of the numbers on their upper faces is multiple of 9.

If a transversal intersects two parallel lines, show that the bisectors of any pairof alternate angles are parallel.

Please solve this math

Chapter :- method of substitution

What is elasticityquestion kyu delete kara yrrr mt kar ni answer dena koi ni delete mt karo

Write the identity of (a-b) the hole square

Income earned from buying and selling of shares is considered under : *(a) Income from business and profession(b) Income from capital gain(c) Income from other sourcespls help