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Proof that :• ( a + b )² = a² + 2ab + b²No spam (=`ェ´=) |
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Answer» (a+B)² = (a+b)×(a+b) = (a+b)(a+b) = [a×(a+b)]+[b×(a+b)] = [a(a+b)]+[b(a+b)] = [{(a×a)+(a×b)}] + [{(b×a)+(b×b)}] = [(a²)+(ab)] + [(ba)+(b²)] = (a²)+(ab)+(ba)+(b²) SINCE a×b = b×a (COMMUTATIVE property), ba = ab. = (a²)+(ab)+(ab)+(b²) = (a²)+(2×ab)+(b²) = (a²)+(2AB)+(b²) |
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