332354 + Interview Questions in Secondary School in Math

1.	If cos x = 5/12 then the value of sin 2A is√119/72√(119/72)(5*√119)/72None of these
Answer» ANSWER: PLEASE REFER to the ATTACHMENT for the answer

1.

If cos x = 5/12 then the value of sin 2A is√119/72√(119/72)(5*√119)/72None of these

Answer»

ANSWER:

PLEASE REFER to the ATTACHMENT for the answer

Discussion

2.	6825×926= what ans slove explain
Answer» ANSWER: 6 319 950, here is your answer!

2.

6825×926= what ans slove explain

Answer»

ANSWER:

6 319 950, here is your answer!

Discussion

3.	Draw the grap of the function f(x)={1+x,-1≤x≤0\1-x,0
Answer» $\large\underline{\sf{Solution-}}$ $\begin{gathered}\begin{gathered}\bf \:Given \: f(x) = y = \begin{cases} &\sf{1 + x \: if \: - 1 \leqslant x \leqslant 0} \\ &\sf{1 - x \: if \: 0 < x \leqslant 1} \end{cases}\end{gathered}\end{gathered}$ Case :- 1 $\sf \: When \: y \: = \: x + 1 \: if \: - 1 \leqslant x \leqslant 0$ 1. Substituting 'x = 0' in the given equation, we get $\rm :\longmapsto\:y = 1 + 0$ $\bf\implies \:y = 1$ 2. Substituting 'x = - 0.5' in the given equation, we get $\rm :\longmapsto\:y = 1 - 0.5$ $\bf\implies \:y = 0.5$ 3. Substituting 'x = - 1' in the given equation, we get $\rm :\longmapsto\:y = 1 - 1$ $\bf\implies \:y = 0$ Hᴇɴᴄᴇ, ➢ Pair of points of the given equation are shown in the below table. $\begin{gathered}\boxed{\begin{array}{c\|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 1 \\ \\ \sf - 0.5 & \sf 0.5 \\ \\ \sf - 1 & \sf 0 \end{array}} \\ \end{gathered}$ Now DRAW a GRAPH using the points (0 , 1), (- 0.5 , 0.5) & (- 1 , 0) ➢ See the attachment graph. (Red line) Case :- 2 $\sf \: When \: y = 1 - x \: if \: 0 < x \leqslant 1$ 1. Substituting 'x = 1' in the given equation, we get $\rm :\longmapsto\:y = 1 - 1$ $\bf\implies \:y = 0$ 2. Substituting 'x = 0.5' in the given equation, we get $\rm :\longmapsto\:y = 1 - 0.5$ $\bf\implies \:y = 0.5$ 3. Substituting 'x = 0.4' in the given equation, we get $\rm :\longmapsto\:y = 1 - 0.4$ $\bf\implies \:y = 0.6$ Hᴇɴᴄᴇ, ➢ Pair of points of the given equation are shown in the below table. $\begin{gathered}\boxed{\begin{array}{c\|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 1 & \sf 0 \\ \\ \sf 0.5 & \sf 0.5 \\ \\ \sf 0.4 & \sf 0.6 \end{array}} \\ \end{gathered}$ Now draw a graph using the points (1 , 0), (0.5 , 0.5) & (0.4 , 0.6) ➢ See the attachment graph. (BLUE line)

3.

Draw the grap of the function f(x)={1+x,-1≤x≤0\1-x,0

Answer»

$\large\underline{\sf{Solution-}}$

$\begin{gathered}\begin{gathered}\bf \:Given \: f(x) = y = \begin{cases} &\sf{1 + x \: if \: - 1 \leqslant x \leqslant 0} \\ &\sf{1 - x \: if \: 0 < x \leqslant 1} \end{cases}\end{gathered}\end{gathered}$

Case :- 1

$\sf \: When \: y \: = \: x + 1 \: if \: - 1 \leqslant x \leqslant 0$

1. Substituting 'x = 0' in the given equation, we get

$\rm :\longmapsto\:y = 1 + 0$

$\bf\implies \:y = 1$

2. Substituting 'x = - 0.5' in the given equation, we get

$\rm :\longmapsto\:y = 1 - 0.5$

$\bf\implies \:y = 0.5$

3. Substituting 'x = - 1' in the given equation, we get

$\rm :\longmapsto\:y = 1 - 1$

$\bf\implies \:y = 0$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 1 \\ \\ \sf - 0.5 & \sf 0.5 \\ \\ \sf - 1 & \sf 0 \end{array}} \\ \end{gathered}$

Now DRAW a GRAPH using the points (0 , 1), (- 0.5 , 0.5) & (- 1 , 0)

➢ See the attachment graph. (Red line)

Case :- 2

$\sf \: When \: y = 1 - x \: if \: 0 < x \leqslant 1$

1. Substituting 'x = 1' in the given equation, we get

$\rm :\longmapsto\:y = 1 - 1$

$\bf\implies \:y = 0$

2. Substituting 'x = 0.5' in the given equation, we get

$\rm :\longmapsto\:y = 1 - 0.5$

$\bf\implies \:y = 0.5$

3. Substituting 'x = 0.4' in the given equation, we get

$\rm :\longmapsto\:y = 1 - 0.4$

$\bf\implies \:y = 0.6$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 1 & \sf 0 \\ \\ \sf 0.5 & \sf 0.5 \\ \\ \sf 0.4 & \sf 0.6 \end{array}} \\ \end{gathered}$

Now draw a graph using the points (1 , 0), (0.5 , 0.5) & (0.4 , 0.6)

➢ See the attachment graph. (BLUE line)

Discussion

4.	For class interval 50-60 write the upper class limit and class with respectively:60-50,10-50,60-10,55-5.
Answer» HI GOOD AFTERNOON how are you

Discussion

5.	The value of cos 4A - cos 4B is(cos A - cos B)(cos A + cos B)(cos A - sin B)(cos A + sin B)2(cos A - cos B)(cos A + cos B)(cos A - sin B)(cos A + sin B)4(cos A - cos B)(cos A + cos B)(cos A - sin B)(cos A + sin B)8(cos A - cos B)(cos A + cos B)(cos A - sin B)(cos A + sin B)
Answer» $\implies$ Step-by-step EXPLANATION: ➩A+B+C= 180 ➩cos4A+cos4B+cos4c ➩cos4(A+B+C) =180 ➩cos 4A +cos4B -SIN 4(2A) ➩cos4-tan4c ➩1+4cos 2a+cos2b+cos2c

5.

The value of cos 4A - cos 4B is(cos A - cos B)(cos A + cos B)(cos A - sin B)(cos A + sin B)2(cos A - cos B)(cos A + cos B)(cos A - sin B)(cos A + sin B)4(cos A - cos B)(cos A + cos B)(cos A - sin B)(cos A + sin B)8(cos A - cos B)(cos A + cos B)(cos A - sin B)(cos A + sin B)

Answer»

$\implies$

Step-by-step EXPLANATION:

➩A+B+C= 180

➩cos4A+cos4B+cos4c

➩cos4(A+B+C) =180

➩cos 4A +cos4B -SIN 4(2A)

➩cos4-tan4c

➩1+4cos 2a+cos2b+cos2c

Discussion

6.	Q.I. (A) Choose the correct alternative.i). Out of the following point ____ lies to the right of the origin on X-axis(A) (-2,0) (B) (0,2)(C) (2, 3)(D) (2,0)ii).The number of tangents that can be drawn to a circle at a point on the circle is (A) 3 (B) 2(C) 1(1)) 0iii). In a cyclic []ABCD, twice the measure of angleA in thrice the measure of angleC. Find the measure of angleC?(A) 36°(B) 72°(C)90°(D)108°iv). 9 sec A-9 tan A=(A) 0 (B) 3(C)-9(D)9
Answer» ANSWER: I) option D II) option B III) option B III) option D Step-by-step EXPLANATION: I THINK helpful to you

6.

Q.I. (A) Choose the correct alternative.i). Out of the following point ____ lies to the right of the origin on X-axis(A) (-2,0) (B) (0,2)(C) (2, 3)(D) (2,0)ii).The number of tangents that can be drawn to a circle at a point on the circle is (A) 3 (B) 2(C) 1(1)) 0iii). In a cyclic []ABCD, twice the measure of angleA in thrice the measure of angleC. Find the measure of angleC?(A) 36°(B) 72°(C)90°(D)108°iv). 9 sec A-9 tan A=(A) 0 (B) 3(C)-9(D)9

Answer»

ANSWER:

I) option D

II) option B

III) option B

III) option D

Step-by-step EXPLANATION:

I THINK helpful to you

Discussion

7.	A number divisible by both 2 and 5 must have ____ in its ones place.
Answer» A number DIVISIBLE by both 2 and 5 MUST have 0 in its ones place Hope it helps you Mark me as brainliest

7.

A number divisible by both 2 and 5 must have ____ in its ones place.

Answer»

A number DIVISIBLE by both 2 and 5 MUST have 0 in its ones place

Hope it helps you

Mark me as brainliest

Discussion

8.	1235 multiply by 432
Answer» ANSWER: 533,520 Is the answer

8.

1235 multiply by 432

Answer»

ANSWER:

533,520

Is the answer

Discussion

9.	10*3b+14b=88 please solve it
Answer» Answer: which CHAPTER wo to BATAO Step-by-step EXPLANATION: HAR chapter me alag alag aata hai answer TELL that

9.

10*3b+14b=88 please solve it

Answer»

Answer:

which CHAPTER wo to BATAO

Step-by-step EXPLANATION:

HAR chapter me alag alag aata hai answer TELL that

Discussion

10.	016 What is the value of 0.1 +0.2 0.3 +0.4 ?(1) 0.56(2) 1.338 1.1(4) 5.6
Answer» Answer: 1 Step-by-step explanation: 0.1+0.2+0.3+0.4= 1 if DONE by ARRANGING then

10.

016 What is the value of 0.1 +0.2 0.3 +0.4 ?(1) 0.56(2) 1.338 1.1(4) 5.6

Answer»

Answer:

1

Step-by-step explanation:

0.1+0.2+0.3+0.4= 1

if DONE by ARRANGING then

Discussion

11.	If tan 2x = cot (x + π/3) then the value of x isx = nπx = nπ + π/6x = nπ - π/6x = nπ + π/3
Answer» Answer: X = nπ + π/6 explanation in the attachment pls REFER to it if found HELPFUL mark it as brainiliest and follow PLZ

11.

If tan 2x = cot (x + π/3) then the value of x isx = nπx = nπ + π/6x = nπ - π/6x = nπ + π/3

Answer»

Answer:

X = nπ + π/6

explanation in the attachment

pls REFER to it

if found HELPFUL mark it as brainiliest and follow PLZ

Discussion

12.	Is it possible to construct a quadrilateral with sides3 cm, 4 cm, 5 cm, 4 cm and diagonal of length 8 cm ? If not why ? DON'T SPAM
Answer» ANSWER: YES ,IT IS POSSIBLE TO CONSTRUCT A QUADRILATERAL WITH GIVEN SIDES.

12.

Is it possible to construct a quadrilateral with sides3 cm, 4 cm, 5 cm, 4 cm and diagonal of length 8 cm ? If not why ? DON'T SPAM

Answer»

ANSWER:

YES ,IT IS POSSIBLE TO CONSTRUCT A QUADRILATERAL WITH GIVEN SIDES.

Discussion

13.	What will be the sum, if 4/6is added 15 times ?
Answer» Answer: 4 is ADDED to the number, then algebraically, this can be expressed as: n + 4. If this sum is multiplied by 3, then, algebraically, we can express this as: 3(n + 4). If this product is, in turn, equal to 30, then we can write the following equation and solve for n: 3(n + 4) = 30 To solve for n, we need to isolate n on the left side of the above equation, and we begin doing this by dividing both sides of the equation by 3 as follows: [3(n + 4)]/3 = 30/3 (3/3)(n + 4) = 10 (1)(n + 4) = 10 n + 4 = 10 Now, we finish isolating n on the left, THUS solving for n, by subtracting 4 from both sides of the equation: n + 4 - 4 = 10 - 4 n + 0 = 6 n = 6 CHECK: Replacing n with 6 in the original equation, we get: 3(n + 4) = 30 3(6 + 4) = 30 3(10) = 30 30 = 30 Therefore, n = 6 is indeed the desired, unknown number.

13.

What will be the sum, if 4/6is added 15 times ?

Answer»

Answer:

4 is ADDED to the number, then algebraically, this can be expressed as: n + 4.

If this sum is multiplied by 3, then, algebraically, we can express this as:

3(n + 4). If this product is, in turn, equal to 30, then we can write the following equation and solve for n:

3(n + 4) = 30

To solve for n, we need to isolate n on the left side of the above equation, and we begin doing this by dividing both sides of the equation by 3 as follows:

[3(n + 4)]/3 = 30/3

(3/3)(n + 4) = 10

(1)(n + 4) = 10

n + 4 = 10

Now, we finish isolating n on the left, THUS solving for n, by subtracting 4 from both sides of the equation:

n + 4 - 4 = 10 - 4

n + 0 = 6

n = 6

CHECK:

Replacing n with 6 in the original equation, we get:

3(n + 4) = 30

3(6 + 4) = 30

3(10) = 30

30 = 30

Therefore, n = 6 is indeed the desired, unknown number.

Discussion

14.	Parallelogram.2.25 Plot the points (2,3), (0, 1) and (4,5).Do they lie on a same line?A card is drawn from a nack of 52 cards , find the probability that the card dra
Answer» ANSWER: dtotdogdoydpdpudppfpphpdlhdoydpdpydoydoydoydooydoyxodhpdoy

14.

Parallelogram.2.25 Plot the points (2,3), (0, 1) and (4,5).Do they lie on a same line?A card is drawn from a nack of 52 cards , find the probability that the card dra

Answer»

ANSWER:

dtotdogdoydpdpudppfpphpdlhdoydpdpydoydoydoydooydoyxodhpdoy

Discussion

15.	(1) 3mn,_5mn,8mn,_4mn(2)30ab+12b+14 (3)_5Y2 from y2
Answer» Step-by-step explanation: 3mn,−5mn,8MN,−4mn=3mn+(−5mn)+8mn+(−4mn) =(3−5+8−4)mn=2mn.

15.

(1) 3mn,_5mn,8mn,_4mn(2)30ab+12b+14 (3)_5Y2 from y2

Answer»

Step-by-step explanation:

3mn,−5mn,8MN,−4mn=3mn+(−5mn)+8mn+(−4mn)

=(3−5+8−4)mn=2mn.

Discussion

16.	If for ap s15 =147 and s14= 123 find t15
Answer» Step-by-step EXPLANATION: this will be the CORRECT answer. best of WORK.

16.

If for ap s15 =147 and s14= 123 find t15

Answer»

Step-by-step EXPLANATION:

this will be the CORRECT answer.

best of WORK.

Discussion

17.	Find tge value of 36/45÷6/9
Answer» ANSWER: 36/45 × 9/6 6/5 is the required answer. PLEASE Mark me as Brainlest. and please FOLLOW.

17.

Find tge value of 36/45÷6/9

Answer»

ANSWER:

36/45 × 9/6

6/5

is the required answer. PLEASE Mark me as Brainlest. and please FOLLOW.

Discussion

18.	X+yvarijas z and x+z varijas y than prove that x+y+z garijas yz
Answer» ANSWER: SORRY can't UNDERSTAND the QUESTION

18.

X+yvarijas z and x+z varijas y than prove that x+y+z garijas yz

Answer»

ANSWER:

SORRY can't UNDERSTAND the QUESTION

Discussion

19.	Very very confused for: q+p+q+p+q
Answer» Answer: 3q+2p is the answer BUDDY. please MARK me as BRAINLEST and FOLLOW

19.

Very very confused for: q+p+q+p+q

Answer»

Answer:

3q+2p

is the answer BUDDY. please MARK me as BRAINLEST and FOLLOW

Discussion

20.	Maya bought 20 pencils for rupees 50 and sold them at rupees 3 each. What was her profit or loss percent?
Answer» ANSWER: at FIRST PRICE =2.5 20×3=60 profit = 60-50=10 profit PERCENT =10÷60×100 = 16 ℅

20.

Maya bought 20 pencils for rupees 50 and sold them at rupees 3 each. What was her profit or loss percent?

Answer»

ANSWER:

at FIRST PRICE =2.5

20×3=60

profit = 60-50=10

profit PERCENT =10÷60×100 = 16 ℅

Discussion

21.	Simplify the following and show your solutions1.) (a³)(a²)(a⁶) =2.) 6⁵/6⁷ =3.) (2y³)² =4.) (m⁴/n²)⁸ =
Answer» Answer: 1 a to the power 36 2 6 to the -2 3 2y WHOLE to the power 6 4 m whole to the power 12 mark me as BRAINLEST

21.

Simplify the following and show your solutions1.) (a³)(a²)(a⁶) =2.) 6⁵/6⁷ =3.) (2y³)² =4.) (m⁴/n²)⁸ =

Answer»

Answer:

1 a to the power 36

2 6 to the -2

3 2y WHOLE to the power 6

4 m whole to the power 12

mark me as BRAINLEST

Discussion

22.	Is the value of x in figure 1 have the same value in y? How about figure 2?
Answer» Answer: Figure 2: -1,0,0,2,3. STEP- by-step ... kason11wd and 1 more users found this answer helpful. Thanks 1. 0.0 ... STILL have questions? ... Х3y53(x, y)(3, 0)(0, 3).

22.

Is the value of x in figure 1 have the same value in y? How about figure 2?

Answer»

Answer:

Figure 2: -1,0,0,2,3. STEP- by-step ... kason11wd and 1 more users found this answer helpful. Thanks 1. 0.0 ... STILL have questions? ... Х3y53(x, y)(3, 0)(0, 3).

Discussion

23.	Estimate the probability that the next patron will check out a audiobook.
Answer» ANSWER: Estimate the probability that the NEXT PATRON will check out a FICTION book. Explain your reasoning. *.

23.

Estimate the probability that the next patron will check out a audiobook.

Answer»

ANSWER:

Estimate the probability that the NEXT PATRON will check out a FICTION book. Explain your reasoning. *.

Discussion

24.	25.The area of a right triangle is 50 sq m.If one of the legs is 20 m, then the length of the other leg is -------. *
Answer» Answer: other leg is equal to 5m Step-by-step EXPLANATION: as we KNOW that AREA of triangle is equal to half of product of base and HIGHT

24.

25.The area of a right triangle is 50 sq m.If one of the legs is 20 m, then the length of the other leg is -------. *

Answer»

Answer:

other leg is equal to 5m

Step-by-step EXPLANATION:

as we KNOW that AREA of triangle is equal to half of product of base and HIGHT

Discussion

25.	Integrate [x^2] dx from 0to 2
Answer» ANSWER: $\\\tt \dfrac{8}{3}$ Step-by-step EXPLANATION: $\\\tt \int\limits^2_0 {x^2} \, dx \\\\$ $\\\tt \[ \dfrac{x^{3}}{3} \Biggr\|_{0}^{2}\]\\\\= \dfrac{2^{3}}{3} - \dfrac{0^{3}}{3}\\\\= \dfrac{8}{3}$

25.

Integrate [x^2] dx from 0to 2

Answer»

ANSWER:

$\\\tt \dfrac{8}{3}$

Step-by-step EXPLANATION:

$\\\tt \int\limits^2_0 {x^2} \, dx \\\\$

$\\\tt \[ \dfrac{x^{3}}{3} \Biggr|_{0}^{2}\]\\\\= \dfrac{2^{3}}{3} - \dfrac{0^{3}}{3}\\\\= \dfrac{8}{3}$

Discussion

26.	For what value(s) of ‘a’, quadratic equation 30ax2 -6x + 1 =0 has no real roots?
Answer» Answer: a > $\frac{3}{10}$ Step-by-step EXPLANATION: The step-by-step SOLUTION is GIVEN in the attached picture. Hoping that I have not MADE any mistakes, You're welcome. Hope you have found my answer USEFUL. If my answer deserves a brainliest, do mark it, Thanks ! GeniusH

26.

For what value(s) of ‘a’, quadratic equation 30ax2 -6x + 1 =0 has no real roots?

Answer»

Answer:

a > $\frac{3}{10}$

Step-by-step EXPLANATION:

The step-by-step SOLUTION is GIVEN in the attached picture.

Hoping that I have not MADE any mistakes, You're welcome.

Hope you have found my answer USEFUL. If my answer deserves a brainliest, do mark it, Thanks !

GeniusH

Discussion

27.	Round of 786 to the nearest hundred
Answer» Answer: 800 Step-by-step explanation: 800 we have to CHECK the tens digit while ROUNDING of and if it is 5,6,7,8,9 then ADD one to the digit towards LEFT and 0 the remaining digits

27.

Round of 786 to the nearest hundred

Answer»

Answer:

800

Step-by-step explanation:

800

we have to CHECK the tens digit while ROUNDING of and if it is 5,6,7,8,9 then ADD one to the digit towards LEFT and 0 the remaining digits

Discussion

28.	2 x^2+ y^2+8 z^2-2√2xy+4 √2yz-8xz
Answer» ANSWER: HERE IS YOUR ANSWER BRO ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️PLS MAKE MY ANSWER AS BRAINLIEST ❤️

28.

2 x^2+ y^2+8 z^2-2√2xy+4 √2yz-8xz

Answer»

ANSWER:

HERE IS YOUR ANSWER BRO ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️PLS MAKE MY ANSWER AS BRAINLIEST ❤️

Discussion

29.	Write 0.00235 in standard form
Answer» 2.35x10³ is the answer Thnx✌️✌️

29.

Write 0.00235 in standard form

Answer»

2.35x10³ is the answer

Thnx✌️✌️

Discussion

30.	Solutions for the equation x ^3+6x^2 -9x +4 =0 find the values of x
Answer» Step-by-step explanation: STEP 1 : Equation at the end of step 1 (((x3) - (2•3x2)) - 6x) - 4 = 0 STEP 2 : Checking for a perfect cube 2.1 x3-6x2-6x-4 is not a perfect cube Trying to factor by pulling out : 2.2 Factoring: x3-6x2-6x-4 Thoughtfully split the expression at hand into groups, each group having TWO terms : Group 1: x3-4 Group 2: -6x2-6x Pull out from each group separately : Group 1: (x3-4) • (1) Group 2: (x+1) • (-6x) Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication Polynomial ROOTS Calculator : 2.3 Find roots (zeroes) of : F(x) = x3-6x2-6x-4 Polynomial Roots Calculator is a set of methods AIMED at finding values of x for which F(x)=0 RATIONAL Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient In this case, the Leading Coefficient is 1 and the Trailing Constant is -4. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,2 ,4 Let us test .... P Q P/Q F(P/Q) Divisor -1 1 -1.00 -5.00 -2 1 -2.00 -24.00 -4 1 -4.00 -140.00 1 1 1.00 -15.00 2 1 2.00 -32.00 4 1 4.00 -60.00 Polynomial Roots Calculator found no rational roots Equation at the end of step 2 : x3 - 6x2 - 6x - 4 = 0 STEP 3 : Cubic Equations: 3.1 Solve x3-6x2-6x-4 = 0 Future releases of Tiger-Algebra will solve equations of the third degree directly. Meanwhile we will use the Bisection method to approximate one real solution. Approximating a root using the Bisection Method : We now use the Bisection Method to approximate one of the solutions. The Bisection Method is an iterative procedure to approximate a root (Root is another name for a solution of an equation). The function is F(x) = x3 - 6x2 - 6x - 4 At x= 6.00 F(x) is equal to -40.00 At x= 7.00 F(x) is equal to 3.00 Intuitively we feel, and justly so, that since F(x) is negative on one side of the interval, and positive on the other side then, somewhere inside this interval, F(x) is zero Procedure : (1) Find a point "Left" where F(Left) < 0 (2) Find a point 'Right' where F(Right) > 0 (3) Compute 'Middle' the middle point of the interval [Left,Right] (4) Calculate VALUE = F(Middle) (5) If Value is close enough to zero goto Step (7) Else : If Value < 0 then : Left <- Middle If Value > 0 then : Right <- Middle (6) Loop back to Step (3) (7) Done!! The approximation found is Middle Follow Middle movements to understand how it works : Left Value(Left) Right Value(Right) 6.000000000 -40.000000000 7.000000000 3.000000000 0.000000000 -4.000000000 7.000000000 3.000000000 3.500000000 -55.625000000 7.000000000 3.000000000 5.250000000 -56.171875000 7.000000000 3.000000000 6.125000000 -36.060546875 7.000000000 3.000000000 6.562500000 -19.150146484 7.000000000 3.000000000 6.781250000 -8.761444092 7.000000000 3.000000000 6.890625000 -3.056240082 7.000000000 3.000000000 6.945312500 -0.072490215 7.000000000 3.000000000 6.945312500 -0.072490215 6.972656250 1.452601016 6.945312500 -0.072490215 6.958984375 0.687274598 6.945312500 -0.072490215 6.952148438 0.306697949 6.945312500 -0.072490215 6.948730469 0.116930426 6.945312500 -0.072490215 6.947021484 0.022176760 6.946166992 -0.025167562 6.947021484 0.022176760 6.946594238 -0.001498110 6.947021484 0.022176760 6.946594238 -0.001498110 6.946807861 0.010338648 6.946594238 -0.001498110 6.946701050 0.004420100 6.946594238 -0.001498110 6.946647644 0.001460953 6.946620941 -0.000018589 6.946647644 0.001460953 6.946620941 -0.000018589 6.946634293 0.000721179 6.946620941 -0.000018589 6.946627617 0.000351294 6.946620941 -0.000018589 6.946624279 0.000166352 6.946620941 -0.000018589 6.946622610 0.000073882 6.946620941 -0.000018589 6.946621776 0.000027646 6.946620941 -0.000018589 6.946621358 0.000004529 6.946621150 -0.000007030 6.946621358 0.000004529 6.946621254 -0.000001251 6.946621358 0.000004529 Next Middle will get us close enough to zero: F( 6.946621280 ) is 0.000000194 The desired approximation of the solution is: x ≓ 6.946621280 Note, ≓ is the approximation symbol One solution was found : x ≓ 6.946621280

30.

Solutions for the equation x ^3+6x^2 -9x +4 =0 find the values of x

Answer»

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(((x3) - (2•3x2)) - 6x) - 4 = 0

STEP

2

:

Checking for a perfect cube

2.1 x3-6x2-6x-4 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3-6x2-6x-4

Thoughtfully split the expression at hand into groups, each group having TWO terms :

Group 1: x3-4

Group 2: -6x2-6x

Pull out from each group separately :

Group 1: (x3-4) • (1)

Group 2: (x+1) • (-6x)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication

Polynomial ROOTS Calculator :

2.3 Find roots (zeroes) of : F(x) = x3-6x2-6x-4

Polynomial Roots Calculator is a set of methods AIMED at finding values of x for which F(x)=0

RATIONAL Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 1 and the Trailing Constant is -4.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1 ,2 ,4

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 -5.00

-2 1 -2.00 -24.00

-4 1 -4.00 -140.00

1 1 1.00 -15.00

2 1 2.00 -32.00

4 1 4.00 -60.00

Polynomial Roots Calculator found no rational roots

Equation at the end of step

2

:

x3 - 6x2 - 6x - 4 = 0

STEP

3

:

Cubic Equations:

3.1 Solve x3-6x2-6x-4 = 0

Future releases of Tiger-Algebra will solve equations of the third degree directly.

Meanwhile we will use the Bisection method to approximate one real solution.

Approximating a root using the Bisection Method :

We now use the Bisection Method to approximate one of the solutions. The Bisection Method is an iterative procedure to approximate a root (Root is another name for a solution of an equation).

The function is F(x) = x3 - 6x2 - 6x - 4

At x= 6.00 F(x) is equal to -40.00

At x= 7.00 F(x) is equal to 3.00

Intuitively we feel, and justly so, that since F(x) is negative on one side of the interval, and positive on the other side then, somewhere inside this interval, F(x) is zero

Procedure :

(1) Find a point "Left" where F(Left) < 0

(2) Find a point 'Right' where F(Right) > 0

(3) Compute 'Middle' the middle point of the interval [Left,Right]

(4) Calculate VALUE = F(Middle)

(5) If Value is close enough to zero goto Step (7)

Else :

If Value < 0 then : Left <- Middle

If Value > 0 then : Right <- Middle

(6) Loop back to Step (3)

(7) Done!! The approximation found is Middle

Follow Middle movements to understand how it works :

Left Value(Left) Right Value(Right)

6.000000000 -40.000000000 7.000000000 3.000000000

0.000000000 -4.000000000 7.000000000 3.000000000

3.500000000 -55.625000000 7.000000000 3.000000000

5.250000000 -56.171875000 7.000000000 3.000000000

6.125000000 -36.060546875 7.000000000 3.000000000

6.562500000 -19.150146484 7.000000000 3.000000000

6.781250000 -8.761444092 7.000000000 3.000000000

6.890625000 -3.056240082 7.000000000 3.000000000

6.945312500 -0.072490215 7.000000000 3.000000000

6.945312500 -0.072490215 6.972656250 1.452601016

6.945312500 -0.072490215 6.958984375 0.687274598

6.945312500 -0.072490215 6.952148438 0.306697949

6.945312500 -0.072490215 6.948730469 0.116930426

6.945312500 -0.072490215 6.947021484 0.022176760

6.946166992 -0.025167562 6.947021484 0.022176760

6.946594238 -0.001498110 6.947021484 0.022176760

6.946594238 -0.001498110 6.946807861 0.010338648

6.946594238 -0.001498110 6.946701050 0.004420100

6.946594238 -0.001498110 6.946647644 0.001460953

6.946620941 -0.000018589 6.946647644 0.001460953

6.946620941 -0.000018589 6.946634293 0.000721179

6.946620941 -0.000018589 6.946627617 0.000351294

6.946620941 -0.000018589 6.946624279 0.000166352

6.946620941 -0.000018589 6.946622610 0.000073882

6.946620941 -0.000018589 6.946621776 0.000027646

6.946620941 -0.000018589 6.946621358 0.000004529

6.946621150 -0.000007030 6.946621358 0.000004529

6.946621254 -0.000001251 6.946621358 0.000004529

Next Middle will get us close enough to zero:

F( 6.946621280 ) is 0.000000194

The desired approximation of the solution is:

x ≓ 6.946621280

Note, ≓ is the approximation symbol

One solution was found :

x ≓ 6.946621280

Discussion

31.	Fill In The Blanks.a. a2-b2 =b. Common factor of ax2 + bx is с (9)2 – (3)2 =d. Factorised form of x2 + 8x + 15 is
Answer» Step-by-step EXPLANATION: don't SOLVED I'll put in another QUESTION mark me BRAINLIEST

31.

Fill In The Blanks.a. a2-b2 =b. Common factor of ax2 + bx is с (9)2 – (3)2 =d. Factorised form of x2 + 8x + 15 is

Answer»

Step-by-step EXPLANATION:

don't SOLVED I'll put in another QUESTION mark me BRAINLIEST

Discussion

32.	The value of sin 18° isDon't report if U don't know stupíd people.
Answer» Answer: LET x = 18° so, 5x = 90° now we can write 2x + 3x = 90° so 2x = 90° - 3x now taking sin both SIDE we can write sin2x = sin(90°-3x) sin2x = cos3x [as we know, sin(90°-3x) = Cos3x ] so evaluating we can write 2sinxcosx =4cos³x - 3cosx [as we know, Cos3x = 4cos³x - 3cosx, This I will explain later ] Now, 2sinxcosx - 4cos³x + 3cosx = 0 cosx(2sinx - 4cos²x + 3) = 0 Now divding both side by cosx we get, 2sinx - 4cos²x + 3 = 0 2sinx - 4(1-sin²x) + 3 = 0 [as we know, cos²x = (1-sin²x), by sin²x + cos²x = 1 ] 2sinx - 4 + 4sin²x + 3 = 0 2sinx + 4sin²x - 1 = 0 we can write it as, 4sin²x + 2sinx - 1 = 0 Now apply Sridhar Acharya Formula Here, ax² + bx + C = 0 so, x = (-b ± √(b² - 4ac))/2a now applying it in the equation SINX = (-2 ± √(2² - 44(-1)))/2.(4) sinx = (-2 ± √(4 +16))/8 sinx = (-2 ± √20)/8 sinx = (-2 ± 2.√5) / 8 sin x = 2(-1 ± √5 ) / 8 sin x = (-1 ± √5)/4 sin18° = (-1 ± √5)/4 Now how I get the Cos3x value? Cox3x = Cos(2x+x) Cox3x = Cos2xCosx - Sin2xSinx Cox3x = (2Cos²x - 1)Cosx - (2SinxCosx)Sinx Cox3x = 2Cos³x -Cosx - 2Sin²xCosx Cox3x = 2Cos³x -Cosx - 2Cosx(1-Cos²x) Cox3x = 2Cos³x -Cosx - 2Cosx + 2Cos³x Cox3x = 4Cos³x - 3Cosx

32.

The value of sin 18° isDon't report if U don't know stupíd people.

Answer»

Answer:

LET x = 18°

so, 5x = 90°

now we can write

2x + 3x = 90°

so 2x = 90° - 3x

now taking sin both SIDE we can write

sin2x = sin(90°-3x)

sin2x = cos3x [as we know, sin(90°-3x) = Cos3x ]

so evaluating we can write

2sinxcosx =4cos³x - 3cosx [as we know, Cos3x = 4cos³x - 3cosx, This I will explain later ]

Now, 2sinxcosx - 4cos³x + 3cosx = 0

cosx(2sinx - 4cos²x + 3) = 0

Now divding both side by cosx we get,

2sinx - 4cos²x + 3 = 0

2sinx - 4(1-sin²x) + 3 = 0 [as we know, cos²x = (1-sin²x), by sin²x + cos²x = 1 ]

2sinx - 4 + 4sin²x + 3 = 0

2sinx + 4sin²x - 1 = 0

we can write it as,

4sin²x + 2sinx - 1 = 0

Now apply Sridhar Acharya Formula Here,

ax² + bx + C = 0

so, x = (-b ± √(b² - 4ac))/2a

now applying it in the equation

SINX =

(-2 ± √(2² - 44(-1)))/2.(4)

sinx = (-2 ± √(4 +16))/8

sinx = (-2 ± √20)/8

sinx = (-2 ± 2.√5) / 8

sin x = 2(-1 ± √5 ) / 8

sin x = (-1 ± √5)/4

sin18° = (-1 ± √5)/4

Now how I get the Cos3x value?

Cox3x = Cos(2x+x)

Cox3x = Cos2xCosx - Sin2xSinx

Cox3x = (2Cos²x - 1)Cosx - (2SinxCosx)Sinx

Cox3x = 2Cos³x -Cosx - 2Sin²xCosx

Cox3x = 2Cos³x -Cosx - 2Cosx(1-Cos²x)

Cox3x = 2Cos³x -Cosx - 2Cosx + 2Cos³x

Cox3x = 4Cos³x - 3Cosx

Discussion

33.	Please answer fast solve everything
Answer» ANSWER: I don't KNOW the answer !!!!

33.

Please answer fast solve everything

Answer»

ANSWER:

I don't KNOW the answer !!!!

Discussion

34.	Find the cube root of the following number by estimationi) 2197 ii) 4913 iii) -24389 iv) 85184 v) 681472 vi) -778688please answer with explanation :(
Answer» Answer: 1.) 2197 =2197×2197×2197 =4,826,809×2197 =1.06 2.) 4913 =4913×4913×4913 =24,137,569×4913 =1.18 3.) -24389 = -24389×-24389×-24389 = -24389×-24389 = -24389 4.) 85184 = 85184×85184×85184 = 7.25×85184 =6.18 5.) 681472 =681472×681472×681472 =7.25×681472 =6.18 6.) -778688 = -778688× -778688× -778688 =-778688× -778688 = -778688 Step-by-step EXPLANATION: This is CORRECT answer please MAKE me BAINLIST

34.

Find the cube root of the following number by estimationi) 2197 ii) 4913 iii) -24389 iv) 85184 v) 681472 vi) -778688please answer with explanation :(

Answer»

Answer:

1.) 2197

=2197×2197×2197

=4,826,809×2197

=1.06

2.) 4913

=4913×4913×4913

=24,137,569×4913

=1.18

3.) -24389

= -24389×-24389×-24389

= -24389×-24389

= -24389

4.) 85184

= 85184×85184×85184

= 7.25×85184

=6.18

5.) 681472

=681472×681472×681472

=7.25×681472

=6.18

6.) -778688

= -778688× -778688× -778688

=-778688× -778688

= -778688

Step-by-step EXPLANATION:

This is CORRECT answer

please MAKE me BAINLIST

Discussion

35.	For the equation 7(x-4)=56 the value of xX
Answer» ANSWER: X = 12 Step-by-step explanation: 7(x-4) = 56 x-4 = 8 x = 12

35.

For the equation 7(x-4)=56 the value of xX

Answer»

ANSWER:

X = 12

Step-by-step explanation:

7(x-4) = 56

x-4 = 8

x = 12

Discussion

36.	Who is more st.upid ??
Answer» the MOM of that SMALL CHILD....

Discussion

37.	1) If n(A)=0, find n[P(A)]
Answer» <P>ANSWER: N[P(A)]= 0 as a is zero all the NUMBERS will become zero

37.

1) If n(A)=0, find n[P(A)]

Answer»

<P>ANSWER:

N[P(A)]= 0

as a is zero all the NUMBERS will become zero

Discussion

38.	Simplify (2a + 3b ) raise to 2
Answer» ANSWER: 2+3= a+b 5=ab 5ab hope U LIKE this answer

38.

Simplify (2a + 3b ) raise to 2

Answer»

ANSWER:

2+3= a+b

5=ab

5ab

hope U LIKE this answer

Discussion

39.	The greatest value of sin x cos x
Answer» The maximum value of sinxcosx=1/2 To get this Multiply with 2 in both numerator and DENOMINATOR and you will get 2sinxcosx/2 But 2sinxcosx=sin2x The MAX value of sin2x is 1 But we have sin2x/2 Therefore,the maximum value is 1/2

39.

The greatest value of sin x cos x

Answer»

The maximum value of sinxcosx=1/2

To get this

Multiply with 2 in both numerator and DENOMINATOR and you will get 2sinxcosx/2

But 2sinxcosx=sin2x

The MAX value of sin2x is 1 But we have sin2x/2

Therefore,the maximum value is 1/2

Discussion

40.	2. If A = {x: x is a prime number}, B = {x: x is an odd natural number}, findA n B?
Answer» Answer: hope it is help to you Step-by-step EXPLANATION: If A={x:x is a natural number },B={x:x is an even natural number}C={x:x is an odd natural number} and D={x:x is a prime number }, find (i) A∩B (ii) A∩C (iii) A∩D (IV) B∩C (v) B∩D (VI) C∩D *mark* me as *brain LIST*

40.

2. If A = {x: x is a prime number}, B = {x: x is an odd natural number}, findA n B?

Answer»

Answer:

hope it is help to you

Step-by-step EXPLANATION:

If A={x:x is a natural number },B={x:x is an even natural number}C={x:x is an odd natural number} and D={x:x is a prime number }, find

(i) A∩B

(ii) A∩C

(iii) A∩D

(IV) B∩C

(v) B∩D

(VI) C∩D

mark me as brain LIST

Discussion

41.	Add : a - b +ab, b - c+bc, c - a+ac
Answer» ANSWER: ANSWER IS ab+bc+ca Step-by-step explanation: $(a - <klux>B</klux> + ab) + (b - c + bc) + (c - a + ca) \\ a - b + ab + b - c + bc + c - a +<klux>AC</klux> \\ a - a - b + b - c + c + ab + bc + ca \\ ab + bc + ca$ -b SE +b cancel -c se +c " a-a " ac and ca means same pls mark me as brainliest

41.

Add : a - b +ab, b - c+bc, c - a+ac

Answer»

ANSWER:

ANSWER IS ab+bc+ca

Step-by-step explanation:

$(a - <klux>B</klux> + ab) + (b - c + bc) + (c - a + ca) \\ a - b + ab + b - c + bc + c - a +<klux>AC</klux> \\ a - a - b + b - c + c + ab + bc + ca \\ ab + bc + ca$

-b SE +b cancel

-c se +c "

a-a "

ac and ca means same

pls mark me as brainliest

Discussion

42.	Divide 20 pens between sheela and sangeeta in the ratio of 3:2
Answer» Answer: so while dividing this qe need to first DIVIDE 20 bye 5 as 3 plus 2 is 5 so each part means 20 divided by 5 which is 4 no multiply each part by four so the answer will be 12 and 8 ❤

42.

Divide 20 pens between sheela and sangeeta in the ratio of 3:2

Answer»

Answer:

so while dividing this qe need to first DIVIDE 20 bye 5

as 3 plus 2 is 5

so each part means 20 divided by 5 which is 4

no multiply each part by four

so the answer will be 12 and 8

❤

Discussion

43.	What is AD, SD, QD ? Mention needs or importance of AD, SD, QD.
Answer» Given : AD, SD, QD To FIND : What are they Solution: AD = AVERAGE Deviation also called Mean Deviation Mean Deviation = ∑ \| xi - Mean\| /n QD = Quartile Deviation Quartile Deviation = {( Q₂ - Q₁ ) + (Q₃ - Q₂)}/2 = (Q₃ - Q₁)/2 SD = √ (∑(xi - Mean)² /n) for population SD = √( ∑(xi - Mean)² /(n-1)) for population Learn More: Coefficient of quartile deviation is 1/4 then Q3/Q1 is - Brainly.in brainly.in/question/13398985 If the third quartile is 30 and median is 22 find the coefficient of ... brainly.in/question/12875627 If the first quartile is 142 and the semi-interquartile range is 18, find ... brainly.in/question/13279139

43.

What is AD, SD, QD ? Mention needs or importance of AD, SD, QD.

Answer»

Given : AD, SD, QD

To FIND : What are they

Solution:

AD = AVERAGE Deviation also called Mean Deviation

Mean Deviation = ∑ | xi - Mean| /n

QD = Quartile Deviation

Quartile Deviation = {( Q₂ - Q₁ ) + (Q₃ - Q₂)}/2

= (Q₃ - Q₁)/2

SD = √ (∑(xi - Mean)² /n) for population

SD = √( ∑(xi - Mean)² /(n-1)) for population

Learn More:

Coefficient of quartile deviation is 1/4 then Q3/Q1 is - Brainly.in

brainly.in/question/13398985

If the third quartile is 30 and median is 22 find the coefficient of ...

brainly.in/question/12875627

If the first quartile is 142 and the semi-interquartile range is 18, find ...

brainly.in/question/13279139

Discussion

44.	In the following figure, find the measures of the angles marked by the lettersa,b and c.
Answer» I HOPE it will HELP you PLEASE make my ANSWER brainliest

44.

In the following figure, find the measures of the angles marked by the lettersa,b and c.

Answer»

I HOPE it will HELP you

PLEASE make my ANSWER brainliest

Discussion

45.	What is thevinin's theorem?answer the given question4 s 3 x :- !!!/fkr jnph yoi/!!
Answer» ANSWER: cchochkckgckhchkckh, hockh HL

45.

What is thevinin's theorem?answer the given question4 s 3 x :- !!!/fkr jnph yoi/!!

Answer»

ANSWER:

cchochkckgckhchkckh, hockh HL

Discussion

46.	The ratio of two number is 3: 5. if both numbers are increased by 5 their ratio becomes 2:3 find the number.
Answer» Given Ratio of two numbers is 3:5 If numbers are increased by 5 then ratio will be 2:3 To Find We have to find the numbers $\sf\huge\bold{\underline{\underline{{Solution}}}}$ Let the number be 5x &3x According to the question: If it is increased by 5 their ratio becomes 2:3 =>(5x+5):(3x+5)=2:3 =>2(5x+5)=3(3x+5) =>10x+10=9x+15 =>10x-9x=15-10 =>x=5 Now, finding the numbers We let the first number 3x So, 5x=5×5=25 first number is 25 Second number =3x=3×5=15 ∴First number is 25 second number is 15 Check Ratio of two numbers is 3:5 =>15:25=3:5 If they are increased by 5 their ratio becomes 2:3 =>15+5=20 =>25+5=30 Ratio =20:30=2:3 Extra information=> Ratio are USED to show that the both fraction values are of same quantity or SAY are in ratio. When a fraction are EXPRESSED in TERMS of a:b it is said to be in ratio where ,b≠0.

46.

The ratio of two number is 3: 5. if both numbers are increased by 5 their ratio becomes 2:3 find the number.

Answer»

Given

Ratio of two numbers is 3:5

If numbers are increased by 5 then ratio will be 2:3

To Find

We have to find the numbers

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Let the number be 5x &3x

According to the question:

If it is increased by 5 their ratio becomes 2:3

=>(5x+5):(3x+5)=2:3

=>2(5x+5)=3(3x+5)

=>10x+10=9x+15

=>10x-9x=15-10

=>x=5

Now, finding the numbers

We let the first number 3x So, 5x=5×5=25

first number is 25

Second number =3x=3×5=15

∴First number is 25

second number is 15

Check

Ratio of two numbers is 3:5 =>15:25=3:5

If they are increased by 5 their ratio becomes 2:3

=>15+5=20

=>25+5=30

Ratio =20:30=2:3

Extra information=>

Ratio are USED to show that the both fraction values are of same quantity or SAY are in ratio.

When a fraction are EXPRESSED in TERMS of a:b it is said to be in ratio where ,b≠0.

Discussion

47.	. A man sold two boxes for Rs.2100 each. He sold one box at a profit of 20%and the other box at a loss of 16%. Find the overall gain or loss?
Answer» Answer: SELLING price of watch A and watch B= Rs. 425 Let COST price of watch A=x Profit =10% ∴ 100 110 x=425 x=386.36 Let cost price of watch B=y Loss =10% ∴ 100 90 y=425 y=472.22 Net cost price =x+y=858.5858 Net selling price =850 Loss%= 858.58 858.5858−850 ×100=1% Step-by-step explanation: pls MARK me brainlist pls pls mark me brainlist pls

47.

. A man sold two boxes for Rs.2100 each. He sold one box at a profit of 20%and the other box at a loss of 16%. Find the overall gain or loss?

Answer»

Answer:

SELLING price of watch A and watch B= Rs. 425

Let COST price of watch A=x

Profit =10%

∴

100

110

x=425

x=386.36

Let cost price of watch B=y

Loss =10%

∴

100

90

y=425

y=472.22

Net cost price =x+y=858.5858

Net selling price =850

Loss%=

858.58

858.5858−850

×100=1%

Step-by-step explanation:

pls MARK me brainlist pls

pls mark me brainlist pls

Discussion

48.	3 as a percent will become 6 1/4
Answer» ANSWER: your answer is 48 refer the ATTACHMENT for the solution hope it HELPED you... HAVE A NICE DAY!!

48.

3 as a percent will become 6 1/4

Answer»

ANSWER:

your answer is 48

refer the ATTACHMENT for the solution

hope it HELPED you...

HAVE A NICE DAY!!

Discussion

49.	(d) A ball pen (without a lid) and a cricket stump are placed vertically in a swimming pool filled withwater such that their pointed ends are at the same depth.
Answer» Answer: YES because there is no written LAW for a batsman to take a particular guard of STUMPS. ... Another classic example is steve smith FORMER Australian captain, he moves to cover all 3 stumps when the bowler is about to bowl his deliver

49.

(d) A ball pen (without a lid) and a cricket stump are placed vertically in a swimming pool filled withwater such that their pointed ends are at the same depth.

Answer»

Answer:

YES because there is no written LAW for a batsman to take a particular guard of STUMPS. ... Another classic example is steve smith FORMER Australian captain, he moves to cover all 3 stumps when the bowler is about to bowl his deliver

Discussion

50.	3. State whether the following statements are True or False:Pq^2+qr^2+rs^2
Answer» Step-by-step EXPLANATION: goggle it NAHH HUHH may it HELP uh....the ANSWER with it...

50.

3. State whether the following statements are True or False:Pq^2+qr^2+rs^2

Answer»

Step-by-step EXPLANATION:

goggle it NAHH HUHH may it HELP uh....the ANSWER with it...

Discussion

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